Answer:
2.5 m/s²
Explanation:
From the question
F = ma................... Equation 1
Where F = Tension, m = mass, a = acceleration of the car
make a the subject of the equation
a = F/m.................. Equation 2
Given: F = 1500 N, m = 600 kg
Substitute these values into equation 2
a = 1500/600
a = 2.5 m/s²
Hence the largest acceleration the rope can give to the car is 2.5 m/s²
*please help fast**15 points*
How is laser light different from the light produced by a flashlight?
A. The crests of laser light waves align with one another.
B. Lasers produce multiple wavelengths of light.
C. Lasers produce light that is incoherent
D. Flashlights use reflecting mirrors and lasers do not.
Answer:
B.
Explanation:
Laser light is different from normal light in other ways as well. First, its light contains only one wavelength (one specific color). ... Whereas a laser generates a very tight beam, a flashlight produces light that is diffuse. Because laser light is coherent, it stays focused for vast distances, even to the moon and back
According to Newton’s second law of motion, weight depends on an object’s mass and the net force acting on the object. True or false
Answer:
true..
Explanation:
Newton's 2nd law of motion is greater the mass of an object the more force it will take to accelerate the object
According to Newton’s second law of motion, weight depends on an object’s mass and the net force acting on the object. The given statement is true.
What is force?Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.
The following equation help to understand the statement;
Force is defined as the product of mass and acceleration. Its unit is Newton.
F=ma
F=mg
W=mg
The weight of an item is determined by its mass and the net force exerted on it, according to Newton's second rule of motion. The provided assertion is correct.
Hence,the given statement is true.
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The statement "if I raise the temperature of
a cup of water, then an increased amount of
sugar will be dissolved" is an example of
A. an observation
B. a hypothesis.
C. a theory
A 2.60 kg lion runs at a speed of 5.00 m/s until he sees his prey. The lion then speeds up 8.00 m/s to catch it. How much work did do after he speeds up?
Answer: 50.7 J
Explanation:
Given
mass of lion is [tex]m=2.6\ kg[/tex]
The initial speed of the lion is [tex]v_1=5\ m/s[/tex]
increased speed of lion is [tex]v_2=8\ m/s[/tex]
Initially, its kinetic energy is [tex]K_1=\frac{1}{2}mv_1^2[/tex]
Final kinetic energy [tex]k_2=\frac{1}{2}mv_2^2[/tex]
work did by lion after speed up is [tex]k_2-k_1[/tex]
[tex]\Rightarrow W=\dfrac{1}{2}\times 2.6[8^2-5^2]\\\\\Rightarrow W=1.3\times [39]=50.7\ J[/tex]
did you guys get this : The x-component of motion of an object is given by x(t) = Axcos(ωxt + φx) and the y-component of motion of the object is given by y(t) = Aycos(ωyt + φy). What relationships between the A,ω, and φ parameters must be true so that the motion of the object is on a circle?
Answer:
Aₓ = A_y = A
wₓ = w_y = w
Фₓ = Ф_y = Ф
Explanation:
For a movement to be circular it must meet the exception of the circle
R² = x² + y²
in the exercise indicate the expressions of the movement in the two axes
x (t) = Aₓ cos (wₓ t + Фₓ)
y (t) = A_y cos (w_y t + Ф_y)
we substitute
R² = Aₓ² cos² (wₓ t + Фₓ) + A_y² sin² w_y t + Ф_y)
for this expression to be a circle it must meet
Aₓ = A_y = A
wₓ = w_y = w
Фₓ = Ф_y = Ф
with these expressions
R² = A² [cos² (w t + Ф) + sin² (wₓ t + Фₓ) ]
use the trigonometry relationship
cos² θ + sin² θ = 1
R² = A²
Therefore, it is fulfilled that it is a circle whose radius is equal to the amplitude of the movement
17
If 225 grams of water is to be heated from 25.0°C to 100.0°C to make a cu
tea, how much heat must be added? The specific heat of water is 4.18 J/g.
