Answer:
n₂ = 1.459
Explanation:
This is a refraction exercise
n₁ sin θ₁ = n₂ sin θ₂
where n₁ and n₂ are the refractive indices of the incident and refracted medium, respectively
In the exercise they indicate that the incident medium is the air that has a refractive index n1 = 1
n₂ = n₁ [tex]\frac{sin \ \theta_1 }{sin\ \theta_2 }[/tex]
let's calculate
n₂ = 1 [tex]\frac{ sin \ 45}{sin \ 29}[/tex]
n₂ = 1.459
The absolute index of refraction of the medium X in which the monochromatic ray of light enters from air is 1.459.
What is Snell's law?According to the Snell's law, the ratio of index of reflection of the different material is equal to the ratio of incident sine angle and reflective sine angle. It can be given as,
[tex]\dfrac{n_1}{n_2}=\dfrac{\sin\theta_2}{\sin\theta_1}[/tex]
Here (n₁ and n₂) are the index and reflective index and (θ₁ and θ₂) are the incident and reflected angle.
A monochromatic ray of light (f = 5.09 x 1014 Hz) travels from air into medium X.
The angle of incidence of the ray in air is 45.0° and the ray's angle of refraction in medium X is 29.0°.
As, it is known that the index of reflection of air is 1. Thus, by the Snell's law, the absolute index of refraction of medium X is,
[tex]\dfrac{1}{n_x}=\dfrac{\sin(29)}{\sin(45)}\\n_x=1.459[/tex]
Thus, the absolute index of refraction of the medium X in which the monochromatic ray of light enters from air is 1.459.
Learn more about the Snell's law here;
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can someone help me write a poem about “SOFIA-infrared telescope on an airplane”
Answer:
this seems to not be worded right
Explanation:
If one 9V battery is used in a circuit with a total resistance of 39Ω, what is the current in the circuit?
Answer:
Using V= IR
I= 0.2307 Ampere
Explain Sound level intensity with mathematical steps?
Answer:
sound intensity is explained by the following formula I= P/A where I= sound intensity(W/m²),P=power(W),A= area(m²) I hope this helps good luck!
Answer:
In a quiet forest, you can sometimes hear a single leaf fall to the ground. After settling into bed, you may hear your blood pulsing through your ears. But when a passing motorist has his stereo turned up, you cannot even hear what the person next to you in your car is saying. We are all very familiar with the loudness of sounds and aware that they are related to how energetically the source is vibrating. In cartoons depicting a screaming person (or an animal making a loud noise), the cartoonist often shows an open mouth with a vibrating uvula, the hanging tissue at the back of the mouth, to suggest a loud sound coming from the throat Figure 2. High noise exposure is hazardous to hearing, and it is common for musicians to have hearing losses that are sufficiently severe that they interfere with the musicians’ abilities to perform. The relevant physical quantity is sound intensity, a concept that is valid for all sounds whether or not they are in the audible range.
Intensity is defined to be the power per unit area carried by a wave. Power is the rate at which energy is transferred by the wave. In equation form, intensity I is I=PAI=PA, where P is the power through an area A. The SI unit for I is W/m2. The intensity of a sound wave is related to its amplitude squared by the following relationship:
\(\displaystyle{I}=\frac{\left(\Delta{p}\right)^2}{2\rho{v}_{\text{w}}}\\\).
Here Δp is the pressure variation or pressure amplitude (half the difference between the maximum and minimum pressure in the sound wave) in units of pascals (Pa) or N/m2. (We are using a lower case p for pressure to distinguish it from power, denoted by P above.) The energy (as kinetic energy mv22mv22) of an oscillating element of air due to a traveling sound wave is proportional to its amplitude squared. In this equation, ρ is the density of the material in which the sound wave travels, in units of kg/m3, and vw is the speed of sound in the medium, in units of m/s. The pressure variation is proportional to the amplitude of the oscillation, and so I varies as (Δp)2 (Figure 2). This relationship is consistent with the fact that the sound wave is produced by some vibration; the greater its pressure amplitude, the more the air is compressed in the sound it creates
Sound intensity levels are quoted in decibels (dB) much more often than sound intensities in watts per meter squared. Decibels are the unit of choice in the scientific literature as well as in the popular media. The reasons for this choice of units are related to how we perceive sounds. How our ears perceive sound can be more accurately described by the logarithm of the intensity rather than directly to the intensity. The sound intensity level β in decibels of a sound having an intensity I in watts per meter squared is defined to be β(dB)=10log10(II0)β(dB)=10log10(II0), where I0 = 10−12 W/m2 is a reference intensity. In particular, I0 is the lowest or threshold intensity of sound a person with normal hearing can perceive at a frequency of 1000 Hz. Sound intensity level is not the same as intensity. Because β is defined in terms of a ratio, it is a unitless quantity telling you the level of the sound relative to a fixed standard (10−12 W/m2, in this case). The units of decibels (dB) are used to indicate this ratio is multiplied by 10 in its definition. The bel, upon which the decibel is based, is named for Alexander Graham Bell, the inventor of the telephone.
