Answer:
The delicate balance between temperature and magnetic domains is destabilized when a magnet is subjected to high temperatures. If a magnet is exposed to this temperature for an extended length of time or heated over its Curie temperature, it will lose its magnetism and become irreversibly demagnetized.
Explanation:
a small block with mass 0.04 kg is moving in the xy-plane. the net force on the block is describe by the potential energy function U(x,y) = (5.80 j/m2)x2 - (3.60 j/m3)y3. What are the magnitude of the acceleration of the block when it is at the point (x=0.30m , y=0.60m ) ?
Answer:
Explanation:
Use that:
[tex]F=-\vec{\nabla}U(x,y)=-\left(\hat{i} \frac{\partial U}{\partial x}+\hat{j}\frac{\partial U}{\partial y}\right)=-11.6x\hat{i}+10.8y^{2}\hat{j}[/tex]
Then use the 2nd Newton's Law of Motion:
[tex]\vec{a}=\frac{\vec{F}}{m}=\frac{-11.6x\hat{i}+10.8y^{2}\hat{j}}{0.04}=-290x\hat{i}+270y^{2}\hat{j}[/tex]
At x = 0.3 and y = 0.6, we can find the acceleration as:
[tex]\vec{a}=-87\hat{i}+97.2\hat{j}[/tex] (in SI unit)
Then the magnitude of the acceleration on that point is:
[tex]a=\sqrt{(-87)^{2}+(97.2)^{2}}\approx 130.44[/tex] (SI Unit)
Two people work together to move a heavy box. One person pulls the box with a force of 200 Newtons. The other person pushes the box with a force of 150 newtons. The force of friction on the box is 400 newtons. Which of the following BEST describes what will happen to the box and people?
A. The person pushing the box will move the box towards the person pulling it.
B. The box will accelerate in the direction of the frictional force.
C. Both people will accelerate in the direction of friction, but the box will remain stationary.
D. Neither the box nor people will move.
Answer:
D. Neither the box nor people will move.
Explanation:
We are given three forces that are present on the box and friction is the result of someone trying to move the box. The net force of the people pulling/pushing is barely 50 Newtons which doesn't compare with the frictional force of 400 Newtons, you will need to surpass a net force of 400 Newtons in order for the box to START moving.
Consider a parallel-plate capacitor with plates of area A and with separation d.
Part A
Find F(V), the magnitude of the force each plate experiences due to the other plate as a function of V, the potential drop across the capacitor.
Express your answer in terms of given quantities and ϵ0.
View Available Hint(s)for Part A
F(V)
The magnitude of the force each plate experiences due to the other plate as a function of V, the potential drop across the capacitor is determined as [tex]\frac{V^2 A \varepsilon _o }{2d^2}[/tex].
Magnitude of the force
The magnitude of the force each plate experiences due to the other plate is determined as follows;
F = U/d
where;
U is potential energy stored in the capacitor[tex]F = \frac{1}{2} \frac{Q^2}{C} \times \frac{1}{d} \\\\[/tex]
Q = CV
[tex]F = \frac{1}{2} \frac{C^2V^2}{C d} = \frac{CV^2}{2d}[/tex]
where;
C is the capacitanceThe capacitance is given as;
[tex]C = \frac{\varepsilon _o A }{d}[/tex]
[tex]F = \frac{\varepsilon _o A }{d} \times \frac{V^2}{2d} \\\\F = \frac{V^2 A \varepsilon _o }{2d^2}[/tex]
Thus, the magnitude of the force each plate experiences due to the other plate as a function of V, the potential drop across the capacitor is determined as [tex]\frac{V^2 A \varepsilon _o }{2d^2}[/tex].
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How much momentum, in the x-direction, was transferred to the more massive cart, in kilogram meters per second
The momentum, in the x-direction, that was transferred to the more massive cart after the collision is 19.38 kgm/s.
Momentum transfered to the more massive cartThe momentum transfered to the more massive cart is determined by applying the principle of conservation of linear momentum as shown below;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where;
m₁ is the mass of the smaller cartu₁ is the initial velocity of the samller cartm₂ is the mass of the bigger cart = 3m₁u₂ is the initial velocity of the bigger cartv₁ is the final velocity of the smaller cartv₂ is the final veocity of the bigger cart⁻ΔP₁ = ΔP₂
ΔP₂ = m₂v₂ - m₂u₂
ΔP₂ = m₂(v₂ - u₂)
ΔP₂ = 3m₁(v₂ - u₂)
ΔP₂ = 3 x 3.8 x (1.7 - 0)
ΔP₂ = 19.38 kgm/s
Thus, the momentum, in the x-direction, that was transferred to the more massive cart after the collision is 19.38 kgm/s.
