A type of golf ball is tested by dropping it onto a hard surface from a height of 1 meter. The height it bounces is known to be normally distributed. A sample of 25 balls is tested and the bounce heights are given below. Use Excel to find a 95% confidence interval for the mean bounce height of the golf ball. Round your answers to two decimal places and use increasing order.
Height
81.4
80.8
84.4
85.6
82.9
76.0
80.0
83.2
80.8
79.6
82.9
83.4
82.2
86.0
76.2
84.8
82.0
76.3
77.0
75.4
82.0
79.8
80.4
86.9
82.1

Answer:

Expected Value of $2:

Expected Value of $2:

Win, 0.3333 x $3 = $1

Plus

Loss, 0.6667 x -$2 = -$1.33

Expected value = ($0.33)

Step-by-step explanation:

Probability of a win = 2/6 = 0.3333

Probability of a loss = 4/6 = 0.6667

Expected Value of $2:

Win, 0.3333 x $3 = $1

Plus

Loss, 0.6667 x -$2 = -$1.33

Expected value = ($0.33)

The casino game player's expected value is computed by multiplying each of the possible outcomes by the likelihood (probability) of each outcome and then adding up the values.  The sum of the values is the expected value, which amounts to a loss of $0.33.

Answer:

25872 ways

Step-by-step explanation:

We're choosing 5 women from a group of 11 and 3 men from a group of 8. We don't care about what order they are picked and so we'll use the combination formula, which is:

n!/(k!)(n-k)! with n as population and k as picks.

We'll multiply the results together. (8! / (3!)(8-3)!) * (11! / (5!)(11-5)!)

That equals: (8! / (3!)(5!) ) * (11! / (5!)(6!)) = 40320/(6x120) * 39916800/ (120x720)

56 * 462 = 25872

Answer:

26^7=8 031 810 176

Step-by-step explanation:

The word has 7 letters. So the word have 7 places where any of 26 letters can be placed.

Any of 26 letters can stay at 1st place

Any of 26 letters can stay at 2-nd place (because letters can be repeated)

Any of 26 letters can stay at 3rd place  

Any of 26 letters can stay at 4th place

Any of 26 letters can stay at 5th place

Any of 26 letters can stay at 6th place

Any of 26 letters can stay at 7th place  

So N= 26*26*26*26*26*26*26=26^7=8 031 810 176

Answer:

4 2/3 :)

Step-by-step explanation:

The total paint in the bucket in the simplified mixed fraction is [tex]6\frac{2}{3}[/tex] pints.

A fraction is written in the form of p/q, where q ≠ 0.

Fractions are of two types they are proper fractions in which the numerator is smaller than the denominator and improper fractions where the numerator is greater than the denominator.

Given, A housepainter mixed [tex]3\frac{1}{2}[/tex] pints of blue paint in a bucket with [tex]1\frac{1}{6}[/tex] pints of white paint.

So, The total paint in the bucket is the sum of the pints of both paints which

is, = [tex](3\frac{1}{2} + 1\frac{1}{6})[/tex] pints.

[tex]= (\frac{7}{2} + \frac{7}{6})[/tex] pints.

[tex]= \frac{21 + 7}{6}[/tex] pints.

[tex]= \frac{28}{6}[/tex] pints.

[tex]= 6\frac{2}{3}[/tex] pints.

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Answer:

B. Square both sides of the equation.

Step-by-step explanation:

You cannot do anything to the equation unless you square both sides to eliminate the square root on the left (squaring each individual term of the equation does not help; you need to square the entire square root to eliminate it).

Hope this helps!

Answer:

18.9 units of fencing

Step-by-step explanation:

First find the perimeter

P = 2(l+w)

P = 2( 2.5+1.28)

P = 2( 3.78)

P =7.56m

We need 2.5 units of fencing for each meter

Multiply by 2.5

7.56*2.5

18.9 units of fencing

Answer:

Julio needs to purchase 18.9 units of fencing.

Step-by-step explanation:

I meter of the perimeter accounts for 2.5 units of fencing. Respectively 2 meters account for 2 times as much, and 3 meters account for 3 times as much of 2.5 units. Therefore, if we determine the perimeter of this rectangular garden, then we can determine the units of fencing by multiplying by 2.5.

