A person standing on a hill throws a ball horizontally with a velocity of 12m / s The ball lands 10.1 m away from the hill. How tall is the hill? Assume no air resistance

A.3.5
B.6.9
C.0.84
D.0.42

The correct answer is option D.

Vertical wind shear changes in wind direction with horizontal distance.

Generally, atmospheric wind is referred to as vertical or horizontal wind shear. It is also called wind gradient.

Simply put, win shear is defined as the change in wind speed over a particular distance.

More specifically, vertical wind shear refers to the alter in wind speed along altitude while the horizontal change refers to the change in wind speed that occurs along lateral side or position of the atmosphere in a given altitude.

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The speed of the longitudinal wave is given or computed as 1.584 or approximately 1.6m/s.

A wave is a propagating dynamic disturbance of one or more variables in physics, mathematics, and related sciences. Periodic waves occur when values oscillate repeatedly about an equilibrium value at a certain frequency.

Longitudinal waves are those in which the medium's vibration is parallel to the wave's travel direction and the medium's displacement is parallel to the wave's propagation direction.

A longitudinal wave is an example of one. P-waves of ultrasonography from earthquakes

Compression, rarefaction, wavelength, amplitude, period, and frequency are all important characteristics of a longitudinal wave.

To estimate the above answer multiply wavelength and frequency to get the speed of a wave.

That is:

2.4 x 0.66

= 1.584

If the frequency is not given, one can divide 6 crests by 9.1 seconds to determine the frequency.

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The magnitude of the force from the ground on each front wheel is  2775N.

Let us call the force on the front axle  F   and the force on the rear axle  R.

We know that    

⇒  F + R= total weight of vehicle  =  1360 * 9.80 =   13328 Newtons

And using torques, you know that  force on the front axle * distance to the center of mass  =  force on the rear axle * distance to the center

of mass

or         F *1.78   =  R * (3.05 - 1.78)

 So

   1.4016F  =  R

Then.

F +  1.4016 F  =  13328

F =   5550 N       and     R = 13328 - 5550  =  7778N

So the force on each front tire is    5550 /2  =   2775N

And the force on each rear tire is    7778 /2  =   3889N

Force is a push or pulls upon an item because of the object's interaction with some other object. Pressure is a power that can exchange the motion of an object. A force can reason an object with mass to alternate its speed, i.e., to boost up. pressure also can be described intuitively as a push or a pull. A force has each significance and course, making it a vector amount.

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The minimum magnitude of the force f is 21 N needed to cause the movement of a 5 kg box pulled by a horizontal force.

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When plates commute in the exact direction it collides, and the plates move to other at convergent boundaries.

The lighter, dense, and much more elastic oceanic plate dips underneath the thicker, more stiff continental plate whenever a continental plate encounters a marine plate.

It's known as subduction. Deep ocean trenches, like the one that runs down South America's west coast, are created by subduction.

The continent's undercut rocks start to melt. On occasions, a chain of eruptions forms as the hot magma rises to the surface and travels through the continent.

Nearly 80% of earthquakes happen along convergent borders when plates are being pushed together.

Destruction, when two continental plates crashes, is just another kind of convergent boundary. The plates collapse and are propelled upward since neither is heavier compared to the other.

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The frictional force applied on the object if a horizontal force of 50N is applied on the object is 19.6 N

N = m g

N = Normal force

m = Mass

g = Acceleration dur to gravity

m = 10 kg

g = 9.8 m / s²

N = 10 * 9.8

N = 98 N

f = μ N

f = Frictional force

μ = Co-efficient of friction

For static friction,

μ = 0.4

f = 0.4 * 98

f = 39.2 N

For kinetic friction,

μ = 0.2

f = 0.2 * 98

f = 19.6 N

Since Applied force of 50 N is greater than the static frictional force of 39.2 N, the frictional force acting on the object is frictional force.

Therefore, the frictional force applied on the object is 19.6 N

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If a person is forced to utilize self-defense, the offensive techniques that should be recommended are as follows:

I would advise them to employ the following defense strategies:

Based on the films, the move(s) that appear to be the most successful for the offense in a circumstance requiring self-defense are to target the problem rather than the person.

An aggressive competitive strategy is a form of company strategy that involves actively pursuing industry changes.

Companies that go on the offensive typically make acquisitions and invest extensively in R&D and technology in order to remain ahead of the competition.

