A college needs to transport 135 fans from the an area parking lot to the baseball game if each bus holds 27 people how many buses should college plan to use

The volume of cone is 2 cubic units.

In this image, we have :

The cylinder has a volume of 18 cubic units and a height of 3.

The cone has a congruent base and the same height.

We have to find the volume of the cone.

We know that:

Volume of the cylinder is :

Volume of cylinder = [tex]\pi r^{2} h[/tex]__(A)

18 = [tex]\pi r^2(3)[/tex]

[tex]\pi r^2= 6[/tex]

Now, Volume of cone = [tex](1/3)\pi r^{2} h[/tex]___(B)

and, The cone has a congruent base and the same height.

substitute equation A in equation B

Volume of cone = (1/3)volume of cylinder

Volume of cone = (1/3) × 6

Volume of cone = 2 units.

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Answer:

option c

Step-by-step explanation:

as it is between 80 and closely 100 adding both the intervals gives 17

The measure of a central angle of a regular polygon with 24 sides is 15°. There is no need to round the answer as it is already in whole degrees.

The measure of a central angle of a regular polygon with 24 sides. A central angle is formed by two radii drawn from the center of the polygon to two consecutive vertices. In a regular polygon, all the sides and angles are equal.

To find the measure of a central angle, you can use the formula: Central Angle = (360°) / (Number of Sides) In this case, the regular polygon has 24 sides.

So the formula would be: Central Angle = (360°) / (24) Now, we can solve for the central angle: Central Angle = 15° So, the measure of a central angle in a regular polygon with 24 sides is 15 degrees. Since the result is already in whole degrees, there's no need to round it to the nearest tenth of a degree

To find the measure of a central angle of a regular polygon with 24 sides, you can use the formula:

Central angle = (360°) / (number of sides)

In this case, the number of sides is 24, so the formula becomes:

Central angle = (360°) / 24

Central angle = 15°

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Answer:

b

Step-by-step explanation:

trust ne

In the given Markov chain X, all states other than the absorbing state s are transient.

To answer this question, we need to show that all states other than the absorbing state s are transient.

First, let's define what it means for a state to be transient. A state i is said to be transient if, starting from state i, the Markov chain has a non-zero probability of never returning to state i. In other words, there is some positive probability that the Markov chain will eventually leave state i and never come back.

Now, we know that all states communicate with the absorbing state s, which means that there is some positive probability Pis(n) for each state i to eventually reach s after n steps. Since s is an absorbing state, once the Markov chain reaches state s, it will stay there forever.

Therefore, if a state i is not equal to s, then there must be some positive probability that the Markov chain will eventually leave state i and reach state s, where it will stay forever. In other words, state i is transient since there is some positive probability that the Markov chain will never return to state i after leaving it.

So, to summarize, all states other than the absorbing state s are transient in this Markov chain. I hope this helps! Let me know if you have any other questions.

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The cost per pound of the soup is $4.06 per pound (rounded to the nearest cent).

To find the cost per pound of the soup, we need to calculate the total cost of all the ingredients and divide it by the total weight of the soup.

The total cost of potatoes is 3 pounds × $3.62 per pound = $10.86.

The total cost of cod is 5 pounds × $4.56 per pound = $22.80.

The total cost of fish broth is 3 pounds × $3.66 per pound = $10.98.

So, the total cost of all the ingredients is:

$10.86 + $22.80 + $10.98 = $44.64

The total weight of the soup is 3 + 5 + 3 = 11 pounds.

Thus, the cost per pound of soup is:

$44.64 / 11 pounds = $4.06 per pound

Therefore, the cost per pound of the soup is $4.06 per pound (rounded to the nearest cent).

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Answer:

1. The medical assistant utilized a total of 200 thermometer probe covers this week at the clinic when taking patient temperatures.

2. The teenage patient grew a total of 5 7/8 inches this year.

3. The infant weighed 14 pounds by his 6-month check-up appointment.

4. There are 24 1-teaspoon doses in a bottle of children's Tylenol.

Step-by-step explanation:

mark brainliest

Answer:

It's D. 6.I think i am right,you can choose letter D.If it's be false you can scold me ok?

A characteristic that cannot be observed cannot be measured in an epidemiologic study. This statement is False

Epidemiologic studies can measure various characteristics that cannot be directly observed, such as underlying health conditions, genetic factors, psychological traits, and attitudes.

