A submarine emerges 1/9 of its volume when it partially floats on the sea surface. For make it completely submerge it is necessary to allow a volume of 50,000 [L] to enter of sea water whose density is 1,026 [g / cm3]. What is the weight of the submarine?

Answers

Answer 1

Answer:

4,524,660 N

Explanation:

Assuming the submarine's density is uniform, 1/9th of the submarine's mass is equal to the mass of the displaced water.

m/9 = (1026 kg/m³) (50 m³)

m = 461,700 kg

mg = 4,524,660 N


Related Questions

Two men, Joel and Jerry, each pushes an object that are identical on a horizontal frictionless floor starting from rest. Joel and Jerry are using the same force F. Jerry stops after 10 min, while Joel is able to push for 5.0 min longer. Compare the work they do.

Answers

Answer:

The work done by Joel is greater than the work done by Jerry.

Explanation:

Let suppose that forces are parallel or antiparallel to the direction of motion. Given that Joel and Jerry exert constant forces on the object, the definition of work can be simplified as:

[tex]W = F\cdot \Delta s[/tex]

Where:

[tex]W[/tex] - Work, measured in joules.

[tex]F[/tex] - Force exerted on the object, measured in newtons.

[tex]\Delta s[/tex] - Travelled distance by the object, measured in meters.

During the first 10 minutes, the net work exerted on the object is zero. That is:

[tex]W_{net} = W_{Joel} - W_{Jerry}[/tex]

[tex]W_{net} = F\cdot \Delta s - F\cdot \Delta s[/tex]

[tex]W_{net} = (F-F)\cdot \Delta s[/tex]

[tex]W_{net} = 0\cdot \Delta s[/tex]

[tex]W_{net} = 0\,J[/tex]

In exchange, the net work in the next 5 minutes is the work done by Joel on the object:

[tex]W_{net} = W_{Joel}[/tex]

[tex]W_{net} = F\cdot \Delta s[/tex]

Hence, the work done by Joel is greater than the work done by Jerry.

Suppose a piece of food is on the edge of a rotating microwave oven plate. Does it experience nonzero tangential acceleration, centripetal acceleration, or both when: (a) The plate starts to spin

Answers

Answer:

the only acceleration it has is radial (centripetal)

Explanation:

The microwaves plate rotates at a constant speed after a very short period of acceleration.

Therefore we can apply Newton's second law

        F = m a

where the acceleration is centripetal

         a = v2 / r = w2 r

therefore as it rotates constant speed it cannot have a tangential acceleration since it changes the modulus of the speed.

Consequently the only acceleration it has is radial (centripetal)

Suppose you are testing a new amusement park roller coaster with an empty car with a mass of 100 kg. One part of the track is a vertical loop with a radius of 12.0 m. At the bottom of the loop (point A), the car has a speed of 25.0 m/s and at the top of the loop (point B), it has a speed of 8.00 m/s. As the car rolls from point A to point B, how much work is done by friction? Use 9.81 m/s2 for the acceleration due to gravity.

Answers

Answer:

Explanation:

Gain  of kinetic energy + work done by friction = loss of potential energy

= 1 / 2 m ( 25² - 8² ) + work done by friction = m x 9.8 x ( 12 + 12 )

= .5 x 100 x ( 625 - 64 ) + work done by friction = 100 x 9.8 x 24

28050 + work done by friction = 23520

work done by friction = -4530 J

How many excess electrons must be distributed uniformly within the volume of an isolated plastic sphere 22.0 cmcm in diameter to produce an electric field of 1340 N/CN/C just outside the surface of the sphere?

Answers

Answer:

1.125x10^-10 electrons

Explanation:

Pls see attached file

If you are asked to modify the robots or drones that are currently used , what kind of modifications you would do and suggest any two fields where it can be used.

Answers

Explanation:

In recent times of pandemic, robots can be use as replacement of labor in the industries. Mundane tasks can be programmed in their system so that they can used readily.

Drones can used delivery for essential goods and services, so that human interference can be least and the spread of virus can be curbed.

