A chemist determines by measurements that moles of nitrogen gas participate in a chemical reaction. Calculate the mass of nitrogen gas that participates.

Answers

Answer 1

Answer:

0.56 g

Explanation:

A chemist determines by measurements that 0.020 moles of nitrogen gas participate in a chemical reaction. Calculate the mass of nitrogen gas that participates.

Step 1: Given data

Moles of nitrogen gas (n): 0.020 mol

Step 2: Calculate the molar mass (M) of nitrogen gas

Molecular nitrogen is a gas formed by diatomic molecules, whose chemical formula is N₂. Its molar mass is:

M(N₂) = 2 × M(N) = 2 × 14.01 g/mol = 28.02 g/mol

Step 3: Calculate the mass (m) corresponding to 0 0.020 moles of nitrogen gas

We will use the following expression.

m = n × M

m = 0.020 mol × 28.02 g/mol

m = 0.56 g


Related Questions

What is the mass number for an atom of zinc containing 30 protons and 34 neutrons?

Answers

Answer:

64

Explanation:

mass number =proton + neutron

=30+34=64

Which describes a difference between cephalopods and gastropods?

Cephalopods have a water vascular system, and gastropods have an open circulatory system.
Cephalopods live only in ocean environments, and gastropods live in a variety of environments.
Cephalopods have a simple nervous system, and gastropods have a complex nervous system.
Cephalopods are the largest group of mollusks, and gastropods are the smallest group of mollusks. CAN SOMEONE PLZZZZ ANWER THIS I WILL GIVE U 15 PIONTS

Answers

Answer:

B

Explanation:

I took the test

Answer:

The correct answer is B

Explanation:

What are the products of the acid-base reaction of sodium carbonate with acetic acid?

Answers

Answer:

The mixture quickly foams up with carbon dioxide gas. If enough vinegar is used, all of the baking soda can be made to react and disappear into the vinegar solution. The reaction is: Sodium bicarbonate and acetic acid reacts to carbon dioxide, water and sodium acetate.

Explanation:

hope this helps

Question 3 (1 point)
Consider the following unbalanced chemical equation representing the combustion of methane, yielding carbon dioxide and water.
CH4 + O2 --> CO2 + H20
If you had burned 800 g of methane, how many moles of Carbon dioxide would be produced?

A)122.22
B)8
C)2200
D)100
E)670

F)750
G)50

Answers

Answer:

Im pretty sure its B

Explanation:

Answer:

G) 50 mol

Explanation:

Given data:

Mass of methane = 800 g

Number of moles of CO₂ produced = ?

Solution:

Chemical equation:

CH₄ + 2O₂      →      CO₂ + 2H₂O

Number of moles of methane:

Number of moles = mass/molar mass

Number of moles = 800 g/ 16 g/mol

Number of moles = 50 mol

Now we will compare the moles of methane and carbon dioxide.

                 CH₄        :         CO₂

                    1           :          1

                  50          :        50


Why does solid water (ice) float when placed in liquid water? *
Ice does not float in liquid water.
Ice is less dense than liquid water.
Ice is more dense than liquid water.
The densities of liquid water and ice are the same .

Answers

Answer:

Ice is less dense than water.

A chemist dissolves of pure potassium hydroxide in enough water to make up of solution. Calculate the pH of the solution. (The temperature of the solution is .) Be sure your answer has the correct number of significant digits.

Answers

Answer:

12.99

Explanation:

A chemist dissolves 716. mg of pure potassium hydroxide in enough water to make up 130. mL of solution. Calculate the pH of the solution. (The temperature of the solution is 25 °C.) Be sure your answer has the correct number of significant digits.

Step 1: Given data

Mass of KOH: 716. mg (0.716 g)Volume of the solution: 130. mL (0.130 L)

Step 2: Calculate the moles corresponding to 0.716 g of KOH

The molar mass of KOH is 56.11 g/mol.

0.716 g × 1 mol/56.11 g = 0.0128 mol

Step 3: Calculate the molar concentration of KOH

[KOH] = 0.0128 mol/0.130 L = 0.0985 M

Step 4: Write the ionization reaction of KOH

KOH(aq) ⇒ K⁺(aq) + OH⁻(aq)

The molar ratio of KOH to OH⁻is 1:1. Then, [OH⁻] = 0.0985 M

Step 5: Calculate the pOH

We will use the following expression.

pOH = -log [OH⁻] = -log 0.0985 = 1.01

Step 6: Calculate the pH

We will use the following expression.

pH + pOH = 14

pH = 14 - pOH = 14 -1.01 = 12.99

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