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Explanation

a) The velocity will never be zero. The velocity at the highest point of the projectile will be the smallest, equal to the horizontal component of the initial velocity.

b) The velocity will be zero when the kinetic energy is zero. When kinetic energy is at its lowest, potential energy is at its highest. Because potential energy is greatest at the highest point, velocity is greatest at the highest point.

c) Because a constant force of gravity acts on the projectile at all times, velocity will never be the same as initial velocity.

d) When the bullet bounces back and strikes the ground, the speed equals the initial speed (at t = 0), because the height is zero and the kinetic energy is equal to the initial energy.

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The motor is an excellent invention for Allison to use as a model for her device.

People use both interchangeably, but the difference is that motors run on electricity and engines run on combustion. The engine converts various forms of fuels into mechanical force, while the motor transforms electrical energy into mechanical energy.

They operate using principles of electromagnetism, which shows that a force is applied when an electric current is present in a magnetic field. This force creates a torque on a loop of wire present in the magnetic field, which causes the motor to spin and perform useful work.

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The net force required to move the object of mass 15 kg and constant velocity is 0N

The mass of the object = 15 kg

The object is moving with a constant velocity = 3 m/s.

The net force required to move the object  can be calculated by using the formula,

                F = ma

where F is the force

          m is the mass

          a is the acceleration.

The acceleration is nothing but a rate of change of velocity (i.e. a = v/t). But for a constant velocity, the acceleration will be zero. Because there will be no change in velocity.

Therefore, the net force is

                      F = 15 x 0

                         = 0 N

Therefore, the net force is 0 N

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A proton and electron separated by 1.0 x 10-10 meters exert 1.0 x 10-47N of gravitational force on each other.

The gravitational force will bring together any two mass-containing objects. The gravitational force is described as attracting because it consistently tries to draw masses together and never tries to push them apart. In reality, you and every other item in the universe are pulling toward one another.

What is the origin of gravity?

All of the mass on Earth is what creates gravity. The cumulative gravitational attraction of all of its mass exerts pressure on all of the body's mass. Your weight is determined by that. Furthermore, your weight would be lower if you were on a planet with a lower mass than Earth.

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The best suitable answer is Option 4 " The driver experienced centrifugal "force" which was actually just his inertia .

What is centrifugal force ?

A hypothetical force called centrifugal force, which is unique to particles travelling in a circle, is a force that has the same strength and dimensions as the centripetal force, but acts in the opposite direction.

A stone rotating in a horizontal plane while attached to a string that is fastened to a ground-based post experiences a constant change in velocity and acceleration in the direction of the post. The square of the speed divided by the length of the string gives us the acceleration.

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The final speed of the car and minivan is 17.95 m/s

The mass of the car = 950 kg

The speed of the car = 22 m/s

The mass of the minivan = 1300 kg

The speed of the minivan = 15 m/s

The final speed of the car and minivan can be found using the conservation of momentum formula,

                 [tex]\displaystyle m_{1}v_{i1 } + m_{2}v_{i2} = m_{1}v_{f1} + m_{2}v_{f2}[/tex]

where [tex]\dispplaystyle m_{1}[/tex] is the mass of the car

           [tex]\dispplaystyle m_{2}[/tex] is the mass of the minivan

           [tex]\dispplaystyle v_{i1}[/tex] and [tex]\dispplaystyle v_{i2}[/tex] is the initial speed of the car and minivan respectively.

          [tex]\dispplaystyle v_{f1}[/tex] and [tex]\dispplaystyle v_{f2}[/tex] is the final speed of the car and minivan respectively.

As the two cars move together, they would have the same final speed, i.e.

                    [tex]\dispplaystyle v_{f1} = \dispplaystyle v_{f2} = \dispplaystyle v_{f}[/tex]

Thus, the above equation becomes,

                      [tex]\displaystyle m_{1}v_{i1 } + m_{2}v_{i2} = (m_{1} + m_{2})v_{f}[/tex]

Let us substitute the known values in the above equation, we get

                       (950 x 22) + (1300 x 15) = (950 + 1300) [tex]\displaystyle v_{f}[/tex]

                                  20,900 + 19.500 = 2,250 [tex]\displaystyle v_{f}[/tex]

                                                  40,400 = 2,250[tex]\displaystyle v_{f}[/tex]

                                     40,400 / 2,250 = [tex]\displaystyle v_{f}[/tex]

                                                               = 17.95 m/s

Therefore, the final speed is 17.95 m/s

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A block of mass 0.260 kg is placed on top of a light, vertical spring of force constant 5 025 n/m and pushed downward. After the block is released, the spring will travel upward to the maximum height of 10.86 meters.

