Answer:
greatest displacement = 44.1m
initial velocity= 29.4m/s
Explanation:
Greatest displacement
s=1/2at^2
= (9.8/2 ×9)m
= 44.1m
initial velocity
s=ut-1/2at^2
44.1= 3u -(1/2×9.8×9)
44.1=3u-44.1
3u=88.2
u=29.4m/s
By starting with a falsifiable hypothesis and proceeding to gather data and ensure replicability, a scientist can contribute to the potential formation of a(n)
Answer:
theory
Explanation:
A scientist can contribute to the formation of a theory in a particular subject by conducting research along the line of that subject.
Conducting research requires the formation of a hypothesis and testing the hypothesis by conducting a relevant experiment during which data are gathered, analyzed, and interpreted in order to falsify or accept the hypothesis.
A good experiment must be replicate-able. When the same experiment is repeated by different independent researchers and the same conclusion is arrived at, this could potentially lead to the formation of a theory.
Hence, a scientist can contribute to the formation of a theory by conducting an experiment with replicability in order to test a hypothesis.
Bruno the bat flies at a speed of 0.5 m/s in circle of radius 1 m. What is his acceleration?
Very urgent pls help
Answer:
Acceleration is 0.25m/s^2
Explanation:
Given the following :
Speed = 0.5m/s
Radius(r) of circle = 1m
Acceleration round a circular path is given as :
a = v^2 / r
Where
a = acceleration of the body
v = speed / velocity
r = radius
Therefore,
a = v^2 / r
a = (0.5)^2 / 1
a = 0.25m/s^2
a skydiver jumped out of a plane and fell 9 miles to the ground. his average speed while falling was 174 miles/hour. how much time did the dive last?
Answer:
t = 0.051 seconds
Explanation:
Given that,
A skydiver jumped out of a plane and fell 9 miles to the ground. It means 9 miles is the distance covered.
The average speed of the skydiver is 174 miles/hour
We need to find the time for which he dive last. It means t is the time taken. Total distance covered divided by time taken is called average speed. So,
[tex]v=\dfrac{d}{t}\\\\t=\dfrac{d}{v}\\\\t=\dfrac{9}{174}\\\\t=0.051\ s[/tex]
So, a skydiver dive for 0.051 seconds.
A series combination of 12 Ω and 3 Ω is connected in parallel with another series combination of 6 Ω and 3 Ω. If a potential difference of 4 V is applied across it find the i) current drawn from the battery ii) current through 12 Ω resistor (iii)potential difference across 6 Ω resistor?
Answer:
Explanation:
Resultant of 12 and 3 ohm in series = 15 ohm
Resultant of 6 and 3 ohm = 9 ohm
Total resultant resistance of circuit = 15 x 9 / (15 + 9)
= 5.625 ohm
current drawn from battery = 4 / 5.625
= .711 A
ii )current through 12 ohm = 4 / (12 + 3 ) , because potential diff over 12 and 6 ohm will be 4 V .
current through 12 ohm = .267 A
iii )
current through 6 ohm
= .711 - .267
= .444 A
potential difference
= .444 x 6
= 2.664 V .
Is a motor a load that can be found in a circuit?
Answer:
yes you can find a motor in a circuit
The solubility of barium nitrate is 9.02 g/100 g H2O at 20°C. A 15.2 g sample of barium nitrate is added to 200.0 g of water at 20°C. Is the solution saturated, unsaturated, or supersaturated?
Answer:
The solution is unsaturated.
Explanation:
Saturated solutions are those solutions with the maximum amount of solute completely dissolved by the solvent. This indicates that although more solute is added, it does not dissolve. In this case the amount of solute is equal to the solubility coefficient.
The supersaturated solution is one in which the amount of solute exceeds the solubility of the solvent, that is, it has a greater amount of dissolved solute than that which it admits at that temperature. In this case a solution contains solute above the solubility coefficient.