As you can see this is a 2.5 by 1.28 garden. The perimeter would be two times the supposed length, added to two times the width.

2.5 x 2 + 1.28 x 2 = 5 + 2.56 = 7.56 - this is the perimeter. The units of fencing should thus be 7.56 x 2.5 = 18.9 units, or option d.

Answer:

Time taken by Stephen = 162 seconds

Step-by-step explanation:

Stephan gathered data which fits in the line of best fit,

y = -2.1x + 565.6

Where x represents the age (in months)

And y represents the time (in seconds) taken by Stephen to run two laps on the track.

Time taken to run 2 laps at the age of 192 months,

By substituting x = 192 months,

y = -2.1(192) + 565.6

  = -403.2 + 565.6

  = 162.4 seconds

  ≈ 162 seconds

Therefore, time taken by Stephen to cover 2 laps was 162 seconds when he was 192 months old.

Answer:

4x² + 30x - 2 = 0

Step-by-step explanation:

Given:

Area = 58 square feet

Width = 7 feet

Length = 8 feet

Since the area is 58, writing the equation, we have:

(8 + 2x)(7 + 2x) = 58

Now expand the equation:

56 + 16x + 14x + 4x² = 58

56 + 30x + 4x² = 58

Collect like terms:

30x + 4x² + 56 - 58 = 0

30x + 4x² - 2 = 0

Rearrange the equation to a proper quadratic equation:

4x² + 30x - 2 = 0

The quadratic equation that can be used to determine the thickness of the frame, x is 4x² + 30x - 2 = 0

The company must produce and sell 350 dishwashers in order to maximize profit.

To determine the number of dishwashers the company must produce and sell in order to maximize profit, we need to find the value of x that corresponds to the maximum point of the profit function.

The profit (P) is given by the equation:

P(x) = Revenue - Cost

The revenue is calculated by multiplying the price per dishwasher (p) by the number of dishwashers sold (x):

Revenue = p * x

The cost is given by the function C(x):

Cost = C(x)

Therefore, the profit function can be expressed as:

P(x) = p * x - C(x)

Substituting the given expressions for p and C(x):

P(x) = (420 - 0.3x) * x - (5000 + 0.3x²)

Expanding and simplifying the equation:

P(x) = 420x - 0.3x² - 5000 - 0.3x²

Combining like terms:

P(x) = -0.6x² + 420x - 5000

To find the value of x that maximizes profit, we need to find the vertex of the quadratic function. The x-coordinate of the vertex can be determined using the formula:

x = -b / (2a)

In our case, a = -0.6 and b = 420:

x = -420 / (2 * -0.6)

x = -420 / (-1.2)

x = 350

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350 dishwashers must the company produce and sell in order to maximize profit.

Maxima means a point at which the function attains the maximum value.

Given the following information:

Price per dishwasher, p = 420 - 0.3x

Total cost of producing x dishwashers, C(x) = 5000 + 0.3x2

Profit= Total Selling price- Total Cost Price

Total Selling price of x dishwasher, S.P= xp

S.P=x(420 - 0.3x)

S.P=420x - 0.3x²

Profit= 420x - 0.3x² - ( 5000 + 0.3x²)

Profit= 420x - 0.3x² - 5000 - 0.3x²

Profit=  -0.6x²+420x-5000

So, profit, f(x)=-0.6x²+420x-5000

To determine the value of x so that maximum profit is possible:

1. Calculate the first derivative of profit function and calculate the value of x by equating it to zero.

2. Select that value of x for which the profit function attains the maximum value, to check the maxima calculate 2nd derivative, if it gives a negative value for the value of x. Then, x is the point of maxima for the given function.

[tex]f(x)=-0.6x^2+420x-5000\\f\prime(x)=-1.2x+420\\f\prime(x)=0\\-1.2x+420=0[/tex]

Calculating the value of x by transposing,

x=420/1.2

x=350

To check maxima, calculating second derivative.