The relation between the potential energy on a string and the length it stretches is given by:

E = 1/2 . kx²

Where:

k  = spring constant

x = spring stretch or compression

In the given problem:

k = 5,025 N/m

x = 0.106 m

Hence,

E = 1/2 . 5025 . (0.106)²

m . g . h =  1/2 . 5025 . (0.106)²

Where;

m = mass

h = height from the release point.

Hence,

0.260 x 10 x h = 28.23

h = 10.86 m

Therefore, the spring will travel upwards up to 10.86 m

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What Fiona did, so her friend could find the stars was to give her friends knowledge about the contents of the sky, such as the shape of planets and stars. Then when you want to see the stars, you have to stay away from light pollution, so the stars can be seen clearly.

Stars are celestial bodies that emit light caused by nuclear fusion reactions that produce energy that occurs in their cores. It should be noted that 'pseudo stars' are not stars, but planets that reflect light from other stars and appear to glow in the sky like a star. A planet or planetary star is an astronomical body orbiting a star or stellar remnant that is massive enough to have its own gravity.

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The work done by the constant force to pulled the elevator upward is 275000 Joules.

The work done by any force is given by,

W = Fa

Where,

W is the work done,

F is the force applied,

s is the displacement along the direction of the force,

The force applied on the elevator to pull it upward is 5500N and the distance to which the elevator is pulled is 50 m.

Now, putting values,

W = 5500(50)

W = 275000 Joules.

So, the work done by the force to pull the elevator upward is 275000 Joules.

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When the proton starts to move upward the direction of the magnetic force changes and when the proton moves straight up the magnetic force turns to the left.

The direction of the force is perpendicular to the direction of the magnetic field and current, as given by Fleming's left-hand rule. Here the magnetic field is to the right and the direction of the current is upward. Protons feel a force on themselves due to the magnetic field. The force on the proton is proportional to the proton's magnetic flux density and velocity.

The velocity and momentum of a proton are affected by the force acting on it. If the velocity of a charged particle is perfectly parallel to the magnetic field, the magnetic field exerts no force on the particle, so the velocity remains constant. The momentum of a proton moving freely in a magnetic field is the product of the proton's mass and the proton's velocity. As the speed of a proton moving in a magnetic field changes, so does the momentum of the proton.

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The speed limit for a curved stretch of road with the coefficient of friction between the wheels and the road is 0.7 when the road is dry and 0.3 when the road is wet is √ 2.94 r m / s

Fc = m ac

Ff = μ N

N = m g

Fc = Centripetal force

m = Mass

ac = Centripetal acceleration

Ff = Frictional force

μ = Co-efficient of friction

N = Normal force

μ = 0.3 ( Wet value to taken to provide zero skidding under any condition)

g = 9.8 m / s²

The only force that is providing the centripetal force is frictional force.

m ac = μ m g

ac = 0.3 * 9.8

ac = 2.94 m / s²

ac = v² / r

2.94 = v² / r

v = √ 2.94 r m / s

Therefore, the speed limit for the curved stretch of road is √ 2.94 r m / s. She should perform her calculations with the coefficient of friction for wet pavement.

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The work done by the tension in the string on the ball - tension does no work at all is the correct answer.

The forces tugging on the rope from either end cause the tension in a particular strand of string or rope. Keep in mind that force is defined as mass times acceleration. If the rope is stretched tightly, any change in the mass or acceleration of the objects it is supporting will result in a change in the tension of the rope.

A force known as tension is particularly effective on medium-length materials like rope and cable that are also flexible. A gravitational force still exists in tension. When the body is traveling upward, the tension is denoted by the formula T = W + ma. The thickness is the same as T = W - ma when the body descends.

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The Method of Interaction It's a cooperative method for more effective teamwork.

A combination of hardware and software components that enables computer users to carry out a single job is known as an interaction technique, user interface technique, or input technique.

Four fundamental interaction tasks exist: position, text, select, and quantify. These can be carried out using a variety of hardware and software tools, each of which has been given a category based on its capabilities and qualities.

An interaction occurs when two or more factors have an impact on one another. If one investigates each of their effects independently, they may not have as strong an impact on a result as they might if they occur simultaneously and interact. Caffeine and painkillers are an example of such interaction.

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The variational technique is one strategy to approximate the ground state with the lowest energy and some stimulated states in quantum mechanics.

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anticlockwise = clockwise (Force*distance)

1 * 20 = 2 * x

x = 10

The amount of work done by friction in stopping the car is given as

Wx > Wy.

There are two cars moving with the same velocity

car X is more massive than car Y

mass of car X = Mx

mass of car Y = My

here given,  Mx >  My

The distance travelled will be the same as the initial velocity, and it is independent of mass.

