According to the question 2.46 moles of HCl are required to react with 0.62 moles of Al.
What is moles?Moles are small mammals that are known for their burrowing habits and dark brown or black fur. They are members of the family Talpidae and are found in most parts of the world. Moles have cylindrical bodies, long pointed snouts, and short, velvety fur.
The equation for the reaction of aluminum and hydrochloric acid is:
2Al + 6HCl → 2AlCl₃ + 3H₂
Therefore, the number of moles of HCl required to react with 0.62 moles of Al can be calculated using the following equation:
Moles HCl = (0.62 moles Al x 6 moles HCl)/2 moles Al
Moles HCl = 2.46 moles HCl
Therefore, 2.46 moles of HCl are required to react with 0.62 moles of Al.
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Using the thermodynamic information in the ALEKS Data tab, calculate the standard reaction free energy of the following chemical reaction 2NH3 =N2H4 +H2
The reaction [tex]2NH_3=N_2H_4+H_2[/tex] has a standard reaction free energy of -62.4 kJ/mol.
What is energy?Energy is the capacity to carry out tasks or affect change. It comes in a variety of shapes and sizes, including kinetic energy (energy of motion), potential energy (stored energy of position), thermal energy (heat), electrical, chemical, and nuclear energy. Energy is required for the survival and growth of all living things. Additionally, it is necessary for the operation of industries and equipment.
Equation can be used to get a reaction's standard reaction free energy.
ΔG°rxn = ΣΔG°f (products) - ΣΔG°f (reactants).
For the reaction [tex]2NH_3=N_2H_4+H_2[/tex], the ΔG°f values are as follows:
ΔG°f ([tex]2NH_3[/tex]) = -46.2 kJ/mol
ΔG°f ([tex]N_2H_4[/tex]) = -20.8 kJ/mol
ΔG°f ([tex]H_2[/tex]) = 0 kJ/mo
The equation yields the average reaction free energy (ΔG°rxn) of the reaction is:
ΔG°rxn = (2 x -20.8) - (-46.2)
= -62.4 kJ/mol
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Help please! I'll give brainliest as well if you show work/explain :)
Explanation: the answer is 3840 because 2950+890=3840
What volume does 0.20 g methane gas (CH4) occupy at 312 K and 2.00 atm?
• Your answer should include two significant figures (round your answer to two decimal places).
0.20 g of methane gas at 312 K and 2.00 atm occupies a volume of 0.13 L (rounded to two significant figures).
What is volume?
To solve this problem, we can use the ideal gas law, which relates the pressure, volume, temperature, and number of moles of a gas:
PV = nRT
where P is the pressure in atmospheres (atm), V is the volume in liters (L), n is the number of moles of gas, R is the gas constant (0.0821 L·atm/mol·K), and T is the temperature in Kelvin (K).
First, we need to calculate the number of moles of methane gas:
n = m/MW
where m is the mass of the gas (0.20 g) and MW is the molecular weight of methane (16.04 g/mol).
n = 0.20 g / 16.04 g/mol = 0.0125 mol
Next, we can rearrange the ideal gas law to solve for the volume:
V = nRT/P
Plugging in the values we have:
V = (0.0125 mol)(0.0821 L·atm/mol·K)(312 K)/(2.00 atm)
V = 0.128 L
Therefore, 0.20 g of methane gas at 312 K and 2.00 atm occupies a volume of 0.13 L (rounded to two significant figures).
What is molecular weight ?
Molecular weight, also known as molecular mass, is the mass of a molecule, which is the sum of the masses of all the atoms in the molecule. It is typically expressed in atomic mass units (amu) or in grams per mole (g/mol). The molecular weight is an important property of a substance in chemistry, as it is used to calculate various properties such as the molar mass, molar volume, and stoichiometric relationships in chemical reactions.
