A cyclist speeds up from 3 m/s to 7 m/s in 8 seconds.
a. What is its change in velocity

Answer:

The kinetic energy before the collision was 8 J

Explanation:

The given parameters are;

The mass of the metal ball at rest, m₁ = 3.0 kg

The velocity of the ball at rest = 0 m/s

The mass of the metal ball that hits the one at rest, m₂ = 1.0 kg

The velocity of the metal ball that hits the one at rest, v₂ = 4.0 m/s

The velocity with which the 3.0 kg ball moves forward = 2.0 m/s

The velocity with which the 1.0 kg ball bounces back = 2.0 m/s

a) Kinetic energy, K.E. = 1/2 × m × v²

Where;

m = The mass of the of the object in motion

v = The velocity of the object

Before the collision, we have;

Initial K.E. = 1/2 × m₁ × v₁² + 1/2 × m₂ × v₂²

∴ Initial K.E. = 1/2 × 3.0 kg × (0 m/s)² + 1/2 × 1.0 kg × (4.0 m/s) ² = 8 J

The kinetic energy before the collision = The initial K.E. = 8 J.

Answer: motion parallax

Explanation:

Motion parallax refers to a form of depth perception whereby objects that are closer to an individual appears to move at a faster speed than the objects that are far.

Therefore, Kate is riding on a train and notices that the wildflowers by the side of the tracks seem to be moving by much faster than the mountains in the distance is an example of motion parallax.

Answer:

(a) the height of the diving board is 22.896 m

(b) the horizontal distance traveled by the girl is 7.02 m

(c) if she had just drop off the board, her time to drop to the water would have been longer.

Explanation:

Given;

initial speed of the girl, u = 3.9 m/s

time to hit the water, t = 1.8 s

(a) the height of the diving board is calculated as;

h = ut + ¹/₂gt²

h = (3.9 x 1.8)  +  ¹/₂ x 9.8 x 1.8²

h = 7.02 + 15.876

h =  22.896 m

(b) the horizontal distance traveled by the girl is calculated as;

X = ut

X = 3.9 x 1.8

X = 7.02 m

(c) if she just drop off the board, then the initial speed will be zero;

h = ut + ¹/₂gt²

h = 0 + ¹/₂gt²

2h = gt²

[tex]t^2 = \frac{2h}{g} \\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2 \ \times\ 22.896 }{9.8} }\\\\t = 2.16 \ s[/tex]

Thus, if she had just dropped off the board, her time to drop to the water would have been longer.

Answer:

Atmospheric Pressure

Explanation:

Answer:

Group IA elements have only one valency electron while Group IIA have two valency electrons.

Group IA elements have cations with higher charge density hence polarizing anions easier resulting into covalent character while Group IIA elements have cations with lower charge density hence difficulty in distorting anions resulting into a ionic character. This is due to difference in cationic radii and charges

Answer:

a = 36.45[m/s²]

Explanation:

We can calculate the acceleration value by means of the following expression of kinematics.

[tex]v_{f}^{2} =v_{o}^{2} +2*a*x[/tex]

where:

vf = final velocity = 270 [m/s]

Vo = initial velocity = 0 (begins from rest)

a = acceleration [m/s]²

x = distance required by the plane = 1000 [m]

[tex](270)^{2} =0+2*a*1000\\72900=2000*a\\a=36.45 [m/s^{2} ][/tex]

Answer:

5) The approximate height is about 80 m. Choice (c)

6) The stone takes about 3 seconds to rise to its maximum height

Explanation:

Free Fall Motion

A free-falling object falls under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the gravitational acceleration, which value is [tex]g = 9.8 m/s^2[/tex].

The distance traveled by a dropped object is:

[tex]\displaystyle y=\frac{gt^2}{2}[/tex]

Question 5

Given the stone reaches the ground in t=4 seconds, the height of the tower is:

[tex]\displaystyle y=\frac{9.8*4^2}{2}=78.4\ m[/tex]

The approximate height is about 80 m. Choice (c)

Question 6

Vertical Motion

The vertical motion of an object is controlled by the force of gravity. This means that there is a non-zero net force acting on the object that makes it accelerate downwards.

