Answer:
What are you asking? Whats the problem?
Answer:
sin 102 cant be put into standard position its already in standard position if you want to covert to rectangular it would be sin (102).
Step-by-step explanation:
sin(x)=0.2 What is x
Which description is paired with its correct expression? two less than the quotient of a number cubed and four, increased by eight; 2 minus StartFraction n cubed Over 4 EndFraction + 8 six times the difference of five and a number squared; 6 (n squared minus 5) three more than the quotient of nine and a number cubed, decreased by two; 3 + StartFraction 9 Over n cubed EndFraction minus 2 twice the difference of a number squared and three; 2 n squared minus 3
Answer:
Three more than the quotient of nine and a number cubed, decreased by two; 3 + StartFraction 9 Over n cubed EndFraction minus 2
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
i took the review
If and are the radi of two concentric circles and (r. > r.). If the chord
of the larger circle AB touches the inter circle. Find the value of AB
Answer:
r1 and r2 are the radii of two concentric circles
To find:
The length of the chord of the larger circle.
Solution:
We have given the two concentric circles which means both the circles have the same centre.
The chord of the larger circle toches the inner circle so the chord of the larger circle will be the tangent of the smaller circle.
And we know that the radius of the circle is perpendicular to the tangent of the circle.
Let 2x be the length of the chord of the circle.
r1 is the radius of the larger circle.
r2 is the radius of the smaller circle.
So by the Pythagoras theorem,
The length of the half of the chord is given by:
r1² = x² + r2²
x² = r1² - r2²
x = √r1² - r2²
So,
The length of the chord will be 2x = 2√r1² - r2² units
Step-by-step explanation:
Pls help me #7thgrademath
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Answer:
68 degrees
Step-by-step explanation:
180 - 90 = 90
90 - 22 = 68
The angle is 68
Which measure of central tendency best describes the data set below?
{1, 2, 3, 4, 5, 6, 12, 23}
A. the mean, 7
B. the mode, 4
C. the range, 22
D. the median, 4.5
Answer:
It is the mean
Step-by-step explanation:
Which measure of central tendency best describes the data set below?
{1, 2, 3, 4, 5, 6, 12, 23}
=mean
56 Divided by 8=7 mean=7
It’s a. the mean, 7 Or d. the median, 4.5
Today is Friday. What day of the week is it 80 days from today?
Answer: Tuesday
April 20,2021
HELP HELP HELP PLEASE!!!! Ryan sells beaded necklaces. Each large necklace sells for $4.10 and each small necklace sells for $3.80. How much will he earn from selling 1 large necklace and 5 small necklaces?
Answer:
23.10
Step-by-step explanation: Each large necklace is 4.10 There are only 1 largfe necklace he sold so we multiply 4.10 by 1 which is 4.10. A small necklace is 3.80 and he sold 5 of them so we multiply 5 by 3.80. 3.80 times 5 is 19. Then we add the large and small necklace product.
19+ 4.10=23.10
Answer:
23.1
Step-by-step explanation:
(4.10*1)+(3.80*5)
4.10*1=4.10
3.80*5=19
4.10+19=$23.1
An inequality is shown below.
Which situation is best represented by the inequality?
Answer:
Option C is the correct answer.
Comment for explaination
Find the area of the circle please
Answer:
A≈149.57
Step-by-step explanation:
The area of the square above is 36. What is the value of x?
A) 2
B) 4
C) 6
D) 9
I think it is A)2 because 3^2 = 9 and 9×4 = 36
Write an equation in slope intercept form that is perpendicular to 3x + 2y equals 12 and passes through the point (1,2)
Answer:
The equation is y = (2/3)x + (4/3).
Step-by-step explanation:
First, you have to change the equation into slope-intecept formula to find its gradient (slope) :
[tex]3x + 2y = 12[/tex]
[tex]2y = - 3x + 12[/tex]
[tex]y = - \frac{3}{2}x + 6[/tex]
Given that when a line is perpendicular to the other line, their slope value multiplied, will form -1. Next, we have to find the slope for line :
[tex]m1 \times m2 = - 1[/tex]
[tex] - \frac{3}{2} \times m2 = - 1[/tex]
[tex]m2 = - 1 \div - \frac{3}{2} [/tex]
[tex]m2 = \frac{2}{3} [/tex]
Lastly, we have to subatitute the x and y values into the equation, to find its intercept value :
[tex]y = \frac{2}{3}x + b[/tex]
[tex]let \: x = 1,y = 2[/tex]
[tex]2 = \frac{2}{3} (1) + b[/tex]
[tex]b = 2 - \frac{2}{3} [/tex]
[tex]b = \frac{4}{3} [/tex]
[tex]y = \frac{2}{3} x + \frac{4}{3} [/tex]
Factor the expression. d2 + 10d + 25
Answer:
(d+5)^2
Step-by-step explanation:
Asanji's school is selling tickets to a spring musical. On the first day of ticket sales the school
sold 1 adult ticket and 1 student ticket for a total of $18. The school took in $57 on the second
day by selling 3 adult tickets and 4 student tickets. Find the price of an adult ticket and the price
of a student ticket.