Table 1. Sound Intensity Levels and IntensitiesSound .
PLZZZZ HELPPPPPP MEEEEEE!!!!!! ASAP!!! ILL GIVE 20 POINTS AND BRAINLIEST!!!
:'(
Answer:
I would choose A. and B
Explanation:
The parent and daughter elements are different and the number of atoms is not conserved.
What is the average power supplied by a 60.0 kg secretary running up a flight of stairs rising vertically 4.0 m in 4.2 s?
Answer:
9.8kW
Explanation:
Given data
Mass= 60kg
Hieght= 4m
Time= 4.2seconds
We know that the energy possessed is given as
PE=mgh
PE=60*9.81*4
PE= 2354.4 Joulse
Also, the expression for power is
Power=Energy*Time
Power= 2354.4*4.2
Power=9888.48 watt
Power= 9.8kW
Susan uses a system of pulleys to lift a 355 N box, but she only exerts 25 N. What is the MA of the pulley system?
Answer:
oof
Explanation:
oof
WHAT IS THE SPEED OF LIGHT?
WHAT DOES LIGHT TRAVEL FASTEST THROUGH?
2ND FASTEST?
3RD FASTEST?
SLOWEST?
Answer:
speed of light: 299,792,458
what does light travel fasted through?: Light will have the fastest velocity when it travels through the air. Light will have the slowest velocity when it travels through gelatin. Why? Light slows down when passing through different transparent materials. The more it slows down, the more it bends when it hits a medium made of that material
If the mean of 6, 7,.x, 13 and 10 is 8, find range.
Answer:
Range = 9
Explanation:
From the question,
Mean = summation data/Total frequency
Mean = (6+7+x+13+10)/5
If the mean is 8,
8 = (36+x)/5
Solve for x
36+x = 8×5
36+x = 40
x = 40-36
x = 4.
Range is the difference between the biggest and the smallest value in a given distribution.
from the above,
Range = 13-4
Range = 9
8N--> 8N--> 3N--> 12N<--
Your math problem
8−−>8−−>3−−>12<−−
whats your question xD
if 332 waves passes through a medium in one second with the speed of 332m/s, then wavelength is?
Answer:
1 metresExplanation:
Using the formula
v = fλ
v is the speed
f is the frequency
λ is the wavelength
Given the following
v = 332m/s
Frequency is the number of oscillation completed in one second. Since 332 waves passes through a medium in one second, hence the frequency us 222 Hertz
From the formula
λ = v/f
λ = 332/332
λ = 1m
Hence the wavelength is 1m
why brittles of a paint brush spread when in water and cling when taken out of water
Answer:
surface tension
Explanation:
because of surface tension in water
When particles in a gas slow down, cool down and gather as a liquid, matter is:
A)freezing
B)sublimating
C)melting
D)condensing
experiment to show acceleration due to gravity
Explanation:
hope it is helpful to you
How much energy is stored in a spring with a spring constant of 250 N/m if the spring is compressed a distance of 0.46 m from its free length?
Group of answer choices
120 J
58 J
53 J
26 J
14000 J
Two students are doing an experiment. They mix 9 sugar cubes and 2 teaspoons of baking soda,
then heat it to make a long black tube of carbon. The sugar cubes have a mass of 2 grams each and
the teaspoon can hold 3 grams of baking soda. What is the total mass of the reactants in this
experiment?
Answer:
15 grams
Explanation:
9 sugar cubes + 2 teaspoons of baking soda + 2 grams of the sugar cubes each + 3 grams of baking soda = 15g.
The total mass of the reactants used is 24 grams.
What is reactant?A reactant is a substance that undergoes a chemical change or reaction with another substance in a chemical reaction. It is one of the starting materials that are transformed or converted into one or more new substances called products. Reactants are typically written on the left-hand side of a chemical equation, while the products are written on the right-hand side.
In some cases, reactants may be in different phases or states of matter, such as a solid, liquid, gas, or aqueous solution. The identification and measurement of the reactants involved in a chemical reaction are important in understanding the underlying chemistry and predicting the outcomes of the reaction.
