800x87979 cuanto es?

Answer:

(a) 5/7 chance

(b) 2/7 chance

(c) 5/7 chance

Step-by-step explanation:

Event X: There are 3 letters that come before "D". A, B, and C. There is a 3 out of 7 chance of picking one of those letters. (3/7)

Event Y: There are 4 letters in "C A G E". Those 4 letters are in the 7 first letters of the alphabet meaning that they are in our pile of tiles. There is a 4 out of 7 chance of picking one of those letters. (4/7)

(a) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a 5/7 chance of either Event X or Event Y happening since tiles "A" and "C" are included in both events.

(b) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a 2/7 chance of both X and Y happening since there are only 2 tiles that are the same in both events, "A" and "C". (We are only allowed to pick one tile)

(c) The complement of Event Y is 1-4/7=5/7 chance.

Answer:

a) 5/7 chance

(b) 2/7 chance

(c) 5/7 chance

Step-by-step explanation:

Event X: There are 3 letters that come before "D". A, B, and C. There is a 3 out of 7 chance of picking one of those letters. (3/7)

Event Y: There are 4 letters in "C A G E". Those 4 letters are in the 7 first letters of the alphabet meaning that they are in our pile of tiles. There is a 4 out of 7 chance of picking one of those letters. (4/7)

(a) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a 5/7 chance of either Event X or Event Y happening since tiles "A" and "C" are included in both events.

(b) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a 2/7 chance of both X and Y happening since there are only 2 tiles that are the same in both events, "A" and "C". (We are only allowed to pick one tile)

(c) The complement of Event Y is 1-4/7=5/7 chance.

Answer:

a)  [tex]\frac{2}{3} \,\frac{lb}{bread}[/tex]

b)  [tex]1\frac{1}{4} \,\frac{in}{domino}[/tex]

Step-by-step explanation:

Part a:

every 4 lbs of flour, she makes 6 loaves of bread. this as a rate in simplest fraction form is:

[tex]\frac{4}{6} \,\frac{lb}{bread} = \frac{2}{3} \,\frac{lb}{bread}[/tex]

Part b:

every 10 inches , 8 dominoes can be placed. then the rate can be written as:

[tex]\frac{10}{8} \,\frac{in}{domino} = \frac{5}{4} \,\frac{in}{domino} =1\frac{1}{4} \,\frac{in}{domino}[/tex]

Answer:

D (The last choice)

Step-by-step explanation:

We know that rays are lines with a dot on one side and an arrow on the other. WE also know that lines have two arrows on each end. Keeping this in mind, we can identify which line segments and rays and lines.

Answer:

converse of alternate exterior angle theorem

Step-by-step explanation:

um im not sure if i should explain the full proof but

Answer:

This question is incomplete, i will answer it as:

"The initial population of a town is ​A, and it grows with a doubling time of 10 years. What will the population be in X ​years?"

Ok, the growth of a population usually is an exponential growth, so we can write this as:

P(t) = A*exp(r*t)

Where A is the initial population.

r is the rate of growth, and t is our variable, in this case, number of years.

Now we know that when t = 10y, the population doubles, so we should have:

P(10y) = 2*A = A*exp(r*10y)

2 = exp(r*10)

ln(2) = r*10

ln(2)/10 = r = 0.069.

Then our equation is:

P(t) = A*exp(0.069*t)

Now, if we want to know the population in X years, we need to replace the variable t by X

P(t = X) = A*exp(0.069*X)

Answer:

Step-by-step explanation:

Fog=2(g)+1

2(3x+2+4)+1

2{3x+6)+1

6x+12+1

=6x+13

Fog(-2)=6(-2)+13

-12+13

=1

Gof=3(f)+2+4

=3(2x+1)+6

6x+3+6

=6x+9

Gof(-2)=6(-2)+9

-12+9

=-3

Answer: 752

Step-by-step explanation:

Given that,

Margin of error = 3% = 0.03

confidence level = 90% = 0.90

therefore from the z-table

z = 1.645

Now since no prior estimate of p is given, so we say p = 0.5

Sample size required will be

n = 1.645² × 0.5 ×(1-0.5) / 0.03² = 751.67

n = 751.67 ≈ 752

Answer:

8.5cm

Step-by-step explanation:

convert 3.4metres to cm that is by multiplying by 100

3.4×100=340cm

1rep 40

?rep 340

that is 340/40

=8.5cm

Answer:

8.5 cm

Step-by-step explanation:

Scale = 1:40

Length of the room = 3.4 meters

3.4 meters =3.4 X 100 =340 cm

Since 1 unit on the diagram represents 40 units

The length of the diagram

[tex]=\dfrac{340}{40}\\\\=8.5$ cm[/tex]

The length of the room on the diagram is 8.5 cm.

