1 #Write a function called phonebook that takes two lists as
2 #input:
3 #
4 # - names, a list of names as strings
5 # - numbers, a list of phone numbers as strings
6 #
7 #phonebook() should take these two lists and create a
8 #dictionary that maps each name to its phone number. For
9 #example, the first name in names should become a key in
10 #the dictionary, and the first number in numbers should
11 #become the value corresponding to the first name. Then, it
12 #should return the dictionary that results.
13 #
14 #Hint: Because you're mapping the first name with the first
15 #number, the second name with the second number, etc., you do
16#not need two loops. For a similar exercise, check back on
17 #Coding Problem 4.3.3, the Scantron grading problem.
18 #
19 #You may assume that the two lists have the same number of #items: there will be no names without numbers or numbers
20 #without names.
21 #Write your function here!
25
26
27
28 #Below are some lines of code that will test your function
29 #You can change the value of the variable(s) to test your
30 #function wit h different inputs 2 If your function works correctly, this ill originally
31
32 #print (although the order of the keys may vary):
33| #('Jackie': '404-555-1234., 'Joshua': .678-555-5678., "Marguerite': '778-555-9012
35
36 name_list ['Jackie', Joshua', 'Marguerite']
37 number list-['484-555-1234, 678-555-5678 770-555-9812']
38 print (phonebook (name list, numberlist))
39
40
41

Answer:

I am writing a Python program.

def concordance(filename):  # function that takes a file name as parameter and returns the concordance for that file

   file = open(filename,"r")  #opens file in read mode

   unique={}  #creates and empty list

   for word in file.read().split():  #loops through every word in the file

       if word in unique:  # if words is already present in the list

           unique[word] += 1  #add 1 to the count of the existing word

       else:    #if word is not present in the list

           unique[word] = 1 #add the word to the list and add 1 to the count of word

           file.close();  # close the file

   for x in sorted(unique):  #sort the list and displays words with frequencies

       print(x, unique[x]);  #prints the unique words and their frequencies in alphabetical order

#prompts user to enter the name of the file

file_name=input('Enter the input file name: ')

concordance(file_name)  #calls concordance method by passing file name to it

Explanation:

The program has a function concordance that takes a text file name as parameter and returns a list of unique words and their frequencies.

The program first uses open() method to open the file in read mode. Here "r" represents the mode. Then creates an empty list named unique. Then the for loop iterates through each word in the file. Here the method read() is used to read the contents of file and split() is used to return these contents as a list of strings. The if condition inside the loop body checks each word if it is already present in the list unique. If the word is present then it adds 1 to the count of that word and if the word is not already present then it adds that unique word to the list and assign 1 as a count to that word. close() method then closes the file. The second for loop for x in sorted(unique):  is used to display the list of unique words with their frequencies. sorted() method is used to sort the list and then the loop iterates through each word in the list, through x, which acts like an index variable, and the loop displays each word along with its frequency.

Answer:

c. rear = (rear + 1) % elements.length; elements[rear] = element;

Explanation:

In the above statement:

Name of the array is elements.

rear holds current index of elements array where current rear element of queue is stored. Front are rear are two open ends of the queue and the end from which the element is inserted into the queue is called rear.

element is the element that is required to enqueue into the queue

Enqueue basically mean to add an element to a queue.

Here it is assumed that the queue is not full. This means an element can be added to the queue.

It is also assumed that code also correctly increments numElements.

rear = (rear + 1) % elements.length; This statement adds 1 to the rear and takes the modulus of rear+1 to the length of the array elements[]. This statement specifies the new position of the rear.

Now that the new position of rear is found using the above statement. Next the element can be enqueued to that new rear position using the following statement:

elements[rear] = element; this statement sets the element at the rear-th (new position) index of elements[] array.

