Complete question is;
A car is new at the beginning of a calendar year. The time, in years, before the car experiences its first failure is exponentially distributed with mean 2. Calculate the probability that the car experiences its first failure in the last quarter of some calendar year.
Answer:
Probability = 0.2052
Step-by-step explanation:
I've attached the explanation to this answer.
Mark the absolute maximum point of the graph.
is the absolute maximum point (-3,5)?
Please help out show work ty!
Answer:
C
Step-by-step explanation:
This is because it has a constant rate of change.
5 x 1.5 = 7.5
6 x 1.5 = 9
7 x 1.5 = 10.5
You can find this image by dividing y by x and testing this rate of change on the other y values. Thus C is correct.
This is Algebra 1 functions and I'm struggling with this one function-
-1•f(-9)+7•g(6)=_____
Answer:
38
Step-by-step explanation:
f(-9) is the value of f(x) when x = -9. Therefore, f(-9) = 4 from the graph. Doing the same with g(6), we can see that g(6) = 6. Our expression becomes:
-1 * 4 + 7 * 6
= -4 + 42
= 38
HELP ASAP PLEASE answer quickly
Answer:
A. [tex]\frac{3}{5}[/tex]
B. [tex]\frac{7}{10}[/tex]
C. B (you already got that right)
Step-by-step explanation:
To find the probability of something, we have to see how many times it happened over the total amount of attempts.
On Tuesday the target was hit 18 times in 30 attempts. So our probability fraction is [tex]\frac{18}{30}[/tex] which simplifies to [tex]\frac{3}{5}[/tex].
Looking at the total results, we can see Ben hit the target 84 times out of 120, so the fraction is [tex]\frac{84}{120}[/tex] which simplifies to [tex]\frac{7}{10}[/tex].
There’s always one rule of statistics/probability - the more data the better. If we want to create a more reliable probability, we’d want more data, and the total data gives us more than just Tuesday’s Data.
Hope this helped!
There are 25 students in Mr. Jones’ art class. Mr. Jones is planning a project where each student needs 0.3 jar of paint. Exactly how much paint does Mr. Jones need for the art project?
Answer:
7.5 jars
Step-by-step explanation:
There are 25 students in the art class.
Mr Jones is planning that for the project, each of the 25 students will need 0.3 jar of paint.
The amount of paint Mr Jones needs for this project is therefore the product of the number of students in the class by the amount of paint each student needs.
That is:
25 * 0.3 = 7.5 jars of paint
Mr Jones needs 7.5 jars of paint for the art project.
30% of a number is 45 what is the number ?
Hey there! I'm happy to help!
When talking about percents, the word "is" usually means equals. Let's use this to solve an equation! We will call our number n. Note that 30% is equal to 0.3 in decimal form because 0.3 is 30% of one! :D
0.3n=45
To solve, we need to isolate the n. To do this, we divide both sides by 0.3 because this cancels out the 0.3 that is being multiplied by n and it shows us what n will then equal.
0.3n÷0.3=45÷0.3
n=150
Therefore, 30% of 150 is 45. Try multiplying 0.3 by 150 and you will get 45!
Have a wonderful day! :D
Please answer this question now
Answer:
541.4 m²
Step-by-step Explanation:
Step 1: find m < V
V = 180 - (50+63) (sum of the angles in ∆)
V = 67
Step 2: find side length of XW using the law of sines
[tex] \frac{XW}{sin(V)} = \frac{XV}{sin(W)} [/tex]
Where,
V = 67°
W = 63°
XV = 37 m
XW
[tex] \frac{XW}{sin(67)} = \frac{37}{sin(63)} [/tex]
Multiply both sides by sin(67) to solve for XW
[tex] \frac{XW}{sin(67)}*sin(67) = \frac{37}{sin(63)}*sin(67) [/tex]
[tex] XW = \frac{37*sin(67)}{sin(63)} [/tex]
[tex] XW = 38.2 m [/tex] (to nearest tenth)
Step 3: find the area using the formula, ½*XW*XV*sin(X)
area = ½*38.2*37*sin(50)
Area = 541.4 m² (rounded to the nearest tenth.
