Answer:
Answer: B. 84 m/s
Explanation:
Uniform Speed Motion
It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time thus, the acceleration is constant.
Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the final speed is calculated as follows:
[tex]v_f=v_o+at[/tex]
The golf ball starts with an initial speed of 100 m/s and slows down at a=-8\ m/s^2. We are required to find the final speed at t=2 s:
[tex]v_f=100-8*2=100-16[/tex]
[tex]v_f=84\ m/s[/tex]
Answer: B. 84 m/s
Dominic has a brain injury. Why is this MOST likely to be a serious injury?
If Dominic has a brain injury, then he must have sustained a serious injury.
Functions of the brainThe brain coordinates all the activities in the body such as speech, locomotion, coordination and intelligence. This makes the brain the master point of control in the body.
Brain injuryWhenever there is an injury to the brain, various parts of the body could be affected. Functions such as speech, locomotion and general coordination may become largely impaired.
Therefore, if Dominic has a brain injury, then he must have sustained a serious injury.
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A graph titled Position versus time for with horizontal axis time (seconds) and vertical axis position (meters). A straight blue line runs with an upward slope from 0 seconds 3 meters to 4 seconds 15 meters.
The starting position of this object is
[___] m.
The object is traveling at a velocity of
[___] m/s.
Answer:
The starting position of this object is
3m.
The object is traveling at a velocity of
3m/s.
Answer:
it never moved (c or 3)
Explanation:
np
. A ventilation fan has blades 0.25 m long rotating at 20 rpm (revolutions per minute). What is the centripetal acceleration of a point on the outer tip of a blade
Answer:
The centripetal acceleration of a point on the outer tip of a blade is 1.097 m/s²
Explanation:
Given;
length of the fan blade, r = 0.25 m
angular speed = 20 rpm
The angular speed in rad/s is given as;
[tex]\omega = \frac{20 \ rev}{ \ \ \min} \ \times \ \frac{2\pi}{1 \ rev} \ \times \ \frac{1 \ \min}{60s} = 2.095 \ rad/s \\\\[/tex]
The centripetal acceleration of a point on the outer tip of a blade is given as;
[tex]\alpha_c = \frac{v^2}{r} = \omega ^2r[/tex]
[tex]\alpha _c = (2.095)^2(0.25)\\\\\alpha _c =1.097 \ m/s^2[/tex]
Therefore, the centripetal acceleration of a point on the outer tip of a blade is 1.097 m/s²
Answer:
The centripetal acceleration = [tex]1.1m/s^2[/tex]Explanation:
Given
[tex]rpm = 20[/tex]
therefore,
[tex]20rpm = \frac{20*2\pi}{60}\\\\=2.1 rad/s = w[/tex]
From,
[tex]V = rw\\\\V = 0.25 * 2.1\\\\V = 0.525m/s[/tex]
Centripetal acceleration,
[tex]a_c = \frac{V^2}{r}\\\\a_c = \frac{0.525^2}{0.25}\\\\a_c = 1.1m/s^2[/tex]
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?
What is the definition of Phyical changes
Answer:
A physical change is the change to the physical properties of an object.
Explanation:
As an example if I take a piece of paper and cut it in half that would be a physical change. Water freezing into ice is also a physical change.
the amplitude of an oscillator decreases to 36.8% of its initial value in 10.0 s. what is the value of the time constant
Answer:
τ = 5 s
Explanation:
When a vibrating body is damped. Its amplitude starts to decrease. This decrement is exponential. And it is given as follows:
[tex]X = X_{0}e^{-\frac{t}{2\tau}[/tex]
where,
τ = Time Constant = ?
X = Instantaneous value of amplitude
X₀ = Initial Value of amplitude
t = time interval = 10 s
The ratio of decrement is given as:
[tex]\frac{X}{X_0} = 36.8\% = 0.368[/tex]
therefore, using these values, we get:
[tex]\frac{X}{X_{0}} = 0.368 = e^{\frac{10\ s}{2\tau}}[/tex]
Taking natural log (ln) on both sides, we get:
[tex]ln(0.368) = \frac{10\ s}{2\tau}\\\\\tau = \frac{10\ s}{2ln(0.368)}[/tex]
τ = 5 s
The value of the time constant for the decrease in the amplitude of this oscillator is 5.
Given the following data:
Decrease in amplitude = 36.8% = 0.368Time = 10.0 seconds.To determine the value of the time constant:
Mathematically, the amplitude for damped harmonic motion is given by the formula:
[tex]X = X_o e^\frac{t}{2 \tau}[/tex]
Where:
t is the time.[tex]\tau[/tex] is the time constant.X is the instantaneous value of amplitude.[tex]X_o[/tex] is the initial value of amplitude.Rearranging the formula, we have:
[tex]\frac{X}{X_o} = e^{-\frac{t}{2 \tau}}[/tex]
Substituting the given parameters into the formula, we have;
[tex]0.368 = e^\frac{-10}{2 \tau}\\\\ln(0.368) = \frac{-10}{2 \tau}\\\\-0.9997 = \frac{-10}{2 \tau}\\\\2 \tau \times -0.9997 = 10\\\\-1.9994\tau=-10\\\\\tau =\frac{-10}{-1.9994} \\\\\tau = 5.0[/tex]
Time constant = 5
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A small object of mass M is shot horizontally from a spring launcher that is attached to a table. All frictional forces are considered to be negligible. The ball
strikes the ground a distance D from the base of the table, as shown in the figure. A second object of mass is launched from the same launcher such that
the spring is compressed the same distance as in the original scenario. The distance from the base of the table that the object lands is
А
greater than but less than D
B
D
greater than D but less than 2D
greater than or equal to 2D.
Answer:
C. greater than D, but less than 2D
Explanation:
The amount of potential energy in the system is a function of the compression of the spring. That is the same for both masses.
The potential energy is transferred to kinetic energy when the spring is released. The kinetic energy is jointly proportional to the mass and the square of the velocity. That is, the velocity is inversely proportional to the square root of the mass, for the same kinetic energy.
The horizontal distance traveled will be proportional to the launch velocity. So a halving of the mass will increase the velocity by a factor of ...
v2 = v1·√(1/(1/2)) = v1·√2
This means the second mass will land at a distance of about D√2, a value ...
greater than D but less than 2D.