If the object is thrown upwards at speed vo, its speed at time t is:

[tex]v_f=v_o-g.t[/tex]

The stone reaches its maximum height when the final speed is zero, thus:

[tex]v_o-g.t=0[/tex]

Solving for t:

[tex]\displaystyle t=\frac{v_o}{g}[/tex]

The stone is thrown vertically upwards with vo=30 m/s, thus:

[tex]\displaystyle t=\frac{30}{9.8}[/tex]

[tex]t=3.06\ s[/tex]

[tex]t\approx 3\ s[/tex]

The stone takes about 3 seconds to rise to its maximum height

Answer:

58.8m

Explanation:

Answer:

Q = 78375 [J]

Explanation:

To solve this problem we must use the following ideal equation for the thermal energy of an element or substance depending on the temperature change.

[tex]Q=m*C_{p}*(T_{final}-T_{initial})[/tex]

where:

Q = heat [J]

m = mass = 0.25 [kg]

Cp = specific heat = 4180 [J/kg*C]

Tinitial = 25[°C]

Tfinal = 100 [°C]

[tex]Q =0.25*4180*(100-25)\\Q = 78375 [J][/tex]

Answer:

Hey mate here's your answer ⤵️

Vernier caliper least counts formula is calculated by dividing the smallest reading of the main scale with the total number of divisions of the vernier scale.LC of vernier caliper is the difference between one smallest reading of the main scale and one smallest reading of vernier scale which is 0.1 mm 0r 0.01 cm

True is the correct answer

Answer:

3 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 2 L

Initial pressure (P₁) = 0.75 atm

Final pressure (P₂) = 0.5 atm

Final volume (V₂) =?

Using the Boyle's law equation, the new volume (i.e final volume) of the Ne gas can be obtained as:

Initial volume (V₁) = 2 L

Initial pressure (P₁) = 0.75 atm

Final pressure (P₂) = 0.5 atm

Final volume (V₂) =?

P₁V₁ = P₂V₂

0.75 × 2 = 0.5 × V₂

1.5 = 0.5 × V₂

Divide both side by 0.5

V₂ = 1.5 / 0.5

V₂ = 3 L

Thus, the new volume of the Ne gas is 3 L

Answer:

displacement: 0

Distance: 30

Explanation:

lol, i asked my brother, he's also in 10th grade

Answer:

Toward the normal line

Explanation:

I had the same question on a quiz

Answer:

The joule is the standard unit of energy in electronics and general scientific applications. One joule is defined as the amount of energy exerted when a force of one newton is applied over a displacement of one meter. One joule is the equivalent of one watt of power radiated or dissipated for one second.

Hope it helps ^^

Answer:

The answer to this question is given below in the explanation section.

Explanation:

how the aperture geometry relates to the

diffraction pattern:

Diffraction is the spreading out of waves as they pass through an aperture or around objects.it occurs when the size of the aperture or obstacle is of the same order of magnitude as the wavelength of  the incident wave.For every small aperture sizes,the vast majority of the wave is blocked.For large apertures the wave passes by or through the obstacle without any significant of diffraction.

            in an aperture with width smaller than the wavelength,the wave transmitted through the aperture spreads all the way around the behave like a point sources of waves.

                             single slit diffraction pattern

The diffraction pattern made by waves passing through a slit of width [tex]\alpha[/tex] (larger than∫) can be understood by imagining a series of point sources all in phase along the width of the slit.The waves moving directly forward are all in phase,so they from a large central maximum.

                 if the waves travels at an angle Ф from the normal to the slit,then there is a path difference x between the waves production at the two end of the slit.

           x=a sinΦ

The path difference between the top and middle waves is λ/2 then they are exactly out of phase and cancel each other out. This happens to all consecutive pairs of waves (the ones produced by the second source from the top and the second source past the middle etc.)at the angle so there is no resultant wave at this angle.Thus a minimum is the diffraction pattern is obtained at

                                                   λ=α sinθ

Now slit can be divided into four equal sections and the pairing of sources to give destructive interference can be repeated for the top two section ,which is identical to the result of pairing off matching sources in the bottom two sections.in this case we obtained from the minimum.