Here In the Question,
The total mass of sugar cubes used is:
9 sugar cubes x 2 grams/sugar cube = 18 grams
The total mass of baking soda used is:
2 teaspoons x 3 grams/teaspoon = 6 grams
So, the total mass of the reactants (sugar cubes and baking soda) used in the experiment is:
18 grams + 6 grams = 24 grams.
Therefore, 24 grams are utilized as the total mass of the reactants.
To learn more about redox reaction click:
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1
Describe the kinetic energy of the pins at
the beginning of the video. Explain your
answer.
Answer:
I think a Kinetic energy of an object is the measure of the work an object can do by the virtue of its motion.”
Hope this help!:)
Three charged particles of charges 3 μC, -2 μC, and 4 μC are placed on the X-Y plane at (1 cm, 0), (2.5 cm, 0), and (1 cm, 2 cm) respectively. Determine the magnitude and direction of the force acting on a -2 μC charge.
Answer:
The total force is [tex]F_{tot}=4.29\: N[/tex]
The direction is [tex]\omega=32.43^{\circ}[/tex]
Explanation:
First, we need to find the angle with respect to the horizontal, of the force between q2 (-2 μC) and q3 (3 μC).
Let's use the tangent function.
[tex]tan(\alpha)=\frac{2}{1.5}[/tex]
[tex]\alpha=53.13^{\circ}[/tex]
Now, let's find the magnitude of the force F(12).
[tex]|F_{12}|=k\frac{q_{1}q_{2}}{d_{12}}[/tex]
Where:
k is the Coulomb constant (9*10⁹ NC²/m²)q1 is 3 μCq2 -2 μCd(12) is the distance between q1 and q2 ( 1.5 cm = 0.015 m)[tex]|F_{12}|=9*10^{9}\frac{3*10^{-6}*2*10^{-6}}{0.015}[/tex]
[tex]|F_{12}|=3.6\: N[/tex]
The magnitude of the force F(23) will be:
[tex]|F_{23}|=k\frac{q_{2}q_{3}}{d_{23}}[/tex]
The distance between these charges is:
[tex]d_{23}=\sqrt{1.5^{2}+2^{2}}[/tex]
[tex]d_{23}=2.5\: m[/tex]
[tex]|F_{23}|=9*10^{9}\frac{2*10^{-6}*4*10^{-6}}{0.025}[/tex]
[tex]|F_{23}|=2.88\: N[/tex]
So, we have the force F(12) in the second quadrant and F(23) in the second quadrant too but with 53.13 ° with respect to the horizontal.
We just need to add these two forces (vectors) and get the total force acting on q2.
Total force in x-direction:
[tex]F_{tot-x}=-F_{12}-F_{23}cos(53.13)[/tex]
[tex]F_{tot-x}=-3.6-2.88cos(53.13)[/tex]
[tex]F_{tot-x}=-5.33\: N[/tex]
Total force in y-direction:
[tex]F_{tot-y}=F_{23}sin(53.13)[/tex]
[tex]F_{tot-y}=2.88sin(53.13)[/tex]
[tex]F_{tot-y}=2.3\: N[/tex]
Therefore, the magnitude of the total force will be:
[tex]|F_{tot}|=\sqrt{(-3.62)^{2}+(2.3)^{2}}[/tex]
[tex]|F_{tot}|=4.29\: N[/tex]
and the direction is:
[tex]tan(\omega)=\frac{2.30}{3.62}[/tex]
[tex]\omega=32.43^{\circ}[/tex]
I hope it helps you!
PLZZZZ HELPPPPPP MEEEEEE!!!!!! ASAP!!! ILL GIVE 20 POINTS AND BRAINLIEST!!!
:'(
I am desperate guys.
This is my fourth time posting this plz help me
Answer:
B i believe
Explanation:
Which of these is emitted during beta decay ?
A) high-energy electromagnetic radiation
B) a small neutral particle
C) a small charged particle
D) a positively charged helium nucleus
Answer:
C. a small charged particle.
Explanation:
typically beta radiation emits an electron which is a small negativity charged particle.
hope it helps. :)
Answer:
A small charged particle.
Explanation:
what is the range of plane if the angle of the projective is 30° with a speed of √2g?
Answer:
The range is 17.32 m
Explanation:
From the question given above, the following data were obtained:
Angle of projection (θ) = 30°
Initial velocity (u) = √2g
Acceleration due to gravity (g) = 10 m/s²
Range (R) =?
