12) If I have 72 liters of gas held at a pressure of 344.4 atm and a temperature of 225 K,
how many moles of gas do I have?

Answer:

41826.05 Calories

Explanation:

1 J = 0.239006 Calories

175 KJ

= 175 x 1000 J

= 175000 J

175000 J to Calories

= 175000 x 0.239006

= 41826.05 Calories

Answer: 41.8

Explanation:

Acellus verified ✅

The degree of proximity between a measured value and the actual value can be defined as Accuracy.

Precision is one that is used to know the level of uniformity present in a group of measurements that are repeated multiple times.

The Possible sources of error in the above experiment can be :

By conducting an experiment and comparing the outcome of the heat of reaction with the accepted value presented in a textbook or table, it is possible to compute the percentage of deviation. The percentage deviation can either be positive or negative and represents whether the experimentally obtained value is higher or lower than the accepted value, respectively.

Each mistake has the potential to result in an excessive or inadequate level of heat for the individual reaction. The  Insufficient execution of the procedure can impact the individual reaction's thermal energy.

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To determine the volume of O2 required to synthesize 11.0 mol of NO, we need to use the ideal gas law equation:

PV = nRT

Where:

P = Pressure (in this case, 760. mmHg)

V = Volume

n = Number of moles (11.0 mol of NO)

R = Ideal gas constant (0.0821 L·atm/(mol·K))

T = Temperature (27 ∘C = 27 + 273 = 300 K)

Rearranging the equation to solve for V:

V = (nRT) / P

Substituting the given values:

V = (11.0 mol) * (0.0821 L·atm/(mol·K)) * (300 K) / (760. mmHg)

Note that we need to convert the pressure from mmHg to atm:

1 atm = 760 mmHg

V = (11.0 mol) * (0.0821 L·atm/(mol·K)) * (300 K) / (760/760)

Simplifying the equation:

V = 3.44 L

Therefore, the volume of O2 required to synthesize 11.0 mol of NO at 760. mmHg and 27 ∘C is 3.44 L.

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If one has an unknown quantity of gas at a pressure of 121.6 mmHg, a volume of 45 L, and a temperature of 87 °C, then that person has approximately 1.93 moles of gas.

To find the number of moles of gas

PV = nRT

where: P = pressure V = volume, n = number of moles R = the gas constant T = temperature.

One needs to rearrange this equation to solve for n:

n = PV/RT

where R is the gas constant, which has a value of 0.08206 L•atm/mol•K.

121.6 mmHg = 0.160 atm

87 °C = 360 K

n = (0.160 atm)(45 L) / (0.08206 L•atm/mol•K)(360 K)

n = 1.93 mol

Therefore, one has approximately 1.93 moles of gas.

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It's never a good idea to use your credit card when experiencing strong emotions, especially if you tend to steer toward 'retail therapy.

Answer: 2.31 L

Explanation:

charles law  v2= V1 x T2/T1

temperature must be in Kelvin

V2=2.5 X 298.15 / 323.15 =2.31 L

We need 0.798 g of copper (ll) sulfate and 0.400 g of sodium hydroxide to make a 50.0 mL of a 0.100 M solution of each reactant.

To determine the amount of solute needed to make a 50.0 mL of a 0.100 M solution of each reactant when using copper (ll) sulfate and sodium hydroxide, we need to use the formula:

Molarity (M) = moles of solute ÷ volume of solution (in liters)

First, we need to calculate the number of moles of solute needed. Since the molar ratio of copper (ll) sulfate to sodium hydroxide is 1:2, we will need twice as many moles of sodium hydroxide as copper (ll) sulfate.

Let's start with copper (ll) sulfate:

Molarity (CuSO4) = 0.100 M

Volume (V) = 50.0 mL = 0.0500 L

Using the formula, we can rearrange it to solve for moles of solute:

moles of CuSO4 = Molarity × Volume

moles of CuSO4 = 0.100 M × 0.0500 L

moles of CuSO4 = 0.00500 mol

Next, we can calculate the number of moles of sodium hydroxide needed:

moles of NaOH = 2 × moles of CuSO4

moles of NaOH = 2 × 0.00500 mol

moles of NaOH = 0.0100 mol

Now that we know the number of moles of each solute needed, we can calculate the mass of each solute needed using their respective molar masses:

mass of CuSO4 = moles of CuSO4 × molar mass of CuSO4

mass of CuSO4 = 0.00500 mol × 159.61 g/mol

mass of CuSO4 = 0.798 g

mass of NaOH = moles of NaOH × molar mass of NaOH

mass of NaOH = 0.0100 mol × 40.00 g/mol

mass of NaOH = 0.400 g

Therefore, we need 0.798 g of copper (ll) sulfate and 0.400 g of sodium hydroxide to make a 50.0 mL of a 0.100 M solution of each reactant.