[tex]f\prime(x)=-1.2x+420=0\\f\prime\prime(x)=-1.2[/tex]

2nd derivative is negative, it means that x=350 is the point of maxima.

Thus, a company must produce and sell 350 dishwashers in order to maximize profit.

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Answer:

[tex]\boxed{15 \ dime \ and \ 10 \ nickel \ coins}[/tex]

Step-by-step explanation:

1 dime = 10 cents

1 nickel = 5 cents

So,

If there are 15 dimes

=> 15 dimes = 15*10 cents

=> 15 dimes = 150 cents

=> 15 dimes = $1.5

Rest is $0.5

So, for $0.5 we have 10 nickels coins

=> 10 nickels = 10*5

=> 10 nickels = 50 cents

=> 10 nickel coins = $0.5

Together it makes $2.00

Answer:

(a) 5/7 chance

(b) 2/7 chance

(c) 5/7 chance

Step-by-step explanation:

Event X: There are 3 letters that come before "D". A, B, and C. There is a 3 out of 7 chance of picking one of those letters. (3/7)

Event Y: There are 4 letters in "C A G E". Those 4 letters are in the 7 first letters of the alphabet meaning that they are in our pile of tiles. There is a 4 out of 7 chance of picking one of those letters. (4/7)

(a) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a 5/7 chance of either Event X or Event Y happening since tiles "A" and "C" are included in both events.

(b) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a 2/7 chance of both X and Y happening since there are only 2 tiles that are the same in both events, "A" and "C". (We are only allowed to pick one tile)

(c) The complement of Event Y is 1-4/7=5/7 chance.

Answer:

a) 5/7 chance

(b) 2/7 chance

(c) 5/7 chance

Step-by-step explanation:

Event X: There are 3 letters that come before "D". A, B, and C. There is a 3 out of 7 chance of picking one of those letters. (3/7)

Event Y: There are 4 letters in "C A G E". Those 4 letters are in the 7 first letters of the alphabet meaning that they are in our pile of tiles. There is a 4 out of 7 chance of picking one of those letters. (4/7)

(a) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a 5/7 chance of either Event X or Event Y happening since tiles "A" and "C" are included in both events.

(b) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a 2/7 chance of both X and Y happening since there are only 2 tiles that are the same in both events, "A" and "C". (We are only allowed to pick one tile)

(c) The complement of Event Y is 1-4/7=5/7 chance.

Answer:

25 students

Step-by-step explanation:

Given the equation of the best line of fit, [tex] y = 0.677x + 1.77 [/tex] , the number of students predicted to be in the matching band, if we have 35 students in the concert band, can be approximated by plugging in 35 as "x" in the equation of the best line of fit, and solve for "y". y would give us the predicted number of students to expect in the marching band.

[tex] y = 0.677(35) + 1.77 [/tex]

[tex] y = 23.695 + 1.77 [/tex]

[tex] y = 25.465 [/tex]

The approximated number of to be in the marching band, with 35 students in the concert band is roughly 25 students.

Answer:25 students

Step-by-step explanation:

Answer:

[tex]\boxed{\sf B \ and \ C}[/tex]

Step-by-step explanation:

The triangle is a right triangle.

We can use trigonometric functions to solve.

[tex]\sf sin(\theta)=\frac{opposite}{hypotenuse}[/tex]

[tex]\sf sin(60)=\frac{5.2}{KL}[/tex]

[tex]\sf KL=\frac{5.2}{sin(60)}[/tex]

[tex]\sf sin(90-60)=\frac{3}{KL}[/tex]

[tex]\sf KL=\frac{3}{sin(90-60)}[/tex]

Answer:

853.8cm^3

Step-by-step explanation:

[tex]h = 9.5cm\\d = 1.5cm + 9.5 = 10.7\\r =d/2=10.7/2=5.35\\\\V = \pi r^2 h\\V = 3.14 \times (5.35)^2 \times 9.5\\\\V =853.8 cm^3[/tex]

Answer:

2π radians

Step-by-step explanation:

Answer:

y is the range

Step-by-step explanation:

the y is the range

x isthe domain

Answer:

b. -1/6

Step-by-step explanation:

slope = (difference in y)/(difference in x)

slope = (1 - 0)/(-2 - 4) = 1/(-6) = -1/6

Answer:

m = -1/6 = B

Step-by-step explanation:

[tex]m = \frac{y_2-y_1}{x_2-x_1} \\ x_1=4\\ y_1=0\\ x_2=-2\\y_2=1.\\m = \frac{1-0}{-2-4} \\m = \frac{1}{-6}[/tex]

Answer:

0.65463

Step-by-step explanation:

From the given question:

It is stated that 2% of the parts are defective (D) out of 50 parts

Therefore the probability of the defectives;

i.e  p(defectives) = [tex]\dfrac{N(D)}{N(S)}[/tex]

p(defectives) = [tex]\dfrac{2}{50}[/tex]

p(defectives) = 0.04

The probability of the failure is the P(Non-defectives)

p(Non-defectives) =  1 - P(defectives)

p(Non-defectives) =  1 - 0.04

p(Non-defectives) =  0.96

Also , Let Y be the number of non -defective out of the 52 stock parts.

and we need Y ≥ 50

P( Y ≥ 50) , n = 52 , p = 0.96

P( Y ≥ 50) = P(50 ≤ Y ≤ 52) = P(Y = 50, 51, 52)

= P(Y = 50) + P(Y =51) + P(Y=52)    (disjoint events)

P(Y = 50) = [tex](^{52}_{50}) ( 0.96)^{50}(1-0.96)^2[/tex]

[tex]P(Y = 50) = 1326 (0.96)^{50}(0.04)^2[/tex]

P(Y = 50) = 0.27557

P(Y = 51) =[tex](^{52}_{51}) ( 0.96)^{51}(1-0.96)^1[/tex]

[tex]P(Y = 51) = 52(0.96)^{51}(0.04)^1[/tex]

P(Y = 51) = 0.25936

(Y = 52) =[tex](^{52}_{52}) ( 0.96)^{52}(1-0.96)^0[/tex]

[tex]P(Y = 52) = 1*(0.96)^{52}(0.04)^0[/tex]

P(Y = 52) = 0.1197

∴

P(Y = 50) + P(Y =51) + P(Y=52) = 0.27557 + 0.25936 + 0.1197

P(Y = 50) + P(Y =51) + P(Y=52) = 0.65463

Answer: 752

Step-by-step explanation:

Given that,

Margin of error = 3% = 0.03

confidence level = 90% = 0.90

therefore from the z-table

z = 1.645

Now since no prior estimate of p is given, so we say p = 0.5

Sample size required will be

n = 1.645² × 0.5 ×(1-0.5) / 0.03² = 751.67

n = 751.67 ≈ 752

[tex]|\Omega|=2\cdot6\cdot52=624\\|A|=1\cdot3\cdot16=48\\\\P(A)=\dfrac{48}{624}=\dfrac{1}{13}[/tex]

Answer:

1/13

Step-by-step explanation:

Answer:

the percentage of people who have an IQ between 115 and 140 is 16.79%

Step-by-step explanation:

From the information given:

We are to  determine the percentage of people who have an IQ between 115 and 140.

i.e

P(115 < X < 140) = P( X  ≤ 140) - P( X  ≤ 115)

[tex]P(115 < X < 140) = P( \dfrac{X-100}{\sigma}\leq \dfrac{140-100}{16})-P( \dfrac{X-100}{\sigma}\leq \dfrac{115-100}{16})[/tex]

[tex]P(115 < X < 140) = P( Z\leq \dfrac{140-100}{16})-P( Z\leq \dfrac{115-100}{16})[/tex]

[tex]P(115 < X < 140) = P( Z\leq \dfrac{40}{16})-P( Z\leq \dfrac{15}{16})[/tex]

[tex]P(115 < X < 140) = P( Z\leq 2.5)-P( Z\leq 0.9375)[/tex]

[tex]P(115 < X < 140) = P( Z\leq 2.5)-P( Z\leq 0.938)[/tex]

From Z tables :

[tex]P(115 < X < 140) = 0.9938-0.8259[/tex]

[tex]P(115 < X < 140) = 0.1679[/tex]

Thus; we can conclude that the percentage of people who have an IQ between 115 and 140 is 16.79%

Using the normal distribution, it is found that 82.02% of people who have an IQ between 115 and 140.

