1-calculate the mass of 4 moles of Na
2-what is the mass of 0.3 moles of water H2o H:1 O:16
3-compute the number of moles found in 10g of ethanol C2H5OH C:12 O:16


please help me as fast you can

Answers

Answer 1

1. 92 g

2. 5.4 g

3. 0.217 moles

Further explanation  

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

Moles can also be determined from the amount of substance mass and its molar mass

[tex]\tt n=\dfrac{m}{MW}[/tex]

1. the mass of 4 moles of Na(MW= 23 g/mol)

[tex]\tt mass=mol\times MW\\\\mass=4\times 23\\\\mass=92~g[/tex]

2.  the mass of 0.3 moles of water(MW=18 g/mol)

[tex]\tt mass=mol\times MW\\\\mass=0.3\times 18\\\\mass=5.4~g[/tex]

3. the number of moles found in 10g of ethanol C2H5OH(MW=46 g/mol) :

[tex]\tt mol=\dfrac{10}{46}\\\\mol=0.217[/tex]


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Answer: A. 5.41

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} Al=\frac{2.50g}{27g/mol}=0.0926moles[/tex]

[tex]\text{Moles of} Pb(NO_3)_2=\frac{8.65g}{331g/mol}=0.0261moles[/tex]

[tex]2Al(s)+3Pb(NO_3)_2(aq)\rightarrow 3Pb(s)+2Al(NO_3)_3(aq)[/tex]  

According to stoichiometry :

3 moles of [tex]Pb(NO_3)_2[/tex] require  = 2 moles of [tex]Al[/tex]  

Thus 0.0261 moles of [tex]Pb(NO_3)_2[/tex] will require=[tex]\frac{2}{3}\times 0.0261=0.0174moles[/tex]  of [tex]Al[/tex]

Thus [tex]Pb(NO_3)_2[/tex] is the limiting reagent as it limits the formation of product and [tex]Al[/tex] is the excess reagent.

As 3 moles of [tex]Pb(NO_3)_2[/tex] give = 3 moles of [tex]Pb[/tex]

Thus 0.0261 moles of [tex]Pb(NO_3)_2[/tex] give =[tex]\frac{3}{3}\times 0.0261=0.0261 moles[/tex]  of [tex]Pb[/tex]

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I hope this helps! :D Have a nice night!

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Explanation:

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