Answer:
Single replacement reaction
Explanation:
Let us try to write down the reaction equation for the reaction of a magnesium ribbon with hydrochloric acid.
Mg(s) + 2HCl(aq) ------> MgCl2(aq) + H2(g)
A single replacement reaction is a type of chemical reaction in which one element is replaced by another element in a compound.
In this reaction, magnesium replaced hydrogen to form the product. Hence it is a single replacement reaction.
Did entropy increase or decrease?
1) 2 SO3 (g) → 2 SO2 (g)+O2 (g)
2) MgCO3 (s) + 2 H3O^+ (aq) → Mg^2+ (aq) + 3 H2 O(I) + CO2 (g)
Answer:
1) increase
2) increase
Explanation:
Entropy is the degree of disorderliness or randomness of a system. It is the measure of the unavailable energy in a system.
Entropy increases with increase in the number of particles. If the number of particles in a system increases from left to right, the entropy of the system increases accordingly.
In reaction 1, the number of particles from left to right increased from two to three hence the entropy was increased.
In reaction 2, the number of particles from left to right increased from three to five hence the entropy was increased.
40 POINTS!!! Ice at 0.0 degrees C is combined with 50.0g of water at 75.0 degrees C. Calculate the grams of ice present initially if the entire mixture comes to a final temperature of 25.0 degrees C after the ice melts. Specific heat of water is 4.18 J/goC. SHOW WORK!
Answer:
mi = 31.28 g
Explanation:
According to the law of conservation of energy:
[tex]Heat\ Gain\ by\ Ice = Heat\ Lost\ by\ Water\\m_iL = m_wC\Delta T\\[/tex]
where,
mi = mass of ice = ?
L = Latent heat of fusion of ice = 334 J/g
mw = mass of water = 50 g
C = specific heat of water = 4.18 J/g.°C
ΔT = change in temperature of water = 75°C - 25°C = 50°C
Therefore,
[tex]m_i(334\J/g) = (50\ g)(4.18\ J/g.^oC)(50^oC)[/tex]
mi = 31.28 g
Considering the limiting reactant concept, how many moles of copper(1) sulfide are produced from the reaction of 20 mole of
copper and 2.4 mole of sulfur?
2 Cu(s) + s(s) Cu2S(s)
(No links or bad answer real d
Which property do all metals have?
А They are hard.
B They conduct electricity.
С They form acidic oxides.
D They react with water.
What is the Kc for the following reaction at equilibrium at 500∘C if [N2]= 0.41 M , [H2]= 0.41 M , and [NH3]= 2.2 M ? N2(g)+3H2(g)⇌2NH3(g)
Answer:
answer po Yan hope it help
If the solubility of sodium chloride is 36 grams per 100 grams of water, which of the following solutions would be considered unsaturated? If the solubility of sodium chloride is 36 grams per 100 grams of water, which of the following solutions would be considered unsaturated? 3.25 moles of NaCl dissolved in 500 ml of water 1.85 moles of NaCl dissolved in 300 ml of water 5.8 moles of NaCl dissolved in 1 L of water none of the above
Answer: If the solubility of sodium chloride is 36 grams per 100 grams of water then 5.8 moles of NaCl dissolved in 1 L of water solution would be considered unsaturated.
Explanation:
A solution which contains the maximum amount of solute is called a saturated solution. Whereas a solution in which more amount of solute is able to dissolve is called an unsaturated solution.
Now, the number of moles present in 36 g of NaCl (molar mass = 58.4 g/mol) is as follows.
[tex]No. of moles = \frac{mass}{molar mass}\\= \frac{36 g}{58.4 g/mol}\\= 0.616 mol[/tex]
This shows that solubility of sodium chloride is 36 grams per 100 grams of water means a maximum of 0.616 mol of NaCl will dissolve in 100 mL of water.
So, a solution in which number of moles of NaCl are less than 0.616 mol per 100 mL then the solution formed will be an unsaturated solution.
