9. Determine the total capacitance between points A and B. D н А- В с E с C C с с с c​

It should travel at a speed of [tex]13.55[/tex] × [tex]10^{-3}[/tex] [tex]\frac{m}{s}[/tex] so that the two balls have the same momentum.

M = mass of the bowling ball = [tex]4.5 kg[/tex]

V = speed of bowling ball = [tex]3.98 \frac{m}{s}[/tex]

P = magnitude of momentum of bowling ball = ?

magnitude of momentum of bowling ball is given as

[tex]P = MV[/tex]

inserting the values

P = [tex]4.5 * 3.98[/tex]

P = [tex]17.91[/tex] [tex]\frac{kgm}{s}[/tex]

m = mass of ping-pong ball = [tex]1.322[/tex] [tex]g[/tex]= [tex]1.322[/tex] x [tex]10^{-3}[/tex] [tex]Kg[/tex]

v = speed of the ping-pong ball = ?

p = magnitude of momentum of ping-pong ball

Given that :

Magnitude of momentum of ping-pong ball  =  magnitude of momentum of bowling ball

[tex]p = P[/tex]

[tex]m v = 17.91[/tex]

([tex]1.322[/tex] x [tex]10^{-3}[/tex]) [tex]v[/tex] = [tex]17.91[/tex]

v = [tex]13.55[/tex] x [tex]10^{-3}[/tex] [tex]\frac{m}{s}[/tex]

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The braking distance does not change. Because both the kinetic energy and the frictional force are doubled.

We found that the stopping distance of a car is proportional to its kinetic energy. Energy is dissipated as heat in the brakes tires and road surface. More energy required means more stopping distance. This explains why the braking distance increases in proportion to the square of the car's speed. The kinetic energy of a car is equal to the braking force multiplied by the stopping distance.

Braking distance also depends on car speed car mass brake and tire wear and road surface. A fast heavy car with worn tires and brakes will have a longer stopping distance on wet or icy roads. Friction forces act in the opposite direction of movement, making it harder to move slowing the car down the ramp and slowing it down, thus reducing the distance covered.

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Largest-size vehicle (kg) it can lift if the diameter of the output and maximum gauge pressure is given is 0.455 * 10³ kg.

Pressure that is measured relative to ambient atmospheric pressure is called gauge pressure. Gauge pressure can be measured using a diaphragm sensor in which one side of the diaphragm is exposed to the pressure media that is to be measured and the other side gets exposed to ambient atmospheric pressure.

Given the diameter of the piston = 25.5 cm,

radius = 12.75 cm= 0.1275 m

Area of the piston is;

A=  πr²

= 3.14 * (0.1275)²

=0.051 m²

Given maximum pressure of the lift= 17 atm

p =1.72 * 10⁶ Pa

Maximum force that piston can lift:

F= p * A

=  1.72 * 10⁶ *( 0.051 )²

= 4.47 * 10³ N

Size of the vehicle :

m = F/g

=  4.47* 10³/ 9.81

mass = 0.455 * 10³ kg

Largest-size vehicle that it can lift is 0.455 * 10³ kg.

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The maximum height of that block-putty system is h/4.

Whtat is inelastic collision?

A collision in which a portion of the kinetic energy of the colliding particles is converted into another type of energy.

What is velocity?

The primary determinant of an object's position and rate of motion is its velocity. It can be explained as the distance an object travels in one unit of time. The object's displacement in a given amount of time is called velocity.

The velocity of block just before hitting the putty (by energy conservation)

K.Ei+P.Ei=K.Ef+P.Ef

⇒0+mgh=21mv2

⇒v=[tex]\sqrt{2}[/tex]gh

Let the common velocity of both block and putty be v'

At collision momentum balance:

mv=mv′+mv′

⇒[tex]\sqrt{2}[/tex]gh=2v′

⇒v′=[tex]\sqrt{g/h}[/tex]

Again applying energy conservation (both block and putty at max height)

K.Ei+P.Ei=K.Ef+P.Ef

⇒1/2 2mv²=2mgh′

⇒1/2 gh/2=gh′

⇒h′=h/4

Therefore, the maximum height is h/4.

