63. Which of the following types of validity is estab-
‘lished by demonstrating that there is a correlation
between scores on a test and later academic
performance?
(A) Content
(B) Predictive
(C) Face
(D) Concurrent
(E) Test-retest
Help I beg someone please help please

Answers

Answer 1

Answer:

Content

Explanation:

The type of validity that is established by demonstrating a correlation between scores on a test and later academic performance is known as CONTENT VALIDITY

The above statement is true because Content validity is a form of validity testing used to assess whether the outcome of a test is a precise measure of the fundamental aspect or domain of the construct.

Hence, to provide a credible result, content validity ensures it covers all suitable parts of the content or topic it attempts to measure.


Related Questions

Please select the word from the list that best fits the definition
location of most volcanoes

Island arc
Lava
Basalt
Magma
Hotspot
Plate boundaries

Answers

Answer:

The answer is E., or "Plate Boundaries".

The word best describes the definition of the location of volcanoes is "plate boundaries". Therefore, option (E) is correct.

What are plate boundaries?

The lithosphere is broken into tectonic plates that undergo some large motions and the boundary regions between plates are called plate boundaries. Based on their motions there are three kinds of plate boundaries: divergent, convergent, and transform.

Divergent boundaries are moving away from one another and separate, they form a rift. As the gap widens, the underlying layer may be soft for molten lava underneath to push upward and resulting in the formation of volcanic islands.

Convergent boundaries move towards one another and collide, subduction usually takes place. The denser plate goes underneath the less dense one and the plate boundaries also experience buckling.

Transform boundaries slide alongside one another and are exposed to huge amounts of stress and strain and are momentarily held in place. The two plates succeed in moving with respect to one another and cause earthquakes.

Learn more about plate boundaries, here:

https://brainly.com/question/18256552

#SPJ5

If you dropped a ball off the roof, and could neglect air resistance, the impact velocity of the ball on the sidewalk would be 102 miles per hour [mph]. Calculate the height of the building in units of feet.

Answers

Answer:

h = 105.98 m

Explanation:

We will use the third equation of motion here:

[tex]2gh= v_f^2-v_i^2[/tex]

where,

g = acceleration due to gravity = 9.81 m/s²

h = height = ?

vf = final speed = (102 mi/h)(1 h/3600 s)(1609.34 m/1 mi) = 45.6 m/s

vi = initial speed = 0 m/s

Therefore,

[tex]2(9.81\ m/s^2)h = (45.6\ m/s)^2-(0\ m/s)^2\\\\h = \frac{ (45.6\ m/s)^2}{2(9.81\ m/s^2)}[/tex]

h = 105.98 m

A p-n junction diode is, as the name suggests, an electronic device that is made up of a p-type semiconductor and an n-type semiconductor joined together.

a. True
b. False

Answers

Answer:

a. True

Explanation:

When a p-type semiconductor is placed adjacent to an n-type semiconductor  the common plane thus formed is termed as P-N Junction or  P-N Junction Diode.

The diode is formed by melting both p-type and n-type semiconductors through a special manufacturing process called "Thermo-Compression Proces".

The P-N junction has a property of one-way conduction. It means it only allows the current to pass through it in one direction and the current flow is practically zero in the other direction. Thus, it can act as a diode. The p-side acts as the anode, while the n-side acts as the cathode.

Hence, the correct option is:

a. True

A 10kg block is Pulled along a horizontal
Surface by a force
of 50N at an angles
of 37° with the horizontal If the
coefficient of sliding friction b/n the
block and the surface is o.2
(g=10m/s^2 Sin 37=O.6 and cos 37 = 0.8)
A, what frictional forces acting on the block?
B,what is the acceleration of the block?​

Answers

Answer:

hope u can understand the method

A solenoid that is 66.2 cm long has a cross-sectional area of 18.0 cm2. There are 1300 turns of wire carrying a current of 8.15 A. (a) Calculate the energy density of the magnetic field inside the solenoid. (b) Find the total energy in joules stored in the magnetic field there (neglect end effects).

