The cost to charge an electric car's home battery charger is $52.02 (to the nearest penny).
The cost to charge an electric car's home battery charger can be calculated using the following equation:
Cost = (kW x hours x rate)
Where kW stands for kilowatts, hrs stands for hours and rate stands for the rate per kilowatt-hour.
In this case, we have: kW = 8.7, hrs = 11 and rate = $0.06
Therefore, Cost = (8.7 x 11 x 0.06) = $52.02
Therefore, it will cost $52.02 (to the nearest penny) to charge the car's battery.
To calculate this cost, we first multiply the kW (8.7) by the hours (11) to get the total kWh used (95.7). We then multiply this number by the rate ($0.06) to get the total cost of charging the battery ($52.02). This cost is to the nearest penny as we rounded up to the nearest cent when multiplying the kWh by the rate.
Complete Question:
An electric car's home battery charger uses 8.7 kilowatts for 11 hours. If electricity costs $0.06 per kilowatt-hour, how much (in dollars, to the nearest penny) does it cost to charge the car's battery? Use exact numbers; do not estimate.
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do photoelectrons from metal 1 have a higher speed, a lower speed, or the same speed as photoelectrons from metal 2?
photoelectrons from metal 1 have a higher speed, a lower speed, or the same speed as photoelectrons from metal 2, If the kinetic energy of photoelectrons from metal 1 is higher than that of metal 2, then the photoelectrons from metal 1 have a higher speed. If the kinetic energy is lower, they have a lower speed. If the kinetic energies are equal, the photoelectrons have the same speed.
we need to consider the following steps:
1. Determine the work function of both metals (the minimum energy required to release an electron from the metal surface). The work function is specific to each metal.
2. Identify the energy of the incident light, which should be the same for both metals to make a fair comparison.
3. Use the photoelectric effect equation: Kinetic energy of photoelectrons = Energy of incident light - Work function of the metal.
4. Compare the kinetic energy of the photoelectrons from both metals.
If the kinetic energy of photoelectrons from metal 1 is higher than that of metal 2, then the photoelectrons from metal 1 have a higher speed. If the kinetic energy is lower, they have a lower speed. If the kinetic energies are equal, the photoelectrons have the same speed.
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what is the energy transformation? initial state: a ball starts high on top of a cliff at rest. final state: the ball is moving and just about to hit the ground.
The energy transformation that occurs in this scenario is gravitational potential energy being converted to kinetic energy.
The ball in its initial state has gravitational potential energy due to its position high on top of the cliff. As the ball falls, this potential energy is transformed into kinetic energy, which is the energy of motion. By the time the ball is just about to hit the ground, it has lost all of its potential energy and gained an equal amount of kinetic energy.
1. Initially, the ball has potential energy due to its height on the cliff. This is gravitational potential energy, calculated as PE = m * g * h, where m is the mass of the ball, g is the gravitational constant (9.81 m/s²), and h is the height of the cliff.
2. As the ball starts to fall, the gravitational potential energy is gradually converted into kinetic energy. Kinetic energy is the energy of motion, calculated as KE = 0.5 * m * v², where m is the mass of the ball, and v is its velocity.
3. Throughout the fall, the conservation of mechanical energy states that the total energy in the system remains constant. So, the sum of potential energy and kinetic energy at any point in the fall is equal to the initial potential energy (PE_initial = PE + KE).
4. Just before the ball hits the ground, its height (h) is approximately zero. Therefore, the potential energy is almost zero, and most of the initial potential energy has been converted into kinetic energy.
In summary, the energy transformation in this scenario involves the conversion of gravitational potential energy into kinetic energy as the ball falls from the cliff and gains speed before hitting the ground.
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a binary star system in the constellation orion has an angular separation between the stars of 10-5 radians. assuming a wavelength of 500 nm, what is the smallest aperture (diameter) telescope that will just resolve the two stars? (1 nm
The smallest aperture (diameter) telescope that will just resolve the two stars is 5 cm.
The angular resolution (minimum resolvable angle) of a telescope can be calculated using the Rayleigh criterion, which states that two objects can be just resolved when the center of the diffraction pattern of one is directly over the first minimum of the diffraction pattern of the other. The formula for the angular resolution is:
θ = 1.22 λ / Dwhere θ is the angular resolution, λ is the wavelength of light, and D is the diameter of the aperture (telescope).
Substituting the given values, we get:
θ = 1.22 x 500 nm / Dθ = 0.61 µrad / DThe angular separation between the stars is given as 10-5 radians. To resolve the stars, the angular resolution of the telescope must be equal to or smaller than this value. Therefore:
θ = 0.61 µrad / D ≤ 10-5 radiansD ≥ 5 cmTherefore, the smallest aperture (diameter) telescope that will just resolve the two stars is 5 cm.