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The top speed of the car is 34.34 m/s and the total time of the run is 11.65 seconds.

The top speed of the car is the final or maximum speed of the car and can be determined by applying the following kinematic equation.

v = u + at

where;

The initial velocity of the car = 0, since the car started from rest.

The final equation for the top speed of the car becomes;

v = 0 + at

v = at

The given parameters include the following;

v = 5.89 m/s²  x   5.83 s

v = 34.34 m/s

The total time of the run is calculated as follows;

s = ut + ¹/₂at²

where;

s = 0 + ¹/₂at²

s = ¹/₂at²

t = √(2s/a)

t = √(2 x 400 / 5.89)

t = 11.65 seconds

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Orthographic projection enables you to notice the surfaces and edges more clearly.

Means of representing three-dimensional objects in two dimensions is called Orthographic projection.

Orthographic views helps us to represent a 3D object in 2D on a drawing. It can show an object viewed from each direction.

An orthographic projection has three views:  front view, top view and side view. The right side is used for the side view but if the left side is used then it will be clearly labeled in the drawing. The final drawing is known as a 3 view drawing.

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The angular acceleration of the wheel is -20.25 rad/sec^2

Angular acceleration is defined as the rate of change of angular velocity over time.

so, α = 2*(θ  -  ωo t ) / t^2

angular velocity of the wheel = ωo  = 96.0 rad/sec

time taken by the wheel to rotate = t = 7 sec

angular distance travelled by the wheel  = θ 28 rev

As we know that,

In one revolution the wheel completes 360 degrees which is equals to  6.28319 rad

therefore angular distance traveled = 28 rev * 6.28319 rad

So, the angular acceleration = 2*(28*6.28 -  96*7) / 7^2 = -20.25 rad/sec^2

The question is incomplete, the complete question is 'A rotating wheel requires 7.00 s to rotate 28.0 revolutions. its angular velocity at the end of the 7.00-s interval is 96.0 rad/s. what is the constant angular acceleration (in rad/s) of the wheel?'

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Answer:

It will be doubled

Explanation:

F = ma

Let's consider m = 1 (the mass of the cart is not changing so it is constant),

F = 2, and a = 4.

2 = 1 x 4

When doubling force we need to maintain equality so acceleration should double too. To understand it better find the ratio of force and acceleration 2/4 = 1/2. The ratio of force to acceleration should always equal half in all scenarios, this way we can see how equality is maintained.

2x2 = 1 x (4x2)  

4 = 1 x 8, and the ratio of force to acceleration is 4/8 = 1/2.

The warmth from the water is flowing to the ice and melting it and The warmth from the burner is flowing to the cold water and increasing its temperature.

Convection, which is essentially the mass transfer of heat, is the process by which heat is moved from one place to another by the movement of fluids. The transport of heat into the atmosphere involves one of three processes: radiation, conduction, or convection.

Heat flow occurs when a hot object transmits its heat through a conductors to a cooler, similar to how high-energy objects impart their power to low-energy objects. How well a conductor transfers heat will impact how quickly and how much heat is transported.

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A passenger on a train traveling at a ground speed of 18.0 m/s in the opposite direction of the first train can hear the frequency approach at 302.05 Hz.

The number of waves that pass a fixed place in a unit of time is referred to as frequency in physics. It also indicates how many vibrations or cycles a body in periodic motion makes in a given amount of time.

Speed is 18.0 m/s.

Consider a train moving through still air at a speed of 30.0 m/s. The train whistle produces a note with a 262 Hz frequency.

We must determine the periodicity.

Using the frequency formula

f' = f(v + [tex]v_{p}[/tex]/v - [tex]v_{s}[/tex])

Fill out the formula with the value,

f' = 262(3441+18/344-30)

f' = 302.05Hz

Thus, 302.05 Hz is the frequency.