For example we have a queue of length 5 and there are already 4 elements inserted into this queue. We have to add a new element i.e. 6 to the queue. There are four elements in elements[] array and length of the array is 5 so this means the queue is not full. Lets say that rear = 3

elements.length = 5

rear = 3

Using above two statements we get.

rear = (rear + 1) % elements.length;

       = 3 + 1 % 5

       = 4%5

      =  4

This computes the new position of rear. So the new position of rear is the 4-th index of elements[]. Now next statement:

elements[rear] = element;

elements[4] = 6

This statement adds element 6 to the 4-th index of elements[] array.

Thus the above statement enqueues element (element 6 in above example) into the queue.

Answer:

Baselines

Explanation:

The idea of software configuration management is that of monitoring and controlling changes in the software. The baseline is the standard and formally accepted form of a software item that is meant to be configured. It is like a generally accepted reference point, which could be applied in effecting incremental changes in the software.

There are three types of baselines which are the functional, developmental, and product baselines. Functional baselines provide an overview of the functionality and specifications of a system. The product baseline encompasses both the functional and physical details of the system.

Answer:

Option D, all of the above, is the right answer.

Explanation:

A Boolean expression is an expression in Computer Science. It is employed in programming languages that create a Boolean value when it is evaluated. There may be a true or false Boolean value. These expressions correspond to propositional formularies in logic. In Boolean expression, the  expression 3 > 5 is evaluated as false while  5 > 3 is evaluated as true

Boolean expressions control  all of the above method execution and as such option d is correct.

A Boolean expression is known to be a kind of logical statement that is said to be one of the two options that is it can be TRUE or FALSE .

Conclusively, Note that Boolean expressions are used to compare two or more data of any type only if  both parts of the expression have equal basic data type.  Boolean expressions control recursion, conditional execution and alternative execution.

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Answer:

the server will atomaticly detect

Explanation:

not worry

Answer:

Spear Phishing and War Dialing

Explanation:

So let's tackle these one at a time.

Vishing is simply any type of message (i.e., email, text, phone call, etc.) that appears to be from a trusted source but is not.

Whaling is simply a spear phishing attack of a high-value target such as a CEO or someone with high-level access at a company.

Spear phishing is simply a targeted phishing attack, usually towards a specific person or group of people.  (Phishing attack is simply a social attack to try and gain unauthorized access to a resource).

Pharming is an attack that attempts to redirect website traffic to a fake site.

War dialing is a technique to automatically scan a list of numbers in an area in attempt to search for exposed modems, computers, board systems, or fax machines, in order to breach the network.

Hoaxing is simply a social attack that describes a serious threat in attempts to retrieve unauthorized access or money from a victim.  (Think microsoft tech support scams)

Now that we have defined these things, let's identify the possible threats that need to be reported.

(a) Vishing?  The sec admin report doesn't mention the source of the message so we cannot associate this one

(b) Whaling? The sec admin report says a user, implying someone not high up in the company, but doesn't say it's not someone high up.  This is possible.

(c) Spear phishing?  The sec admin report says a user, implying that only this user is being targeted so this is definitely valid.

(d) Pharming?  The sec admin report says nothing about site redirection.

(e) War dialing? The sec admin report doesn't say anything about unauthorized scanning; however, it mentions the user has an old functioning modem, so this is possible.

(f) Hoaxing?  The sec admin report doesn't mention a pop up in the email or the content of the email so we are uncertain.

Thus with these considerations, the two threats that are identified and need mitigation are Spear phishing and War Dialing/Whaling.  Note that we aren't positive of the war dialing or whaling, but a case could be made for either; however, given the modem information, the question seems to indicate war dialing.

Answer:

A printer is connected locally on Computer1 and is shared on the network. Computer2 installs the shared printer and connects to it. Computer1 considers the printer to be a(n) _____local___________ printer, and Computer2 considers the printer to be a(n) _____network___________ printer.

Explanation:

Any printer installed directly to Computer 1 is a local printer.  If this printer is then shared with computers 2 and 3 in a particular networked environment, it becomes a shared printer.  For these other computers 2 and 3, the shared printer is a network printer, because it is not locally installed in each of them.  There may be some features which network computers cannot use on a shared printer, especially if the printer can scan documents.