A solution is considered to be unsaturated if the mass of dissolved solute is less than that corresponding to that of saturation. This indicates that it is possible to add more solute and that it dissolves. In this case the solution contains solute below the solubility coefficient.
The solubility of barium nitrate is 9.02 g/100 g H₂O at 20°C.
A 15.2 g sample of barium nitrate is added to 200.0 g of water at 20°C. This is: 15.2 g /200 g H₂O. Dividing by two you get: 7.6 g /100 g H₂O
Comparing with the solubility of barium nitrate, you can see that the mass of dissolved solute is less than the corresponding one. This indicates that the solution is unsaturated.
Barry walks from one end to the other of a 30-meter long moving walkway at a constant rate in 30 seconds, assisted by the walkway. When he reaches the end, he reverses direction and continue walking with the same speed, but this time it takes him 120 seconds because he is traveling against the direction of the moving walkway. If the walkway were to stop moving, how many seconds would it take Barry to walk from one end of the walkway to the other
Answer:
Δt=48 s
Explanation:
v: Barry's speed
v.: speed of the walkway
Δx=30 m
Δt1=30 s , Δt2=120 s
|Δx1|=|Δx2|
Δx=v*Δt
=> (v+v.)*30=(v-v.)*120
v=v.*5/3
30=(v+v.)*30
=> 30=(5v./3 +v.)*30
v.=3/8 m/s
v=5v./3 , v.=3/8
=> v=5/8 m/s
Δx=v*Δt
30=5/8 *Δt
Δt=48 s
Which is the best example of muscular endurance
Answer:
personally I'd say C by do not know if that is the exact answer
how much heat is required to raise the temperature of 5kg of iron from 50°c to250°c
Answer:
462000J
Explanation:
Quantity of heat= mass x specific heat capacity of iron x change in temp
specific heat capacity of iron is 462J/Kg/K
change in temp = 250-50= 200°C
200°C is equivalent to 200K since 1°C is 1K
Q= mct
= 5x462x200
= 462000J
A small child has a wagon with a mass of 10 kilograms. The child pulls on the wagon with a force of 2 newtons. What is the acceleration of the wagon?
Answer:
0.2 m/s²Explanation:
Given,
Mass ( m ) = 10 kg
Force ( f ) = 2 Newtons
Acceleration ( a ) = ?
Now, let's find the acceleration :
We know that,
[tex]f = ma[/tex]
Plug the values
[tex]2 = 10a[/tex]
Swap the sides of the equation
[tex]10a = 2[/tex]
Divide both sides of the equation by 10
[tex] \frac{10a}{10} = \frac{2}{10} [/tex]
Calculate
[tex]a = 0.2 \: {metre \: per \: second \: }^{2} [/tex]
Hope this helps...
Best regards!!
help me its emergency I need a correct answer please if you don't know then please dont guess
Answer:
True.
Explanation:
Total internal reflection is bound to occur when light travels from dense medium to less dense.
From the table given in the question above, we obtained:
Refractive Index of Crown glass = 1.52
Refractive Index of Asphalt = 1.635
From the above, Crown glass has a lower refractive index when compared to Asphalt. This means that Crown glass is less dense than Asphalt.
Therefore, total internal reflection will not occur when light travels from Crown glass to Asphalt because Crown glass is less dense than Asphalt.
Ask Your Teacher An electric utility company supplies a customer's house from the main power lines (120 V) with two copper wires, each of which is 34.0 m long and has a resistance of 0.109 Ω per 300 m. (a) Find the potential difference at the customer's house for a load current of 116 A.
Answer:
The potential difference at the customer's house is 117.1 V.
Explanation:
a) The potential difference at the customer's house can be calculated as follows:
[tex] \Delta V_{h} = \Delta V_{p} - \Delta V_{l} [/tex]
Where:
[tex]V_{h}[/tex]: is the potential difference at the customer's house
[tex]V_{p}[/tex]: is the potential difference from the main power lines = 120 V
[tex]V_{l}[/tex]: is the potential difference from the lines
[tex] \Delta V_{h} = \Delta V_{p} - IR [/tex]
The resistance, R, is:
[tex]\frac{0.109 \Omega}{300 m}*2*34.0 m = 0.025 \Omega[/tex]
Now, the potential difference at the customer's house is:
[tex]\Delta V_{h} = 120 V - 116A*0.025 \Omega = 117.1 V[/tex]
Therefore, the potential difference at the customer's house is 117.1 V.
