The time taken for the car's tires to complete one full rotation when it car drives down the road at 6m/s. The tires on the car have a diameter of .7m. is 0.37 s.
What is time?Time is the measure of the duration of past , present or future event.
To calculate the time taken for the tires to complete one full rotation, we use the formula below.
Formula:
v = 2πr/t............ Equation 1Where:
v = Velocity of the carr = radius of the tiret = timeπ = pie
Make t the subject of the equation
t = 2πr/v............... Equation 2From the question,
Given:
r = 0.7/2 = 0.35 mv = 6 m/sπ = 3.14Substitute these values into equation 2
t = (2×0.35×3.14)/6t = 0.37 s.Hence, The time taken for the car's tires to complete one full rotation is 0.37 s.
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Minnie sota hits the end of a bar 1. 2 m long with a hammer. Sketch the standing wave on the bar for the following situations. The speed of waves in the bar is 6,500. M/s
(a) The wavelength of the wave for the fundamental mode is 2.4 m.
(b) The fundamental frequency of the wave is 2,708.33 Hz.
Wavelength of the wave for fundamental modeThe wavelength of the wave for the fundamental mode is calculated as follows;
Node to Node, N → N = λ/2
L = λ/2
λ = 2L
λ = 2 x 1.2
λ = 2.4 m
Fundamental frequency of the waveThe fundamental frequency of the wave is calculated as follows;
f = v/λ
f₀ = v/2L
f₀ = (6500)/(2 x 1.2)
f₀ = 2,708.33 Hz
The diagram of the wave for the fundamental mode is in the image uploaded.
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Please see attached.
Answer:
D
Explanation:
The speed is increasing and he was stationary which means the acceleration is not 0
Based on the first law of thermodynamics, the energy gained by a system is _____ the energy lost by the surroundings.
Based on the first law of thermodynamics, the energy gained by a system is equal to the energy lost by the surroundings.
Laws of thermodynamicsThe laws of thermodynamics can be summarised as follow
The first law states that energy can neither be created nor destroyed. The second law states that the entropy of the universe will always increase for every spontaneous process. The third law states that for a perfect crystal at zero Kelvin, the entropy is zero.From the laws given above precisely the first law, we can conclude that the energy gained by a system is equal to the energy lost by the surroundings
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20. Free-Body Diagram You are sitting in the back seat of a
car going around a curve to the right. Sketch motion
and free-body diagrams to answer these questions:
a. What is the direction of your acceleration?
b. What is the direction of the net force on you?
Centripetal acceleration
#1
Direction towards centre#2
Direction of force also towards centre
An empty coal car of a train of mass 8000 kg is moving at 12 m/s along rails. 24000 kg of coal is dumped into the car from a motionless bin. What is the speed of the coal car afterward?
Answer:
3 m/s
Explanation:
Initial = Final
Mass * Velocity = Mass *Velocity
8000kg * 12m/s = (8000kg+ 24000kg) * (Final Velocity)
(96000 kgm/s) / (32000kg) = (Final Velocity)
Final Velocity = 3 m/s
The speed of the coal car afterward is 3 m/s if an empty coal car of a train of mass 8000 kg is moving at 12 m/s along rails. 24000 kg of coal is dumped into the car from a motionless bin.
What is the law of conservation of momentum?The momentum of the body before the contact is always equal to the momentum of the body after the collision, according to the law of conservation of momentum.
According to the law of conservation of momentum;
Momentum before collision =Momentum after collision
We have:
Mass of the empty coal car of train M(e) = 8000 kg
Speed V(e) = 12 m/s
Mass of the coal M(c) = 24000 kg
Let's suppose the speed of the coal car afterward V(c)
M(e) ×V(e) = (M(c)+M(e))× V(c)
8000×12 = (24000+8000)×V(c)
V(c) = 3 m/s
Thus, the speed of the coal car afterward is 3 m/s if an empty coal car of a train of mass 8000 kg is moving at 12 m/s along rails. 24000 kg of coal is dumped into the car from a motionless bin.
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Under which condition would time periods of daylight and darkness be equal everywhere on Earth all year?.
If the earth rotated on an axis that was not tilted with respect to earth's orbit Under this condition time periods of daylight and darkness be equal everywhere on earth all year.
What is the earth's orbit?The Earth orbits the Sun in a counterclockwise pattern above the northern hemisphere at an average distance of 149.60 million km.
The Earth revolves around its axis once every 24 hours and orbits the sun once every 365 days. The Earth's rotation on its axis, not its orbit around the sun, causes day and night.
The term 'one day' refers to the time it takes the Earth to rotate once on its axis, which includes both day and night.
Hence the earth rotated on an axis that was not tilted with respect to the earth's orbit Under this condition time periods of daylight and darkness be equal everywhere on earth all year.
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A 20 kω resistor is connected in series with an initially uncharged 100 μf capacitor and a 5 v battery. What is the charge on the capacitor when the circuit has reached steady state?
Hi there!