(5 Points)
63536)
70538)
117562)
705)
Answer:
Heat energy required (Q) = 70,537.5 J
Explanation:
Given:
Mass of water (m) = 225 grams
Initial temperature of water = 25.0°C
Final temperature of water = 100.0°C
Specific heat of water (c) = 4.18 J/g
Find:
Heat energy required (Q)
Computation:
Change in temperature Δt = Final temperature of water - Initial temperature of water
Change in temperature Δt = 100 - 25
Change in temperature Δt = 75°C
Using Heat energy formula
Q = (m)(c)(Δt)
Heat energy required (Q) = (225)(4.18)(75)
Heat energy required (Q) = 70,537.5 J
Can you help with these physics questions about motion? Please!!!!
Answer:
Explanation:
5-) in the 1st system the right side is heavier, the system is moving in that way with a 9.8k m^2/s
in the 2nd system right side is heavier too, the system is moving in that way with a 9.8k m^2/s
in the 3rd system both sides got the same weight so the system isn't moving in anyway. 0 m^2/s
A 0.2 kg ball is charged up to a net charge of Q, and is then suspended on a 0.25 m string in a uniform horizontal electric field strength of your [E=Birth month N/C] , Choose an angle of your choice at which the ball comes to rest =(30, 20,45 deg) from the vertical. What is the charge on the ball?
[tex]{T sin \theta}[/tex]Answer:
q = 27.16 C
Explanation:
For this exercise we use the equations of equilibrium. Let's set a reference system with the x-axis horizontally.
X axis
F_e - Tₓ = 0
Axis y
T_y -W = 0
let's use trigonometry
cos θ = T_y / T
sin θ= Tx / T
T_y = T cos θ
Tₓ = T sin θ
Axis y
T cos θ = W
T = mg / cos θ
X axis
F_e = T sin θ
qE = T sin θ
q = [tex]\frac{T sin \theta}{E}[/tex]
q = [tex]\frac{mg}{cos \theta } \frac{sin \thrta }{E}[/tex]
q = [tex]\frac{mg}{E} tan \theta[/tex]
in the exercise they indicate that the electric field is the month of birth E = 8 N / C and the angle tea = 30º
let's calculate
q = 0.2 9.8 8 / tan 30
q = 27.16 C
In one cycle of any heat engine
A. the net work done is larger than the heat exhausted.
B. more heat flows from the engine than enters the engine.
C. The internal energy of the engine does not change.
D. the net heat flow is zero.
A 16 lb weight stretches a spring 6 inches in equilibrium. It is attached to a damping mechanism with constant c. Find all values of c such that the free vibration of the weight has infinitely many oscillations.
Answer:
[tex]-8<c<8[/tex]
Explanation:
Given data:
Weight W = 16 lb
length l = 6/12 = 0.5 ft
hence, spring constant k = W/l = 16/0.5 = 32 lb/ft
The equation of motion of spring is
[tex]mx''+cx+kx=0\\0.5x''+cx'+32x=0[/tex]
the auxiliary equation can be written as
[tex]0.5r^2+cr+32=0\\r^2+2cr+64=0[/tex]
The discriminate of equation is
[tex]D =(2c)^2+-4(1)(64)\\=4(c^2-64)[/tex]
To get the value of the damping constant,
[tex]D<0\\4(c^2-64)<0\\c>-8, c<8\\-8<c<8[/tex]
PLEASE HELP 50 POINTS SPACE QUESTION
Explain how we know that the distance to the Sun is NOT the reason for seasons.
Earth's distance from the sun doesn't change enough to cause seasonal differences. Instead, our seasons change because Earth tilts on its axis.
hope it helps.
mc2
Describe the process of nuclear fission and how the famous equation E
relates to this process.
frfyuegffffjhAnswer:
frjhgfjgresjytgfejygfjse
Explanation:
which instrument is accurate in measuring the dimensions of an object
Vernier Caliper
Vernier Caliper
It is counted in the list of quality measuring instruments, which are used to measure small parameters with high accuracy. It has got two different jaws to measure outside and inside dimensions of an object. It can be a scale, dial or digital type Vernier calliper
Answer:
Vernier Caliper
It is counted in the list of quality measuring instruments, which are used to measure small parameters with high accuracy.
