832.59÷100=
18.6 ÷0.12=
12.42 ÷ 4.6=

Please help me with all of them :,> Offering all my points for all of them.

Answer:

1. half angle

2. x

Step-by-step explanation:

The missing parts of the proof is the variable x.

Trigonometric functions are those functions which are the ratio of the sides of a right angled triangle.

Given,

sin² (x) = [1 - cos (2x)] / 2

We have to prove sin ([tex]\frac{x}{2}[/tex]) = ± [tex]\sqrt{\frac{1-cos (x)}{2} }[/tex]

First, we have

sin² (x) = [1 - cos (2x)] / 2

Substituting x/2 in place of x, we get,

sin² (x/2) = [1 - cos (2x/2)] / 2

sin² (x/2) =  [1 - cos (x)] / 2

sin² ([tex]\frac{x}{2}[/tex]) = [tex]{\frac{1-cos (x)}{2} }[/tex]

Taking square root on both sides,

sin ([tex]\frac{x}{2}[/tex]) = ± [tex]\sqrt{\frac{1-cos (x)}{2} }[/tex]

Hence it is proved.

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I don't know sorry but I recommend using quizlet

Answer:

A) = m

Step-by-step explanation:

Answer:

t = -1.54.

Step-by-step explanation:

The test statistic is:

[tex]t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

H0:μ=54.5

This means that [tex]\mu = 54.5[/tex]

Your sample consists of 48 subjects, with a mean of 54.1 and standard deviation of 1.8.

This means, respectively, that [tex]n = 48, \mu = 54.1, \sigma = 1.8[/tex]

Test statistic

[tex]t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]t = \frac{54.1 - 54.5}{\frac{1.8}{\sqrt{48}}}[/tex]

[tex]t = -1.54[/tex]

The test statistic is t = -1.54.

Answer:

A = 1.5386

Step-by-step explanation:

Quarter circle area formula:

A = (πr²)/4

A= (π1.4²)/4

A = (3.14*1.96)/4

A = (6.1544)/4

A = 1.5386

Answer:

86

Step-by-step explanation:

Answer:

Expression of the statement = 18 - 2x

Answer:

18 - 2x

Step-by-step explanation:

Answer:

~114.56

Step-by-step explanation:

Because you're asked to find the number so that x% is y, we will have to find that number. The equation in that case would be NUM * 0.934 = 107. Divide both sides by .934 to get an answer of approximately 114.56.

Answer:

1/12

Step-by-step explanation:

if Mr.Tough can grade 1 in 12 hours he can do 1/12

The fraction of the exams that Mr Tough and Mrs Nice grade in 1 hour if they work together is 3/20

A fraction is used to denote a portion or component of a whole. Numerator and denominator are the two components that make up a fraction. There are three types of fractions: proper, incorrect, and mixed.

Using, rate × time = work done

So, Mr Tough's rate:

Mr Tough's rate × 12 hours = final exam

Mr Tough's rate = 1/12

and, Mrs. Nice's' rate:

Mrs .Nice's' rate × 15 hours = final exam

Mrs .Nice's' rate = 1/15

So, Total time:

T(1/12 hours + 1/15 hours) = final exam

T =  final exam / (1/12 + 1/15)

T =  final exam / (0.15)

Now, 1 hour =  final exam / (0.15)

final exam = 1 × 0.15

                = 0.15

                = 15/ 100

                = 3/20

Therefore, 3/20 fraction of the final exam.

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Answer:

The population of city A is 6,300,000.

Step-by-step explanation:

1,800,000 × 3[tex]\frac{1}{2}[/tex]

3[tex]\frac{1}{2}[/tex] is equal to 3.5

Plug in 1,800,000 × 3.5 into your calculator

= 6,300,000

Answer:

35 (C)

Step-by-step explanation:

Answer:

B) 30

Step-by-step explanation:

This is a pretty tricky question. If you draw the line of best fit and go to 9 salespeople, it would be closer to 30 compared to any of the other choices.