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Answer:

3, 4, 1, 2

Explanation:

The overall momentum of a system is constant.

Hence, The time taken to get to the shuttle is  4.49  min.

according to  the linear momentum conservation theorem, we have:

M1 V1 + M2 V2 =M1 V[tex]_0[/tex]1 + M2 V[tex]_0[/tex]2.

the initial velocity is Zero

then,

M1 V1 = - M2 V2

V1 = ( - M2 V2)/ M1

V1 = -  [tex]\frac{0.767 *12}{54.8}[/tex] = - 0.168 m/s

That is 0.168 m/s in the opposite direction of the camera.

the time taken to get to the shuttle is given by:

t = d/v

t = [tex]\frac{45.3}{0.168}[/tex] = 269.64 s

[tex]t_{min} =\frac{269.64}{60}[/tex] = 4.49 min.

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The applied force is 7.68 × 10³N.

A force that is applied is one that one object applies to one or more other objects. Applied forces have the power to alter an object's shape, size, state of motion, direction of motion, and other properties.

W = 1.3 × 10⁴

v₁ = 0

v (friction) = 84km/h = 23.3 m/s

t = 5s

f = 1500N

Mass of body = W / g

Mass of body = 1.3 × 10⁴ / 9.8

Mass of body = 1327 kg

v(friction) = v + at

23.3 = 5a

a = 4.66 m/s

Force Net = F₁ + F₂ + F₃ = ma

F (engine) = ma + F

F = 1327 (4.66) + 1500

F = 768.382

F = 7.68 × 10³N.

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The distance of the travel covered within 5 hours with a speed of 120km/hr is the product of time and this speed and it is 600 km.

Velocity of a substance is the measure of distance travelled per unit time. Thus it is the ratio of distance to time.In physics, velocity is the rate of speed.

Velocity = distance/time.

Hence, as the time taken for the travel increases velocity will decreases. The time given here is 5 hours and the speed of the vehicle is 120 km/hr. Hence, the distance can be calculated as follows:

Distance = time  × speed

               = 5 hr × 120 km/hr

               =  600 km.

Hence, if you drive at a speed of 120 km/hr for 5 hours you will cover a distance of 600 km.

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Answer:The correct statement regarding single convicts made A is false if we don't choose the correct statement. Okay, which is not true. The image is always a virtual coma, erect and small in size, for the single mirror. Real objects regardless of traditions are small. Is it okay? The enemy's position needs to be smaller than the object position if the image is virtual erect. The third option will become the false statement that it will be the answer and the fourth option will give us a virtual object that will give us a real image. We can use a virtual object to give us a real image. It is a real image. The answer to the problem is the option three. Thank you for taking the time to thank me.

Explanation:

One form of StyrofoamTM product, commonly used in craft projects, is Styrofoam balls. The spherical polystyrene foam objects known as Styrofoam balls range in diameter from one inch (2.54 cm) to eight inches (20.3 cm). The uses for Styrofoam balls in crafts are incredibly diverse.

Calculating the ball's volume using

V = 4/3 * pi * r3

r = 10 cm = 0.10 m.

V = 0.00418 m^3

The mass of the water with a volume of 0.0446 m3 is equal to m =??

V = 0.00418 m3,

and d = 1000 kg/m3.

m=V*dm=0.00418*1000=4.18 kg

then determining the styrofoam ball's mass.

V = 0.00418 m3

d = 32 kg per m3, which equals m = 0.00418 * 32 m = 0.1337 kg.

Finding the necessary mass to place on the ball's surface.

The distinction is what you'll need to put on the ball.

4.18 - 0.1337 = 4.046 kg ans.

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75 lbs/in^2 is the value of pressure. The force delivered perpendicularly to an object's surface per unit area across which that force is dispersed is known as pressure.

In the physical sciences, pressure is defined as the stress at a point within a confined fluid or the perpendicular force per unit area.

The force delivered perpendicularly to an object's surface per unit area across which that force is dispersed is known as pressure. In comparison to the surrounding pressure, gauge pressure is the pressure. Pressure is expressed using a variety of units.