Answers

Answer:

(a) Energy Density = 160.94 J/m³

(b) Energy Stored = 0.192 J

Explanation:

(a)

The energy density of the magnetic field inside the solenoid is given by the following formula:

[tex]Energy\ Denisty = \frac{B^2}{2\mu_o}\\[/tex]

where,

B = magnetic field strength of solenoid = [tex]\frac{\mu_oNI}{l}[/tex]

Therefore,

[tex]Energy\ Density = \frac{\mu_oN^2I^2}{2l^2}[/tex]

where,

μ₀ = permeability of free space = 4π x 10⁻⁷ N/A²

N = No. of turns = 1300

I = current = 8.15 A

L = length = 66.2 cm = 0.662 m

Therefore,

[tex]Energy\ Density = \frac{(4\pi\ x\ 10^{-7}\ N/A^2)(1300)^2(8.15\ A)^2}{2(0.662\ m)^2}[/tex]

Energy Density = 160.94 J/m³

(b)

Energy Stored = (Energy Density)(Volume)

Energy Stored = (Energy Density)(Area)(L)

Energy Stored = (160.94 J/m³)(0.0018 m²)(0.662 m)

Energy Stored = 0.192 J

What cycle moves carbon from one part of the Earth to another

Answers

Answer:

The cycle that moves carbon from one part of the Earth to another is called the carbon cycle.

Explanation:

     The carbon cycle describes the process in which carbon atoms continually travel from the atmosphere to the Earth and then back into the atmosphere. Since our planet and its atmosphere form a closed environment, the amount of carbon in this system does not change. Where the carbon is located — in the atmosphere or on Earth — is constantly in flux.

     On Earth, most carbon is stored in rocks and sediments, while the rest is located in the ocean, atmosphere, and in living organisms. These are the reservoirs, or sinks, through which carbon cycles. Carbon is released back into the atmosphere when organisms die, volcanoes erupt, fires blaze, fossil fuels are burned, and through a variety of other mechanisms. In the case of the ocean, carbon is continually exchanged between the ocean’s surface waters and the atmosphere, or is stored for long periods of time in the ocean depths.

     Humans play a major role in the carbon cycle through activities such as the burning of fossil fuels or land development. As a result, the amount of carbon dioxide in the atmosphere is rapidly rising; it is already considerably greater than at any time in the last 800,000 years.

A 34-kg child runs with a speed of 2.8 m/s tangential to the rim of a stationary merrygo-round. The merry-go-round has a momentum of inertia of 510 kg*m2 and a radius of 2.31 m. When the child jumps onto the merry-go-round, the entire system begins to rotate. What is the angular speed of the system

Answers

Answer: [tex]0.43\ rad/s[/tex]

Explanation:

Given

Mass of child [tex]m=34\ kg[/tex]

speed of child is [tex]v=2.8\ m/s[/tex]

Moment of inertia of merry go round is [tex]I=510\ kg.m^2[/tex]

radius [tex]r=2.31\ m[/tex]

Conserving the angular momentum

[tex]\Rightarrow mvr=I\omega \\\Rightarrow 34\times 2.8\times 2.31=510\times \omega\\\\\Rightarrow \omega=\dfrac{219.912}{510}\\\Rightarrow \omega=0.43\ rad/s[/tex]

In the physics lab, a block of mass M slides down a frictionless incline from a height of 35cm. At the bottom of the incline it elastically strikes another block that is only one-half its mass. Find the velocity of block M at the bottom of the incline before the collision with the small block m.

Answers

Solution :

Given :

M = 0.35 kg

[tex]$m=\frac{M}{2}=0.175 \ kg$[/tex]

Total mechanical energy = constant

or [tex]$K.E._{top}+P.E._{top} = K.E._{bottom}+P.E._{bottom}$[/tex]

But [tex]$K.E._{top} = 0$[/tex] and [tex]$P.E._{bottom} = 0$[/tex]

Therefore, potential energy at the top = kinetic energy at the bottom

[tex]$\Rightarrow mgh = \frac{1}{2}mv^2$[/tex]

[tex]$\Rightarrow v = \sqrt{2gh}$[/tex]

      [tex]$=\sqrt{2 \times 9.8 \times 0.35}$[/tex]      (h = 35 cm = 0.35 m)

      = 2.62 m/s

It is the velocity of M just before collision of 'm' at the bottom.