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why should ay be close to 9.8 m/s2, with the other two being close to 0? why should all three gyroscope values be essentially 0?
The values you mentioned are related to the motion of a typical object near the surface of the Earth.
The acceleration due to gravity, represented by "g", is approximately 9.8 [tex]m/s^2[/tex] at sea level. This value is constant and acts vertically downward, so it's common to see it represented as a negative value in equations. If an object is at rest on a level surface, then its acceleration in the x and y directions should be close to zero. This is because the object is not moving in those directions, so it's not accelerating.
Regarding the gyroscope values, a gyroscope is a device that measures angular velocity or rotation rate. If a gyroscope is at rest or is not undergoing any rotation, its output should be zero. This is because there is no change in angular velocity to measure. So, if all three gyroscope values are essentially zero, it suggests that the device is not rotating or undergoing any significant angular velocity changes.
In summary, the values you mentioned are related to the motion of objects on or near the Earth's surface, and their values reflect the physical laws that govern that motion.
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acid precipitation can be traced back to a the burning of fossil fuels. b the release of particulate matter into the atmosphere. c thermal inversions. d the use of electrostatic precipitators.
Acid precipitation is caused by the burning of fossil fuels, which releases sulfur dioxide and nitrogen oxides into the atmosphere. The correct option is a) the burning of fossil fuels.
What causes precipitation of acid?Released into the atmosphere, sulphur dioxide and nitrogen oxides react with water, oxygen, and other elements to produce sulfuric acid and nitric acid, respectively. Acid-impacted rain often has a pH that is below 4.5.
What kind of contaminants are created when fossil fuels are burned?Nitrogen oxides are released into the atmosphere during the burning of fossil fuels and contribute to the formation of smog and acid rain.
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A 56 kg girl stands on the Earth. (Diagram not to scale)
a) what is her weight?
b)If she were standing on a tower that is as high as the radius of the Earth what would
she weigh there?
(a) The weight of the girl on Earth is 548.8 N
(b) The girl would weigh approximately 137.2 N on the tower at a height equivalent to the radius of the Earth.
What is the weight of the girl?a) The weight of the girl on Earth can be calculated using the formula for gravitational force:
Weight = mass × acceleration due to gravity
The acceleration due to gravity on Earth is approximately 9.8 m/s^2.
Given that the mass of the girl is 56 kg, her weight on Earth would be:
Weight = 56 kg × 9.8 m/s^2 = 548.8 N (Newtons)
b) If the girl were standing on a tower that is as high as the radius of the Earth, she would be at the height of the Earth's orbit.
Assuming the girl is at a height equivalent to the radius of the Earth, which is approximately 6,371 km, the acceleration due to gravity would be significantly lower.
Let's assume it's approximately 1/4 of the surface gravity, which is a rough estimate.
Acceleration due to gravity at height of radius of Earth = 9.8 m/s^2 ÷ 4 = 2.45 m/s^2
Using this lower acceleration due to gravity, the girl's weight on the tower would be:
Weight = mass × acceleration due to gravity at height
Weight = 56 kg × 2.45 m/s^2 = 137.2 N (Newtons)
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What does freezing in the water cycle mean
Answer: Changing state from a liquid to a solid
Explanation: When liquid water loses thermal energy, it gets cold and undergoes freezing.
if successful, leibnez's argument proves the existence of a necessary, uncaused, timeless, spaceless, immaterial, personal creator of the universe. true or false?
If successful, Leibniz's argument, also known as the Cosmological Argument, does aim to prove the existence of a necessary, uncaused, timeless, spaceless, immaterial, personal creator of the universe. The statement is true.
Leibniz's cosmological argument, also known as the Principle of Sufficient Reason, aims to demonstrate that there must be a necessary, uncaused, timeless, spaceless, immaterial, personal creator of the universe. According to the argument, every contingent thing in the universe has an explanation for its existence, and this explanation must ultimately rest on a necessary being that exists by its own nature and does not depend on anything else for its existence. This necessary being, by definition, must possess the attributes mentioned above. Therefore, if the argument is successful, it would indeed prove the existence of a necessary, uncaused, timeless, spaceless, immaterial, personal creator of the universe.
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the horizontal component of the earth's magnetic field at the location of the loop is 1.69e-5 t. calculate the maximum emf induced in the coil by the earth's field.
The maximum EMF induced in the coil by the Earth's magnetic field is zero.