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Complete question is: 0.13 L volume does 0.20 g methane gas (CH4) occupy at 312 K and 2.00 atm.
if only 11.00g SnF2 were produced calculate percent yield
A. The mass (in grams) of SnF₂ that can be produced theoretically from the reaction is 13.20 g
B. The percentage yield of the reaction is 83.3%
A. How do i determine the mass produced theoretically?The mass of SnF₂ produced theorethically, can be obtained as shown below:
Sn + 2HF -> SnF₂ + H₂
Molar mass of Sn = 118.71 g/molMass of Sn from the balanced equation = 1 × 118.71 = 118.71 g Molar mass of SnF₂ = 156.71 g/molMass of SnF₂ from the balanced equation = 1 × 156.71 = 156.71 gFrom the balanced equation above,
118.71 g of Sn reacted to produce 156.71 g of SnF₂
Therefore,
10 g of Sn will react to produce = (10 × 156.71) / 118.71 = 13.20 g of SnF₂
Thus, the mass of SnF₂ produced is 13.20 g
B. How do i determine the percentage yield?The percentage yield for the reaction can be obtained as follow:
Actual yield of SnF₂ = 11 gTheoretical yield of SnF₂ = 13.20 gPercentage yield of SnF₂ =?Percentage yield = (Actual /Theoretical) × 100
Percentage yield of SnF₂ = (11 / 13.20) × 100
Percentage yield of SnF₂ = 83.3%
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Complete question:
See attached photo
sample of gas in a balloon has an initial temperature of 42 ∘C
and a volume of 1.47×103 L
. If the temperature changes to 94 ∘C
, and there is no change of pressure or amount of gas, what is the new volume, V2
, of the gas?
The new volume [tex]V_{2}[/tex]) of the gas is approximately 1710 L when the temperature changes from 42 ∘C to 94 ∘C, assuming no change in pressure or amount of gas.
What is Temperature?
Temperature is a measure of the average kinetic energy of the particles in a substance, such as a gas, liquid, or solid. It is commonly measured in Celsius (°C), Fahrenheit (°F), or Kelvin (K) scales. Temperature determines the direction of heat transfer, which is the movement of energy between substances due to a temperature difference.
To use the ideal gas law, we need to convert the temperatures to Kelvin by adding 273.15 to each:
[tex]T_{1}[/tex] = 42 + 273.15 = 315.15 K
[tex]T_{2}[/tex]= 94 + 273.15 = 367.15 K
Since the pressure, amount of gas, and ideal gas constant remain constant in this problem, we can set up the following ratio:
([tex]V_{1}[/tex] / [tex]T_{1}[/tex]) = ([tex]V_{2}[/tex]/ [tex]T_{2}[/tex])
Plugging in the values:
(1.47 ×[tex]10^{3}[/tex]L / 315.15 K) = ([tex]V_{2}[/tex] / 367.15 K)
Now we can solve for [tex]V_{2}[/tex]:
[tex]V_{2}[/tex] = 1.47×[tex]10^{3}[/tex] L * 367.15 K / 315.15 K
[tex]V_{2}[/tex]≈ 1710 L (rounded to three significant figures)
Therefore, the new volume (V2) of the gas is approximately 1710 L when the temperature changes from 42 ∘C to 94 ∘C, assuming no change in pressure or amount of gas.
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Calculate the standard change in Gibbs free energy for the reaction at 25 °C. Refer to the ΔG°f values.
Fe2O3(s)+2Al(s)⟶Al2O3(s)+2Fe(s)
Δ°rxn=
The standard change in Gibbs free energy for the given reaction at 25°C is -757.9 kJ/mol.
Describe Gibbs Energy.Gibbs energy, also known as Gibbs free energy, is a thermodynamic quantity used to determine the maximum amount of work that can be obtained from a system at a constant temperature and pressure. It is denoted by the symbol G and is named after the American physicist Josiah Willard Gibbs who introduced the concept in the late 19th century.
Gibbs energy is defined as the difference between the enthalpy of a system and the product of the temperature and the entropy of the system:
G = H - TS
where H is the enthalpy, T is the temperature in Kelvin, and S is the entropy of the system.
The Gibbs energy is related to the equilibrium constant of a reaction through the following equation:
ΔG = -RTlnK
To calculate the standard change in Gibbs free energy for the given reaction at 25°C, we need to use the ΔG°f values (standard Gibbs free energy of formation) for the reactants and products involved in the reaction.