We know that in elastic collision velocity after collision is given by :

[tex]$v_1=\frac{m_1-m_2}{m_1+m_2}v_1+ \frac{2m_2v_2}{m_1+m_2}$[/tex]

here, [tex]$m_1=M, m_2 = m, v_1 = 2.62 m/s, v_2 = 0$[/tex]

∴ [tex]$v_1=\frac{0.35-0.175}{0.5250}+\frac{2 \times 0.175 \times 0}{0.525}[/tex]

      [tex]$=\frac{0.175}{0.525}+0$[/tex]

     = 0.33 m/s

Therefore, velocity after the collision of mass M = 0.33 m/s

 

On a distance-time graph, what is shown when the curve is flat going from left to the right?

A. a negative speed
B. no speed
C. a positive speed
D. It does not mean anything.

Please help me !!im on a test

Answers

The answer is B. No speed

An object whose weight is 100 lbf experiences a decrease in kinetic energy of 500 ft-lbf and an increase in potential energy of 1500 ft-lbf. The initial velocity and elevation of the object, each relative to the surface of the earth, are 40 ft/s and 30 ft, respectively.

Required:
a. Find final velocity in ft/s.
b. Find final elevation.

Answers

Answer:

a) the final velocity is 35.75 ft/s

b) The final elevation is 45 ft

Explanation:

Given the data in the question;

Weight of object; W = 100 lbf

Change in kinetic energy; ΔE = 500 ft-lb

so

[tex]\frac{1}{2}[/tex]m[tex]v_i^2[/tex] - [tex]\frac{1}{2}[/tex]m[tex]v_f^2[/tex] = ΔE

[tex]\frac{1}{2}[/tex]m[tex]v_i^2[/tex] - [tex]\frac{1}{2}[/tex]m[tex]v_f^2[/tex] = 500

multiply both sides by 2

m[tex]v_i^2[/tex] - m[tex]v_f^2[/tex] = 1000

m( [tex]v_i^2[/tex] - [tex]v_f^2[/tex] ) = 1000

[tex]v_i^2[/tex] - [tex]v_f^2[/tex] = 1000/m

[tex]v_i^2[/tex] - [tex]v_f^2[/tex] = (1000)(g) / W

we know that, acceleration due to gravity g = 9.8 m/s² = 32.18 ft/s²

so we substitute

[tex]v_i^2[/tex] - [tex]v_f^2[/tex] = (1000)(32.18) / 100

[tex]v_i^2[/tex] - [tex]v_f^2[/tex] = (1000)(32.18) / 100

[tex]v_i^2[/tex] - [tex]v_f^2[/tex] = 32180 / 100

[tex]v_i^2[/tex] - [tex]v_f^2[/tex] = 321.8

since The initial velocity [tex]v_i[/tex] is given to be 40 ft/s;

(40)² - [tex]v_f^2[/tex] = 321.8

1600 - [tex]v_f^2[/tex] = 321.8

[tex]v_f^2[/tex] = 1600 - 321.8

[tex]v_f^2[/tex] = 1278.2

[tex]v_f[/tex] = √1278.2

[tex]v_f[/tex] = 35.75 ft/s

Therefore, the final velocity is 35.75 ft/s

b)

we know that;

change in potential energy is;

ΔP.E = mg( h[tex]_f[/tex] - h[tex]_i[/tex] )

given that; increase in potential energy; ΔP.E = 1500 ft-lbf

and mg = Weight = 100 lbf

we substitute

1500  = 100( h[tex]_f[/tex] - h[tex]_i[/tex] )

h[tex]_f[/tex] - h[tex]_i[/tex] = 1500 / 100

h[tex]_f[/tex] - h[tex]_i[/tex] = 15 ft

given that, elevation of the object; h[tex]_i[/tex] = 30 ft

h[tex]_f[/tex] - 30 ft = 15 ft

h[tex]_f[/tex] = 15 ft + 30 ft

h[tex]_f[/tex] = 45 ft

Therefore, The final elevation is 45 ft

Types of government

Answers

Answer:

Explanation:

The different types of government include a direct democracy, a representative democracy, socialism, communism, a monarchy, an oligarchy, and an autocracy

Direct democracy a representative democracy,socialism,communism,a monarchy,an oligarchy and an autocracy

what is the maximum distance we can shoot a dart,from ground level provided our toy dart gun gives a maximum initial velocity of 2.7m/s and air resistance is negligible​

Answers

Answer:

R = v^2 sin 2 theta / g

The range provides the distance a projectile can travel

R(max) = v^2 / g    if theta = 45 deg

R = 2.7^2 / 9.8 = .74 m

A 4.00-kg block hangs by a light string that passes over a massless, frictionless pulley and is connected to a 6.00-kg block that rests on a frictionless shelf. The 6.00-kg block is pushed against a spring to which it is not attached. The spring has a spring constant of 180 N/m, and it is compressed by 30.0 cm. Find the speed of the block after the spring is released and the 4.00-kg block has fallen a distance of 40.0 cm.

