a merry-go-round (model it as a flat disk) is rotating with initial angular velocity 0.50 r a d / s 0.50rad/s and angular acceleration 0.20 r a d / s 2 0.20rad/s 2 . what is the merry-go-round's angular velocity after 7.0 7.0 seconds?

The first step to solving this problem is to calculate the net force acting on the cart. To do this, we need to use Newton's second law, which states that the net force is equal to the mass of the object multiplied by its acceleration. So, in this case, the net force on the cart is:

Net force = (55 kg)(2.0 m/s^2) = 110 N

Next, we need to determine the force of friction acting on the cart. We know that it is acting in the opposite direction to the applied force, so it is equal in magnitude to the net force but in the opposite direction. Therefore, the force of friction is:

Force of friction = -110 N

Finally, we can use the formula for work, which is:

Work = force x distance x cos(theta)

where theta is the angle between the force and the direction of motion. In this case, the force of friction is acting opposite to the direction of motion, so theta is 180 degrees and cos(theta) is -1.

The distance traveled by the cart is 10 m, so we can plug in the values and get:

Work = (-110 N)(10 m)(-1) = 1100 J

Therefore, the work done by the force of friction as it acts to impede the motion of the cart is 1100 J.

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When the hair dryer is turned on, it draws in cool air from its back end and passes it over a heating element, which increases the temperature of the air.

Cool air is taken in and is heated using a heating element as described. The heated air is then forced out through the front end of the dryer by a fan. As the warm air blows over the hair, it causes the water molecules in the hair to evaporate, thus drying the hair. The hair dryer also helps to style hair by blowing it in different directions, causing it to move and create volume.

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The distance to the RR Lyrae variable star will be underestimated by a factor of 10 due to the effect of interstellar dust.

The distance to an astronomical object can be determined using the inverse square law, which states that the apparent brightness of an object decreases as the square of the distance increases.

The apparent magnitude of an object is a measure of its brightness as seen from Earth. The lower the magnitude, the brighter the object.

If interstellar dust makes an RR Lyrae variable star look 5 magnitudes fainter than it should, then the apparent magnitude of the star as observed from Earth is 5 magnitudes greater than its true apparent magnitude.

Using the inverse square law, we can write:

Apparent brightness ~ 1 / (distance[tex])^2[/tex]

If the apparent brightness is 5 magnitudes fainter than it should be, we can express the distance to the star as:

distance = sqrt(100^(0.4 * 5)) x true distance

where 0.4 is the conversion factor from magnitudes to brightness ratios, and 100 is the ratio of the brightness of the star as observed from Earth to its true brightness.

Simplifying this expression, we get:

distance = 100^(0.5) x true distance

distance = 10 x true distance

Therefore, the distance to the RR Lyrae variable star will be underestimated by a factor of 10 due to the effect of interstellar dust.

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According to Newton's second law of motion, the force required to accelerate an object is directly proportional to its mass. This means that the larger the mass of an object, the greater the force required to move it.

In this scenario, the large truck has a much greater mass than the small car. Therefore, the large truck would be more difficult to push to the gas station. It would require a much greater force to overcome its inertia and start its motion. Once the truck is in motion, it would also require a greater force to keep it moving at a constant speed.

On the other hand, the small car has a smaller mass and would require less force to push it to the gas station. Once in motion, it would require less force to maintain its speed.

Therefore, due to the larger mass of the truck, it would be more difficult to push to the gas station compared to the smaller car.

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If a red giant appears the same brightness as a red main sequence star, it is most likely that the red giant is further away.

Here's a step-by-step explanation:

1) Red giants and red main sequence stars are both types of stars that are similar in color, but they have different sizes and luminosities.

2) Red giants are much larger and more luminous than red main sequence stars. They are formed when a star like the sun runs out of fuel and begins to expand and cool.

3)Red main sequence stars, on the other hand, are smaller and less luminous than red giants. They are stars that are still burning hydrogen fuel in their cores.

4) The apparent brightness of a star depends on both its intrinsic luminosity and its distance from Earth. The farther away a star is, the dimmer it appears to us on Earth.

5) If a red giant appears the same brightness as a red main sequence star, this means that the red giant must be much farther away from Earth than the red main sequence star.

6) This is because the red giant is intrinsically much more luminous than the red main sequence star. If both stars were at the same distance from Earth, the red giant would appear much brighter than the red main sequence star.

7) However, since the red giant appears the same brightness as the red main sequence star, this means that the red giant must be much farther away from Earth and therefore appears dimmer.

Overall, by comparing the apparent brightness of a red giant and a red main sequence star, we can determine which star is farther away.

If the red giant appears the same brightness as the red main sequence star, then the red giant is likely to be much farther away.

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The speed of the particle at x = 8.0 m is 9.30 m/s.

We can solve this problem using the work-energy theorem, which states that the net work done on an object is equal to its change in kinetic energy,

W_net = ΔK

Where W_net is the net work done by all forces acting on the object, and ΔK is the change in kinetic energy of the object.

In this case, the only force acting on the particle is F(x) = 3x N, which is a conservative force, so the net work done by this force can be expressed as the negative gradient of a potential energy function:

W_net = -ΔU

Where ΔU is the change in the potential energy of the particle.

Since F(x) = -dU/dx, we can integrate both sides with respect to x to find the potential energy function:

[tex]U(x) = -\int F(x) dx\\= -\int 3x dx[/tex]

= -1.5x² + C

where C is an arbitrary constant of integration. To determine the value of C, we can use the fact that U(x) is defined up to an arbitrary constant, so we can set U(3) = 0:

U(3) = -1.5(3)² + C = 0

C = 13.5

So the potential energy function is,

U(x) = -1.5x² + 13.5

Now we can use the conservation of energy to find the velocity of the particle at x = 8.0 m. At x = 3.0 m, the kinetic energy of the particle is,

K(3) = (1/2)mv² = (1/2)(2.6 kg)(7.0 m/s)² = 67.9 J

The potential energy at x = 3.0 m is:

U(3) = -1.5(3)² + 13.5 = 0 J

So the total energy of the particle at x = 3.0 m is:

E(3) = K(3) + U(3) = 67.9 J

At x = 8.0 m, the potential energy is:

U(8) = -1.5(8)² + 13.5 = -94.5 J

Therefore, the kinetic energy of the particle at x = 8.0 m is:

K(8) = E(3) - ΔU = 67.9 J - (-94.5 J) = 162.4 J

The velocity of the particle at x = 8.0 m can be found using the kinetic energy formula:

K = (1/2)mv²

v = √(2K/m) = √(2(162.4 J)/(2.6 kg)) = 9.30 m/s

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The solid hemisphere exerts a pressure of 17,350 Pascals on the surface.

To find the pressure exerted by the solid hemisphere, we need to consider the weight of the object and the surface area in contact with the surface. The weight of the solid hemisphere is equal to its mass times the acceleration due to gravity, which is 10 kg x 9.81 m/s^2 = 98.1 N.

The surface area in contact with the surface is the curved surface area of the hemisphere, which is half the surface area of a sphere with radius 30 mm. Using the formula for the surface area of a sphere, we get:

Surface area = 2πr^2 = 2π(30 mm)^2 = 5,655.6 mm^2

To convert this to square meters, we divide by 1,000,000, which gives us 0.0056556 m^2.

Finally, we can calculate the pressure exerted by the solid hemisphere using the formula:

Pressure = Weight / Surface area = 98.1 N / 0.0056556 m^2 = 17,350 Pa

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The results of this experiment do support my hypothesis that the tennis ball would experience the highest energy loss due to its larger mass and larger surface area.

Hypothesis is a statement or a theory that is used as a starting point for further investigation. It is an educated guess or a prediction about the relationship between two or more variables. Hypothesis is used in scientific experiments to test possible explanations and predictions of natural phenomena. Hypothesis testing involves gathering data to test the hypothesis and then analyzing the results to determine if the data supports or disproves the hypothesis. If the data does not support the hypothesis, then the hypothesis is rejected and a new hypothesis must be formed.

The results showed that the tennis ball had the highest average energy loss out of the three balls tested at 42.2%. This was followed by the golf ball at 36.3%, and the ping pong ball at the lowest average energy loss of 33.9%.
Overall, this experiment was successful in that it demonstrated that the larger mass and surface area of the tennis ball do result in a higher energy loss compared to the other two balls. This experiment thus supports the hypothesis that heavier, larger balls experience more energy loss due to their size and mass.

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The speedometer of your car reading v = 45 m/s indicates the instantaneous speed of your car at that particular moment in time.

Instantaneous speed is the speed of an object at a specific moment in time and is often represented as the magnitude of the instantaneous velocity vector. In the context of your car's speedometer, the reading of 45 m/s indicates the speed of your car at the exact moment the reading was taken.

In contrast, the average speed is the total distance travelled by an object divided by the time it took to travel that distance. It represents the average rate at which the object covered the distance, and does not provide information about the object's speed at any particular moment in time.

Therefore, the reading on your car's speedometer represents instantaneous speed, not average speed.

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The speedometer of your car reading v = 45 m/s is the instantaneous speed of the car.

Instantaneous speed is the speed of an object at a particular moment in time, without taking into account any previous or future motion. In this case, the speedometer is providing a real-time reading of the car's speed at that moment.

The speedometer measures the speed of the car through a device called a speed sensor.

The sensor measures the rotation of the wheels and converts it into an electrical signal, which is then used to calculate the speed of the car.

The speedometer then displays this speed in m/s or mph on the dashboard of the car.

It's important to note that instantaneous speed can change rapidly as the car accelerates, decelerates, or changes direction. This means that the speedometer reading will change as the car's speed changes.

In contrast, average speed is calculated by dividing the total distance traveled by the total time taken to travel that distance.

It provides an average value of the speed over a period of time, such as the entire trip or journey.

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If the distance between the thermopile sensor and the source is doubled and all other parameters remain the same, the thermopile reading will decrease by 75%.

The thermopile reading is a measure of the temperature difference between the thermopile sensor and the source. If the distance between the thermopile sensor and the source is doubled, the temperature difference between the two will decrease. This is because the heat will have to travel a longer distance to reach the thermopile sensor, resulting in a lower temperature difference. It is important to note that this calculation assumes that all other parameters remain constant.

The percentage decrease in the thermopile reading can be calculated using the inverse square law. According to this law, the intensity of the heat radiation is inversely proportional to the square of the distance between the source and the thermopile sensor. This means that if the distance is doubled, the intensity of the heat radiation will decrease by a factor of four (2 squared). Therefore, the thermopile reading will decrease by 75% (4/1) when the distance between the thermopile sensor and the source is doubled.

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Answer:

The solute and solvent have distinct chemical characteristics.

Explanation:

The solute and solvent could not have been mixed at the current temperature. The solute and solvent have distinct chemical characteristics. There was more pressure. The mixture was fully saturated.

Hope this helped :)

Answer: The fact that the solute does not mix with the solvent even after boiling and stirring repeatedly could be due to various reasons:

Insolubility: The solute may be insoluble in the solvent, meaning it cannot dissolve in it.  This could be because the solute particles are too large or have a different molecular structure compared to the solvent. For example, oil and water do not mix because oil is non-polar while water is polar.

Immiscibility: The solute and solvent may be immiscible, which means they cannot form a homogeneous mixture.  Immiscibility occurs when there is a significant difference in polarity or density between the solute and solvent.  An example of immiscible substances is oil and water, where they form separate layers instead of mixing.

Saturation: The solvent may already be saturated with the solute. Saturation occurs when the solvent can no longer dissolve any more of the solute at a given temperature. Further boiling and stirring would not result in any additional mixing.

Chemical reaction: There might be a chemical reaction occurring between the solute and solvent, leading to the formation of a new substance or a precipitate.  This can prevent the solute from dissolving completely in the solvent.

To determine the specific reason why the solute is not mixing with the solvent, it would be helpful to know the nature of the solute and solvent, as well as any other conditions or factors involved in the process.

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The distance traveled by Dheepthi from point A to B is 29.5m.

To find the distance AB, we need to use Pythagoras' theorem, which states that the square of the hypotenuse (the longest side) of a right triangle is equal to the sum of the squares of the other two sides.

In this case, we can break down Dheepthi's journey into a series of right triangles.

First, she walks 4m in the south direction from point A. Then, she turns right and walks 5m, forming a right triangle with legs of 4m and 5m.

Using Pythagoras' theorem, we can calculate the hypotenuse (her distance from point A) to be 6.4m.

Next, she turns left and walks 3m, forming another right triangle with legs of 1.6m (the remainder of her distance south) and 3m. Using Pythagoras' theorem again, we can calculate the hypotenuse of this triangle to be 3.4m.

Then, she turns right and walks 4m, forming a right triangle with legs of 1.6m and 4m. The hypotenuse of this triangle is 4.2m.

Finally, she turns right again and walks 15m, forming a right triangle with legs of 4.2m and 15m. The hypotenuse of this triangle is 15.5m.

Adding up all of these distances, we get a total distance of 6.4m + 3.4m + 4.2m + 15.5m = 29.5m. Therefore, the distance AB is 29.5m.

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Frequency = the rate per second of a vibration constituting a wave, either in a material (as in sound waves), or in an electromagnetic field (as in radio waves and light).

The frequency is =  0.00030864 Hz

Solution -  To find the frequency of the oscillation after an intense earthquake, we need to use the formula:
Frequency (f) = 1 / Period (T)
Given that the period of the Earth's oscillation is 54 minutes, we first need to convert this to seconds:
54 minutes * 60 seconds/minute = 3240 seconds
Now, we can find the frequency:
Frequency (f) = 1 / 3240 seconds ≈ 0.00030864 Hz
the frequency of the oscillation after the intense earthquake is approximately 0.00030864 Hz.

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To find the distance between the object and image produced by a converging lens with a 35.5 cm focal length when the object is 45 cm from the lens, you can use the lens formula:

1/f = 1/do + 1/di

Where:
f = focal length (35.5 cm)
do = object distance (45 cm)
di = image distance

Step 1: Plug in the values for f and do:
1/35.5 = 1/45 + 1/di

Step 2: Subtract 1/45 from both sides:
1/35.5 - 1/45 = 1/di

Step 3: Find a common denominator and subtract:
(45 - 35.5)/(35.5 * 45) = 1/di
9.5/(35.5 * 45) = 1/di

Step 4: Take the reciprocal of both sides:
di = (35.5 * 45)/9.5

Step 5: Calculate di:
di ≈ 168.42 cm

So, the object and image produced by the converging lens with a 35.5 cm focal length when the object is 45 cm from the lens are approximately 168.42 cm apart.

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A photon with a longer wavelength has a lower frequency than a photon with a short wavelength, the correct option is (d)

The wavelength and frequency of a photon are related to its energy and color. Photons with shorter wavelengths have higher frequencies and higher energy, while photons with longer wavelengths have lower frequencies and lower energy.

This is described by the equation E = hf, where E is energy, h is Planck's constant, and f is frequency. Therefore, a photon with a longer wavelength has a lower frequency than a photon with a shorter wavelength, the correct option is (d)

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The complete question is:

A photon with a longer wavelength

a) is more energetic than a photon with a short wavelength.

b) travels slower than a photon with a short wavelength.

c) is more blue than a photon with a short wavelength.

d) has a lower frequency than a photon with a short wavelength.

e) All of the above

The force exerted on the charge 10q has a magnitude that is greater than F.

The force between two charged particles is given by Coulomb's law:

F = k * q1 * q2 / r^2

If we consider the system of two charges, q and 10q, and assume that they are at the same distance from the test charge:

[tex]F = k * q * qtest / r^2[/tex]

where qtest is the charge of the test charge.

Similarly, the force on the test charge due to 10q is given by:

F' = k * (10q) * qtest / r^2

Dividing second equation by the first, we get:

F' / F =[tex](10q * qtest) / (q * qtest)[/tex] = 10

So the force exerted on the charge 10q has a magnitude that is greater than the force exerted on the charge q by a factor of 10.

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The maximum speed is 62.8 cm/s.

We can start by finding the frequency of the oscillation:

Then, we can use the formula for the displacement of an object in simple harmonic motion:

Where x is the displacement (in meters), A is the amplitude (in meters), f is the frequency (in Hz), and t is the time (in seconds).

We are given that the displacement is 10.0 cm = 0.1 m, and we know that the amplitude is half of the total displacement (since the ruler moves symmetrically around its equilibrium position), so:

Using this information, we can find the maximum speed by taking the derivative of the displacement equation:

At the point of maximum displacement (when sin(2πft) = 1), the speed is:

vmax = 2πfA = 2π(2.5 Hz)(0.05 m) = 0.628 m/s = 62.8 cm/s (to one decimal point).

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Momentum is defined as mass multiplied by velocity, so the total momentum before the extinguisher is thrown is 70 kg*m/s.

Velocity is a vector quantity that measures the rate of change of an object's position. It is determined by the displacement of an object over a given period of time, and is usually expressed in terms of distance over time.

The astronaut's resulting velocity will be the same as the fire extinguisher's velocity, 3.5 m/s.
This is because the astronaut and extinguisher have the same mass and momentum must be conserved.
Momentum is defined as mass multiplied by velocity, so the total momentum before the extinguisher is thrown is 75 kg * 0 m/s + 20 kg * 3.5 m/s
= 70 kg*m/s.

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The law of conservation of mass states that the mass in an isolated system can neither be created nor be destroyed but can be transformed from one form to another.

In the conversion of any form of energy, it obeys the law of conservation. That is to say that energy is not lost but can be converted from one form to another.

A form of energy can transform to another form when there is a change in its state.

For example, light energy in bulbs is being converted to heat energy with the bulb is lit.

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The spring can produce 0.00585 kJ of work when compressed 3 cm from its unloaded length.

To calculate the work done by a spring, we can use the formula:

W = (1/2) k [tex]x^2[/tex]

where W is the work done by the spring, k is the spring constant, and x is the displacement of the spring from its equilibrium position.

In this case, the spring constant is given as 13 kN/cm, which is equivalent to 130 N/cm or 13,000 N/m (since 1 kN = 1000 N). The displacement of the spring from its unloaded length is 3 cm.

So, the work done by the spring is:

W = (1/2) k [tex]x^2[/tex]

W = (1/2) (13,000 N/m) (0.03 m[tex])^2[/tex]

W = 5.85 J

To convert joules to kilojoules, we can divide the answer by 1000:

W = 5.85 J / 1000

W = 0.00585 kJ

Therefore, the spring can produce 0.00585 kJ of work when compressed 3 cm from its unloaded length.

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The clock must be moving at a velocity of approximately 4.53 m/s relative to the observers on the ground in order to experience a time dilation of 2.7 ns over the course of one day.

According to Einstein's theory of relativity, time dilation occurs when an object moves at a constant velocity relative to an observer. This means that time appears to pass more slowly for an object in motion than for an observer at rest. The amount of time dilation depends on the relative velocity between the two objects.

In this problem, we are given that a clock moving at some velocity loses 2.7 nanoseconds (ns) over the course of one day, as measured by observers on the ground. We want to determine the velocity of the clock.

We can use the formula for time dilation, which states that the observed time interval (Δt') is related to the proper time interval (Δt) by:

[tex]$\Delta t' = \frac{\Delta t}{\sqrt{1 - \frac{v^2}{c^2}}}$[/tex]

where v is the velocity of the clock, c is the speed of light, and the square root is taken using the binomial approximation (since v << c).

We know that Δt' = Δt - 2.7 ns and Δt = 1 day = 86400 seconds. Substituting these values and simplifying, we get:

[tex]$86400 - 2.7 = \frac{86400}{\sqrt{1 - \frac{v^2}{c^2}}}$[/tex]

Squaring both sides and rearranging, we can solve for v:

[tex]$v = c \sqrt{1 - \left(\frac{2.7}{86400}\right)^2} \approx 4.53 \text{ m/s}$[/tex]

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The work done by the torque to stop the wheel is -1918 J.

The given parameters are:
- Wheel radius (r): 15 cm = 0.15 m
- Rotational inertia (I): 2.3 kg·[tex]m^{2}[/tex]
- Angular velocity (ω): 6.5 revolutions per second = 6.5 * 2π rad/s ≈ 40.84 rad/s

To find the work done by the torque to stop the wheel, we can use the rotational work-energy theorem: W = 0.5 * I * (ω_[tex]f^{2}[/tex] - ω_[tex]i^{2}[/tex]), where W is the work done, ω_f is the final angular velocity (0 rad/s), and ω_i is the initial angular velocity.

Plugging in the given values:
W = 0.5 * 2.3 kg·[tex]m^{2}[/tex] * (0^2 - 40.84 rad/s^2)
W = 0.5 * 2.3 kg·[tex]m^{2}[/tex] * (-1667.86 rad^2/s^2)
W ≈ -1918.24 J

Since work is done against the frictional force to bring the wheel to a stop, the work done is negative. Therefore, the work done by the torque to stop the wheel is most nearly -1918 J.

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A student is constructing a stream table to investigate how erosion by a meandering stream is affected by the slope of the land should  vary,  the number of blocks stacked beneath the tray. Option A

The purpose of the experiment is to investigate how the slope of the land affects erosion by a meandering stream. By varying the number of blocks stacked beneath the tray, the student can change the slope of the land and observe how this affects the behavior of the stream and the resulting erosion.

Varying the sediment size, the volume of water, or the size of the hole in the bottom of the container would not directly address the question of how slope affects erosion by a meandering stream.

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Type 1 cable consists of a braided outer shield surrounding the entire cable core and covered with a jacket, the correct answer is c.

Type 1 cable is commonly used in high-frequency applications where signal interference is a concern. The braided shield provides excellent protection against electromagnetic interference (EMI) and radio frequency interference (RFI). It also helps to reduce signal loss and attenuation by keeping the signal within the cable and preventing it from escaping.

The jacket provides an additional layer of protection against environmental factors such as moisture, abrasion, and temperature extremes. Type 1 cable is a reliable and effective option for applications where signal integrity and protection against interference are critical factors, the correct answer is c.

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The complete question is:

Type 1 cable consists of ?

a. twisted pairs

b. each individually shielded with foil

c. with a braided outer shield surrounding the entire cable core and covered with a jacket.

Equipment that is designed to be dust-ignitionproof must be constructed in a way that prevents dust from getting inside and removes the possibility that heat, sparks, or arcs generated inside the apparatus would result in explosions or fires.

This is due to the fact that dust can be extremely hazardous in some working situations and can result in mishaps that could harm personnel or harm equipment.

In order to work safely in dusty environments, it is crucial to design and construct dust-ignitionproof equipment that can do so by avoiding the ignition of any dust that may be present inside or around the equipment. The ability to operate the machinery safely without endangering their health or safety is thus guaranteed.

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The change in sound of the train whistle from a higher pitch to a lower pitch after the train passes can be explained by the Doppler Effect.

Here is a step-by-step explanation:

1) The Doppler Effect is the change in frequency or pitch of a sound wave due to the relative motion of the sound source and the observer.

2) When the train is approaching the observer, the sound waves from the train are compressed and the frequency or pitch of the sound wave appears higher.

3) As the train passes the observer, the sound waves from the train are stretched and the frequency or pitch of the sound wave appears lower.

4) This change in frequency or pitch can be explained by the relative motion of the train and the observer.

When the train is approaching the observer, the sound waves from the train are "bunched up" and appear closer together, resulting in a higher frequency or pitch.

When the train is moving away from the observer, the sound waves are "stretched out" and appear further apart, resulting in a lower frequency or pitch.

5) The change in frequency or pitch of the train whistle can be represented by a graph showing the frequency of the sound wave over time.

Before the train passes, the frequency of the sound wave gradually increases as the train approaches the observer.

After the train passes, the frequency of the sound wave gradually decreases as the train moves away from the observer.

6) The change in frequency or pitch of the train whistle can also be calculated using the Doppler Effect equation, which relates the frequency of the sound wave, the speed of the sound wave, and the relative velocity of the train and the observer.

In summary, the change in sound of the train whistle from a higher pitch to a lower pitch after the train passes is due to the Doppler Effect, which is caused by the relative motion of the train and the observer.

The change in frequency or pitch can be represented by a graph or calculated using the Doppler Effect equation.

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The final angular speed of the hard disk is 766.9 rad/s, and it takes 4.04 s to reach this speed with an angular acceleration of 190.0 [tex]rad/s^2[/tex].

To take care of this issue, we want to utilize the equation that relates the rakish removal of a pivoting object to its precise speed increase, time, and beginning rakish speed. The equation is given by:

θ = 1/2 * α * [tex]t^2[/tex] + ω0 * t + θ0

Where θ is the complete point pivoted by the plate, α is the precise speed increase, t is the time slipped by, ω0 is the underlying rakish speed, and θ0 is the underlying point.In this issue, the circle begins from rest, so ω0 = 0. The rakish speed increase of the plate is given as 190 [tex]rad/s^2[/tex], and the last precise speed is 7200 rpm.

We want to change the last precise speed from rpm over completely to rad/s by increasing it with 2π/60. In this manner, the last precise speed is 240π rad/s.We can now substitute these qualities into the recipe and compute the absolute point pivoted by the circle after 10.0 seconds:

θ = 1/2 * 190 [tex]rad/s^2[/tex] * [tex](10.0 s)^2[/tex] + 0 rad/s * 10.0 s + 0 rad

θ = 9500 rad

To change this point over completely to the quantity of insurgencies, we partition it by 2π, as one unrest compares to a point of 2π radians. Consequently:

θ in transformations = 9500 rad/(2π rad/unrest) = 1507 upheavals

Accordingly, the plate has made 1507 insurgencies after 10.0 seconds from its underlying state.

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The complete question is:

A computer hard disk starts from rest, then speeds up with an angular acceleration of 190.0 [tex]rad/s^{2}[/tex]until it reaches a final angular speed of 7300.0 rpm.

(a) What is the final angular speed in units of rad/s? rad/s.

(b) How long does it take for the disk to reach this angular speed? s

(c) How many revolutions (not radians) does it make in getting to the final angular speed? rev

(d) Once the disk reaches its final angular speed, it continues rotating at this same speed. How many revolutions has the disk made 10.0 s after it started up from rest?

According to the article, the Juno spacecraft has several observational capabilities. Juno's observational capabilities allow scientists to study Jupiter's atmosphere, magnetic field, and gravity field.

The Juno spacecraft has several observational capabilities that have been identified in various articles. Some of the observational capabilities of the Juno spacecraft are:

Learn more about the Juno spacecraft: https://brainly.com/question/13753163

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