Chemistry High School

54. Copper(I) sulfide is formed when copper and sulfur are
heated together. In this reaction, 127 g of copper reacts
with 41 g of sulfur. After the reaction is complete, 9 g of
sulfur remains unreacted. What is the mass of copper
sulfide formed?
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Ma

Answers

Answer 1

Answer:

159g

Explanation:

Answer 2

Copper (I) sulfide is formed by the chemical reaction between copper and sulfur. Copper is a limiting reagent that results in the formation of 190.26 grams of copper(I) sulfide.

What is a limiting reagent?

A limiting reagent is defined as the reactant that gets completely utilized in the reaction and affects the amount of the product formation. On the contrary, the excess reagent is present in more amounts.

Given,

Mass of copper = 127 gm

Mass of sulfur = 41 gm

Moles of copper:

n = mass ÷ molar mass

n = 127 ÷ 63.546

n = 1.99

Moles of sulfur:

n = 41 ÷ 32.065

n = 1.27

The reaction is shown as:

Cu + S → CuS

Here, 9 g of sulfur remains unreacted and hence is an excess reagent, and copper being consumed is a limiting reagent.

Here, 1 mole of copper reacts to form 1 mole of copper sulfide hence, 1.99 moles of Cu produces, 1.99 moles of copper sulfide.

Mass of CuS is calculated as:

Mass = moles × molar mass

Mass = 1.99 mol × 95.611 g/mol

= 190.26 grams

Therefore, 127 gm of copper and 41 gm of sulfur produces 190.26 grams of copper sulfide.

Learn more about limiting reagents, here:

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Answers

Answer:

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Explanation:

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