2x^5-x^2+1=0
can you help me ?
slove it in details
thanks
Answers
●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●
Hi my lil bunny!
❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙
[tex]\boxed{x = 7}[/tex]
Move 1 to the left side of the equation by subtracting it from both sides.
[tex]\sqrt{2x -5 - 2 - 1 = 0 }[/tex]
Subtract 1 from -2.
[tex]\sqrt{2x -5 - 3 = 0 }[/tex]
Add 3 to both sides of the equation.
[tex]\sqrt{2x - 5 = 3}[/tex]
To remove the radical on the left side of the equation, square both sides of the equation.
[tex]\sqrt{2x - 5^3 = 3^2}[/tex]
Simplify each side of the equation.
Multiply the exponents in [tex](( 2x - 5) ^\frac{1}{2})^2[/tex] .
Apply the power rule and multiply exponents, [tex](a^m)^n = a^mn[/tex]
[tex](2x -5)^\frac{1}{2}.2 = 3^2[/tex]
Cancel the common factor of 2.
[tex](2x - 5)^1 = 3^2[/tex]
Simplify.
[tex]2x - 5 = 3^2[/tex]
Raise 3 to the power of 2.
[tex]2x - 5 = 9[/tex]
Solve for x
Move all terms not containing x to the right side of the equation.
Add 5 to both sides of the equation.
[tex]2x = 9 + 5[/tex]
Add 9 and 5.
[tex]2x = 14[/tex]
Divide each term by 2 and simplify.
Divide each term in 2x = 14 by 2.
[tex]\frac{2x}{2} = \frac{14}{2}[/tex]
Cancel the common factor of 2.
[tex]x = \frac{14}{2}[/tex]
Divide 14 by 2.
[tex]x = 7[/tex]
❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙
●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●
Hope this helped you.
Could you maybe give brainliest..?
❀*May*❀
Answer:
root of f(x) = -0.7419124700395855 to about 16 figures
Step-by-step explanation:
given
f(x) = 2x^5-x^2+1 = 0
The polynomial is prime, so cannot solve by factoring.
Since it is a 5th degree polynomial, it has at least one real root.
Graphing helps locate where roots are, if more than one.
(refer to first graph)
So there is a real root between -1 and 0.
We will use numerical methods to find the root to a good degree of accuracy. The technique applies to any univariable function which is differentiable and continuous near the roots. This requirement is true for all polynomials.
However, we must know approximately where the root is, usually found by graphing.
The formula used is a recursive one, which gives a better approximation (x1) from the initial (x0) one , and can be repeated until the required accuracy is reached.
Here, we see that the slope of the function at the root is quite steep, so convergence will be rapid.
The formula is
x1 = x0 - f(x0) / f'(x0), where
x1 = new approximation
x0 = initial (or previous) approximation
f(x0) = value of function when x=x0
f'(x0) = value of derivative of function when x=x0
For the given function
f(x) = 2x^5-x^2+1 = 0
f'(x) = 10x^4-2x = 2x(5x^3-1)
From the graph of f(x), we can take an initial approximation as
x0 = -1
x1 = -1 - (-2)/12 = -5/6
Repeat using x0=-5/6
x1 = -5/6 - ( 2(-5/6)^5 - (-5/6)^2 + 1 ) / (2(-5/6(5(-5/6)^3-1))
= 0.7565596512088784
Repeat again, multiple times
x1 = -0.7423377914518363
x1 = -0.7419128371988212
x1 = -0.7419124700398593
x1 = -0.7419124700395855
x1 = -0.7419124700395855
So we see that the root of f(x) = x1 = -0.7419124700395855 to about 16 figures
Note that the accuracy of the iterations approximately doubles every time.
Related Questions
If you have 2345 and you multiple it by 2 divide it by 6 and add on 22299 what will the answer be?
Answers
Answer:
69242/3 or 23080.666667
Step-by-step explanation:
2345 is multiplied by 2. Then the result is divided by 6. Then 22299 is added to the final result.
2345 × 2
= 4690
4690/6
= 2345/3
2345/3 + 22299
= 69242/3
Find the area of the shape shown below.
