Answer:
[tex]y=\frac{1}{3} x+7[/tex]
Step-by-step explanation:
We need to find the equation of a line perpendicular to [tex]y=-3x-3[/tex], which passes through the point (-3, 6).
Recall that a line perpendicular to a line of the form: [tex]y=mx+b[/tex], must have a slope which is the opposite of the reciprocal of the slope of the original line. that is, a slope of the form;
[tex]slope=-\frac{1}{m}[/tex]
Then, in our case, since the original line has slope "-3", a perpendicular line to it should have a slope given by:
[tex]slope=-\frac{1}{-3} =\frac{1}{3}[/tex]
We now know the slope, and also a point for this new line, so we use the point-slope form of a line:
[tex]y-y_0=m_\perp\,(x-x_0)\\y-6=\frac{1}{3} (x-(-3))\\y-6=\frac{1}{3} x+\frac{3}{3} \\y-6=\frac{1}{3} x+1\\y=\frac{1}{3} x+7[/tex]
Help! Pls pls pls! Fast!
it is transformed [tex]|x|[/tex] function. moved down by and right by 1 unit,
so $y=|x-1|-1$
In the figure, m∠CED = m∠A. Complete the following proportions: ED/ A F= CE/? = CD/?
Answer:
The completed proportions are;
ED/A_F = CE/CA = CF/CD
Step-by-step explanation:
The given m∠CED = m∠A
∴ Angle ∠CDE = Angle ∠A_FC, (corresponding angles)
Angle ∠ECD = Angle ∠ACF (reflexive property)
Triangle ΔDCE is similar to triangle ΔACF (Angle Angle Angle (AAA) similarity)
In triangle ΔDCE and triangle ΔACF
m∠A is bounded by CA and A_F
m∠CED is bounded by CE and ED
∠DCE is bounded by CE and DE
∠C is bounded by CA and CF
Based on the orientation of the two triangles, we have
ED is the corresponding side to A_F, CD is the corresponding side to CF, CE is the corresponding side to CA
Therefore, we have;
ED/A_F = CE/CA = CF/CD.
Which is a diagonal through the interior of the cube? Side A H Side B E Side C H Side F G
Answer:
Option (A)
Step-by-step explanation:
Every cube has 8 vertices and 6 faces.
Cube shown in the picture attached,
Diagonal through interior of the given cube will be the segments joining the vertices A-H, G-B, C-F and D-E.
Therefore, from the given options diagonal of the interior of the cube will be Side AH.
Option A will be the answer.
Answer:
the awnser is A
Step-by-step explanation:
i took a quiz
A company offering online speed reading courses claims that students who take their courses show a 5 times (500%) increase in the number of words they can read in a minute without losing comprehension. A random sample of 100 students yielded an average increase of 415% with a standard deviation of 220%. Calculate a 95% confidence interval for the average increase in number of words students can read in a minute without losing comprehension. Choose the closest answer.
Answer:
C.I = (371.88 , 458.12)
Step-by-step explanation:
Given that:
sample size n = 100
sample mean [tex]\overline x =[/tex] 415
standard deviation = 220
The objective is to calculate the 95% confidence interval for the average increase in number of words students who can read in a minute without losing comprehension.
At 95% confidence interval; level of significance ∝ = 1 - 0.95
level of significance ∝ = 0.05
[tex]z_{\alpha/2} = 0.05/2[/tex]
[tex]z_{\alpha/2} = 0.025[/tex]
The critical value at [tex]z_{\alpha/2} = 0.025[/tex] is 1.96
C.I = [tex]\overline x \pm M.O,E[/tex]
C.I = [tex]\overline x \pm z_{\alpha/2} \dfrac{\sigma }{\sqrt{n}}[/tex]
C.I = [tex]415\pm 1.96 \dfrac{220 }{\sqrt{100}}[/tex]
C.I = [tex]415\pm 1.96 *\dfrac{220 }{10}[/tex]
C.I = [tex]415\pm 1.96 *22[/tex]
C.I = [tex]415\pm 43.12[/tex]
C.I = (371.88 , 458.12)
Urgent help I need it right now!!!!
