If -xy – 5+ y^2+ x^2= 0 and it is known that dy/dx= y-2x/-x+2y, find all
coordinate points on the curve where x = -1 and the line tangent to the
curve is horizontal, or state that no such points exist.

Answers

Answer 1

Answer:

There is no point of the form (-1, y) on the curve where the tangent is horizontal

Step-by-step explanation:

Notice that when x = - 1. then dy/dx becomes:

dy/dx= (y+2) / (2y+1)

therefore, to request that the tangent is horizontal we ask for the y values that make dy/dx equal to ZERO:

0 = ( y + 2) / (2 y + 1)

And we obtain y = -2 as the answer.

But if we try the point (-1, -2) in the original equation, we find that it DOESN'T belong to the curve because it doesn't satisfy the equation as shown below:

(-1)^2 + (-2)^2 - (-1)*(-2) - 5 = 1 + 4 + 2 - 5 = 2  (instead of zero)

Then, we conclude that there is no horizontal tangent to the curve for x = -1.


Related Questions

20 less than 5 times a number is 85. What is the number

Answers

Answer: I don’t understand the question??

Step-by-step explanation: Can you say the question again like the same way the homework does

Luis solves the following system of equations by elimination.
5s+ 3t = 30
2s+3t=-3
What is the value of s in the solution of the system?

Answers

the value of s is 11

X^9/7 convert from exponent form to radical form

Answers

Answer:

[tex]x^{\frac{9}{7}} = \sqrt[7]{x^9}[/tex]

Step-by-step explanation:

You can solve this by realising that the denominator of a fractional exponent can be expressed as the base of a radical.

Note also that the order does not matter.  You could also express it as

[tex]\sqrt[7]{x}^9[/tex]

The reason this works is that you're effectively breaking the exponent into fractions.  The first answer is the equivalent of:

[tex](x^9)^{1/7}[/tex]

and the second would be:

[tex](x^{1/7})^9[/tex]

In both cases, the exponents would be multiplied, giving the same result.

Asphere has a radius of 27 inches. A horizontal plane passes through the center of the sphere.
Part 1 out od 2
Describe the cross section formed by the plane and the sphere.

Answers

9514 1404 393

Answer:

  circle of radius 27 inches

Step-by-step explanation:

Anywhere a plane cuts a sphere, the cross section is a circle. When the plane includes the center of the sphere, the circle has the same radius the sphere has.

The cross section is a circle of radius 27 inches.

Solve x4 - 11x2 + 18 = 0.

Answers

Answer:

x=√2, x=-√2, x= 3 and x=-3

Step-by-step explanation:

We need to solve the equation x^4 - 11x^2+18=0  

We can replace x^4 = u^2 and x^2 = u

So, the equation will become

u^2 -11u+18 = 0

Factorizing the above equation:

u^2 -9u-2u+18 =0

u(u-9)-2(u-9)=0

(u-2)(u-9)=0

u=2, u=9

As, u = x^2, Putting back the value:

x^2 =2 , x^2 =9  

taking square roots:

√x^2 =√2 ,√x^2=√9  

x=±√2 , x = ±3

so, x=√2, x=-√2, x= 3 and x=-3

Answer:

The second answer is correct.

Step-by-step explanation:

Mark brainliest if correct please

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