Answer:
7m/s²
Explanation:
Given parameters:
Velocity at the top = 1m/s
Velocity at the bottom = 36m/s
Time = 5s
Unknown:
Average acceleration = ?
Solution;
Acceleration is the rate of change of velocity with time. It is expressed as;
A = [tex]\frac{v -u}{t}[/tex]
v is the velocity at the top
u is the velocity at the bottom
t is the time taken
Now, insert the parameters and solve;
A = [tex]\frac{36 - 1}{5}[/tex] = 7m/s²
Given values:
Top velocity,
v = 1 m/sBottom velocity,
u = 36 m/sTime,
t = 5 sThe acceleration is:
→ [tex]A = \frac{v -u}{t}[/tex]
By putting the values,
[tex]= \frac{36-1}{5}[/tex]
[tex]= \frac{35}{5}[/tex]
[tex]= 7 \ m/s^2[/tex]
Thus the answer above i.e., "option d" is correct.
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You throw an orange out a window at a height of 12.00 meters
upwards at an angle of 32° to the horizontal at a velocity of 3.5
m/s. What is the maximum height that the orange will reach?
Answer:
12.18
Explanation:
The maximum height that the orange will reach is 12.18 m.
What is projectile?When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion.
You throw an orange out a window at a height of 12.00 meters upwards at an angle of 32° to the horizontal at a velocity of 3.5 m/s.
If u is the initial speed, the maximum height of the ball from the point of throwing is
H = u² sin²θ / 2g
Put the values, we get
H = 3.5² sin²32° / (2x9.81)
H = 0.1753 m
So, the maximum height calculated from the ground is
12 + 0.18 = 12.18 m
Thus ,the maximum height that the orange will reach is 12.18 m.
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A man carries a load of mass 2.6kg from one end of a uniform pole 100cm long which has a mass 0.4kg. The pole rest on his shoulder at a point 60.0cm from the load and he holds it by the other end. What vertical force must be applied by his hand and what is the force on his shoulder?
Answer:
F = 39.2 N (hand force) and N = 68.6 N (shoulder force)
Explanation:
In this exercise we must use the rotational and translational equilibrium conditions, we have several forces: the weight (W) of the pole applied at its geometric center, the load (w1) at one end, the shoulder support (N) 60 cm from the load and hand force (F) at the other end of the pole
Let's set the reference system at the fit point of the shoulder
∑ τ = 0
We will assume that the counterclockwise turns are positive
w₁ 0.60 + W 0.1 + F₁ 0 - F 0.4 = 0
all distances are measured from the support of the man (x₀ = 0.60 m)
F = (w₁ 0.60 + W 0.1) / 0.4
F = (m₁ 0.6 + m 0.1) g / 0.4
let's calculate
F = (2.6 0.6 + 0.4 0.1) 9.8 / 0.4
F = 39.2 N
this is the force that the hand must exert to keep the system in balance
We apply the translational equilibrium condition
-w₁ -W + N - F = 0
N = w₁ + W + F
N = (m₁ + m) g + F
let's calculate
N = (2.6 + 0.4) 9.8 + 39.2
N = 68.6 N
If a chicken has a weight of 300 N on Earth, what would be its weight on Mercury if the gravity is 0.38.
Answer:
114N
Explanation:
gravity on earth: 10m/s (exact: 9.82)
mass if chicken = 300/10 = 30Kg
weight of chicken on mercury = 3.8 x 30 = 114N (you wrote 0.38 but Mercury's gravity is about 3.7)
Answer:
113.15 g
Explanation:
That's because the planets weigh different amounts, and therefore the force of gravity is different from planet to planet. For example, if you weigh 100 pounds on Earth, you would weigh only 38 pounds on Mercury. That's because Mercury weighs less than Earth, and therefore its gravity would pull less on your body.
pls help me with this question pls
Explanation:
pls help me with this question pls
A roller coaster is stopped on a track. When the engineer presses a launch button on the coaster, the coaster moves forward. Explain this change in terms of balanced and unbalanced forces.
I need help on this question
Answer:
at rest because time is passing and speed is still at 0
Explanation:
can u plz help
Define: Medium
Answer:
Medium: something in a middle position, maybe in between sizes big or small, or in a situation it's not negative or positive it's just neutral. (I'm sorry if that wasn't helpful)
Explanation:
is it true that scientific theories and scientific laws both describe observed events??? provide evidence!!!!! only 2 people could answer so if you can't then comment and provide evidence thank you very much!!!!!!
Answer:
I'm not positive but I think the answer is Yes, because both scientific laws and theories are based on evidence.