Answer:
[tex]\boxed{\sf 30 \ bean \ cans}[/tex]
Step-by-step explanation:
The ratio of bean cans to corn cans is 6 : 7
Given that Corn cans = 35
Let the bean can be x
So,
The proportion for it will be:
6 : 7 = x : 35
Product of Means = Product of Extremes
7 * x = 6 * 35
7x = 210
Dividing both sides by 7
x = 30
So, 30 bean cans have to be put on the table to hold the needed ratio
The roots of 100x2 – 20x + 1 = 0 is:
Answer:
x = 0.1Step-by-step explanation:
[tex]100x^2-20x+1=0\\\\(10x)^2-2\cdot10x\cdot1+1^2=0\\\\(10x-1)^2=0\\\\10x-1=0\\\\10x=1\\\\x=0.1[/tex]
discriminant of xsqaure - 1/2x +1/2=0
Answer:
[tex]\boxed{D = 15/8}[/tex]
Step-by-step explanation:
=> [tex]x^2-\frac{1}{2} x +\frac{1}{2} = 0[/tex]
Comparing it with the standard form of quadratic equation [tex]ax^2+bx+c = 0,[/tex] we get
a = 1, b = -1/2 and c = 1/2
Discriminant = [tex]b^2-4ac[/tex]
[tex]D = (-1/2)^3+4(1)(1/2)\\D = -1/8 + 2\\D = \frac{-1+16}{8} \\D = \frac{15}{8}[/tex]
1. A box without a top is to be made from a rectangular piece of cardboard, with dimensions 8 in. by 10 in., by cutting out square corners with side length x and folding up the sides. (a) Write an equation for the volume V of the box in terms of x. (b) Use technology to estimate the value of x, to the nearest tenth, that gives the greatest volume. Explain your process.
Step-by-step explanation:
The dimensions are (8-2x) and (10-2x) We will say the depth of the box is x. The equation we use for the volume of the box is V=x(8-2x)(10-2x)
Answer:
part b of the answer is x=1.5 inches
Step-by-step explanation:
3) In a paddling pool there are 30 floating ducks. Each duck is marked with a number on the underside. 15 are marked with the number 1, 9 are marked with the number 2 and 6 are marked with number 3. There are prizes for those who pick a duck with the number 3 on it. What is the probability of Molly picking a duck with the number 3 on it? Give your answer as a fraction in its lowest terms.
Answer: 1/5
Step-by-step explanation:
Given the following :
Total number of ducks in pool = 30
Mark 1 = 15 ducks
Mark 2 = 9 ducks
Mark 3 = 6 ducks
Probability of picking a duck with Mark 3:
Probability = (number of required outcomes / total possible outcomes)
Number of required outcomes = number of ducks with mark 3 = 6 ducks
P(picking a duck with Mark 3) = 6/30
6/30 = 1/5
= 1/5
the legnth of rectangular sheet decreases by 34.5 cm its width decreases proportionally that is by the same percentage. if the sheets original width was half of the legnth and the new (smaller) area was 1.2 m^2 what was original sheet's width
Answer:
The original width was 94.71 cm
Step-by-step explanation:
Given:
new smaller area = 1.2m^2
Decrease in length of the rectangular sheet = 34.5cm
Therefore:
1. the final width of the sheet is given as
2X^2 = 1.2 m^2
X^2 - 0.6 m^2
X^2 = 10000 * 0.6 cm
X = 77.46 cm (this is the width)
2. The length of the sheet
= 2 * 77.46
= 154.92 cm.
3. Initial length of the sheet
= 154.92 + 34.5
= 189.42 cm.
4. Initial width of the sheet ( original ).
= 189.42 / 2
= 94.71 cm.
5. Initial area of the sheet
= 94.71 * 189.92
= 17939.9 cm^2
New area of the sheet
= 79.46 * 154.92
= 12000.1 cm^2
Difference between the initial and new area
= 17939.9 - 12000.1
= 5939.86 cm^2
Percentage of area decrease
= 5939.86 ' 17939.9
= 33.1%
The graphed line shown below is y=-3x+6...Which equation, when graphed with the given equation, will form a system that has no solution?