Answers
Answer:
28
Step-by-step explanation:
We divide the shape covenientely, like this, and area 1 is 4*4=16
area 2=4*4/2=8
area 3= 2*4/2=4
Area total = Area 1 + Area 2 + Area 3=16+8+4=28
A life insurance company sells a $100,000 one year term life insurance policy to a 30-year old male for $475. The probability that the male survives the year is .999172. Find the expected value for the insurance company.
Answers
Answer:
The expected value for the insurance company is $392.20.
Step-by-step explanation:
The expected value of a random variable, X is:
[tex]E(X)=x\cdot P(X)[/tex]
It is provided that a life insurance company sells a $100,000 one year term life insurance policy to a 30-year old male for $475.
The probability that the male survives the year is, P(S) = 0.999172.
Then the probability that the male does not survives the year is:
P (S') = 1 - P (S)
= 1 - 0.999172
P (S') = 0.000828
The amount the company owes the male if he survives is, S = $475.
The amount the company owes the male if he does not survives is,
S' = $475 - $100,000 = -$99525.
Compute the expected value for the insurance company as follows:
[tex]E(\text{Insurance Company})=S\cdot P(S)+S'\cdot P(S')[/tex]
[tex]=(475\times 0.999172)+(-99525\times 0.000828)\\=474.6067-82.4067\\=392.20[/tex]
Thus, the expected value for the insurance company is $392.20.
im stuck on this question helm me out I will mark you as brainliest
Answers
Answer: it is =4176000000000000
Step-by-step explanation:
(2.9)(100000)(7.2)(10^2)
5(10^−8)
=
(290000)(7.2)(10^2)
5(10^−8)
=
2088000(10^2)
5(10^−8)
=
(2088000)(100)
5(10^−8)
=
208800000
5(10^−8)
=
208800000
5(1/100000000)=
208800000/1
20000000
=4176000000000000
hope i helped
-lvr
The graph of h(x) is a translation of f (x) = RootIndex 3 StartRoot x EndRoot. On a coordinate plane, a cube root function goes through (negative 3, negative 1), has an inflection point at (negative 2, 0), and goes through (negative 1, 1). Which equation represents h(x)?
Answers
Answer:
The correct option is;
[tex]h(x) = \sqrt[3]{x + 2}[/tex]
Step-by-step explanation:
Given that h(x) is a translation of f(x) = ∛x
From the points on the graph, given that the function goes through (-1, 1) and (-3, -1) we have;
When x = -1, h(x) = 1
When x = -3, h(x) = -1
h''(x) = (-2, 0)
Which gives
d²(∛(x + a))/dx²= [tex]-\left ( \dfrac{2}{9} \cdot \left (x + a \right )^{\dfrac{-5}{3}}\right )[/tex], have coordinates (-2, 0)
When h(x) = 0, x = -2 which gives;
[tex]-\left ( \dfrac{2}{9} \cdot \left (-2 + a \right )^{\dfrac{-5}{3}}\right ) = 0[/tex]
Therefore, a = (0/(-2/9))^(-3/5) + 2
a = 2
The translation is h(x) = [tex]\sqrt[3]{x + 2}[/tex]
We check, that when, x = -1, y = 1 which gives;
h(x) = [tex]\sqrt[3]{-1 + 2} = \sqrt[3]{1} = 1[/tex] which satisfies the condition that h(x) passes through the point (-1, 1)
For the point (-3, -1), we have;
h(x) = [tex]\sqrt[3]{-3 + 2} = \sqrt[3]{-1} = -1[/tex]
Therefore, the equation, h(x) = [tex]\sqrt[3]{x + 2}[/tex] passes through the points (-1, 1) and (-3, -1) and has an inflection point at (-2, 0).
Answer: B
Step-by-step explanation:
Consider the function represented by the table.
What is f(0)?
04
O 5
06
O 7
Answers
Answer:
6
Step-by-step explanation:
From the table given defining a function, the values of "x" on the table represents the input of the function, which gives us an output, f(x), which can be labelled as "y" in some instances.
Thus, the value of f(0), is simply the output value we would get, given an input value of "0".
So therefore, f(0) = 6. That is, at x = 0, f(x) = 6.
