a circle of radius r has area a = πr2. if a random circle has radius that is uniformly dis- tributed on [0, θ]: what are the mean and variance of the area of the circle?

Answer:

Approximately 68% of the area under a standard normal distribution curve is within one standard deviation of the mean, also known as the 68-95-99.7 rule.

Specifically, the rule states that:

This means that if we have a normally distributed dataset with a mean of 0 and a standard deviation of 1, approximately 68% of the data points will fall within the range of -1 to +1 standard deviations from the mean.

If we consider a mountain number with its middle digit is larger than any other digit, then there are possible three-digit mountain numbers are equals the 240.

A number is called a 'mountain' if its decimal digits insitiate with 1, i.e. 'base camp', increase continuously to one largest digit, then decrease continuously back to one i.e. back to base camp. We have a number is called a mountain number. Now, there are 100 to 999 total 3-digit numbers. Now, with 2 in the middle, we have = 2 numbers[1 x 2] - 120 = 121

So, we have a total of Total Number = 2 + 6 + 12 + 20 + 30 + 42 + 56 + 72 = 240 "mountain numbers". Hence, the required number , value is 240.

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Let's label the 8 questions as Q1, Q2, Q3, Q4, Q5, Q6, Q7, and Q8.

Let's label the 8 students as A, B, C, D, E, F, G, and H.

Since each problem has been correctly solved by exactly 5 students, we can say that the following is true:

Q1: A, B, C, D, E

Q2

A) The expected value of the sampling distribution is 0.40.

B) The standard error is 0.05.

C) The sampling distribution will be centered around the population proportion of 0.40, with a spread given by the standard error of 0.05.

D) By examining the sampling distribution, we can see how likely it is to obtain a certain sample proportion by chance alone, and therefore make conclusions about the population based on the sample.

A) The expected value (also called the mean) of a sampling distribution is equal to the population parameter being estimated. In this case, the population parameter is the proportion, p, which is 0.40.

B) The standard error is the standard deviation of the sampling distribution. For a proportion, the formula for the standard error is √((p(1-p))/n), where p is the population proportion and n is the sample size. Plugging in the values given, we get √((0.40(1-0.40))/100) = 0.049.

C) The sampling distribution of a proportion is approximately normal if both np and n(1-p) are greater than or equal to 10. In this case, np = 1000.40 = 40 and n(1-p) = 100*0.60 = 60, so the conditions for normality are met.

D) The sampling distribution of a proportion shows the distribution of all possible sample proportions of a given size that could be drawn from a population with a known proportion.

The sampling distribution allows us to make inferences about the population proportion, such as constructing confidence intervals or conducting hypothesis tests.

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Complete Question:

A random sample of size 100 is selected from a population with p =0 .40.

A. What is the expected value (to 2 decimals)?

B. What is the standard error (to 2 decimals)?

C. Show the sampling distribution (to 2 decimals).

D. What does the sampling distribution of show?

Answer:

Hm

Step-by-step explanation:

The bacteria population is observed to double after five days, which means that its growth rate is 100% over a period of five days. This corresponds to a daily growth rate of r = 100%/5 = 20%.

If the initial population is 10,000, then the bacteria population after d days can be modeled by the exponential function:

f(d) = 10,000 * (1 + r/100)^d

Substituting r = 20% and simplifying, we get:

f(d) = 10,000 * (1.2)^d

Therefore, the correct option is:

D. f(d) = 10,000 * (1.2)^d

Answer:

square, quadrilateral, rhombus, parallelogram, rectangle



Answer:

Quadrilateral, rectangle, parallelogram, rhombus, square

Step-by-step explanation:

It is a quadrilateral bc it has four sides.

It is a rectangle bc it has four right angles.

It is a parallelogram bc it has two pairs of parallel sides.

It is a rhombus bc all four sides are congruent.

It is a square bc it is both a rectangle and a rhombus.

The predicted total number of calories for a food containing 25 grams of fat is approximately 483.55. 

The equation for the least-squares regression line is:

z = 13.198x + 153.6

where ŷ= predicted value of y (total calories), x = value of the predictor variable (grams of fat), 13.198= slope of the line, and 153.6= y-intercept of the line.

