Answer: the acceleration of the truck a_t is 0.6911 m/s²
Explanation:
Given the data in the question;
There is no external force on the system; net force on the system is 0
Mass of the truck with the woman M = 1767 kg + 41 kg = 1808 kg
mass of the car m = 833 kg
car acceleration a_c = 1.5 m/s²
now let a_t be the acceleration of the truck in opposite direction
Action force on the car = Reaction force on the car
ma_c = Ma_t
a_t = ma_c / M
we substitute
a_t = (833 × 1.5) / 1808
a_t = 1249.5 / 1808
a_t = 0.6911 m/s²
Therefore, the acceleration of the truck a_t is 0.6911 m/s²
Allen and Jason are chucking a speaker around. On one particular throw, Allen throws the speaker, which is playing a pure tone of frequency f, at a speed of 10 m/s directly towards Jason, but his aim is a bit off. As a result, Jason runs forward towards the speaker at a speed of 6 m/s before catching it. Then, the frequency that Jason hears while running can be written as (m/n)f Hz, where m and n are relatively prime positive integers. Compute m n.
Answer:
Explanation:
We shall apply Doppler's effect of sound .
speaker is the source , Jason is the observer . Source is moving at 10 m /s , observer is moving at 6 m/s .
apparent frequency = [tex]f_o\times\frac{V+v_o}{ V-v_s}[/tex]
V is velocity of sound , v₀ is velocity of observer and v_s is velocity of source and f_o is real frequency of source .
Here V = 340 m/s , v₀ is 6 m/s , v_s is 10 m/s . f_o = f
apparent frequency = [tex]f\times \frac{340+6}{340-10}[/tex]
= [tex]f\times \frac{346}{330}[/tex]
So m = 346 , n = 330 .