P1V1=P2V2

The amount of force applied to a certain region is referred to as pressure. Absolute pressure, gauge pressure, and differential pressure are the three categories into which pressure is divided.

The distance between that point and the surface, the liquid's density. Gravitational acceleration are the factors of pressure.

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The rock's impact velocity with the river is - 98.1 m/s. At the time of impact, the  rock was traveling at a speed of 42.14 m/s.

G = -9.81 m/s2 is the acceleration of gravity close to the earth. Simply multiply the acceleration of gravity by the period of time since the object was released to determine the object's speed (or velocity).

In other words, velocity is equal to -9.81 m/s2 * time, or V = gt.

The rock was traveling at 42.14 m/s when it impacted the ocean.

Then V = -9.81 * 10 = -98.1.

There for,

The rock's impact velocity with the river is -98.1m/s .

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The initial speed of the block is 0.648 m/s

Define distance?

Distance is a quantitative or qualitative measurement of the distance between two objects or places. Distance can refer to a physical length or an estimation based on other factors in physics or common use (e.g. "two counties over"). Because spatial cognition is a rich source of conceptual metaphors in human thought, the term is also used metaphorically to mean an estimation of the amount of difference between two similar objects (such as statistical distance between probability distributions or edit distance among strings of text) or a degree of separation (as exemplified by distance between people in a social network). The concept of a metric space is used to codify most such conceptions of distance, both physical and metaphorical.

Given;

mass of block, m = 15 kg

force constant k = 3600 N/m

compression , x = 0.052 m

kinetic energy = elastic potential

¹/₂mv² = ¹/₂kx²

mv²  = kx²

v=√Kx^2/m

where;

v=initial speed of the block

x=compression of the spring

v=√3600 x (0.052)^2/15

v=0.648m/s

the initial speed of the block was 0.648 m/s

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According to the given statement 17.15 N force is exerted on the segment of wire in n.

Magnitude is essentially "distance or quantity" in the context of physics. In terms of motion, it shows the absolute and relative size, direction, or movement of an object. It is used to describe there is something volume or scope. Quantity in physics typically refers to a size or quantity.

The magnitude of the magnetic force on a conducting wire of length I carrying current II, and making an angle θ with a magnetic field of strength B is given by:

[tex]$|\vec{F}|$[/tex] = I l B sin 0

Rearranging to get the current:

I = [tex]$|\vec{F}|$[/tex]/ lB sin0

= 7 * 10⁻³ / 0.75 * (5.5 * 10⁻⁵)sin60

= 195.95 A

[tex]$|\vec{F}|$[/tex] = I l Bsin0

= (195.95)(0.05)(1.75)sin90

=17.15 N

I = 195.95 I

[tex]$|\vec{F}|$[/tex] = 17.15 N

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To draw a free body diagram, draw the object of interest, plot all the forces acting on it, and decompose all force vectors into their x and y components.

A separate free body diagram must be drawn for each object in question. There are not always four forces acting on an object. The number of forces represented in the free body diagram can be one, two, or three. External forces acting on an object include friction, gravity, normal forces, drag, tension, or human force by pushing or pulling. In non-inertial frames (see Frames below), conceptual forces such as centrifugal pseudo-forces are appropriate.

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MRI and FMRI are the  combination of neurological imaging techniques contains two methods that utilize magnetic imaging.

A magnetic field and radio waves produced by a computer are used in the magnetic resonance imaging (MRI) medical imaging procedure to provide precise images of the organs and tissues inside your body.

Large, magnetized tubes are the common shape of MRI equipment. The magnetic field briefly realigns water molecules in your body as you lie within the MRI machine. To produce cross-sectional MRI pictures, which resemble the slices of a loaf of bread, radio waves induce these aligned atoms to emit tiny signals.

Your doctor can evaluate your organs, tissues, and skeletal system with an MRI without performing any intrusive procedures. It generates detailed images of the body's.