In a recent example, Argentina where aerial data has reportedly been used to accelerate the construction of emergency hospitals.

explain why the term Nano is used to describe nanotechnology​

Answers

Answer:

Nanotechnology means working with materials at the scale of one billionth of a metre.

Explanation:

The prefix “nano” refers to one billionth: it’s part of the scientific scale of measurement. Its science, engineering, and technology are conducted at the nanoscale, which is about 1 to 100 nanometers. Nanoscience and nanotechnology are the study and application of extremely small things. Thus, this describes why the term nano is used to describe nanotechnology.

I hope this helps :)

Answer:

Nanotechnology is technology that is about a nanometer in size, or between 1 nm and 100 nm.

Explanation:

its the sample response on edge 2021

identify the motion when a car is moving with constant speed along a curve

Answers

Answer:

Uniform circular motion

Explanation:

When a car is moving with constant speed along a curve, it will said to have uniform circular motion. The speed of the car remains constant in this case. But its velocity keeps on changing. The velocity can be calculated by drawing the tangent on the circle. Hence, the motion of the car is uniform circular motion.

Answer:

Uniform motion

Explanation:

The motion when a car is moving with constant speed along a curve is an example of uniform motion.

A car moving at constant speed covers equal distances in equal intervals of time. The average speed remains the same in uniform motion.

The curve defines the path of the motion and the speed remains constant.

Which of the following would cause the force of static friction to increase?

Answers

Answer:

Answer B)  An increase in [tex]\mu_S[/tex]

Explanation:

Since we are talking about the force of static friction, due to its definition as the product between the normal force to the surface times the coefficient of static friction, the only two ways such force could increase is due to an increase in the normal force, or an increase in the coefficient of static friction [tex]\mu_S[/tex].

So the only valid answer is answer B)

How do you find the rest mass (kg) of a 3.1 eV electron?

Answers

Answer:

Explanation:

The rest energy of any substance is defined by the Einstein's mass energy equivalence relation. Thus the rest mass of a electron is 9.11x10^-31 kg. The speed of light is 299,792,458 m/s. Thus multiplying the square of speed of light with the rest mass of electron gives the rest energy of the electron.

Answer the following three questions in complete sentences. 1. How much does the earth weigh? 2. How far away is the sun? 3. What is a black hole?

Answers

Answer: find the answer in the explanation.

Explanation:

1.) The weight of the earth can be calculated and estimated by the physicist by considering the mass of the earth and the knowlegde of gravity.

If the mass of the earth is considered to be 6 × 10^24 kg. Then with Physics formula and some mathematical techniques, we can conclude that the weight of the earth is approximately equal to 6 × 10^25 N.

2.) The distance of the sun to the earth is approximately 1.5 × 10^8 km. This measure is the distance from the surface of the earth to the sun.

3.) The black hole is approximately the size of the earth of very large gravitational field strength. It is a region of space of enormous gravity where no particular object can escape from it. Even electromagnetic radiation or light cannot escape from it.

Answer:

The Earth weighs 5.972 × 10^24 kg

The Sun is 94.022 million miles away.

A black hole is is a region of spacetime where gravity is so strong that nothing, no particles or even electromagnetic radiation such as light can escape from it. The theory of general relativity predicts that a sufficiently compact mass can deform spacetime to form a black hole.

I hope this helps!! :)

When you urinate, you increase pressure in your bladder to produce the flow. For an elephant, gravity does the work. An elephant urinates at a remarkable rate of 0.0060 m3 (a bit over a gallon and a half) per second. Assume that the urine exits 1.0 m below the bladder and passes through the urethra, which we can model as a tube of diameter 8.0 cm and length 1.2 m. Assume that urine has the same density as water, and that viscosity can be ignored for this flow.
1) What is the speed of the flow? It is 1.2 m/s
2) If we assume that the liquid is at rest in the bladder (a reasonable assumption) and that the pressure where the urine exits is equal to atmospheric pressure, what does Bernoulli's equation give for the pressure in the bladder? (In fact, the pressure is higher than this; other factors are at work. But you can see that no increase in bladder pressure is needed!)