We can use the equation for the charge of a charging capacitor:
[tex]q(t) = C\epsilon( 1 - e^{-\frac{t}{RC}})[/tex]
Using Capacitor equations:
[tex]C = \frac{Q}{V}}\\\\Q = CV[/tex]
Therefore, Cε equals the steady-state charge of the capacitor (the function approaches this value as t ⇒ ∞.
We can plug in the givens and solve.
[tex]\epsilon = 5 V\\\\C = 100\mu F = 0.0001 F[/tex]
[tex]Q = C \epsilon = (0.0001)(5) = \boxed{0.0005 C}[/tex]
The charge on the capacitor when the circuit has reached a steady-state is 0.0005C.
What is capacitance?The capacitance of a conductor is defined as the ratio of the quantity of electric charge stored on it to the difference in electric potential.
Given that the resistance of the resistor is 20 kω, while the capacitance of the capacitor is 100 μf, and the voltage of the battery is 5V.
Now, the charge on the capacitor when the circuit has reached a steady-state can be written as,
[tex]Q=CV\\\\Q = 100\mu F \times 5V\\\\Q = \dfrac{100}{1,000,000}F \times 5V\\\\Q = 0.0005C[/tex]
Hence, the charge on the capacitor when the circuit has reached a steady state is 0.0005C.
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Is a dog barking an example of kinetic energy to potential energy
Which scientist received a nobel prize for the discovery of x-rays?.
Answer:
That's Rontgen
Explanation:
Wilhem Rontgen
Different between :
Metalloids and alloys
Answer:
Alloys are just mixtures of metal and metalloids are metallic substances with properties of metal.
Answer:
metalloids are chemical elements that form substances that have properties of metals and non metals while alloys is a mixture of metals
A compression spring with a spring constant of 200 N/m catches a ball that's falling with
kinetic energy of 0.5 J. How far will the spring compress to stop the ball?
Pls help It would be great if someone can show the steps too thank u
Answer:
distance of compression: 0.07071 m
Explanation:
[tex]\sf energy = \dfrac{1}{2} kx^2[/tex]
[tex]\rightarrow \sf 0.5= \dfrac{1}{2} (200)x^2[/tex]
[tex]\rightarrow \sf 0.5= (100)x^2[/tex]
[tex]\rightarrow \sf 5\ *\ 10^{-3}= x^2[/tex]
[tex]\rightarrow \sf x = \sqrt{5\ *\ 10^{-3}}[/tex]
[tex]\rightarrow \sf x =0.07071 \ m[/tex]
A radio has a frequency of 220 hertz (Hz). The wavelength sound produced is 4.2m. Identify
the speed of the wave. Equation: Speed= wavelength x frequency (Hz)
A. 11m/s
B. 0.01m/s
C. 52.3m/s
D. 924m/s
Question :-
A Radio has a Frequency of 220 Hertz . The Sound produced by the Wavelength is 4.2 meter . Identify the Speed of the Wave .11 m/s0.01 m/s52.3 m/s924 m/sAnswer :-
Speed of the Wave is 924 m/s .Explanation :-
As per the provided information in the given question, we have been given that the Frequency of the Radio is 220 Hertz . Wavelenght is given as 4.2 meter . And, we have been asked to calculate the Speed of the Wave .
For calculating the Speed , we will use the Formula :-
[tex] \bigstar \: \: \: \boxed{ \sf{ \: Speed \: = \: Wavelength \: \times \: Frequency \: }} [/tex]
Therefore , by Substituting the given values in the above Formula :-
[tex] \dag \: \: \: \sf{Speed \: = \: Wavelength \: \times \: Frequency} [/tex]
[tex] \longmapsto \: \: \: \sf{Speed \: = \: 4.2 \: \times \: 220} [/tex]
[tex] \longmapsto \: \: \: \textbf {\textsf {Speed \: = \: 924 }} [/tex]
Hence :-
Fourth Option is Correct Answer .[tex] \underline {\rule {180pt} {4pt}} [/tex]
Answer:
A Radio has a Frequency of 220 Hertz . The Sound produced by the Wavelength is 4.2 meter . Identify the Speed of the Wave .
11 m/s
0.01 m/s
52.3 m/s
924 m/s
Answer :-
Speed of the Wave is 924 m/s .
Explanation :-
As per the provided information in the given question, we have been given that the Frequency of the Radio is 220 Hertz . Wavelenght is given as 4.2 meter . And, we have been asked to calculate the Speed of the Wave .
For calculating the Speed , we will use the Formula :-
\bigstar \: \: \: \boxed{ \sf{ \: Speed \: = \: Wavelength \: \times \: Frequency \: }}★
Speed=Wavelength×Frequency
Therefore , by Substituting the given values in the above Formula :-
\dag \: \: \: \sf{Speed \: = \: Wavelength \: \times \: Frequency}†Speed=Wavelength×Frequency
\longmapsto \: \: \: \sf{Speed \: = \: 4.2 \: \times \: 220}⟼Speed=4.2×220
\longmapsto \: \: \: \textbf {\textsf {Speed \: = \: 924 }}⟼Speed = 924
Hence :-
Fourth Option is Correct Answer .