The complete question is beblow
A cart of mass 3.8 kg is traveling to the right (which we will take to be the positive x-direction for this problem) at a speed of 6.9 m/s. It collides with a stationary cart that is three times as massive. After the collision, the more massive cart is moving at a speed of 1.7 m/s, to the right.
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Explain newtons's law of gravitation
Newton's law of universal gravitation is typically stated that every particle attracts every particle in the universe with force that is directly proportional to the result of their masses and inversely proportional to the square of distance between their centers.
A negatively charged plastic comb is brought close to, but does not touch, a small piece of paper. If the comb and the paper are attracted to each other the charge on the paper
A) must be negative
B) may be positive or neutral
C) may be negative or neutral D)must be positive
If the comb and the paper are attracted to each other the charge on the paper, is D)must be positive
Laws of electrical attraction
This states that
Like charges attract Unlike charges repelNow, given that a negatively charged plastic comb is brought close to, but does not touch, a small piece of paper. If the comb and the paper are attracted to each other the charge on the paper, this implies that both the negatively charged plastic comb and the paper have opposite charges.
Since the charge on the plastic comb is negative, this means that the charge on the paper must be positive
So, if the comb and the paper are attracted to each other the charge on the paper, is D)must be positive
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3
3
If a jogger runs a 10 kilometer race in 60 minutes, what is
her average speed?
A
10 km/hr
B
5 km/hr
С 6 km/hr
D
1.66 km/hr
If a jogger runs a 10 kilometer race in 60 minutes, her average speed is 10km/hr. Details about average speed can be found below.
How to calculate average speed?Average speed can be calculated by dividing the distance moved by a body by the time taken. That is;
Average speed = Distance/Time
According to this question, a jogger runs a 10 kilometer race in 60 minutes. The average speed is calculated as follows:
Average speed = 10km/1hr
Average speed = 10km/hr.
Therefore, if a jogger runs a 10 kilometer race in 60 minutes, her average speed is 10km/hr.
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Read the materials on Biomolecules. Summarize and creatively translate them into a poem describing
what you have learned about biomolecules write your answer
Biomolecules are fundamental for life. They required both energy supply and building structures.
What are biomolecules?Biomolecules are organic molecules that fundamental for life and must be ingested from the regular diet.
Biomolecules include proteins (e.g., meal proteins), lipids (fats) and also carbohydrates (e.g., glucose).
Biomolecules required both energy supply (e.g., glucose) and building structures (e.g., amino acids in proteins).
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Predict the magnitude of the gravitational force....
Answer:
a=650.549
b=246.4819
c=38.5261
Explanation:
Read the text below. Each sentence is about one, two or no energy at all. (5 points) Name the type (s) of energy for each sentence, or leave the space blank (if in the sentence no energy is mentioned). Artan decided to paint the house. He moved the furniture, climbed the stairs, and began work. After two hours he took a break, ate lunch and turned on the radio to listen to some music. When done, turn on a heater to allow the paint to dry as quickly as possible. At dinner everything had ended. a) ............................................................................................................................................ b) ............................................................................................................................................ c) ............................................................................................................................................ d) ............................................................................................................................................ e) ............................................................................................................................................
A school bus and a small Toyota Prius collide in a head-on collision
Which vehicle pushed with a greater force? Explain
Which vehicle has a greater mass?
Which vehicle has a greater acceleration after the moment of impact? Explain why
Hi there!
Part 1:
According to Newton's Third Law, every action has an EQUAL and OPPOSITE reaction.
For a collision, the objects involved exert an EQUAL and OPPOSITE impulse on each other, which means the forces exerted are equal as well.
Therefore, the school bus and Toyota Prius exert an EQUAL FORCE on each other.
Part 2:
The school bus has a greater mass.
Part 3:
Using Newton's Second Law:
[tex]\Sigma F = ma[/tex]
Using this relationship, the smaller the mass, the larger the acceleration. Since the forces are EQUAL, the Toyota Prius will experience a larger acceleration because it has a smaller mass.
When you apply increasing thermal energy to a certain material, it reaches a temperature of 50 degrees C. However, when it reaches this temperature, applying more increasing thermal energy does not cause the temperature to rise. Which of the following best explains what is happening?
1. The system is having its heat leaking out that is not going into the material
2. The material is at its phase change temperature and the thermal energy is going to change the phase instead of increase the temperature
3. The material is made of a heat resistant alloy that is preventing the thermal energy from being fully absorbed
4. The material has already absorbed enough thermal energy and cannot absorb any more
The material is at its phase change temperature and the thermal energy is going to change the phase instead of increase the temperature.