Answers

Answer:

1)  v = 1.19 m / s , 2)     P₁ = 9.308 10⁴ Pa  

Explanation:

In this exercise we will simulate the emission of urine as a fluid mechanics system

1) they indicate the urine flow rate Q = 0.0060 m³ / s, they also give the diameter of the tube 8.0 cm, they ask us the speed.

   Let's use the continuity equation

            Q = v A

The area of ​​a cycling tube is

            A = π r² = π d² / 4

we substitute

            Q = v π d² / 4

            v = 4Q / π d²

let's calculate

            v = 4 0.006 / (π 0.08²)

            v = 1.19 m / s

2) they ask to find the pressure in the bladder, for this we use the Bernoulli equation, where the index is for the bladder and the index 2 is for the exit point

            P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

in the exercise it indicates that the outlet pressure is equal to the atmospheric pressure P₂ = 1,013 10⁵ Pa, the velocity of the liquid in the bladder is v₁ = 0 and the height difference 1.0 m

           P₁ = P₂ + ½ ρ v₂² + ρ g (y₂-y₁)

let's calculate

          P₁ = 1.013₁ 10⁵⁵ + ½ 1000 1.19 + 1000 9.8 (0-1)

          P₁ = 1.013 105 + 595 - 9800

          P₁ = 9.308 10⁴ Pa

A hollow circular shaft made of 304 stainless steel uniformly tapers from an outer diameter of 3.0 cm to an outer diameter of 4.0 cm over a length of 2 meters. The inner diameter of 1.0 cm is constant over the length of the shaft. The shaft is subjected to an applied torque of 500 Nm. Determine the maximum shear stress in the shaft.

Answers

Answer:

maximum shear stress = τ(max) = 95.49 × 10⁶N/m²

Explanation:

given

outer diameter at one end(D₁) = 3.0cm

outer diameter at the other end(D₂) = 4.0cm

inner diameter(d₁) = 1.0cm

torque applied(T) = 500Nm

maximum shear stress will occur at lower outer diameter

the formula is τ/r = T/J

τ= T × r/J

where r is radius

T is the torque

J is the polar 2nd M of area

attached is the calculation of the question

Bumper car A (281 kg) moving +2.82 m/s makes an elastic collision with bumper car B (209 kg) moving +1.72 m/s. What is the velocity of car A after the collision? Would greatly appreciate the actual answer!

Answers

Answer:

Hello There. ☆~\《--_^■^_--》\~☆ The final velocity of the car A is -1.053 m/s. For an elastic collision both the kinetic energy and the momentum of the system are conserved.

Hope It Helps!~ ♡

ItsNobody~ ☆

The velocity of CAR after the collision is "1.881 m/s".

Given:

[tex]M_A = 281 \ kg \\\\ v_A= 2.82 \frac{m}{s}\\\\M_B = 209 \ kg \\\\ V_B = 1.72 \frac{m}{s}[/tex]

To find:

velocity=?

Solution:

Using the formula for the velocity of CAR after the collision:

[tex]\to V_A = \frac{V_A(M_A -M_B) +2 M_B V_B}{M_A+M_B}\\\\[/tex]

         [tex]= \frac{2.82(281 - 209) +2 \times 209 \times 1. 72}{ 281+ 209}\\\\ = \frac{2.82(72) +718.96}{490}\\\\= \frac{203.04 +718.96}{490}\\\\= \frac{922.00}{490}\\\\= \frac{922}{490}\\\\=1.881 \ \frac{m}{s}[/tex]

Therefore, the answer is "[tex]\bold{1.881\ \frac{m}{s}}[/tex]"

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What does addition of two vectors give you?

Answers

Answer:

Explanation:

To add or subtract two vectors, add or subtract the corresponding components. Let →u=⟨u1,u2⟩ and →v=⟨v1,v2⟩ be two vectors. The sum of two or more vectors is called the resultant. The resultant of two vectors can be found using either the parallelogram method or the triangle method .