The ΔG°f values for Fe₂O₃(s), Al(s), Al₂O₃(s), and Fe(s) can be found in a table of thermodynamic data and are:
ΔG°f [Fe₂O₃(s)] = -824.2 kJ/mol
ΔG°f [Al(s)] = 0 kJ/mol
ΔG°f [Al₂O₃(s)] = -1582.3 kJ/mol
ΔG°f [Fe(s)] = 0 kJ/mol
The standard change in Gibbs free energy for the reaction can be calculated using the following equation:
Δ°rxn = ΣΔG°f(products) - ΣΔG°f(reactants)
Substituting the values, we get:
Δ°rxn = [ΔG°f(Al₂O₃(s)) + 2ΔG°f(Fe(s))] - [ΔG°f(Fe₂O₃(s)) + 2ΔG°f(Al(s))]
Δ°rxn = [(-1582.3 kJ/mol) + 2(0 kJ/mol)] - [(-824.2 kJ/mol) + 2(0 kJ/mol)]
Δ°rxn = -757.9 kJ/mol
Therefore, the standard change in Gibbs free energy for the given reaction at 25°C is -757.9 kJ/mol.
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The combustion of ethane (C2H6) produces CO2 and H2O:
2C2H6 (g) + 7O2 (g) → 4CO2 (g) + 6H2O (g)
How many moles of O2 are needed to react with 15.5 g of ethane?
When 3 g of a petroleum are burned with more oxygen than is required, 8.8 g of Atmospheric carbon dioxide plus 5.4 g liquid [tex]H_{2}O[/tex] are produced.
What happens when ethane gas ([tex]C_{2}H_6}[/tex]) and oxygen gas ([tex]O_{2}[/tex]) burn together?
Oxygen gas and ethane ([tex]C_{2}H_6}[/tex]) react to create water as well as carbon dioxide. Find the total quantity of carbon dioxide created when the reaction yield is 60% when 5 mol of methane is burned and 16 mol of oxygen initially. 2[tex]C_{2}H_4}[/tex]+7[tex]O_{2}[/tex] →4[tex]CO_{2}[/tex]+6[tex]H_{2}O.[/tex]
How many tumours of CO2 are created when 2.2 blackheads of [tex]C_{2}H_4}[/tex]are burned?
As a result, 2 m of carbon dioxide is generated from mole of a substance of [tex]C_{2}H_4} .[/tex] Thus, multiply 2.2 over 2 by 1 pot to get 2.2 moles for c into h or just a cross. It consists of 4.4 moles of carbon.
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Lattice energy is an estimate of the bond
Answer:
strength in ionic compounds.
Explanation:
:)
Lattice energy is an estimate of the bond of strength. It denotes the amount of energy required to break down one mole of a solid ionic compound into its constituent gaseous ions.
What does the lattice energy represent?The strength of an ionic compound's ionic bonds is measured by lattice energy. It explains several properties of ionic solids, including their volatility, solubility, and hardness. An ionic solid's lattice energy cannot be measured directly.
How does lattice energy influence ionic compound solubility in water?The higher an ionic compound's lattice energy, the more difficult it is to disassemble the crystal lattice structure and dissolve it in water. As a result, compounds with high lattice energies are less soluble in water than those with low lattice energies.
What factors influence lattice energy?The value of lattice energy is determined by the charges on the two ions as well as the distance between them. The distance between the ions is directly proportional to their size.
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Complete question:
Lattice energy is an estimated bond of the bond:
A. conductivity
B. group
C. length
D. strength
Choose the correct option.
what is the compound formed between two or more non metal element that share electron
A compound formed between two or more non-metal elements that share electrons is called a covalent compound or a molecular compound.
In covalent compounds, the atoms share electrons in order to achieve a full outer shell of electrons and become more stable. Covalent compounds typically have low melting and boiling points, are often gases or liquids at room temperature, and are poor conductors of electricity. Examples of covalent compounds include water (H2O), carbon dioxide (CO2), and methane [CH4].
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Question 4 of 10
Based on information from the periodic table, what does this image
represent?
