Answers
Answer:
the first one has one solution because eventually they will cross
Related Questions
30% of a number is 45 what is the number ?
Answers
Hey there! I'm happy to help!
When talking about percents, the word "is" usually means equals. Let's use this to solve an equation! We will call our number n. Note that 30% is equal to 0.3 in decimal form because 0.3 is 30% of one! :D
0.3n=45
To solve, we need to isolate the n. To do this, we divide both sides by 0.3 because this cancels out the 0.3 that is being multiplied by n and it shows us what n will then equal.
0.3n÷0.3=45÷0.3
n=150
Therefore, 30% of 150 is 45. Try multiplying 0.3 by 150 and you will get 45!
Have a wonderful day! :D
the hypotnuse of a 45 -45 -90 triangle measures 22√2 units. what is the length of the leg of the triangle?
Answers
Answer:
22 units.
Step-by-step explanation:
In 45- 45- 90 triangles, there is a 1 to 1 to the square root of 2 formula. Each side length measures 1x, while the hypotenuse measures x times the square root of 2.
In this case, the hypotenuse measures 22 and the square root of 2 units. To find the value of x, simply divide that by the square root of 2 units, and you get x = 22 units. Multiply that by 1, and you get 22 units, which is the length of the leg of the triangle.
Hope this helps!
Check all that apply. If tan theta = 15/8 then:
Answers
Answer:
B, C, D
Step-by-step explanation:
if tan theta = 15/8 then the hypotenuse is 17
therefore the correct answers are B, C, D
Find the greatest number of children to whom 125 pens 175 pencil can be divided equally.
Answers
Answer:
25 children
So , each child will get 25 pens and 7 pencils
You have to find the highest common factor of 125 and 175 which is 25 and then you have to multiply it by those two numbers to find how may pens and pencils will be given to 1 child
Hope this helps and pls mark as brianliest :)
What is 1/9 of 63% of 6000?
Answers
Answer:
420
Step-by-step explanation:
To find 63% of 6000, we can do 0.63 * 6000 = 3780 because 63% = 0.63.
1/9th of that is 1/9 * 3780 = 420.
Answer:
420
Step-by-step explanation:
Let's first start by finding 63% of 6000 so we can later find 1/9 of that number.
We can set up a percentage proportion.
[tex]\frac{x}{6000} = \frac{63}{100}[/tex]
[tex]6000\cdot63=378000\\378000\div100 = 3780[/tex]
Now to find 1/9 of 3780.
[tex]\frac{1}{9} \cdot \frac{3780}{1}\\\\\frac{3780}{9} = 420[/tex]
So, the answer is 420.
Hope this helped!
In the article, Attitudes About Marijuana and Political Views (Psychological Reports, 1973), researchers reported on the use of cannabis by liberals and conservatives during the 1970's. To test the claim (at 1% significance) that the proportion of voters who smoked cannabis frequently was lower among conservatives, the hypotheses were
Answers
Answer:
Option B.
Step-by-step explanation:
According to the question, the data provided is as follows
[tex]H_o : p_1 - p_2 = 0\ (p_1 = p_2)\\\\ H_\alpha : p_1 - p_2 < 0\ (p_1 < p_2)[/tex]
Based on the above information,
The type ii error is the error in which there is an acceptance of a non rejection with respect to the wrong null hypothesis. The type I error refers to the error in which there is a rejection of a correct null hypothesis and the type II refers that error in which it explains the failure of rejection with respect to null hypothesis that in real also it is wrong
So , the type II error is option B as we dont create any difference also the proportion is very less
Solve and CHECK the following: 2(a−3)/3=4
Answers
Answer:
2(a - 3). = 4
_______
3
Cross multiply.
2(a- 3) = 12
2a - 6 = 12
2a = 12 + 6
2a = 18
a = 18 ÷ 2
a = 9
Answer:
a = 9
Step-by-step explanation:
Given
[tex]\frac{2(a-3)}{3}[/tex] = 4 ( multiply both sides by 3 to clear the fraction
2(a - 3) = 12 ( divide both sides by 2 )
a - 3 = 6 ( add 3 to both sides )
a = 9
As a check substitute a = 9 into the left side of the equation and if equal to the right side then it is the solution.