To find the predicted total calories for a food with 25 grams of fat, simplify by substituting x = 25 into the equation.

z = 13.198x + 153.6

ŷ = 13.198(25) + 153.6

ŷ = 329.95 + 153.6

z = 483.55

Therefore, the predicted total number of calories for a food containing 25 grams of fat is approximately 483.55. 

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a) The expression for the amount of pure copper sulfate in 3x liters of 25% solution is  0.675x.

b) The percentage of pure copper sulfate in the resulting solution is 39.375%.

Since the solution is 25% copper sulfate, we know that there are 0.25(3x) = 0.75x liters of copper sulfate in the solution.

The amount of pure copper sulfate in the solution is given by 0.9 times the amount of copper sulfate. Therefore, the expression for the amount of pure copper sulfate in 3x liters of 25% copper sulfate solution is:

0.9(0.75x) = 0.675x

The amount of pure copper sulfate added from the 90% copper sulfate solution is 0.9x liters.

The amount of pure copper sulfate in the 25% copper sulfate solution is 0.675x liters.

The total amount of pure copper sulfate in the resulting solution is:

0.9x + 0.675x = 1.575x

The total volume of the resulting solution is:

x + 3x = 4x

To find the percentage of pure copper sulfate in the resulting solution, we divide the amount of pure copper sulfate by the total volume of the solution and multiply by 100:

(1.575x / 4x) * 100 = 39.375%

Therefore, the percentage of pure copper sulfate in the resulting solution is 39.375%.

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The mean and median are both measures of center, but which one is more appropriate depends on the data set.

Appropriate behavior is behavior that is socially acceptable and respectful of others. This includes treating others with kindness, politeness, and respect, refraining from using offensive language, and not engaging in hurtful or violent behavior. Appropriate behavior also means following established rules, laws, and cultural norms. Examples of appropriate behavior include being honest and trustworthy, showing respect for others and their property, and being courteous and polite.

The mean is the average of the data set and is affected by extreme values. The median is the middle value in the data set and is not affected by extreme values. If the data set has extreme values, the median is usually the more appropriate measure of center. If the data set does not have extreme values, the mean is usually the more appropriate measure of center.

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Based on the given pattern:

2 x 4 + 1 = 3 x 3

3 x 5 + 1 = 4 x 4

4 x 6 + 1 = __ + __

__ x 7 + 1 = __ x __

__ x __ + __ = __ + __

The general pattern is that the first term is multiplied by one more than itself, and then 1 is added to the result, which is equal to the second term squared.

When the first term is 25, the equation would look like:

25 x 26 + 1 = __ + __

The first blank would be filled with 26, and the second blank would be filled with 676 (which is 26 squared). So the complete equation would be:

25 x 26 + 1 = 26 + 676

The probability that the auto policyholder will file exactly one type of claim is 0.40.

To calculate the probability, let M be the event that the policyholder files a medical claim and P be the event that the policyholder files a property claim. We are given:

P(M) = 0.30

P(P) = 0.42

P(M or P) = 0.60

We want to calculate the probability that the policyholder files exactly one type of claim, given that the policyholder will not file both types of claims. This can be expressed as:

P(exactly one type of claim | not both types of claims) = P((M and not P) or (not M and P)) / P(not both types of claims)

We can use the fact that:

P(not both types of claims) = P(M or P) - P(M and P)

To calculate the numerator, we have:

P((M and not P) or (not M and P)) = P(M and not P) + P(not M and P)

We can use the fact that:

P(not P) = 1 - P(P)

To calculate:

P(M and not P) = P(M) - P(M and P)

Putting everything together, we get:

P(M and not P) = 0.30 - P(M and P) = 0.30 - (0.60 - 0.30) = 0.00

P(not M and P) = P(P) - P(M and P) = 0.42 - (0.60 - 0.30) = 0.12

P((M and not P) or (not M and P)) = 0.00 + 0.12 = 0.12

P(not both types of claims) = 0.60 - 0.30 = 0.30

Therefore:

P(exactly one type of claim | not both types of claims) = 0.12 / 0.30 = 0.40

So the probability that the auto policyholder will file exactly one type of claim, given that the policyholder will not file both types of claims, is 0.40.

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The height of the door frame is approximately [tex]68.2 + 2t = 68.2 + 2\sqrt(131.2) \approx95.1[/tex]inches.

Basic geometry concepts.

Firstly, we need to recognize that the two identical rectangular tiles form a vertical rectangle in both figure 1 and figure 2.