Answer: 6
Step-by-step explanation:
Select all that apply. If x^2+b/ax+c/a=0 ; then: The sum of its roots = -b/a? The difference of its roots =-b/a? The product of its roots = c/a?The division of its roots = c/a? I can select multiple.
Answers
Answer:
The first and the thirdStep-by-step explanation:
[tex]x^2+\frac bax+\frac ca=0\\\\ ax^2+bx+c=0\\\\x_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a}\qquad\quad x_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\\\\\x_1+x_2=\dfrac{-b-\sqrt{b^2-4ac}}{2a}+\dfrac{-b+\sqrt{b^2-4ac}}{2a}=\dfrac{-2b}{2a}=\dfrac{-b}a\\\\\\x_1\cdot x_2=\dfrac{-b-\sqrt{b^2-4ac}}{2a}\cdot\dfrac{-b+\sqrt{b^2-4ac}}{2a}=\\\\{}\ \ =\dfrac{b^2-b\sqrt{b^2-4ac}+b\sqrt{b^2-4ac}-(\sqrt{b^2-4ac})^2}{2a}=\dfrac{b^2-(b^2-4ac)}{4a^2}=\\\\{}\ \ =\dfrac{b^2-b^2+4ac}{4a^2}=\dfrac{4ac}{4a^2}=\dfrac{c}{a}[/tex]
[tex]x_1-x_2=\frac{-b-\sqrt{b^2-4ac}}{2a}-\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{-2\sqrt{b^2-4ac}}{2a}=\frac{-\sqrt{b^2-4ac}}{a}\\\\\\x_1\div x_2=\frac{-b-\sqrt{b^2-4ac}}{2a}\div\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{-b-\sqrt{b^2-4ac}}{2a}\,\cdot\,\frac{2a}{-b+\sqrt{b^2-4ac}}=\\\\=\frac{-b-\sqrt{b^2-4ac}}{-b+\sqrt{b^2-4ac}}=\frac{b+\sqrt{b^2-4ac}}{b-\sqrt{b^2-4ac}}=\frac{b^2+2\sqrt{b^2-4ac}+b^2-4ac}{b^2-b^2+4ac}=\frac{2b^2+2\sqrt{b^2-4ac}-4ac}{4ac}=[/tex]
[tex]=\frac{b^2+\sqrt{b^2-4ac}-2ac}{2ac}[/tex]
What does the denominator of the fraction \dfrac23 3 2 start fraction, 2, divided by, 3, end fraction mean?
Answers
Answer: It represents that 2 will be divided into 3 equal parts.
Step-by-step explanation:
Numerator is the top number in a fraction. It represents the total item it has to divide.Denominator is the bottom number in a fraction. it represents the number of equal parts the item is divided into.The given fraction : [tex]\dfrac{2}{3}[/tex]
here, Numerator = 2
Denominator = 3
It represents that 2 will be divided into 3 equal parts.
What is the sum of 3x to the second power +2x-1
Answers
Answer:
[tex]3x^2+2x+1[/tex]
Step-by-step explanation:
Sum means to add and second power means that the exponent is "2". So, the expression is:
=> [tex]3x^2+2x+1[/tex]
It cannot be simplified further.
A car bought for $20,000. Its value depreciates by 10% each year for 3 years. What is the car's worth after3 years?
Answers
Answer:
$14,580
Step-by-step explanation:
To start off, 10% of 20,000-one easy way to do this is to multiply 20,000 by 0.1, which is 10% in decimal form
-In doing that, you get 2,000
-Now the question says that the value is depreciated which means it goes down in value, so subtract 2,000 from 20,000 to 18,000
-the value of the car after one year is now $18,000
Now, let's move to the second year. This time find 10% of 18,000
-multiply 18,000 by 0.1 to get 1,800
-since the value is depreciating, or becoming less, we will subtract 1,800 from 18,000 to get 16,200
-the value of the car after two years is now $16,200
Finally, let's look at the value of the car after three years. Only this time, we will now find 10% of 16,200
-multiply 16,200 by 0.1 to get 1,620
-since value is being depreciated, or lessened, we will once again be subtracting. Subtract 1,620 from 16,200 to get 14,580
Therefore, the value of the car after three years is now $14,580.
