3. What is the distance from (−4, 0) to (2, 5)? Round your answer to the nearest hundredth. (4 points)

Answer:

A) Fail to Reject the Null Hypothesis

Step-by-step explanation:

Given that:

A local Internet provider wants to test the claim that the average time a family spends online on a Saturday is at least 7 hours.

sample size = 30

sample mean [tex]\bar x[/tex] = 6

standard deviation [tex]\sigma[/tex] = 1.5

level of significance ∝ = 0.05

The null hypothesis and the alternative hypothesis can be computed as:

[tex]\mathbf{ H_o: \mu \leq 7}[/tex]

[tex]\mathbf{ H_i: \mu \geq 7}[/tex]

The test statistic  can be computed as:

[tex]z = \dfrac{\bar x - \mu}{\dfrac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \dfrac{6 -7} {\dfrac{1.5}{\sqrt {30}}}[/tex]

[tex]z = \dfrac{-1} {\dfrac{1.5}{5.477}}}[/tex]

[tex]z = \dfrac{-5.477} {1.5}[/tex]

z = -3.65

Given that ;

level of significance of 0.05;

z = -3.65

degree of freedom = 30 -  1 = 29

The p-value = P([tex]t_{29}[/tex] > - 3.65)

= 0.9998

Decision Rule: Reject [tex]H_o[/tex] if p-value is less than the level of significance

But since the p -value is greater than the level of significance, we conclude that There is no enough evidence to support the  Internet provider  claim, Therefore;

Fail to Reject the Null Hypothesis

Answer:

x=6.28 inches

y=191.08 inches

Step-by-step explanation:

Let the dimensions of the rectangle be x and y

Area of the rectangular sheet

x*y=1200 in^2}

x = circumference of the cylinder

This means x=2πr

Volume of a cylinder=πr^2h

h=y

Volume of the cylind=πr^2(y)=600 in^3

From x=2πr

r=x/2π

Substitute r=x/2π into Volume=πr^2(y)=600 in^3

We have,

Volume of the cylinder=πr^2(y)=600 in^3

π*(x/2π)^2(y)=600

(x^2/4π)y=600

Recall, x*y=1200

y=1200/x

Substitute y=1200/x into (x^2/4π)y=600

(x^2/4π)y=600

(x^2/4π)(1200/x)=600

1200x/4π=600

Multiply both sides by 4π

(x^2/4π)(1200/x)(4π)=600*4π

1200x=2400π

Divide both sides by 1200

1200x/1200 = 2400π/1200

x=2π

Substitute x=2π into y=1200/x

We have,

y=1200/2π

y=600/π

The dimensions are x=2π and y=600/π

Let π=3.14

x=2π

=2(3.14)

=6.28 inches

y=600/π

=600/3.14

=191.08 inches

Answer: The average rate of change for this function for the interval from x=3 to x=5 is 12.

Step-by-step explanation:

Complete question is provided in the attachment below.

Formula: The average rate of change for this function y=f(x) for the interval from  x= a to x= b :

[tex]Rate =\dfrac{f(b)-f(a)}{b-a}[/tex]

Let y= f(x) for the given table:

At x= 3 , f(3)=8 and f(5)=32

Then, the average rate of change for this function for the interval from x=3 to x=5:

[tex]Rate=\dfrac{f(5)-f(3)}{5-3}\\\\=\dfrac{32-8}{2}\\\\=\dfrac{24}{2}=12[/tex]

Hence, the average rate of change for this function for the interval from x=3 to x=5  is 12.  (Option A is correct.)

Answer:

a. (24 ln 2 − 7) / 9

b. x tan x + ln|cos x| + C

Step-by-step explanation:

a. ∫₁² x² ln x dx

Integrate by parts.

If u = ln x, then du = 1/x dx.

If dv = x² dx, then v = ⅓ x³.

∫ u dv = uv − ∫ v du

= (ln x) (⅓ x³) − ∫ (⅓ x³) (1/x dx)

= ⅓ x³ ln x − ∫ ⅓ x² dx

= ⅓ x³ ln x − ¹/₉ x³ + C

= ¹/₉ x³ (3 ln x − 1) + C

Evaluate between x=1 and x=2.

[¹/₉ 2³ (3 ln 2 − 1) + C] − [¹/₉ 1³ (3 ln 1 − 1) + C]

⁸/₉ (3 ln 2 − 1) + C + ¹/₉ − C

⁸/₉ (3 ln 2 − 1) + ¹/₉

⁸/₃ ln 2 − ⁸/₉ + ¹/₉

⁸/₃ ln 2 − ⁷/₉

(24 ln 2 − 7) / 9

b. ∫ x sec² x dx

Integrate by parts.

