a) Work = 200 Joules
b) The motor moved a distance of 3.08 meters
Explanation:Force, F = 65 N
Power, P = 20 W
Time, t = 10 seconds
a) Calculate the work done
Power = Work / Time
20 = Work / 10
Work = 20 x 10
Work = 200 Joules
b) How far did it move?
Work = Force x Distance
200 = 65 x Distance
Distance = 200/65
Distance = 3.08 m
a 60 kg student traveling in a car with a constant velocity has the kinetic energy 1.2*10^4 J . what is the speedometer reading of the car in km/h?
Given data
The mass of the student is m = 60 kg
The kinetic energy possessed by the car is KE = 1.2 x 104 J
The expression for the kinetic energy of the car is given as:
[tex]\begin{gathered} KE=\frac{1}{2}mv^2\ldots.\ldots.(1) \\ v=\sqrt[]{\frac{2\times KE}{m}} \end{gathered}[/tex]Here, the velocity of the car is taken as v.
Substitute the value in the above equation.
[tex]\begin{gathered} v=\sqrt[]{\frac{2\times1.2\times10^4\text{ J}}{60\text{ kg}}} \\ v=20\text{ m/s} \\ v=20\text{ }\frac{m}{s}\times\frac{1\text{ km}}{1000\text{ m}}\times\frac{3600\text{ s}}{1\text{ h}} \\ v=72\text{ km/h} \end{gathered}[/tex]Thus, the car speedometer reading is 72 km/h.
In a student laboratory exercise, the wavelength of a 62,300 Hz ultrasound wave is measured to be 0.566 cm. Find the air temperature (in K).K
The speed of the sound wave produced in the experiment can be calculated like this:
v = lf
l = wavelength = 0.566 cm = 0.00566 m
f = frequency of wave = 62300 Hz
v = 0.00566*62300 = 352.618 m/s
We also have this equation, relating v, in m/s, to Tc, temperature, in Celsius:
v = 331.5 + 0.6Tc
352.618 = 331.5 + 0.6Tc
Solving for Tc,
Tc = 35.2 C
However, the question asks for temperature in Kelvin.
Tk = Tc + 272.15
Tk = 35.2 + 272.15
Tk = 307.35 K
A person that weighs 600 N on Earth travels to another planet with 5 times the mass and 5 times the radius of Earth. What is the weight of the person on this planet?
Given data
*The weight of the person is W = 600 N
*The other planet radius is R_p = 5 × R_e
*The other planet with mass is m_p = 5 × m_e
The formula for the acceleration due to gravity on the other planet is given as
[tex]g=\frac{Gm_p}{R^2_p}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} g_p=\frac{G(5\times m_e)_{}}{(5R_e)^2} \\ =\frac{Gm_e}{5R^2_e} \\ =\frac{g_e}{5} \end{gathered}[/tex]The mass of the person on the planet is calculated as
[tex]\begin{gathered} m_p=\frac{W}{g_p} \\ =\frac{600}{g_p} \end{gathered}[/tex]The weight of the person on the planet is calculated as
[tex]\begin{gathered} W_p=m_pg_p \\ =\frac{600}{g_p}\times\frac{g_p}{5} \\ =120\text{ N} \end{gathered}[/tex]Which is the best definition ofbuoyancy?A. force of attraction between all matterB. upward force exerted by fluidsC. force that opposes the motion of an object
Answer:
B. upward force exerted by fluids
Explanation:
We observe boyan
Rex flips a coin vertically upwards with an initial velocity of 2.62m/s. Determine the height to which the coin will rise above the initial height. At what velocity is the coin moving when the coin returns to Rex's hand and he catches it.
Givens.
• The initial velocity is 2.62 m/s.
It's important to notice that the velocity of the coin at its maximum height point is zero because the coin will stop instantaneously to then go down. Also, the acceleration due to gravity is g = 9.8 m/s^2.
Use a formula that relates, initial velocity, final velocity, gravity, and height.
[tex]v^2_f=v^2_0+2gh_{}_{}[/tex]Where v_0 = 2.62 m/s, v_f = 0, and g = 9.8 m/s^2.
[tex]\begin{gathered} 0=(2.62\cdot\frac{m}{s})^2+2(-9.8\cdot\frac{m}{s^2})h_{\max } \\ 0=6.86\cdot\frac{m^2}{s^2}-19.6\cdot\frac{m}{s^2}\cdot h_{\max } \\ -6.86\cdot\frac{m^2}{s^2}=-19.6\cdot\frac{m}{s^2}\cdot h_{\max } \\ h_{\max }=\frac{-6.86\cdot\frac{m^2}{s^2}}{-19.6\cdot\frac{m}{s^2}} \\ h_{\max }=0.35m \end{gathered}[/tex]Therefore, the height is 0.35 meters.
At the moment the coin is in Rex's hand again, the velocity is 2.62 m/s because the movement is symmetrical, which means the movement downwards develops the same magnitudes but in opposite direction.
Which of the following objects would be moved more easily by an applied force
To find:
The reason for the regular interval of 12 hours between the tides.
Explanation:
The earth rotates in the same direction as the revolution of the moon around the earth. Thus, it takes the earth an extra fifty minutes every day to catch up to the moon. That is the earth catches up to the moon every 24 hours and 50 minutes.