[tex]\frac{2(9-3)}{3}[/tex] = [tex]\frac{2(6)}{3}[/tex] = [tex]\frac{12}{3}[/tex] = 4 = right side
Thus solution is a = 9
There are 25 students in Mr. Jones’ art class. Mr. Jones is planning a project where each student needs 0.3 jar of paint. Exactly how much paint does Mr. Jones need for the art project?
Answers
Answer:
7.5 jars
Step-by-step explanation:
There are 25 students in the art class.
Mr Jones is planning that for the project, each of the 25 students will need 0.3 jar of paint.
The amount of paint Mr Jones needs for this project is therefore the product of the number of students in the class by the amount of paint each student needs.
That is:
25 * 0.3 = 7.5 jars of paint
Mr Jones needs 7.5 jars of paint for the art project.
Graph [tex]y=\frac{2}{3} x[/tex] Which of the following statements are true?
Answers
Answer:
A,C,D
Step-by-step explanation:
When b=0, there is a proportional relationship.
The slope in y=mx+b is the value next to x.
Using RISE/RUN when there is a change of 3 units in x, there is a change of 2 units in y.
Determine the parent function.
Answers
Answer:
y= [tex]\sqrt{x}[/tex]
Step-by-step explanation:
The first three steps in determining the solution set of the system of equations algebraically are shown.
y = x2 − x − 3
y = −3x + 5
What are the solutions of this system of equations?
(−2, −1) and (4, 17)
(−2, 11) and (4, −7)
(2, −1) and (−4, 17)
(2, 11) and (−4, −7)
Answers
Answer:
(2, −1) and (−4, 17)
Step-by-step explanation:
I used a graphing tool to graph the systems of equations. The parabola and line pass at points (2, -1) and (-4, 17).
Answer:(2, −1) and (−4, 17) Its C on Edge 2023
Step-by-step explanation: Its (C) after an extensive research
Please answer this question now
Answers
Answer:
541.4 m²
Step-by-step Explanation:
Step 1: find m < V
V = 180 - (50+63) (sum of the angles in ∆)
V = 67
Step 2: find side length of XW using the law of sines
[tex] \frac{XW}{sin(V)} = \frac{XV}{sin(W)} [/tex]
Where,
V = 67°
W = 63°
XV = 37 m
XW
[tex] \frac{XW}{sin(67)} = \frac{37}{sin(63)} [/tex]
Multiply both sides by sin(67) to solve for XW
[tex] \frac{XW}{sin(67)}*sin(67) = \frac{37}{sin(63)}*sin(67) [/tex]
[tex] XW = \frac{37*sin(67)}{sin(63)} [/tex]
[tex] XW = 38.2 m [/tex] (to nearest tenth)
Step 3: find the area using the formula, ½*XW*XV*sin(X)
area = ½*38.2*37*sin(50)
Area = 541.4 m² (rounded to the nearest tenth.
¡Ayuda!
1. Método del Triángulo: Una embarcación navega a una distancia de 800 km hacia el Oeste y después avanza 1400 km a 135 °. ¿Cuál es la magnitud, dirección y sentido del desplazamiento resultante? R /. 2,080 km, 155 ° NO.
Answers
Answer:
La magnitud del desplazamiento resultante es 2045.463 kilómetros. La dirección absoluta del desplazamiento resultante es 151.055º, el cual corresponde al sentido noroeste.
Step-by-step explanation:
En primer lugar, se construye el triángulo. La figura resultante se encuentra incluida como archivo adjunto. La magnitud del desplazamiento resultante se determina mediante la Ley del Coseno:
[tex]r = \sqrt{(800\,km)^{2}+(1400\,km)^{2}-2\cdot (800\,km)\cdot (1400\,km)\cdot \cos 135^{\circ}}[/tex]
[tex]r \approx 2045.463\,km[/tex]
La magnitud del desplazamiento resultante es 2045.463 kilómetros.
