Physics College

A gasoline engine has a power output of 210 kW (about 282 hp ). Its thermal efficiency is 28.5%.
a) How much heat must be supplied to the engine per second? Express your answer in joules.
b) How much heat is discarded by the engine per second? Express your answer in joules.

Answers

Answer 1

The heat supplied the engine per second is 736 kJ and the heat discarded by the engine per second is 526 kJ.

A gasoline engine has a power output of 210kW and the effciency of engine is 28.5%. The Work done of the engine in time 1s is,

Work done = power × time

                   = 210 × 1

                  = 210 kJ

The work done of the engine is,W = 210 kW.

The efficiency of the engine,η = Work / (Qh)

Qh is the heat suppllied to the engine, η is the efficiency and is equal to 28.5 %

Qh = 210kW / (0.285)

    = 736.8 kW

The heat discarded by the engine,

(Qc) = Qh - W'

       =  736.8 - 210

       =526.8 kW

The heat discarded by the engine, (Qc) = 526.8 kW

The heat supplied to the engine, (Qh) = 736.8 kW.

To learn more about the work done by the engine:

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Related Questions

A 1500, kg space probe is orbiting the Earth at a distance of 25 000. km from
the Earth's centre. The probe is hit head-on by a 2000. kg meteor moving at
1000, kph in the opposite direction. (see class example 2 for diagram). After the
completely inelastic collision, the meteorite and crumpled probe will fall
together into a lower orbit. Find the (average) radius of this new stable orbit.
(13 500 km-1.35x107 m)

Answers

The radius of the new stable orbit is around 13,500 kilometers.

How to calculate raduis of orbit?

First, find the velocity of the meteor relative to the Earth, which is:

V = 1000 km/h = 1000/3600 km/s = 0.2778 km/s

Since the probe is in orbit, it has a velocity of:

Vp = √(GMe/Re)

Where G = gravitational constant,

Me = mass of the Earth, and

Re = distance from the center of the Earth to the probe's original orbit.

Plugging in the values:

Vp = √((6.6743 × 10⁻¹¹ m³/(kg s²)) x (5.972 × 10²⁴ kg) / (25000 km + 6371 km)) = 7.785 km/s

The total momentum of the system is conserved, so:

(meteor × V) + (probe × Vp) = (meteor + probe) × Vf

Where Vf = velocity of the combined mass after the collision.

Solving for Vf:

Vf = [(meteor × V) + (probe × Vp)] / (meteor + probe) = (2000 kg x 0.2778 km/s + 1500 kg x 7.785 km/s) / (2000 kg + 1500 kg) = 6.083 km/s

Now find the radius of the new orbit using:

Vf = √(GMe/Rnew)

Solving for Rnew:

Rnew = (GMe)/(Vf²) = (6.6743 × 10⁻¹¹ m³/(kg s₂)) x (5.972 × 10²⁴ kg) / (6.083 km/s)² = 1.35 × 10⁷ m = 13,500 km

Therefore, the new stable orbit has a radius of approximately 13,500 km.

Find out more on inelastic collision here: https://brainly.com/question/29220028

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What is the magnetic field at the position of the dot in (Figure 1)? Give your answer as the components of a vector.

Answers

Answer:

200000000000 x 10^-7

Explanation:

The Biot Savart Law defines fundamental quantitative relationship between an electric current and the magnetic field it produces, based on the experiments in 1820 of the French scientists Jean-Baptiste Biot and Félix Savart.

The Biot-Savart law is applied in a specific case by adding up the contributions to the magnetic field at a given point from the whole series of short current segments that constitute a specific conductor of whatever shape

name the five major kingdoms in the classification of living organism ​

Answers

Explanation:

Kingdom moneraKingdom protistaKingdom planteaKingdom animaleaKingdom Fungi
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