If u = x, then du = dx.

If dv = sec² x dx, then v = tan x.

∫ u dv = uv − ∫ v du

= x tan x − ∫ tan x dx

= x tan x + ∫ -sin x / cos x dx

= x tan x + ln|cos x| + C

Answer:

-2.05

Step-by-step explanation:

From the given information,

Let consider [tex]\mu[/tex] to represent the population mean

Therefore,

The null and alternative hypothesis can be stated as :

[tex]H_o :\mu=9[/tex]

[tex]H_1 :\mu<9[/tex]

From the hypothesis , the alternative hypothesis is one tailed (left)

when the level of significance = 0.020, the Z- critical value can be determined from the standard normal distribution table

Hence, the Z-critical value at ∝ = 0.020 is -2.05

None of these options seem to be correct. You can check each result by differentiation:

[tex](e^x\sec^2x)'=e^x(\sec^2x+2\sec^2\tan x)=e^x\sec^2x(1+\tan x)[/tex]

[tex](e^x\sec x)'=e^x(\sec x+\sec x\tan x)=e^x\sec x(1+\tan x)[/tex]

[tex](e^x\tan^2x)'=e^x(\tan^2x+2\tan x\sec^2x)=e^x\tan x(\tan x+2\sec^2x)[/tex]

[tex](e^x\tan x)'=e^x(\tan x+\sec^2x)[/tex]

But none of these are equivalent to [tex]e^x(\sec x+\tan^2x)[/tex]...

Answer:

An architect is designing a house for the Frazier family. In the design he must consider the desires of the family and the local building codes. The rectangular lot on which the house will be built has 91 feet of frontage on a lake and is 158 feet deep.

The building codes states that one can build no closer than 10 ft. to the lot line. Write an inequality and solve to see how long the front of the house facing the lake may be.

------

length = 91 - 2*10 = 71 ft.

-------------------------------

The Fraziers requested that the house contain no less 2800 ft square and no more than 3200 ft square of floor sample. Write an inequality to represent the range of permissible widths for the house.

---------

2800 <= area <= 3200

2800 <= (length)(width) <= 3200

2800 <= 71w <= 3200

39.44 <= width <= 45.07

hope it helpsss

Step-by-step explanation:

Answer: An architect is designing a house for the Frazier family. In the design he must consider the desires of the family and the local building codes. The rectangular lot on which the house will be built has 91 feet of frontage on a lake and is 158 feet deep.

The building codes states that one can build no closer than 10 ft. to the lot line. Write an inequality and solve to see how long the front of the house facing the lake may be.

------

length = 91 - 2*10 = 71 ft.

-------------------------------

The Fraziers requested that the house contain no less 2800 ft square and no more than 3200 ft square of floor sample. Write an inequality to represent the range of permissible widths for the house.

---------

2800 <= area <= 3200

2800 <= (length)(width) <= 3200

2800 <= 71w <= 3200

39.44 <= width <= 45.07

Answer:

the dimensions that will minimize the cost of constructing the box is:

a = 5.8481  in ;   b = 5.848 in  ; c = 10.234 in

Step-by-step explanation:

From the information given :

Let a be the base if the rectangular box

b to be the height and c to be the  other side of the rectangular box.

Then ;

the area of the base is ac

area for the front of the box is ab

area for the remaining other sides   ab + 2cb

The base of the box is made from a material costing 8 ac

The front of the box must be decorated, and will cost 10 ab

The remainder of the sides will cost 4 (ab + 2cb)

Thus ; the total cost  C is:

C = 8 ac + 10 ab + 4(ab + 2cb)

C = 8 ac + 10 ab + 4ab + 8cb

C = 8 ac + 14 ab + 8cb   ---- (1)

However; the volume of the rectangular box is V = abc = 350 in³

If abc = 350

Then b = [tex]\dfrac{350}{ac}[/tex]

replacing the value for c in the above equation (1); we have :

[tex]C = 8 ac + 14 a(\dfrac{350}{ac}) + 8c(\dfrac{350}{ac})[/tex]

[tex]C = 8 ac + \dfrac{4900}{c}+\dfrac{2800}{a}[/tex]

Differentiating C with respect to a and c; we have:

[tex]C_a = 8c - \dfrac{2800}{a^2}[/tex]