As 5.8 moles of NaCl dissolved in 1 L (or 1000 mL) of water. So, moles present in 100 mL are calculated as follows.[tex]Moles = \frac{5.8 mol}{1000 mL} \times 100 mL\\= 0.58 mol[/tex]
Moles present in 100 mL of water for 3.25 moles of NaCl dissolved in 500 ml in water are as follows.[tex]Moles = \frac{3.25 mol}{500 mL} \times 100 mL\\0.65 mol[/tex]
Moles present in 100 mL of water for 1.85 moles of NaCl dissolved in 300 ml of water are as follows.[tex]Moles = \frac{1.85 mol}{300 mL} \times 100 mL\\= 0.616 mol[/tex]
Thus, we can conclude that if the solubility of sodium chloride is 36 grams per 100 grams of water then 5.8 moles of NaCl dissolved in 1 L of water solution would be considered unsaturated.
In the endothermic reaction below, how would adding heat affect the equilibrium of the system? (2 points)
A + B + energy ⇄ + D
a. shift it to the left toward the reactants
b. shift it to the right toward the products
c. equally create more products and reactants
d. it would have no effect
What is the greatest concentration of pollution
Answer:
B
Explanation:The poisonous substances, present in the environment can easily get into the trophic level as living organism depends on each other and environment for food and nutrition. These poisonous substances may not be broken down in the body or excreted easily, efficiently and quickly. Instead, they accumulate in the tissues, and as the living organism eats more, the concentration of these substances increases and they pass from one trophic level to the next. The tertiary consumer being at the top of trophic levels receives the maximum pollutant. This phenomenon is known as biological magnification.
So, the correct answer is option B.
what is the difference between transmutation and natural radioactivity
Answer:
o diferença chave entre a radioatividade e a transmutação é que a radioatividade se refere à transmutação natural, enquanto a transmutação se refere à mudança de um elemento químico em outro por meios naturais ou artciais.Tanto a radioatividade quanto a transmutação são processos químicos que envolvem a mudança de núcleos atômicos para formar um novo elemento químico a partir de um elemento químico existente. A radioatividade é um tipo de processo de transmutação
Explanation:
mais informação em; ahttps://pt.strephonsays.com/radioactivity-and-transmutation-9500
What causes the lines in the spectrum for elements
Which of the following patients should be admitted as an inpatient at a
hospital?
A. Katie's having her tonsils removed and will be able to go home
shortly after she wakes up from surgery.
B. Phil's having his blood sugar tested and having his annual
physical
c. Salvatore's having a hip transplant and will need to be closely
monitored for a week.
D. Chen's having chest X-rays taken to determine if he has a broken
rib.
SUBMIT
Jupiter's mass is more than _________ the mass of the other planets put together.
Answer:
2.5 times
Explanation:
Jupiter's mass is 2.5 times that of all the other planets in the Solar System combined—this is so massive that its barycenter with the Sun lies beyond the Sun's surface at 1.068 solar radii from the Sun's center.
help me plss plss.plsss.plsssplss plsss.plsss plsss plsss plsss
Answer:
1. Distance = 5 cm
Displacement = 1 cm
2. Distance = 7 cm
Displacement = 1 cm
3. Distance = 5 cm
Displacement = -1 cm
4. Distance = 6 cm
Displacement = -2 cm
5. Distance = 4 cm
Displacement = 0 cm
Explanation:
The distance an object travels is a measure of the total ground cobpvered bybthe object without regard to the direction of motion. It is a scalar quantity as it only takes into account magnitude but not the direction of a quantity.
Displacement however, is a measure of how far away or apart an object is from its starting position. It a vector quantity as it takes into account both the magnitude and direction in its measurement.
From the attachment provided, considering forward direction as positive and reverse as negative :
