Answer:
Minimum percentage error = 20%
Explanation:
The zero error of the screw gauge is
(5*0.5)/50 = 0.05 mm
Least count on the circular scale is 0.5/50 = 0.01 mm
Equivalent circular scale reading = 0.01 * 25 = 0.25 mm
Reading on the main scale = 2 * 0.5 = 1 mm
Actual measurement = 1 +0.25-0.05 = 1.20 mm
The minimum percentage error in the reading will be (1.20 mm -1.00 mm)/1*100 = 20%
When was the most gravitational potential energy stored between the model and Earth? Assume that the model's mass did not change.
Answer:
As the ball falls from C to E, potential energy is converted to kinetic energy. The velocity of the ball increases as it falls, which means that the ball attains its greatest velocity, and thus its greatest kinetic energy
Explanation:
Answer:As the ball falls from C to E, potential energy is converted to kinetic energy. The velocity of the ball increases as it falls, which means that the ball attains its greatest velocity, and thus its greatest kinetic energy
Explanation:
Explain gravitational implicit energy in terms of work done against graveness.Show how knowledge of the implicit energy as a function of position can be used to simplify computations and explain physical marvels. Show that the gravitational potential energy of an object of mass m at height h on Earth is given by PEg=mgh.In the experiment, a meter is hooked up to a speaker to monitor the amplitude of the received sound. Suppose the background signal level is 13 mV, the signal is 91 mV with no attenuator and is 25 mV with an attenuator in place. Calculate pt/pi including the background correction.
Answer:
The answer is "[tex]15.38\%[/tex]"
Explanation:
Background[tex]= 13 \ mv\\\\[/tex]
corrected signal[tex]= 91 \ mv-13\ mv= 78\ mv\\\\[/tex]
with attenuator[tex]=25\ mv-13\ mv= 12\ mv\\\\[/tex]
[tex]\to \frac{p_t}{p_i}=\frac{12}{78}\times 100= 15.38\%[/tex]
Please helpppppppppp!!!!!!!!!!!
There are three 20.0 Ω resistors connected in series across a 120 V generator
Answer:
That is equal to R1 + R2. If three or more unequal (or equal) resistors are connected in series then the equivalent resistance is: R1 + R2 + R3 +…, etc. One important point to remember about resistors in series networks to check that your maths is correct.
WILL GIVE BRAINLIEST
Answer:
[tex]2\:\mathrm{m/s^2}[/tex]
From Newton's 2nd Law, we have [tex]\Sigma F=ma[/tex]. Substituting given values, we have:
[tex]40=20a,\\a=\frac{40}{20}=\boxed{2\:\mathrm{m/s^2}}[/tex]
A boat travels at 15 m/s in a direction 45° east of north for an hour. The boat then turns and travels at 18 m/s in a
direction 5° north of east for an hour.
What is the magnitude of the boat's resultant velocity? Round your answer to the nearest whole number.
I mis
What is the direction of the boat's resultant velocity? Round your answer to the nearest whole degree.
north of east
Done
Intro
Answer:
v = 31 m, / s; θ = 1 north- east
Explanation
One of the easiest ways to solve these problems is to work with the components of vectors.
Let's set a reference system where the x axis coincides with the West - East direction
Let's use trigonometry
cos 45 = v₁ₓ / v₁
sin 45 = v_{1y} / v₁
v₁ₓ = v1 cos 45
v_{1y} = v₁₁ sin 5
v₁ₓ = 15 cos 45 = 10.6 m / s
v _{1y} = 15 sin 45 = 10.6 m / s
sin 5 = v₂ₓ / v₂
cos 5 = v_{2y} / v₂
v₂ₓ = v2 sin 5
v_{2y}= v2 sin 5
v₂ₓ = 18 sin 5 = 1.569 m / s
v_{2yₓ} = 18 cos 5 = 17.93 m / s
Let's look for the speed in each axis
vₓ = v₁ₓ + v₂ₓ
vx = 10.6 + 1.569
vx = 12.17 m / s
v_y = v_{1y} + v_{2y}
v_y = 10.6 + 17.93
v_y = 28.53 m / s
to find the velocity let's use the Pythagorean theorem
v = [tex]\sqrt{v_x^2 +v_2^2 }[/tex]
v = √ (12.17² + 28.53²)
v = 31.02 m / s
approaching the nearest ether
v = 31 m / s
b) we use trigonometry
tan θ = vy / vx
θ = tan -1
θ = tan vy / vx
θ = tan-1 17.93 / 12.17
θ= 1.47
the closeΕst integer is
θ = 1 north- east
he open circuit voltage of circuit containing ideal sources and resistors is measured at 10 while the current through the short circuit passing through the terminals is 100 . Find the operating point that will occur at the terminals when circuit is connected to circuit consisting of 15 in parallel with 200 .