[tex]C_c = 8a - \dfrac{4900}{c^2}[/tex]

[tex]8c - \dfrac{2800}{a^2}=0[/tex] --- (2)

[tex]8a - \dfrac{4900}{c^2}=0[/tex]   ---(3)

From (2)

[tex]8c =\dfrac{2800}{a^2}[/tex]

[tex]c =\dfrac{2800}{8a^2}[/tex] ----- (4)

From (3)

[tex]8a =\dfrac{4900}{c^2}[/tex]

[tex]a =\dfrac{4900}{8c^2}[/tex]   -----(5)

Replacing the value of a in 5 into equation (4)

[tex]c = \dfrac{2800}{8*(\dfrac{4900}{8c^2})^2} \\ \\ \\ c = \dfrac{2800}{\dfrac{8*24010000}{64c^4}} \\ \\ \\ c = \dfrac{2800}{\dfrac{24010000}{8c^4}} \\ \\ \\ c = \dfrac{2800*8c^4}{24010000} \\ \\ c = 0.000933c^4 \\ \\ \dfrac{c}{c^4}= 0.000933 \\ \\ \dfrac{1}{c^3} = 0.000933 \\ \\ \dfrac{1}{0.000933} = c^3 \\ \\ 1071.81 = c^3\\ \\ c= \sqrt[3]{1071.81} \\ \\ c = 10.234[/tex]

From (5)

[tex]a =\dfrac{4900}{8c^2}[/tex]   -----(5)

[tex]a =\dfrac{4900}{8* 10.234^2}[/tex]

a = 5.8481

Recall that :

b = [tex]\dfrac{350}{ac}[/tex]

b = [tex]\dfrac{350}{5.8481*10.234}[/tex]

b =5.848

Therefore ; the dimensions that will minimize the cost of constructing the box is:

a = 5.8481  in ;   b = 5.848 in  ; c = 10.234 in

The dimensions that will minimize the cost of constructing this box are: a = 5.8481 inches, b = 5.848 inches, and c = 10.234 inches and this can be determined by using the given data.

Given :

According to the given data the total cost is given by:

C = 8ac + 14ab + 8cb   --- (1)

The volume of the rectangular box is (V = abc = 350 inch cube). So, the value of b is given by:

[tex]\rm b = \dfrac{350}{ac}[/tex]

Now, substitute the value of 'b' in the equation (1).

[tex]\rm C = 8ac + \dfrac{4900}{c}+\dfrac{2800}{a}[/tex]

First differentiating the above equation with respect to c.

[tex]\rm C_c = 8a-\dfrac{4900}{c^2}[/tex]   --- (2)

Now, differentiating the above equation with respect to a.

[tex]\rm C_a = 8c-\dfrac{2800}{a^2}[/tex]    --- (3)

Now, equate equation (2) and equation (3) to zero.

From equation (2):  

[tex]\rm a=\dfrac{4900}{8c^2}[/tex]    ----- (4)

From equation (3):

[tex]\rm c=\dfrac{2800}{8a^2}[/tex]   ----- (5)

Now, from equations (4) and (5).

[tex]\rm c = \dfrac{2800}{8\left(\dfrac{4900}{8c^2}\right)^2}[/tex]

Now, simplifying the above expression in order to get the value of c.

c = 10.234

Now, put the value of 'c' in equation (5) in order to get the value of 'a'.

a = 5.8481

The value of 'b' is given by:

[tex]\rm b = \dfrac{350}{5.8481\times 10.234}[/tex]

b = 5.848

So, the dimensions that will minimize the cost of constructing this box are: a = 5.8481 inches, b = 5.848 inches, and c = 10.234 inches.

For more information, refer to the link given below:

https://brainly.com/question/19770987

Answer:

72 cents.

Step-by-step explanation:

The expected winnings is the amount times the probability that you will get that amount.

2,000 * (1/10,000) = 2,000 / 10,000 = 2 / 10 = 0.2.

700 * (4 / 10,000) = 2,800 / 10,000 = 28 / 100 = 0.28.

300 * (8 / 10,000) = 2,400 / 10,000 = 24 / 100 = 0.24.

0.2 + 0.28 + 0.24 = 0.72.

Hope this helps!

Answer:

Step-by-step explanation:

The side lengths are equal - supposedly

30                          25

?                              ?

25 + ? = 45

-25        - 25

? = 20

45 - 30 = 15

The question mark should be equal to 15.