= 9 Protons
= 10 Neutrons
= 10 Electrons
A.Neutral fluorine
B. A positively charged fluoride ion
C. A negatively charged fluoride ion
D. A neutral neon atom
How can you evaluate how well a transportation system meets the needs of a community?
four score and seven years ago (our father) brought this continent, a new nation,
answer our fathersA 1.5 L sample of a 0.44 M H Br solution is mixed with 2.2 L of a 0.080 M HCIO4 solution. What is the pH of the mixture?
Given:
2KI → 2K + I2
Calculate the number of moles of iodine produced in the decomposition of 7.0 moles of potassium iodide (KI). Express your answer to the correct number of significant figures.
Since 2 moles of KI produce 1 mole of I2, then 7.0 moles of KI will produce 7.0/2 moles of I2. In other words, 3.5 moles of I2 will be produced
what volume of SO3 would be produced by complete reaction of 100cm3 of HO2 with O2?
The volume of [tex]SO_{3}[/tex] would be produced by complete reaction of 100cm3 of [tex]H_{2}O[/tex]with [tex]O_{2}[/tex] is at STP is 60.03L.
Volume22.4 L divided by 2.68 moles per mole yields 60.03 L [tex]SO_{3}[/tex].
describing the elements contributing to the response,
[tex]2SO_{2(g)}+ O_{2} = 2SO_{3}[/tex]
In this instance, [tex]SO_{3}[/tex] and [tex]O_{2}[/tex] have a mole ratio of 2:1. Assume the reaction takes place at STP, where 1 mole of any gas has a volume of 22.4 L. Consequently, 30 [tex]dm^{3}[/tex]of [tex]O_{2}[/tex] (1 dm3 = 1 L) equals 30 L of [tex]O_{2}[/tex] and 30 L/22.4 L times 1 mole equals 1.34 moles of [tex]O_{2}[/tex].
According to stoichiometry, when 1.34 moles of [tex]O_{2}[/tex]are reacted with [tex]SO_{2}[/tex], 2.68 moles of [tex]SO_{3}[/tex] are created, or 2/1 x 1.34 moles of [tex]SO_{3}[/tex].
This means that the amount of [tex]SO_{3}[/tex]produced will be (2.68 moles/1 mole) x 22.4 L = 60.03 L [tex]SO_{3}[/tex].
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A 2.6 mol sample of N2 is held in a 4191 mL balloon at 89.9 atm. What temperature (in Celcius) is the gas at? Answer to one decimal place.
Answer: the temperature of the gas is approximately 16.1°C.
Explanation: PV=nRT Rearranging the equation gives us T = PV/(nR), with all variables defined as before. Convert mL to L: V = 4191 mL = 4.191 L. Use equation: T = (89.9 atm) x (4.191 L) / (2.6 mol x 0.08206 L atm/(mol K)). Simplify to get T = 289.2 K. Convert Kelvin to Celsius: T = 289.2 K - 273.15 = 16.1°C.
the rate constant for a specific reaction has been determined at the following temps. 82 C, k= 3.97x10^-3 M^-1 x s^-1 , 125 C, k= 2.07x10^-2 ,M^-1 x s^-1. a) calculate the activation energy for the reaction
b) If data points were plotted in Arrhenius plot, what would the slope of the line be?
c) at what temp will the rate constant have k=1.00x10^-3 M^-1 x s^-1
A) the activation energy is = 66.5 kJ/mol
B) the slope of the line in this case would be -8000 K^-1
C) the temperature at which the rate constant is 1.00x10^-3 M^-1 x s^-1 is 408 K (135°C).
The activation energy, slope and temperaturea) To calculate the activation energy, we can use the Arrhenius equation:
k = Ae^(-Ea/RT)
where k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant (8.314 J/mol x K), and T is the temperature in Kelvin.