Right triangle ABC is located in A(-1,-2), B(-1,1) and C(3,1) on a coordinate plane. what is the equation of a circle with radius AC?
A) (x+1)*2+(y+2)*2=9
B) (x+1)*2+(y+2)*2=25
C) (x-3)*2+(y-1)*2= 16
D) (x-3)*2+(y-1)*2=25
Answers
Answer:
Hey there!
First, we want to find the radius of the circle, which equals the length of line segment AC.
Length of line segment AC, which we can find with the distance formula: [tex]\sqrt{25\\[/tex], which is equal to 5.
The equation for a circle, is: [tex](x-h)^2+(y-k)^2=r^2[/tex], where (h, k) is the center of the circle, and r is the radius.
Although I don't know the center of the circle, I can tell you that it is either choice B or D, because the radius, 5, squared, is 25.
Hope this helps :) (And let me know if you edit the question)
Answer: The equation of the circle is (x+1)²+(y+1)² = 25
Step-by-step explanation: Use the Pythagorean Theorem to calculate the length of the radius from the coordinates given for the triangle location: A(-1,-2), B(-1,1) and C(3,1) The sides of the triangle are AB=3, BC=4, AC=5.
Use the equation for a circle: ( x - h )² + ( y - k )² = r², where ( h, k ) is the center and r is the radius.
As the directions specify, the radius is AC, so it makes sense to use the coordinates of A (-1,-2) as the center. h is -1, k is -2 The radius 5, squared becomes 25.
Substituting those values, we have (x -[-1])² + (y -[-2])² = 25 .
When substituted for h, the -(-1) becomes +1 and the -(-2) for k becomes +2.
We end up with the equation for the circle as specified:
(x+1)²+(y+1)² = 25
A graph of the circle is attached. I still need to learn how to define line segments; the radius is only the segment of the line between the center (-1,-2) and (1,3)
!!!!PLEASE HELP!!!!!
Answers
Answer:
inverse = ( log(x+4) + log(4) ) / (2log(4)), or
c. y = ( log_4(x+4) + 1 ) / 2
Step-by-step explanation:
Find inverse of
y = 4^(-6x+5) / 4^(-8x+6) - 4
Exchange x and y and solve for y.
1. exchange x, y
x = 4^(-6y+5) / 4^(-8y+6) - 4
2. solve for y
x = 4^(-6y+5) / 4^(-8y+6) - 4
transpose
x+4 = 4^(-6y+5) / 4^(-8y+6)
using the law of exponents
x+4 = 4^( (-6y+5) - (-8y+6) )
simplify
x+4 = 4^( 2y - 1 )
take log on both sides
log(x+4) = log(4^( 2y - 1 ))
apply power property of logarithm
log(x+4) = (2y-1) log(4)
Transpose
2y - 1 = log(x+4) / log(4)
transpose
2y = log(x+4) / log(4) + 1 = ( log(x+4) + log(4) ) / log(4)
y = ( log(x+4) + log(4) ) / (2log(4))
Note: if we take log to the base 4, then log_4(4) =1, which simplifies the answer to
y = ( log_4(x+4) + 1 ) / 2
which corresponds to the third answer.
values of r and h, what do you notice about the proportions of the cylinders?
Answers
Answer:
Below
Step-by-step explanation:
r us the radius of the base and h is the heigth of the cylinder.
The volume of a cylinder is given by the formula:
V = Pi*r^2*h
V/Pi*r^2 = h
We can write a function that relates h and r
Answer:
One of the cylinders is short and wide, while the other is tall and thin.
Step-by-step explanation:
sample answer given on edmentum
[tex] \sqrt[3]{y} = a(c + \frac{1}{x})[/tex]
Answers
Greetings from Brasil...
Here we don't have much to go
∛Y = A.(C + 1/X)
∛Y = (AC + A/X)
raising both members to the cube.....