Please answer this question now
Answer:
Step-by-step explanation:
The side y is across from the angle Y which is 68 degrees. Angle Y is next to both the hypotenuse (14 units) and adjacent to the side XY (5 units). If we are finding side y, we need to use one of the trig ratios that relates the angle Y to the side across from it. That would be either the sin of Y which is the side opposite y) over the hypotenuse (14) or the tan of Y which is the side opposite over the side adjacent. Either one will get you the side lengths within a tenth or hundredth of each other. Let's do both, just because. First the sine:
[tex]sin(68)=\frac{y}{14}[/tex] and
14sin(68) = y so
y = 12.98 and rounded to the nearest tenth is 13.0
Now the tangent:
[tex]tan(68)=\frac{y}{5}[/tex] and
5tan(68) = y so
y = 12.37 and rounded to the nearest tenth is 12.4.
As an integer, your answer would be 13; as a decimal it would be the 12.4
Apparently, either is fine.
Show that (a - b)+(b-c)+(c -a)3 = 3 (a - b) (b -c) (c-a)
Answer:
I think that it should be
[tex] {(a - b)}^{3} + {(b - c)}^{3} + {(c - a)}^{3} = 3(a - b)(b - c)(c - a)[/tex]
Step-by-step explanation:
Here,
we take , a - b = A,b-c = B , c - a= C
A+B+C = 0
we know that,
[tex] {a}^{3} + {b}^{3} + {c}^{3} - 3abc = (a + b + c)( {a}^{2} + {b}^{2} + {c}^{2} - ab - bc - ca)[/tex]
Here , A+B+C = 0
so,
A^3 +B^3 + C^3 = 3 ABC
now we put the values
[tex]{(a - b)}^{3} + {(b - c)}^{3} + {(c - a)}^{3} = 3(a - b)(b - c)(c - a)[/tex]
I am done .
I think that it should be
{(a - b)}^{3} + {(b - c)}^{3} + {(c - a)}^{3} = 3(a - b)(b - c)(c - a)
Step-by-step explanation:
Here,
we take , a - b = A,b-c = B , c - a= C
A+B+C = 0
we know that,
{a}^{3} + {b}^{3} + {c}^{3} - 3abc = (a + b + c)( {a}^{2} + {b}^{2} + {c}^{2} - ab - bc - ca)
Here , A+B+C = 0
so,
A^3 +B^3 + C^3 = 3 ABC
now we put the values
{(a - b)}^{3} + {(b - c)}^{3} + {(c - a)}^{3} = 3(a - b)(b - c)(c - a)
I am done .
What are the square roots of; (note: i think there are supposed to be 2 each) 36 12 1.96 0.64 400 25/36
Answer:
36 : 6 and -6
12 = [tex]2\sqrt{3} , -2\sqrt{3}[/tex]
1.96 =1.4 and -1.4
0.64 : 0.8 and -0.8
400 : 20 and -20
25/36 = 5/6 and -5/6
Step-by-step explanation:
we know that
(-x)^2 = x^2
ALSO
(x)^2 = x^2
thus, square of both negative and positive number is same positive number.