Taking the natural logarithm of both sides of the equation, we get:
ln(k) = ln(A) - (Ea/RT)
We can use the two sets of data to set up two equations:
ln(k1) = ln(A) - (Ea/RT1)
ln(k2) = ln(A) - (Ea/RT2)
Solving for Ea by taking the difference between the two equations:
ln(k2/k1) = (Ea/R) [(1/T1) - (1/T2)]
Ea = -R ln(k2/k1) / [(1/T1) - (1/T2)]
Plugging in the values:
Ea = -8.314 J/mol x K x ln(2.07x10^-2 / 3.97x10^-3) / [(1/398 K) - (1/398 K)]
Ea = 66.5 kJ/mol
b) In an Arrhenius plot, ln(k) is plotted against 1/T, and the slope of the line is equal to -Ea/R. Therefore, the slope of the line in this case would be:
slope = -Ea/R = -(66.5 x 10^3 J/mol) / (8.314 J/mol x K) = -8000 K^-1
c) To solve for the temperature at which the rate constant is 1.00x10^-3 M^-1 x s^-1, we can rearrange the Arrhenius equation:
k = Ae^(-Ea/RT)
ln(k) = ln(A) - (Ea/RT)
1/T = (ln(k) - ln(A)) / (-Ea/R)
T = -R / (Ea ln(k) - ln(A))
Plugging in the values:
T = -8.314 J/mol x K / [(66.5 x 10^3 J/mol) ln(1.00x10^-3) - ln(3.97x10^-3)]
T = 408 K
Therefore, the temperature at which the rate constant is 1.00x10^-3 M^-1 x s^-1 is 408 K (135°C).
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48 grams of MgCl2 is dissolved in 500g of water, DENSITY OF
WATER = 1 kg/1L. What is the MOLALITY of this solution? Please
show your steps.
mol
kg
m =
or
m = mol = kg
Step1: given information:
solute=
(UNIT=
Solvent =
(UNIT =
)
)
The molality of the solution is 1.080 mol/kg of a 48 grams of MgCl2 is dissolved in 500g of water, density of water = 1 kg/1L.
How to calculate molality?Taking the moles of solute and dividing it by the kilograms of solvent yields the molality of a solution.
Molality is calculated as follows: kg of solvent/kg of solute
500 g, or 0.500 kg, is the mass of the solvent.
MgCl2 molecular weight divided by its mass gives the amount of moles.
48 g / 95.2 g m o l 1 equals the quantity of moles of magnesium chloride.
0.504 moles of MgCl2 are present in one mole.
Molality is calculated as 0.504moles per kilogram.
Molality is equal to 1.080 mol k g 1.
As stated in the definition, molality is the "total moles of a solute contained in a kilogram of a solvent." The terms "molality" and "molal concentration" are synonymous. It is a measurement of a solvent.
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Which of these pairs of atoms would experience a polar covalent bond?
Cl and Cl
K and Br
P and S
C and O
C and O since their electronegativity differs by quite a lot
what is a type of atom that can be bonded with water and hydrogen
Answer: Oxygen (??)
Explanation: Im not sure but smth like H2O (my brain is not braining T-T)
The two possible units of molarity are
Answer: The units for molarity are moles/liter.
Similarly, the equation to find molarity is moles divided by liters.
Explanation:
mol / L is a unit of molar concentration. These are the number of moles of dissolved material per liter of solution. 1 mol / L is also called 1M or 1molar. Mol / m3 is also a unit of molar concentration.
Molarity is expressed in units of moles per liter (mol / L). This is a very common unit, so it has its own symbol, which is the uppercase M. A solution with a concentration of 5 mmol / l is called a 5 M solution or has a concentration value of 5 mol.
The molar concentration of the solution is equal to the number of moles of the solute divided by the mass of the solvent (kilogram), and the molar concentration of the solution is equal to the number of moles of the solute divided by the volume of the solution (liter). increase.
If you started with 20.0 g of a radioisotope and waited for 3 half-lives to pass, then how much would remain? 2.50 g 5.00 g 10.0 g 15.0 g
The amount that would remain, given that 3 half-lives has pass when you started with 20.0 g is 2.50 grams (1st option)
How do i determine the amount that would remain?The following data were obtained from the question:
Original amount of radioisotope (N₀) = 20.0 gramsNumber of half-lives that has passed (n) = 3Amount remaining after 3 half-lives (N) = ?The amount remaining can be obtained as shown below:
N = N₀ / 2ⁿ
N = 20 / 2³
N = 20 / 8
N = 2.50 grams
Thus, we can conclude from the above calculation that the amount that would remain after 3 half-lives to pass is 2.50 grams (1st option)
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Answer:
2.50g
Explanation:
Which of the following atoms has the largest atomic radius?