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The airplane is heading away from us when we see a manned aircraft in the distance while flying our drone at night.

Distance is the length between two points or items, and it is directionless. Since distance is a scalar attribute, it only takes into account the overall magnitude and ignores the start and end locations. Being a scalar attribute, distance may only be positive or zero; it cannot be the opposite.

Although kilometers (km) and centimeters (cm) or millimeters (mm) can also be used to express shorter distances, the meter (m) is the most used unit of measurement for distance (mm). When calculating distance, the letter D is usually used to denote the distance traveled.

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For mass movements, gravity is the primary driving force. A trigger is frequently present in mass-wasting occurrences.

It could be caused by human operations like grading a new road, quake shaking, super volcano, storm waves, or storm-related waves. Mass-wasting is most frequently caused by an increase in water content in the slope. Rapidly dissolving snow or ice, as well as a heavy downpour, can cause the water content to rise. The force of gravity pulls everything towards to the Earth’s centre from every point on its surface. Gravity pulls downward on a level surface that is also parallel to the surface of the Earth. The stability of the consolidated and poorly consolidated earth materials can be compromised by gravity, increasing moisture content, and seismic events. The earth material slides down slope due to the compromised stability, a process known as mass wasting.

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Using the concepts of angular displacement, we got that 0.241 rad/s is the angular velocity of track star which runs a 230 m race on a 230 m circular track in 26 s.

We know very well that angular velocity is given by change in angular displacement per unit time.

Here, we can see that a truck distance covered and length of circular track is same.

Perimeter of circular track is equal to the distance covered by the truck.

It means, truck rounds a full circle in 26 sec

So, the angle covered by truck is 360° or 2π radian.

Initially angle is 0 radian and final angle is 2π radian

Therefore, angular velocity =(θ[tex]_f_i_n_a_l[/tex] -θ[tex]_i_n_i_t_i_a_l[/tex])/time

                               => ω=(2π-0)/26

                               =>w=(2π/26)

                                =>w=(2×3.14)/26

                                =>ω=6.28/26

                                =>w=0.241 rad/sec.

Hence, when a track star runs a 230 m race on a 230 m circular track in 26 s, the angular velocity assuming a constant speed is 0.241 rad/sec.

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solid particles vibrate and slip past each other when they become liquid.

Area in physics can be found by division of the area into simple figures such as triangles, rectangles and trapezoids and offsets from a straight line.

Area is a measure of how much space is there inside a shape and calculating the area of a shape or surface can be useful in everyday life.

The amount of surface a two-dimensional shape can cover which is measured in square units is called area and the SI unit of area is the square meter.

Area = length x breadth and  Area = π × radius × radius - formulas can be used for finding area of different quadrilaterals.

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Mental A has the smaller density. An object's density is defined as its mass divided by its volume.. Density is commonly expressed in grams per cubic centimeter (g/cm3).

Density is the amount of "stuff" in a given amount of space. A block of the heavier element lead (Pb), for example, will be denser than a block of the softer, lighter element gold (Au). A Styrofoam block is less dense than a brick. It is expressed in terms of mass per unit volume.

An object's density is defined as its mass divided by its volume. Density is commonly expressed in grams per cubic centimeter (g/cm3). Remember that grams are a unit of mass and cubic centimeters are a unit of volume (the same volume as 1 milliliter).

The SI density unit is m3kg. Volume Mass Density = m3kg

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The pressure applied by the cube of mass 500 kg and side 50 cm on the floor is 200000 Pascal

The mass of the cube is 500 kg and the side of the cube is 50 cm.

Converting the side of the cube from cm to m.

The side of the cube is 0.5 m.

The pressure applied by any body is given by the force applied by the body divided by the area on which the force is applied.

Pressure = force/area

The force applied by the cube will be equal to the weight of the cube,

The weight of the cube is 5000 Newton.

The area of only one side of the cube is in contact with the floor so the area is,

Area = 0.025 m

Putting values,

P = 5000/0.025

P = 200000 Pascal.

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