Answers

Answer:

v = 2.82 m/s

Explanation:

For this exercise we can use the conservation of energy relations.

We place our reference system at the point where block 1 of m₁ = 4 kg

starting point. With the spring compressed

        Em₀ = K_e + U₂ = ½ k x² + m₂ g y₂

final point. When block 1 has descended y = - 0.400 m

        Em_f = K₂ + U₂ + U₁ = ½ m₂ v² + m₂ g y₂ + m₁ g y

as there is no friction, the energy is conserved

       Em₀ = Em_f

       ½ k x² + m₂ g y₂ = ½ m₂ v² + m₂ g y₂ + m₁ g y

       ½ k x² - m₁ g y = ½ m₂ v²

 

       v² = [tex]\frac{k}{m_2} x^2 - 2 \frac{m_1}{m_2} \ g y[/tex]

let's calculate

        v² = [tex]\frac{180}{6.00} \ 0.300^2 - 2 \ \frac{4.00}{6.00} \ 9.8 \ (- 0.400)[/tex]

        v² = 2.7 + 5.23

        v = √7.927

        v = 2,815 m / s

using of significant figures

        v = 2.82 m/s

The Equipartition Theorem follows from the fundamental postulate of statistical mechanics--that every energetically accessible quantum state of a system has equal probability of being populated, which in turn leads to the Boltzmann distribution for a system in thermal equilibrium.

a. True
b. False

Answers

Answer:

Hello! Your answer would be, A) True

Explanation:

Hope I helped! Ask me anything if you have any questions. Brainiest plz!♥ Hope you make a 100%. Have a nice morning! -Amelia♥

Se transmiten ondas transversales en una cuerda tensada orientada sobre el eje x. La función de ondas correspondientes es y= 5.00 sen(6.05x + 5.19t + 1.57). Donde y y x están en metros y t en segundos. Cual es la rapidez de las ondas que se transmiten en dicha cuerda?

Answers

Answer:

Explanation:

Whats the entire question?

When a particular hanging mass is suspended from the string, a standing wave with two segments is formed. When the weight is reduced by 2.2 kg, a standing wave with five segments is formed. What is the linear density of the string

Answers

Solution :

Mass is varied keeping frequency constant.

Wavelength, λ  [tex]$=\frac{2l}{n}$[/tex]

where length of spring = l

           number of segments = n

Velocity, v = λ x f

                 = [tex]$\sqrt{\frac{T}{\mu}}$[/tex]

[tex]$\mu $[/tex] =  mass density, T = tension in string

[tex]$T=\frac{4 \mu l^2f^2}{n^2}$[/tex]

[tex]$T=mg = \frac{4 \mu l^2f^2}{n^2}$[/tex]  , n = 2

[tex]$T = (m-2.2)g = \frac{4 \mu l^2f^2}{n^2}, n = 5$[/tex]

[tex]$\Rightarrow \frac{m}{m-2.2}=\frac{25}{4}$[/tex]

[tex]$\Rightarrow m = 2.619\ kg$[/tex]

Therefore, μ = 0.002785 kg/ m

Frequency is varied keeping T constant

[tex]$T=\frac{4 \mu l^2f^2}{n^2}, f=60 , \ \ n = 2$[/tex]

[tex]$T=\frac{4 \mu l^2f^2}{n^2}, f=? , \ \ n = 7$[/tex]

[tex]$\Rightarrow \frac{60^2}{4}=\frac{f^2}{49}$[/tex]

f = 210 Hz

The density of table sugar is 1.59g/cm3 what is the volume of 7.85g of sugar?

Answers

Answer: 4.94cm³

Explanation:

Data;

ρ = 1.59g/cm³

mass = 7.85g

volume = ?

density = mass / volume

ρ = m / v

v = m / ρ

v = 7.85 / 1.59

v = 4.94cm³

What is an appraisal of an employee's performance in the workplace?
A. consensus
B. evaluation
C. procedure
D. metacognition

Answers

Answer:

B. evaluation

Explanation:

An employee can be defined as an individual who is employed by an employer of labor to perform specific tasks, duties or functions in an organization.

