Answer:
100 V
Explanation:
V = IR
100 x 1 = 100
100 volts
The voltage across a 100-ohm circuit element that draws a current of 1 A is 100 V.
What is electric current?Electric current is a term used to describe how much electricity flows across a circuit and how it flows in an electronic circuit. Amperes are used to measure it (A).
The more electricity flowing across the circuit, the higher the ampere value. The difference in electric potential between two places is known as voltage, electric potential difference, electric pressure, or electric tension.
Ampere is the SI unit of electric current and ohm is the SI unit of electric resistance.
The circuit element is 100 ohms
The current is 1 A.
Voltage = current (I) x resistance (r)
V = IR
100 x 1 = 100
100 volts
Therefore, the voltage across a 100-ohm circuit element is 100 volts.
To learn more about electric current, refer to the below link:
https://brainly.com/question/28019870
#SPJ2
IF YOUR VEHICLE BREAKS DOWN, YOU SHOULD?
Answer:
1. TURN ON YOUR HAZARD/EMERGENCY LIGHTS
Turn on your hazard lights to warn other drivers as soon as you sense something's wrong. Keep them on until help arrives, recommends the National Motorists Association (NMA).
2. SLOW DOWN AND PULL OFF THE ROAD
Aim for the right shoulder of the road. Consumer reports recommends that you pull over to a safe, flat location that is as far away from moving traffic as possible.
3. TURN YOUR WHEELS AWAY FROM THE ROAD AND PUT ON THE EMERGENCY BRAKE
The California Department of Motor Vehicles (DMV) recommends pulling your emergency brake, sometimes called the parking brake. If you have to park on a hill or slope, turn the car's wheels away from the road to help prevent the care from rolling into traffic, says the California DMV.
4. STAY IN YOUR VEHICLE
If you're on a highway or crowded road, the Insurance Information Institute (III) recommends that you avoid getting out of your vehicle to look at the damage or fix a mechanical problem. If you need to get out of the car, get your vehicle to a safe place and make sure the road around you is completely clear. If you're stopped on the right-hand side of the road, get out through the passenger-side door.
5. BE VISIBLE
Once you're safely out of the vehicle, prop up your hood to let other drivers know they should proceed with caution. This will alert other drivers that you're broken down, according to the NMA.
6. SET UP FLARES OR TRIANGLES
Place flares or triangles with reflectors behind your car to alert other drivers to the location where you've stopped, says the III.
7. CALL FOR HELP
Call or use an app to get a tow truck, mechanic or roadside assistance to come help. your insurance company or other provider who may be able to help. If you're in an emergency situation or are not sure who to contact, call 911 or the local police for help.
Hope this helps :)
Vacancy diffusion statement refer to that a mechanism that
atom at lattice traveled to a vacant latblèe
• True
• False
Answer:
true
Explanation:
A business owned by one people is a
Answer:
A sole proprietorship, also known as the sole trader, individual entrepreneurship or proprietorship, is a type of enterprise that is owned and run by one person and in which there is no legal distinction between the owner and the business entity.
Explanation:
Answer:
A business owned by one people is a-Sole proprietorship
Explanation:
This is correct i did it for my electives class which was career reaserch and decision making.
brainliest?
List 3 specific things you can do with a screw gun (not just screw in screws)
Answer:
Install drywall
insert wood panels
unscrew nails
Explanation:
A plane stress state (2D) of material is defined by: [σ] = [800300300−400] (MPa). Define the principal stresses σ1, σ2 using:
• Determinant Method
• Mohr’s Circle (determine also ????max)
Answer:
Explanation:
Given that:
[tex][\sigma] = \left[\begin{array}{cc}800&300\\ \\300&-400\end{array}\right] (MPa)[/tex]
[tex][\sigma] = \left[\begin{array}{cc}\sigma_{xx}&\sigma_{xy}\\ \\\sigma_{yx}&\sigma_{yy}\end{array}\right][/tex]
Using Determinant method
The principal stress is the maximum or minimum normal stress acting on any plane. For the 2D stress system, the 2-principle plane always carries zero shear stress.
For principal stress [tex]( \sigma_1, \sigma_2)[/tex]
[tex]\sigma_{1,2} = \dfrac{\sigma_x+ \sigma_y}{2} \pm \sqrt{( \dfrac{\sigma_x - \sigma_y}{2} )^2 + \sigma^2_{xy}}[/tex]
[tex]\sigma_{1} = \dfrac{800+(-400)}{2} \pm \sqrt{( \dfrac{800 -(-400)}{2} )^2 + (300)^2}[/tex]
[tex]\sigma_{1} = \dfrac{400}{2} \pm \sqrt{ (600)^2 + (300)^2}[/tex]
[tex]\sigma_{1} = 200+ 670.82 \\ \\ \sigma_{1} = 870.82 \ MPa[/tex]
[tex]\sigma_{2} = \dfrac{800+(-400)}{2} \pm \sqrt{( \dfrac{800 -(-400)}{2} )^2 + (300)^2}[/tex]
[tex]\sigma_{2} = 200- 670.82 \\ \\ \sigma_{1} = - 470.82 \ MPa[/tex]
According to Mohr's circle;
Mohr's circle is the locus provided that the position of the normal stress and the shear stress is acting on any plane.
Center = (a,0)
[tex]a = \dfrac{\sigma_{x}+\sigma_{y}}{2}[/tex]
[tex]a = \dfrac{800+(-400)}{2}[/tex]
a = 200 MPa
radius (r) = [tex]\sqrt{ (\dfrac{\sigma_{x}-\sigma_{y}}{2})^2 + \sigma^2 _{xy}}[/tex]
[tex]=\sqrt{ (\dfrac{800-(-400)}{2})^2 + (300)^2}[/tex]
[tex]=\sqrt{ (600)^2 + (300)^2}[/tex]
r = 670.82 MPa
[tex]\sigma_1 = a +r \\ \\ \sigma_1 = 200 + 670.82 \\ \\ \sigma_1 = 870.82 \ MPa[/tex]
[tex]\sigma_2 =-(r-a)[/tex] (it is negative because of the negative x-axis)
[tex]\sigma_2 =670.82 - 200 \\ \\ \sigma_1 = 470.82 \ MPa[/tex]
[tex]\tau_{max} = radius \ of \ Mohr's \ circle[/tex]
[tex]\tau_{max} = 670.82 \ MPa[/tex]