Answer:
j
Step-by-step explanation:
Answer: The price of adult ticket is $ 13and child ticket is $12.Hope this will help u.....
Step-by-step explanation:
how many tims can 60 go into 72 pls help
Answer:
The answer is 1 time
Step-by-step explanation:
If you subtract 60 from 72 you come out with 12. Which is not enough for you to subtract 60 again so the answer is 1.
Show all work for the following
Algebraically solve the following system of equations.
(x+2)2+(y-3)2=16
x+y-1=0
Answer:
[tex](-2-2\sqrt{2},3+2\sqrt{2})\,,\,(-2+2\sqrt{2},3-2\sqrt{2})[/tex]
Step-by-step explanation:
Given:
[tex](x+2)^2+(y-3)^2=16\\x+y-1=0[/tex]
To find: value of [tex]x,y[/tex]
Solution:
[tex](x+2)^2+(y-3)^2=16\,\,\,...(i)\\x+y-1=0\,\,\,(ii)[/tex]
From (ii),
[tex]x=1-y[/tex]
Put this value of [tex]x[/tex] in (i)
[tex](1-y+2)^2+(y-3)^2=16\\(3-y)^2+(y-3)^2=16\\(y-3)^2+(y-3)^2=16\\2(y-3)^2=16\\(y-3)^2=8[/tex]
[tex]y-3=[/tex] ± [tex]\sqrt{8}[/tex] = ± [tex]2\sqrt{2}[/tex]
[tex]y=3[/tex] ± [tex]2\sqrt{2}[/tex]
At [tex]y=3[/tex] + [tex]2\sqrt{2}[/tex] ,
[tex]x=1-(3+2\sqrt{2})=1-3-2\sqrt{2}=-2-2\sqrt{2}[/tex]
At [tex]y=3-2\sqrt{2}[/tex] ,
[tex]x=1-(3-2\sqrt{2})=1-3+2\sqrt{2}=-2+2\sqrt{2}[/tex]
Solutions are [tex](-2-2\sqrt{2},3+2\sqrt{2})\,,\,(-2+2\sqrt{2},3-2\sqrt{2})[/tex]
For this polynomial identify the coefficients and degree of each term.
Step-by-step explanation:
first term
degree 1
coefficient 4
second term
degree. 2
coefficient 8
third term
degree 3
coefficient -5
fourth term
degree 4
coefficient -5
fifth term
degree 0
coefficient -5
What is the height of the cone below?
Answer:
Where's the cone at and I might be able to help
Step-by-step explanation:
Answer: Please put a picture of the cone underneath the question!
Step-by-step explanation:
A recipe calls for 1/3 cup of sugar for every 1/2 cup of flour. In cups, how much sugar is needed per one cup of flour?
Answer:
1 equals two of 1/2 which means you get the equation 1/3 x 2 for the answer
please help. loll
which expression is equal to 1/3b-7?
1)1/3(b+21)
2)-1/3(b-21)
3)-1/3(b+21)
4)1/3(b-21)
Answer:
4 1/3(b-21) im pretty sure
PLEASE ANSWER THIS QUESTION RIGHT.What do we call the graph of a quadratic?
Answer:
parabola
Step-by-step explanation:
Solve for x, given the attached image.
Answer:
x = 8
Step-by-step explanation:
Central angle = measure of intercepted arc
Central angle = 47°
Arc measure = 7 + 5x
Therefore:
7 + 5x = 47
Subtract 7 form both sides
5x = 47 - 7
5x = 40
Divide both sides by 5
x = 40/5
x = 8
You get about 32 homework assignments every 4 weeks. Circle
equation that models this.
Use your equation to determine the number of homework
assignments you get after 9 weeks.
What shape is this cross-section?
Answer:
circle D
Step-by-step explanation:
One lap around a track is equal to 1/4 of a mile. A horse ran a distance of 9 laps in 2 minutes and 30 seconds. What was the horse's average speed in miles per minute? Need Help!!
In the graph above, what's the distance between (5, –2) and (5, 3)?
Answer:
5
Step-by-step explanation:
To find the distance between two points, subtract the two values and find the absolute value. So in this question, our equation would be |-2-3| which equals |-5| which then solves to 5.
solve fast please. its related to mathematics...