Answer:
The equation, when graphed together with the line y=-3x +6, which will form a system of equations with no solution is y=-3(x +6), meaning the second option on the picture.
Step-by-step explanation:
hope this helps!
Answer: 2 or B
Step-by-step explanation:
What is the diameter of the circle whose center is at (6, 0) and that passes through the point (2, -3)?
Answer:
10
Step-by-step explanation:
[tex]\left(x-h\right)^{2}+\left(y-k\right)^{2}=r^2[/tex]
[tex]\left(x-6\right)^{2}+\left(y-0\right)^{2}=r^2\\[/tex]
We used (2,-3)
[tex]\left(2-6\right)^{2}+\left(-3-0\right)^{2}=25[/tex]
[tex]r^2=25\\[/tex] , so [tex]r = 5[/tex]
But this one is asking for the diameter, and to find it. It's simply 2r.
2*5 = 10
Based on your work in Question 1 through 3, what is the relationship between the radius, AB , and the tangent line, BC ? What can you conclude about any tangent line to a circle and the radius of the circle? Explain.
Without further context I can't say much other than the radius is perpendicular to the tangent. In other words, the radius and tangent line form a 90 degree angle. This is one particular radius and its not just any radius. The radius in question must have the point of tangency as its endpoint.
The radius, AB is perpendicular to the tangent line, BC so their slopes are negative reciprocals of one another. Because I generated a circle at random for this activity, this conclusion likely applies to any tangent line to a circle. In other words, the tangent line to any circle is perpendicular to the radius at their point of intersection.
PLSSSS HELP The area of a cylinder varies jointly with the radius and the height. When the radius is 3 and the height is 6 the area is 36π. Find the are when the radius is 4 and the height is 5
Answer:
167.55
Step-by-step explanation:
so it varies jointly so
A-area if cylinder
so
[tex]a \: \alpha \: \pi \: r \: ^{2} h[/tex]
so
[tex]a = k\pi \: r^{2}h[/tex]
where k is the constant
so apply the first set of values to get k=2/3
then substitute the k with the second set of values
Banita has a piece of string that is One-tenth times 7 inches long. Which fraction is equal to the length of Banita’s string?
Answer: The length is 7/10 inches.
Step-by-step explanation:
So if is says that the string is 1/10 times 7 inches long, then it represents the length of the string.
So L = [tex]\frac{1}{10}*7[/tex]
L = 7/10
Answer:
l=7/10
Step-by-step explanation:
A bag contains two red marbles, two green ones, one lavender one, five yellows, and six orange marbles. HINT [See Example 7.] How many sets of four marbles include one of each color other than lavender?
Answer: 120
Step-by-step explanation:
Given: A bag contains two red marbles, two green ones, one lavender one, five yellows, and six orange marbles.
The total number of marbles in the bag : 2+2+1+5+6=16
Now, the number of ways of selecting sets of four marbles include one of each color other than lavender is
[tex]\( C(2,1) \times C(2,1) \times C(5,1) \times C(6,1)=2 \times 2 \times 5 \times 6\)=120[/tex] [[tex]\because\ C(n,1)=n[/tex]]
Hence, the number of sets of four marbles include one of each color other than lavender = 120
2/3 divided by 5?If she walks 2/3 by another 5.
Answer:
The answer is 0.133
Step-by-step explanation:
All you have to do is take 2/3 as if it was a whole number and divide it by 5, or if you are able to use a calculator, you can just but it in as 2 divided by 3 and then divide 5 by whatever answer you get.
Answer:
Hello! 2/3 divided by 5 in fraction will be 2/15
Step-by-step explanation:
Since we have a 5 we need to change that into a fraction
5 would turn into 1/5
Now you have to multiply both of the fractions to get your answer.
2/3 x 1/5
= 2/15
(So 2/15 will be your answer.)