These characteristics can be assessed through self-reported information, medical records, laboratory tests, and other types of data collection methods. However, some characteristics may be more difficult to measure accurately than others, and measurement error can affect the validity and reliability of study findings.

While it is challenging to measure unobservable characteristics in an epidemiologic study, researchers can use various methods, such as proxy measures, questionnaires, or interviews, to indirectly assess these characteristics. Thus, it is not impossible to measure them in an epidemiologic study.

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Answer: x= 2, -2.5

Step-by-step explanation: trust lol

To construct a proof demonstrating the validity of the argument ∃xF x → ∀xF x, F g ∴ Mg, we need to use the rules of propositional logic and quantifier rules.

1. Assume ∃xF x (Assumption)
2. Choose an arbitrary element g and assume F g (Assumption)
3. From ∃xF x, we can conclude that there exists an element x such that F x (Existential Elimination)
4. Since we assumed F g in step 2, we can use Universal Instantiation to conclude that ∀xF x (g is an arbitrary element)
5. From the premise ∃xF x → ∀xF x, we can use Implication Elimination to conclude ∀xF x
6. Using Universal Elimination, we can conclude F g from ∀xF x
7. From F g and the premise F g ∴ Mg, we can use Modus Ponens to conclude Mg
8. Since we assumed ∃xF x in step 1 and derived Mg in step 7, we can use Existential Introduction to conclude ∃xMx

Therefore, we have constructed a proof demonstrating the validity of the argument ∃xF x → ∀xF x, F g ∴ Mg, which can be summarized as follows:

1. ∃xF x (Assumption)
2. F g (Assumption)
3. ∃xF x → ∀xF x (Premise)
4. ∃x F x (Existential Elimination)
5. ∀xF x (Implication Elimination)
6. F g (Universal Elimination)
7. F g ∴ Mg (Premise)
8. Mg (Modus Ponens)
9. ∃xMx (Existential Introduction)

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A, C, D, and E are the correct statements among the given statement.

The correct statements are:
A. If the first-principal minor of the Hessian matrix, | H1|>0, the second-principal minor of the Hessian matrix, |H2|>0, ..., and the nth principal minor of the Hessian matrix, |Hn| > 0, that is, if all principal minors of the Hessian matrix are greater than zero, at the critical point the function is at a relative maximum.
C. The Hessian matrix is a special matrix with all second-order partial derivatives of a given function as its elements.
D. In a 2x2 Hessian matrix, the principal minors of the Hessian matrix are the determinants of the matrices found by starting with the first element in the first row and then expanding by adding the next row and column.
E. If the first-principal minor of the Hessian matrix, |H1| < 0, the second-principal minor of the Hessian matrix, |H2|<0, and the nth principal minor of the Hessian matrix, |Hn| < 0, that is, if all principal minors of the Hessian matrix are negative, at the critical point the function is at a relative minimum.

Note: Statement B is incorrect as the size of the Hessian matrix depends on the number of variables involved in the function, and it can be larger than 2x2.

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The distance of the student from the foot of the tower is 25.63m the nearest 1/2 is 25.5m.

Given that From the top of a tower 14m high

The angle of depression of a student is 32°

we can use trigonometry to find the distance from the foot of the tower to the student:

tan(32°) = opposite/adjacent = 14/distance

Rearranging this equation gives:

distance = 14/tan(32°)

= 25.63m

Therefore, the distance of the student from the foot of the tower is approximately 25.63m nearest 1/2, this is 25.5m.

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The partial derivatives ∂N/∂u, ∂N/∂v, and ∂N/∂w when u=9, v=4, and w=3 are:

[tex]∂N/∂u = 96[/tex]

[tex]∂N/∂v = 19[/tex]

[tex]∂N/∂w = 35[/tex]

To find the indicated partial derivatives, we can use the chain rule of differentiation. Starting with ∂N/∂u, we have:

[tex]∂N/∂u = (∂N/∂p) \times (∂p/∂u) + (∂N/∂q) \times (∂q/∂u) + (∂N/∂r) \times (∂r/∂u)[/tex]

Substituting the given values for p, q, and r, we get:

[tex]∂N/∂u = (1 + q) \times 1 + (p + r) \times w + u \times w[/tex]

Using the values of p, q, and r in terms of u, v, and w, we get:

[tex]∂N/∂u = (1 + v + uw) + (u + vw + w + uv) \times 3 + 9 \times 3[/tex]

Simplifying the expression, we get:

[tex]∂N/∂u = 60 + 4u + 3v + 12w[/tex]

We can find ∂N/∂v and ∂N/∂w by applying the chain rule of differentiation and using the given values for u, v, and w. Substituting the values, we get:

[tex]∂N/∂v = 3u + 4 + 3w[/tex]

[tex]∂N/∂w = 3u + 3v + 2[/tex]

The chain rule allows us to find the partial derivatives of a function with respect to its variables, by breaking down the function into its component parts and differentiating each part separately.