Answer:

Using java

//assuming that hashmap object name is ChangeMap

ChangeMap. replace("short", "long");

System.out.println("New HashMap: "

+ ChangeMap.toString());

Explanation:

From the above we have used the replace method to replace the value of the "short" key in the hashtable with "long" instead of the previous value "tall". We have used the printed the hashtable to the console using println and the ".toString()" method that we added to the function's parameter.

Answer:

The drivers wont be loaded and the deamons will not be running in the background unnecessarily, that makes the processes to run more faster

Explanation:

The chief advantage of deferred configuration or the advantage when some network applications defer configuration until a service is needed is that the drivers won't be loaded and the deamons will not be running in the background unnecessarily or when idle, that makes the processes to run more faster.

Network configuration is the activity which involves setting up a network's controls, flow and operation to assist the network communication of an organization or network owner.

Answer:

A structure can contain an instance of itself

Explanation:

The statement which is known to be false out of the option given is that a structure may comprise or contain an instance of itself. Because to my knowledge, variables of diverse type are always most likely to attributed and contain by a structure.

It is worthy of note that object that aren't similar are utilize in constructing a structure. Another true statement about structure is that a semicolon usually end it's explanation.

Answer:

See comments for line by line explanation (Lines that begins with // are comments)

The function written in C, is as follows:

//The function starts here

int check(x,y,n)

{

//This if condition checks if x and y are within range of 0 to n - 1

if((x>=0 && x<=n-1) && (y>=0 && y<=n-1))

{

//If the if conditional statement is true, the function returns 1

 return 1;

}

else

{

//If the if conditional statement is false, the function returns 0

 return 0;

}

//The if condition ends here

}

//The function ends here

Explanation:

Answer:

Here is the python method:

def is_power(n1, n2): # function that takes two positive integers n1 and n2 as arguments

   if(not n1>0 and not n2>0): #if n1 and n2 are not positive integers

       print("The number is not a positive integer so:") # print this message if n1 and n2 are negative

       return None # returns none when value of n1 and n2 is negative.

   elif n1 == n2: #first base case: if both the numbers are equal

       return True #returns True if n1=n2

   elif n2==1: #second base case: if the value of n2 is equal to 1

       return False #returns False if n2==1

   else: #recursive step

       return is_divisible(n1, n2) and is_power(n1/n2, n2) #call divisible method and is_power method recursively to determine if the number is the power of another

Explanation:

Here is the complete program.

def is_divisible(a, b):

   if a % b == 0:

       return True

   else:

       return False

def is_power(n1, n2):

   if(not n1>0 and not n2>0):

       print("The number is not a positive integer so:")  

       return None  

   elif n1 == n2:

       return True

   elif n2==1:

       return False

   else:

       return is_divisible(n1, n2) and is_power(n1/n2, n2)  

print("is_power(10, 2) returns: ", is_power(10, 2))

print("is_power(27, 3) returns: ", is_power(27, 3))

print("is_power(1, 1) returns: ", is_power(1, 1))

print("is_power(10, 1) returns: ", is_power(10, 1))

print("is_power(3, 3) returns: ", is_power(3, 3))

print("is_power(-10, -1) returns: ", is_power(-10, -1))  

The first method is is_divisible method that takes two numbers a and b as arguments. It checks whether a number a is completely divisible by number b. The % modulo operator is used to find the remainder of the division. If the remainder of the division is 0 it means that the number a is completely divisible by b otherwise it is not completely divisible. The method returns True if the result of a%b is 0 otherwise returns False.

The second method is is_power() that takes two numbers n1 and n2 as arguments. The if(not n1>0 and not n2>0) if statement checks if these numbers i.e. n1 and n2 are positive or not. If these numbers are not positive then the program prints the message: The number is not a positive integer so. After displaying this message the program returns None instead of True of False because of negative values of n1 and n2.

If the values of n1 and n2 are positive integers then the program checks its first base case: n1 == n2. Suppose the value of n1 = 1 and n2 =1 Then n1 is a  power of n2 if both of them are equal. So this returns True if both n1 and n2 are equal.