The gas in a balloon has T=280K and V=0.0279m^3. If the temperature increases to 320K at constant pressure, what is the new volume of the balloon? (Hint: n and P are constant) (Unit= m^3)

Answers

Answer:

[tex]\boxed{ V_{2}= 0.03189 m^3}[/tex]

Explanation:

According to Charles Law

=> [tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}[/tex]

Where [tex]V_{1}[/tex] = 0.0279 m³, [tex]T_{1}[/tex] = 280 K and [tex]T_{2}[/tex] = 320 K

=> [tex]\frac{0.0279}{280} = \frac{V_{2}}{320}[/tex]

=> [tex]V_{2}[/tex] = 0.03189 m³

How is a less-intense wave different from a more-intense wave?
It has fewer decibels.
O It has a higher pitch.
O It has more volume.
It has more energy.

Answers

Answer: It has fewer decibels.

Explanation:

In a sound-wave, the intensity is defined as the power carried by the wave. The decibel is a measure of the ratio between two quantities. And in acoustics is used as the unit of the sound pressure level, which is related to the intensity of the wave, then:

As the intensity increases, we also should notice an increase in the decibels.

How is a less-intense wave different from a more-intense wave?

The less-intense wave has fewer decibels.

Answer:

It has fewer decibels.

Explanation:

Which of the following statements describes nucleons?
A. Nucleons are the particles that make up a nucleus.
B. Nucleons are the particles in an atom that are neutral.
C. Nucleons are the particles that make up an atom.
D. Nucleons are the particles in an atom that have a charge.

Answers

Answer: nucleons are the particles that make up in nucleus

Explanation:

Nucleons are the particles that make up a nucleus, and they include protons and neutrons.

What are nucleons?

Nucleons are particles that make up nucleus of an atom. They include either proton or neutron, or both found in atomic nucleus.

Generally, nucleons are subatomic particles found within nucleus of an atom.

Therefore, we can conclude that, nucleons are the particles that make up a nucleus.

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A patient had stunted growth,swelling on face,discolaration of hair and skin disease.the doctor advised him to eat a lot of pulses,grams,albumin of the egg and milk etc.,which is wrong with the patient?Explain in two sentences

Answers

Answer:

The patient is suffering from protein deficiency

Explanation:

Protein deficiency is characterized by symptoms such as stunted growth; skin, nail and hair problems, loss of muscle mass, and in extreme cases, kwashiorkor.

Deficiency in protein is usually corrected by taking foods rich in protein such as egg's albumin, milk, pulses, beans, etc; hence the advice of the doctor.

It has been a hot summer, so when you arrive at a lake, you decide to go for a swim even though it it nighttime. The water is cold. The next day, you go swimming again during the hottest part of the day, and even though the air is warmer the water is still almost as cold. Why?
(a) Water is fairly dense compared with many other liquids.
(b) Water remains in a liquid state for a wide range of temperatures.
(c) Water has a high bulk modulus.
(d) Water has a high specific heat.

Answers

Answer:

(d) Water has a high specific heat.

Explanation:

At night, when the temperature of earth goes down due to loss of heat , the temperature of water is lost slowly and temperature of land is lost fast because of high specific heat of water . Water loses as well as gains temperature comparatively slowly due to its high specific heat .

During daytime when earth gains heat , the temperature of land rises more rapidly than water so water appears cool even during daytime when land becomes  hotter . It is also due to high heat holding capacity of water or due to high specific heat of water .

The power source provides a current of 1.86 A at a potential difference of 3.90 V. Calculate the power of the power source. Use the equation:
power = potential difference × current

Choose the correct unit from the box below

C W J

Answers

Answer:

W

Explanation:

The unit for Power which is  (Volt X Current) is Watts. and the symbol for Watts is W.

What rule should be used to transform a table of data to represent the
reflection of f(x) over the yaxis?

Answers

Answer:

Multiply the x values with -1.

Explanation:

By multiplying the numbers by one, you are changing them to be the opposite of their original state.

You multiply the numbers that are in the x-value column because you are reflecting the image over the y-axis.

Hope this helped and good luck!