Hope this helps! :)
$i^{11} + i^{16} + i^{21} + i^{26} + i^{31}$[tex]$i^{11} + i^{16} + i^{21} + i^{26} + i^{31}$[/tex]
Answer:
Step-by-step explanation:
i^{11}+i^{16}+i^{21}+i^{26}+i^{31}
[tex]=(i^{2} )^5i+(i^{2} )^8 +(i^{2} )^{10} i+(i^{2} )^{13}+(i^{2} )^{15} i\\=(-1)^5 i+(-1)^8+(-1)^{10} i+(-1)^{13} +(-1)^{15} i\\=- i+1+i-1-i\\=0- i[/tex]
Una compañía sabe que si produce "x" unidades mensuales su utilidad "u" se podría calcular con la expresión: u(x)=-0.04x^2+44x-4000 donde "u" se expresa en dólares. Determine la razón del cambio promedio de la utilidad cuando el nivel de producción cambia de 600 a 620 unidades mensuales. Recuerde que la pendiente de la recta secante a la gráfica de la función representa a la razón de cambio promedio.
Answer:
The ratio of the average change in profit when the level of production changes from 600 to 620 units per month is -24 : 5.
Step-by-step explanation:
The question is:
A company knows that if it produces "x" monthly units its utility "u" could be calculated with the expression: u (x) = - 0.04x ^ 2 + 44x-4000 where "u" is expressed in dollars. Determine the ratio of the average change in profit when the level of production changes from 600 to 620 units per month. Remember that the slope of the secant line to the graph of the function represents the average rate of change.
Solution:
The expression for the utility is:
[tex]u (x) = - 0.04x ^ {2} + 44x-4000[/tex]
It is provided that the slope of the secant line to the graph of the function represents the average rate of change.
Then the ratio of the average change in profit when the level of production changes is:
[tex]\text{Average change in profit}=\frac{u(x_{2})-u(x_{1})}{x_{2}-x_{1}}[/tex]
Compute the values of u (x₁) and u (x₂) as follows:
x₁ = 600
[tex]u (x_{1}) = - 0.04x_{1} ^ {2} + 44x_{1}-4000[/tex]
[tex]= - 0.04(600) ^ {2} + 44(600)-4000\\=-14400+26400-4000\\=8000[/tex]
x₂ = 620
[tex]u (x_{2}) = - 0.04x_{2} ^ {2} + 44x_{2}-4000[/tex]
[tex]= - 0.04(620) ^ {2} + 44(620)-4000\\=-15376+27280-4000\\=7904[/tex]
Compute the average rate of change as follows:
[tex]\text{Average change in profit}=\frac{u(x_{2})-u(x_{1})}{x_{2}-x_{1}}[/tex]
[tex]=\frac{7904-800}{620-600}\\\\=\frac{-96}{20}\\\\=-\frac{24}{5}\\\\=-24:5[/tex]
Thus, the ratio of the average change in profit when the level of production changes from 600 to 620 units per month is -24 : 5.
find the distance of the line segment joining the two points (-4 /2 - /12) and (/32, 2/3)
Answer: [tex]4\sqrt{3}[/tex] .
Step-by-step explanation:
Distance formula : Distance between points (a,b) and (c,d) is given by :-
[tex]D=\sqrt{(d-b)^2+(b-a)^2}[/tex]
Distance between points [tex](-4\sqrt{2},\sqrt{12}) \text{ and }(-\sqrt{32}, 2\sqrt{3})[/tex].
[tex]D=\sqrt{(2\sqrt{3}-(-\sqrt{12}))^2+(-\sqrt{32}-(-4\sqrt{2}))}\\\\=\sqrt{(2\sqrt{3}+\sqrt{2\times2\times3})^2+(-\sqrt{4\times4\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}-\sqrt{2^2\times3})^2+(-\sqrt{4^2\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}+2\sqrt{3})^2+(-4\sqrt{2}+4\sqrt{2})^2}\\\\=\sqrt{(4\sqrt{3})^2+0}\\\\=4\sqrt{3}\text{ units}[/tex]
Hence, the correct option is [tex]4\sqrt{3}[/tex] .