             λ/2=α/4 sinθ

we can divided the slit aperture into six equal sections and pair off sources in the top two divisions and then the bottom two,to give destructive interference for every matched pair.The minimum of intensity are obtained at angles

                      nλ = α sinθ

where n is an integer (1,2,......),  but not n=0.There is a maximum of intensity in the center of the pattern. This process only gives the position of the minima,does not work for positions of the maxima,and so does not give the intensities of the maxima.

Answer:

The work done by picking up 100 20-L bottles and raising it vertically 1 meter is 19614 joules.

Explanation:

By the Work-Energy Theorem, the work needed to raise vertically 100 bottles of water is equal to the gravitational potential energy, units for work and energy are in joules:

[tex]\Delta W = \Delta U_{g}[/tex] (1)

Where:

[tex]\Delta W[/tex] - Work.

[tex]\Delta U_{g}[/tex] - Gravitational potential energy.

The work is equal to the following formula:

[tex]\Delta W = n\cdot \rho \cdot V \cdot g \cdot \Delta h[/tex] (2)

Where:

[tex]n[/tex] - Number of bottles, dimensionless.

[tex]\rho[/tex] - Density of water, measured in kilograms per cubic meter.

[tex]V[/tex] - Volume, measured in cubic meters.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]\Delta h[/tex] - Vertical displacement, measured in meters.

If we know that [tex]n = 100[/tex], [tex]\rho = 1000\,\frac{kg}{m^{3}}[/tex], [tex]V = 0.02\,m^{3}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\Delta h = 1\,m[/tex], then the work done is:

[tex]\Delta W = (100)\cdot \left(1000\,\frac{kg}{m^{3}} \right)\cdot (0.02\,m^{3})\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (1\,m)[/tex]

[tex]\Delta W = 19614\,J[/tex]

The work done by picking up 100 20-L bottles and raising it vertically 1 meter is 19614 joules.

Answer:

I think the the answer is creating and layout and template style     ( C )

Explanation:

I did it before and i was checking my notes and i wrote that down , Hope this Helps :)

Answer:

1) Periodically check the no stop or NDL time on their computers

2) The dive computer planning mode can be used if available

3) Make use of a dive planning app

4) Check data from the RDP table or an eRDPML

Explanation:

The no stop times information from the computer gives the no-decompression limit (NDL) time allowable which is the time duration a diver theoretically is able to stay at a given depth without a need for a decompression stop

The dive computer plan mode or a downloadable dive planning app are presently the easiest methods of dive planning

The PADI RDP are dive planners based on several years of experience which provide reliable safety limits of depth and time.

Answer:

In reality, the filament gets so hot it in a real sense bubbles off molecules and electrons. Now and again this material gathers as a dull spot at the highest point of the bulb. Eventually, the filament falls apart, gets frail, and breaks, subsequently finishing the life of the light. Lights radiate light by siphoning an electric flow through a dainty tungsten fiber. The filament warms and emits light. Over the long haul, the filament oxidizes and turns out to be increasingly fragile, until it splits up and the bulb goes out. ... Tungsten picks up obstruction as it warms.

Hope this helped :)

1. ) It's good to remember contact information such as phone number or email.

2.) Your address, so if they need to mail anything to you, they can. This is also a necessary point of information on most job applications anyway.

3.) Past job experiences and ways to contact them. This is probably one of the most important things as it shows you've worked before and are willing to talk to past employers.