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The correct statement is,

⇒ Not enough information to draw a valid conclusion.

Given that;

If the range for a set of data is 24, from 2 to 26,

And, the mean is 17.

Now, We know that;

To find mean we have to need that all the terms, but here only first and last terms are given.

Thus, Not enough information to draw a valid conclusion.

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The measure of <Z is B. 66^o.

A triangle is a figure bounded by three straight lines called its sides. As such, the sum of the internal angles of a triangle is 180^o.

From the given diagram, it can be seen that;

<Y = 90^o, and <X = 24^o

Thus,

<X + <Y + <Z = 180^o

24 + 90 + <Z = 180

114 + <Z = 180

<Z = 180 - 114

    = 66

<Z = 66^o

The measure of <Z is 66^o. Thus option B.

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Answer:

0.0

Step-by-step explanation:

0.019 or 0.0

Answer:25.2

Step-by-step explanation:

To find the value of x, we first need to find the missing angle value, which is 180-90-59, making it 31.

Now that we have that value, we can use SOH to find the hypotenuse.

The equation would look something like this:

[tex]\sin\left(31\right)=\frac{13}{x}[/tex]

Which we can change to get the x value like this:

[tex]\frac{13}{\sin\left(31\right)}=x[/tex]

This makes the X value equal to 25.241.

Since you need it as the nearest tenth, you can round it down to 25.2.

Rectangle A’B’C’D’ is the image of rectangle ABCD then 90 degrees rotation about the origin is true

To determine which rotation was done to transform point BBCD to A'B'C'D'

90 degrees rotation about the origin

This transformation would map point ABCD to A'B'C'D" which is the same as A'.

However, this transformation is clockwise, whereas the actual transformation was counterclockwise.

Hence, 90 degrees rotation about the origin, followed by a reflection about the y-axis is correct

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The whole number(s) are 3 and -2.  A whole number doesn't have fractions or places after the decimal.  

The natural number(s) is 3.  Think of a natural number as those used for counting, like "1, 2, 3, 4..."

The integer(s) are 3 and -2.  An integer includes positive or negative whole numbers, and 0.

The rational number(s) are 3, -2, and 1/4.  A rational number can be written as a fraction.

And irrational number, the square root of 5, cannot be written as a fraction.  It is the opposite of a rational number.  

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Using diagram whole numbers, natural numbers, integers, and rational or irrational numbers, which category does -2, 3, 1/4, and square root of 5

which is a whole number, natural number, integer, or rational or irrational number: -2, 3,  1/4, and square root of 5

Answer:

24 and 7/100 written as a decimal is 24.07.

Step-by-step explanation:

Answer: 250 square centimeters

Step-by-step explanation:

Height (h) = 10 cm

Length (l) = 5 cm

Width (w) = 5 cm

Plugging in these values into the formula, we get:

SA = 2(5)(5) + 2(5)(10) + 2(5)(10)

SA = 50 + 100 + 100

SA = 250

So, the surface area of the rectangular prism is 250 square centimeters (cm^2).

If the money supply doubles and the velocity of money is stable, the long-run impact on real GDP will depend on other factors that influence the economy's overall growth. In the short term, a sudden increase in the money supply may boost economic activity and output as businesses have more access to credit and consumers have more disposable income to spend.

However, in the long run, the economy's potential output is determined by its ability to produce goods and services efficiently, which is reflected in the level of real GDP.
If the money supply continues to grow faster than the economy's capacity to produce, it can lead to inflation, which can erode the purchasing power of money and reduce economic growth. Therefore, in the long run, the impact of a doubling of the money supply on real GDP will depend on whether it leads to sustainable economic growth or inflationary pressures.