Answer:

Multiply each x-value in the table by -1

Explanation:

A point charge +Q is located on the x axis at x = a, and a second point charge –Q is located on the x axis at x = –a. A Gaussian surface with radius r = 2a is centered at the origin. The flux through this Gaussian surface is

Answers

Answer:

Net flux through the surface is zero.

Explanation:

Recall that the net electric flux through a closed surface depends on the net charge enclosed inside that surface.

In our case, there are two point charges of exactly opposite charge (net charge - zero), which are located inside the Gaussian surface of radius "2 a" centered at the origin - both charges are located at a distance "a" from the origin of coordinates, therefore inside the Gaussian surface.

Then the net flux through the surface is also ZERO.

Experimenting with free fall, Mariana observes that her baseball takes 1.5 s to travel the last 30m before hitting the ground. From what height above the ground did Mariana drop the ball?

Answers

Answer:

37.8 m

Explanation:

At point 0, the ball is at height y₀.

At point 1, the ball is at height 30 m.

At point 2, the ball is at height 0 m.

Given:

y₁ = 30 m

y₂ = 0 m

v₀ = 0 m/s

a = -10 m/s²

t₂ − t₁ = 1.5 s

Find: y₀

Use constant acceleration equation.

y = y₀ + v₀ t + ½ at²

Evaluate at point 1.

y₁ = y₀ + v₀ t₁ + ½ at₁²

30 m = y₀ + (0 m/s) t₁ + ½ (-10 m/s²) t₁²

30 = y₀ − 5t₁²

Evaluate at point 2.

y₂ = y₀ + v₀ t₂ + ½ at₂²

0 m = y₀ + (0 m/s) t₂ + ½ (-10 m/s²) t₂²

0 = y₀ − 5t₂²

y₀ = 5t₂²

Substitute:

y₀ = 5 (1.5 + t₁)²

y₀ = 5 (2.25 + 3t₁ + t₁²)

y₀ = 11.25 + 15t₁ + 5t₁²

30 = 11.25 + 15t₁ + 5t₁² − 5t₁²

30 = 11.25 + 15t₁

t₁ = 1.25

30 = y₀ − 5t₁²

30 = y₀ − 5(1.25)²

y₀ ≈ 37.8

Una tractomula se desplaza con rapidez de 69 km/h. Cuando el conductor ve una vaca atravesada enmedio de la carretera, acciona los frenos y se detiene 4 s después. Si la vaca estaba a 25 m de la tractomulacuando el conductor pisó el freno. ¿atropelló la vaca? Justifique su respuesta.

Answers

Answer:

Los datos que tenemos:

Rapidez: 69km/h

Tiempo que tarda en frenar = 4s.

Distancia inicial entre la tracto-mula y la vaca = 25m

Ok, la ecuación de desaceleración es:

D = (sf - si)/t

sf = velocidad final = 0m/s

si = velocidad inicial = 69km/h

t = tiempo = 4s

D = -69km/h/4s

ok, 1h = 3600s

D = (-69km/s)*1/(4*3600s)  = -0.0048 km/s^2

Entonces la ecuación de aceleración es:

a(t) =  -0.0048 km/s^2

Para la velocidad, integramos sobre el tiempo

v(t) = (-0.0048 km/s^2)*t + v0

donde v0 es la velocidad inicial, en este caso v0 = 69km/3600s = 0.0191km/s  

v(t) =  (-0.0048 km/s^2)*t + 0.0191km/s

Para la posición volvemos a integrar sobre el tiempo, esta vez suponemos la posición inicial igual a cero.

p(t) = (1/2)*(-0.0048 km/s^2)*t^2 + 0.0191m/s*t

Ahora, si p(t=4s) < 25m, esto implica que la tracto-mula no impacto con la vaca.

p(4s) = (1/2)*(-0.0048 km/s^2)*(4s)^2 + 0.0191km/s*4s = 0.038km

y 1km = 1000m

0.038km = 0.038*1000m = 38m

Entonces si, atropello a la vaca.