In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

In this problem:

The proportion of people who have an IQ between 115 and 140 is the p-value of Z when X = 140 subtracted by the p-value of Z when X = 115, hence:

X = 140:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{140 - 100}{16}[/tex]

[tex]Z = 2.5[/tex]

[tex]Z = 2.5[/tex] has a p-value of 0.9938.

X = 115:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{115 - 100}{16}[/tex]

[tex]Z = -0.94[/tex]

[tex]Z = -0.94[/tex] has a p-value of 0.1736.

0.9938 - 0.1736 = 0.8202.

0.8202 = 82.02% of people who have an IQ between 115 and 140.

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Answer:

x=5y-3

Step-by-step explanation:

[tex]4x+12=20y\\4x=20y-12\\x=\frac{20y-12}{4} \\x=\frac{20y}{4}- \frac{12}{4} \\x=5y-3[/tex]

Answer:

This question is incomplete, i will answer it as:

"The initial population of a town is ​A, and it grows with a doubling time of 10 years. What will the population be in X ​years?"

Ok, the growth of a population usually is an exponential growth, so we can write this as:

P(t) = A*exp(r*t)

Where A is the initial population.

r is the rate of growth, and t is our variable, in this case, number of years.

Now we know that when t = 10y, the population doubles, so we should have:

P(10y) = 2*A = A*exp(r*10y)

2 = exp(r*10)

ln(2) = r*10

ln(2)/10 = r = 0.069.

Then our equation is:

P(t) = A*exp(0.069*t)

Now, if we want to know the population in X years, we need to replace the variable t by X

P(t = X) = A*exp(0.069*X)

Answer:

The demand function is  [tex]\mathbf{D(x) = 1200(\sqrt{25-x^2})+ 124000}[/tex]

Step-by-step explanation:

A firm has the​ marginal-demand function [tex]D' x = \dfrac{-1200}{\sqrt{25-x^2 } }[/tex].

Find the demand function given that D = 16,000 when x = $4 per unit.

What we are required to do  is to find the demand function D(x);

If we integrate D'(x) with respect to x ; we have :

[tex]\int\limits \ D'(x) \, dx = \int\limits{\dfrac{-1200 x}{\sqrt{25-x^2}} } \, dx[/tex]

[tex]D(x) = \int\limits{\dfrac{-1200 x}{\sqrt{25-x^2}} } \, dx[/tex]

Let represent   t  with [tex]\sqrt{25-x^2}}[/tex]

The differential of t with respect to x is :

[tex]\dfrac{dt}{dx}= \dfrac{1}{2 \sqrt{25-x^2}}}(-2x)[/tex]

[tex]\dfrac{dt}{dx}= \dfrac{-x}{ \sqrt{25-x^2}}}[/tex]

[tex]{dt}= \dfrac{-xdx}{ \sqrt{25-x^2}}}[/tex]

replacing the value of  [tex]\dfrac{-xdx}{ \sqrt{25-x^2}}}[/tex]  for dt in   [tex]D(x) = \int\limits{\dfrac{-1200 x}{\sqrt{25-x^2}} } \, dx[/tex]

So; we can say :

[tex]D(x) = \int\limits{\dfrac{-1200 x}{\sqrt{25-x^2}} } \, dx[/tex]

[tex]D(x) = 1200\int\limits{\dfrac{- x}{\sqrt{25-x^2}} } \, dx[/tex]

[tex]D(x) = 1200\int\limits \ dt[/tex]

[tex]D(x) = 1200t+ C[/tex]

Let's Recall that :

t  = [tex]\sqrt{25-x^2}}[/tex]

Now;

[tex]\mathbf{D(x) = 1200(\sqrt{25-x^2}})+ C}[/tex]

GIven that:

D = 16,000 when x = $4 per unit.

i.e

D(4) = 16000

SO;

[tex]D(x) = 1200(\sqrt{25-x^2}})+ C[/tex]