1. When a object moves from point 1 to point 4 and reverses to point 2.:
Distance = from 1 to 4 = 3 cm; from 4 back to 2 = 2 cm; 3 + 2 = 5 cm
Displacement = from 1 to 4 = +3 cm; from 4 back to 2 = -2 cm; 3 - 2 = 1 cm
2. When an object moves from point 1 to 5 and reverses to 2:
Distance = from 1 to 5 = 4cm; from 5 back to 2 = 3 cm; 4 + 3 = 7 cm
Displacement = from 1 to 5 = +4 cm; from 5 back to 2 = -4 cm; 4 - 3 = 1 cm
3. When an object moves from point 1 to 3 and then reverses to 0.
Distance = from 1 to 3 = 2 cm; from 3 back to 0 = 3 cm; 2 + 3 = 5 cm
Displacement = from 1 to 3 = +2 cm; from 3 back to 0 = -3 cm; 2 - 3 = -1 cm
4. When an object moves from point 3 to 5 and then reverses to 1:
Distance = from 3 to 5 = 2 cm; from 5 back to 1 = 4 cm; 2 + 4 = 6 cm
Displacement = from 3 to 5 = +2 cm; from 5 back to 1 = -4 cm; 2 - 4 = -2 cm
5. When an object moves from point 2 to 4 and then reverses to 3.
Distance = from 2 to 4 = 2 cm; from 4 back to 2 = 2 cm; 2 + 2 = 4 cm
Displacement = from 2 to 4 = +2 cm; from 4 back to 2 = -2 cm; 2 - 2 = 0 cm
I'm having with chemistry assignments I need a help
Answer:
the question please? illl help
Which of the following behaviors might indicate a patient is drug seeking?
A. A patient wants to avoid a specific medication because of
potential side effects.
B. A patient explains that she is from out of town and needs a
specific medicine because she left her prescription at home.
C. A patient fears her new prescription will conflict with another
medication she's currently taking.
D. A patient thinks she needs a smaller dose of her prescription
because it gives her headaches.
SUBMIT
Answer:
B is correct :)
Explanation:
Trust me I just took the test
Calculate the frequency of a light wave that has a wavelength of 9.2dm.
(a) Using the expression Ka=[H+][A−][HA] , explain how to determine which solution has the lower pH , 0.10MHF(aq) or 0.10MHC2H3O2(aq) . Do not perform any numerical calculations.
Answer:
Ka=[H+][A−]/[HA]
which solution has the lower pH, 0.10MHF(aq) or 0.10MHC2H3O2(aq) :
Higher value of Ka indicates greater ionization thus more protons in solution, higher H+ concentration in solution means lower pH value.
Since HF have higher Ka have, thus HF solution will have lower pH.
The measurement is when the solution has the lower pH so HF should have higher ka.
Measurement when the solution has the lower pH?In the given solution, it contains the lower pH, 0.10MHF(aq) or 0.10MHC2H3O2(aq).
Here higher value of Ka represents the high ionization so there should be more protons in the solutions. and, the higher h+ concentration have the lower pH value.
So in the case when HF has higher Ka, due to this, HF solution will have lower pH.
Learn more about solution here: https://brainly.com/question/14619461
Arenediazoniums can undergo electrophilic aromatic substitutions with a wide variety of activated aromatic compounds to yield new azo dyes.
a. True
b. False
Chemical formula for Aluminum Oxide
Answer: Al₂O₃
Explanation:
20. Identi
21. Name the process and explain what is occurring at D.
Answer:
At D: Soil erosion us the process taking place.
Soil erosion is the washing away of the Earth's or soil's top layer by eroding agents.
i need help help me please
Answer:
C is the correct answer.
Explanation:
We can eliminate some answers immediately:
A is incorrect because nitrogen and hydrogen do not change their identity, they just combine into a new molecule that contains them. Notice how there are 2 nitrogen atoms and 6 hydrogen atoms on both sides of the equation.
B is incorrect because the first law of thermodynamics tells us that matter and energy will always be conserved, so the mass of the products must be equal to the mass of the reactants, not less than the mass of the reactants.
C is correct because balanced chemical equations help chemists predict how much product will form from certain amounts of reactants.
D is incorrect because this equation is showing the exact opposite. Molecular hydrogen and nitrogen can combine stoichiometrically to form ammonia.
what is the formula for tin(III) sulfate
Answer:
SnSO₄
Explanation:
Tin(II) sulfate is a chemical compound. It is a white solid that can absorb enough moisture from the air to become fully dissolved, forming an aqueous solution; this property is known as deliquescence.
Answer:
please give me brainlist and follow
Explanation:
SnSO₄
Consider the following ionization reaction.
HNO3 (aq) + H20 () = NO,- (aq) + H2O* (aq)
a)
Define acid and base according to Bronsted-Lowry, and give an example of each.