La dirección del desplazamiento resultante es hallada por medio de la Ley del Seno, sabiendo que el ángulo del desplazamiento resultante a la recta de 1400 kilómetros:
[tex]\frac{1400\,km}{\sin \alpha} = \frac{2045.463\,km}{\sin 135^{\circ}}[/tex]
Se despeja el ángulo correspondiente:
[tex]\alpha = \sin^{-1}\left(\frac{1400\,km}{2045.463\,km}\times \sin 135^{\circ} \right)[/tex]
[tex]\alpha \approx 28.945^{\circ}[/tex]
La dirección absoluta del desplazamiento resultante es:
[tex]\alpha' = 180^{\circ}-\alpha[/tex]
[tex]\alpha' = 180^{\circ}-28.945^{\circ}[/tex]
[tex]\alpha' = 151.055^{\circ}[/tex]
La dirección absoluta del desplazamiento resultante es 151.055º, el cual corresponde al sentido noroeste.
Show that (a - b)+(b-c)+(c -a)3 = 3 (a - b) (b -c) (c-a)
Answers
Answer:
I think that it should be
[tex] {(a - b)}^{3} + {(b - c)}^{3} + {(c - a)}^{3} = 3(a - b)(b - c)(c - a)[/tex]
Step-by-step explanation:
Here,
we take , a - b = A,b-c = B , c - a= C
A+B+C = 0
we know that,
[tex] {a}^{3} + {b}^{3} + {c}^{3} - 3abc = (a + b + c)( {a}^{2} + {b}^{2} + {c}^{2} - ab - bc - ca)[/tex]
Here , A+B+C = 0
so,
A^3 +B^3 + C^3 = 3 ABC
now we put the values
[tex]{(a - b)}^{3} + {(b - c)}^{3} + {(c - a)}^{3} = 3(a - b)(b - c)(c - a)[/tex]
I am done .
I think that it should be
{(a - b)}^{3} + {(b - c)}^{3} + {(c - a)}^{3} = 3(a - b)(b - c)(c - a)
Step-by-step explanation:
Here,
we take , a - b = A,b-c = B , c - a= C
A+B+C = 0
we know that,
{a}^{3} + {b}^{3} + {c}^{3} - 3abc = (a + b + c)( {a}^{2} + {b}^{2} + {c}^{2} - ab - bc - ca)
Here , A+B+C = 0
so,
A^3 +B^3 + C^3 = 3 ABC
now we put the values
{(a - b)}^{3} + {(b - c)}^{3} + {(c - a)}^{3} = 3(a - b)(b - c)(c - a)
I am done .
will mark brainliest!!!plz helppp
Answers
Answer:
(5,-6)
Step-by-step explanation:
ONE WAY:
If [tex]f(x)=x^2-6x+3[/tex], then [tex]f(x-2)=(x-2)^2-6(x-2)+3[/tex].
Let's simplify that.
Distribute with [tex]-6(x-2)[/tex]:
[tex]f(x-2)=(x-2)^2-6x+12+3[/tex]
Combine the end like terms [tex]12+3[/tex]:
[tex]f(x-2)=(x-2)^2-6x+15[/tex]
Use [tex](x-b)^2=x^2-2bx+b^2[/tex] identity for [tex](x-2)^2[/tex]:
[tex]f(x-2)=x^2-4x+4-6x+15[/tex]
Combine like terms [tex]-4x-6x[/tex] and [tex]4+15[/tex]:
[tex]f(x-2)=x^2-10x+19[/tex]
We are given [tex]g(x)=f(x-2)[/tex].
So we have that [tex]g(x)=x^2-10x+19[/tex].
The vertex happens at [tex]x=\frac{-b}{2a}[/tex].
Compare [tex]x^2-10x+19[/tex] to [tex]ax^2+bx+c[/tex] to determine [tex]a,b,\text{ and } c[/tex].
[tex]a=1[/tex]
[tex]b=-10[/tex]
[tex]c=19[/tex]
Let's plug it in.
[tex]\frac{-b}{2a}[/tex]
[tex]\frac{-(-10)}{2(1)}[/tex]
[tex]\frac{10}{2}[/tex]
[tex]5[/tex]
So the [tex]x-[/tex] coordinate is 5.
Let's find the corresponding [tex]y-[/tex] coordinate by evaluating our expression named [tex]g[/tex] at [tex]x=5[/tex]:
[tex]5^2-10(5)+19[/tex]
[tex]25-50+19[/tex]
[tex]-25+19[/tex]
[tex]-6[/tex]
So the ordered pair of the vertex is (5,-6).
ANOTHER WAY:
The vertex form of a quadratic is [tex]a(x-h)^2+k[/tex] where the vertex is [tex](h,k)[/tex].
Let's put [tex]f[/tex] into this form.