Explanation:
Sorry I don't have notes on this, hope this helps! :)
A man drops a penny V=0 off the top of the Golden Gate Bridge how fast will the penny be moving when it hits the ground? The golden hat bridge is 275 meters tall
Answer:
Vf = 73.4 m/s
Explanation:
This is the case of vertical motion where we have to find the final velocity of the penny when it hits the ground. We can use 3rd equation of motion to find the final velocity:
2gh = Vf² - Vi²
where,
g = 9.8 m/s²
h = height = 275 m
Vf = Final Velocity = ?
Vi = Initial Velocity = 0 m/s
Therefore,
2(9.8 m/s²)(275 m) = Vf² - (0 m/s)²
Vf = √5390 m²/s²
Vf = 73.4 m/s
The speed with penny dropped from the Golden Gate Bridge hits the ground is 73.4m/s.
Given the data in the question;
Since the penny was at rest before it was dropped
Initial velocity; [tex]u = 0[/tex]Height or distance of the golden hat bridge; [tex]s = 275m[/tex]Final velocity; [tex]v = \ ?[/tex]
To determine the speed with which the penny hits the ground, we use the Third Equation of Motion:
[tex]v^2 = u^2 + 2as[/tex]
Where v is the final velocity, u is the initial velocity, s is the height of the bridge and a is acceleration due to gravity ( since its under gravity; [tex]a = g = 9.8m/s^2[/tex] )
We substitute our values into the equation
[tex]v^2 = 0 + [ 2\ *\ 9.8m/s^2\ *\ 275m]\\\\v^2 = 5390m^2/s^2\\\\v = \sqrt{5390m^2/s^2}\\\\v = 73.4 m/s[/tex]
Therefore, the speed with penny dropped from the Golden Gate Bridge hits the ground is 73.4m/s.
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Charlie's father built a tree house in their backyard. He constructed a spiral staircase around the tree trunk and installed a ladder. Which will involve more work in climbing up the tree house from the ground?
Answer:
The spiral staircase will require more work
Explanation:
This is because, work can be calculated as force (which is mass of the individual climbing the stairs in this case) multiplied by distance (or length) of the stairs. The only variable that changes in the work done while climbing any of the two (ladder or spiral staircase) is the distance and it is obvious the length of the spiral staircase will be longer; thus the spiral staircase will involve more work.
Disponemos de datos de presión y volumen de tres situaciones de un gas ideal que se han medido manteniendo la temperatura del gas constante representa los valores de un gráfico p-v expresa matemáticamente la ley de Boyle-Mariotte y calcula el valor de la constante
Answer:
Explanation:
This is an exercise in thermodynamics, the ideal gas equation is
PV = n R T
In this case the temperature is constant, so
n R T = cte
throughout the experiment
We can write the relationship for the three points 1, 2 and 3
P₁ V₁ = P₂ V₂ = P₃ V₃ = cte
In the attached graph we can see a graph of this relationship
the data for this graph are
V(m³) P ( Pa)
V₀ P₀
V₀/2 2 P₀
V₀/4 4 P₀
for the graph, let it be assumed that V₀ = 1 and P₀ = 1
To calculate the value of the constant s, you must know the moles of gas and the temperature at which the experiment is carried out, for example, if we have a mole of gas and room temperature (T = 300K), the constant is
n R T = 1 8,314 300
n R T = 2492.2 J
An object O is acted upon by a 6 N force and a 5 N force. The angle between these two forces is 60°. Draw a scale diagram showing the forces acting on object O and determine the resultant force.
Answer:
Resultant force = [tex]\sqrt{91}[/tex]N
Explanation:
Rf = [tex]\sqrt{f1²+f2²+2.f1.f2.cos60}[/tex]
Rf = [tex]\sqrt{6²+5²+2.6.5.1/2}[/tex]
Rf = [tex]\sqrt{36+25+30}[/tex]
Rf = [tex]\sqrt{91}[/tex]
doesn't look right though...
The magnitude of resultant force is 9.54 N and it is acting an angle 33° with the direction of 5 N force.
What is force?An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.
The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.
Given parameters:
Two forces are 6 N and 5N.
Angle between them is 60 degree.
So, magnitude of resultant force be = √(6² + 5² + 2× 6 × 5 × cos60°) N = = 9.54 N.
Angle of the resultant force with respect to 5 N is = tan⁻¹{6sin60°/(5 +6 cos60°) } = 33⁰.
Hence, magnitude of resultant force is 9.54 N and it is acting an angle 33° with the direction of 5 N force.
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A bar magnet is a permanent magnet, While an electromagnetic temperary?
yes an electromagnetic is temporary
According to the Declaration of Independence, all people are created in what manner?
Answer:
All men are created equal.
Explanation:
We hold these truths to be self-evident, that all men are created equal, that they are endowed by their Creator with certain unalienable Rights, that among these are Life, Liberty and the pursuit of Happiness.
