A thin 1.5 mm coating of glycerine has been placed between two microscope slides of width 0.8 cm and length 3.9 cm . Find the force required to pull one of the microscope slides at a constant speed of 0.28 m/s relative to the other.

Answers

Answer 1

The  force required to pull one of the microscope sliding at a constant speed of 0.28 m/s relative to the other is zero.

Force required to pull one end at a constant speed

The force required to pull one of the microscope sliding at a constant speed of 0.28 m/s relative to the other is determined by applying Newton's second law of motion as shown below;

F = ma

where;

m is massa is acceleration

At a constant speed, the acceleration of the object will be zero.

F = m x 0

F = 0

Thus, the  force required to pull one of the microscope sliding at a constant speed of 0.28 m/s relative to the other is zero.

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Related Questions

what are the milestones of modern phyiscs?

Answers

Answer:

The articles appearing under "Milestones in Physics" will give an insight into special events or situations that have been decisive for the evolution of Physics

Answer:

We have invented many new ways to get energy, especially renewable means of energy, and we have made many new carbon-neutral devices more widespread and cheaper.

Modern physics milestones are getting harder and harder to get because almost every element has been discovered, many gaseous and liquid substances have been experimented with and dozens of other mid 20th century discoveries.

The lifting force, F, exerted on an airplane wing varies jointly as the area, A, of the wing's surface and the square of the plane's velocity, v. The lift of a wing with an area
of 280 square feet is 27,800 pounds when the plane is going 220 miles per hour. Find the lifting force on the wing if the plane slows down to 130 miles per hour.
(Leave the variation constant in fraction form or round to at least 5 decimal places. Round off your final answer to the nearest pound.)

Answers

Answer:

If the lifting force varies jointly with wing surface area and the square of the plane's velocity, then:

F = kAv²

If the lift is 27,800 pounds when the area is 190 sq. ft and the velocity is 230 mph, then the constant of proportionality is:

27,800 = k(190)(230)²

k = (27,800) / (190)(230)² = 139/50255

The lifting force the plane slows down to 200 mph is:

F = (139/50255)(190)(200)²

F = 21,020.79

Rounded to the nearest pound, the lifting force is 21,021 pounds.

PLEASE HELP!! A TOTAL OF 50 POINTS WHEN GIVEN BRAINLIEST!!

Part A: Find the work done in lifting 1 L of blood (mass 1 kg ) from the foot to the head of a 1.9 m -tall person.

Part B: If blood circulates through the body at the rate of 5.0 L/min , estimate the heart's power output. (Your answer underestimates the power by a factor of about 5 because it neglects fluid friction and other factors.)

Answers

Explanation:

for part A:

work done is equal to change in potential energy which is

MgH

so the answer is 1.9 × 1 × 9.81

ANSWER FOR PART A: 18.639

FOR PART B:

power = flow rate x gh

= 5×9.81×1.9

93.195 watts

A child pushes a toy truck up an inclined plane. The lifting force is...
Select one:
a. the weight of the truck.
b. the length of the inclined plane.
c. the force the child uses to push the truck.
d. equal to the total amount of work done.

Answers

The lifting force when a child pushes a toy truck up an inclined plane is  equal to the total amount of work done.

Work-energy theorem

The work-energy theroem states, the work done on an object is equal to the change in mechanical energy of the object.

The net force applied by the child on the truck, will create a lifting force on the object.

Fd - Ffd = k.E

Where;

Fd is the work done by the childFfd is the work done by frictionK.E is the kinetic energy of the truck

Thus, the lifting force when a child pushes a toy truck up an inclined plane is  equal to the total amount of work done.

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