_________________________________________________
36 = 6*6
36 = -6*-6
hence
square roots of 36 is both -6 and 6
12 = 4*3 = [tex]2^2*\sqrt{3} *\sqrt{3}[/tex]
[tex]\sqrt{12} = 2\sqrt{3}[/tex]
also
12 = [tex]-2\sqrt{3} *-2\sqrt{3}[/tex]
[tex]\sqrt{12} = -2\sqrt{3}[/tex]
___________________________________
1.96 = 196/100 = (14/10)^2
1.96 = 196/100 = (-14/10)^2
hence
[tex]\sqrt{1.96} = 14/10 \ or -14/10[/tex]
_______________________________
0.64 = 64/100 = (8/10)^2 = 0.8^2
0.64 = 64/100 = (-8/10)^2 = (-0.8)^2
Thus, square root of 0.64 = 0.8 and -0.8
_________________________________
400 = 20^2
400 = (-20)^2
[tex]\sqrt{400} = 20\\\sqrt{400} = -20\\[/tex]
__________________________________
25/36 = (5/6)^2
25/36 = (-5/6)^2
[tex]\sqrt{ 25/36} = 5/6 \\\sqrt{ 25/36} = (-5/6[/tex]
Find the value of x in the
following parallelogram:
2x - 10
2x + 50
Answer:
The value of x is 35
Step-by-step explanation:
In order to calculate the value of x in the following parallelogram: 2x - 10
2x + 50, we would have to calculate the following formula:
m<QPS+m<PQR=180°
According to the given data we have the following:
m<QPS=2x - 10
m<PQR=2x + 50
Therefore, 2x - 10+2x + 50=180
4x+40=180
x=140/4
x=35
determine the area and the circumference of the flat shape
Answer:
Hey there!
Circumference: [tex]2\pi r+95+95[/tex]
Area: [tex]\pi r^2+70(95)[/tex]
r=35
Circumference: 410
Area: 10498.
Hope this helps :)
Answer:
Area= 10498.5 cm²
Step-by-step explanation:
Area of rectangle= l x w
= 95 x 70 = 6650
Area of circle = πr²
= π x 35²
= 1225π
=3838.5 cm²
Area of shape: 6650 + 3848.5 = 10498.5 cm²
The diameter of a circle is 3.5 inches. What is the circumference of the circle?
Answer:
About 11 (10.9955742876...)
Step-by-step explanation:
Circumference=(pi) (diameter) or C=πd
Hope this helps!
The circumference of the circle is about 11 inches.
We are given that the diameter of a circle is 3.5 inches.
Noted that the circumference of the circle that has a radius of r is defined as the product of diameter to the pie value.
Therefore circumference of the circle = 2πr
Circumference=(2πr)
The diameter or C = πd
diameter = 3.5 inches
Circumference=(3.5 x 3.14)
Circumference = (10.99) inches
Learn more about circumference here;
brainly.com/question/12512221
#SPJ2
Write an equation of the line that passes through the point (–4, 6) with slope –4.
Answer:
y = - 4x - 10
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = - 4 , thus
y = - 4x + c ← is the partial equation
To find c substitute (- 4, 6) into the partial equation
6 = 16 + c ⇒ c = 6 - 16 = - 10
y = - 4x - 10 ← equation of line
Answer:
y = -4x+10
Step-by-step explanation:
Using the slope intercept form of a line
y = mx+b where m is the slope and b is the y intercept
y = -4x +b
Substituting the point in
6 = -4(-4) + b
6 = 16+b
Subtract 16 from each side
-10 =b
The equation is
y = -4x+10
The first three steps in determining the solution set of the system of equations algebraically are shown.
y = x2 − x − 3
y = −3x + 5
What are the solutions of this system of equations?
(−2, −1) and (4, 17)
(−2, 11) and (4, −7)
(2, −1) and (−4, 17)
(2, 11) and (−4, −7)
Answer:
(2, −1) and (−4, 17)
Step-by-step explanation:
I used a graphing tool to graph the systems of equations. The parabola and line pass at points (2, -1) and (-4, 17).
Answer:(2, −1) and (−4, 17) Its C on Edge 2023
Step-by-step explanation: Its (C) after an extensive research
Please help me as fast as you can. thanks
Answer:
<DEF = 40<EBF = <EDF = 56<DCF = <DEF =40<CAB = 84Step-by-step explanation:
In triangle DEF, we have:
Given:
<EDF=56
<EFD=84
So, <DEF =180 - 56 - 84 =40 (sum of triangle angles is 180)
____________
DE is a midsegment of triangle ACB
( since CD=DA(given)=>D is midpoint of [CD]
and BE = EA => E midpoint of [BA] )
According to midsegment Theorem,
(DE) // (CB) "//"means parallel
and DE = CB/2 = FB =CF
___________
DEBF is a parm /parallelogram.