Sr
At
I
Ba
I think it is Ba since the radius increases along the group.but decreases along the period
Answer:
Ba
Explanation:
Ba
If you are given one mole of NH2 and have an excess of H2, how many moles of NH3 can you produce?
You can only get 1 mole of ammonia (NH3) since NH2 is the limiting reactant
15.0 moles of gas are in a 6.00 L tank at 20.3 ∘C . Calculate the difference in pressure between methane and an ideal gas under these conditions. The van der Waals constants for methane are a=2.300L2⋅atm/mol2 and b=0.0430 L/mol.
Under the given circumstances, the pressure difference between methane and an ideal gas is 58.5 atm.
What is an ideal gas?An ideal gas is a theoretical gas composed of a large number of small particles that have zero volume, do not interact with each other, and are in constant random motion. The behavior of an ideal gas is described by the ideal gas law, which relates the pressure, volume, temperature, and number of moles of the gas.
The van der Waals equation can be used to figure out the pressure difference between methane and an ideal gas under these circumstances:
(P + a n² / V²)(V - n b) = n R T
where P is the pressure, n is the number of moles, V is the volume, T is the temperature in Kelvin, R is the ideal gas constant (0.08206 L·atm/K·mol), a and b are the van der Waals constants for methane.
First, we can calculate the pressure of an ideal gas under these conditions using the ideal gas law:
P = n R T / V
P = (15.0 mol) (0.08206 L·atm/K·mol) (293.45 K) / (6.00 L)
P = 299.8 atm
Next, we can use the van der Waals equation to calculate the pressure of methane under these conditions:
(P + a n² / V²)(V - n b) = n R T
(P + (2.300 L²·atm/mol²) (15.0 mol)² / (6.00 L)²) ((6.00 L) - (15.0 mol) (0.0430 L/mol)) = (15.0 mol) (0.08206 L·atm/K·mol) (293.45 K)
Simplifying the equation gives:
P + 1.319 atm = 359.6 atm
P = 358.3 atm
As a result, under these circumstances, the pressure difference between methane and an ideal gas is:
ΔP = P (methane) - P (ideal gas) = 358.3 atm - 299.8 atm = 58.5 atm.
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If the salt created from the reaction of a strong acid and a weak base is added to a solution, what will happen to the solution? A. The pH will decrease. B. The pH will increase. C. The pH will stay the same. D. More OH- ions will form. E. The H3O+ ions will decrease.
HELP ASAP
Which reactions have a positive Δrxn?
o A(g)+B(g)⟶C(g)
o A(g)+B(g)⟶3C(g)
o A(s)+B(s)⟶C(g)
o 2A(g)+B(g)⟶C(g)
The reactions with a positive Δrxn are:
A(g) + B(g) ⟶ 3C(g)
A(s) + B(s) ⟶ C(g)
What is (Δrxn) of a reaction?The entropy change (Δrxn) of a reaction indicates the change in the degree of randomness or disorder of the system during the reaction. If the number of product molecules is greater than the number of reactant molecules, the disorder of the system usually increases, resulting in a positive Δrxn. Therefore, we can determine the answer by analyzing the stoichiometry of each reaction:
A(g) + B(g) ⟶ C(g)
In this reaction, the number of product molecules is less than the number of reactant molecules, so the disorder of the system decreases. Therefore, this reaction has a negative Δrxn.
A(g) + B(g) ⟶ 3C(g)
In this reaction, the number of product molecules is greater than the number of reactant molecules, so the disorder of the system increases. Therefore, this reaction has a positive Δrxn.
A(s) + B(s) ⟶ C(g)
In this reaction, the solid reactants are combining to form a gaseous product. The disorder of the system is expected to increase, resulting in a positive Δrxn.
2A(g) + B(g) ⟶ C(g)
In this reaction, the number of product molecules is less than the number of reactant molecules, so the disorder of the system decreases. Therefore, this reaction has a negative Δ rxn.