We can use Faraday's law of electromagnetic induction to calculate the maximum EMF induced in the coil by the Earth's magnetic field. Faraday's law states that the EMF induced in a coil is equal to the rate of change of the magnetic flux through the coil.
Assuming the loop is a circle of radius r, the magnetic flux through the loop due to the Earth's magnetic field is given by:
Φ = B * A * cosθ
where B is the horizontal component of the Earth's magnetic field, A is the area of the loop, and θ is the angle between the normal to the loop and the direction of the magnetic field. Since the loop is lying flat on the ground, θ = 0, and cosθ = 1.
The area of a circle is A = π[tex]r^2[/tex], so we have:
Φ = B * π[tex]r^2[/tex]
The rate of change of the magnetic flux through the loop is given by the time derivative of Φ:
dΦ/dt = d(B * π[tex]r^2[/tex])/dt = π[tex]r^2[/tex] * dB/dt
Since the horizontal component of the Earth's magnetic field is constant, dB/dt = 0, so the rate of change of the magnetic flux is zero.
Therefore, the maximum EMF induced in the coil by the Earth's magnetic field is zero.
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The current through one resistor in a parallel resistor circuit is always (need help ASAP)
a. The same as the current in the other resistors in the circuit
b. Equal to the total current in the circuit.
c. More than the total current in the circuit.
d. Less than the total current in the circuit
In a parallel resistor circuit, the current through one resistor is not always the same as the current in the other resistors in the circuit. The correct answer is: d.
In a parallel resistor circuit, the current is split between the different branches of the circuit. The total current in the circuit is equal to the sum of the currents in each branch. Each resistor in a parallel circuit has a different resistance, which determines how much current flows through it. The resistor with the lowest resistance will have the highest current flowing through it, while the resistor with the highest resistance will have the lowest current flowing through it. Therefore, option d is correct.
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22. radio waves are diffracted by large objects such as buildings, whereas light is not noticeably diffracted. why is this? a) radio waves are unpolarized, whereas light is normally polarized. b) the wavelength of light is much smaller than the wavelength of radio waves. c) the wavelength of light is much greater than the wavelength of radio waves. d) radio waves are coherent and light is usually not coherent. e) radio waves are polarized, whereas light is usually unpolarized.
Radio waves are diffracted by large objects such as buildings, whereas light is not noticeably diffracted, because b) the wavelength of light is much smaller than the wavelength of radio waves.
The diffraction is the bending of waves around obstacles or through small openings, and the amount of diffraction is proportional to the size of the obstacle or opening and the wavelength of the wave. Since radio waves have much longer wavelengths than visible light, they are more easily diffracted by large objects such as buildings. On the other hand, visible light has a much smaller wavelength than radio waves, which makes it less prone to diffraction. Polarization and coherence are not directly related to diffraction.
Polarization refers to the direction of oscillation of the electromagnetic waves, while coherence refers to the consistency of phase between waves. Therefore, the correct answer is b) the wavelength of light is much smaller than the wavelength of radio waves. Radio waves are diffracted by large objects such as buildings, whereas light is not noticeably diffracted, because b) the wavelength of light is much smaller than the wavelength of radio waves.
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a long focal length lens that magnifies the subject and narrows the field of view is called a __
Convex Lens:- A long focal length lens that magnifies the subject and narrows the field of view is called a convex lens.
However, it's important to note that lenses can also be concave, which will have the opposite effect of a convex lens, causing the subject to appear smaller and the field of view to appear wider. And the lenses will change their nature if kept in a denser medium than them.
Convex lenses are used in eyeglasses for correcting farsightedness, where the distance between the eye's lens and retina is too short, as a result of which the focal point lies behind the retina. Eyeglasses with convex lenses increase refraction and accordingly, reduce the focal length.
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A long focal length lens that magnifies the subject and narrows the field of view is called a telephoto lens.
A zooming focal point is a sort of camera focal point with a long central length that amplifies the subject and limits the field of view. Dissimilar to a customary focal point, a zooming focal point can amplify an article or a subject without genuinely drawing nearer to it, making it valuable for catching far off items or untamed life. Zooming focal points are usually utilized in sports and natural life photography, where the photographic artist needs to catch a subject from a good ways.
Because of their long central length, zooming focal points can likewise deliver a shallow profundity of field, obscuring the foundation and making the subject stick out. Notwithstanding, zooming focal points are frequently heavier and more costly than standard focal points, making them less pragmatic for ordinary use.