I hope it helps you!
2x+4y
GCF for the polynomial
Answer:
[tex]\boxed{2}[/tex]
Explanation:
The GCF is the greatest common factor of the polynomial.
[tex]2x = 1, \ 2, \ x[/tex]
[tex]4y=1, \ 2, \ 4,\ y[/tex]
The greatest common factor is 2.
Two small, identical conducting spheres repel each other with a force of 0.035 N when they are 0.35 m apart. After a conducting wire is connected between the spheres and then removed, they repel each other with a force of 0.055 N. What is the original charge on each sphere? (Enter the magnitudes in C.)
Explanation:
Given:
distance between two sphere =0.35 m
Electrical repel force =0.035 N
Electrical repel force after connecting wire =0.055 N.
The electrical force between the two spheres:
[tex]F=k \frac{q_{1} q_{2}}{r^{2}}[/tex]
The electrical force between the two spheres after the wire is attached and removed:
[tex]F=k \frac{q^{2}}{r^{2}}[/tex]
[tex]q^{2}=\frac{F r^{2}}{k}[/tex]
[tex]q=r \sqrt{\frac{F}{k}}=0.35 \times \sqrt{\frac{0.055}{8.99 \times 10^{9}}}=6.46 \times 10^{-7} \mathrm{C}[/tex]
So the total charge of the two spheres [tex]=2 q=2 \times 6.46 \times 10^{-7}=1.29 \times 10^{-6} \mathrm{C}[/tex]
Then before connecting the wire, one sphere charge was [tex]q[tex] and the charge of the other sphere was [tex]\left(1.29 \times 10^{-6}-q\right)[/tex]
The electrical force between the two spheres before connecting the wire:
[tex]F=k \frac{q\left(1.29 \times 10^{-6}-q\right)}{r^{2}}[/tex]
[tex]q\left(1.29 \times 10^{-6}-q\right)=\frac{F r^{2}}{k}=\frac{0.035 \times(0.35)^{2}}{8.99 \times 10^{9}}=0.348 \times 10^{-12}[/tex]
[tex]-q^{2}+\left(1.29 \times 10^{-6}\right) q-\left(0.348 \times 10^{-12}\right)=0[/tex]
[tex]-q^{2}+\left(1.29 \times 10^{-6}\right) q-\left(0.348 \times 10^{-12}\right)=0[/tex]
The mass density of a certain planet is uniform throughout the volume of the planet. If r is the distance from the center of the planet to a point mass inside the planet, the gravitational force on the mass is
Answer:
F= GMm/r^2
Explanation:
According to newtons formula for gravitation,
F= GMm/r^2
Hello Guys! Could u help me with this question. Starting with an initial velocity of 2 m/s, Rohan pressed the accelerator of his car to attain a velocity of 12 m/s in 30s. Then he applies the brakes such that the car comes to rest in the next 15s. Calculate the acceleration of the car in both the cases.
Imagine that your standing on a beach but cannot swim. Your friend encourages you to walk into the surf zone created by incoming deep-water waves that have a wavelength of 30 meters. Would it be safe to walk out to where the waves are breaking? Explain how you arrived at your answer.
Answer:
It would not be safe to walk out to where waves are breaking due to the effect of rip currents
Explanation:
The water depth in the surf zone is between 5 to 10 meters deep and with a wavelength of 30 meters, the speed of the wave is considerably fast such that control for safety may be difficult
Also the speed of the wave is directly related to the depth of the water which means that where the wave described above is fast as well as the rip current, also the water depth is expected to be considerable for a non swimmer
It is best to seek for sign post regarding safe areas and do not go into the water where there are no lifeguards or marked safe zones.