The question is incomplete. The complete question is :
The open circuit C containing ideal sources and resistors is measured at [tex]$V_{OC} = 10 \ V$[/tex] while the current through the short circuit passing through the terminals is [tex]$I_{SC} =100 \ mA$[/tex] . Find the operating point (V, I) that will occur at the terminals when circuit C is connected to circuit [tex]$C_2$[/tex] consisting of [tex]$V_2=15 \ V$[/tex] in parallel with [tex]$R_2=200 \ \Omega$[/tex] .
Solution :
Given :
[tex]$V_{OC} = 10 \ V$[/tex]
[tex]$I_{SC} =100 \ mA$[/tex]
[tex]$= 100 \times 10^{-3} \ A$[/tex]
[tex]$R_{th} =\frac{V_{OC}}{I_{SC}}$[/tex]
[tex]$=\frac{10}{0.1}$[/tex]
= 100 Ω
Therefore, by KVL, we get
[tex]$I=\frac{V_{OC}-V_2}{1/R_{th}+1/R_2}$[/tex]
[tex]$=\frac{10-15}{400/5}$[/tex]
[tex]$=-5 \times \frac{5}{400}$[/tex]
= [tex]$-\frac{1}{16}$[/tex] mA
By the KVL in loop,
-10 + 100 I + V = 0
V = 10 - 0.2
= 9.8 volts
Two blocks are connected by a massless rope that passes over a 1 kg pulley with a radius of 12 cm. The rope moves over the pulley without slipping. The mass of block A is 2.1 kg and the mass of block B is 4.1 kg. Block A is also connected to a horizontally-mounted spring with a spring constant of 358 J/m2. What is the angular frequency (in rad/s) of oscillations of this system
Answer:
[tex]F=1.159[/tex]
Explanation:
From the question we are told that:
Mass of pulley [tex]M=1kg[/tex]
Radius [tex]r=12cm[/tex]
Mass of block A [tex]M_a=2.1kg[/tex]
Mass of block B [tex]m_b=4.1kg[/tex]
Spring constant[tex]\mu= 358 J/m2[/tex]
Generally the equation for Torque is mathematically given by
Since [tex]\sumF=ma[/tex]
At mass A
[tex]T_2-f_3=2.1a[/tex]
At mass B
[tex]4.8-T_1=4.1a[/tex]
At Pulley
[tex]R(T_1-T_2)=\frac{1*1*R^2}{2}\frac{a}{R}[/tex]
[tex]R(T_1-T_2)=0.55a[/tex]
Therefore the equation for total force F
At mass A+At mass B+At Pulley
[tex](T_2-f_3+4.8-T_1+R(T_1-T_2)=2.1a+4.1a+0.55a[/tex]
[tex](T_2-f_3+4.8-T_1+R(T_1-T_2)=2.7a+4.8a+0.55a[/tex]
[tex]-f_3+4.1=6.75a[/tex]
[tex]-f_3=6.75a+4.8[/tex]
Since From above equation
[tex]M_{eff}=6.7kg[/tex]
Therefore
[tex]T=2\pi \sqrt{{\frac{M_{eff}}{k}}[/tex]
[tex]T=2\pi \sqrt{{\frac{6.75}{\mu}}[/tex]
[tex]T=0.862s[/tex]
Generally the equation for frequency is mathematically given by
[tex]F=\frac{1}{T} \\F=\frac{1}{0.862}[/tex]
[tex]F=1.159[/tex]
ADHD is triggered ________ by genetic and neurological factors and ________ by social or environmental ones.
A. less; more
B. somewhat; somewhat
C. little; mostly
D. more; less
Answer:
D More: Less
Explanation:
ADHD is triggered more by genetic and neurological factors and less by social or environmental ones.