Proof: (DE) // (FB) ( (DE) // (CB))
AND DE = FB
Then, <EBF = <EDF = 56
___________
DEFC is parm.
Proof: (DE) // (CF) ((DE) // (CB))
And DE = CF
Therefore, <DCF = <DEF =40
___________
In triangle ACB, we have:
<CAB =180 - <ACB - <ABC =180 - 40 - 56 =84(sum of triangle angles is 180)
[tex]HOPE \: THIS \: HELPS.. GOOD \: LUCK! [/tex]
Figure G is rotated 90Degrees clockwise about the origin and then reflected over the x-axis, forming figure H. On a coordinate plane, triangle G has points (negative 3, 1), (negative 1, 2), (negative 2, 5). Triangle H has points (2, negative 1), (1, negative 3), (5, negative 2). Which sequence of transformations will produce the same results?
Answer:
The 1st selection is appropriate.
_____
2nd: the rotation would need to be 90° CCW
3rd, 4th: rotation or double reflection will give the original orientation. This figure is reflected an odd number of times, so has its orientation reversed.
Hope it helps.. Mark brainliest
The sequence of transformations are reflection over the y-axis and then a rotation 90 clockwise about the origin.
What is rotation rule of 90°?Here are the rotation rules: 90° clockwise rotation: (x, y) becomes (y, -x) 90° counterclockwise rotation: (x, y) becomes (-y, x) 180° clockwise and counterclockwise rotation: (x, y) becomes (-x,-y).
Given that, figure G is rotated 90° clockwise about the origin and then reflected over the x-axis, forming figure H.
Vertices of triangle G are (-3, 1), (-1, 2) and (-2, 5).
The reflection of point (x, y) across the y-axis is (-x, y).
On reflection over x-axis, we get coordinates as (3, 1), (1, 2) and (2, 5)
90° clockwise rotation: (x, y) becomes (y, -x)
On 90° clockwise rotation, we get coordinates as (1, -3), (2, -1) and (5, -2)
Triangle H has points (2, -1), (1, -3), (5, -2).
Hence, the sequence of transformations are reflection over the y-axis and then a rotation 90° clockwise about the origin.
Learn more about the rotation of 90° counterclockwise here:
brainly.com/question/1571997.
#SPJ6
find two rational numbers whose sum is -10,0,15
Answer:
Sum of two rational numbers-
-10 = -5+-5
0= -5+5
15= 10+5
Step-by-step explanation:
Area of a triangle is 1400 cm² the base of the triangle is 5 times the height what is the height of the triangle
Answer:
≈23.66
Step-by-step explanation:
Height ---> x
base ---> 5x
Formula for area of triangle: (base*height)/2
((5x)(x))/2 = 1400
[tex]5x^{2}[/tex]/2 = 1400
[tex]5x^{2}[/tex] = 1400 · 2 = 2800
[tex]x^2[/tex] = 2800/5 = 560
x= √560 ≈ 23.66
7. The radius of a cylinder whose curved surface area is 2640 2 and height 21 cm is _________. (a) 100 ° (b) 50° (c) 80° (d) 90°
Answer:
The answer is 21.25cm
Step-by-step explanation:
Hope i am marked as brainliest
Y varies directly as cube root of
[tex]x[/tex]
And y=3 when
[tex]x = 27[/tex]
A. Find the value of the constant
B. Find the relationship
C. Find the value of y when
[tex]x = 8[/tex]
Step-by-step explanation:
Y varies directly as cube root of x is written as
y = k³√x
where k is the constant of proportionality
A).when y = 3
x = 27
We have
[tex]3 = k \sqrt[3]{27} [/tex]
But ³√27 = 3
That's
3 = 3k
Divide both sides by 3
k = 1
The value of the constant is 1B).The value of the relationship is
[tex]y = \sqrt[3]{x} [/tex]C).When x = 8
We have
[tex]y = \sqrt[3]{8} [/tex]y = 2Hope this helps you
The figure above shows a right-angled triangle OAB. AOC is a minor sector enclosed in the triangle. If OA = 7 cm, AB = 6 cm, calculate the area and perimeternof the shaded region. PLEASE HELP!