Let's call the height of this rectangle "h" and the width "w".
In figure 1, we can see that the distance from the top of the rectangle to the top of the door frame is "h".

Similarly, the distance from the bottom of the rectangle to the bottom of the door frame is also "h".

Therefore, the height of the door frame is simply the sum of the height of the rectangle and the height of the two tiles.
Height of door frame = h + 2t
"t" is the height of one tile.
Next, we can use the same logic for figure 2.

The distance from the top of the rectangle to the top of the door frame is now "y".

Similarly, the distance from the bottom of the rectangle to the bottom of the door frame is "z".

Therefore, we can write:
[tex]Height of door frame = (h - t) + 2t[/tex]
Where (h - t) is the height of the rectangle above the tiles.
Now, we can equate the two expressions for the height of the door frame:
[tex]h + 2t = (h - t) + 2t[/tex]
Simplifying, we get:
h = 3t
We are given that the distance from w to h is 45 inches, so we can use Pythagoras' theorem to find the length of the rectangle:
[tex]w^2 + h^2 = 45^2[/tex]
Substituting h = 3t, we get:
[tex]w^2 + 9t^2 = 2025[/tex]
Similarly, we can use the information in figure 2 to get another equation:
[tex]w^2 + 4t^2 = 1369[/tex]
Now we have two equations with two variables (w and t), which we can solve simultaneously.

Subtracting the second equation from the first, we get:
[tex]5t^2 = 656[/tex]
Therefore,
[tex]t^2 = 131.2[/tex]
And
[tex]h = 3t = 3sqrt(131.2)[/tex][tex]\approx68.2 inches[/tex]
Finally, we can use the Pythagorean theorem again to find the length of the door frame:
[tex]w^2 + h^2 = 45^2[/tex]
Substituting h = 68.2, we get:
[tex]w^2 + 68.2^2 = 2025[/tex]
Solving for w, we get:
[tex]w \approx 41.2 inches[/tex]

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The statements that are true are:

→ Line Segment KL ≅ Line Segment JM

→ Quadrilateral JKLM is a trapezoid.

A trapezoid is a quadrilateral with at least one pair of parallel sides. The parallel sides are called the bases of the trapezoid, and the non-parallel sides are called the legs.

In the quadrilateral JKLM

Using the distance formula, we can find the lengths of the line segments:

JK = √[(7-3)² + (8-5)²] = √58

KL = √[(13-7)² + (5-8)²] = √58

LM = √[(13-13)² + (0-5)²] = 5

JM = √[(13-3)² + (0-5)²] = √109

From this, we can analyze each statement:

a.) Line Segment KL ║ Line Segment JM

We can see from the sketch that the two line segments are not parallel. Therefore, statement a is false.

b.) Line Segment KL ≅ Line Segment JM

We found that the length of KL is equal to the length of JM. Therefore, statement b is true.

c.) Line Segment JK ≅ Line Segment LM

We can see from the sketch that the two line segments are not congruent. Therefore, statement c is false.

d.) Line Segment JK ║ Line Segment LM

We can see from the sketch that the two line segments are perpendicular. Therefore, statement d is false.

e.) Quadrilateral JKLM is a trapezoid.

A trapezoid is defined as a quadrilateral with at least one pair of parallel sides. We can see from the sketch that line segments KL and JM are not parallel, but line segments JK and LM are parallel. Therefore, statement e is true.

f.) Quadrilateral JKLM is an isosceles trapezoid.

An isosceles trapezoid is defined as a trapezoid with congruent base angles and congruent non-parallel sides. We can see from the sketch that neither the base angles nor the non-parallel sides are congruent. Therefore, statement f is false.

Therefore, the statements that are true are b and e.

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Answer:

A) KL⎯⎯⎯⎯⎯∥JM⎯⎯⎯⎯⎯

C) JK⎯⎯⎯⎯⎯≅LM⎯⎯⎯⎯⎯⎯

E) Quadrilateral JKLM is a trapezoid.

F) Quadrilateral JKLM is an isosceles trapezoid.

Step-by-step explanation:

These where the correct answer I got when taking the assignment with that question

The GCF of 48 and 60 is 12

To find the greatest common factor (GCF) of 48 and 60, we can start by finding the prime factorization of each number

48 = 2^4 × 3

60 = 2^2 × 3 × 5

Next, we can identify the common factors of both numbers by looking at their prime factorization

The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

The factors of 60 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

The common factors of 48 and 60 are: 1, 2, 3, 4, 6, and 12.