Now the program checks its second base case n2 == 1. Lets say n1 is 10 and n2 is 1 Then the function returns False because there is no positive integer that is the power of 1 except 1 itself.

Now the recursive case return is_divisible(n1, n2) and is_power(n1/n2, n2)  calls is_divisible() method and is_power method is called recursively in this statement. For example if n1 is 27 and n2 is 3 then this statement:

is_divisible(n1, n2) returns True because 27 is completely divisible by 3 i.e. 27 % 3 = 0

is_power(n1/n2,n2) is called. This method will be called recursively until the base condition is reached. You can see it has two arguments n1/n2 and n2. n1/n2 = 27/3 = 9 So this becomes is_power(9,3)

The base cases are checked. Now this else statement is again executed  return is_divisible(n1, n2) and is_power(n1/n2, n2) as none of the above base cases is evaluated to true. when is_divisible() returns True as 9 is completely divisible by 3 i.e. 9%3 =0 and is_power returns (9/3,3) which is (3,3). So this becomes is_power(3,3)

Now as value of n1 becomes 3 and value of n2 becomes 3. So the first base case elif n1 == n2: condition now evaluates to true as 3=3. So it returns True. Hence the result of this statement print("is_power(10, 2) returns: ", is_power(10, 2))  is:                                                                                                

is_power(27, 3) returns:  True

Following are the program to the given question:

Program Explanation:

Program:

def is_divisible(a, b):#defining a method is_divisible that takes two parameters

   return a % b == 0#using return keyword that modulas parameter value and checks its value equal to 0

def is_power(a, b):#defining a method is_power that takes two parameters  

   if a == 1:#defining if block that checks a value equal to 1  or check odd number condition

       return True#return value True

   if b ==  1:#defining if block that checks b value equal to 1  or check odd number condition

       return False#return value False

   if not is_divisible(a, b):#defining if block that check method is_divisible value

       return False##return value False

   return is_power(a/b, b)#using return keyword calls and return is_power method                          

print("is_power(10, 2) returns: ", is_power(10, 2))#using print method that calls is_power which accepts two parameter

print("is_power(27, 3) returns: ", is_power(27, 3))#using print method that calls is_power which accepts two parameter

print("is_power(1, 1) returns: ", is_power(1, 1))#using print method that calls is_power which accepts two parameter

print("is_power(10, 1) returns: ", is_power(10, 1))#using print method that calls is_power which accepts two parameter

print("is_power(3, 3) returns: ", is_power(3, 3))#using print method that calls is_power which accepts two parameter

Output:

Please find the attached file.

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Answer:

The answer is below

Explanation:

Given that:

Frame transmission time (X) = 40 ms

Requests = 50 requests/sec, Therefore the arrival rate for frame (G) = 50 request * 40 ms = 2 request

a) Probability that there is success on the first attempt = [tex]e^{-G}G^k[/tex] but k = 0, therefore Probability that there is success on the first attempt = [tex]e^{-G}=e^{-2}=0.135[/tex]

b) probability of exactly k collisions and then a success = P(collisions in k attempts) × P(success in k+1 attempt)

P(collisions in k attempts) = [1-Probability that there is success on the first attempt]^k = [tex][1-e^{-G}]^k=[1-0.135]^k=0.865^k[/tex]

P(success in k+1 attempt) = [tex]e^{-G}=e^{-2}=0.135[/tex]

Probability of exactly k collisions and then a success = [tex]0.865^k0.135[/tex]

c) Expected number of transmission attempts needed = probability of success in k transmission = [tex]e^{G}=e^{2}=7.389[/tex]

Answer:

int ComputeFibonacci(int N) {

   if(N == 0)

       return 0;

   else if (N == 1)

       return 1;

   else

       return ComputeFibonacci(N-1) + ComputeFibonacci(N-2);

}

Explanation:

Inside the function ComputeFibonacci that takes one parameter, N, check the base cases first. If N is eqaul to 0, return 0. If N is eqaul to 1, return 1. Otherwise, call the ComputeFibonacci function with parameter N-1 and N-2 and sum these and return the result.

