△ABC and △JKL are two triangles such that ∠A≅∠J and ∠B≅∠K. Which of the following would be sufficient to prove that the triangles are congruent? A ACJL=BCKL B ∠C≅∠L C AB≅JK D BC≅Jk

Answer:

Option D is the correct option.

Step-by-step explanation:

y = - 2x - 3 → Equation ( i )

y = 3x + 2 → Equation ( ii )

Using elimination method

y + 2x = - 3

y - 3x = 2

---------------------

5x = - 5

Divide both sides of the equation by 5

[tex] \frac{5x}{5} = \frac{ - 5}{5} [/tex]

Calculate

[tex]x = - 1[/tex]

Again, Putting the value of x in equation ( ii ) in order t get the value of y

[tex]y = 3x + 2[/tex]

plug the value of x

[tex] = 3 \times ( - 1) + 2[/tex]

Any expression multiplied by ( - 1 ) equals it's opposite

[tex] = - 3 + 2[/tex]

Calculate

[tex] = - 1[/tex]

Therefore, The possible solution of the system is the ordered pair ( x , y )

[tex](x \:, y \: ) = ( - 1 \:, - 1)[/tex]

-----------------------------------------------------------------------

Check if the given ordered pair is the solution of the system of equation

[tex] - 1 = - 2 \times ( - 1) - 3[/tex]

[tex] - 1 = 3 \times ( - 1) + 2[/tex]

Simplify the equation

[tex] - 1 = - 1[/tex]

[tex] - 1 = - 1[/tex]

Since all the equalities are true, the ordered pair is the solution of the system.

Hope this helps..

Best regards!!

Hey there! I'm happy to help!

We have 6 rock, 4 country, and 4 rap CDs. If we add these all together ,we have 14 total CDs.

Since there are 4 country CDs, we have a 4/14 chance of picking one, which simplifies to 2/7 chance.

Have a wonderful day!

Answer:

Bearing of R from S = S 45° E or 135°

The bearing of R from Q

= S 66.42° w or 246.42°

Step-by-step explanation:

Distance between R and S

RS²= RP²+PS²

RS²= 15²+15²

RS²=225+225

RS= √450

RS= 21.21

Angle at S

21.21= 15/sins

Sin s= 15/21.21

S= sin^-1 15/21.21.

S= 45°

90+45= 135°

Bearing of R from S = S 45° E or 135°

Distance between R and Q

RQ²= PQ²+PR²

RQ²= 35²+15²

RQ²=1225+225

RQ= √1450

RQ= 38.08

RQ= 15/sinQ

SinQ= 15/38.08

SinQ= 0.40

Q=23.58°

90-23.58 = 66.42°

66.42+180= 246.42°

The bearing of R from Q

= S 66.42° w or 246.42°

Answer:

Step-by-step explanation:

Discount =$7000-$4900

Discount% =

[tex] \frac{2100}{7000} \times 100 \\ = \frac{210000}{7000 } \\ = \frac{210}{7} = 30[/tex]

Answer:

Step-by-step explanation:

($26.5 - $3 - $5.50) : $0.6/m =

= $18 : 0.6$/m

= 30 miles

Answer:

[tex]a^2+b^2=c^2[/tex]

Step-by-step explanation:

The Pythagorean Theorem is used to find a missing side length in a right triangle, and the formula [tex]a^2+b^2=c^2[/tex] is used to find the missing side, assuming a and b are legs, while c is the hypotenuse.

Answer:

in a right triangle, the sum of the squares of the leg lengths is equal to the square of the hypotenuse length

Answer:

D. 4z^3

Step-by-step explanation:

First, you see what cubed is 64, which is 4, so you know it is either A or D, but it can not be A because it is not z to the power 5 but x to the power of 3

Hope this helps, if you want me to explain more, feel free to ask questions.

Have a good day! :)

Answer:

4 z^3

Step-by-step explanation:

( 64 z^9) ^ 1/3

Rewriting 64 as 4^3

( 4^3 z^9) ^ 1/3

We know that ( ab) ^c = a^c  * b^c

4^3 ^ 1/3 z^9  ^ 1/3

We know that a^ b^c = a^ ( b*c)

4^(3 * 1/3) z^ (9  * 1/3)

4 ^ ( 1)  z^ ( 3)

4 z^3

Answer:

[tex] \frac{5x + 11}{3(x + 8)} [/tex]

Step-by-step explanation:

[tex] \frac{5x + 11}{3(x + 8)} [/tex]

Five times the sum of a number and eleven, divided by three times the sum of the number and eight

Five times the sum= 5(_+_)

a number and eleven= x+11

divided= ÷ or /

3 times the sum of= 3(_+_)

the number and eight.