What is latent heat?Latent heat is defined as the thermal energy absorbed or released during a phase change of a substance.
Latent heat can also be explained as the energy in hidden form which is supplied or extracted to change the state of a substance without changing its temperature.
From the above explanation, we can conclude that, the material is at its phase change temperature and the thermal energy is going to change the phase instead of increase the temperature.
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Plant and animal cells are both eukaryotic cells that share many organelles and cell structures in common. However, each have unique organelles that perform specific functions in each cell type. Examine each of the lists of cell structures. Which of these are found in plant cells? Select ALL that apply.
A) nucleus, ribosomes, and chloroplasts
B) mitochondria, cell wall, chloroplasts
C) nucleus, mitochondria, and centrioles
D) cell membrane, ribosomes, small vacuoles
E) cell wall, central vacuole, and cell membrane
Answer:
A) nucleus, ribosomes, and chloroplasts
B) mitochondria, cell wall, chloroplasts
D) cell membrane, ribosomes, small vacuoles
E) cell wall, central vacuole, and cell membrane
Explanation:
It cannot be C as the list features centrioles, which is an animal-cell only structure.
What do all waves transfer?
Question 1 options:
matter
energy
particles
water
Answer:
Matter
Explanation:
A wave is a disturbance that transfers energy from one place to another without transferring matter. Waves transfer energy away from the source, or starting place, of the energy.
Answer:
energy
Explanation:
I took the test think of hydropower dams
A pendulum bob has it maximum speed at 3ms at the lowest position 0. Calculate the height of the bob above 0,where it velocity is 0
Hello!
We know that at the BOTTOM of the pendulum's trajectory, the bob has a maximum speed. This means that its KINETIC ENERGY is at a maximum, while its Gravitational POTENTIAL ENERGY is at a minimum.
On the other hand, when the bob is at its highest points, the bob has a velocity of 0 m/s, so its KE is at a minimum and its PE is at a maximum.
We can use the work-energy theorem to solve. Let the Initial Energy equal the bob's energy at one of the sides, while the final Energy equals the bob's energy at the bottom.
[tex]E_i = E_f\\\\PE = KE[/tex]
Recall that:
PE = mgh
m = mass (kg)
g = acceleration due to gravity (m/s²)
h = height (m)
KE = 1/2mv²
m = mass (kg)
v = velocity (m/s)
Set the two equal and solve for 'h'.
[tex]mgh = \frac{1}{2}mv^2[/tex]
Cancel mass.
[tex]gh = \frac{1}{2}v^2[/tex]
Solve for 'h'.
[tex]h = \frac{v^2}{2g}\\\\h = \frac{3^2}{2(9.8)} = \boxed{0.459 m}[/tex]
how can you find the reading of main scale and vernier scale
Answer:
this pdf should help you out
Explanation:
7. A 2.0 kg block, starting from rest, is pushed by a
constant force along a frictionless track. The
position of the block as a function of time is
recorded in the data above. The final momentum
of the block is
(A) 0.8 kgm/s
(B) 1.2 kgm/s
(C) 1.6 kgm/s
(D) 3.2 kgm/s
Answer:
(A) 0.8 kgm/s
Explanation:
because of the even ground it would only slow down
Differences between fundamental and derived quantities
Answer:
Fundamental quantities are quantities that were created to measure a object/substance which are the basis on which derived quantities are formed, where as derived quantities are created by extracting variables from the fundamental quantities.
A rectangular gymnasium is 50 m long, 25 m wide and 8.0 m high.
The density of air is 1.2 kg/mº.
What is the best estimate of the mass of air in the gymnasium?
[tex]\text{Volume,}~V = 50 \times 25 \times 8 = 10000~ m^3\\\\\text{Density,}~\rho = 1.2 ~ kg ~m^{-3}\\ \\\\\text{We know that,}\\\\`~~~~~~~\rho = \dfrac{m}{V}\\\\\implies m = \rho V \\\\\implies m = 1.2 \times 10000 = 12000~kg}\\\\\text{Hence the mass of air is 12000 kg.}[/tex]
Why was the government in giving support to addressing and researching the HIV epidemic ?
Three different scientific institutions provide data about how much the annual global temperature has deviated from the norm in the years 1880 to 2014. The nort is
based on the temperatures of a base period, from 1951 to 1980
Institution A's data show that the annual global temperature deviated from the norm by 0.75°C in 2010
Institution B's data show that the annual global temperature deviated from the norm by 0.72°C in 2010
Institution C's data show that the annual global temperature deviated from the norm by 0.77°C in 2010.