What is ADHD?ADHD is one of the most common neurodevelopmental disorders of childhood. It is usually first diagnosed in childhood and often lasts into adulthood. Children with ADHD may have trouble paying attention, controlling impulsive behaviors (may act without thinking about what the result will be), or be overly active.
Moreover, ADHD tends to run in families and, in most cases, it's thought the genes you inherit from your parents are a significant factor in developing the condition. Research shows that parents and siblings of someone with ADHD are more likely to have ADHD themselves.
Therefore, adults with attention deficit hyperactivity disorder (ADHD or ADD) lead anxious lives. The nature of ADHD often makes day-to-day life stressful, creating situations and environments fraught with uncertainty – anxiety's primary fuel.
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A thermionic tube with only a cathode and anode is called
Answer:
the simplest vacuum tube, the diode
A cylindrical cable with 2.38 x 10-8 m resistivity carries a current of 1100 A. There is a potential difference of 1.5 x 10-2 V between two points on the cable that are 0.22 m apart. What is the radius of the cable
Answer:
11.1 mm
Explanation:
The resistance of the cable R = ρl/A where ρ = resistivity of cable = 2.38 × 10⁻⁸ Ωm, l = distance between the two points on the cable = 0.22 m and A = cross-sectional area of cable = πr² where r = radius of cable. Also, from Ohms' law, R = V/I where V = potential difference between the two points = 1.5 × 10⁻² V and I = current in cable = 1100 A
So,
ρl/A = V/I
A = ρlI/V
πr² = ρlI/V
r² = ρlI/πV
taking square root of both sides, we have
r = √(ρlI/πV)
substituting the values of the variables into the equation, we have
r = √(ρlI/πV)
r = √(2.38 × 10⁻⁸ Ωm × 0.22 m × 1100 A/[π × 1.5 × 10⁻² V)
r = √(575.96 × 10⁻⁸ Ωm²A/4.712 × 10⁻² V)
r = √(122.2225 × 10⁻⁶ m²)
r = 11.06 × 10⁻³ m
r = 11.06 mm
r ≅ 11.1 mm
Copper zinc and magnesium do not contain any iron. What word is used to describe these types of
metals?
Answer:
Metals that do not contain traces or large proportions of iron in them are called Non-Ferrous metals.
A 17-mm-wide diffraction grating has rulings of 530 lines per millimeter. White light is incident normally on the grating. What is the longest wavelength that forms an intensity maximum in the fifth order
Answer:
377 nm
Explanation:
Number of lines per meter is, [tex]N &=530 \times 1000 \\ &=530000 \text { lines } / \mathrm{m} \end{aligned}[/tex]
Grating element is, [tex]d=\frac{1}{N}[/tex]
[tex]=1.8868 \times 10^{-6} \mathrm{~m}[tex]
Order is, n=5
Condition for maximum intensity is, [tex]d \sin \theta=n \lambda[/tex]
[tex]\lambda &=\frac{1.8868 \times 10^{-6}}{5(\sin 90)} \\ &=0.377 \times 10^{-6} \mathrm{~m} \\ &=377 \mathrm{~nm}[/tex]
which statement describes the molecules and a reaction once it reaches equilibrium
A. They maintain stable concentrations
B. They stop moving
C. They consist mainly of reactant molecules
D. They react only if they are disturbed
Answer:
They maintain stable concentrations
Explanation:
Just took the test.
The statement describes the molecules and a reaction once it reaches equilibrium: they maintain stable concentrations, which is option A as the When a chemical reaction reaches equilibrium, the rate of the forward reaction is equal to the rate of the reverse reaction.
What is equilibrium?Equilibrium is a dynamic state, meaning that the reaction is still ongoing but the rates of the forward and reverse reactions are equal. This means that molecules are still reacting with each other, but at a constant rate, so that the concentrations of the reactants and products remain stable. When a reaction is not at equilibrium, the concentrations of the reactants and products change as the reaction progresses. However, once equilibrium is reached, the concentrations of the reactants and products no longer change, but the individual molecules are still moving and reacting with each other.
Hence, The statement describes the molecules and a reaction once it reaches equilibrium: they maintain stable concentrations, which is an option. A
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A sound wave with a frequency of 700 Hz and a wavelength of 5 m travels through a liquid. How fast does sound travel through the liquid?
A.
140 m/s
B.
0.007 m/s
C.
3500 mHz
D.
3500 m/s
what are the phenomena that physics in applied in ?