Thus there will be two high and two low tides in a day. Thus there will be 12 hours of interval between two high tides. In other words, the side of the earth that is far from the moon will be near the moon after 12 hours.
Final answer:
Thus the correct answer is option B.
Question 7 of 10Choose the one statement that is true of the noble gases.O A. They are very unstable.O B. They do not have valence shells.C. They do not need to gain or lose electrons to fill their valenceshell.D. They need to react with other noble gases to gain stability.SUBMIT
We will have that the statement that is true is:
Noble gases: They do not need to gain or lose electrons to fill their valence shell.
Take a look at this circuit and calculate the current that will run through each LED. What will the total current be? How much power is used to run the circuit below? Which LED(s) will glow the brightest?
The first step is to find the equivalent resistance of the circuit.
For the 1 kohm and 330 ohm resistors, they are in series. Thus,
equivalent resistance = 1000 + 330 = 1330 ohms
For the 330 ohm and 330 ohm resistors, they are in series
equivalent resistance = 330 + 330 = 660 ohms
Thus, 1330 ohms, 2kohms and 660 ohms are in parallel. We would calculate the equivalent resistance as shown below
1/Req = 1/1330 + 1/2000 + 1/660
1/Req = 0.002767
Req = 1/0.002767
Req = 361.398 ohms
V = IR
I = V/R
where
V is the voltage
I is the current
R is the resistance
Given that V = 9,
Total current = 9/361.398
Total current = 0.025 A
Power = IV = 0.025 x 9
Power = 0.225 W
Since the voltage passing through the circuit is the same, more current will pass through the two leds on the right since their equivalent resistance is lowest
A 3.10-cm diameter coin is placed a distance of 25.0cm from a concave lens that has a focal length of -11.0 cm. Determine the image distance ad diameter of the image.Must follow GRESA format. Make sure to list the L-O-S-T Image formed accordingly Solution format:Given Required: Equation(s) Needed: Solution:(a) (b) Final Answer L-ocation: O-rientation: S-ize: T-ype:
Given
3.1 cm diameter coin
25 cm from the concave lens
11 cm focal lens
Procedure
Below is a sketch how the image is created using a concave lens:
Equation(s) Needed:
[tex]\begin{gathered} \frac{1}{o}+\frac{1}{i}=\frac{1}{f} \\ \frac{1}{i}=\frac{1}{f}-\frac{1}{o} \end{gathered}[/tex]Solution
[tex]\begin{gathered} \frac{1}{i}=\frac{1}{-11}-\frac{1}{-25} \\ i=-7.64\text{ cm} \end{gathered}[/tex]The negative sign means that the image is virtual.
(b)
[tex]\begin{gathered} \frac{h}{i}=\frac{H}{o} \\ h=\frac{H}{o}\cdot i \\ h=3.1\text{ cm}\cdot\frac{7.64\text{ cm}}{25\text{ cm}} \\ h=0.95\text{ cm } \end{gathered}[/tex]0.95 cm - the diameter of the coin’s image
Final answer:
L-ocation: -7.64 cm
O-rientation: Inverted
S-ize: 0.95 cm
T-ype: Virtual
Currently, the tallest building in the world is the Burj Khalifa (with 160 stories) in Dubai, United Arab Emirates, which is 828 m tall. Previously, the tallest was the Taipei 101 skyscraper (with 101 floors) in Taiwan, which is 508 m tall.Referring to the information above, how much shorter in feet is the Taipei 101 than the Burj Khalifa? in feet
We will recall that t1 ft is approximately 0.3048 m, thus:
[tex]\begin{gathered} 828m(\frac{1ft}{0.3048m})-508m(\frac{1ft}{0.3048m})=1049.868766...ft \\ \\ \approx1050ft \end{gathered}[/tex]So, it is approximately 1050 ft shorter than the Burl Khalifa.
Explain how projectile motion works in real life like basketball
We will have that projectile motion works in an almost exact way as the theory tells us; the difference lies in the fact that the theories are modeled for a perfect system, but real life is not perfect and there are incredibly small variables that affect the movement of objects.
Now, in the case of basketball for example an object will have a mass, this object will be thrown with an initial velocity, acceleration and angle; now all of this affects the parabolic motion of the object. When in movement there are other forces the object has already been subjected to, like gravity that "pulls" on the object every moment, but when thrown then starts to bring the object to the ground.
The general form of the projectile movement is the one presented in the graph; but in real life there are factors that change the behavior slightly, such as friction with the medium, pressure, temperature, inertia of the object, another external forces, and so on.
An empty bottle moves up and down as water waves pass beneath it. However, it does not move toward the shore with the waves. What does this demonstrate about the propagation of waves through a medium? A. Waves transmit matter but not energy as they progress through a medium.B. Waves do not transmit matter or energy as they progress through a medium.C. Waves transmit energy but not matter as they progress through a medium.D. Waves transmit energy as well as matter as they progress through a medium
Given:
An empty bottle moves up and down as water waves pass beneath it.
The bottle does not move toward the shore with the waves.
Required: To choose the correct option.
Explanation:
The waves are disturbances in the medium which transfer their energy to the surrounding particles in the medium without changing their place.
Final Answer: Waves transmit energy but not matter as they progress through a medium(Option C).