Salt compounds are commonly used to melt ice that forms on sidewalks in the winter. A common chemical that is used to melt sidewalk ice is calcium chloride, CaCl2(s). When calcium chloride dissolves into solution is releases thermal energy which aides in melting
the ice.

The molar mass of water is 18.02 g/mol

The thermal energy, in kilojoules (kJ) that must be released from the calcium chloride,
CaCl2(s), to melt 10.0 kg of ice, expressed in scientific notation is a.bc x 104 k).
46
55
The values of a, b, c, and d.

Answers

Answer:

The values of a, b, c and d are

a = 3, b = 3, c = 4 and d = 3

Explanation:

The quantity of heat needed to melt the ice is given by Q = mL where m = mass of ice and L = latent heat of fusion of ice = 334 kJ/kg. This quanity of heat is also the thermal energy needed to be released by the calcium chloride, CaCl₂

Now, the mass of ice = 10 kg. So,

Q = mL

Q = 10 kg × 334 kJ/kg

Q = 3340 kJ

In scientific notation,

Q = 3.34 × 10³ kJ

So the thermal energy needed to be released by the calcium chloride is 3.34 × 10³ kJ

Comparing Q = 3.34 × 10³ kJ with a.bc × [tex]10^{d}[/tex] kJ

So, a = 3, b = 3, c = 4 and d = 3

The values of a, b, c and d are

a = 3, b = 3, c = 4 and d = 3

Earthquake damage causes two rabbits to be separated from the rest of the rabbits in their large habitat. They have no way to get back to their original habitat. The two rabbits mate with each other. Over time, all the offspring in the new habitat are descendants of the original two rabbits. What are the outcomes of this situation? A.The rabbits in the new habitat will have lower genetic variation than the rabbits in the original habitat. B. The rabbits in the new habitat will have a higher risk of random genetic mutations than the rabbits in the original habitat. C. The rabbits in the original habitat have a greater likelihood of choosing an unrelated mate than the rabbits in the new habitat. D.The rabbits in the original habitat will be less likely to reproduce than the rabbits in the new habitat.

Answers

Answer:

A.The rabbits in the new habitat will have lower genetic variation than the rabbits in the original habitat.

Explanation:

If two animals of opposite sex are isolated from a larger group of animal, and made to reproduce. They will produce offspring with similar genetic makeup. If this offspring still remain isolated, and continue to interbreed within themselves for a number of consecutive generations, their offspring will all be very closely related genetically. Situations like this just as with the two rabbits in the question leads to a lower genetic variation within the offspring of the two animals.

Animals need to reproduce within a larger group in order to increase genetic variation. Increasing genetic variation reduces the risk of been sucked into a gene pool. A lower genetic variation reduces the fitness of the animals involved. It is only an advantage in cases in which the the original pair are resistant to a deadly disease. In this case all the offspring also develop this immunity. Mostly the effects of a lower genetic variation leaves negative impacts, and animals try to avoid this by preferring to interbreed with unrelated partner

Answer:

I got this and got the answer correct.

Explanation:

Hope it helps :)

Which of the following are double-displacement reactions? multiple answers
A. 2H2(g) + O2(g) -> 2H2O(g)
B. Zn(s) + 2HCI(aq) -> H2(g) + ZnCI2(s)
C. Ba(OH)2(aq) + 2HCIO4(aq) -> Ba(CIO4)2(aq) + 2H2O(I)
D. HNO3 (aq) + KOH (aq) -> H2O(I) + KNO3 (aq)​

Answers

Answer:

C and D

Explanation:

A: is a simple composition

B: is a single replacement

C: C is a double displacement

D: is a double replacement

Answer:

The answers are C abd D.

Explanation:

Here,

A no. Is a combination or analysis chemical reaction.

B no.is a single displacement reaction as cl2 goes to zn.

C no. Is double displacement reaction.

D no. Is a double displacement reaction.

Hope it helps.....

A mass of 1.15 kg of air at 111 kPa and 27 C is contained in a gas-tight, frictionless piston cylinder device. The air is now compressed to a final pressure of 0.84 MPa. During this process, heat is transferred from the air such that the temperature inside the cylinder remains constant. Calculate the work input (in kJ) during this process.