Hope this helps,

Kavitha

Answer:

Step-by-step explanation:

[tex]\frac{x-1}{2} =t\\\frac{y-2}{3} =t\\\frac{z-3}{4} =t\\so~eq.~of~line~L_{1}~is\\\frac{x-1}{2} =\frac{y-2}{3} =\frac{z-3}{4} \\its~d.r's~are~2,3,4\\again~\frac{x-2}{1} =s\\\frac{y-4}{2} =s\\\frac{z+1}{-4} =s\\so~eq. ~of~line~L_{2}~is\\\frac{x-2}{1} =\frac{y-4}{2} =\frac{z+1}{-4} \\its~d.r's ~are~1,2,-4\\let ~the ~d.r's~of~line~perpendicular~to~both~L_{1}~and~L_{2}~be~a,b,c,~then~\\2a+3b+4c=0\\1a+2b-4c=0\\solving\\\frac{a}{3*-4-4*2} =\frac{b}{4*1-2*-4} =\frac{c}{2*2-3*1} \\[/tex]

[tex]\frac{a}{-20} =\frac{b}{-4} =\frac{c}{1} \\d.r's~of ~reqd~line~is~-20,-4,1~or~20,4,-1[/tex]

now you find the point of intersection.

then calculate the angle.

Answer:

18

Step-by-step explanation:

Given the above table of the data set, the number of values less than or equal to 6 would be the sum of the frequencies of all values that is equal to or less than 6.

From the table above, we would add up the frequencies of the values of 6 and below, which is:

2 + 3 + 6 + 4 + 3 = 18

Answer = 18

The number of values less than or equal to 6 is 18

Here the number of values should be less than or equivalent to 6 represent the sum of the frequencies i.e. equal or less than 6

So, here the number of values should be

= 2 + 3 + 6 + 4 + 3

= 18

Hence, we can conclude that  The number of values less than or equal to 6 is 18

Learn more about frequency here: https://brainly.com/question/20875379

Answer:

❄️The answer is 7.0 or 7❄️

Step-by-step explanation:

It mostly depends on how many zeros will you put in 7.0

It actually doesn’t matter how many zeros you put after the decimal point.

Below I attached a picture of how to solve this kinds of problem.

Hope this helps! ^-^

By:❤️BrainlyMagic❤️

Note:if you ever need help, you can always ask me!

Answer:

It’s 7.0 or 7

Step-by-step explanation:

Trust me I got it right in my homework.

Answer:

Option (2)

Step-by-step explanation:

In the two triangles ΔWVZ and ΔYXZ,

If the sides WV and XY are parallel and the segments WY and VX are the transverse.

∠X ≅ ∠V [Alternate angles]

∠W ≅ ∠Y [Alternate angles]

Therefore, ΔWVZ ~ ΔYXZ [By AA postulate of the similarity]

Option (2) will be the answer.

Answer:

7 children

Step-by-step explanation:

Answer:

7 children is the correct answer

and you follow me if you can't I will unfollow you

Answer:

B (4, 2+3)

Step-by-step explanation:

To do this you fill in x with 4 so the equation becomes y = (4)2 - 3

You then solve to y = 8 - 3

then 8 - 3 is 5.

Making the coordinates (4, 5) and in this case with the answers (4, 2+3)

Answer:

A. (4, 4^2 – 3)

Answer:

see below.

Step-by-step explanation:

1st row has four small boxes

2nd row has three big boxes

big box 1 has no items ragged in it.

big box 2 has small box 1 and also small box 1 dragged into it.

big box 3 has small box 3 and small box 4 dragged into it.

Answer:

There is sufficient evidence to conclude that women make less money than men doing the same job.

Step-by-step explanation:

The hypothesis for the test can be explained as follows:

H₀: Women does not make less money than men doing the same job, i.e. [tex]\mu\geq \$1343[/tex].

Hₐ: Women make less money than men doing the same job, i.e. [tex]\mu<\$1343[/tex].

From the provided data compute the sample mean and standard deviation:

[tex]\bar x=\frac{1}{n}\sum X=\frac{1}{18}[1811+728+...+1170]=1125.11\\\\s=\sqrt{\frac{1}{n-1}\sum (X-\bar x)^{2}}=\sqrt{\frac{1}{18-1}\times 1322541.86}=278.92[/tex]

Compute the test statistic as follows:

[tex]t=\frac{\bar x-\mu}[\s/\sqrt{n}}=\frac{1125.11-1343}{278.92/\sqrt{18}}=-3.143[/tex]

The test statistic value is -3.143.