Answer:
Step-by-step explanation:
Given that:
OA = 7 cm, AB = 6 cm. ∠A = 90°, OA = OC = 7 cm
Using Pythagoras theorem: OB² = OA² + AB²
OB² = 6² + 7²=85
OB = √85 = 9.22 cm
to find ∠O, we use sine rule:
[tex]\frac{AB}{sin(O)}=\frac{OB}{sin(A)}\\ \\sin(O)=\frac{AB*sin(A)}{OB}=\frac{6*sin(90)}{9.22} =0.65 \\\\O=sin^{-1}0.65=40.6^o[/tex]
AOC is a minor sector with radius 7 cm and angle 40.6
The Area of the triangle OAB = 1/2 × base × height = 1/2 × OA × AB = 1/2 × 7 × 6 = 21 cm²
Area of sector OAC = [tex]\frac{\theta}{360}*\pi r^2=\frac{40.6}{360}*\pi *7^2=17.37 \ cm^2[/tex]
Area of shaded region = The Area of the triangle OAB - Area of sector OAC = 21 - 17.37 = 3.63 cm²
Perimeter of arc AC = [tex]\frac{\theta}{360}*2\pi r=\frac{40.6}{360}*2\pi *7=4.96\ cm[/tex]
CB = OB - OC = 9.22 - 7 = 2.22
Perimeter of shaded region = AB + CB + arc AC = 6 + 2.22 + 4.96 = 13.18 cm
Abenfos has a rectangular field.it is 85m long and 25m wide. How long is the fence round the field?
Answer:
The fence must have:
220 meters
Step-by-step explanation:
The perimeter of the field is equal to the long of the fence round the field.
then:
perimeter = 2(long + wide)
perimeter = 2(85 + 25)
perimeter = 2*110
perimeter = 220m
PLEASE HELP!!!
What does it mean to say that a data point has a residual of -1?
Answer: Option C, 1 unit bellow.
Step-by-step explanation:
The residual of a data point is equal to the vertical distance between the point and the regression line
If the data point is above the line, the residual is positive
if the data point is below the line, the residual is negative.
So here we have a negative residual equal to -1
This would mean that our point is 1 unit below the regression line.
Then the correct option is C.
Answer:
The answer is 1 unit below.
Step-by-step explanation:
This is because the residual is the difference between the actual value of a dependent variable & the value predicted by a regression equation. So if the data point has a residual of -1, that means that the data point lies 1 unit below the regression line.
the hypotnuse of a 45 -45 -90 triangle measures 22√2 units. what is the length of the leg of the triangle?
Answer:
22 units.
Step-by-step explanation:
In 45- 45- 90 triangles, there is a 1 to 1 to the square root of 2 formula. Each side length measures 1x, while the hypotenuse measures x times the square root of 2.
In this case, the hypotenuse measures 22 and the square root of 2 units. To find the value of x, simply divide that by the square root of 2 units, and you get x = 22 units. Multiply that by 1, and you get 22 units, which is the length of the leg of the triangle.
Hope this helps!
Sketch the graph of y=-3(x-3)2+4 and identify the axis of symmetry.
Answer:
The axis of symmetry of parabola is the equation where it cuts the middle of the graph.
So the axis of symmetry is x = 2 .
y=8-2x. What is the value of y when x = 8?