-Declaration of Independence
If the velocity of an object is zero, then that object cannot be accelerating. | True or False
Answer: False
Explanation:
A horse gallops for 3.5 minutes around the raceing track. During this time it changes velocity from 543 min to 628 min. Calculate the acceleration of the horse during this 3.5min interval
Answer:
The acceleration of the horse during this time interval is 24.286 m/min²
Explanation:
Given;
initial velocity of the horse during the gallop, u = 543 m /min
final velocity of the horse during the gallop, v = 628 m /min
time of motion, t = 3.5 minutes
The acceleration of the horse is given by the change in velocity per change in time;
[tex]a = \frac{v-u}{t}\\\\a = \frac{628-543}{3.5}\\\\a = 24.286 \ m/min^2[/tex]
Therefore, the acceleration of the horse during this time interval is 24.286 m/min²
Please help with this!
On the way down the ball's velocity is Positive 9.8.
Option A) is the correct answer.
What is velocity:?
This refers to the speed at which an object moves in a given direction. It unit is meters per secocond, m/s.
What is acceleration?
This is the rate of change of velocity with respect to time. The speed and direction of the accelerating object are also very important. It unit is meters per second square, m/s².
What is Gravity?
This is the force that pulls a body toward the center of the earth. This force causes objects to fall freely. This free-falling object has an acceleration of 9.8m/s downward the earth. This is called acceleration gravity.
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A weight lifter is trying to lift a 1,500 N weight but can apply a force of only 1,200 N on the weight. One of his friends helps him lift it at a constant velocity. What force was applied to the rope
Answer:
400N is applied to the rope
Answer:
300N
Explanation:
Assuming his friend didn't throw the box, they would need a total of 1,500N to lift it, if the first person is already applying 1,200N, the only other amount of force needed is 300N to make a total of 1,500N! Simple math problem :)
Hope this helps! <3
Which of the following is a FALSE statement? (A) Heat moves through solids by conduction (B) Molecules move faster in warmer substances (C) Warm water is denser than cold water (D) Heat moves through liquids and gases by convection
Answer:
C.
Explanation:
The English Channel is 35 km wide at its narrowest point, which is where most swimmers attempt to cross north to south from England to France. The current across this portion of the English Channel runs at about 2 km/h east to west.
a. If a swimmer has a relative velocity to the shore of 3 km/h north to south, how long will it take her to cross the 35 km distance?
b. What must be her velocity relative to the water if she has a velocity of 3 km/h north to south relative to the shore?
Answer:
a.) 20.4 h
b.) 3.46 km/h
Explanation:
Given that an English Channel is 35 km wide at its narrowest point, which is where most swimmers attempt to cross north to south from England to France. The current across this portion of the English Channel runs at about 2 km/h east to west.
a.) If a swimmer has a relative velocity to the shore of 3 km/h north to south, The resultant velocity (Vr) will be achieved by using Pythagoras theorem
Vr = [tex]\sqrt{2^{2} + 3^{2} }[/tex]
Vr = [tex]\sqrt{4 + 9}[/tex]
Vr = [tex]\sqrt{12}[/tex]
Vr = 3.46 m/s
To get how long it take her to cross the 35 km distance, Let us first find acceleration by using third equation of motion.
[tex]V^{2} = U^{2} + 2aS[/tex]
Where U = 0
Substitute all the parameters into the equation
[tex]3.46^{2} = 2 x a x 35[/tex]
11.97 = 70a
a = 11.97/70
a = 0.17 km/h^2
The time can be found by using equation
V = U + at
let U = 0
3.46 = 0.17t
t = 3.46/0.17
t = 20.35h
b. What must be her velocity relative to the water if she has a velocity of 3 km/h north to south relative to the shore?
her velocity relative to the water will be
Vr = [tex]\sqrt{2^{2} + 3^{2} }[/tex]
Vr = [tex]\sqrt{4 + 9}[/tex]
Vr = [tex]\sqrt{12}[/tex]
Vr = 3.46 m/s
If you committed a crime, would it be easy for investigators to match this print to your records? Why or why not? Hint: how’s the quality of the lifted print? How rare is your pattern? (At least two sentences)
Answer:
This question is incomplete
Explanation:
This question is incomplete because of the absence of the picture of the print in question. However, when the quality of the print obtained from a crime scene is high/good, then this is a good/positive step in identification of a suspect. However, if the quality is bad, other options might need to be explored in addendum to the print obtained in identifying a suspect.
If the quality of the print is good enough to make a pattern, then another factor comes into play. If the pattern is a rare pattern or is not common, then it becomes easier to identify the suspect because there would be fewer people having that fingerprint and fewer people to deal with. Of the three major patterns of fingerprints (whorl, loop and arch), arch fingerprints are the least common.