Moreover, the relationship between money supply, velocity, and real GDP is complex and influenced by various factors, such as fiscal policy, monetary policy, technological progress, and demographic changes. Therefore, while a doubling of the money supply may lead to short-term growth, its long-term impact on real GDP depends on the broader economic context in which it occurs.
If the money supply doubles and the velocity of money remains stable, in the long run, the real GDP may not be significantly affected. Here's a step-by-step explanation of this scenario:

1. When the money supply doubles, there will be more money circulating in the economy. This increase may initially lead to higher demand for goods and services, causing prices to rise.

2. The velocity of money, which is the rate at which money is exchanged from one transaction to another, remains stable. This means that the overall pace of economic transactions doesn't change.

3. In the short run, the increased money supply may lead to a temporary boost in economic activity and possibly higher nominal GDP. However, this increase is primarily due to the inflation caused by the rise in prices, not necessarily an increase in the production of goods and services.

4. In the long run, the economy will adjust to the higher money supply, and the real GDP will return to its original level. This is because the long-run growth of the real GDP is determined by factors such as productivity, technological advancements, and the availability of resources, rather than changes in the money supply.

5. Eventually, the economy will reach a new equilibrium with higher prices, but the real GDP will remain unchanged in the long run. The increase in the money supply will only lead to higher inflation, not a sustainable increase in real economic output.

In summary, doubling the money supply while keeping the velocity of money stable may temporarily boost nominal GDP, but it won't result in a long-term increase in real GDP, as other factors determine its growth.

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Answer:

To prove that n^3 + 3n + 4 is Θ(2^n), we need to show that it is both O(2^n) and Ω(2^n).

First, let's show that it is O(2^n). To do this, we need to find constants c and n0 such that n^3 + 3n + 4 <= c * 2^n for all n >= n0.

We can start by simplifying the left-hand side: n^3 + 3n + 4 <= n^3 + n^3 + n^3 (since 3n <= n^3 and 4 <= n^3 for all n >= 1).

So we have: n^3 + 3n + 4 <= 3n^3

Now, for n >= 1, we know that 2^n <= 3^n, so we can write: 3n^3 >= 2^n

Therefore, we have: n^3 + 3n + 4 <= 3n^3 <= c * 2^n for c = 3 and n0 = 1.

So, n^3 + 3n + 4 is O(2^n).

Next, let's show that it is Ω(2^n). To do this, we need to find constants c and n0 such that n^3 + 3n + 4 >= c * 2^n for all n >= n0.

One way to approach this is to try to find a lower bound for n^3 + 3n + 4 by removing some terms (because we want to show that the left-hand side is at least as big as some constant times 2^n, and the more terms we have on the left-hand side, the harder that is to do).

If we remove the 3n and the 4, we have n^3 <= n^3.

If we remove only the 4, we have n^3 + 3n >= n^3.

Either way, we have: n^3 + 3n >= n^3 >= c * 2^n for c = 1 and n0 = 1.

Therefore, n^3 + 3n + 4 is Ω(2^n).

Since we have shown that n^3 + 3n + 4 is both O(2^n) and Ω(2^n), we can conclude

Step-by-step explanation:

We have shown that n^3 + 3n + 4 is in the order of e(2n^3), as required.

To prove that n^3 + 3n + 4 is in the order of e(2n^3), we need to show that there exist positive constants c and n0 such that:

n^3 + 3n + 4 <= c * e(2n^3) for all n >= n0

Taking natural logarithm on both sides of the inequality, we get:

ln(n^3 + 3n + 4) <= ln(c) + 2n^3

Now, we need to show that there exist positive constants c and n0 such that the inequality holds.

Taking the derivative of the left-hand side of the inequality, we get:

d/dn (ln(n^3 + 3n + 4)) = (3n^2 + 3) / (n^3 + 3n + 4)

For n >= 1, we have:

3n^2 + 3 <= 3n^3 + 3n^2 <= 6n^3

n^3 + 3n + 4 >= n^3

Therefore,

d/dn (ln(n^3 + 3n + 4)) <= (6n^3) / n^3 = 6

This means that the function ln(n^3 + 3n + 4) is bounded above by a constant of 6. Thus, we can set c = e^6 and n0 = 1.

For all n >= 1, we have:

ln(n^3 + 3n + 4) <= 6 + 2n^3

n^3 + 3n + 4 <= e^(6 + 2n^3) = e^6 * e^(2n^3)

Therefore, we have shown that n^3 + 3n + 4 is in the order of e(2n^3), as required.

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The total number of ways to select the jerseys is [tex]$38220+499200=537420$[/tex].