For example,

If N = 4 as in the main part:

ComputeFibonacci(4) → ComputeFibonacci(3) + ComputeFibonacci(2) = 2 + 1 = 3

ComputeFibonacci(3) → ComputeFibonacci(2) + ComputeFibonacci(1) = 1 + 1 = 2

ComputeFibonacci(2) → ComputeFibonacci(1) + ComputeFibonacci(0) = 1 + 0  = 1

*Note that you need to insert values from the bottom. Insert the values for ComputeFibonacci(1) and  ComputeFibonacci(0) to find ComputeFibonacci(2) and repeat the process.

Answer:

System.gc()

Explanation:

System.gc() can be defined as the method which can be used to effectively request for garbage collection because they runs the garbage collector, which in turn enables JMV which is fully known as JAVA VIRTUAL MACHINE to claim back the already unused memory space of the objects that was discarded for quick reuse of the memory space , although Java virtual machine often perform garbage collection automatically.

Answer:

I am writing a C++ program:

#include <iostream>  //to use input output functions

#include<iomanip>  // to format the output

using namespace std;   // to identify objects like cin cout

void calculateCharge(double weight, double distance);   // function prototype

int main(){  //start of main() function body

  double w = 0.0, t = 0.0;  // w variable is for weight and t is for total

   unsigned int d = 0;   // d variable is to hold the value of distance

   calculateCharge(w, d); }  //calls calculateCharge method by passing weight and distance values to this method

void calculateCharge(double weight, double distance){  //method that takes weight and distance as parameters and compute the shipping charge

   double charge = 0.0;  //to store the value of shipping charges

   do {  // do while loop to handle multiple packages until a weight of 0 is entered

       cout << "Enter weight: " << endl;  //prompts user to enter weight

       cin >> weight;  //reads the input weight value

       if (weight == 0){  // if the value of weight is equal to 0

           break; }  // the loop breaks if value of weight is 0

       cout << "Enter distance: " << endl;  // if value of weight is not zero then the program precedes by prompting user to enter the value of distance

       cin >> distance;  //reads the input distance value

       cout << fixed << setprecision(2) << endl;  //set the precision to 2 means the sets the number of digits of an output to 2 decimal places

       if(weight <= 2)  //if the value of weight is less than or equals to 2

charge = (distance/500) * 3.10;  //compute the charge by this formula

else if(weight > 2 && weight <= 6)  //if weight is over 2 kg but not more than 6 kg

charge = (distance/500) * 4.20;  //charge is computed by multiplying value of distance to that of weight and if distance is greater than 500 then it is divided by 500 first

else if(weight > 6 && weight <= 10)  // if weight is over 6 kg but not more than 10 kg

charge = (distance/500) * 5.30;  //compute shipping charges by this formula

else  //if weight is over 10 kg

charge = (distance/500) * 6.40;   // compute shipping charge by multiplying value of distance to that of 6.40 weight value and if distance is greater than 500 then distance is divided by 500 first

cout << "Shipping charges: $" << charge << "\n";   //display the computed shipping charge

   } while (weight != 0);  //the loop continues to execute until weight 0 is entered

}              

Explanation:

The program is explained in the comments mentioned above. The program has a main() function that declares variable for weight, distance and total and then calls calculateCharge() method passing weight and dsitance in order to compute and return the shipping charge.

In calculateCharge() the user is prompted to enter the values for weight and distance. Then the based on the value of weight , the shipping charge is computed. Shipping charge is computed by multiplying the weight with distance. The distance is assumed to be 500 but if the distance entered by user exceeds 500 then the distance value is divided by 500 and then multiplied by the specified weight (according to if or else if conditions) in order to compute shipping charge. The program has a do while loop that keeps taking input from user until the user enters 0 as the value of weight.

The screenshot of the program and its output is attached.

Answer:

Following are the answer to this question:

Explanation:

The server would be generally a powerful processor instead of a desktop pc. It must choose the Dell server browser to choose a server for industrial applications.

Answer:

Mon Feb 26 2017

Explanation:

Since the current date is considered as Monday, February 26, 2017, thisDay will be set to that value.