W1 has a weight of 220 N acting 0.6m away from the pivot.
How far does W2 whose weight is 180 N need to sit for the see
saw to be in equilibrium.
&
?
W-220 N
W2 - 180N
a) 0.3 m
Ob) 0.73 m
C) 0.5m
O d) 0.83 m
Answer:
0.73m
Explanation:
Given parameters:
W1 = 220N
D1 = 0.6m
W2 = 180N
Unknown
D2 = ?
Solution:
The torque on each side must be balanced;
Torque = force x distance
T₁ = T₂
W1 x D1 = W2 x D2
Insert the parameters and solve for D2;
220 x 0.6 = 180 x D2
132 = 180D2
D2 = [tex]\frac{132}{180}[/tex] = 0.73m
What is the net force on a bathroom scale when a 110 pound person stands on it? How do you know?
Two students are measuring the Gravitational Attraction between each other. One student weighs 120 kg. The other student weighs 108 kg. Calculate the gravitational pull they have on each other.
Answer:
[tex]F=8.64\times 10^{-9}\ N[/tex]
Explanation:
Given that,
Mass of student 1, m₁ = 120 kg
Mass of student 2, m₂ = 108 kg
Let they are at a distance of 10 m.
We need to find the gravitational pull they have on each other. The gravitational force acting between two objects is given by :
[tex]F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{120\times 108}{(10)^2}\\\\=8.64\times 10^{-9}\ N[/tex]
So, the gravitational pull between students is [tex]8.64\times 10^{-9}\ N[/tex].
If a car manufacturer reduced the mass of a new car model, so that it took a force of 4000 N
to accelerate towards the barrier at 4 m/s2, what would be the mass of
the new car?
Answer:
1000 kg
Explanation:
Force = mass x acceleration, Hence, mass = Force/acceleration
mass = 4000/4 = 1000 kg
Parker (73.2 kg) is being dragged down the hall with an applied force of 123 N. If the frictional force is 27.4 N, what is the coefficient of friction in the hall?
Answer:
The coefficient of friction in the hall is 0.038
Explanation:
Given;
mass of the Parker, m = 73.2 kg
applied force on the parker, F = 123 N
frictional force, Fs = 27.4 N
the coefficient of friction in the hall = ?
frictional force is given by;
Fs = μN
Where;
μ is the coefficient of friction
N is normal reaction = mg
Fs = μmg
μ = Fs / mg
μ = (27.4) / (73.2 x 9.8)
μ = 0.038
Therefore, the coefficient of friction in the hall is 0.038
You are helping your friend move a new refrigerator into his kitchen. You apply a horizontal force of 280 N in the positive x direction to try and move the 63 kg refrigerator. The coefficient of static friction is 0.55.
Complete Question
You are helping your friend move a new refrigerator into his kitchen. You apply a horizontal force of 280 N in the positive x direction to try and move the 63 kg refrigerator. The coefficient of static friction is 0.55.
(a) How much static frictional force does the floor exert on the refrigerator? Give both magnitude and direction.
magnitude N
direction
(b) What maximum force do you need to apply before the refrigerator starts to move?
Answer:
a
The magnitude is [tex]F_f = 339.57 \ N[/tex]
The direction is [negative x - axis ]
b
The maximum force to be applied for the refrigerator to start moving is
[tex]F_{max} = 339.57 \ N[/tex]
Explanation:
From the question we are told that
The horizontal force applied is [tex]F_a = 280 \ N[/tex] the direction is +ve x-axis
The mass of the refrigerator is [tex]m = 63 \ kg[/tex]
The coefficient of static friction is [tex]\mu_s = 0.55[/tex]
Generally the frictional force exerted on the refrigerator is mathematically represented as
[tex]F_f = \mu * m * g[/tex]
=> [tex]F_f = 0.55 * 63 * 9.8[/tex]
=> [tex]F_f = 339.57 \ N[/tex]
From the value obtained we see that the static force exerted by the floor on the refrigerator is greater than the force (280 N ) exerted by the person and the direction is -ve x-axis
Generally the maximum force that is to be applied by the person is mathematically equal to the force exerted by the floor on the refrigerator but the direction is in the positive x-axis i.e
[tex]F_{max} = F_f = 339.57 \ N[/tex]
Where would you find the photosphere
What allows us to categorize rocks into the three rock types: Igneous, Sedimentary, and Metamorphic?
Whether or not the rock melts
Involvement of sediment
Process of formation
O Magma or weathering.
Answer:process of formation
Explanation:
If Chris throws the baseball 60 meters forward in 4.2 sec, what is the velocity of the ball? I need answer immediately
Answer:
14.3 m/s
Explanation:
velocity equation
v= d/t
v= 60/4.2
v=14.28
round it to 1 decimal place
v= 14.3m/s