(∛Y)³ = (AC + A/X)³
from Notable Products: (a + b)³ = a³ + 3a²b + 3ab² + b³
Y = (AC)³ + 3(AC)².(A/X) + 3AC(A/X)² + (A/X)³
Y = A³[C³ + (3C²/X) + (3C/X²) + (1/X³)]
An exponential growth function has a base that is____one?
Please help
Answers
Answer:
greater than
Step-by-step explanation:
An exponential growth function has a base that is__greater than__one.
If the base is less than one, it will be a decay function.
Note: the above assumes an exponent greater than one as well.
If a cone is 5 meters tall and has a radius of 3 meters, What is its volume? 15π m3 60π m3 45π m3 30π m3
Answers
Answer:
V = 15 pi m^3
Step-by-step explanation:
The volume of a cone is
V = 1/3 pi r^2 h
The radius is 3 and the height is 5
V = 1/3 pi ( 3)^2 *5
V = 15 pi m^3
Answer:
15 pi m3
Step-by-step explanation:
vertical stretch of the graph f(x)= x² by a factor of 5
PLEASE HELP!!
Answers
Answer:
f(x) = 5x^2
Step-by-step explanation:
A vertical stretch is in the y direction
y = Cf(x) C > 1 stretches it in the y-direction
f(x) = 5x^2
(pic inside) What is the approximate value of the function at x = 1?
Answers
Answer: -2
Step-by-step explanation:
When x = 1, y = -2.
Hope it helps <3
Draw a diagram of this statement,
Fifteen thousand dollars was raised by the booster club. This was two thirds of
the goal.
Use your diagram to determine the percent by which the booster club fell short of their goal
Answers
Answer:
The percentage by which the booster club fell short is 33% as shown on the chart
Step-by-step explanation:
To represent the given data pictorially, a pie chart is suitable
The circumference of the pie chart will represent the amount to be raised by the booster club and a sector of the circle which is two-thirds of the circumference represents the amount raised
Given that the amount raised = 2/3×Goal = $15,000, we have;
We represent the amount raised as a sector of the circle as follows;
Sector angle = 2/3×360° = 240°
Total sector of goal amount = Entire circle = 360°
Amount club fell short = 360° - 240° = 120°
The goal amount = 3/2 × $15,000
Percentage by which the club fell short = 120/360×100 = 1/3×100 = 33.33%
Grace starts with 100 milligrams of a radioactive substance. The amount of the substance decreases by 14 each week for a number of weeks, w. She writes the expression 100(14)w to find the amount of radioactive substance remaining after w weeks. Ryan starts with 1 milligram of a radioactive substance. The amount of the substance decreases by 40% each week for a number of weeks, w. He writes the expression (1 – 0.4)w to find the amount of radioactive substance remaining after w weeks. Use the drop-down menus to explain what each part of Grace’s and Ryan’s expressions mean.
Answers
Answer:
100= Initial Amount
1/4= decay factor for each week
w= number of weeks
1/4w= decay factor after w weeks
1 - 0.4= decay factor for each week
w= number of weeks
0.4= percent decrease
Step-by-step explanation:
Given that StartFraction D F Over P R EndFraction = StartFraction F E Over R Q EndFraction = three-halves, what additional information is needed to prove △DEF ~ △PQR using the SSS similarity theorem?
Answers
Answer:
The additional information required to prove ΔDEF ~ ΔPQR is the value of the ratio DE/PQ which has to be equal to three-halves for ΔDEF to be similar to ΔPQR
Step-by-step explanation:
Given DF/PR = FE/RQ = 3/2
The Side Side Side, SSS, similarity theorem states that where there are two triangles that have corresponding sides that are proportional to each other, the two triangles are said to be similar
Given ΔDEF and ΔPQR, have sides DF/PR = FE/RQ, to prove that ΔDEF and ΔPQR, then the additional information required is the ratio of the third sides of the triangles which is DE/PQ.
If DE/PQ = Three-halves, the two triangles ΔDEF and ΔPQR are similar, if not, that is DE/PQ ≠ Three-halves, then the two triangles ΔDEF and ΔPQR are not similar.
Answer:
D: DE/PQ = 3/2
Step-by-step explanation:
Did it on edge 2020
How does the period of f(x)= cos(2x) relate to the period of the parent function cos x?