Let, μ be the coefficient of kinetic friction

work done by the frictional force is given as:

F = μMg

Fx = μMxg

Fy = μMyg

W = F.s

Wx = μMxg.s

Wy = μMyg.s

Wx > Wy

The amount of work done by friction in stopping the car is given as

Wx > Wy.  

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The intensity of the sound at a distance of 0.40 m from the source is 0,398 W/m²

Sound waves are classified as a longitudinal wave where the direction of propagation is parallel to the direction of vibration.

Sound intensity is formulated as follows:

I = P / A

I = Sound Intensity (W/m²)

P = Power of the Sound Source (W)

A = Area of the field through which the sound wave passes (m²)

Since the sound wave propagates in all directions, the area of the field traversed by this sound wave will form the surface area of the sphere, then:

I = P / (4πR²)

R = Surface radius (m)

So, The intensity of the sound at a distance of 0.40 m from the source is:

I = P / A

I = P / ( 4π . R² )

I = 0,80 / ( 4π . (0,4)²)

I = 0,398 W/m²

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An inelastic collision between two objects is characterized by the fact that a) the total momentum of the system is conserved. Choice A is correct

Inelastic collisions are the collisions in which the kinetic energy is lost. The momentum of the system is conserved in inelastic collisions, but kinetic energy is not. This is because some of the kinetic energy was transferred to another.

Suppose two similar cars are approaching. They collide, but the sled is equipped with a magnetic clutch so that when they collide they combine into a single agglomerate. This type of collision is completely inelastic as the maximum possible kinetic energy is lost. This does not mean that the final kinetic energy of the system is necessarily zero. Momentum is not yet maintained.

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The tension in the tow rope that is pulling the skier is 5283.33 N

since we are given the  average power of 2.74 × 10^4 W., with a speed of 12 m/s. So, the tension acting on the motor at this point is :

P= T X v

T = P/v =2.74 × 10^4/ 12 =2283.33 N

For the  second case, the average  power is 9.20 × 10^4 W, so the tension  will be  :T = P/v = 9.20 × 10^4 /12 =  7666.66

so the tension in the tow rope is :  7666.66 -2283.33 =  5283.33 N

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the motor of a ski boat generates an average power of 2.74 × 10^4 W when the boat is moving at a constant speed of 12 m/s . when the boat is pulling a skier at the same speed, the engine must generate an average power of 9.20 × 10^4 W. what is the tension in the tow rope that is pulling the skier?

The net force on both the cars car a and car B will be zero.

According to the first law of motion stated by Newton,

An object would continuously written it's state of motion or rest if the net force on the object is zero. It means that, no matter how many forces are working on the body if they all cancel out each other and the net force becomes zero the body will continue it's same state.

Also according to second law of Newton,

The force is rate of change of momentum with respect to time.

F = ma

Here, both the cars the car A of mass 500 kg and the car B of mass 800 kg are moving with a constant velocity of 20 m/s and 15 m/s respectively.

If the velocity of the car is not changing with time it means that there is no acceleration on the body.

If there is no acceleration on the body, then there is no net force on the body.

So, we can conclude hair that the net force on the cards is zero.

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When approaching the root of an equation, the Newton-Raphson method will quickly converge. this is a false.

" Root is a mathematical symbol that stands for the square root symbol or square root sign. In words, we call this symbol radical. The various types of symbols that are used to carry out arithmetic operations may have been covered in your math classes. In mathematics, the square root of any number is denoted by the root symbol.

As an illustration, 2 is used to symbolize the square root of 2. Similarly, for other natural numbers like 5, 6, 7, 8, 10, etc., we can write their corresponding square roots as 5, 6, 7, 8, and 10, respectively. The square root that is positive is always represented by this symbol.

Radicand: The number that appears beneath the root is referred to as the radicand, not the square root symbol.

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The parallel component of the total weight is 320 N.

The perpendicular component of the total weight is 554.3 N.

The components of the total weight of the builder and new roof tiles can be parallel component or perpendicular component.

The parallel component of the total weight of the builder and new roof tiles is calculated as follows;

Fn ( parallel ) =  W sin ( θ )

where;

Fn ( parallel ) =  W sin ( θ )

Fn ( parallel ) =  640 sin ( 30 )

Fn ( parallel ) = 320 N

The perpendicular component of the total weight of the builder and new roof tiles is calculated as follows;

Fn ( parallel ) =  W cos ( θ )

where;

Fn ( perpendicular ) =  W cos ( θ )

Fn ( perpendicular ) =  640 cos ( 30 )

Fn ( perpendicular ) = 554.3 N

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