We are given [tex]f(x)=x^2-6x+3[/tex].
We will need to complete the square.
I like to use the identity [tex]x^2+kx+(\frac{k}{2})^2=(x+\frac{k}{2})^2[/tex].
So If you add something in, you will have to take it out (and vice versa).
[tex]x^2-6x+3[/tex]
[tex]x^2-6x+(\frac{6}{2})^2+3-(\frac{6}{2})^2[/tex]
[tex](x+\frac{-6}{2})^2+3-3^2[/tex]
[tex](x+-3)^2+3-9[/tex]
[tex](x-3)^2+-6[/tex]
So we have in vertex form [tex]f[/tex] is:
[tex]f(x)=(x-3)^2+-6[/tex].
The vertex is (3,-6).
So if we are dealing with the function [tex]g(x)=f(x-2)[/tex].
This means we are going to move the vertex of [tex]f[/tex] right 2 units to figure out the vertex of [tex]g[/tex] which puts us at (3+2,-6)=(5,-6).
The [tex]y-[/tex] coordinate was not effected here because we were only moving horizontally not up/down.
Consider this system of equations. Which equation represents the first equation written in slope-intercept form? 5 x minus 2 y = 10. Y = one-fourth x + 1.
Answers
Answer:
[tex]y = \frac{5x}{2} - 5[/tex]
Step-by-step explanation:
Given the equation 5x - 2y = 10, to write the equation in slope-intercept form, we need to write it in the standard format y = mx+c where m is the slope/gradient and c is the intercept.
From the equation given 5x - 2y = 10, we will make y the subject of the formula as shown;
[tex]5x - 2y = 10\\\\subtract \ 5x \ from \ both \ sides\\\\5x - 2y - 5x = 10 - 5x\\\\-2y = 10-5x\\\\Dividing \ both \ sides\ by \ -2;\\\\\frac{-2y}{-2} = \frac{10-5x}{-2}\\ \\[/tex]
[tex]y = \frac{10}{-2} - \frac{5x}{-2} \\\\y = -5 + \frac{5x}{2}\\\\y = \frac{5x}{2} - 5[/tex]
Hence the equation that represents the first equation written in slope-intercept form is [tex]y = \frac{5x}{2} - 5[/tex]
Find the value of x in the
following parallelogram:
2x - 10
2x + 50
Answers
Answer:
The value of x is 35
Step-by-step explanation:
In order to calculate the value of x in the following parallelogram: 2x - 10
2x + 50, we would have to calculate the following formula:
m<QPS+m<PQR=180°
According to the given data we have the following:
m<QPS=2x - 10
m<PQR=2x + 50
Therefore, 2x - 10+2x + 50=180
4x+40=180
x=140/4
x=35
Write an equation of the line that passes through the point (–4, 6) with slope –4.
Answers
Answer:
y = - 4x - 10
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = - 4 , thus
y = - 4x + c ← is the partial equation
To find c substitute (- 4, 6) into the partial equation
6 = 16 + c ⇒ c = 6 - 16 = - 10
y = - 4x - 10 ← equation of line
Answer:
y = -4x+10
Step-by-step explanation:
Using the slope intercept form of a line
y = mx+b where m is the slope and b is the y intercept
y = -4x +b
Substituting the point in
6 = -4(-4) + b
6 = 16+b
Subtract 16 from each side
-10 =b
The equation is
y = -4x+10
Find the midline for f(x)=2cos(3x−5π6)−2
Answers
Answer: y = -2
Step-by-step explanation:
f(x) = A cos (Bx - C) + D
↓
center line (aka midline)
f(x) = 2 cos (3x - 5π/6) - 2
↓
midline = -2
The midline of the cos function f(x) = 2cos(3x − 5π/6) − 2 is y = -2 after comparing with standard cos function f(x) = Acos(Bx - C) + D
What is cos function?It is defined as a function that is sin-cos wave in nature, and it has a domain of all real numbers and lies between the [a, a] where is the amplitude of the function.