It won't be safe to walk out to where the waves are breaking.
This is because the wavelength is 30 meters which is a characteristic of
areas with significant water depth in the range of 5-11 meters.Under these
conditions the waves are usually very fast and may get swept with the
current from the water waves when trying to run from it.
It is recommended that we stay in areas where the depth is noted as not
being much and should always seek help and clarity from the life guards so
as to prevent drowning and death.
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You and a friend are on a swing set and her swing is slightly longer than yours. If you both start swinging at the same time, from the same height, where will she be after you have completed one complete swing back and forth?
a. She will still be at the same height as you.
b. She will be slightly higher than you.
c. She will be slightly lower than you but moving downward away from you.
d. She will be slightly lower than you but moving upward toward you.
Answer:
d. She will be slightly lower than you but moving upward toward you.
Explanation:
Since your swing is slightly shorter than your friend's swing, then you will have more angular speed than your friend. Angular speed increases with a decrease in radius. The closer the body is to the center, the faster the body swings. By the time you would have completed one complete swing back and forth, your friend will just be moving towards you, and she will be slightly lower than you but moving upwards towards you. This principle is the same reason gymnasts pull their limbs closer to their body when they need to swing faster.
(blank)a0 is undeniably accepted by scientists all over the world as the primary language of science.
Answer:
English.
Explanation:
English is undeniably accepted by scientists all over the world as the primary language of science. It is a language spoken all over the world and is also the language of science because it is an official language and can be understood by almost everyone.
Answer:
[tex]\boxed{\mathrm{English}}[/tex]
Explanation:
English is undeniably accepted by scientists all over the world as the primary language of science. The scientific methods and experiments are done by communicating and writing in English. Scientists use English to communicate and share knowledge as English is understood by people from around the world.
Velocity is a description of an object’s blank
Velocity is the description of an object's motion from one point to another.
It tells the speed with which the trip is completed, and the direction from the start-point to the end-point. It tells nothing about any twists, turns, loops, bends, or stops along the way.
How does increasing frequency affect the crests of a wave?
They get higher.
They get closer together.
They get lower.
They get farther apart.
Answer:
they get closer together
Explanation:
calculate the magnitude of the electric field intensity in vacuum at a distance of 20 cm from a charge of 5 * 10 raise to power - 3 column
Answer:
1.1259*10^9 Newton per Columb
Explanation:
the magnitude of the electric field intensity can be calculated using the expresion below;
E=Kq/r^2
Where k= constant
q= electric charge
r=distance= 2cm= 20*10^-2m( we convert to m for unit consistency
:,K=59*10^9 Columb
If we substitute the value into above formula we have
E=(9*10^9)*(5*10^-3)/(20*10^-2)^2
=1.1259*10^9 Newton per Columb
Therefore,the magnitude of the electric field intensity in vacuum at a distance of 20 cm is 1.1259*10^9 Newton per Columb
Laboratory measurements show hydrogen produces a spectral line at a wavelength of 486 nm. A particular galaxy's spectrum shows the same hydrogen line at a wavelength of 484 nm. What can we conclude?
Answer:
*if a hydrogen emission line is observed in the galaxy, this implies that the galaxy has a significant amount of a chemical element
*difference between the two wavelengths e can be explained by the relativistic Doppler effect
Explanation:
The emission of the materials depends on the distribution of the electrons around the atoms and their possible transitions. These emissions are maintained even when the element is mixed in some compound.
Consequently, if a hydrogen emission line is observed in the galaxy, this implies that the galaxy has a significant amount of a chemical element.
The small difference between the two wavelengths e can be explained by the relativistic Doppler effect, due to the movement of the galaxy
A piano has a mass of 99 kg. What is the weight of the piano?
Explanation:
weight of the piano = mg
w = 99 x 10 =990 N
Bumper car A (281 kg) moving +2.82 m/s makes an elastic collision with bumper car B (209 kg) moving +1.72 m/s. What is the velocity of car B after the collision?