10. Read the following word problem, then choose which linear equation models the problem.
The length of a rectangle is six feet more than twice the width. The rectangle’s perimeter is 84 feet. Find the width and length of the rectangle.
A. 2w + 6 + w = 84
B. 2(2w + 6) + 2w = 84
C. 2(2w +6) • (2w) = 84
D. (2w + 6) • (w) = 84
Answer:
D. ( 2w+6). (w)
i tried my best
hope this is the answer
stay at home stay safe
Please help I don't understand this at all
Answer:
Since ΔABC is equilateral, ∠ACB = 60°. Since ΔCED is isosceles (we know this because CE = ED from the graph), ∠ECD = ∠EDC from Base Angles Theorem, and since the sum of angles in a triangle is 180°, they measure (180 - 32) / 2 = 74° each. Since BCD is a straight line, it measures 180° so we can write:
60 + x + 74 = 180
134 + x = 180
x = 46°
Answer:
46 degrees
Step-by-step explanation:
Since triangle ABC is equilateral that means each angle in that triangle is 60 degrees.
We also know that for triangle ECD angle C and angle D have to be 74 degrees, because a triangle has 180 degrees in total and the only unique angle is at the top which is 32. So it is 180-32=148, than 148/2=74.
We than know that a half circle is 180 degrees aswell, so we do 180-60=120
120-74=46
what is the distance between the points (4, 5) and (10, 13) on a coordinte plane a. 12 units b. 8 units c. 10 units d. 14 units
Answer:
10 unitsOption C is the correct option
Step-by-step explanation:
Let the points be A and B
A ( 4 , 5 ) ------> ( x1 , y1 )
B ( 10 , 13 ) ------> ( x2 , y2 )
Now, let's find the distance between these points:
[tex] \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } [/tex]
plug the values
[tex] = \: \sqrt{(10 - 4) ^{2} + {(13 - 5)}^{2} } [/tex]
Calculate the difference
[tex] = \sqrt{ {(6)}^{2} + {(8)}^{2} } [/tex]
Evaluate the power
[tex] = \sqrt{36 + 64} [/tex]
Add the numbers
[tex] = \sqrt{100} [/tex]
Write the number in exponential form with. base of 10
[tex] = \sqrt{ {(10)}^{2} } [/tex]
Reduce the index of the radical and exponent with 2
[tex] = 10 \: units[/tex]
Hope this helps..
Best regards!!
A sixth-grade class is growing plants for their
science projects. Each student spent $1.00 for a
package of seeds and $2.50 for a container to
plant the seeds in. There are 30 students in the
class. How much money did the sixth-grade class
spend on seeds and containers in all?
Answer:
5.76
Step-by-step explanation:
Answer:
$105
Step-by-step explanation:
Each student buys one package of seeds and one container
s = Amount of students; p = price of seed package; c = price of container
s*(p+c)=30(1.00+2.50)=30(3.5)$105.
Hope This Helps!
please solve i will give brainiest 100 point question ****** do the whole page please
Answer:
a) point (2, 1) is when the ball is on it's way down at 2 seconds
b) vertex (1, 2) is the highest the ball goes, which is 2 at 1 second.
c) y-intercept (0, 1) at time zero the ball is starting at a height of 1.
d) Points (0, 1) and (2, 1) are the points at which the ball starts and when it is in the same position from the ground as when it started, which is 1.
e) zero (x-int) is when the ball hits the ground at 2.5 seconds.
Step-by-step explanation:
Answer:
See below
step by step explanation
A. (2 , 1 ) is point on the parabola . It represents that the height of the ball after 2 second have passed.
b. The vertex is at ( 1 , 2 ) . It represent that the maximum height of the ball which is 2 units to at t = 1 second
c. The y - intercept is ( 0 , 1 ) . It represent that the initial height of ball at t = 0 second is 1 unit.
d. Point ( 0 , 1 ) and ( 2 , 1 )
This point represent the set of point having equal height at two different time. It represents how long before the ball reaches the same height from the starting point.
e. The zero or x - intercept is ( 2.5 , 0 )
It represent the time taken by ball before it reaches the ground.