The range can be obtained as follow:
R = u²Sine2θ /g
R = (√2g)²Sine 2θ / g
R = 2g² × Sine (2×30) / g
R = 2g × Sine 60
R = 2 × 10 × 0.8660
R = 17.32 m
Therefore, the range is 17.32 m
Two slits are illuminated with green light (λ = 540 nm). The slits are 0.05 mm apart and the distance to the screen is 1.5 m. At what distance (in mm) from the central maximum on the screen is the average intensity 50% of the intensity of the central maximum?
Answer:
0.21486 mm
Explanation:
The formula for the maximum intensity is given by;
I = I_o•cos²(Φ/2)
Now,we are not given Φ but it can be expressed in terms of what we are given as; Φ = πdy/(λL)
Where;
y is the distance from the central maximum
d is the distance between the slits
λ is the wavelength
L is the distance to the screen
Thus;
I = I_o•πdy/(λL)
We are given;
d = 0.05 mm = 0.5 × 10^(-3) m
λ = 540 nm = 540 × 10^(-9) m
L = 1.25 m
I/I_o = 50% = 0.5
From earlier, we saw that;
I = I_o•πdy/(λL)
We have I/I_o = 0.5
Thus;
I/I_o = πdy/(λL)
Plugging in the relevant values;
0.5 = (π × 0.5 × 10^(-3) × y)/(540 × 10^(-9) × 1.25)
Making y the subject, we have;
y = (0.5 × 540 × 10^(-9) × 1.25)/(π × 0.5 × 10^(-3))
y = 0.00021486 m
Converting to mm, we have;
y = 0.21486 mm
fuel was consumed at a certain rate of 0.05Kg\s in a rocket engine and ejected as a gas with a speed of4000m\s . Determine the thrust on the rocket
Answer:
Thrust = 200 N
Explanation:
The engine thrust can be found by using the following formula:
[tex]Thrust = mv[/tex]
where,
m = mass flow rate of the fuel = 0.05 kg/s
v = velocity of ejected gases = 4000 m/s
Therefore, using the given values in the equation, we get:
[tex]Thrust = (0.05\ kg/s)(4000\ m/s)[/tex]
Thrust = 200 N
what is the function of layer of air trapped under the hovercraft
Answer:b
Explanation:
The air trapped under the hovercraft is used to provide the lift force by creating a cushion of pressurised air under the hovercraft.
What is friction?Friction is a type of force that resists or prevents the relative motion of two physical objects when their surfaces come in contact.
The friction force prevents any two surfaces of objects from easily sliding over each other or slipping across one another. It depends upon the force applied to the object.
A hovercraft is machine used to uplift the heavy object by using the lift force of the air trapped under the hovercraftcraft used to provide the pressure that is utilised for the uplifting of the heavy bodies.
The layer of air trapped under the hovercraft provide the necessary cushion for the proper functioning of the hovercraft , the pressure of the trapped layer of air has slightly higher pressure than the atmospheric air.
Thus,the function of layer of air trapped under the hovercraft is to reduce the amount of friction when hovercraft provide movement and uplift object over rough surfaces.
Learn more about friction from here link given below
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2. If you are sitting on the passenger side of a car driving down the
highway, name a frame of reference that indicates you are NOT moving?
Answer:
The building are not getting farther and farther away, road signs, exits, other cars
Explanation:
Calculate the pressure exerted on the ground by a boy of a mass 60 kg if he stands on one foot.the area of the sole of his shoe is 150cm²
Answer:
40 Kpa
Explanation:
150 cm2 = 0.015 m2
[tex]p \: = \frac{mg}{ a} = 40000[/tex]
Which FITT component has to do with how hard you work during exercise?
A Intensity
B Type
C Frequency
D Time
Answer:
Intensity, 1. Option
Explanation:
brainliest?
The correct answer is intensity.
how to test the pH level of a soap?
Answer:
One of the most common is to use pH strips.
Explanation:
PLZZZZ HELPPPPPP MEEEEEE!!!!!! ASAP!!! ILL GIVE 20 POINTS AND BRAINLIEST!!!
:'(
Answer:
Option B is correct
Explanation:
Here the
Mass number of carbon is 11 and that of boron is 11. While the atomic number varies by a a unit 1 value.
Thus, on the right hand side, a particle with atomic number 1 and mass number 0 is released
Thus, option B is correct
Please help me!!!!! It's due soon!!!! NO LINK PLEASE!!!!!!
Answer:
The direction of partlcle movement is perpendicular to the direction of movement of energy of the wave.
An object with a 25 µC charge is 0.54 m away from a second charged object. They experience a force of 3250 N. What is the charge on the second object?
Your answer