Answer:
For empiricists like van Fraassen, the phenomena of physics are the appearances observed or perceived by sensory experience. Constructivists, however, regard the phenomena of physics as artificial structures generated by experimental and mathematical methods.
Explanation:
I hope it's help u Have a great dayWe have that the the phenomena that physics in applied in are much but these are phenomena's where Physics as a discipline is applied
Physics is applied in LightingElectricityMovementHeatGravityWe first define physics Before we go into it variant applications
Physics
Physics is a part(branch,denomination) of science a that focuses heavily on the facts of Matter and Energy that is seen on earth and the world around us.
Different Application of Physics
Physics is applied in Lighting
one of the Greatest phenomena of the application of Physics is the light bulb
this follows its distinct principle follow laws and principle to achieve its invention
Electricity
Physics studies atoms and its particle electron which is the bases of electricity
Movement
Movement or motion is a core part of physics with newtons three laws of motion playing a big role to the understanding of motion
Heat
Physics studies the heat and all its principle and sources e.g the sun, and Quantities used to define heat at different stages
Gravity
Gravity is a constant force that that acts on all matter that exist.
It is the bases of weight as weight is a function of Gravity and Mass of matter
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Which of the following. Chemical represent the law of conservation of Matter?
Answer:
The answer is first one 1...
What is meant by electricity and magnetism
Electricity is just the flow of electrons or charges from a point of production through a conductor, to another point where it can be utilized or converted to another form of energy.
Magnetism is the force exerted by magnets when they attract or repel each other. Magnetism is caused by the motion of electric charges from two or more magnetic substances.
Answer:
By Electricity.. We mean the Flow of electrical power or Charge.
While Magnetism is a phenomenon that occurs from or by the Motion of Charges
What is the flow rate of water in a pipe flowing full with an area of 0.3 m2 and velocity of 2.5 m/s?
Answer:
0.75 m³/s
Explanation:
Applying,
Q = vA.................... Equation 1
Where Q = flow rate of the water, v = velocity of the water, A = area of the pipe.
From the question,
Given: v = 2.5 m/s, A = 0.3 m²
Substitute these values into equation 1
Q = 2.5(0.3)
Q = 0.75 m³/s
Hence the flow rate of water in the pipe is 0.75 m³/s
what is the transfer of heat energy by direct contact. A . convection b. radiation c. thermal or heat and d. conduction
Answer:
d. conduction
Explanation:
Conduction involves the transfer of electric charge or thermal energy due to the movement of particles. When the conduction relates to electric charge, it is known as electrical conduction while when it relates to thermal energy, it is known as heat conduction.
In the process of heat conduction, thermal energy is usually transferred from fast moving particles to slow moving particles during the collision of these particles. Also, thermal energy is typically transferred between objects that has different degrees of temperature and materials (particles) that are directly in contact with each other but differ in their ability to accept or give up electrons.
Any material or object that allow the conduction (transfer) of electric charge or thermal energy is generally referred to as a conductor. Conductors include metal, steel, aluminum, copper, frying pan, pot, spoon etc.
In conclusion, conduction typically involves the transfer of heat energy by direct contact between two or more conductors such as a pot and electric cooker.
Answer:
d. conduction
Explanation:
Conduction is the transfer of energy from one molecule to another by direct contact.
The radius of the aorta in a test subject determined by MRI is 1.2 cm. At rest, his end diastolic volume is 120 mL and his end systolic volume is 50 mL. If we start the cardiac cycle at the opening of the mitral valve, the aortic valve in this person opens at 0.5 s and closes at 0.9 s. The entire cycle lasts 1.2 s in this person. The density of blood is 1.055 g mL-1 and its viscosity is 3.0 x 10^-3 Pa s. A pascal is one N m-2. Using this information:
A. What is the stroke volume?B. What is the heart rate?C. What is the cardiac output?D. What is the period of ejection?E. What is the average velocity of blood in the aorta?F. What is the Reynolds number for blood during ejection?G. Is blood flow in the aorta laminar or turbulent?H. What is the kinetic energy of the ejected blood?I. W hat pressure-volume work is done during ejection?
Answer:
A) SV = 70 mL
B) H.R = 49.8 bpm
C) H.R = 49.8 bpm
D) P_e = 0.4 s
E) v¯ = 38.68 cm/s
F) Re ≈ 3265
G) turbulent flow.