Together it will be

[tex]the \: \: one \: written \: in \: the \: answering \: section[/tex]

Hope this helps ;) ❤❤❤

Answer:

y = 12.9

Step-by-step explanation:

To find the value of the side y, simply apply the law of cosines.

y^2 = (14)^2 + (9)^2 - 2(14)(9)cos(64)

y^2 = 196 + 81 - 110.47

y^2 = 166.53

y = 12.9

Therefore, your solution should be y = 12.9

Cheers.

Answer:

The percentage of hatchbacks that run on gasoline: 78%

The percentage of diesel vehicles that are hatchbacks: 21 %

Step-by-step explanation:

The given table represents the following:

Hatchbacks that run on Gasoline = 18

Hatchbacks that run on Diesel = 5

Total number of hatchbacks = 23

Sedan that run on Gasoline = 15

Sedans that run on Diesel = 12

Total number of sedans = 27

SUVs that run on Gasoline = 3

SUVs that run on Diesel = 7

Total number of SUVs = 23

Total number of gasoline vehicles = 36

Total number of Diesel vehicles = 24

To find:

the percentage of hatchbacks that run on gasoline

the percentage of diesel vehicles that are hatchbacks

Solution:

[tex]\text{Percentage of hatchbacks that run on gasoline = } \dfrac{\text{Number of hatchbacks on gasoline}}{\text{Total number of hatchbacks}}\times 100\\\Rightarrow \text{Percentage of hatchbacks that run on gasoline = } \dfrac{18}{23}\times 100 \approx 78\%[/tex]

[tex]\text{Percentage of diesel vehicles that are hatchbacks = } \dfrac{\text{Number of hatchbacks that run on diesel}}{\text{Total number of diesel vehicles}}\times 100\\\Rightarrow \text{Percentage of diesel vehicles that are hatchbacks = } \dfrac{5}{24}\times 100 \approx 21\%[/tex]

So, the answer is:

The percentage of hatchbacks that run on gasoline: 78%

The percentage of diesel vehicles that are hatchbacks: 21%

Answer:

I used a calculator and this is what can up with

Step-by-step explanation:

Answer:

-7 is no, -2 is no, 7 is no, and 10 is yes

Step-by-step explanation:

-5+9*(-7)>58

-5+-63>58

-68>58

-5+9*(-2)>58

-5+-18>58

-23>58

-5+9*(7)>58

-5+63>58

58>58

-5+9*(10)>58

-5+90>58

85>58

so the only one that is a solution is v=10, hope this helps

Answer: No, No, No, Yes

Step-by-step explanation:

Solve the equation for "v":

-5 + 9v > 58

      9v > 63

        v > 7

Check the options to see if they make a true statement:

-7 > 7    False

-2 > 7    False

7 > 7     False

10 > 7   TRUE!

ayuda plis nosé donde estoy q Brainli es este

ayuda

Answer:

hmm I'm not sure but i think it's B. a numerical expression

Sowwy if this didn't help :c

Answer:

Step-by-step explanation:

α = 180° - 135° = 45°

β = 180° - 120° = 60°

γ = 180° - 60° = 120°

δ = 180° - x

ε = 180° - 80° = 100°

If we divide the pentagon into five triangles then:

5•180° = α + β + γ + δ + ε + 4x

900° = 45° + 60° + 120° + x + 100° + 4x

900° = 325° + 5x

5x = 575°

x = 115°

60° + 120° + 135° + 80° + 115° = 510° ≠ 360°

Complete Question:

The total volume of a tree increases 6% each year. What will its volume be after 7 years if its volume is 5 cubic meters now? A. 5(0.06)^7 B. 5(7)(0.06) C. 5(1.06)^7 D. 5(7)(1.06)

Answer:

C. 5(1.06)^7

Step-by-step explanation:

The volume of a tree increases by 7% every year

The formula we would be using is

V(t) = Vo (1 + r)t

Where V(t) = Volume after t years

Vo = Present of initial volume

r = rate of increase

t = time

From the question,

V(t) = Volume after t years = unknown

Vo = Present of initial volume = 5m³

r = rate of increase = 6% = 0.06

t = time = 7 in years

V(t) = 5 × ( 1 + 0.06)^ 7

V(t) =(5)(1.06)^7

Therefore, its volume be after 7 years if its volume is 5 cubic meters now is

Option C: (5)(1.06)^7

Answer:

f(x) = 5x^2

Step-by-step explanation:

A vertical stretch is in the y direction

y = Cf(x)  C > 1 stretches it in the y-direction

f(x) = 5x^2

Answer:

[tex] s = 14.1 [/tex]

Step-by-step explanation:

Given:

<S = 31°

SQ = r = 9

SR = q = 21

s = ?