The greatest common factor is the largest number that both 48 and 60 can be divided evenly by. In this case, that number is 12. Therefore, the GCF is 12.

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The given question is incomplete, the complete question is:

Find the GCF of 48 and 60.

The 95% confidence interval for the standard deviation of the height of students at UH is (1.918, 5.732), which corresponds to option b.

To construct a 95% confidence interval for the standard deviation of the height of students at UH, we will use the Chi-square distribution. Given the sample standard deviation (s) of 3.2 feet, a sample size (n) of 19 students, and assuming normality for the data, we can find the confidence interval as follows:
1. Determine the degrees of freedom: df = n - 1 = 19 - 1 = 18
2. Identify the Chi-square values for the confidence level (95%): χ²_lower = 7.632, χ²_upper = 32.852 (using a Chi-square table or calculator)
3. Calculate the lower and upper bounds of the confidence interval:
Lower bound = sqrt((n - 1) * s² / χ²_upper) = sqrt(18 * (3.2)² / 32.852) ≈ 1.918
Upper bound = sqrt((n - 1) * s² / χ²_lower) = sqrt(18 * (3.2)² / 7.632) ≈ 5.732

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The 95% confidence interval for the standard deviation of the height of students at UH is approximately (1.918, 5.732), Option B.

Construct a 95% confidence interval for the standard deviation of the height of students at UH, we'll use the given data and the Chi-Square distribution.

Here's a step-by-step explanation:
SRS (simple random sample) of 19 students, which means the degrees of freedom (df) = n - 1 = 19 - 1 = 18.
The sample standard deviation (s) is given as 3.2 feet.
Assume normality for the data.
A 95% confidence interval, we'll use the Chi-Square distribution table to find the critical values.

The two tail probabilities are 0.025 and 0.975, so we'll look up the Chi-Square values for 18 degrees of freedom and these probabilities:
[tex]- X^2_{0.025} = 30.191 (upper limit)[/tex]
[tex]- X^2_{0.975} = 8.231 (lower limit)[/tex]
Calculate the confidence interval for the population standard deviation (σ):
[tex][tex](\sqrt((n - 1) \times s^2 / X^2_{upper}), \sqrt((n - 1) \times s^2 / X^2_{lower}))[/tex][/tex]
Plug in the values:
[tex]- n = 19[/tex]
[tex]- s = 3.2[/tex]
[tex]- df = 18[/tex]
[tex][tex]- X^{2} _{upper} = 30.191[/tex][/tex]
[tex][tex]- X^2_{lower} = 8.231[/tex][/tex]
Calculate the confidence interval:
[tex](√((18 \times 3.2^2) / 30.191), \sqrt((18 \times 3.2^2) / 8.231)) \approx (1.918, 5.732)[/tex]

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The area of a circle is given by the formula:

A = πr^2

where r is the radius of the circle.

Substituting the value of the radius as r = 10 cm, we get:

A = π(10)^2

A = 100π

Therefore, the area of the circle with radius 10 cm is 100π square centimeters.

~~~Harsha~~~

Thus, the given quadratic equation has two real roots x = 3 and x = -2.

A function or mathematical statement of degree two is a quadratic function. This indicates that two is the function's highest power. The roots of all quadratic functions are two.

Given equation:

x² - x - 6 = 0

Using the quadratic formula:

x = [-b ± √(b² - 4ac) ] / 2a

a = 1 , b = -1 and c = -6

x = [1 ± √((-1)² - 4*1*(-6) ] / 2*1

x = [1 ± √(1 + 24) ] / 2

x = [1 ± 5 ] / 2

Now,

x = (1 + 5)/2 = 3

x = (1 - 5)/ 2 = -2

Thus, the given quadratic equation has two real roots x = 3 and x = -2.

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complete question:

Check whether the given equation has, one solution, two solution ,many solution or no real solution.

x² - x - 6 = 0

Answer:

a 1053

b 250

multiply 650 by 1.62 for part a.

for part b divide by 1.62 since pound is less than dollar

hope this helps :)

The area of the shaded area is 3.27 ft²

We can find the area of the shaded area by subtracting the area of the triangle from the area of the sector. That is;

Area of shaded area = Area of sector - area of triangle

Area of shaded area = (60/360 * π * 6²) - (1/2 * 6 * 6 * sin 60)

Area of shaded area = (60/360 * 22/7 * 36) - (1/2 * 36 * 0.866)

Area of shaded area = 3.27 ft²

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Answer:

B) 3p/9

D)1/3p

Step-by-step explanation:

The area of space with no carpet is 268.25 sq ft.

In order to calculate the area of square room we have to subtract the section that is not carpeted from the total area of the room.

The given dimensions of the room is 16 1/2‘ x 16 1/2‘ square room

therefore,

16.5 x 16.5 = 272.25 sq ft

now if we consider that the entertainment system is 2 feet in measurement then,

2 x 2 = 4 sq ft

hence, the space with no carpet is

271.25 - 4

= 268.25 sq feet

The area of space with no carpet is 268.25 sq ft.

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Answer: The least common denominator is 3x(x+10)

The equation will have 2 valid solutions

Step-by-step explanation: sorry if wrong

1) A histogram would be the best graphical representation for the teacher's data on the subject preferences of students. 2) The correct circle graph is option 2. 3) Option 4: Paddleboarding.

The frequency or relative frequency of the data points falling within each interval is depicted by the height of the bars in a histogram, which is a graphical representation of the distribution of continuous data. Histograms are frequently used in data analysis to show how a single variable is distributed and to spot any patterns or trends. Additionally, they can be used to compare the distributions of two or more variables or to spot anomalies or outliers in the data.

1) A histogram would be the best graphical representation for the teacher's data on the subject preferences of students.

2) Given the type of transportation we have he total number of visitors as:

(120+24+45+30+81=300)

Now, for walk we have:

120/300 = 40/100 = 40%

For Bicycle we have:

24/300 = 8%

Thus, the correct circle graph is option 2: circle graph titled New York City visitor's transportation, with five sections labeled walk 40 percent, bicycle 8 percent, car service 15 percent, bus 10 percent, and subway 27 percent

3) For the central angle to be 54 the number of campers needs to correspond to this number. The activity that corresponds to 54 degrees is Paddleboarding.

4) For the number of principals in conference we set up a proportionality with total people as follows:

We know that, 52 principals out of 70 people thus:

52/70 = x/750

Now,

x = (52/70) * 750

x = 557.14

Hence, we can predict that there were about 557 principals in attendance at the conference.

5) Given that, out of 225 students 27 prefer cookies thus,

27/225 = 0.12

That is 12% students like cookies.

Now, for the total number of students we have:

0.12 * 4000 = 480

Thus, option A: The college will have about 480 students who prefer cookies.

6) For the given description of the line plot the median is:

For Bus 47 = 16

For Bus 18 = 13

The faster bus is Bus 47, with a median of 16.

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Hence, OC bisects AB, as congruent parts of congruent triangles are equal.

When two or more geometric figures are similar in size, form, and orientation, this is referred to as congruency in geometry. Two figures can be overlaid on one another by translation, rotation, and/or reflection when they are congruent because they are almost similar to one another and do not alter in size, form, or orientation.

For the given problem, the complete steps of proof with reasoning are:

(a) OC is perpendicular to AB in circle O (given). i.e ∠OCA and ∠OCB are right angles.

Reason: This is given in the problem statement. It establishes that OC forms a right angle with AB at point C in circle O. i

(b) Draw OA and OB (construction).

Reason: This is a construction step that introduces radii OA and OB from the center O of the circle to points A and B on the circle. This sets up the framework for the subsequent steps and establishes the positions of A and B in relation to the circle and the perpendicular OC.