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7. a high-frequency photon is scattered off of an electron andexperiences a change of wavelength of 1.7 x 10-4 nm at whatangle must a detector be placed to detect the scattered photon(relative to the direction of the incoming photon)?
The detector must be placed at an angle of approximately 0.003 degrees relative to the direction of the incoming photon to detect the scattered photon.
This formula relates the change in wavelength of the scattered photon to the scattering angle and the rest mass of electron.
Δλ = h/mc (1 - cosθ)
Rearranging the formula to solve for θ, we get:
cosθ = 1 - (Δλ mc)/h
Plugging in the given values, we get:
cos\theta = 1 - [(1.7 * 10^{-4} nm) * (9.11 * 10^{-31} kg) * (3 * 10^{8} m/s)] / \\(6.626 * 10^{-34} J.s)
cosθ ≈ 0.999996
θ ≈ 0.003 degrees
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compared to the buoyant force of the atmosphere on a 1-kilogram iron block, the buoyant force on a nearby 1-kilogram helium-filled balloon is group of answer choices the same. considerably less. considerably more.
The buoyant force on a 1-kilogram helium-filled balloon will be considerably more than the buoyant force of the atmosphere on a 1-kilogram iron block.
The buoyant force is the force exerted by a fluid, such as air or water, on an object that is submerged in it. It is equal to the weight of the fluid displaced by the object.
In this case, we are comparing the buoyant force of the atmosphere on a 1-kilogram iron block to the buoyant force on a nearby 1-kilogram helium-filled balloon.
Helium is a gas that is much less dense than air, which means that it will displace a larger volume of air than the iron block of the same mass.
Therefore, the buoyant force on the helium-filled balloon will be considerably more than the buoyant force on the iron block. This is because the buoyant force is directly proportional to the volume of fluid displaced by the object.
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a block of mass m containing a net positive charge q is placed on a smooth horizontal table which terminates in a vertical wall as shown in figure (29-e2). the distance of the block from the wall is d. a horizontal electric field e towards right is switched on. assuming elastic collisions (if any) find the time period of the resulting oscillatory motion. is it a simple harmonic motion ?
In conclusion, the time period of the resulting oscillatory motion is T = 2d/v, and the motion is not simple harmonic.
When the electric field is switched on, the charged block will experience a force in the direction of the electric field, i.e., towards the right. This force will cause the block to move towards the wall. If the block collides elastically with the wall, it will rebound with the same speed but in the opposite direction.
Let the velocity of the block just before collision with the wall be v. The time taken by the block to travel a distance d to reach the wall is given by t = d/v. The time taken by the block to return to its initial position is also t, as the block moves with the same speed v during the rebound. Therefore, the time period of the oscillatory motion is T = 2t = 2d/v.
Now, let's analyze whether the motion is simple harmonic or not. For simple harmonic motion, the restoring force should be proportional to the displacement from the equilibrium position and should be directed towards the equilibrium position. In this case, the restoring force is provided by the electric field, which is always directed towards the right. Therefore, the motion is not simple harmonic as the restoring force is not proportional to the displacement from the equilibrium position.
In conclusion, the time period of the resulting oscillatory motion is T = 2d/v, and the motion is not simple harmonic.
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if a jar wrench whose handle extends 19 cm from the center of the jar is attached to the lid, what is the minimum force required to open the jar?
To calculate the minimum force required to open a jar using a jar wrench, we need to consider the torque required to overcome the friction between the lid and the jar.
The torque required to open a jar can be calculated using the formula:
Torque = Force x Distance
where Force is the minimum force required to open the jar, and Distance is the distance between the center of the jar and the point where the force is applied (in this case, the distance between the center of the jar and the end of the jar wrench handle, which is 19 cm).
The minimum force required to open the jar can be calculated by dividing the torque required by the radius of the lid.
Let's assume that the radius of the lid is 4 cm.
So, the minimum force required to open the jar is:
Force = Torque / Radius of the lid
To calculate the torque required, we need to estimate the force of friction between the lid and the jar. Let's assume that the force of friction is 0.2 times the weight of the jar, which is the typical range for a well-sealed jar.
So, the torque required to open the jar is:
Torque = Force of friction x Distance
Torque = 0.2 x Weight of the jar x Distance
Let's assume that the weight of the jar is 500 grams, which is equivalent to 4.9 N (Newtons), and the distance between the center of the jar and the end of the jar wrench handle is 19 cm.
So, the torque required to open the jar is:
Torque = 0.2 x 4.9 N x 19 cm
Torque = 1.86 N-cm
Now we can calculate the minimum force required to open the jar:
Force = Torque / Radius of the lid
Force = 1.86 N-cm / 4 cm
Force = 0.47 N
Therefore, the minimum force required to open the jar using a jar wrench with a handle that extends 19 cm from the center of the jar is approximately 0.47 N.