Basically, an employee is saddled with the responsibility of providing specific services to the organization or company where he is currently employed while being paid a certain amount of money hourly, daily, weekly, or monthly depending on the contractual agreement between the two parties (employer and employee).

Hence, while an employer may be the owner of a business firm or company, an employee is a subordinate employed to provide unwavering services to the employer while also, being professional and diligent at all times.

Human resources management (HRM) can be defined as an art of managing, controlling and improving the number of people (employees or workers), functions, evaluation of employees, activities which are being used effectively and efficiently by an organization.

Hence, human resources managers are saddled with the responsibility of recruiting, evaluating, managing and improving the welfare and working conditions of the employees working in an organization.

Basically, the human resources manager carry out appraisals on the performance of the various employees working in an organization. These informations about employees are typically used for promotional purposes, allowances and other benefits or form of rewards.

An ocean thermal energy conversion system is being proposed for electric power generation. Such a system is based on the standard power cycle for which the working fluid is evaporated, passed through a turbine, and subsequently condensed. The system is to be used in very special locations for which the oceanic water temperature near the surface is approximately 300 K, while the temperature at reasonable depths is approximately 280 K. The warmer water is

Answers

Answer:

Explanation:

Dear Student, this question is incomplete, and to attempt this question, we have attached the complete copy of the question in the image below. Please, Kindly refer to it when going through the solution to the question.

To objective is to find the:

(i) required heat exchanger area.

(ii) flow rate to be maintained in the evaporator.

Given that:

water temperature = 300 K

At a reasonable depth, the water is cold and its temperature = 280 K

The power output W = 2 MW

Efficiency [tex]\zeta[/tex] = 3%

where;

[tex]\zeta = \dfrac{W_{out}}{Q_{supplied }}[/tex]

[tex]Q_{supplied } = \dfrac{2}{0.03} \ MW[/tex]

[tex]Q_{supplied } = 66.66 \ MW[/tex]

However, from the evaporator, the heat transfer Q can be determined by using the formula:

Q = UA(L MTD)

where;

[tex]LMTD = \dfrac{\Delta T_1 - \Delta T_2}{In (\dfrac{\Delta T_1}{\Delta T_2} )}[/tex]

Also;

[tex]\Delta T_1 = T_{h_{in}}- T_{c_{out}} \\ \\ \Delta T_1 = 300 -290 \\ \\ \Delta T_1 = 10 \ K[/tex]

[tex]\Delta T_2 = T_{h_{in}}- T_{c_{out}} \\ \\ \Delta T_2 = 292 -290 \\ \\ \Delta T_2 = 2\ K[/tex]

[tex]LMTD = \dfrac{10 -2}{In (\dfrac{10}{2} )}[/tex]

[tex]LMTD = \dfrac{8}{In (5)}[/tex]

LMTD = 4.97

Thus, the required heat exchanger area A is calculated by using the formula:

[tex]Q_H = UA (LMTD)[/tex]

where;

U = overall heat coefficient given as 1200 W/m².K

[tex]66.667 \times 10^6 = 1200 \times A \times 4.97 \\ \\ A= \dfrac{66.667 \times 10^6}{1200 \times 4.97} \\ \\ \mathbf{A = 11178.236 \ m^2}[/tex]

The mass flow rate:

[tex]Q_{H} = mC_p(T_{in} -T_{out} ) \\ \\ 66.667 \times 10^6= m \times 4.18 (300 -292) \\ \\ m = \dfrac{ 66.667 \times 10^6}{4.18 \times 8} \\ \\ \mathbf{m = 1993630.383 \ kg/s}[/tex]

A soccer ball is released from rest at the top of a grassy incline. After 6.2 seconds, the ball travels 47 meters. One second later, the ball reaches the bottom of the incline.
(a) What was the balls acceleration?(assume that the acceleration was constant).
(b) How long was the incline?

Answers

Answer:

(a) a = 2.44 m/s²

(b) s = 63.24 m

Explanation:

(a)

We will use the second equation of motion here:

[tex]s = v_it+\frac{1}{2}at^2[/tex]

where,

s = distance covered = 47 m

vi = initial speed = 0 m/s

t = time taken = 6.2 s

a = acceleration = ?