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In 0.8291 moles of hexane ([tex]C_6H_1_4[/tex]) there are 20.8 liters in 0.8291 moles of hexane at room temperature and atmospheric pressure.

To determine the number of liters in 0.8291 moles of hexane (C6H14), we need to use the ideal gas law equation:

PV = nRT

where:

P = pressure (atm)

V = volume (L)

n = moles of gas

R = gas constant (0.0821 L*atm/mol*K)

T = temperature (K)

We need to rearrange this equation to solve for V:

V = nRT/P

First, we need to calculate the number of moles of hexane:

n = mass/molar mass

The molar mass of hexane (C6H14) is:

6(12.01 g/mol) + 14(1.01 g/mol) = 86.18 g/mol

n = 0.8291 moles

Next, we need to convert the temperature to Kelvin. Assuming room temperature (25°C or 298 K):

T = 298 K

Finally, we need to assume a pressure value. Let's assume atmospheric pressure (1 atm).

P = 1 atm

Now we can plug in the values and solve for V:

V = (0.8291 mol)(0.0821 L*atm/mol*K)(298 K)/(1 atm)

V = 20.8 L

Therefore, there are 20.8 liters in 0.8291 moles of hexane at room temperature and atmospheric pressure.

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Based on the given information, we can conclude that substance X and substance Y are solids and did not filter through the filter paper into the flask. Option D

Substance Z, on the other hand, is a liquid that passed through the filter paper and collected in the flask.

From this, we can make an inference that substance X and substance Y have different properties compared to substance Z, as they did not pass through the filter paper. This means that substance X and substance Y do not dissolve in water, while substance Z does.

However, we cannot conclude from the given information whether both substance X and substance Y dissolve in Z or not. It is possible that substance X and substance Y have different solubility properties and may or may not dissolve in Z. Therefore, we cannot choose option A or option D.

Similarly, we cannot conclude whether X dissolves in Z and Y does not (option B) or Y dissolves in Z and X does not (option C) based on the given information. Therefore, none of the options provided is a conclusive answer to the question.

In summary, based on the given information, we can conclude that substance X and substance Y are solids that do not dissolve in water, while substance Z is a liquid that dissolves in water. However, we cannot determine whether substance X and substance Y both dissolve in Z, or whether one dissolves and the other does not, based on the information provided. Option D

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The chemical structure of the compound is shown in the image attached.

Ascertain the molecule's atomic composition and the types of bonds (covalent, ionic, etc.) that each atom forms.

The skeletal structure, which is a straightforward illustration of the molecule's framework, should be drawn first. To do this, a series of lines are drawn to symbolize the atoms' bonds.

By positioning the atoms at the ends of the bond lines, you may complete the skeleton framework.

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Gene copies that are different versions of a trait are called alleles. Understanding alleles and their inheritance patterns is crucial in genetics and is the foundation of the principles of Mendelian inheritance.

An allele is a specific form of a gene that is responsible for a particular trait or characteristic. For example, the gene for eye color may have different alleles such as brown, blue, green, or gray. Each allele controls the expression of the eye color trait differently, resulting in different eye colors in individuals.

Alleles can be dominant or recessive, with dominant alleles expressing their trait even if only one copy is present, while recessive alleles require two copies to express the trait. In addition, individuals can have different combinations of alleles, which can result in variations in traits within a population.

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The volume (in liters) of oxygen gas, O₂ that will be needed for the above reaction at STP is 35 liters (option A)

The volume of oxygen gas needed for the reaction can be obtain as shown below:

Balanced equation:

2C₂H₆(g) + 7O₂(g) —> 4CO₂(g) + 6H₂O(g)

From the question given above, we were told that the reaction occur at standard temperature and pressure, STP. Thus we can obtain the volume of oxygen needed as follow::

2 liters of C₂H₂ reacted with 7 liters of O₂

Therefore

10 liters of C₂H₂ will react = (10 liters × 7 liters) / 2 liters = 35 liters of O₂

Thus, we can conclude that the volume of oxygen gas needed for the reaction is 35 liters (option A)

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The concept molarity is an important method which is used to calculate the concentration of a solution. It is mainly employed to find out the concentration of a binary solution. Here the molarity is 0.67 M. The correct option is D.