Compute the p-value as follows:

[tex]p-value=P(t_{n-1}<-3.143)=P(t_{17}<-3.143)=0.003[/tex]

*Use a t-table.

The p-value of the test is 0.003.

The p-value of the test is very small for all the commonly used significance level. The null hypothesis will be rejected.

Conclusion:

There is sufficient evidence to conclude that women make less money than men doing the same job.

Answer:

complementary because 2 angles that add up to 90º is a complementary angle and x=9 :)

Step-by-step explanation:

90=46+5x-1

45=5x

x=9

Answer:

x = 9 Complementary

Step-by-step explanation:

The angles are compplementary cause the angle add up to 90°

Well to find x we need to make the following equation,

46 + (5x - 1) = 90

We need to simplify and combine like terms,

46 - 1 = 45

45 + 5x = 90

-45 to both sides

5x = 45

Divide 5 by both sides

x = 9

Thus,

x is 9.

Hope this helps :)

Answer:

Step-by-step explanation:

The mean which is also known as the average is determined by dividing the sum of the weight of the packages by the total number of packages. From the information given,

Mean = (26 + 18 + 58 + 22 + 54 + 50)/6 = 38

If you include a package that weighs 66 ounces, the new mean would be

New mean = (26 + 18 + 58 + 22 + 54 + 50 + 66)/7 = 42

For the median, we would rearrange the weights in ascending order. It becomes

18, 22, 26, 50, 54, 58

Median = (26 + 50)/2 = 38

By adding the new weight, it becomes

18, 22, 26, 50, 54, 58, 66

New median = 50

It can be seen that both the median increased by more. It increased by 12 while the mean increased by 4

Answer: The mean which is also known as the average is determined by dividing the sum of the weight of the packages by the total number of packages. From the information given, Mean = (26 + 18 + 58 + 22 + 54 + 50)/6 = 38If you include a package that weighs 66 ounces, the new mean would be New mean = (26 + 18 + 58 + 22 + 54 + 50 + 66)/7 = 42For the median, we would rearrange the weights in ascending order. It becomes18, 22, 26, 50, 54, 58Median = (26 + 50)/2 = 38By adding the new weight, it becomes18, 22, 26, 50, 54, 58, 66New median = 50It can be seen that both the median increased by more. It increased by 12 while the mean increased by 4

Step-by-step explanation:

Answer:

(2,0)

Step-by-step explanation:

From the information the first equation is y = 0.5 x  - 1 and the the line through (3,1) and (-5,-7) is  

y = x - 2  .   From those two equations you get

x - 2 = 0.5 x -1     and     x = 2  , y = 0.  So  it is the last point.   (2,0)

Answer:

D. (2,0)

Step-by-step explanation:

Answer:

(12.141, 14.059)

Step-by-step explanation:

Explanation is provided in the attached document.

Answer:

$15,842

Step-by-step explanation:

We use the Present value formula

Present Value = Future value/(1 + r)ⁿ

r = 6% = 0.06

n = 4 years

Future value = $20,000

Present value = 20,000/(1 + 0.06)⁴

= $15841.873265

≈ $15,842

Answer:

Thickness of rectangle prism is 20 inches.

Step-by-step explanation:

Given:

Surface area of rectangular prism, A =  992 sq inches.

Height, h = 12 inches

Width, w = 8 inches

To find:

Thickness / length of prism, [tex]l[/tex] = ?

Solution:

First of all, let us learn the formula for surface area of a rectangular prism.

Formula for surface area of a prism is given as:

[tex]A=2(wl+hl+hw)[/tex]

As there are 6 faces, each face is a rectangle and area of all the faces is considered in the formula. It is just like a cuboid like structure.

Putting all the given values in the formula to find the value of [tex]l[/tex]:

[tex]992=2(8l+12l+8 \times 12)\\\Rightarrow 496 = 20l + 96\\\Rightarrow 20 l =496-96\\\Rightarrow 20 l =400\\\Rightarrow l = \dfrac{400}{20}\\\Rightarrow l = 20\ inches[/tex]

So, the answer is Thickness of rectangle prism is 20 inches.

Answer:

a.  $75.60

b.  $1335.60

Step-by-step explanation:

A.  First convert the percentage to a decimal.

6% = 0.06

Multiply the cost of the computer by the decimal to find the tax paid.

