Answer:
f. 500N
Explanation:
The force exerted by the wagon on the horse is 500N directed in the opposite path .
This is premised on the Newton's third law of motion which states that "action and reaction forces are equal and opposite in direction".
So, as the action force of 500N is used by the horse to drag the wagon, the wagon also exerts an oppositely directed force of 500N on the horse.
This way, the acceleration can continue.
11. A bowling ball has a mass of 7 kg and a velocity of 3 m/s.
(A) What is the ball's momentum?
Answer: 21 kg x m/s
Momentum can be found using the equation p = mv, or momentum = mass times velocity.
Therefore, to find the momentum of the bowling bowl, you can plug the mass and velocity values into the equation to get p = (7kg)(3m/s)
Solve the equation to get a momentum of 21kg x m/s
I hope I could help :)
Mercury is a liquid metal having a density of 13.6 g/mL. What is the
volume of 0.45 kg of mercury metal?
Answer:
[tex]\boxed {\boxed {\sf v \approx 33.088 \ mL}}[/tex]
Explanation:
The formula for density is:
[tex]d= \frac{m}{v}[/tex]
where m is the mass and v is the volume.
The mass is 0.45 kilograms and the density is 13.6 grams per milliliter. The density is given in grams, so we must convert the mass.
There are 1000 grams in 1 kilogram or [tex]\frac{1000 \ g} {1 \ kg}[/tex]. We can multiply the mass by this ratio.
[tex]0.45 \ kg * \frac{1000 \ g} {1 \ kg} = 0.45 * 1000 \ g = 450 \ g[/tex]
Now we have values for the mass and density:
[tex]13.6 \ g/mL =\frac{450 \ g}{ v}[/tex]
Cross multiply.
[tex]\frac {13.6 \ g/mL}{1} =\frac{450 \ g}{ v}[/tex]
[tex]13.6 \ g/mL * v=450 \ g * 1 \\13.6 \ g/mL * v=450 \ g[/tex]
We are trying to find the volume, so we must isolate that variable.
13.6 and v are being multiplied. The inverse of multiplication is division. Divide both sides by 13.6
[tex]\frac {13.6 \ g/mL*v } { 13.6 \ g/mL} = \frac{ 450 \ g} {13.6 \ g/mL}[/tex]
[tex]v= \frac{ 450 \ g} {13.6 \ g/mL}[/tex]
The grams will cancel.
[tex]v= 33.0882353 \ mL\\v \approx 33.088 \ mL[/tex]
The volume is about 33.088 milliliters.
What variable is the dependent variable?
A. Time
B. Temperature
Answer:
the answer is b temperature
What is the guage pressure of an object with a mass of 30 kg and 5ft height?
Answer: D=pg
Explanation:
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15 mm Hg is the guage pressure of an object with a mass of 30 kg and 5ft height.
What is gauge pressure?The measurement of pressure in relation to atmospheric pressure is known as gauge pressure. The zero point for this pressure measurement is set at 1 atm. With relation to atmospheric pressure, pressure is measured.
When a car climbs a mountain, the gauge pressure rises as the air pressure falls, but the tire's absolute pressure stays the same, assuming no tire leaks.
guage pressure = mass×height
= 30×5
=15 mm Hg
Therefore, 15 mm Hg is the guage pressure of an object with a mass of 30 kg and 5ft height.
To know more about gauge pressure, here:
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