The velocity of car B after the calculation can be obtained as 5.5 m/s.
What is a collision?We have to look at the principle of the conservation of the linear momentum and that is what we need so as to be able to deal with the problem that we have in this question as we have it here.
We know that the total momentum of the system would have to be constant and the implication of this is that the momentum before collision must be the same as the momentum after collision if we have been able to designate the system as a closed system.
Using the formula as we have shown it, we know that;
Momentum before Collison must be equal to momentum after collision
As such we have the following as shown below;
(281 * 2.82) + (209 * 1.72) = (281 * 0) + (209 * v)
792.42 + 359.48 = 209 v
v = 5.5 m/s
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You can chew through very tough objects with your incisors because they exert a large force on the small area of a pointed tooth. What pressure in Pa can you create by exerting a force of 360 N with your tooth on an area of 1.08 mm2
Answer:
3.33×10⁸ Pa
Explanation:
Pressure: This can be defined as the force acting normally (perpendicular) per unit area. The S.I unit of force is N/m² or Pa.
P = F/A.................. Equation 1
Where F = force created with the tooth, A = Area.
Given: F = 360 N, A = 1.08 mm² = 1.08/1000000 = 1.08×10⁻⁶m.
Substitute this values into equation 1
P = 360/1.08×10⁻⁶
P = 3.33×10⁸ Pa.
Hence the pressure created = 3.33×10⁸ Pa
Which statement describes one feature of a closed circuit? Charges do not flow. Bulbs will not shine. The circuit is broken. The circuit is complete.
I inferred you've referring to a close electrical circuit.
Answer:
The circuit is complete.
Explanation:
A closed electrical circuit is indeed a complete circuit. Also, it allows charges to flow, the bulbs in the circuit will shine and it is not broken.
It is termed closed circuit because there is no brokage in the series of electrical wires or the switch; which may prevent the free flow of current or charges. Thus, a feature that marks closed circuits is that they are complete.
Answer:
The circuit is complete.
Explanation:
9) Of all the types of light the Sun gives off, it emits the greatest amount of light at visible wavelengths of light. If the Sun were to cool off dramatically and as a result start giving off mainly light at wavelengths longer than visible light, how would the frequency, energy, and speed of this light given off by the Sun also be different? Explain your reasoning.
Answer:
* most of the emission would be in the infrared part, the visible radiation would be very small.
*total intensity of the semition decreases that the intensity depends on the fourth power of the temperature
Explanation:
The radiation emitted by the Sun is approximately the radiation of a black body, if the Sun were to cool, the maximum emission wavelength changes
λ T = 2,898 10⁻³
λ = 2,898 10⁻³ / T
if the temperature decreases the maximum wavelength the greater values are moved, that is to say towards the infrared. Therefore the emission curve also moves, in this case most of the emission would be in the infrared part, the visible radiation would be very small.
Furthermore, the total intensity of the semition decreases that the intensity depends on the fourth power of the temperature according to Stefan's law
P = σ A eT⁴
7.Why are we able to drink cold drink with straw from a bottle?
Explanation:
Because of air pressure
Calculating heat gained, need help!!!
Q=(m)(c)(triangle T)
trial 1:
Q=(0.4)(4.186 J/kg)(78)=?
trial 2:
Q=(0.6)(4.186 J/kg)(78)=?
trial 3:
Q=(0.45)(4.186 J/kg)(75)=?
Explanation:
q = mCΔT
where m is mass,
C is specific heat capacity,
and ΔT is change in temperature.
Make sure all your units match. Assuming the substance is water, C = 4186 J/kg/°C.
Trial 1:
q = (0.4 kg) (4186 J/kg/°C) (78°C)
q = 130,600 J
Trial 2:
q = (0.6 kg) (4186 J/kg/°C) (78°C)
q = 195,900 J
Trial 3:
q = (0.45 kg) (4186 J/kg/°C) (75°C)
q = 141,300 J