It is given that the cos function is:
f(x) = 2cos(3x - 5π/6) - 2
As we know, the standard form of the cos function is:
f(x) = Acos(Bx - C) + D
Here, A is the amplitude
B is the period of the cos function
C is the phase shift of the cos function
D is the vertical shift of the cos function/midline
On comparing:
D = -2
The midline:
y = -2
Thus, the midline of the cos function f(x) = 2cos(3x − 5π/6) − 2 is y = -2 after comparing with standard cos function f(x) = Acos(Bx - C) + D
Learn more about the cos function here:
https://brainly.com/question/14397255
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Mark the absolute maximum point of the graph.
is the absolute maximum point (-3,5)?
Answers
Factor x2 - 2x + 3
I have no idea and no one else has done it
Answers
Answer:
prime
Step-by-step explanation:
x^2 - 2x + 3
What two numbers multiply to 3 and add to -2
There are none so this cannot be factored in the real numbers
It is 64º F at the 5000-foot level of a mountain, and 48º F at the 10,000-foot level of the mountain. Write a linear equation, in slope-intercept form, to find the temperature T at an elevation e on the mountain, where e is in thousands of feet.
Answers
Answer:
T = - 3.2e + 80
Step-by-step explanation:
Given the following :
e = elevation in thousands of feets
T = temperature (°F)
e1 = 5 ; e2 = 10 (in thousands of feet)
T1 = 64° ; T2 = 48°
y = mx + c ; T = me + c
y = ; m = slope, c = intercept
64 = m5 + c - - - - (1)
48 = m10 + c - - - - (2)
From (1)
c = 64 - m5
Substitute c = 64 - m5 into (2)
48 = m10 + c - - - - (2)
48 = m10 + 64 - m5
48 - 64 = 10m - 5m
-16 = 5m
m = - 16 / 5
m = - 3.2
Substitute the value of m into c = 64 - m5
c = 64 - 5(-3.2)
c = 64 - (-16)
c = 64 + 16
c = 80
Inserting our c and m values into T = me + c
T = - 3.2e + 80
Where e is in thousands of feet
T is in °F
graph itttt plssssss
Answers
━━━━━━━☆☆━━━━━━━
▹ Answer
You can use a graphing calculator. Attached is a picture of it graphed.
Hope this helps!
CloutAnswers ❁
Brainliest is greatly appreciated!
━━━━━━━☆☆━━━━━━━
y=8-2x. What is the value of y when x = 8?
Answers
Because the math problem is y=8-2x8
You multiple 2x8 which equals 16
You are then left with y=8-16
And 8-16 = -8
Answer:
y = -8
Step-by-step explanation:
Start by filling 8 in place of x
y = 8 - 2(8)
Multiply -2(8)
y = 8 - 16
Subtract 16 from 8
y = -8
7. The radius of a cylinder whose curved surface area is 2640 2 and height 21 cm is _________. (a) 100 ° (b) 50° (c) 80° (d) 90°
Answers
Answer:
The answer is 21.25cm
Step-by-step explanation:
Hope i am marked as brainliest
What are the square roots of; (note: i think there are supposed to be 2 each) 36 12 1.96 0.64 400 25/36
Answers
Answer:
36 : 6 and -6
12 = [tex]2\sqrt{3} , -2\sqrt{3}[/tex]
1.96 =1.4 and -1.4
0.64 : 0.8 and -0.8
400 : 20 and -20
25/36 = 5/6 and -5/6
Step-by-step explanation:
we know that
(-x)^2 = x^2
ALSO
(x)^2 = x^2
thus, square of both negative and positive number is same positive number.
_________________________________________________
36 = 6*6
36 = -6*-6
hence
square roots of 36 is both -6 and 6
12 = 4*3 = [tex]2^2*\sqrt{3} *\sqrt{3}[/tex]
[tex]\sqrt{12} = 2\sqrt{3}[/tex]
also
12 = [tex]-2\sqrt{3} *-2\sqrt{3}[/tex]
[tex]\sqrt{12} = -2\sqrt{3}[/tex]
___________________________________
1.96 = 196/100 = (14/10)^2
1.96 = 196/100 = (-14/10)^2
hence
[tex]\sqrt{1.96} = 14/10 \ or -14/10[/tex]
_______________________________
0.64 = 64/100 = (8/10)^2 = 0.8^2
0.64 = 64/100 = (-8/10)^2 = (-0.8)^2
Thus, square root of 0.64 = 0.8 and -0.8
_________________________________
400 = 20^2
400 = (-20)^2
[tex]\sqrt{400} = 20\\\sqrt{400} = -20\\[/tex]
__________________________________
25/36 = (5/6)^2
25/36 = (-5/6)^2
[tex]\sqrt{ 25/36} = 5/6 \\\sqrt{ 25/36} = (-5/6[/tex]
Figure G is rotated 90Degrees clockwise about the origin and then reflected over the x-axis, forming figure H. On a coordinate plane, triangle G has points (negative 3, 1), (negative 1, 2), (negative 2, 5). Triangle H has points (2, negative 1), (1, negative 3), (5, negative 2). Which sequence of transformations will produce the same results?