To find s, use the Law of Cosines:

s² = r² + q² - 2rs*cos(S)

[tex] s^2 = 9^2 + 21^2 - 2*9*21*cos(31) [/tex]

[tex] s^2 = 81 + 441 - 378*0.8572 [/tex]

[tex] s^2 = 522 - 324.02 [/tex]

[tex] s^2 = 197.98 [/tex]

[tex] s = 14.1 [/tex] (nearest tenth)

Answer:

[tex]h=64t-4.9t^{2}[/tex]

Please refer to the attached graph.

Step-by-step explanation:

Given that

Initial velocity of rocket = 64 and is launched vertically.

To find:

Quadratic equation in time to represent the height of rocket in feet.

Solution:

Unit of initial velocity is not given in the question statement, let the velocity be in feet/second only.

Initial velocity, u  = 64 feet/s

The acceleration will be = -g because it is going opposite to gravitational force so it will be negative acceleration motion (speed will be decreasing) so -g will be the acceleration.

Formula for distance traveled is given as:

[tex]s=ut+\dfrac{1}{2}at^2[/tex]

Here Let us represent s by 'h'

a = -g = 9.8 m/[tex]s^2[/tex]

Let us put the known values in the formula:

[tex]h=64t+\dfrac{1}{2}(-9.8)t^2\\\Rightarrow h =64t-4.9t^2[/tex]

It is a quadratic equation, the equation represents the graph of a parabola.

Please refer to the attached graph.

Value of height is 0 at 0 second and ~13 seconds

Answer:

350 meters cubed.

Step-by-step explanation:

If you visualize it, there are two rectangular prisms: one flat one on the top, and one large one on the bottom.

The width of the top one is 5 meters. The length is 7 meters. The height is 8 - 5 = 3 meters. So, one prism has a volume of 5m x 7m x 3m.

The width of the bottom one is 7 meters. The length is 7 meters. The height is 5 meters. So, the bottom prism has a volume of 7m x 7m x 5m.

(5 * 7 * 3) + (7 * 7 * 5)

= (35 * 3) + (49 * 5)

= 105 + 245

= 350

So, the volume of the figure is 350 meters cubed.

Hope this helps!

Answer:

His gain percent is 20%

Step-by-step explanation:

In this question, we want to find the percentage gain of the business.

We need the following parameters;

The cost price which is the sum of the amount she bought the goods + the amount spent on transport

Using the values we have in the question;

The cost price will be;

13,600 + 400 = Rs 14,000

The selling price = Rs 16,800

Mathematically the percentage gain will be;

% gain = (selling price- cost price)/selling price * 100%

% gain = (16,800-14,000)/14,000 * 100/1

% gain = 2800/14,000 * 100/1 = 1/5 * 100/1 = 20%

Answer:

Step-by-step explanation:

Side AC is the side opposite the reference angle of 70 degrees while side BC is the side adjacent to the reference angle. AB is the hypotenuse since it is across from (or opposite) the right angle. The trig ratio that uses the sides opposite from and adjacent to the reference angle is the tangent. Setting up to solve for AC:

[tex]tan(70)=\frac{?}{3}[/tex] and

3tan(70) = ? so

? = 8.24

Answer:

The additional information required to prove ΔDEF ~ ΔPQR is the value of the ratio DE/PQ which has to be equal to three-halves for ΔDEF to be similar to ΔPQR

Step-by-step explanation:

Given DF/PR = FE/RQ = 3/2

The Side Side Side,  SSS, similarity theorem states that where there are two triangles that have corresponding sides that are proportional to each other, the two triangles are said to be similar

Given ΔDEF and ΔPQR, have sides DF/PR = FE/RQ, to prove that ΔDEF and ΔPQR, then the additional information required is the ratio of the third sides of the triangles which is DE/PQ.