The molarity of a solution is defined as the number of moles of the solute dissolved per liter of the solution. It is represented by the letter 'M' and it is expressed in the unit mol / L.

Molarity = Number of moles of solute  / Volume of solution in liters

M = 0.500 / 0.75 = 0.66 mol / L ≈ 0.67 M

Thus the correct option is D.

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The element with atom or ion can be filled as

B        neutral atom          5 proton             5 electron

[tex]Mg^{2+}[/tex]       cation                12 proton                10 electron

[tex]Ge^-[/tex]           anion                32 proton               33 electron

Because they have an equal amount of protons and electrons, atoms are neutral particles. Ions are electrically charged particles that may be created by either taking electrons away from neutral atoms to form positive ions or adding electrons to neutral atoms to produce negative ions. The quantity of protons remains constant during the formation of an ion. By taking out one or more electrons, neutral atoms can be transformed into positively charged ions.

B        neutral atom          5 proton             5 electron

[tex]Mg^{2+}[/tex]       cation               12 proton                10 electron

[tex]Ge^-[/tex]           anion                32 proton               33 electron

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Answer:

Rubidium (Rb)

Explanation:

Sb: 206pm

As: 185pm

Rb: 303pm

Ba: 268pm

The mass of copper produced is 0.48 g.

From the balanced equation, we can see that 2 moles of NH3 produce 1 mole of N2. Therefore, the number of moles of N2 produced from 0.12 dm³ (120 cm³) of N2 gas at RTP can be calculated as:

n(N2) = (volume of gas at RTP) / (molar volume at RTP)

n(N2) = (120 cm³) / (24 dm³/mol)

n(N2) = 0.005 mol

According to the balanced equation, 3 moles of Cu is produced for every 2 moles of NH3. Therefore, the number of moles of Cu produced can be calculated as:

n(Cu) = (3/2) * n(N2)

n(Cu) = (3/2) * 0.005 mol

n(Cu) = 0.0075 mol

The molar mass of Cu is 64 g/mol. Therefore, the mass of copper produced can be calculated as:

mass(Cu) = n(Cu) * M(Cu)

mass(Cu) = 0.0075 mol * 64 g/mol

mass(Cu) = 0.48 g

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The molecular formula mass ratio is approximately 1.48, the molecular formula of the compound is approximately N₁O₂.

To determine the molecular formula of the compound, we need to follow a series of steps. First, we calculate the moles of nitrogen (N) and oxygen (O) in the given mass percentage composition.

Assuming we have 100 g of the compound, we would have:

30.45 g of N

69.55 g of O

Next, we calculate the number of moles of each element using their respective molar masses:

Moles of N = 30.45 g / 14.01 g/mol ≈ 2.18 mol

Moles of O = 69.55 g / 16.00 g/mol ≈ 4.35 mol

We then divide the number of moles by the smallest number of moles (in this case, N) to obtain a simple ratio:

N ≈ 2.18 mol / 2.18 mol = 1

O ≈ 4.35 mol / 2.18 mol ≈ 2

This gives us the empirical formula, which is N₁O₂.

Finally, to determine the molecular formula, we need to find the ratio of the empirical formula's molar mass to the experimental molar mass provided. We calculate:

Empirical formula mass of N₁O₂ = 14.01 g/mol + (2 × 16.00 g/mol) = 46.01 g/mol

Experimental molar mass = 1.63 g / (389 mL × 0.00°C / 22.4 L/mol × 0.775) = 68.34 g/mol

Dividing the experimental molar mass by the empirical formula mass:

Molecular formula mass ratio = 68.34 g/mol / 46.01 g/mol ≈ 1.48

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Answer:

22°C + 14.82°C = 36.82°C

Explanation:

We can use the formula:

q = mCΔT

where q is the heat absorbed by the water, m is the mass of the water, C is the specific heat of water, and ΔT is the temperature change of the water.