Answers
Answer:
Both have the same period which is 2π
Step-by-step explanation:
Answer the problem below
Answers
Answer:
D. 4z^3
Step-by-step explanation:
First, you see what cubed is 64, which is 4, so you know it is either A or D, but it can not be A because it is not z to the power 5 but x to the power of 3
Hope this helps, if you want me to explain more, feel free to ask questions.
Have a good day! :)
Answer:
4 z^3
Step-by-step explanation:
( 64 z^9) ^ 1/3
Rewriting 64 as 4^3
( 4^3 z^9) ^ 1/3
We know that ( ab) ^c = a^c * b^c
4^3 ^ 1/3 z^9 ^ 1/3
We know that a^ b^c = a^ ( b*c)
4^(3 * 1/3) z^ (9 * 1/3)
4 ^ ( 1) z^ ( 3)
4 z^3
A total of $10,000 is invested in two mutual funds. The first account yields 5% and the second account yields 6%. How much was invested in each account if the total interest earned in a year is $575?
Answers
Answer:
$2,500 was invested in the first account while $7,500 was invested in the second account
Step-by-step explanation:
Here in this question, we want to find the amount which was invested in each of the accounts, given their individual interest rates and the total amount that was accorded as interest from the two investments
Now, since we do not know the amount invested , we shall be representing them with variables.
Let the amount invested in the first account be $x and the amount invested in the second account be $y
Since the total amount invested is $10,000, this means that the summation of both gives $10,000
Mathematically;
x + y = 10,000 ••••••(i)
now for the $x, we have an interest rate of 5%
This mathematically translates to an interest value of 5/100 * x = 5x/100
For the $y, we have an interest rate of 6% and this mathematically translates to a value of 6/100 * y= 6y/100
The addition of both interests, gives 575
Thus mathematically;
5x/100 + 6y/100 = 575
Multiplying through by 100, we have
5x + 6y = 57500 •••••••••(ii)
From 1, we can have x = 10,000-y
let’s substitute this into equation ii
5(10,000-y) + 6y = 57500
50,000-5y + 6y = 57500
50,000 + y = 57500
y = 57500-50,000
y = 7,500
Recall;
x = 10,000-y
so we have;
x = 10,000-7500 = 2,500
If $6a^2 + 5a + 4 = 3,$ then what is the smallest possible value of $2a + 1$?
Answers
Answer: 0
Step-by-step explanation:
The given equation: [tex]6a^2+5a+4=3[/tex]
Subtract 3 from both the sides, we get
[tex]6a^2+5a+1=0[/tex]
Now , we can split 5a as 2a+3a and [tex]2a\times 3a = 6a^2[/tex]
So, [tex]6a^2+5a+1=0\Rightarrow\ 6a^2+2a+3a+1=0[/tex]
[tex]\Rightarrow\ 2a(3a+1)+(3a+1)=0\\\\\Rightarrow\ (3a+1)(2a+1)=0\\\\\Rightarrow\ (3a+1)=0\text{ or }(2a+1)=0\\\\\Rightarrow\ a=-\dfrac{1}{3}\text{ or }a=-\dfrac{1}{2}[/tex]
At [tex]a=-\dfrac{1}{3}[/tex]
[tex]2a+1=2(-\dfrac{1}{3})+1=-\dfrac{2}{3}+1=\dfrac{-2+3}{3}=\dfrac{1}3{}[/tex]
At [tex]a=-\dfrac{1}{2}[/tex]
[tex]2a+1=2(-\dfrac{1}{2})+1=-1+1=0[/tex]
Since, [tex]0< \dfrac{1}{3}[/tex]
Hence, the possible value of 2a+1 is 0.
This is probably pretty easy, I could solve all the other ones but I got stuck on this one.