Hope this helps...
Best regards!!
Find the measure of b.
Please help
Answer:
125 degrees
Step-by-step explanation:
Using a theorem, you know that angle a is half of 110. Also, in all quadrilaterals inscribed in a circle, the opposite angles are supplimentary. So then, knowing that angle a is 55 degrees, you can come to the conclusion that b is 125 degrees.
Hope this is helpful! :)
Solve for x. 60 10 20 120
Answer:
Hey there!
We have the angle is equal to half the measure of the arc of 120 degrees. (Just another rule for circles)
7x-10=0.5(120)
7x-10=60
7x=70
x=10
Hope this helps :)
Answer:
x = 10
Step-by-step explanation:
Tangent Chord Angle = 1/2 Intercepted Arc
7x-10 = 1/2 ( 120)
7x -10 = 60
Add 10 to each side
7x -10+10 = 60+10
7x = 70
Divide by 7
7x/7 = 70/7
x = 10
write the sum of twice a number and eleven as an algebraic expression
Answer:
2x-11
Step-by-step explanation:
2 x X = 2x + 11
1) In rectangle ABCD, AE is perpendicular on diagonal BD, BE=3DE and AC∩BD={O}.
1. DE/EO=?
2. If BD=8√2 inches, find out the lenght of AE
3. Calculate the measure of angle AOD.
2) In rectangle MNPQ, MA⊥NQ, A∈NQ, MA∩PQ={B}. If AN measures 12 inches, AQ=27 inches, calculate the lenght of MA and MB.
Please help me with these. Or at least with one of them.
Answer:
to be honest I'm not sure how to do
A ladder is leaning against a wall at an angle of 70° with the ground. The distance along the ground is 86cm. Find the length of the ladder
Answer:
[tex]\boxed{x = 251.4 cm}[/tex]
Step-by-step explanation:
Part 1: Sketching the triangle
We are given the angle of elevation, 70°, and the distance along the ground, 86 centimeters. Our unknown is a ladder leaning against the building. Buildings are erected vertically, so the unknown side length is the hypotenuse of the triangle.
We can then sketch this triangle out to visualize it (attachment).
Part 2: Determining what trigonometric ratio can solve the problem
Now, we need to refer to our three trigonometric ratios:
[tex]sin = \frac{opposite}{hypotenuse}[/tex]
[tex]cos = \frac{adjacent}{hypotenuse}[/tex]
[tex]tan = \frac{opposite}{adjacent}[/tex]
Visualizing the sketched triangle, we can assign the three sides their terms in correspondence to the known angle -- this angle cannot be the right angle because the hypotenuse is opposite of it.
Therefore, we know our unknown side length is the hypotenuse of the triangle and because the other side is bordering the 70° angle, it is the adjacent side.
By assigning the sides, we can see that we need to use the trigonometric function that utilizes both the hypotenuse and the adjacent side to find the angle. This is the cosine function.
Part 3: Solving for the unknown variable
Now that we have determined what side we need to solve for and what trigonometric function we are going to use to do so, we just need to plug it all into the equation.
The cosine function is provided: [tex]cos( \alpha) = \frac{adjacent}{hypotenuse}[/tex], where [tex]\alpha[/tex] is the angle. We just need to plug in our values and solve for our unknown side; the hypotenuse.
[tex]cos (70) = \frac{86 cm}{x}[/tex], where x is the unknown side/the hypotenuse.
[tex]x * cos (70) = \frac{86 cm}{x} * x[/tex] Multiply by x on both sides of the equation to eliminate the denominator and make the unknown easier to solve for.
[tex]\frac{xcos (70)}{cos(70)} = \frac{86 cm}{cos(70)}[/tex], Evaluate the second fraction because the first one cancels down to just the unknown, x.
[tex]\frac{86}{cos(70)} = 251.4[/tex], round to one decimal place.
Your final answer is [tex]\boxed{x=251.4cm}[/tex].