Answer:
The answer is 6
Step-by-step explanation:
[tex]\lim_{x \to 4} \frac{x^3 - 64}{x^2 - 16} \\\\= \lim_{x \to 4} \frac{x^3 - 64}{(x + 4)(x - 4)} \\\\=\lim_{x \to 4} \frac{(x^2 + 4x + 16)(x - 4)}{(x + 4)(x - 4)} \\\\= \lim_{x \to 4} \frac{(x^2 + 4x + 16)}{(x + 4)} \\\\= (16 + 16 + 16) / 8\\= 48 / 8\\= 6[/tex]
f(x)=2x-11
FIND x when f(x)= -17
Answer:
[tex]f(x) = 2x - 11 \\ f (x)= 2( - 17) - 11 \\ \\ f(x) = - 34 - 11 \\ f(x) = - 45[/tex]
Evaluate the expression 6x for x 6.
6x = blank when x=6
Step-by-step explanation:
[tex] \underline{ \underline{ \text{Given}}} : [/tex]
x = 6[tex] \underline{ \underline{ \text{To \: find}}} : [/tex]
Value of 6x[tex] \underline{ \underline{ \text{Solution}}} : [/tex]
~ Plug the value of x and then multiply !
⇾ [tex] \tt{6x = 6 \times 6 \times = \boxed{36}}[/tex]
[tex] \red{ \boxed{ \boxed{ \text{Our \: final \: answer : \boxed{ \tt{36}}}}}}[/tex]
Hope I helped ! ♡
Have a wonderful day / night ! ツ
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Can someone please help
Answer:
340
Step-by-step explanation:
Write the negation of each of the following logical expressions so that all negations immediately precede predicates. In some cases, it may be necessary to apply one or more laws of propositional logic.
a. ∃x ∀y(P(x,y) → Q(x,y))
b. ∃x ∀y(P(x,y) → P(y,x))
c. ∃x ∃y P(x,y) ∧ ∀x ∀y Q(x,y)
Answer:
a. Negation of ∃x ∀y(P(x,y) → Q(x,y)) = ∀x ∃y P(x,y) ∧ ¬Q(x,y) ]
b. Negation of ∃x ∀y(P(x,y) → P(y,x)) = ∀x ∃y [ ¬P(x,y) ∨ ¬P(y,x) ] ∧ [P(x,y) ∨ P(y,x)]
c. Negation of ∃x ∃y P(x,y) ∧ ∀x ∀y Q(x,y) = ∀x ∀y ¬ [P(x,y)] ∨ ∃x ∃y ¬ [Q(x,y)]
Step-by-step explanation:
a.∃x ∀y(P(x,y) → Q(x,y))
Negation = ¬ [ ∃x ∀y(P(x,y) → Q(x,y)) ]
= ∀x ¬ [ ∀y(P(x,y) → Q(x,y)) ]
= ∀x ∃y ¬ [ (P(x,y) → Q(x,y)) ]
= ∀x ∃y ¬ [ ¬P(x,y) ∨ Q(x,y) ]
= ∀x ∃y P(x,y) ∧ ¬Q(x,y) ]
Negation of ∃x ∀y(P(x,y) → Q(x,y)) = ∀x ∃y P(x,y) ∧ ¬Q(x,y) ]
b. ∃x ∀y(P(x,y) → P(y,x))
Negation = ¬ [ ∃x ∀y(P(x,y) → P(y,x)) ]
= ∀x ¬ [ ∀y(P(x,y) → P(y,x)) ]
= ∀x ∃y ¬ [ (P(x,y) → P(y,x)) ]
= ∀x ∃y ¬ [ ( P(x,y) ∧ P(y,x) ) ∨ ( ¬P(x,y) ∧ ¬P(y,x) )]
= ∀x ∃y ¬ [ P(x,y) ∧ P(y,x) ] ∧ ¬[ ¬P(x,y) ∧ ¬P(y,x) ]
= ∀x ∃y [ ¬P(x,y) ∨ ¬P(y,x) ] ∧ [ P(x,y) ∨ P(y,x) ]
∴ we get
Negation of ∃x ∀y(P(x,y) → P(y,x)) = ∀x ∃y [ ¬P(x,y) ∨ ¬P(y,x) ] ∧ [P(x,y) ∨ P(y,x)]
c. ∃x ∃y P(x,y) ∧ ∀x ∀y Q(x,y)
Negation = ¬ [ ∃x ∃y P(x,y) ∧ ∀x ∀y Q(x,y) ]
= ¬ [ ∃x ∃y P(x,y) ] ∨ ¬ [ ∀x ∀y Q(x,y) ]
= ∀x¬ [ ∃y P(x,y) ] ∨ ∃x ¬ [ ∀y Q(x,y) ]
= ∀x ∀y ¬ [ P(x,y) ] ∨ ∃x ∃y ¬ [ Q(x,y) ]
∴ we get
Negation of ∃x ∃y P(x,y) ∧ ∀x ∀y Q(x,y) = ∀x ∀y ¬ [ P(x,y) ] ∨ ∃x ∃y ¬ [ Q(x,y) ]