Answers
Answer:
The 1st selection is appropriate.
_____
2nd: the rotation would need to be 90° CCW
3rd, 4th: rotation or double reflection will give the original orientation. This figure is reflected an odd number of times, so has its orientation reversed.
Hope it helps.. Mark brainliest
The sequence of transformations are reflection over the y-axis and then a rotation 90 clockwise about the origin.
What is rotation rule of 90°?Here are the rotation rules: 90° clockwise rotation: (x, y) becomes (y, -x) 90° counterclockwise rotation: (x, y) becomes (-y, x) 180° clockwise and counterclockwise rotation: (x, y) becomes (-x,-y).
Given that, figure G is rotated 90° clockwise about the origin and then reflected over the x-axis, forming figure H.
Vertices of triangle G are (-3, 1), (-1, 2) and (-2, 5).
The reflection of point (x, y) across the y-axis is (-x, y).
On reflection over x-axis, we get coordinates as (3, 1), (1, 2) and (2, 5)
90° clockwise rotation: (x, y) becomes (y, -x)
On 90° clockwise rotation, we get coordinates as (1, -3), (2, -1) and (5, -2)
Triangle H has points (2, -1), (1, -3), (5, -2).
Hence, the sequence of transformations are reflection over the y-axis and then a rotation 90° clockwise about the origin.
Learn more about the rotation of 90° counterclockwise here:
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This is Algebra 1 functions and I'm struggling with this one function-
-1•f(-9)+7•g(6)=_____
Answers
Answer:
38
Step-by-step explanation:
f(-9) is the value of f(x) when x = -9. Therefore, f(-9) = 4 from the graph. Doing the same with g(6), we can see that g(6) = 6. Our expression becomes:
-1 * 4 + 7 * 6
= -4 + 42
= 38
the shape of a piece is pallelogram whose adjacent side are 12m and 9 m and the corresponding diagonal is 15 .find the area of land
Answers
Answer: The area of land =108 m²
Step-by-step explanation:
In the given piece of land is in the shape of a parallelogram.
Diagonals divide it into 2 equal parts.
So, area of parallelogram = 2 x (Area of triangle with sides 12m and 9 m and 15 m)
Heron's formula :
Area of triangle = [tex]\sqrt{s(s-a)(s-b)(s-c)}[/tex], where [tex]s=\dfrac{a+b+c}{2}[/tex]
Let a= 12 , b= 9 and c = 15
[tex]s=\dfrac{12+9+15}{2}=18[/tex]
Area of triangle = [tex]\sqrt{18(18-12)(18-9)(18-15)}[/tex]
[tex]=\sqrt{18\times6\times9\times3}=\sqrt{2916}=54\ m^2[/tex]
Then, area of parallelogram= 2 x 54 = 108 m²
Hence, the area of land =108 m²
Given the coordinate points of the preimage, use the transformation given to provide the points of the image. E(−5,−1) D(−5,1) C(−1,0) B(−2,−3) Rotation: 180∘ about the origin
Answers
Answer:
The points of the image are;
E'(5, 1), D'(5, -1), C'(1, 0), E'(-2, -3)
Step-by-step explanation:
The coordinates of the preimage are E(-5, -1) D(-5, 1) C(-1, 0) B(-2, -3)
Rotation of a point 180° about the origin gives;
Coordinates of the point of the preimage before rotation = (x, y)
The coordinates of the image after rotation = (-x, -y)
Therefore, the coordinates of the points EDCB after 180° rotation about the origin are;
E(-5, -1) rotated 180° becomes E'(5, 1)
D(-5, 1) rotated 180° becomes D'(5, -1)
C(-1, 0) rotated 180° becomes C'(1, 0)
B(-2, -3) rotated 180° becomes E'(-2, -3).