$1260 × 0.06 = $75.60

B.  To find the total cost, add the cost of the computer with the tax.

$1260 + $75.60 = $1335.60

Answer:

[tex]\boxed{\sf Option \ E}[/tex]

Step-by-step explanation:

(1) 3.25 kg

(2) 1 kg = 1000 g

(3) 1000 mg = 1g

= (4) 3.25 mg

The first problem occurred in column (4) where we actually had to multiply it by 1000 but we divided it by 1000 and so our conversion was incorrect.

The correct form of it is:

1) 3.25 kg

2) 1 kg = 1000 g ; 3.25 kg = 3250 g

3) 1 g = 1000 mg ; 3250 * 1000 = 3,250,000 mg

4) Answer = 3,250,000 mg

Answer:

[tex]\boxed{\sf Option \ E}[/tex]

Step-by-step explanation:

1 kg = 1000 g

1000 mg = 1g

3.25 kilograms is to be multiplied by 1000 to get the value in grams. Then the result should be multiplied again by 1000 to get the value in milligrams.

3.25 kg ⇒ 3250 g ⇒ 3250000 mg

The first problem occurs in column (4). The multiplication and division was performed incorrectly.

Answer:

Sample size

Step-by-step explanation:

Central Limit Theorem states that population with mean and standard deviation and if the sample size is large then the distribution of sample mean will be will be normally distributed. The central limit theorem holds assumptions that the factors to be considered when assessing central limit theorem is sample size.

The CLT is the factor(s) to be considered when assessing if the central theorem holds are sample.

It is given that the objective that central limit theorem assumptions. the factor(s) to be considered when assessing if the central theorem holds.

It is required to describe the above theorem.

It is defined as the in statistics the assumption holds that the sample means distribution of arbitrary variables follows a normal distribution or close to normal distribution if the sample size is big.

We have an objective:

The CLT is the factor to be considered when assessing if the CLT holds a large sample size.

If we draw the random sample data and its measures, the Central limit theorem explains the distribution will explain the normal bell curve, the mean of the parameters and the distribution will be the same.

Thus, the CLT is the factor(s) to be considered when assessing if the central theorem holds are sample.

Learn more about the Central limit theorem here:

https://brainly.com/question/5027686

Answer:

Interval notation is

[tex]\left(-\infty, -5\right)\cup \left(0,1)[/tex]

Solutions:

[tex]\left(-\infty, -5\right)[/tex]

[tex]\left(0,1)[/tex]

Step-by-step explanation:

[tex]x^3 + 4x^2 - 5x < 0[/tex]

In this inequality, luckly we can easily factor it.

[tex]x^3 + 4x^2 - 5x[/tex]

[tex]x(x^2+4x-5)[/tex]

[tex]x(x-1)(x+5)[/tex]

So we have

[tex]x(x-1)(x+5)<0[/tex]

In exercises of this kind I usually do in my mind, but just to make it clear, let's do a table to organize. This table represents the x-intercepts in order to evaluate the inequality.

Consider [tex]x(x-1)(x+5)=0[/tex]. Here, those are the possible values for [tex]x[/tex] for each factor to be 0:

The first step to complete the table is the x value where the factor will be equal to zero.

       [tex]x<-5[/tex]       [tex]x=5[/tex]         [tex]-5<x<0[/tex]        [tex]x=0[/tex]      [tex]0<x<1[/tex]      [tex]x=1[/tex]      [tex]x>1[/tex]                                                                  

[tex]x[/tex]                                                                        0

[tex]x-1[/tex]                                                                                                    0        

[tex]x+5[/tex]                      0

Then, just consider the signal:

  [tex]x<-5[/tex]       [tex]x=5[/tex]         [tex]-5<x<0[/tex]        [tex]x=0[/tex]      [tex]0<x<1[/tex]      [tex]x=1[/tex]      [tex]x>1[/tex]                                                                  

[tex]x[/tex]    -                -                       -                   0               +                 +             +

[tex]x-1[/tex]  -             -                      -                   -               -                  0             +

[tex]x+5[/tex]  -             0                     +                   +                +               +              +

[tex]x(x-1)(x+5)[/tex]    -     0       +     0      -      0     +

When [tex]x(x-1)(x+5)<0[/tex] ?

It happens when [tex]x<-5[/tex]     and when [tex]0<x<1[/tex]

The solution is

[tex]\{x \in \mathbb{R} | x<-5 \text{ or } 0<x<1 \}[/tex]

[tex]\left(-\infty, -5\right)\cup \left(0,1)[/tex]