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calculate the applied torque needed to accelerate the wheel from rest to 1950 rpm in 5.00 s . take into account a fritional torque that has been measured to slow down the wheel from 1500 rpm to rest in 55.0 s .
1.43 Nm is the torque needed to accelerate the wheel from rest to 1950 rpm in 5.00 s. take into report a frictional torque that has been calculated to slow down the wheel from 1500 rpm to rest in 55.0 s
Speed of wheel = 1950 rpm
Time is taken to accelerate = 5.00 s
Speed of wheel to slowdown = 1500 rpm
Time taken to rest =55.0 s
To calculate the torque needed to accelerate the wheel:
τ = Iα
To calculate the angular acceleration:
α = Δω / Δt
the change in angular velocity is calculated by using the formula:
Δω = ωf - ωi
At initial the velocity is Zero.
ωf = 1950 rpm
ωf = 1950 rev/min = 1950/60 rad/s
ωf = 32.5 rad/s
The angular acceleration is:
α = Δω / Δt = (32.5 rad/s) ÷ 5.00
α = 6.50 rad/s^2
To calculate the moment of inertia,
I = (1/2)MR^2
The final speed of the wheel is 1950 rpm, which corresponds to a linear speed of:
v = ωf R = (1950/60 rev/s) ÷ (2π R)
v = 204.2 R m/s
To calculate the circumference,
C = 41.67 * (2π R)
C = 83.34 π R
The linear distance traveled during this time is:
d = v t = (204.2 R m/s) (55.0 s)
d = 11,231 R m
to calculate the radius of wheels:
83.34 π R = 11,231 R m
R = 42.7 m
V = π R^2 h
V =[tex]3.14 * (0.427 m)^2 *(0.02 m)[/tex]
V = 0.000574 m
The mass is:
M = V ρ = [tex](0.000574 m^3) (7.8 g/cm^3) (1000 cm^3/m^3)[/tex]
M = 4.49 kg
Now we can calculate the torque needed to accelerate the wheel using the formula:
τ = Iα = (1/2)MR^2 α
τ = [tex](1/2) (4.49 kg) (0.427 m)^2 (6.50 rad/s^2)[/tex]
τ = 1.43 Nm
Therefore, we can conclude that the applied torque needed is 1.43 Nm.
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a 130-w lamp is placed in series with a resistor and a 120-v source. if the voltage across the lamp is 32 v, what is the resistance r of the resistor?
The resistance r of the resistor which is placed in series with a 130-w lamp and a 120 V source is 21.66 Ω
According to the question,
Power of the lamp = 130 W
The voltage of the source = 120 V
The voltage across the lamp = 32 V
According to Kirchow's voltage Law,
The algebraic sum of voltage in a closed loop is zero.
So ∑V = [tex]V_{resistor}+V_{lamp}+V_{source}[/tex] =0
[tex]V_{Lamp}=-32 V[/tex]
[tex]V_{source}=120V[/tex]
0 = 120 - 32 + [tex]V_{resistor}[/tex]
[tex]V_{resistor}[/tex] = -88 V
Power of the lamp = V * I
130 = 32 * I
I = [tex]\frac{130}{32} A[/tex]
According to Ohm's Law,
V ∝ I
V = I*R
where V is the potential difference across the resistor
I is the current flowing through the resistor
R is the resistance of the resistor
Since the lamp and resistor are connected in series, they have the same amount of current flowing
Therefore, 88 = [tex]\frac{130}{32}[/tex] * r
r = [tex]\frac{88*32}{130}[/tex]
r = 21.66 Ω
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what is the moment of inertia of this system, about an axis perpendicular to the page and passing through the point where the rods touch?
The moment of inertia is 2.98 kg*m^2.
Moment of inertia about point of contact and perpendicular axis?To find the moment of inertia of the system, we need to consider the contributions of each object to the moment of inertia and add them up using the parallel axis theorem. Let's label the two rods A and B.
The moment of inertia of rod A about an axis passing through its center of mass and perpendicular to the rod is:
I_A = (1/12)M_AL_A^2
where M_A is the mass of rod A and L_A is its length.
Similarly, the moment of inertia of rod B about an axis passing through its center of mass and perpendicular to the rod is:
I_B = (1/12)M_BL_B^2
where M_B is the mass of rod B and L_B is its length.