Answers

Answer:

Work input W = -200.39 KJ

Explanation:

From the question, we are given;

m = 1.15 kg

Constant temperature T1 = T2 = 27 + 273 = 300k

Since the temperature is constant, we can say that the process is isothermal

P1 = 111 KPa

P2 = 0.84 MPa = 0.84 * 1000 KPa = 840 KPa

Now what we want to calculate is W1-2

Mathematically, for isothermal process;

W1-2 = mRTlnP1/P2

where R can be obtained from table and it is equal to 0.287 KJ/kg.k

Hence;

W1-2 = (1.15)(0.287)(300)(ln 111/840)

W1-2 = 99.015 * -2.023871690525 = -200.39 KJ

Kindly note that the value of the work is negative because work is done on the system and not by the system

What is density?
O A. The net energy transferred between two objects
B. A measure of mass per unit volume
O C. A measure of the movement of molecules
O D. The force exerted on an area​

Answers

Answer:

B. A measure of mass per unit volume

Explanation:

Mass and volume are intimately correlated with density. In reality, it explains the precise nature of the connection between the two. We can determine an object's density by dividing its mass by volume. Thus, option B is correct.

What best defines about density?

The mass or amount per unit of volume of a substance determines its density. Density is calculated using the formula mass/volume. It is considered to have a low density if a mass has a high volume but a tiny mass.

The volume and subsequently the density of a material typically alter when it changes its phase or state of matter. Temperature is the primary component, even though pressure can also affect how a material changes state.

Water availability, climate, relief (the contour of the terrain), vegetation, soils, and the accessibility of renewable energy sources are physical elements that impact population density. Social, political, and economic variables altering humans all have an impact on population density.

Therefore,  A measure of mass per unit volume.

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Find the net force on q3. Include the direction ( +or-).
q1= -53.0 uC; q2=105 uC; q3= -88.0 uC; q1 to q2= 0.50m; q2 to q3= 0.95m
I will give brainliest to whoever gets the correct answer!

Answers

Answer:

72.16 N

Explanation:

Given:

q₁ = -53.0 μC

q₂ = 105 μC

q₃ = -88.0 μC

q₁ to q₂ = 0.50 m

q₂ to q₃ = 0.95 m

To find:

Net force on q₃

Solution:

First compute net electric field on q₃

E = F/q = k.Q/d²

The formula of electric field at q₃:

E = k.Q / r²

Where    

r is distance

Q is magnitude of charge

k is a constant with a value of 8.99 x 10⁹ N m²/C²

When

q₂ to q₃ = 0.95m and

q₂ = 105 μC then

Find electric field due to charge q₂

E = ( (8.99 x 10⁹)x( 105 x 10⁻⁶) ) / 0.95²

  =  (8990000000  x 0.000105) / 0.9025

  = 943950  / 0.9025

  = 1045927.977839

  = 1.046 x 10⁶ N/C

This interprets that it will act or point away from q₂

q₁ to q₂= 0.50m

q₂ to q₃ = 0.95m and

q₁ = -53 μC then

Find electric field due to charge q₁

E = (8.99 x 10⁹) x (53 x 10⁻⁶) / (0 .50 + 0.95)²

  =  (8990000000  x  0.000053) / (1.45)²

  = 476470 /2.1025

  = 226620.689655

  = 0.227  x 10⁶ N/C

This interprets that it will act or point towards q₁

Since these fields are opposite in direction.

Compute Net Field

Net Field = 1.046 x 10⁶ - 0.227  x 10⁶ N/C

               =  1046000 - 227000

               = 819000

               = 0.819 x 10⁶

               ≈ 0.82 x 10⁶

This interprets that it will act or point away from q₂

Compute force on q3

q₃ E  = 88 x 10⁻⁶ x 0.82 x 10⁶

       = 88000000  x 820000

       = 72160000000000

       = 72.16 N

Force on -ive charge in a field is always in a direction opposite to direction of field

So this interprets that direction of this field will be towards q₂.

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