Answers
Answer:
78
Step-by-step explanation:
Let x be the score on the next test
We are averaging 6 tests and want an average of 75
( 82+91+38+78+83+x) /6 = 75
Multiply each side by 6
( 82+91+38+78+83+x) = 75*6
( 82+91+38+78+83+x) =450
Combine like terms
x+372 = 450
Subtract 372 from each side
x+372-372 = 450-372
x =78
The mean one-way commute to work in Chowchilla is 7 minutes. The standard deviation is 2.4 minutes, and the population is normally distributed. What is the probability of randomly selecting one commute time and finding that: a). P (x < 2 mins) _____________________________ b). P (2 < x < 11 mins) _____________________________ c). P (x < 11 mins) ________________________________ d). P (2 < x < 5 mins) _______________________________ e). P (x > 5 mins)
Answers
Answer:
The answer is below
Step-by-step explanation:
Given that:
The mean (μ) one-way commute to work in Chowchilla is 7 minutes. The standard deviation (σ) is 2.4 minutes.
The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
a) For x < 2:
[tex]z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08[/tex]
From normal distribution table, P(x < 2) = P(z < -2.08) = 0.0188 = 1.88%
b) For x = 2:
[tex]z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08[/tex]
For x = 11:
[tex]z=\frac{x-\mu}{\sigma}=\frac{11-7}{2.4} =1.67[/tex]
From normal distribution table, P(2 < x < 11) = P(-2.08 < z < 1.67 ) = P(z < 1.67) - P(z < -2.08) = 0.9525 - 0.0188 = 0.9337
c) For x = 11:
[tex]z=\frac{x-\mu}{\sigma}=\frac{11-7}{2.4} =1.67[/tex]
From normal distribution table, P(x < 11) = P(z < 1.67) = 0.9525
d) For x = 2:
[tex]z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08[/tex]
For x = 5:
[tex]z=\frac{x-\mu}{\sigma}=\frac{5-7}{2.4} =-0.83[/tex]
From normal distribution table, P(2 < x < 5) = P(-2.08 < z < -0.83 ) = P(z < -0.83) - P(z < -2.08) = 0.2033- 0.0188 = 0.1845
e) For x = 5:
[tex]z=\frac{x-\mu}{\sigma}=\frac{5-7}{2.4} =-0.83[/tex]
From normal distribution table, P(x < 5) = P(z < -0.83) = 0.2033
Solve the equation and show the solution set on a number line: |x+5|=x+5
Answers
Answer: x ≥ -5
Step-by-step explanation:
First, let's see how the function f(x) = IxI works:
if x ≥ 0, IxI = x
if x ≤ 0, IxI = -x
Notice that for 0, I0I = 0.
Ok, we want that:
|x+5| = x+5
Notice that this is equivalent to:
IxI = x
This means that |x+5| = x+5 is only true when:
(x + 5) ≥ 0
from this we can find the possible values of x:
we can subtract 5 to both sides and get:
(x + 5) -5 ≥ 0 - 5
x ≥ -5
So the graph in the number line will be a black dot in x = -5, and all the right region shaded.
something like:
-7__-6__-5__-4__-3__-2__-1__0__1__2__3__4__ ...
The local ice cream shop offers 3 different types of cones and 15 different flavors of ice cream. How many possible ice cream cones (one scoop) can a customer order? a 40 b 18 c 45 d 35
Answers
Answer:
45
Step-by-step explanation:
There are 3 cones and 15 flavors
Multiply the number of cones by the number of flavors
3*15
45
There are 45 possible combinations
WILL MARK BRAINLIEST!!!!!!!!!!!!!!!!!! Why would someone choose to use a graphing calculator to solve a system of linear equations instead of graphing by hand? Explain your reasoning.
Answers
Answer:
A graphing calculator is more accurate than graphing by hand. If the slope and/or y-intercept is a fraction or decimal, it is more difficult to accurately graph by hand.
Step-by-step explanation:
Answer:
WHEN U GRAPH WITH A CALCULATOR IT IS MUCH MORE ACCURATE
ESPECIALLY IF THERE R FRACTIONS AND DECIMALS AND THE GRAPHING CALCULATOR GOES ON FOREVER WHERE AS THE GRAPHING PAPER ENDS
Step-by-step explanation:
HOPE I HELPED
PLS MARK BRAINLIEST
DESPERATELY TRYING TO LEVEL UP
✌ -ZYLYNN JADE ARDENNE
JUST A RANDOM GIRL WANTING TO HELP PEOPLE!
PEACE!