To use the parallel axis theorem, we need to find the distance between the axis of rotation and the center of mass of each object. Let's call this distance r. For rod A, r is half the length of the rod, since the axis of rotation passes through the center of the rod where it touches rod B. So:
r_A = L_A/2
For rod B, r is the distance from its center of mass to the point where it touches rod A. The center of mass of rod B is at a distance of L_B/2 from the end that touches rod A, so:
r_B = sqrt[(L_B/2)^2 + (L_A/2)^2]
Now we can use the parallel axis theorem to find the total moment of inertia:
I_total = I_A + I_B + M_Ar_A^2 + M_Br_B^2
Plugging in the values, we get:
I_total = (1/12)2.00 kg(0.800 m)^2 + (1/12)3.00 kg(1.20 m)^2 + 2.00 kg*(0.400 m)^2 + 3.00 kg*sqrt[(0.400 m)^2 + (0.600 m)^2]^2
Simplifying, we get:
I_total = 2.98 kg*m^2
Therefore, the moment of inertia of the system about an axis perpendicular to the page and passing through the point where the rods touch is 2.98 kg*m^2.
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inelastic collisions in one dimension: a 5.00-kg ball is hanging from a long but very light flexible wire when it is struck by a 1.50-kg stone traveling horizontally to the right at 12.0 m/s. the stone rebounds to the left with a speed of 8.50 m/s, and the ball swings to a maximum height h above its original level. the value of h is closest to
We can solve this problem using conservation of momentum and conservation of energy.
First, we can find the initial momentum of the system before the collision:
[tex]p_i = m_stone * v_stone[/tex] = 1.50 kg * 12.0 m/s = 18.0 kg m/s
After the collision, the stone rebounds to the left with a speed of 8.50 m/s, so we can find its final momentum:
[tex]p_f = m_stone * v'_stone = 1.50 kg * (-8.50 m/s)[/tex]= -12.75 kg m/s
The ball and the stone move together after the collision, so their final velocity is the same. Let's call it v_f. We can find the final momentum of the system:
[tex]p_f = (m_ball + m_stone) * v_f[/tex]
Since momentum is conserved, we can set p_i = [tex]p_f[/tex]and solve for v_f:
[tex]v_f = p_i / (m_ball + m_stone) = 18.0 kg m/s / (5.00 kg + 1.50 kg)[/tex]= 3.0 m/s
Now we can use conservation of energy to find the maximum height h that the ball reaches. At the maximum height, all of the kinetic energy has been converted to potential energy:
[tex]1/2 * (m_ball + m_stone) * v_f^2 = (m_ball + m_stone) * g * h[/tex]
Solving for h, we get:
[tex]h = v_f^2 / (2 * g) = 3.0 m/s^2 / (2 * 9.8 m/s^2) = 0.153 m[/tex]
So the value of h is closest to 0.153 m.
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compared to the electric field 1 cm away from an infinite line of charge, what are the electric field 2 cm away from the same line of charge will be
The electric field 2 cm away from an infinite line of charge will be less than the electric field 1 cm away.
The electric field follows an inverse square law, which means that the strength of the electric field decreases as the distance from the charge increases. Specifically, the electric field at a distance r from an infinite line of charge with charge density λ is given by:
E = λ / (2πε₀r)
where ε₀ is the permittivity of free space. Therefore, if r doubles from 1 cm to 2 cm, the electric field will decrease by a factor of 2π.
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2.5-Newton's Third Law
An astronaut in deep space is at rest relative to a nearby space station. The astronaut needs to
return to the space station. A student makes the following claim: "The astronaut should
position her feet pointing away from the space station. Then, she should repeatedly move her
feet in the opposite direction to each other. This action will propel the astronaut toward the
space station." Is the student's claim correct? Justify your selection.
The student's claim is incorrect. According to Newton's Third Law of Motion, for every action, there is an equal and opposite reaction.
How is Newton's Third Law explained for a spacecraft?In this case, the force exerted by the astronaut on her feet is equal and opposite to the force exerted by the feet on the astronaut. Therefore, moving her feet in the opposite direction to each other will result in equal and opposite forces, which will cancel each other out and not propel the astronaut towards the space station.
To propel herself towards the space station, the astronaut needs to exert a force in the direction opposite to the direction of the space station. This can be achieved by using a jetpack or another propulsion system.
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as per subpart b, a physician who is a member of the research team on a study involving nonviable neonates may assist the treating physicians in determining whether neonates are nonviable. True or false?
True a significant factor in algal blooms and the excessive growth of aquatic vegetation that results in competition for sunlight and congestion.