Answer:

The demand function is  [tex]\mathbf{D(x) = 1200(\sqrt{25-x^2})+ 124000}[/tex]

Step-by-step explanation:

A firm has the​ marginal-demand function [tex]D' x = \dfrac{-1200}{\sqrt{25-x^2 } }[/tex].

Find the demand function given that D = 16,000 when x = $4 per unit.

What we are required to do  is to find the demand function D(x);

If we integrate D'(x) with respect to x ; we have :

[tex]\int\limits \ D'(x) \, dx = \int\limits{\dfrac{-1200 x}{\sqrt{25-x^2}} } \, dx[/tex]

[tex]D(x) = \int\limits{\dfrac{-1200 x}{\sqrt{25-x^2}} } \, dx[/tex]

Let represent   t  with [tex]\sqrt{25-x^2}}[/tex]

The differential of t with respect to x is :

[tex]\dfrac{dt}{dx}= \dfrac{1}{2 \sqrt{25-x^2}}}(-2x)[/tex]

[tex]\dfrac{dt}{dx}= \dfrac{-x}{ \sqrt{25-x^2}}}[/tex]

[tex]{dt}= \dfrac{-xdx}{ \sqrt{25-x^2}}}[/tex]

replacing the value of  [tex]\dfrac{-xdx}{ \sqrt{25-x^2}}}[/tex]  for dt in   [tex]D(x) = \int\limits{\dfrac{-1200 x}{\sqrt{25-x^2}} } \, dx[/tex]

So; we can say :

[tex]D(x) = \int\limits{\dfrac{-1200 x}{\sqrt{25-x^2}} } \, dx[/tex]

[tex]D(x) = 1200\int\limits{\dfrac{- x}{\sqrt{25-x^2}} } \, dx[/tex]

[tex]D(x) = 1200\int\limits \ dt[/tex]

[tex]D(x) = 1200t+ C[/tex]

Let's Recall that :

t  = [tex]\sqrt{25-x^2}}[/tex]

Now;

[tex]\mathbf{D(x) = 1200(\sqrt{25-x^2}})+ C}[/tex]

GIven that:

D = 16,000 when x = $4 per unit.

i.e

D(4) = 16000

SO;

[tex]D(x) = 1200(\sqrt{25-x^2}})+ C[/tex]

[tex]D(4) = 1200(\sqrt{25-4^2}})+ C[/tex]

[tex]D(4) = 1200(\sqrt{25-16}})+ C[/tex]

[tex]D(4) = 1200(\sqrt{9}})+ C[/tex]

[tex]D(4) = 1200(3}})+ C[/tex]

16000 = 1200 (3) + C

16000 = 3600 + C

16000 - 3600 = C

C = 12400

replacing the value of C = 12400 into [tex]\mathbf{D(x) = 1200(\sqrt{25-x^2}})+ C}[/tex], we have:

[tex]\mathbf{D(x) = 1200(\sqrt{25-x^2})+ 124000}[/tex]

∴ The demand function is  [tex]\mathbf{D(x) = 1200(\sqrt{25-x^2})+ 124000}[/tex]

Answer:

11 / 12 or 0.9167

Step-by-step explanation:

Given:

3/4 + 1/6

Find:

Value with expression

Computation:

"3/4 added to number 1/6"

3/4 + 1/6

By taking LCM

[9 + 2] / 12

11 / 12 or 0.9167

Answer:

105°

Step-by-step explanation:

Supplementary angle of 75° = 180° - 75° = 105°

Answer:

105°

Step-by-step explanation:

angle given is 75°

= 180° - 75°

= 105°

Answer:

C-(7)

Step-by-step explanation:

Given figure is a trapezoid and 21 - x is the mid segment.