Answer:

3 seconds

Step-by-step explanation:

Initial height = 144 feet

t = Time taken

The equation of the height from the ground is

[tex]h(t)=-16t^2+\text{Initial height}[/tex]

The time taken to reach the ground is needed. Here the ground is taken as reference so [tex]h(t)=0[/tex]

[tex]0=-16t^2+144\\\Rightarrow -144=-16t^2\\\Rightarrow t=\sqrt{\dfrac{144}{16}}\\\Rightarrow t=3\ \text{s}[/tex]

So, time taken by the quarter to reach the ground is 3 seconds.

Step-by-step explanation:

[tex]f(x) = {x}^{2} + 2x - 10 \\ f( - 2) = { (- 2)}^{2} + 2( - 2) - 10 = \\ = 4 - 4 - 10 = - 10[/tex]

Answer:

○ B. [tex]\displaystyle 186\:square\:units[/tex]

Explanation:

All edges conjoin to form right angles, therefore you have these:

[tex]\displaystyle \boxed{186} \hookrightarrow 121 + 30 + 35 \Rightarrow 11^2 + 5 \times 6 + 5 \times 7[/tex]

OR

[tex]\displaystyle \boxed{186} \hookrightarrow 120 + 66 \Rightarrow 24 \times 5 + 6 \times 11[/tex]

I am joyous to assist you at any time.

Answer:

10 x X - 5 = -13

Answer:

Step-by-step explanation:

10x-5= -13

10x= -13+5

10x= -8

x= 10/-8

x= -1.25 or 5/-4

Answer:

C

Step-by-step explanation:

3(8+5)=39

3(13)=39

or

3(8)+3(5)=39

Answer:

b. 9

Step-by-step explanation:

if c = 8 and d = - 5

3( c + d)

= 3( 8 + (-5))

= 3 * 3

= 9

Answer:

28

Step-by-step explanation:

Answer:

The student got 28 questions correct and 7 wrong.

The minimum value of both sine and cosine is -1. However the angles that produce the minimum values are different, [tex]-\pi/2, \pi[/tex] for sine and cosine respectively.

The question is, can we find an angle for which the sum of sine and cosine of such angle is less than the sum of values at any other angle.

Here is a procedure, first take a derivative

[tex]\frac{d}{dx}(\sin x+\cos x)=\cos x -\sin x[/tex]

Then compute critical points of a derivative

[tex]\cos x-\sin x=0\implies x_1=\frac{\pi}{4},x_2=\frac{5\pi}{4}[/tex].

Then evaluate [tex]\sin x +\cos x[/tex] at [tex]x_1,x_2[/tex].

You will obtain global maxima and global minima [tex]\sqrt{2}, -\sqrt{2}[/tex] respectively.

The answer is [tex]-\sqrt{2}[/tex].

Hope this helps.

Step-by-step explanation:

i think it's a b and answer my new question it's 100 point question I really need the answer pls help me

Answer:

To do this you need to add both sides by 8. yw

Step-by-step explanation:

The roots of x^2 + (1 - k).x+k-3 = 0 are real for all real values of k

The equation is given as:

x^2 + (1 - k).x+k-3 = 0

For an equation to have real root, then the following must be true:

[tex]b^2 \ge 4ac[/tex]

In x^2 + (1 - k).x+k-3 = 0, we have:

a = 1

b = 1 - k

c = k - 3

So, we have:

[tex](1 - k)^2 \ge 4 * 1 * (k - 3)[/tex]

Evaluate

[tex]1 - 2k + k^2 \ge 4k - 12[/tex]

Collect like terms

[tex]k^2 - 2k - 4k + 1 + 12 \ge 0[/tex]

[tex]k^2 - 6k + 13 \ge 0[/tex]

Using a graphing calculator, the value of k is all real numbers

Hence, the roots of x^2 + (1 - k).x+k-3 = 0 are real for all real values of k

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Answer:

Step-by-step explanation:

Answer:

4/6

Step-by-step explanation:

the total time the dice roll over four.. which is also 4/6

Answer:

The answer should be C

Step-by-step explanation:

I hope that helps you!

Answer    "v = 1.2s"

Step-by-step explanation: because 1.2 is 1*1.2, 2.4 is 2*1.2 and so on..