(i) If he would like to hang up more or equal number of football jerseys than basketball jerseys, there are two cases:

Case 1: He hangs up 6 football jerseys and 0 basketball jerseys.

He can select 6 football jerseys from 15 in [tex]$\binom{15}{6}=5005$[/tex]ways.

Case 2: He hangs up 5 football jerseys and 1 basketball jersey.

He can select 5 football jerseys from 15 in [tex]$\binom{15}{5}=3003$[/tex] ways.

He can select 1 basketball jersey from 10 in [tex]$\binom{10}{1}=10$[/tex] ways.

Therefore, the total number of ways to select the jerseys is [tex]$5005+3003\times10=32035$[/tex].

(ii) If he would like to hang up an equal number of football and basketball jerseys, but he can't hang up Surya's basketball jersey without also hanging up Ashu's football jersey, there are two cases:

Case 1: He hangs up 3 football jerseys and 3 basketball jerseys, without Surya's jersey.

He can select 3 football jerseys from 15 in [tex]$\binom{15}{3}=455$[/tex] ways.

He can select 3 basketball jerseys (excluding Surya's) from 9 in [tex]$\binom{9}{3}=84$[/tex] ways.

Therefore, the total number of ways to select the jerseys is [tex]$455\times84=38220$[/tex].

Case 2: He hangs up 4 football jerseys and 2 basketball jerseys, with Surya's jersey.

He can select Surya's basketball jersey and Ashu's football jersey, then select 3 football jerseys from the remaining 13 and 1 basketball jersey from the remaining 8.

He can select 2 basketball jerseys (excluding Surya's) from 8 in [tex]$\binom{8}{2}=28$[/tex] ways.

Therefore, the total number of ways to select the jerseys is [tex]$2\times\binom{13}{3}\times\binom{8}{2}=499200$[/tex].

Thus, the total number of ways to select the jerseys is [tex]$38220+499200=537420$[/tex].

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Answer:

Step-by-step explanation:

Option D is the correct option.

What is Mean Absolute Deviation?

'The mean absolute deviation (MAD) is the mean (average) distance between each data value and the mean of the data set.'

According to the given problem,

The mean height Variety A = 19 [ from the table ]

The mean height of variety B = 13 [ from the table ]

The spread is given by the mean absolute deviation, which 1.2 for Variety A and 2.4 for Variety B. So we can see that, the spread in Variety A is lesser than the spread in Variety B, which shows that the average height of Variety A varies less than the average height of Variety B.

We can see from the table that the average height of a variety A is indeed greater than that of Variety B. Also we can see that the Mean Absolute deviation of Variety A is 1.2 which is lesser than the Mean Absolute deviation of Variety B.

Hence, option D is correct since the average height of Variety A is greater than Variety B, and also the mean varies lesser in Variety A than in Variety B.

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Answer:

D

Step-by-step explanation:

hope this helps

You read in a book about bridge that the probability that each of the four players is dealt exactly one ace is about 0.11. This means that (c) in a very large number of bridge deals, the percent of deals on which each player has one ace will be very close to 11%.

The correct answer is (c) in a very large number of bridge deals, the percent of deals on which each player has one ace will be very close to 11%. This is because the given probability is an estimate based on a large number of bridge deals, and the law of large numbers states that as the number of trials (bridge deals) increases, the observed percentage will approach the true probability. Option (a) is incorrect because the given probability is not a guarantee for every 100 bridge deals. Option (b) is incorrect because the number of deals with each player having one ace will vary and may not be exactly 110,000. Option (d) is incorrect because the given probability only refers to the likelihood of each player having one ace, not the average number of aces in a hand.

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The coordinates of the vertices after the reflection across x = 1 are:

⇒ X'(2,-3),  W(1,0),  V'(2,1)

Now First, let's visualize the reflection across x = 1.

This means that all points will have the same x-coordinate but their y-coordinate will be mirrored across the line x = 1.

So, X(0,-3) will reflect to X'(2,-3),

Since, the distance between X and the line x = 1 is 1 unit,

and the y-coordinate of X' will be the same as that of X.

Similarly, W(1,0) will remain unchanged, as it lies on the line of reflection.

And, Lastly, V(4,1) will reflect to V'(2,1),

Since, the distance between V and the line x = 1 is 3 units, and the y-coordinate of V' will be the same as that of V.

Therefore, the coordinates of the vertices after the reflection across x = 1 are:

⇒ X'(2,-3),  W(1,0),  V'(2,1)

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