What exactly is a contest?Job competition is fierce. Computer firms compete fiercely with one another. The two businesses are in opposition to one another.It can also be described more broadly as the either direct or indirect relationship between species that affects fitness when they share a resource.When there is monopolistic competition, several vendors offer differentiated goods—goods with minor differences but similar functions.
An organism is what?Therefore, every animal, plant, mould, protist, organism, or archaeon found on Earth would be considered an organism. There are numerous methods to categorise these species.a single organism that uses its organs to carry out its life's functions
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which type of spectrum contains dark bands that represent wavelengths intercepted by a material between a radiation source and the earth?
The type of spectrum being referred to is an absorption spectrum. Here are the steps involved in creating an absorption spectrum:
1) A radiation source emits a continuous spectrum of light, which contains all wavelengths of visible light.
2) The light from the radiation source passes through a material, such as a gas, liquid, or solid.
3) The material absorbs certain wavelengths of light that are specific to its chemical composition.
These absorbed wavelengths correspond to the energy levels of the electrons in the material's atoms or molecules.
4) The remaining light that passes through the material is a spectrum that has dark bands or lines where the absorbed wavelengths should be. These dark bands represent the wavelengths that were absorbed by the material.
5) The resulting spectrum is an absorption spectrum that can be used to identify the elements or compounds present in the material.
To summarize, an absorption spectrum contains dark bands that correspond to the specific wavelengths of light that are absorbed by a material between a radiation source and the earth. By analyzing the absorption spectrum, scientists can identify the composition of the material.
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moment of inertia times angular velocity; measured in units of mass times units of velocity or expressed as kilogram-meters squared per second in si; a vector quantity.
The quantity that is expressed as the product of moment of inertia and angular velocity is known as angular momentum.
Angular momentum is a vector quantity and is measured in units of mass times units of velocity, which is equivalent to kilogram-meters squared per second in SI units. It represents the rotational analog of linear momentum and is important in understanding the conservation of angular momentum in rotating systems.
The concept of angular momentum, which involves moment of inertia and angular velocity. Angular momentum (L) is the product of an object's moment of inertia (I) and its angular velocity (ω). It can be represented mathematically as:
L = I * ω
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The moment of inertia times angular velocity is a measure of rotational motion and is expressed as the ˘ of the moment of inertia and the angular velocity. The units of velocity are typically meters per second (m/s) or radians per second (rad/s), depending on the context.
The units of moment of inertia are kilograms times meters squared (kg x m²). When these units are multiplied together, the resulting unit is kilogram-meters squared per second (kg x m²/s), which is the SI unit for angular momentum. Since angular momentum is a vector quantity, it has both magnitude and direction.
I is the moment of inertia, a measure of an object's resistance to rotational motion, and is typically determined by the object's mass distribution and geometry.
ω is the angular velocity, a measure of how fast an object rotates about a specific axis, and is typically expressed in radians per second (rad/s).
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a father with twice the mass of his daughter is watching her skate as he is standing still on ice with his skates on. she approaches him with speed v and then grabs him so that it is a perfectly inelastic collision. at what speed do the two of them move, i.e. what is their center of mass velocity? assume the ice is frictionless and there is no wind resistance.
The center of mass velocity after the perfectly inelastic collision is Vf = v/3.
To determine the center of mass velocity after the perfectly inelastic collision between the father and daughter on frictionless ice with no wind resistance.
Step 1: Assign variables to the given information.
Let the mass of the father be 2m and the mass of the daughter be m. The daughter approaches the father with a speed of v, and the father is initially at rest.
Step 2: Apply the conservation of momentum principle.
In a collision, the total momentum before the collision equals the total momentum after the collision. Let Vf represent the final velocity of both the father and daughter after the collision. The initial momentum is given by:
p_initial = (mass_daughter × v_daughter) + (mass_father × v_father)
Since the father is initially at rest, his initial velocity is 0:
p_initial = (m × v) + (2m × 0) = m × v
Step 3: Calculate the total momentum after the collision.
After the collision, the combined mass of the father and daughter is 2m + m = 3m. The final momentum is:
p_final = (mass_combined) × Vf = (3m) × Vf
Step 4: Set the initial momentum equal to the final momentum and solve for the final velocity, Vf.
m × v = (3m) × Vf
Divide both sides by 3m:
Vf = (m × v) / (3m)
The mass m cancels out:
Vf = v / 3
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the energy gap is about 8 kilocalories per pound of lost weight. bill has just lost 25 pounds, so he needs __________ fewer kilocalories per day to maintain his weight loss.
