Answer:
One atom of that element like helium neon and other Noble gases
Explanation:
Answer:
Please make sure to re-write this on your own so your teacher doesn't think you cheating!Explanation:
The number of protons in the nucleus of an atom determines an element's atomic number. In other words, each element has a unique number that identifies how many protons are in one atom of that element. An example is all hydrogen atoms, and only hydrogen atoms, contain one proton and have an atomic number of 1.
Xenon tetrafluoride has two sets of lone pairs of electrons. What should be the relative positions of the two sets of lone pairs?Why?
Answer: Two equatorial positions so as to minimize the repulsion.
Explanation:
Formula used for calculating number of electrons :
[tex]\frac{1}{2}[V+N-C+A][/tex]
where,
V = number of valence electrons present in central atom = 8
N = number of monovalent atoms bonded to central atom = 4
C = charge of cation = 0
A = charge of anion = 0
Now we have to determine the hybridization of the [tex]XeF_4[/tex] molecule.
[tex]\frac{1}{2}[8+4-0+0]=6[/tex]
Bond pair electrons = 4
Lone pair electrons = 2
The number of electrons are 6 that means the hybridization will be [tex]sp^3d^2[/tex] and the electronic geometry of the molecule will be octahedral.
The molecular geometry will be square planar as two alternate positio ns will be occupied by lone pair of electrons so as to minimize the repulsion.
Using the van der waals equation, the pressure in a 22.4 L vessel containing 1.50 mol of chlorine gas at 0.00 c is____________atm. (a= 6.49L^2-atm/mol^2, b=0.0562 L/mol)
A. 1.50
b. 0.676
c. 0.993
d. 1.48
e. 1.91
Answer:
D. 1.48atm
Explanation:
Van der waals equation is given as:
(P +an²/v²) (v - nb) = nRT
Where;
P = pressure (atm)
V = volume (L)
R = gas constant (0.0821 Latm/molK)
a and b = gas constant specific to each gas
T = temperature (K)
n = number of moles
According to the given information; V = 22.4L, T = 0.00°C (273.15K), R = 0.0821 Latm/molK, a = 6.49L^2-atm/mol^2, b = 0.0562 L/mol, n = 1.5mol
Hence;
(P + 6.49 × 1.5²/22.4²) (22.4 - 1.5×0.0562) = 1.5 × 0.0821 × 273.15
(P + 6.49 × 2.25/501.76) (22.4 - 0.0843) = 33.638
(P + 0.0291) (22.316) = 33.638
22.316P + 0.649 = 33.638
22.316P = 33.638 - 0.649
22.316P = 32.989
P = 32.989/22.316
P = 1.478
P = 1.48atm