We are given q = 12,357 J, m = 234.2 g, and an initial temperature of 22C. The specific heat of water is 4.184 J/(g·°C).

Plugging in the numbers, we get:

12,357 J = (234.2 g)(4.184 J/(g·°C))(ΔT)

Solving for ΔT, we get:

ΔT = 14.82°C

Therefore, the final temperature of the water would be:

22°C + 14.82°C = 36.82°C

The final volume when 0.694 L of a 36.2% (m/v) solution is diluted to 20.3% (m/v) is approximately 1236 mL.

To calculate the final volume in milliliters when a solution is diluted, we can use the formula:

(V1)(C1) = (V2)(C2),

where V1 is the initial volume, C1 is the initial concentration, V2 is the final volume, and C2 is the final concentration.

In this case, we have:

V1 = 0.694 L (initial volume)

C1 = 36.2% (m/v) (initial concentration)

C2 = 20.3% (m/v) (final concentration)

We need to solve for V2, the final volume.

Using the formula, we can rearrange it to solve for V2:

V2 = (V1)(C1) / C2

Substituting the given values:

V2 = (0.694 L)(36.2% (m/v)) / 20.3% (m/v)

Calculating this expression, we find:

V2 = (0.694 L)(0.362) / 0.203

V2 = 1.23628 L

Since the question asks for the final volume in milliliters, we convert the result to milliliters by multiplying by 1000:

V2 = 1.23628 L × 1000 mL/L

V2 ≈ 1236 mL

Therefore, the final volume when 0.694 L of a 36.2% (m/v) solution is diluted to 20.3% (m/v) is approximately 1236 mL.

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Answer:

approx 7.41 sextillion

Explanation:

One mole of any substance contains 6.022 x 10^23 particles (Avogadro's Number). Therefore, 1 mole of water contains 6.022 x 10^23 water molecules.

To find how many moles are represented by 7.43 x 10^18 molecules of water, we can divide 7.43 x 10^18 by Avogadro's Number:

7.43 x 10^18 / 6.022 x 10^23 = 0.0123 moles of water

Now, we can use this to find the number of water molecules:

0.0123 moles x 6.022 x 10^23 molecules/mole = 7.41 x 10^21 molecules of water

Therefore, 7.43 x 10^18 molecules of water represent 7.41 x 10^21 molecules or approximately 7.41 sextillion (7,410,000,000,000,000,000) molecules of water.

:Response: 2.21 atm The ideal gas law says that the pressure of a gas is equal to the quantity of the gas times the universal gas constant (R) times the temperature (T) times the volume (V) divided by the number of moles in the gas.

Consequently, we may apply the following equation to this issue: P = (n*R*T)/V. We may get the pressure of the gas in atmospheres by using the following formula, where n is the number of moles, V is the volume, T is the temperature, and R is the universal gas constant.

P is equal to 2.21 atm or (3.43 mol*0.0821 L*atm/mol*K*492.15 K)/27.17 L. As a result, choice A) 2.21 atm is the right one.

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11. The concentration of C is 200

12. The concentration of B is 0.4

Equilibrium constant, K is defined as follow:

nReactant ⇌ mProduct

Equilibrium constant, K = [Product]ᵐ / [Reactant]ⁿ

With the above formula, we can obtain the equilibrium concentration of the missing substance as follow:

11. For concentration of C

K = [C] / [A][B]

20 = [C] / (2 × 5)

20 = [C] / 10

Cross multiply

[C] = 20 × 10

Concentration of C, [C] = 200

12. For concentration of B

K = [C] / [B]

10 = 4/ [B]

Cross multiply

10 × [B] = 4

Divide both sides by 10

[B] = 4 / 10

Concentration of B, [B] = 0.4

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Complete question:

Find the concentration of the missing substance

11) A + B = C

K = 20

[A] = 2

[B] = 5

[C] =?

12) A(s) + B(ag) = C(g)

K = 10

[C] = 4

[B] = ?

Answer:

high tides are a little higher and low tides are a little lower than average

Explanation:

A spring tide is the highest tide (when the greatest difference between the high and low tides). This happens during the new and full moon.

Answer: It's worth noting that low tides can sometimes be lower than usual, which is referred to as spring tides. Despite its name, this phenomenon isn't related to spring and has a different historical origin.