The toDateString() method returns the first three letters of the name of the day (The first letter is capitalized), the first three letters of the name of the month (The first letter is capitalized), the day of the month as an integer, and the year as an integer (There are spaces between all)

Answer:

A total of 6,000 bps of bandwidth is used by the distributed routing algorithm

Explanation:

This is a bandwidth requirement question.

We proceed as follows;

To calculate the total number of bits for a routing table, we use the following formula;

Routing table=Number of routers * length of cost

we are given the following parameters from the question;

Number of routers = 500

length of cost = 4 bits

Routing table = 500*4

=2000

Hence, a routing table is 2000 bits in length.

Now we proceed to calculate the bandwidth required on each line using the formula below;

Bandwidth = no.of seconds * no.of bits in routing table

Bandwidth required on each line = 3*2000

=6000

Answer:

I am writing a Python program. Here is the function twoWordsV2:

def twoWordsV2 (length,firstLetter):#definition of function which takes length of the first word and first letter of the second word as parameter and returns these two words in a list

   word1 = "" # stores the first word

   word2= "" #holds the second word  

   while(len(word1)!=length): # checks if the input word1 length is not equal to the specified length

       word1 = input('A ' + str(length) + '-letter word please: ') #asks user to enter the input word1 of specified length

   while(word2!=firstLetter): #checks if the first character of input word2 is not equal to the specified firstLetter character

       word2 = input('A word beginning with ' + firstLetter+ ' please: ')#asks user to enter the input word2 begining with specified first letter

       if word2[0] == firstLetter.upper() or word2[0] == firstLetter.lower():#second word may begin with either an upper or lower case instance of firstLetter      

           return [word1,word2] #return the two words in a list                

#to check the working of the function use the following statement        

print(twoWordsV2(4,'B')) #calls twoWordsV2  method by passing 4 (length) and B (first letter)

Explanation:  

twoWordsV2 method has two parameters i.e length which is the length of the first word and firstLetter which is the first character of the the second word. This means the first word should be of specified length, and the second word should begin with a specified first letter. The function returns the two resultant words with the above specifications. These two words are displayed in a list. I will explain the working of the function with the help of an example:

Suppose length = 4 and firstLetter = 'B' and user enters "ok" as word1. input() method takes first word input from user.

The first while loop checks if the length of word1 i.e. ok is not equal to specified length i.e. 4. Length of word1 is checked using len function which returns 2 so length of word1 is 2. The loop condition is true because length of word1 i.e. 2 is not equal to specified length i.e. 4. So the body of the loop executes which displays this message:

A 4-letter word please:

Here notice that str(length) is changed to 4. This is because length=4 and str() converts this value into string.

So the above message keeps displaying until user enters a four letter word. Lets suppose user now enters "four". Now the while loop condition evaluates to false and the loop breaks. The program control  moves to the next line which is a while loop.

The second while loop checks if the first character of input word2 is not equal to the specified firstLetter character. Suppose word2 = "apple" and firstLetter= 'B'

Now the loop condition evaluates to true because word2 is not equal to first letter B. Now the main part of this while loop is the if condition: if word2[0] == firstLetter.upper() or word2[0] == firstLetter.lower() This statement checks if the first index of the word2 is equal to firstLetter. The word2 can contain a capital B or a small B so if condition checks both the cases by using upper and lower methods that converts the firstLetter to upper or lower and then match with the first letter of word2 i.e. the letter at index 0 of the word2. If this condition evaluates to true then next return statement returns the word1 and word2 in a list otherwise the second while loop keep asking user to enter the word2 with starting letter to be firstLetter i.e. 'B'.

The screenshot of the program and its output is attached.

The function for the given problem is:

These 10 lines of code were written using the Python programming language and this was used to define, store and hold the function and then request input from the user, check if the given input was according to the required parameters, and then print the output.