(c) OA = OB (radii of the same circle are equal).

Reason: Radii of the same circle are always equal in length. This is a basic property of circles, where all radii have the same length, which can be stated as OA = OB based on the definition of a circle.

(d) OC = OC (Reflexive Property of Equality)

Reason: It is a property of line segments that they are equal to themselves. This is known as the Reflexive Property of Equality, which states that any quantity is equal to itself.

(f) AC = BC (common side of congruent triangles).

Reason: AC and BC are line segments that are both radii of the same circle, and OA = OB (Step c). Therefore, by the definition of congruent segments, AC = BC.

(e) Triangle ACO is congruent to triangle BCO (HL congruence criterion for right triangles).

Reason: Angle ACO and angle BCO are both right angles based on the given information that OC is perpendicular to AB (Step a). Also, AC = BC (Step d) and OA = OB (Step c). Therefore, by the Hypotenuse-Leg congruence criterion for right triangles, triangle ACO is congruent to triangle BCO.

(g) OC bisects AB (congruent parts of congruent triangles are equal).

Reason: Since triangle ACO is congruent to triangle BCO (Step e), the corresponding parts of congruent triangles are equal. In this case, OC is a common side (hypotenuse) of both triangles, and AB is a side of both triangles. Therefore, by the definition of a segment bisector, OC bisects AB.

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The value of f square plus g square is 61.

How to find square of any number?

To find the square of a number, you can multiply that number by itself.

Write the number you want to square. Let's use the number "x" as an example.

Raise the number to the power of 2 by using the exponentiation operator (^) or by multiplying the number by itself. Either way, the result is the same. The expression to calculate the square of a number can be written as x² = x × x = x²

For example, to find the square of 5, you can multiply 5 by 5, which gives you 25.

So,the square of 5 is 25.

In mathematical notation, the square of a number "x" can be represented as "x²". So, the square of 5 can also be written as 5², which equals 25.

If f = 5 and g = 6, then f square (f²) is 5² = 25 and g square (g²) is 6² = 36. Therefore, f² + g² = 25 + 36 = 61. So, f square plus g square when f is 5 and g is 6 is 61.

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Correct question is "What is f square plus g square? Where f is equal to 5 and g is equal to 6."

1. Multiply both sides by 2. 4 + 3x = 5 * 2
2. Simplify. 4 + 3x = 10
3. Subtract 4 from both sides to single out x. 3x = 10 - 4
4. Simplify. 3x = 6
5. Divide by 3. x = 6/3
6. Simplify. x = 2

Input 2 into the original equation to check this answer and you will get 5 = 5 which means that x = 2 is your final answer.

Answer: x = 2

Step-by-step explanation:

    To solve for x, we will isolate the variable (x).

Given:

    [tex]\displaystyle \frac{4+3x}{2}=5[/tex]

Multiply both sides of the equation by 2:

    4 + 3x = 10

Subtract 4 from both sides of the equation:

    3x = 6

Divide both sides of the equation by 3:

    x = 2

The total surface area of the composite shapes are 69 square cm, 63 square cm and 108 square yd

The surface area of composite shapes can be found by breaking the composite shape down into simpler shapes and then finding the surface area of each individual shape.

Once the surface areas of all the individual shapes are found, they can be added together to find the total surface area of the composite shape.

Figure 1

Here, we have

Area = Area of rectangle + square

So, we have

Area = 5 * 5 + 4 * 11

Area = 69 square cm

Figure 2

Here, we have

Area = Area of  square + triangle

So, we have

Area = 7 * 7 + 1/2 * 7 * 4

Area = 63 square cm

Figure 3

Here, we have

Area = Area of rectangle + square

So, we have

Area = 12 * 6 + 6 * 6

Area = 108 square yd

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Answer

Number 14: 7 faces, 15 edges, and 10 vertices.

Number 15: 10 faces, 24 edges, and 16 vertices.

Number 16: 7 faces, 12 edges, and 7 vertices.

:D

Step-by-step explanation:

The approximate volume of the small truck is 577.5 cubic feet.

A truck that would be best for them to rent is the 3-Bedroom Moving Truck.

The volume of the Mega Moving Truck is about 641.25 cubic feet greater than the 2-bedroom moving truck.

In Mathematics and Geometry, the volume of a rectangular prism can be calculated by using the following formula:

Volume of a rectangular prism = L × W × H

Where:

For the approximate volume of the small truck, we have;

Volume of small truck = 11 1/3 × 7 5/12 × 7

Volume of small truck = 577.5 cubic feet.

The approximate volume of each moving truck can be calculated as follows;

2-Bedroom Moving Truck = 14.5 × 7.5 × 7 = 761.25 cubic feet.

3-Bedroom Moving Truck = 21 × 7.5 × 8 = 1,260 cubic feet.

Mega Moving Truck = 22 × 7.5 × 8.5 = 1,402.5 cubic feet.

Difference = 1,402.5 cubic feet - 761.25 cubic feet

Difference = 641.25 cubic feet.

Read more on volume of prism here: brainly.com/question/21012007

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