H) KE = 0.01105 J
I) Diastolic and Systolic pressure are not given so work can't be found
Explanation:
We are given;
Radius of aorta; r = 1.2 cm
Diastolic volume; DV = 120 mL
Systolic volume; SysV = 50 mL
Period that cycle lasts; t_cycl = 1.2 s
the aortic valve opens at; t_ao = 0.5 s aortic valve closes at; t_ac = 0.9 s
Density; ρ = 1.055 g/mL = 1.055 g/cm³
viscosity; μ = 3 × 10^(-3) Pa.s = 0.03 g/cm-s
A) Formula for stroke volume is;
SV = DV - SysV
SV = 120 - 50
SV = 70 mL
B) formula for heart rate is;
H.R = 1/t_cycl
H.R = 1/1.2
H.R = 0.83 beats per seconds
Converting to beats per minutes gives;
H.R = 0.83 × 60
H.R = 49.8 bpm
C) Formula for cardiac output is;
cardiac output = SV × HR
Let's convert SV to L to get;
SV = 0.07 L
Thus;
Cardiac output = 0.07 × 49.8
Cardiac output = 3.49 L/min
D) Period of ejection = t_ac - t_ao
Period of ejection = 0.9 - 0.5
Period of ejection; P_e = 0.4 s
E) average velocity; v¯ = SV/(A × P_e)
A = πr²
A = π × 1.2² cm²
SV = 70 mL = 70 cm³
Thus;
v¯ = 70/(π × 1.2² × 0.4)
v¯ = 38.68 cm/s
F) Reynolds number is calculated from;
Re = ρv¯D/μ
r = 1.2 and so diamter; D = 2r = 2 × 1.2 = 2.4 cm
Thus;
Re = 1.055 × 38.68 × 2.4/(0.03)
Re ≈ 3265
G) Reynolds number is greater than 2000 and thus it is a turbulent flow.
H) Formula for kinetic energy is;
KE = ½mv²
We know that; mass = volume × density
Thus; mass = 1.055 × 70 g
KE = ½ × 1.055 × 70 × 38.68²
KE = 110,490.12 g.cm²/s²
Converting to Joules gives;
KE = 0.01105 J
I) work volume relationship is given by;
W = ∫PdV
But we are not given the Diastolic and Systolic pressure, so it's not possible to calculate the work
The flow of electricity from one place to another is called
Answer:Electric Current!
Explanation: Electric current ;)
You have two flashlights that have 0.500-A currents flowing through them. One flashlight has a single 1.50-V battery in its circuit, and the second flashlight has three 1.50-V batteries connected in a chain that provides 4.50 V. How much power is the battery in the first flashlight providing
Answer: 0.75 W
Explanation:
Given
Current flowing [tex]I=0.5\ A[/tex]
The first flashlight has a single 1.5 V battery
The second flashlight has three 1.5 V batteries connected to provide 4.5 V
Power is the product of voltage and current.
For the first flashlight
[tex]\Rightarrow P=1.5\times 0.5\\\Rightarrow P=0.75\ W[/tex]
Thus, the first flashlight providing 0.75 W of power.
you c. can answer only the a question if you want, but can you please answer this question??
Answer:
earth
mars
saturn
a
b
Explanation:
A gyroscope slows from an initial rate of 34 rad/s at a rate of 0.619 rad/s2. The angular displacement when it stops moving is _
Answer: [tex]933.76\ rad[/tex]
Explanation:
Given
The initial rate of gyroscope is [tex]\omega_o=34\ rad/s[/tex]
Angular deceleration [tex]\alpha =0.619\ rad/s^2[/tex]
Using angular equation of motion
[tex]\Rightarrow \omega^2-\omega_o^2=2\alpha \theta[/tex]
Insert the values
[tex]\Rightarrow 0-34^2=2(-0.619)\theta \\\\\Rightarrow \theta =\dfrac{34^2}{2\times 0.619}\\\\\Rightarrow \theta =933.76\ rad[/tex]
Thus, the angular displacement is [tex]933.76\ rad[/tex]
To have the highest magnification in a telescope, the focal length of the objective lens should be _________ and the focal length of the eyepiece lens should be ________.
Answer:
Large; small.