[tex]D(4) = 1200(\sqrt{25-4^2}})+ C[/tex]

[tex]D(4) = 1200(\sqrt{25-16}})+ C[/tex]

[tex]D(4) = 1200(\sqrt{9}})+ C[/tex]

[tex]D(4) = 1200(3}})+ C[/tex]

16000 = 1200 (3) + C

16000 = 3600 + C

16000 - 3600 = C

C = 12400

replacing the value of C = 12400 into [tex]\mathbf{D(x) = 1200(\sqrt{25-x^2}})+ C}[/tex], we have:

[tex]\mathbf{D(x) = 1200(\sqrt{25-x^2})+ 124000}[/tex]

∴ The demand function is  [tex]\mathbf{D(x) = 1200(\sqrt{25-x^2})+ 124000}[/tex]

Answer:

The full production costs are:

ABC = $22,900,000

PQR = $1,700,000

Step-by-step explanation:

Traditional costing method is a costing method that allocates or applies overhead based on a particular metric determined by a company. It therefore add both direct cost of production and production overheads absorbed to obtain the full cost of production.

Since production overheads in this question is absorbed on demand sales basis, the full production costs for ABC and PQR can be computed as follows:

ANZ Corporation

Computation of Full Production Costs

Particulars                                      ABC                 PQR    

Sales demand                             30,000             15,000

Cost                                                   $                        $    

Direct cost:

Direct materials cost (w.1)        1,350,000           900,000

Direct labor cost (w.2)                900,000          600,000  

Total direct cost                     22,500,000        1,500,000

Indirect cost:

Production overhead (w.3)        400,000          200,000

Full production cost            22,900,000        1,700,000

Workings:

w.1: Computation of direct material cost

Direct material cost = Direct material cost per unit * Sales demand

Therefore;

ABC Direct material cost = $45 * 30,000 = $1,350,000

PQR Direct material cost = $60 * 15,000 = $900,000

w.2: Computation of direct labor cost

Direct labor cost = Direct labor cost per unit * Sales demand

Therefore;

ABC Direct material cost = $30 * 30,000 = $900,000

PQR Direct material cost = $40 * 15,000 = $600,000

w.3: Allocation of production overhead

Production overheads allocated to a model = Production overheads * (Model's Sales Demand / Total Sales demand)

Total Sales demand = 30,000 + 15,000 = 45,000

Therefore, we have:

Production overhead allocated to ABC = $600,000 * (30,000 / 45,000) = $400,000

Production overhead allocated to PQR = $600,000 * (15,000 / 45,000) = $200,000

Answer:

Step-by-step explanation:

Fog=2(g)+1

2(3x+2+4)+1

2{3x+6)+1

6x+12+1

=6x+13

Fog(-2)=6(-2)+13

-12+13

=1

Gof=3(f)+2+4

=3(2x+1)+6

6x+3+6

=6x+9

Gof(-2)=6(-2)+9

-12+9

=-3

Answer:

converse of alternate exterior angle theorem

Step-by-step explanation:

um im not sure if i should explain the full proof but

Answer:

11 / 12 or 0.9167

Step-by-step explanation:

Given:

3/4 + 1/6

Find:

Value with expression

Computation:

"3/4 added to number 1/6"

3/4 + 1/6

By taking LCM

[9 + 2] / 12

11 / 12 or 0.9167

Answer:

a)  [tex]\frac{2}{3} \,\frac{lb}{bread}[/tex]

b)  [tex]1\frac{1}{4} \,\frac{in}{domino}[/tex]

Step-by-step explanation:

Part a:

every 4 lbs of flour, she makes 6 loaves of bread. this as a rate in simplest fraction form is:

[tex]\frac{4}{6} \,\frac{lb}{bread} = \frac{2}{3} \,\frac{lb}{bread}[/tex]

Part b:

every 10 inches , 8 dominoes can be placed. then the rate can be written as:

[tex]\frac{10}{8} \,\frac{in}{domino} = \frac{5}{4} \,\frac{in}{domino} =1\frac{1}{4} \,\frac{in}{domino}[/tex]