May I have brainliest please? :)

Answer:

the other answer is correct

Explanation:

i do flvs and this was on the career final exam

Answer:

The rank of the frequencies from largest to smallest is

The largest frequency of oscillation is given by the string in option D

The second largest frequency of oscillation is given by the string in option B

The third largest frequency of oscillation is given by the string in option A

The smallest frequency of oscillation is given by the string in option C

Explanation:

The given parameters are;

The mass per unit length of all string, m/L = Constant

The tension of all the string, T = Constant

The frequency of oscillation, f, of a string is given as follows;

[tex]f = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L}[/tex]

Where;

T = The tension in the string

m = The mass of the string

L = The length of the string

n = The number of overtones

[tex]Therefore, \ {\sqrt{\dfrac{T}{m/L} } } = Constant \ for \ all \ strings = K[/tex]

For the string in option A, the length, L = 27 cm, n = 3 we have;

[tex]f_A = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(3 + 1) \times K }{2 \times 27} = \dfrac{2 \times K}{27} \approx 0.07407 \cdot K[/tex]

For the string in option B, the length, L = 30 cm, n = 4 we have;

[tex]f_B = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(4 + 1) \times K }{2 \times 30} = \dfrac{ K}{12} \approx 0.08 \overline 3\cdot K[/tex]

For the string in option C, the length, L = 30 cm, n = 3 we have;

[tex]f_C = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(3 + 1) \times K }{2 \times 30} = \dfrac{K}{15} \approx 0.0 \overline 6 \cdot K[/tex]

For the string in option D, the length, L = 24 cm, n = 4 we have;

[tex]f_D = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(4 + 1) \times K }{2 \times 24} = \dfrac{5 \times K}{48} \approx 0.1041 \overline 6 \cdot K[/tex]

Therefore, we have the rank of the frequency of oscillations of th strings from largest to smallest given as follows;

1 ) [tex]f_D[/tex] 2) [tex]f_B[/tex] 3) [tex]f_A[/tex] 4) [tex]f_C[/tex]

The order of the frequencies is  [tex]f_D>f_B>f_A>f_C[/tex]

The frequency of the standing wave in a string tied at both ends is given by:

[tex]f=\frac{nv}{2L}[/tex]

where n is the mode of frequency

v is the velocity of the wave

and L is the length of the string.

Now the velocity of a wave in a string tied at both ends is given by

[tex]v=\sqrt{\frac{T}{\mu}}[/tex]

where T is the tension and μ is the mass per unit length.

Since T and μ are the same for all the strings, velocity [tex]v[/tex] will be the same for all.

Now to find the mode of frequency we can calculate the number of nodes (including the nodes at the ends) in the given figure and subtract by 1. Nodes are the point where the amplitude of the wave is zero.

[tex]f_A=\frac{3v}{2\times27}=\frac{v}{18}\;s^{-1}\\\\f_B=\frac{4v}{2\times30}=\frac{v}{15}\;s^{-1}\\\\f_C=\frac{3v}{2\times30}=\frac{v}{20}\;s^{-1}\\\\f_D=\frac{4v}{2\times24}= \frac{v}{12}\;s^{-1}[/tex]

Hence, [tex]f_D>f_B>f_A>f_C[/tex]

Learn more about standing waves:

https://brainly.com/question/1698005?referrer=searchResults

Answer:

Apparent Motion

Explanation:

Apparent Motion of a star is a scientific term that describes the phenomenon that is observed as a result of the earth's rotation which is based on the area or where the observer is situated, and then the point at which the star is found comparable to the rotation axis of the earth.

This often makes the start to appear like it's moving across the sky.

Hence, A star has APPARENT MOTION; it appears to be moving across the sky as the night progresses.

Explanation:

The third class lever cannot magnify our force because in third class lever the effort it between the load and the fulcrum. Also, in this type of lever no matter where the force is applied, it is always greater than the force of load. Hence, That type of lever cannot magnify our force.

Answer:

Explain. yes it is possible because when the net force is zero and acceleration is zero. ... no, Neglecting air friction, the only force acting on this object is the force of gravity downward. There is no force of equal magnitude as the force of gravity acting in the opposite direction.

Answer:

follow me for the answer