If DE/PQ = Three-halves, the two triangles ΔDEF and ΔPQR are similar, if not, that is DE/PQ ≠ Three-halves, then the two triangles ΔDEF and ΔPQR are not similar.

Answer:

D: DE/PQ = 3/2

Step-by-step explanation:

Did it on edge 2020

Answer:

x ≈ 2.3 cm

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos55° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{x}{4}[/tex] ( multiply both sides by 4 )

4 × cos55° = x , thus

x ≈ 2.3 cm ( to 1 dec. place )

Answer:

B) 5 + 3√5 units

Step-by-step explanation:

The length of ZX is 2√5 units. What is the perimeter of triangle XYZ?  

A) 5 +√3 + 2 √5 units  

B) 5 + 3√5 units  

C) 5 + √6 + 2√5 units  

D) 10 + 2√5 units

From the diagram attached, point X is at (-1, 4), Y(3, 1), Z(1, 0).

The distance between two point

[tex]O(x_1,y_1)\ and\ A(x_2,y_2)\ is\ given\ as:\\\\OA=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]

The lengths of the sides of the triangle are:

[tex]|XY| = \sqrt{(3-(-1))^2+(1-4)^2}=\sqrt{25} =5\ unit\\ \\|XZ|= \sqrt{(1-(-1))^2+(0-4)^2}=\sqrt{20} =2\sqrt{5} \ unit\\\\|YZ|= \sqrt{(1-3)^2+(0-1)^2}=\sqrt{5} \ unit[/tex]

The perimeter of the triangle is the sum of all the sides, i.e.

Perimeter = |XY| + |YZ| + |XZ| = 5 + 2√5 + √5 = 5 + 3√5  

Answer:

B

Step-by-step explanation:

Answer: 40x

First, let's find f(2x)

[tex]f(2x)=4(2x)=8x[/tex]

Using this, let's find g(f(2x)):

[tex]g(f(2x))=g(8x)=5(8x)=40x[/tex]

That's the answer. Let me know if you need any clarifications, thanks!

Answer:

80x²

Step-by-step explanation:

f(x) = 4x², g(x) = 5x

f(2x) = 4(2x)² = 16x²

g(f(2x)) = 5(16x²) = 80x²

Answer:

a = 26°

b = 48°

c = 26°

d = 106°

Answer:

4c

Step-by-step explanation:

We can say that the maximum number of cars can be represented as:

Maximum number of cars = Total of rows × Number of cars per row

In this particular case, we have 4 rows and the number of cars per row is c, thus, the expression above becomes:

Maximum number of cars = 4c

Answer:

10 cm overlap required to make a 30 cm long strip.

Step-by-step explanation:

Given:

Four paper strips of the same length.

Two of them glued together with a 4 cm overlap to make a new strip which is 36 cm long.

To find:

Overlap required to make a strip which is 30 cm long = ?

Solution:

First of all, let us understand the concept of overlap.

Please refer to the attached image.

Let length of each strip be [tex]x[/tex] cm.

Given that there is 4 cm overlap resulting in new strip of length 36 cm.

The overlapping length is counted only once as clear from the figure attached.

So, Let us try to find the equation:

[tex]x +(x-4) = 36\\\Rightarrow 2x=40\\\Rightarrow x = 20\ cm[/tex]

i.e. each strip length is 20 cm.

Now, let us assume, an overlap of 'y' cm is to be made to make a new strip of 30 cm.

The equation will be:

[tex](20-y)+20 =30\\\Rightarrow y = 40-30\\\Rightarrow y = 10\ cm[/tex]

Answer:

84 km... Mark me as BRAINLIEST

Step-by-step explanation:

Refer to the pic...

Hope it helped you!

Step-by-step explanation:

Since it takes 6 trips to cover 24 km -

1 trip = 24/6

Therefore 1 trip is -

4 km

Now, the distance for 21 trips is -

21*4 = 84

Therefore, Brad has walked -

84 km

HOPE YOU FIND THIS HELPFUL

Answer:

0.0617

Step-by-step explanation:

so the formula is 1.96[tex]\sqrt{\frac{p(1-p)}{n} }[/tex]

P is the proportion (.45) and n is the sample size (250). Inserting these into the problem, we get 1.96[tex]\sqrt{\frac{.45(1-.45)}{250} }[/tex]. Solving this out, you should solve the inside of the square root to get .00099. Take the square root of this, and multiply by 1.96 to get your answer!

This method applies to any problems with the same basic format. Good luck!