Therefore,

[tex]47\ m = (0\ m/s)(6.2\ s)+\frac{1}{2}a(6.2\ s)^2\\\\a = \frac{2(47\ m)}{(6.2\ s)^2}[/tex]

a = 2.44 m/s²

(b)

Now, we will again use the second equation of motion for the complete length of the inclined plane:

[tex]s = v_it+\frac{1}{2}at^2[/tex]

where,

s = distance covered = ?

vi = initial speed = 0 m/s

t = time taken = 7.2 s

a = acceleration = 2.44 m/s²

Therefore,

[tex]s = (0\ m/s)(6.2\ s)+\frac{1}{2}(2.44\ m/s^2)(7.2\ s)^2\\\\[/tex]

s = 63.24 m

How much heat is required to raise the temperature of 50 grams of water from 30 °C to 90 °C? C of water 4186 J / kg C.
12558 J
12558000 J
125580 J
1255800 J

Answers

Answer:

12558 J

Explanation:

Please do mark as brainliest. Hope this helps! :)

Imagine a truck crashes into a building. What kind of sound wave does this make?

Answers

Thr wave of sound that makes the truck is vibration

what unit is used to measure resistance

Answers

Answer:

Ohms

Explanation:

The unit of resistance is ohms.

Gravitationally, how does the alignment of the sun, earth, and moon being in a straight line influence earth's tides?

Answers

Answer:

The alignment of the sun, earth, and moon being in a straight line causes very low and extra-high, low and high tides respectively due to the additive effect of the solar tide on the lunar tide.

Explanation:

Tides can be defined as the rise and fall of water level in water bodies such as lakes and oceans due to the gravitational force of attraction exerted by the moon on earth. The side closest to the moon creates a bulge of water known as high tide. Low tides are generally experienced when a sea level is not within the bulge.

Generally, the gravitational pull of the Moon cause visible changes on planet Earth's surface.

This ultimately implies that, the pull of the Moon's gravity causes high and low tides on planet Earth's surface.

The various types of ocean tides based on the position of the Earth, Moon and the Sun are;

I. Neap tides.

II. Spring tides.

III. Low tide.

IV. High tide.

V. Brown tide.

VI. Rip tide.

VII. Red tide.

Generally, the alignment of the sun, earth, and moon being in a straight line causes very low and extra-high, low and high tides respectively due to the additive effect of the solar tide on the lunar tide. Thus, this alignment of the sun, earth, and moon being in a straight line gives rise to spring tides.

what is the difference between kinetic and potential energy​

Answers

Answer:

Kinetic energy is energy possessed by a body by virtue of its movement. Potential energy is the energy possessed by a body by virtue of its position or state. While kinetic energy of an object is relative to the state of other objects in its environment, potential energy is completely independent of its environment. Hence the acceleration of an object is not evident in the movement of one object, where other objects in the same environment are also in motion. For example, a bullet whizzing past a person who is standing possesses kinetic energy, but the bullet has no kinetic energy with respect to a train moving alongside.

I think this answer is helped you

Answer:

the what state does alduos is 500 stack of ml tayo the little man ♂️ jajao

kalokoha ya

ansjsjdk

what is relative density​

Answers

Answer:

Relative density, or specific gravity, is the ratio of the density (mass of a unit volume) of a substance to the density of a given reference material.

Explanation:

EMERGENT please answer

Answers

Answer:

meaning i dont know sorry

The table provided shows the masses and volumes of four liquids. A student has a mystery liquid with a density of 3 g/mL. Which liquid does the student have?





Liquid 1

Liquid 2


Liquid 3


Liquid 4

Answers

Answer: Liquid 2, if it's 3 g/mL and liquid 2 has 6gs and 2 mLs than it's 3g/mL

Which is the best way to become familiar with your company's policies and procedures?
O
A. ask the person who hired you
O
B. look in the employee handbook
C. tell your supervisor you need help
D. visit the company's website

Answers

The best way to become familiar with your company’s policies and procedures is C. Tell your supervisor you need help.

Calculate the potential difference across the 8 ohm resistor

Answers

Explanation:

if the current is 1A

V=iR

V= 1 × 8

V = 8volts

Other Questions
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