The energy gap is about 8 kilocalories per pound of lost weight. bill has just lost 25 pounds, so he needs 200 fewer kilocalories per day to maintain his weight loss.
When someone loses weight, their body requires fewer calories to maintain their new weight. This is because the body has less mass to maintain, and therefore requires less energy to do so.
The amount of energy saved per pound of weight loss is referred to as the energy gap. In this case, the energy gap is 8 kilocalories per pound of lost weight. This means that for every pound of weight lost, the body requires 8 fewer kilocalories per day to maintain that weight loss.
If Bill has just lost 25 pounds, then he would need to consume 8 x 25 = 200 fewer kilocalories per day to maintain his weight loss compared to what he needed before his weight loss.
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a ball with a mass of .15 mg is moving at 3m/s. what is the momentum of the ball?
a train car with a mass of 250 kg is moving at 4 m/s. what is the movementum of the train car
momentum is the same for a dog with a mass of 12kg and a dog with a mass of 14kg because their velocity is the same
true or false
all moving objects at the same velocity move the same momentum
true or false
the momentum of a truck moving at 20 m/s is the same as a bicycle moving at 20 m/s
true or false
The momentum of the ball is approximately 0.00045 g m/s.
the momentum of the train car is 1000 kg m/s.
False. The momentum of an object depends on both its mass and velocity
True. If two objects have the same velocity, their momenta will be the same as long as their masses are equal.
False. The truck moving at 20 m/s will have a much larger momentum than a bicycle moving at 20 m/s
What is momentumThe momentum (p) of an object is defined as the product of its mass (m) and velocity (v), so we can use the formula p = m*v to solve the problems:
The momentum of a ball with a mass of 0.15 mg (0.00015 g) moving at 3 m/s is:
p = mv = (0.00015 g)(3 m/s) = 0.00045 g m/s.
So, the momentum of the ball is approximately 0.00045 g m/s.
The momentum of a train car with a mass of 250 kg moving at 4 m/s is:
p = mv = (250 kg)(4 m/s) = 1000 kg m/s.
So, the momentum of the train car is 1000 kg m/s.
False. The momentum of an object depends on both its mass and velocity, so two objects with different masses will have different momenta even if they have the same velocity.
True. If two objects have the same velocity, their momenta will be the same as long as their masses are equal.
False. The momentum of an object depends on both its mass and velocity, so a truck moving at 20 m/s will have a much larger momentum than a bicycle moving at 20 m/s, since the truck has much more mass.
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What is the tension on a rope allowing a 7.50 kg box to accelerate downward at 4.00 m/s2?
43.5N
5.8N
13.8N
104N
The tension on the rope allowing the box to accelerate downward at 4.00 m/s² is 43.5 N.
To find the tension on the rope, we need to use the equation for the net force acting on the box:
F_net = ma
where F_net is the net force, m is the mass of the box, and a is the acceleration of the box. The box is accelerating downward at 4.00 m/s², so we can substitute in the values:
F_net = (7.50 kg)(4.00 m/s²) = 30.0 N
The tension on the rope is equal in magnitude but opposite in direction to the weight of the box. We can find the weight of the box using the equation:
F_weight = mg
where F_weight is the weight, m is the mass of the box, and g is the acceleration due to gravity (9.81 m/s²).
F_weight = (7.50 kg)(9.81 m/s²) = 73.6 N
Therefore, the tension on the rope is:
Tension = F_weight - F_net = 73.6 N - 30.0 N = 43.6 N
So, the tension on the rope allowing the box to accelerate downward at 4.00 m/s² is 43.5 N.
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A tank of helium gas used to inflate toy balloons is at a pressure of 15.5x106 Pa and a temperature of 293 K. The tank’s volume is 0.020 m3. How large a balloon would it fill at 1.00 atmosphere and 323 K?
Under the circumstances, a balloon with a volume of 0.035 m³ could be filled from the helium gas tank.
A weather balloon with a 2000L volume has what pressure?At an altitude of 1000 metres, where the atmospheric pressure is measured to be 60.8 kPa, a weather balloon with a 2000-liter volume and a pressure of 96.3 kPa ascends.
PV = nRT
n = PV/RT = (15.5x10⁶ Pa x 0.020 m³) / (8.31 J/K/mol x 293 K) = 0.0148 mol
Next, we can use the ideal gas law again to find the new volume of the helium at the given conditions:
(P1V1)/T1 = (P2V2)/T2
We can solve for V2:
V2 = (P1V1T2)/(P2T1) = (15.5x10⁵ Pa x 0.020 m³ x 323 K)/(1 atm x 293 K) = 0.035 m³
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