The order of a reaction is determined experimentally and describes the relationship between the rate of a reaction and the concentration of reactants, whereas the molecularity of a reaction is a theoretical concept that describes the number of molecules that participate in the rate-determining step of a reaction.

The order of a reaction is the mathematical representation of the relationship between the rate of a reaction and the concentration of reactants. It describes how the rate of a reaction changes with respect to the change in concentration of reactants.

The order of a reaction is determined experimentally by observing how the rate of a reaction changes as the concentration of reactants is varied while keeping the concentration of other reactants and conditions constant. The order of a reaction can be 0, 1, 2, or even a fraction.

The molecularity of a reaction ​is the number of reactant molecules that collide in a single step to form the product. The molecularity of a reaction can be unimolecular (1), bimolecular (2), or termolecular (3). It is important to note that not all reactions have a molecularity, as some reactions have multiple steps and multiple reactants involved.

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Use the following formula to obtain the ascorbic acid content in milligrams of a vitamin C tablet:

Mass of ascorbic acid (mg) = Volume of NaOH (mL) x Concentration of NaOH (mol/L) x Molar mass of ascorbic acid (g/mol) x 1000 / 1

We must first determine the molar mass of ascorbic acid:

Molar mass of ascorbic acid = (6 x atomic mass of carbon) + (8 x atomic mass of hydrogen) + (6 x atomic mass of oxygen)

= (6 x 12.01) + (8 x 1.01) + (6 x 16.00)

= 176.12 g/mol

Now we can substitute the values ​​in the formula into:

Mass of ascorbic acid (mg) = 20.74 mL x 0.201 mol/L x 176.12 g/mol x 1000 / 1

= 739.1 mg

Therefore, the amount of ascorbic acid in the Vitamin C tablet is 739.1 mg.

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Your question is incomplete, most probably the complete question is:

A vitamin C (ascorbic acid) tablet was dissolved in approximately 50 mL of distilled water and titrated with the standardized NaOH solution. From the results of this titration, the mg of ascorbic acid in the tablet was calculated. Molecular formula of ascorbic acid: C6H8O6 Volume of NaOH required to neutralize ascorbic acid in Vitamin C tablet (mL) 20.74 Concentration of NaOH in mol/L, 0.201 Calculate the amount of ascorbic acid in the Vitamin C tablet in (mg).

The chemical equation for the reaction between HNO₃ and NH₃ is:

HNO₃ + NH₃ → NH₄NO₃

Acids: HNO₃

Bases: NH₃

Other: NH₄NO₃ (this is a salt formed by the neutralization of the acid and base)

The given chemical equation shows the reaction between nitric acid (HNO₃) and ammonia (NH₃) which results in the formation of ammonium nitrate (NH₄NO₃), a salt. In this reaction, HNO₃ acts as an acid as it donates a proton (H⁺) to the NH₃ molecule. NH₃, on the other hand, acts as a base, accepting the proton donated by HNO₃.

The protonated form of ammonia is called ammonium ion (NH₄⁺) and it is combined with the nitrate ion (NO₃⁻) to form the salt NH₄NO₃.

Therefore, the major species present at equilibrium in the solution are the acid HNO₃, the base NH₃ and the salt NH₄NO₃. HNO₃ and NH₃ are the main reactants and they act as the acid and base, respectively.

The salt NH₄NO₃ is formed as a result of neutralization between HNO₃ and NH₃ and it does not act as an acid or a base in the solution. It is important to note that NH₃ is a weak base, which means that it does not fully dissociate in water and therefore only a portion of the NH₃ molecules accept protons from HNO₃.

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Answer:

Explanation:

VSEPr Gives you the structures of molecules

A

Explanation:

For dissolving dry mortar on floor tiles, you can use concrete and mortar dissolver. You can find this product at your local hardware store or online12.

For removing KMnO stains, you can use vinegar. Mix vinegar with water and spray or pour it on the tile surface. Let the vinegar water set in for a few minutes, then sponge the entire area to get it as clean as possible. Next, use a razor blade or scraper to peel up the mortar. Be careful not to gouge or scratch the tiles3.

KMnO is potassium permanganate. it makes water drinkable if it's polluted

For drying acid anhydrides, you can use calcium chloride. Calcium chloride is a hygroscopic substance that absorbs moisture from the air and can be used as a desiccant.

desiccants keeps things dry so they last longer like food & clothes

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