Therefore by mid-segment formula of a trapezoid, we have:

21 - x = 1/2(17 + 11)

21 - x = 1/2 * 28

21 - x = 14

21 - 14 = x

7 = x

x = 7

Answer:

2π radians

Step-by-step explanation:

Answer:

[tex](4,7)[/tex]

Step-by-step explanation:

Given

[tex]2x - 3 < y[/tex]

[tex](x,7)[/tex]

Required

Find one possible value of x

From the given parameters;

[tex](x,7)[/tex] is a possible solution of [tex]2x - 3 < y[/tex] where y= 7

Substitute 7 for y

[tex]2x - 3 < 7[/tex]

Add 3 to both sides

[tex]2x - 3 + 3 < 7 + 3[/tex]

[tex]2x < 10[/tex]

Divide both sides by 2

[tex]2x/2 < 10/2[/tex]

[tex]x < 5[/tex]

The result of the inequality implies that x is less than 5; So, the possible values of x is all real numbers less than 5;

Having said that;

[tex](4,7)[/tex] is one possible coordinate of [tex]2x - 3 < y[/tex]

An outlier in statistics is a data point that deviates considerably from other observations. The given data set has no outlier.

An outlier in statistics is a data point that deviates considerably from other observations. An outlier can be caused by measurement variability or by experimental mistake; the latter is sometimes eliminated from the data set.

To find the outlier for the given data set follow the given steps.

Step one: The first step is to find the quartiles for the data set.

For this data set, the quartiles are:

Q1 = 45.5

Q3 = 62.5

Step Two: Find the Interquartile Range

The interquartile range is the difference between the first and third quartiles.

IQR = Q3 - Q1

IQR = 45.5 - 62.5

IQR = 17

Step Three:

The next step is to set up a fence beyond the first and third quartiles using the interquartile range.

Lower Fence = Q1 - (1.5 × IQR)

Lower Fence = 45.5 - (1.5 × 17)

Lower Fence = 20

Upper Fence = Q3 + (1.5 × IQR)

Upper Fence = 62.5 + (1.5 × 17)

Upper Fence = 88

Step Four: Find the Outliers

Any numbers in the data that are above or below the fences are outliers.

Since there are no numbers outside the two fences. Hence, it can be concluded that the given data set does not have, any outlier.

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Answer:

18.9 units of fencing

Step-by-step explanation:

First find the perimeter

P = 2(l+w)

P = 2( 2.5+1.28)

P = 2( 3.78)

P =7.56m

We need 2.5 units of fencing for each meter

Multiply by 2.5

7.56*2.5

18.9 units of fencing

Answer:

Julio needs to purchase 18.9 units of fencing.

Step-by-step explanation:

I meter of the perimeter accounts for 2.5 units of fencing. Respectively 2 meters account for 2 times as much, and 3 meters account for 3 times as much of 2.5 units. Therefore, if we determine the perimeter of this rectangular garden, then we can determine the units of fencing by multiplying by 2.5.

As you can see this is a 2.5 by 1.28 garden. The perimeter would be two times the supposed length, added to two times the width.

2.5 x 2 + 1.28 x 2 = 5 + 2.56 = 7.56 - this is the perimeter. The units of fencing should thus be 7.56 x 2.5 = 18.9 units, or option d.

Answer:

We can think that the line of the kite is the hypotenuse of a triangle rectangle, and the altitude is one of the cathetus of the triangle.

And we know that it makes an angle of 65° with the horizontal (i guess this is measured between the hypotenuse and the horizontal adjacent to the kite.

This angle is complementary to the top angle of our triangle rectangle, such that A + 65° = 90°

A = 90° - 65° = 25°

Then the altitude of the kite is the adjacent cathetus to this angle.

We can use the relation:

sin(A) = Adjacent cathetus/hypotenuse.

Sin(25°) = X/350ft

Sin(25°)*350ft = X = 147.9m

The kite is flying at an altitude of approximately 317.20 feet.

The situation will form a right angle triangle.

The hypotenuse of the triangle is the will be the line of the kite which is 350 ft long.

The line makes an angle of 65° with the horizontal  direction. The horizontal direction is the adjacent of the triangle formed.

Using trigonometric ratio, the altitude of the kite can be found below.