Answer:
y = -8
Step-by-step explanation:
Start by filling 8 in place of x
y = 8 - 2(8)
Multiply -2(8)
y = 8 - 16
Subtract 16 from 8
y = -8
Please help me.. T-T
Step-by-step explanation:
The inequality is [tex]\frac{x}{-3}[/tex] >2
[tex]\frac{x}{-3}[/tex] > 2 multiply each side by -3 x < 2*(-3) the sign is switched since we multiplied by a negative number x < -6x is less than -6 and -6 is excluded so it will be represented by an empty circle and a line going toward negative values
so it's D
Please answer this question now
Answer:
36°
Step-by-step explanation:
<U + < V + <W = 180° (sum of angles in a triangle)
<W = 54°
The tangent is always perpendicular to the radius drawn to the point of tangency...
therefore,
<U = 90°
90° + <V + 54° = 180°
144° + <V = 180°
<V = 180° - 144°
<V = 36°
Answer:
V=36
Step-by-step explanation:
tangent makes rigt angle with radius angle U=90
W+V+U=180
V=180-90-54
V=36
will mark brainliest!!!plz helppp
Answer:
(5,-6)
Step-by-step explanation:
ONE WAY:
If [tex]f(x)=x^2-6x+3[/tex], then [tex]f(x-2)=(x-2)^2-6(x-2)+3[/tex].
Let's simplify that.
Distribute with [tex]-6(x-2)[/tex]:
[tex]f(x-2)=(x-2)^2-6x+12+3[/tex]
Combine the end like terms [tex]12+3[/tex]:
[tex]f(x-2)=(x-2)^2-6x+15[/tex]
Use [tex](x-b)^2=x^2-2bx+b^2[/tex] identity for [tex](x-2)^2[/tex]:
[tex]f(x-2)=x^2-4x+4-6x+15[/tex]
Combine like terms [tex]-4x-6x[/tex] and [tex]4+15[/tex]:
[tex]f(x-2)=x^2-10x+19[/tex]
We are given [tex]g(x)=f(x-2)[/tex].
So we have that [tex]g(x)=x^2-10x+19[/tex].
The vertex happens at [tex]x=\frac{-b}{2a}[/tex].
Compare [tex]x^2-10x+19[/tex] to [tex]ax^2+bx+c[/tex] to determine [tex]a,b,\text{ and } c[/tex].
[tex]a=1[/tex]
[tex]b=-10[/tex]
[tex]c=19[/tex]
Let's plug it in.
[tex]\frac{-b}{2a}[/tex]
[tex]\frac{-(-10)}{2(1)}[/tex]
[tex]\frac{10}{2}[/tex]
[tex]5[/tex]
So the [tex]x-[/tex] coordinate is 5.
Let's find the corresponding [tex]y-[/tex] coordinate by evaluating our expression named [tex]g[/tex] at [tex]x=5[/tex]:
[tex]5^2-10(5)+19[/tex]
[tex]25-50+19[/tex]
[tex]-25+19[/tex]
[tex]-6[/tex]
So the ordered pair of the vertex is (5,-6).
ANOTHER WAY:
The vertex form of a quadratic is [tex]a(x-h)^2+k[/tex] where the vertex is [tex](h,k)[/tex].
Let's put [tex]f[/tex] into this form.
We are given [tex]f(x)=x^2-6x+3[/tex].
We will need to complete the square.
I like to use the identity [tex]x^2+kx+(\frac{k}{2})^2=(x+\frac{k}{2})^2[/tex].
So If you add something in, you will have to take it out (and vice versa).
[tex]x^2-6x+3[/tex]
[tex]x^2-6x+(\frac{6}{2})^2+3-(\frac{6}{2})^2[/tex]
[tex](x+\frac{-6}{2})^2+3-3^2[/tex]
[tex](x+-3)^2+3-9[/tex]
[tex](x-3)^2+-6[/tex]
So we have in vertex form [tex]f[/tex] is:
[tex]f(x)=(x-3)^2+-6[/tex].
The vertex is (3,-6).
So if we are dealing with the function [tex]g(x)=f(x-2)[/tex].
This means we are going to move the vertex of [tex]f[/tex] right 2 units to figure out the vertex of [tex]g[/tex] which puts us at (3+2,-6)=(5,-6).
The [tex]y-[/tex] coordinate was not effected here because we were only moving horizontally not up/down.