(3 marks)
b) Identify all acids and its conjugate base pairs from the above equation.
(2 marks)
Answer:
See explanation
Explanation:
According to Bronsted-Lowry, an acid is a proton donor while a base is a proton acceptor.
Hence, if we consider the reaction above, we will notice that for each base there is a conjugate acid and for each acid there is a conjugate base.
For the acid HNO3, its conjugate base is NO3^- while for the acid H3O^+, its conjugate base is H2O.
atoms that have a high electronegativity...
Helium, bromine, agron, neon,flourine
C3H8+3O2 = 3CO2+4H2O what is the enthalpy combustion please show work
Answer:
[tex]\Delta H_{comb}=2043.85kJ/mol[/tex]
Explanation:
Hello there!
In this case, according to the given chemical reaction, it possible for us to set up the expression for the calculation of the enthalpy change as shown below:
[tex]\Delta H_r=-\Delta H_{comb}=3\Delta _fH_{CO_2}+4\Delta _fH_{H_2O}-\Delta _fH_{C_3H_8}-3\Delta _fH_{O_2}[/tex]
Thus, given the values of the enthalpies of formation on the attached file, we obtain:[tex]-\Delta H_{comb}=3(-393.5kJ/mol)+4(-241.8kJ/mol)-(-103.85kJ/mol)-3(0kJ/mol)\\\\-\Delta H_{comb}=-2043.85kJ/mol\\\\\Delta H_{comb}=2043.85kJ/mol[/tex]
Best regards!
Write balanced equations for all the reactions in the catabolism of glucose to two molecules of glyceraldehyde 3-phosphate (the preparatory phase of glycolysis), including the standard free-energy change for each reaction. Then write the overall or net equation for the preparatory phase of glycolysis, with the net standard free-energy change.
Solution :
The balanced chemical equation are
The Catabolism of the glucose takes place in five stages :
1. Glucose + [tex]$ATP$[/tex] → glucose - [tex]$6$[/tex] - phosphate [tex]$+ ADP$[/tex] , [tex]$\Delta G^0=-16.7 \ kJ/mol$[/tex]
2. Glucose - [tex]$6$[/tex] - phosphate → Fructose - [tex]$6$[/tex] - phosphate , [tex]$\Delta G^0=1.7 \ kJ/mol$[/tex]
3. Glucose - [tex]$6$[/tex] - phosphate + [tex]$ATP$[/tex] → [tex]$ADP$[/tex] + Fructose - [tex]$1,6- \text{biophosphate}$[/tex], [tex]$\Delta G^0=-14.2 \ kJ/mol$[/tex]
4. Fructose - [tex]$1,6- \text{biophosphate}$[/tex] → dihydroxyacetonephosphate + glyceraldehyde [tex]$-3 - $[/tex] phosphate, [tex]$\Delta G^0=23.8 \ kJ/mol$[/tex]
5. Dihydroxyacetonephosphate → glyceraldehyde [tex]$-3 - $[/tex] phosphate , [tex]$\Delta G^0=7.5 \ kJ/mol$[/tex]
Therefore, the overall net equations
Glucose + [tex]$2ATP \rightarrow$[/tex] glyceraldehyde [tex]$-3 - $[/tex] phosphate + [tex]$2ADP$[/tex] [tex]$\Delta G^0=2.1 \ kJ/mol$[/tex]
An isolated atom of a certain element emits light of wavelength 655 nm when the atom falls from its fifth excited state into its second excited state. The atom emits a photon of wavelength 435 nm when it drops from its sixth excited state into its second excited state. Find the wavelength of the light radiated when the atom makes a transition from its sixth to its fifth excited state.