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Answer:

SQRRR or SQ3R is a reading comprehension method named for its five steps: survey, question, read, recite, and review. The method was introduced by Francis P. Robinson, an American education philosopher in his 1946 book Effective Study. The method offers a more efficient and active approach to reading textbook material

Answer:

nxlskshwhhwwlqlqoejebx znznxjslaa

Answer:

(B) It allows an attacker to redirect targets to malicious webserver.

(D) It affects any clients querying the poisoned DNS server.

Explanation:

DNS cache poisoning is a serious type of attack that is designed to exploit the vulnerabilities inherent in a Domain Name Server (DNS) where a user is redirected from a real server to a fake one. It is also called DNS spoofing.

Normally, when your browser tries to visits a website through a given domain name, it goes through the DNS server. A DNS server maintains a list of domain names and their equivalent Internet Protocol addresses. This server (DNS) then responds to the request with one or more IP addresses for the browser to reach the website through the domain name.

The computer browser then get to the intended website through the IP address.

Now, if the DNS cache is poisoned, then it has a wrong entry for IP addresses. This might be via hacking or a physical access to the DNS server to modify the stored information on it. Therefore, rather than responding with the real IP address, the DNS replies with a wrong IP address which then redirects the user to an unreal website.

Although they might not be able to control your computer remotely as long as you are not trying to visit a web page via the poisoned information, there are other dangers attached to this type of attack.

Once the DNS server has been poisoned, any client trying to query the server will also be affected since there is no direct way of knowing if the information received from the server is actually correct.

Answer:

for (var i = 0; i <20; i++)

{

var lineY = 20 + (i * 20);

line(0, lineY, 400, lineY);

}

Explanation:

To turn the loop while to for loop, you start by considering the iterating variable i and its iterating operations which are;

var i = 0; while (i < 20) and i++;

Where var i = 0; is the initializing statement

(i < 20) is the conditional statement

i++ is the increment

The next is to combine these operations to a for loop; using the following syntax: for(initializing; condition; increment){}

This gives: for(var i = 0; i<20; i++)

Hence, the full code snippet is:

for (var i = 0; i <20; i++)

{

var lineY = 20 + (i * 20);

line(0, lineY, 400, lineY);

}

Answer:

The answer is "\root"

Explanation:

Answer:

Parameter.

Explanation:

A parameter variable stores information which is passed from the location of the method call directly to the method that is called by the program.

Class or Variable parameter serve as a model for a family of classes or variables in functions' definitions.

For instance, they can serve as a model for a function; when used as an input, such as for passing a value to a function and when used as an output, such as for retrieving a value from the same function.

Hence, when you create classes or variables in a function, you can can set the values for their parameters.

For instance, to pass a class to a family of classes use the code;

\\parameter Name as Type (Keywords) = value;

\\procedure XorSwap (var a,b :integer) = "myvalue";

This question is incomplete because the options are missing; here are the options for this question:

Which of the following is the most effective way for Velma to save money each month?

A. Automatically reroute a portion of her paycheck to her savings account.

B. Manually deposit 10% of her paycheck in her savings account.

C. Pay all of her bills and then place the remaining money in her savings account.

D. Pay all of her bills and then place the remaining money in her piggy bank.

The correct answer to this question is A. Automatically reroute a portion of her paycheck to her savings account.

Explanation:

In this case, Velma needs to consistently save money for her vacation as this guarantees she will have the money for the trip. This means it is ideal every month she contributes consistently to her savings for the vacation.

This can be better be achieved by automatically rerouting a part of her paycheck for this purpose (Option A) because in this way, every month the money for the vacations will increase and the amount of money will be consistent, which means Velma will know beforehand the money she will have for the vacation. Moreover, options such as using a piggy bank or paying the bills and using the rest for her savings, do not guarantee she will contribute to the savings every month, or she will have the money she needs at the end.

Answer:

Decommission/Recycle

Explanation:

This specific scenario that is being described belongs to the final stage of the hardware lifecycle known as Decommission/Recycle. This is when the asset in question has completed its function for an extended period of time and is no longer functioning at maximum efficiency and/or newer hardware has hit the market. Once in this stage, the hardware in question is either repaired or scrapped for resources that can be used to create newer products.