The altitude of the kite is the height/ opposite side of the triangle.

Therefore,

sin 65° = opposite / hypotenuse

sin 65° = opposite / 350

cross multiply

opposite = 350  × sin 65

altitude of the kite = 350 × 0.90630778703

altitude of the kite = 317.207725463

altitude of the kite ≈ 317.20 ft

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Answer:

the percentage of people who have an IQ between 115 and 140 is 16.79%

Step-by-step explanation:

From the information given:

We are to  determine the percentage of people who have an IQ between 115 and 140.

i.e

P(115 < X < 140) = P( X  ≤ 140) - P( X  ≤ 115)

[tex]P(115 < X < 140) = P( \dfrac{X-100}{\sigma}\leq \dfrac{140-100}{16})-P( \dfrac{X-100}{\sigma}\leq \dfrac{115-100}{16})[/tex]

[tex]P(115 < X < 140) = P( Z\leq \dfrac{140-100}{16})-P( Z\leq \dfrac{115-100}{16})[/tex]

[tex]P(115 < X < 140) = P( Z\leq \dfrac{40}{16})-P( Z\leq \dfrac{15}{16})[/tex]

[tex]P(115 < X < 140) = P( Z\leq 2.5)-P( Z\leq 0.9375)[/tex]

[tex]P(115 < X < 140) = P( Z\leq 2.5)-P( Z\leq 0.938)[/tex]

From Z tables :

[tex]P(115 < X < 140) = 0.9938-0.8259[/tex]

[tex]P(115 < X < 140) = 0.1679[/tex]

Thus; we can conclude that the percentage of people who have an IQ between 115 and 140 is 16.79%

Using the normal distribution, it is found that 82.02% of people who have an IQ between 115 and 140.

In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

In this problem:

The proportion of people who have an IQ between 115 and 140 is the p-value of Z when X = 140 subtracted by the p-value of Z when X = 115, hence:

X = 140:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{140 - 100}{16}[/tex]

[tex]Z = 2.5[/tex]

[tex]Z = 2.5[/tex] has a p-value of 0.9938.

X = 115:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{115 - 100}{16}[/tex]

[tex]Z = -0.94[/tex]

[tex]Z = -0.94[/tex] has a p-value of 0.1736.

0.9938 - 0.1736 = 0.8202.

0.8202 = 82.02% of people who have an IQ between 115 and 140.

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Answer:

A. 3/5

Step-by-step explanation:

Simple math, 9/15. Divide both by 3.

3*3=9 and 3*5=15 so answer is 3/5!

Answer:

answer is A

Step-by-step explanation:

this is a probability question

divide the number of baskets made by the total number of attempts

9/15 = 3/5

Answer:

b. -1/6

Step-by-step explanation:

slope = (difference in y)/(difference in x)

slope = (1 - 0)/(-2 - 4) = 1/(-6) = -1/6

Answer:

m = -1/6 = B

Step-by-step explanation:

[tex]m = \frac{y_2-y_1}{x_2-x_1} \\ x_1=4\\ y_1=0\\ x_2=-2\\y_2=1.\\m = \frac{1-0}{-2-4} \\m = \frac{1}{-6}[/tex]

Answer:

Time taken by Stephen = 162 seconds

Step-by-step explanation:

Stephan gathered data which fits in the line of best fit,

y = -2.1x + 565.6

Where x represents the age (in months)

And y represents the time (in seconds) taken by Stephen to run two laps on the track.

Time taken to run 2 laps at the age of 192 months,

By substituting x = 192 months,

y = -2.1(192) + 565.6

  = -403.2 + 565.6

  = 162.4 seconds

  ≈ 162 seconds

Therefore, time taken by Stephen to cover 2 laps was 162 seconds when he was 192 months old.

Answer:

4.647 to the nearest thousandth.

Step-by-step explanation:

The formula for the length of an arc between  x = a and x = b is

  a

    ∫  √( 1 + (f'(x))^2) dx

  b

Here f(x) = √x so

we have  ∫  (√( 1 + (1/2 x^-1/2))^2 )   between x = 0 and x = 4.

=   ∫ ( √( 1 + 1/(4x)) dx   between  x = 0 and x = 4.

