441-p²=(21)²-(17)²
maths algebra​

Answer:

5.5×5.5=30.5

we rounded 30.25 in nearest tenth it becomes 30

Answer:

C.] 5.5

Step-by-step explanation:

It is mentioned that the number was multiplied by the number itself.

Let's take 'x' as the number. It was multiplied by itself and the product is 30. So the equation will be:

x × x = 30

[tex]x^{2}[/tex] = 30

x = [tex]\sqrt{30}[/tex]

x = 5.47 = 5.5 (to the nearest tenth)

Answer:

SAS

Step-by-step explanation:

ITS CORRECT CUZ SAME ANGLE, AND TWO OF THE SAME SIDES

Answer:

1.1.1) -61

1.1.2) Term 42

Step-by-step explanation:

Tn= dn (difference) + t0 (term 0)

Tn= -4n+ 11

You can now take this general rule to find out the other terms.

Tn= -4(18)+11

Tn= -61

And the term -157

Tn= -4n+11

-157= -4n + 11

-157 - 11= - 4n

-168= -4n

-168/-4= n

42= n

Answer:

[tex]f(x) = 3(x - 1)^2-3[/tex]

Step-by-step explanation:

Given

[tex]f(x) = 3x^2 - 6x + 6[/tex]

Required

Write as:

[tex]f(x) = a(x - h)^2 + k[/tex]

In [tex]f(x) = 3x^2 - 6x + 6[/tex], the coefficient of x is -6

Divide by 2: -3

Square: 9

Add 9 - 9 to the above equation

[tex]f(x) = 3x^2 - 6x +9-9+ 6[/tex]

Split to 2

[tex]f(x) = [3x^2 - 6x +9]-[9- 6][/tex]

[tex]f(x) = [3x^2 - 6x +9]-[3][/tex]

Factorize:

[tex]f(x) = [3x^2 - 3x -3x+9]-[3][/tex]

[tex]f(x) = [3x(x - 1) -3(x-1)]-[3][/tex]

[tex]f(x) = [(3x - 3)(x-1)]-[3][/tex]

Factorize 3x - 3

[tex]f(x) = [3(x - 1)(x-1)]-[3][/tex]

[tex]f(x) = 3(x - 1)^2-[3][/tex]

[tex]f(x) = 3(x - 1)^2-3[/tex]

Answer:

X=75

Y=5X+100

Y=5*75+100

Y=375+100

Y=475

Therefore, you burnt 475 calories if you walked for 75 minutes

Answer:‍♀️

Step-by-step explanation:

Answer:

[tex]q=31.7\\p=28.4[/tex]

Doing all calculations with 3 significant figures.

Step-by-step explanation:

First, we'll obtain the value of 'q', this by realizing how the two angles together form a right triangle with inner angles of 30, 60, 90.

Furthermore, the opposite side of the angle of 30 is 'q' and its adjacent is given as 55. Hence, we can solve for 'q' using tangent as follows:

[tex]tan(30)=\frac{q}{55} =.577[/tex]

We solve for 'q':

[tex]q=.577*55=31.7[/tex]

Now to solve for 'p', we first will calculate what '55-p' is equal to.

First, we realize '55-p' corresponds to the adjacent side to the angle of 50 inside the small right triangle (the one with inner angles of 50, 40, 90) and q (which we now know is 31.7) correspond to the opposite side. Hence, we again use tangent as follows:

[tex]tan(50)=\frac{q}{55-p} =\frac{31.7}{55-p} =1.19[/tex]

We solve for 'p':

[tex]1.19(55-p)=31.7\\65.5-1.19p=31.7\\1.19p=33.8\\p=\frac{33.8}{1.19}=28.4[/tex]

Answer:

5u-15=10 |+15

5u=25 |:5

u=5

The solution is 25

I hope it helps

have anice day

Answer:

scalene triangle

..... .

Answer:

(a) [tex]A = 1500(1 - e^{-0.01t})[/tex]

(b) [tex]t = 0[/tex]

Step-by-step explanation:

Given

[tex]V= 300gal[/tex] --- Volume of tank

[tex]B = 5lb/gal[/tex] --- Brine solution

[tex]R_1 = 3gal/min[/tex]  --- Rate in, in gallon/min

[tex]R_2 = 6gal/min[/tex] --- Rate out, in gallon/min

Required

Determine A(t)

First, calculate the rate in (R in) and (R out) in lb/min

[tex]R_{in} = B * R_1[/tex]

[tex]R_{in} = 5lb/gal * 3gal/min[/tex]

[tex]R_{in} = 15lb/min[/tex]

R(out) is calculated by multiply the rate at which brine leaves the tank (lb/gal) * R2

So, we have:

[tex]R_{out} = \frac{A(t)}{300} lb/gal * 3gal/min[/tex]

[tex]R_{out} = \frac{3*A(t)}{300} lb/min[/tex]

[tex]R_{out} = \frac{A(t)}{100} lb/min[/tex]

The change in the amount of brin e in the tank at time t is given as:

[tex]A'(t) = R_{in} - R_{out}[/tex]

[tex]A'(t) = 15 - \frac{A(t)}{100}[/tex]

Rewrite:

[tex]\frac{dA}{dt} = 15 - \frac{A}{100}[/tex]

Multiply through by dt

[tex]dA = [15 - \frac{A}{100}]* dt[/tex]

Make dt stand alone

[tex]\frac{dA}{15 - \frac{A}{100}} = dt[/tex]

[tex]ln|15 - \frac{A}{100}| = -0.01t + ln\ c[/tex]

Express as exponents

[tex]15 - \frac{A}{100} = ce^{-\frac{t}{100}}[/tex]