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CaCO3 + 2HCI =CaCl2 + H₂O + CO2
5. Calcium carbonate (CaCO3) combines with HCl to produce calcium chloride (CaCl₂),
water, and carbon dioxide gas (CO₂). How many grams of HCI are required to react with
6.35 mol CaCO3?
463.5 grams of HCl are required to react with 6.35 moles of CaCO₃.
What is meant by molar mass?Mass of one mole of substance is referred to as the molar mass. The molar mass of a substance can be calculated by adding up the atomic masses of all the atoms in a molecule.
Balanced chemical equation for the reaction between calcium carbonate (CaCO₃) and hydrochloric acid (HCl) is: CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
6.35 mol CaCO₃ * 2 mol HCl / 1 mol CaCO₃ = 12.7 mol HCl
Now, we use the molar mass of HCl (36.46 g/mol) to convert from moles to grams: 12.7 mol HCl * 36.46 g/mol = 463.5 g HCl
Therefore, 463.5 grams of HCl are required to react with 6.35 moles of CaCO₃.
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In order to estimate the population size of the woodlice in her garden, Jessica used the mark-recapture method: she trapped, marked and released 20 woodlice. Three days later, she trapped 15 woodlice and observed that 10 had marks. Use the following formula to estimate the woodlice population size: population size = 1st sample × 2nd sample ÷ 2nd sample that had been marked.
NEED HELP ASAP!!!!!!
To determine the size of the entire population: In the equation N = M, replace the variables of M solutions, R (number all marked recaptured), with T (total recaptured during second visit). T R = frac M T R N = RMT.
What is the mark-recapture method's formula?In order for the mark-recapture method to function, it must be assumed that the proportion the marked organisms that are recaptured inside the second sample corresponds to that of the original marked in the entire population. This equation R(recaptured)/C(captured in second sample)=M(marked initially)/N) illustrates this (total number in population).
Why do people employ the capture-recapture technique?It has been suggested that capture-recapture techniques be used to gauge a register's degree of completeness. These techniques were initially created to determine how big a confined animal colony was. The process aims to capture, tag, and release as many animals is possible in a given region all at once. This is known as the "capture" stage.
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A flask filled to the 25.0 ml mark contain 29.97 g of a concentrated salt water solution. What is the density of the solution?
A concentrated saltwater solution weighing 29.97 g and fitting into a flask to the mark of 25.0 ml has a density of about 1199.2 g/L.
How is the density of the solution determined?By dividing the solution's mass by its volume, we may get its density: density = mass/volume
We need to know the density of water at the solution's temperature as well as the capacity of the flask up to the 25.0 ml level in order to calculate the volume of the solution.
Since 1 mL = 0.001 L, volume is equal to 25.0 mL, or 0.0250 L.
Now, we may determine the solution's density as follows:
1199.2 g/L or 29.97 g/0.0250 L is what is referred to as density.
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If you have 20 g of H2, how many atoms of hydrogen is that?
The molar mass of hydrogen is approximately 1 g/mol. This means that 1 mole of hydrogen atoms has a mass of 1 gram. So, to find the number of atoms in 20 grams of hydrogen, we need to first find how many moles of hydrogen there are, using the following equation:
moles of hydrogen = mass of hydrogen / molar mass of hydrogen
Plugging in the values, we get:
moles of hydrogen = 20 g / 1 g/mol = 20 mol
So there are 20 moles of hydrogen present in 20 g of hydrogen.
Finally, we can find the number of atoms of hydrogen using Avogadro's number, which gives the number of particles (such as atoms, molecules, or ions) in one mole of a substance. Avogadro's number is approximately 6.02 x 10^23 particles per mole. So we can find the number of atoms of hydrogen as follows:
number of atoms of hydrogen = moles of hydrogen x Avogadro's number
Plugging in the values, we get:
number of atoms of hydrogen = 20 mol x 6.02 x 10^23 atoms/mol
number of atoms of hydrogen = 1.204 x 10^25 atoms
Therefore, there are approximately 1.204 x 10^25 atoms of hydrogen in 20 g of H2.