This is not easy to integrate  but some software I have gives me the following

length =  √17 + 1/8 log(33 + 1/8 √17)

= 4.647.

Answer:

y is the range

Step-by-step explanation:

the y is the range

x isthe domain

[tex]|\Omega|=2\cdot6\cdot52=624\\|A|=1\cdot3\cdot16=48\\\\P(A)=\dfrac{48}{624}=\dfrac{1}{13}[/tex]

Answer:

1/13

Step-by-step explanation:

Answer:

1.

a. 20 m²: barn door is 5m x 4m

b. 468 m²:surface area of barn

i. left and right barn walls: 2(15 x 7) = 210

ii. back wall: 7 x 8 = 56

iii. front wall: (7 x 8) - 20* = 36

*20 for the barn door

iv. front of roof: (4 x 4) / 2 = 8 x 2* = 16

*I split the triangle into 2 smaller triangles

v. sides of roof: 2(5 x 15) = 150

2.

a. 15 m²: silo door is 3m x 5m

b.  244.18 m²: surface area of silo

i. SA(silo)=2πrh+2πr²

ii. SA(silo) = 2π(2.5)(14) + 2π(2.5)²

iii. SA(silo) = 259.18

iv. SA(silo - door) = 259.18 - 15

v. SA(silo - door) = 244.18

3.

a. 712.18 m²: total surface area painted red

i. add both surface areas: 468 + 244.18 = 712.18 m²

hope this helps :)

Answer:

4 2/3 :)

Step-by-step explanation:

The total paint in the bucket in the simplified mixed fraction is [tex]6\frac{2}{3}[/tex] pints.

A fraction is written in the form of p/q, where q ≠ 0.

Fractions are of two types they are proper fractions in which the numerator is smaller than the denominator and improper fractions where the numerator is greater than the denominator.

Given, A housepainter mixed [tex]3\frac{1}{2}[/tex] pints of blue paint in a bucket with [tex]1\frac{1}{6}[/tex] pints of white paint.

So, The total paint in the bucket is the sum of the pints of both paints which

is, = [tex](3\frac{1}{2} + 1\frac{1}{6})[/tex] pints.

[tex]= (\frac{7}{2} + \frac{7}{6})[/tex] pints.

[tex]= \frac{21 + 7}{6}[/tex] pints.

[tex]= \frac{28}{6}[/tex] pints.

[tex]= 6\frac{2}{3}[/tex] pints.

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Answer:

Expected Value of $2:

Expected Value of $2:

Win, 0.3333 x $3 = $1

Plus

Loss, 0.6667 x -$2 = -$1.33

Expected value = ($0.33)

Step-by-step explanation:

Probability of a win = 2/6 = 0.3333

Probability of a loss = 4/6 = 0.6667

Expected Value of $2:

Win, 0.3333 x $3 = $1

Plus

Loss, 0.6667 x -$2 = -$1.33

Expected value = ($0.33)

The casino game player's expected value is computed by multiplying each of the possible outcomes by the likelihood (probability) of each outcome and then adding up the values.  The sum of the values is the expected value, which amounts to a loss of $0.33.

Answer:

B. Square both sides of the equation.

Step-by-step explanation:

You cannot do anything to the equation unless you square both sides to eliminate the square root on the left (squaring each individual term of the equation does not help; you need to square the entire square root to eliminate it).

Hope this helps!

Answer:

[tex]\boxed{15 \ dime \ and \ 10 \ nickel \ coins}[/tex]

Step-by-step explanation:

1 dime = 10 cents

1 nickel = 5 cents

So,

If there are 15 dimes

=> 15 dimes = 15*10 cents

=> 15 dimes = 150 cents

=> 15 dimes = $1.5

Rest is $0.5

So, for $0.5 we have 10 nickels coins

=> 10 nickels = 10*5

=> 10 nickels = 50 cents

=> 10 nickel coins = $0.5

Together it makes $2.00

Answer:

f(x)= 8(0.5)^x

Step-by-step explanation:

As you can see on the graph there are two specific points labeled:

(0,8) and (1,4)

The 8 would be the initial value and starting point of the "design"

A is always the initial value so replace that.

Then proceed to divide 4 by 8 to figure out the percentage change its 0.5

leave x as it is