Explanation:
A telescope can be defined as an optical instrument or device which comprises of a curved mirror and lenses used for viewing distant objects i.e objects that are very far away such as stars and other planetary bodies. The first telescope was invented by Sir Isaac Newton.
Magnification can be defined as a process in which the size of an object is increased or enlarged by a percentage and as such making the object bigger than its original size.
A lens can be defined as a transparent optical instrument that refracts rays of light to produce a real image.
Basically, there are two (2) main types of lens and these includes;
I. Diverging (concave) lens.
II. Converging (convex) lens.
In order to have the highest magnification in a telescope, the focal length of the objective lens should be large and the focal length of the eyepiece lens should be small.
This ultimately implies that, the eyepiece lens should have a small focal length while the objective lens should have a large focal length.
A. Obtain the following: microwave, ruler, something meltable (e.g. candy bar, marshmallows) B. A microwave works by setting up a standing electromagnetic wave inside of a box made of conducting materials. What is the value of an electric field inside a conductor
Answer:
E = 124.7 N / C
Explanation:
Let's analyze the exercise: the microwave creates an electromagnetic wave of frequency F = 2.45 GHz, this wave is introduced into the microwave cavity and is reflected on the metal walls, which is why one or more standing waves are formed.
The electric field of the standing wave is
I = E²
E =√I
where I is the intensity of the radiation.
What is it
I = P / A
where P is the effective emission power, almost all the power of the microwave and A is the area of the cavity, in the most used microwaves
P = 700 W and the area is A = 25 x 18 cm² = 0.045 m²
I = 700 / 0.045
I = 15555.56 W/m²
let's calculate the electric field
E = √15555.56
E = 124.7 N / C
The table below shows a sample wavelength of each type of electromagnetic radiation, along with its frequency and energy.
Type
of EM
Radiation Sample
Wavelength
(cm) Frequency
(Hz) Energy
(electron-volts)
radio 150 2.0 × 108 8.3 × 10-7
microwave 1.0 3.0 × 1010 1.2 × 10-4
infrared 1.0 × 10-3 3.0 × 1013 0.12
Visible 5.0 × 10-5 6.0 × 1014 2.5
ultraviolet 5.0 × 10-6 6.0 × 1015 25
X-rays 1.0 × 10-8 3.0 × 1018 1.2 × 104
gamma
rays 1.0 × 10-10 3.0 × 1020 1.2 × 106
Because electromagnetic waves possess different wavelengths, frequencies, and energies, they are used for different purposes.
Radio waves, for example, can be used to transmit data, such as music and text messages. Microwaves are used to cook food, and infrared rays are used in night vision goggles.
On the other end of the spectrum, ultraviolet rays can affect vitamin D levels in humans, X-rays are used in medical imaging, and gamma rays are used in radiation cancer therapy.
Given this information, what type of electromagnetic waves are most likely the safest if one is exposed to them?
A.
waves with shorter wavelengths
B.
waves with higher frequencies
C.
higher amplitude waves
D.
lower energy waves
Answer:
D lower energy waves is most likely the safest if one is exposed to.
What type of eclipse occurs when the Moon moves in between the Sun and the Earth. (Not very common)
lunar
solar
A closed loop conductor that forms a circle with a radius of 2.0 m is located in a uniform but changing magnetic field. If the maximum emf Induced in the loop is 5.0 V what is the maximum rate at which the magnetic field strength is changing if the magnetic field is oriented perpendicular to the plane in which the loop lies
Answer:
The maximum rate at which the magnetic field strength is changing if the magnetic field is oriented perpendicular to the plane in which the loop lies 0.398 T/s.
Explanation:
Given;
radius of the circular loop, r = 2.0 m
maximum induced emf, E = 5.0 V
The emf induced in a magnetic field is given as;
[tex]emf = \frac{d\phi}{dt} \\\\\phi = AB\\\\emf = A\frac{dB}{dt} \\\\\frac{dB}{dt} = \frac{emf}{A} \\\\where;\\A \ is \ the \ area \ circular \ l00p = \pi r^2 = \pi (2)^2 = 4\pi \ m^2\\\\\frac{dB}{dt} = \frac{5}{4\pi} \\\\\frac{dB}{dt} = 0.398 \ T/s[/tex]
Therefore, the maximum rate at which the magnetic field strength is changing if the magnetic field is oriented perpendicular to the plane in which the loop lies 0.398 T/s.