Multiply through by 100

[tex]1500 - A = 100ce^{-\frac{t}{100}}[/tex]

[tex]A = 1500 - 100ce^{-\frac{t}{100}}[/tex]

[tex]A = 1500 - 100ce^{-0.01t}[/tex]

Apply initial conditions

[tex]A(0) = 0[/tex]

Substitute 0 for t in: [tex]A = 1500 - 100ce^{-0.01t}[/tex]

[tex]0 = 1500 - 100ce^{-0.01*0}[/tex]

[tex]0 = 1500 - 100ce^{0}[/tex]

[tex]0 = 1500 - 100c[/tex]

[tex]100c = 1500[/tex]

[tex]c = 15[/tex]

Substitute 15 for c in [tex]A = 1500 - 100ce^{-0.01t}[/tex]

[tex]A = 1500 - 100*15e^{-0.01t}[/tex]

[tex]A = 1500 - 1500e^{-0.01t}[/tex]

Factorize:

[tex]A = 1500(1 - e^{-0.01t})[/tex]

How long to empty the tank

Set A to 0

[tex]1500(1 - e^{-0.01t}) = 0[/tex]

Divide through by 1500

[tex]1 - e^{-0.01t} = 0[/tex]

Collect Like Terms

[tex]e^{-0.01t} = 1[/tex]

Take ln of both sides

[tex]ln\ (e^{-0.01t}) = ln\ 1[/tex]

[tex]-0.0t = 0[/tex]

[tex]t = 0[/tex]

Answer:

y = -x - 1

y = 1.5x + 6

(-3, 2)

Step-by-step explanation:

y = mx + b

y-intercepts are plotted on the graph

slope = rise over run

Solution is plotted on the graph

Answer:

the answer is (-3, 2)

value of x = -3

value of y = 2

Answer:

54, 63

Step-by-step explanation:

6 x 9 = 54

7 x 9 = 63

Answer:

it's less than

Step-by-step explanation:

12/8 simplified is 3/2

11/6 cannot be further simplified

3/2<11/6

Answer:

0.03

Step-by-step explanation:

Step-by-step explanation:

4x² - 12x + 9 = 5 → 4x² - 12x + 4 = 0 → x² - 3x + 1 = 0

∆ = b² - 4ac → ∆ = (-3)² -4(1)(1) = 9 - 4 = 5

x = (-(-3) ± √5)/2(1) = (3 ± √5)/2

x² - 3x + 1 = 0 → (x - 3/2)² - 9/4 + 1 = 0 → (x - 3/2)² = 5/4 → x - 3/2 = ±√5 / 2 → x = ½( 3 ± √5)

Answer:

pressure=force/area

2000. ×area =10

area. =10/2000

area =0.005cm²

Answer:

0.9692 = 96.92% probability of getting someone in the 22-29 age bracket or someone who agreed to respond.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Find the probability of getting someone in the 22-29 age bracket or someone who agreed to respond.

357 people.

281 in the 22-29 age bracket + 65 in the 18-21 that agree to respond. So

[tex]p = \frac{281+65}{357} = 0.9692[/tex]

0.9692 = 96.92% probability of getting someone in the 22-29 age bracket or someone who agreed to respond.

Answer:

angle 7

Step-by-step explanation:

Answer:

angle 7 angle forms a pair of alternate

exterior angles with angle 2.

Answer:

Step-by-step explanation:

Answer:

[tex]+\sqrt{55i}[/tex]

Step-by-step explanation:

Khan <3

Answer:

c=5/72

Step-by-step explanation:

5/9=14c-5/12

Switch sides

14c-5/12=5/9

Add 5/12 tp both sides

14c-5/12+5/12=5/9+5/12

Simplify;

14c-5/12+5/12

=14c

Simplify;

5/9+5/12

LCM of 9, 12;

36

The least common multiplier of a, b is the smallest positive number that is divisible by both a and b.

Prime factorization of 9;

3*3

Prime factorization of 12;

2*6

=2*2*3

=3*3*2*2

=36

5/9=5*4/9*4=20/36

5/12=5*3/12*3=15/36

=20/36+15/36

20+15/36

=35/36

14c=35/36

14c/14=35/36/14

14c/14=c

35/36*14

=35/504

=5/72

Answer c=5/72

Answer to the following question is as follows;

Value of C = 5 / 72

Step-by-step explanation:

Given:

[tex]\frac{5}{9} = 14c - \frac{5}{12}\\\\[/tex]

Find:

Value of C

Computation:

[tex]\frac{5}{9} = 14c - \frac{5}{12}\\\\[/tex]

By taking 5/12 to LHS Side

[tex]\frac{5}{9} + \frac{5}{12} = 14c\\\\[/tex]

By taking LCM;

[tex]\frac{(4)(5) + (3)(5)}{36} = 14c\\\\[/tex]

[tex]\frac{20 + 15}{36} = 14c\\\\[/tex]

[tex]\frac{35}{36} = 14c\\\\[/tex]

By transfer 14 to LHS side

[tex]\frac{35}{36 \times 14 } = c\\\\[/tex]

[tex]\frac{5}{36 \times 2 } = c\\\\[/tex]

[tex]\frac{5}{72} = c\\\\[/tex]

Value of C = 5 / 72

Learn more;

https://brainly.com/question/21481562?referrer=searchResults

Answer:

6 / 8 or 3 / 4

Step-by-step explanation:

Subtraction lol

Answer:

80cm2

Step-by-step explanation:

Answer: C 144 BABA

Step-by-step explanation:

Answer:

n=5

Step-by-step explanation:

6n=30

n=30 /÷6

n=5

Answer: 1.7004 × 10^2

Step-by-step explanation: