A mixing chamber receives a steady flow of water from different parts of a processing plant. It has two inlets and one outlet. The mixing chamber is NOT well insulated and DOES allow heat transfer between the device and the surroundings. Kinetic and potential energy effects are negligible. Determine the mass flow rate at inlet 1 in [kg/s]. Determine the rate of heat transfer between the mixing chamber and the surroundings in [kW]; carefully indicate direction (i.e., does energy move by heat transfer to or from the chamber

Answers

Answer 1

Answer:

hello your question has some missing information attached below is the missing information

answer :

a) 9.17431 kg/s

b) 2598.4374 kW

Explanation:

a) Calculate mass flow rate at inlet 1

Given data :

AV1 = 0.01 m^3/s

pressure ( P1 ) = 5 bar , temp ( T1 ) = 150°C

therefore : m1 = AV1 / v1 ------ ( 1 )

where : v1 = 0.00109 m^3/kg  ( value gotten from compressed table )

back to equation 1

m1 =  ( 0.01 m^3/s  / 0.00109 m^3/kg )  = 9.17431 kg/s

b) Calculate the rate of heat transfer

first determine mass balance

m3 = m1 + m2  

     = 9.17431 + 19 = 28.17431 kg/s

apply the energy balance equation to determine the rate of heat transfer

m1*h1 + m2*h2 = m3*h3 + Q

∴ Q = m1*h1 + m2*h2 - m3*h3 ------------ ( 1 )

where :

h1 = 632.266 kJ/kg  value gotten from compressed water table

h2 = 2812.45 kJ/kg  value gotten from superheated steam table

h3 = 2010.2965 kJ/kg value gotten from saturated pressure table

input values into equation 1 above

Q = 2598.4374 kW  . the energy moves from the chamber to the surroundings

A Mixing Chamber Receives A Steady Flow Of Water From Different Parts Of A Processing Plant. It Has Two

Related Questions

A piece of corroded steel plate was found in a submerged ocean vessel. It was estimated that the original area of the plate was 5 in.2 and that approximately 2.3 kg had corroded away during the submersion. Assuming a corrosion penetration rate of 200 mpy for this alloy in seawater, estimate the time of submersion in years. The density of steel is 7.9 g/cm3.

Answers

Answer:

the estimated time of submersion is 17.7 years

Explanation:

Given the data in the question;

estimate the time of submersion in years.

we write down the relation between time of submersion and corrosion penetration as follows;

CPR(mpy) = K × W(mg) / [ A(in²) × p(g/cm³) × t(hr) ]

we solve for t

t = (K × W) / ( AP × CPR )

given that;  

Area A = 5 in²

W = 2.3 kg = 2.3 × 10⁶ mg

density of steel p = 7.9 g/cm³

CPR = 200

we know that K is 534

so we substitute

t = (534 × 2.3 × 10⁶ mg) / ( 5 in² × 7.9 g/cm³ × 200 mpy )

t = 1,228,200,000 / 7900

t = 155468.3544 hr

t = 155468.3544 hr × ( 1 yrs / ( 365 × 24 hrs )

t = 17.7 years

Therefore, the  estimated time of submersion is 17.7 years

A fuel oil is burned with air in a furnace. The combustion produces 813 kW of thermal energy, of which 65% is transferred as heat to boiler tubes that pass through the furnace. The combustion products pass from the furnace to a stack at 6500C. Water enters the boiler tubes as a liquid at 200C and leaves the tubes as saturated steam at 20 bar absolute. Calculate the rate (kg/h) at which steam is produced.

Answers

The rate at which steam is produced is equal to 701 kg/hour.

What is a Boiler?

A Boiler may be characterized as a type of device or instrument that significantly transforms water into steam. There are two types of boiler are found. They are water tube boilers and fire tube boilers.

According to the question,

The power generated by combustion, W = 813kW.

The efficiency of the boiler, η = 65% = 0.65.

Temperature, To = 650°C.

Water enters the boiler tubes as a liquid, T1 = 20°C.

Water leaves the tubes as saturated steam, P2 = 20 bar.

The enthalpy of water at 20°C, [tex]h_1[/tex] = 83.9kJ/kg.

The enthalpy of water at 20 bar pressure, [tex]h_2[/tex] = 2797.29kJ/kg.

Enthalpy change can be calculated by ΔH = [tex]h_2-h_1[/tex]

= 2797.29kJ/kg - 83.9kJ/kg = 2713.3 kJ/kg.

The total energy that can be developed can be calculated by the formula:

Q = W × η = 813 × 0.65 = 528.45 kW.

The mass of the flow rate of the rate at which steam is produced is calculated by the following formula:

[tex]m^.[/tex] = Q/ΔH

             = 528.45 kW/2713.3 kJ/kg.

             = [tex]\frac{528.45kW }{2713.3kJ/kg} *\frac{3600kJ/h}{1kW}[/tex] = 701 kg/hour.

Therefore, the rate at which steam is produced is equal to 701 kg/hour.

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The atomic weights of C and H are 12 and 1, respectively. The chemical formula of polyethylene is (C2H4)n. The number average mean molecular weight of polyethylene with a degree of polymerization of 12,000 is:_____.
a. 120,000.
b. 336,000.
c. 280,000.
d. 296,000.

Answers

Answer:

b. 336,000.

Explanation:

Step 1: Calculate the molecular weight of the monomer

Polyethilene is a polymer with the formula (C₂H₄)ₙ, where C₂H₄ is the monomer and n is the number of monomers in the polymer. We can calculate the molecular weight of the monomer by addition of the weights of the atoms that form it.

MC₂H₄ = 2 × MC + 4 × MH

MC₂H₄ = 2 × 12 + 4 × 1 = 28

Step 2: Calculate the average molecular weight of polyethylene

The average degree of polymerization (DP) of polyethylene is 12,000. We can calculate the average molecular weight of polyethylene using the following expression.

DP = M(C₂H₄)ₙ/MC₂H₄

M(C₂H₄)ₙ = DP × MC₂H₄

M(C₂H₄)ₙ = 12,000 × 28 = 336,000

The 150 mm thick wall of a gas fired furnace is constructed of fireclay brick (k=1.5 W/m.K) , tho=2600 kg/m3, and cp=1000 J/kg.K ) and is well insulated at its outer surface. The wall is at a uniform initial temperature of 20 degree C, when the burners are fired and inner surface is exposed to products of combustion for which T infinity=950 degree C and h=100 W/ m2.K.
(A) How long does it take for the outer surface of the wall to reach a temperature of 750 degree C?
(B) plot the temperature distribution in the wall at the foregoing time.

Answers

Answer:

I am thick but I dont know the anwser

The time that it will take for the outer surface of the wall to reach a temperature of 750 degree C will be 33800 seconds.

How to calculate the time?

Using the approximation methods, Fo will be;

= In(0.215/1.262)/(1.4289)²

= 0.867

Then, the time taken will be:

= 0.867(0.15)²/(1.5/2600 × 1000)

= 33800 seconds.

In conclusion, the time taken is 33800 seconds.

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