Answer:
[tex]\frac{1}{\lambda_{6-5}} \approx 752nm[/tex]
Explanation:
From the question we are told that
Light wavelength [tex]\lambda_l=655nm[/tex]
Light wavelength atom fall [tex]x_L=5th-2nd[/tex]
Photon wavelength [tex]\lambda_p=435nm[/tex]
Photon wavelength atom fall [tex]x_P=^th-2nd[/tex]
Generally the equation for the reciprocal of wavelength of emitted photon is is mathematically given by
[tex]\frac{1}{\lambda}=R(\frac{1}{ \lambda _f^2}-\frac{1}{\lambda _i^2} )[/tex]
Therefore for initial drop of 5th to 2nd
[tex]\frac{1}{\lambda_{5-2}}=R(\frac{1}{2^2}-\frac{1}{5^2} )[/tex]
Therefore for initial drop of 6th to 2nd
[tex]\frac{1}{\lambda_{6-2}}=R(\frac{1}{2^2}-\frac{1}{6^2} )[/tex]
Generally we subtract (5th to 2nd) from (6th to 2nd)
[tex]\frac{1}{\lambda_{5-2}}- \frac{1}{\lambda_{6-2}}=R(\frac{1}{2^2}-\frac{1}{5^2} )-\frac{1}R(\frac{1}{2^2}-\frac{1}{6^2} )[/tex]
[tex]\frac{1}{\lambda_{5-2}}- \frac{1}{\lambda_{6-2}}=R(\frac{1}{5^2}-\frac{1}{6^2} )[/tex]
[tex]\frac{1}{\lambda_{5-2}}- \frac{1}{\lambda_{6-2}}=\frac{1}{\lambda_{5-6}}[/tex]
[tex]\frac{1}{\lambda_{5-6}}=\frac{1}{4350nm}-\frac{1}{655nm}[/tex]
[tex]\frac{1}{\lambda_{5-6}}=1.33*10^{-3}[/tex]
Therefore for 6th to 5th stage is mathematically given by
[tex]\frac{1}{\lambda_{6-5}}=(1.33*10^{-3})^{-1}[/tex]
[tex]\frac{1}{\lambda_{6-5}}=751.879nm[/tex]
[tex]\frac{1}{\lambda_{6-5}} \approx 752nm[/tex]
6.3x10-5M. What is the pH?
Answer:
https://sensorex.com/ph-calculator/
Explanation:
go to this link and then scroll down a little bit and then you'll find the answer
What do you plan to do this weekend !
( Giving out Branliest ) <3
Answer:
Go to the pool , Bake, sleep, Watch ,Movies, go out with my freinds<3
Explanation:
Explain why each of these elements occur as diatomic molecules, Match the words in the left column to the appropriate blanks in the sentences on the right.
triple
double
octet
single
duet
When two hydrogen atoms pair together, they form a ____bond to achieve a complete _______which is a stable configuration.
When two halogens poir together,they form a________bond to achieve a complete_______ which is a stable configuration
to achieve a completo
When two oxygen atoma pair together, they form a_________bond to achieve a complete which is a stable configuration
When two nitrogen atomo poir together, they form a_________bond to achieve a complete which is a stable configuration
Answer: When two hydrogen atoms pair together, they form a single bond to achieve a complete duet which is a stable configuration.
When two halogens poir together,they form a single bond to achieve a complete octet which is a stable configuration
When two oxygen atoma pair together, they form a double bond to achieve a complete octet which is a stable configuration
When two nitrogen atoms pair together, they form a triple bond to achieve a complete octet which is a stable configuration
Explanation:
The tendency of atoms to achieve a noble gas configuration that is eight valence electrons is said to be octet rule. This is done to attain noble gas configuration and stability.
In order to attain stability the atoms tends to have eight electrons in its valence shell which can be obtained by either by sharing of electrons or complete transfer of electrons.
Hydrogen [tex](H:1s^1)[/tex] has one valence electron each, so sharing of electrons result in formation of single bond and the same electron configuration as the Helium and thus complete its duet.
Halogens [tex](F:1s^22s^22p^5)[/tex] have 7 valence electron each, so sharing of electrons result in formation of single bond. The stable noble gas configuration is attained and thus complete its octet.
Oxygen [tex](O:1s^22s^22p^4)[/tex] has six valence electrons each, so sharing of two electrons result in a double bond. The stable noble gas configuration is attained and thus complete its octet.
Nitrogen [tex](N:1s^22s^22p^3)[/tex] has 5 valence electrons, so sharing of three electrons result in a triple bond. The stable noble gas configuration is attained and thus complete its duet.