A car starts from rest and goes down a slope with a constant
acceleration of 5 m/s2
. After 5 s the car reaches the bottom of the hill. Its
speed at the bottom of the hill, in meters per second, is:
Answer:
25m/s
Explanation:
here we use 1st equation of motion
then we find this ans
Questlon 3 of 25
What is the magnification of a real image if the image is 15.0 cm from a lens
d;
and the object is 60.0 cm from the lens? Use the equation m=--
d.
A. -0.25
B. -4.0
C. 4.0
O D. 0.25
what is the main cause of the seasons
equivalent resistance:
What is the equivalent resistance between points P & Q?
(None of the resistors are the same and the wires are without resistors.)
Answer:
equivalent register what is the equivalent resistance between points P and Q no knows registers are the same and the virus faila
A boy weighs 50 kg and is running with 225 J of energy, what is his velocity?
What does the transfer of energy have to do with natural disasters?
Answer: When an earthquake occurs energy is transferred, from where the rocks break, and travels throughout the world. The bigger the quake the further from the epicentre the waves will travel. There are four types of earthquake wave generated during an earth quake
Explanation:
The intensity of a natural disaster can be determined by the amount of energy transferred due to it.
What is meant by natural disaster ?Natural disasters include calamities with atmospheric, geological, and hydrological causes (such as droughts, earthquakes, floods, hurricanes, and landslides), which can result in fatalities, property damage, and social and environmental disturbance.
Here,
Internal and external forces work together to create natural disasters. The first is internal forces that are caused by the earth's internal heat energy and result in geologic hazards including earthquakes, volcanoes, and tsunamis.
Energy is transferred during an earthquake and propagates throughout the globe from the point at which the rocks split. The waves' distance from the epicenter increases with the size of the earthquake.
During an earthquake, four different kinds of seismic waves are produced. They transfer energy out of the earthquake's epicentre.
Hence,
The intensity of a natural disaster can be determined by the amount of energy transferred due to it.
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Which of the following is the type of rock
layer disturbance that occurs when
molten rock squeezes into existing rock?
A. rock cycling
B. superpositioning
C. tilting
D. intrusion
Answer:
d. intrusion
Explanation:
An intrusion is molten rock from the Earth's interior that squeezes into existing rock and cools. Folding Folding occurs when rock layers bend and buckle from Earth's internal forces.
What is the wavelength associated with 0.113kg ball traveling with velocity of 43 m/s?
Answer:
Wavelength = 1.36 * 10^{-34} meters
Explanation:
Given the following data;
Mass = 0.113 kg
Velocity = 43 m/s
To find the wavelength, we would use the De Broglie's wave equation.
Mathematically, it is given by the formula;
[tex] Wavelength = \frac {h}{mv} [/tex]
Where;
h represents Planck’s constant.
m represents the mass of the particle.
v represents the velocity of the particle.
We know that Planck’s constant = 6.6262 * 10^{-34} Js
Substituting into the formula, we have;
[tex] Wavelength = \frac {6.6262 * 10^{-34}}{0.113*43} [/tex]
[tex] Wavelength = \frac {6.6262 * 10^{-34}}{4.859} [/tex]
Wavelength = 1.36 * 10^{-34} meters
what Sport is similar to Ulama
Fossil fuels can be replaced.
Yet, they are considered
nonrenewable. Why?
A. Fossil fuels only take a few years to
replenish.
& Dirt
al
B. Fossil fuels take millions of years to
replenish.
C. Fossil fuels can never be replenished.
Silt
What are the features of nanotechnology?
Answer:
Characteristics of Nanotechnology
Explanation:
Nanotechnology deals with putting things together atom by atom and with structures so small they are invisible to the naked eye. It provides the ability to create materials, devices and systems with fundamentally new functions and properties
A constant applied force Fp of 11.0 N pushes a box with a mass=7 kg a distance x=15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is .110. Assuming the box starts from the rest, what is the final velocity vf of the box at 15.0 m point? If there were no friction between the box and the floor, what applied force Fnew would give the box the same final velocity?