Which are accurate statements about this data? Select the two correct answers
(1 point)
Based on the findings above, the accurate statements are:
B. The institutions have not yet gathered enough data for scientists to draw a conclusion about whether the annual global temperature is gradually increasing.C. The data gathered by each institution is very similar to the data gathered by the other institutions.What are the accurate statements?The information that all three institutions gathered is quite similar with their results showing a range of annual temperature deviation of 0.05°C in 2010.
However, this data is not enough to say that temperatures are rising gradually because there is no information on temperatures from the previous years.
Find out more on annual temperatures at https://brainly.com/question/27043563.
I NEED HELP FAST
Match the term with the appropriate image
A) Focal length
B) Object position
C) Image position
1st image - B) Object position
2nd image - A) Focal length
3rd image - C) Image position
object position is from the lens to the object.image position is from the lens to where both rays meet together.Focal length is where the ray meets the principal axis.enumerate two ways that you practice to control manage noise pollution
1.
2.
please answer it correctly i really need it
nonsense-report
Topic : Collisions and Conservation of Momentum
1. A 0.2 kg ball moves to the right with a speed of 3 m/s. It hits a 0.5 kg ball, which is at rest? After the collision, the second ball moves to the right with a speed of 1 m/s. What is the speed of the first ball after the collision?
2. A 1000 kg rocket carrying 25 kg of fuel and oxygen rises at a velocity of 305 m/s. If all the mass of fuel and oxygen is burned to form gases of combustion, what is the downward velocity of these gases?
2. All of the following are examples of physical properties except:
A. tearing B. density C. melting point D. boiling point
All of the following are examples of physical properties except tearing.
What is Physical property?
This is used to describe the state of a physical system and is usually measurable.
Examples include:
DensityMelting point Boiling pointTearing isn't an example of a physical property which was why option A was chosen as the most appropriate choice.
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how many electrons flow through a 3 A current in 3 seconds
Can someone please help me with this assignment, this is due today
Answer:
did you get it done if not lmk I will help you out tomorrow when I get up
The terminal velocity of a 3 × 10^-5 raindrop is about 9 m/s. Assuming a drag force Fd = −bv, determine (a) the value of the constant b and (b) the time required for such a drop, starting from rest, to reach 63% of terminal velocity.
Based on the data provided, the value of the constant b is 3.27 × 10^-5 kg/s and the time required to reach 63% of terminal velocity is 0.58 s.
What is terminal velocity?The terminal velocity of a body is the velocity at which the body falls at constant velocity through a fluid.
For the falling raindrop, let positive direction be downwards and negative direction upwards,
mass of the raindrop, m = 3×10-5 kg velocity at time t, is v(t)terminal velocity, v0 = 9 m/sgravitational acceleration, g = 9.81 m/s²The raindrop experiences a downward gravitational force mg, and an upward drag force -bv.
The total force at a time t is given as
F(t) = mg - bv(t)a)
Terminal velocity is achieved then the total force is 0,
0 = mg - bv0
Therefore
b = mg/v0
Substitutingthe values:
b = (3 × 10^-5 × 9.8)/9
b = 3.27 × 10^-5 kg/s
b) Applying Newton's Second Law
F = ma
where
a = v/tF = mgTherefore,
mg = mv/t t = v/g
however, t is at 63% velocity
thus:
t = 0.63v/g
t = 0.63 × 9 /9.8
t = 0.58 s
Therefore, the value of the constant b is 3.27 × 10^-5 kg/s and the time required to reach 63% of terminal velocity is 0.58 s
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A car of mass 1000 kg moves 3 km east in a straight line and then 4 km north. What is the total distance and displacement of the car from the initial position?
The net (resultant) force on the car is
Select one:
a) distance = 7 km and displacement = 5 km
b) distance = 5 km and displacement =7 km.
c) distance = 25 km and displacement =7 km.
d) distance = 7 km and displacement = 25 km
Answer:
a
Explanation:
Distance is simply the distance travelled which in this case would be 4km + 3km = 7km
To work out displacement, try to imagine the situation.
Draw a straight line to the east (label it 3) and then draw another line from the end of the first line upwards (label this one 4). Thus, you've created a right angles triangle. Now use pythagorean theorem to work out the displacement
4^2 + 3^2 = 25
sqrt 25 = 5 = displacement
The higher the wattage of a light bulb, the more work the light bulb does. Group of answer choices
True
False
Answer:
True.
Explanation:
The higher the wattage the brighter the light. The efficiency of the system was introduced using and coletician lamps