We have that for the Question " constant applied force Fp of 11.0 N pushes a box with a mass=7 kg a distance x=15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is .110." it can be said that
the final velocity vf is
[tex]vf=3.83m/s[/tex]
and the applied force Fnew is
[tex]F_{new}=3.43N[/tex]
From the question we are told
A constant applied force Fp of 11.0 N pushes a box with a mass=7 kg a distance x=15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is .110. Assuming the box starts from the rest, what is the final velocity vf of the box at 15.0 m point? If there were no friction between the box and the floor, what applied force F new would give the box the same final velocity?
Generally the equation for the Force is mathematically given as
F_p-\mu mg=ma
Therefore
11-0.110*7*9.8=7*a
a=0.49m/s^2
Using Newtons equation
v^2=u^2+2as
v^2=0+2*0.49*15
v=3.83m/s
Therefore
F=ma
F=0.49*7
F_{new}=3.43N
Therefore
the final velocity vf is
[tex]vf=3.83m/s[/tex]
and the applied force Fnew is
[tex]F_{new}=3.43N[/tex]
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An organism is composed of several organ systems. Often, the different organ systems work together towards a common purpose. For example, going for a run requires the use of several different organ systems. List two systems below and describe how they are used while running. *
Answer:
Skeletal system, muscular system
Explanation:
Skeletal system:
bones
Muscular system:
muscles
Together, they work together and create the musculoskeletal system.
Answer:
A number of body systems are used when we are running. These systems include the nervous system, skeletal system, muscular system, respiratory system and the circulatory system. When we decide to run, a signal is sent from our brain to our muscles through the nervous system. Once the signal is received, our muscles starts to contract and we start running using our legs. The process of running uses a lot of energy and this energy is provided to us by cellular respiration. We use the respiratory system to bring oxygen into the body, where it interacts with food and generates energy. The carbon dioxide produced is removed by the respiratory system. The gases are transported throughout the body by our circulatory system. Thus, a number of body systems work in conjunction to enable a simple activity like running.
Hope this helps.
1.Mention two uses of the concave mirror.
1.Discuss the theory of the two methods of determining focal length (f).
Answer:
1. telescope
2.
[tex]f = \frac{r}{2} [/tex]
[tex]f = \frac{r}{2} [/tex]f- focal length
[tex]f = \frac{r}{2} [/tex]f- focal length r- the radius of curvature of the mirror
[tex] \frac{1}{f} = \frac{1}{p} + \frac{1}{l} [/tex]
p-the distance of the object from the vertex of the mirror
l-the distance of the figure from the vertex of the mirror
I need help please!!!!!!!!!!!
Answer:
correct answer is rapid city
A car starts from rest and reaches a speed of 25m/s in 4 seconds. What is the acceleration?
Also, Calculate the distance the object traveled,
Can y’all help me with this one
Answer:
a = 6.25 m/s/s
d = 50 m
Explanation:
Given:
v1 (initial velocity)= 0 m/s (cz its at rest)
v2 (final velocity)= 25 m/s
t = 4s
a = ?
d = ?
to determine acceleration
a = (v2 - v1)/ t
= (25m/s - 0m/s)/4s
= 6.25 m/s/s
to determine distance traveled
d = 1/2(v1 + v2)t
=1/2(0m/s+25m/s)(4s)
=50 m
Answer:
Answer in explanation.
Explanation:
Using Equation
[tex]v = u + at[/tex]
where v is the final velocity
u is initial velocity
a is acceleration
t is time taken
given u = 0, v = 25, t = 4,
[tex]25 = 0 + 4a \\ 4a = 25 \\ a = 6.25 \frac{m}{ {s}^{2} } [/tex]
Now, using equation
[tex]v {}^{2} = {u}^{2} + 2as[/tex]
where v and u remains the same, a = 6.25 and s is the distance,
[tex](25) {}^{2} = \: {0}^{2} + 2(6.25)s \\ 12.5s = 625 \\ s = \frac{625}{12.5} \\ s = 50m[/tex]
As amplitude of a wave increases, the
_____ of the wave also increases.
frequency
wave speed
wavelength
energy
i think so it is frequency