An insect is 3.5 millimeters long. Which expression finds the length of the insect in decimeters? Use the metric table to
help answer the question.
Metric Table
kilo-
1,000
hecto-
100
unit
deka-
10
centi-
deci-
0.1
1
milli-
0.001
0.01
A.) 3.5 x 100
B.) 3.5-100
C.) 3.5-10
D.) 3.5x 10

Answers

Answer 1

Answer:b

Step-by-step explanation:

C and D are wrong because both of them should be divided and by 100. A is wrong because you are supposed to divide because if you multiply 3.5 x 100 its 350 and it just doesn’t make any sense because milli is smaller than deci. So by process of elimination b is the right answer.

Answer 2

Answer:

b

Step-by-step explanation:

:D


Related Questions

Find the area of the shape shown below.

Answers

Answer:

28

Step-by-step explanation:

We divide the shape covenientely, like this, and area 1 is 4*4=16

area 2=4*4/2=8

area 3= 2*4/2=4

Area total = Area 1 + Area 2 + Area 3=16+8+4=28

two bags and four hats cost $100 in all. three bags and seven hats cost $164 in all. what is the cost of 1 hat?

Answers

Answer:

Bags = 22

Hat = 14

22 x 2 = 44

14 x 4 = 56

So the first part is true

3 x 22 = 66

7 x 14 = 98

So the second part is true

14 is the answer

It's trial and error

Step-by-step explanation:

Plot the image of point D under a dilation about point P with a scale factor of 1/3

Answers

Answer:

check the graph below

Step-by-step explanation:

Dilation involves changing the size and position of a point

The image of the dilation is (4,-3)

From the figure, the coordinates of point D and point P are:

[tex]D = (13,2)[/tex]

[tex]P = (1,11)[/tex]

The scale factor of dilation is given as:

[tex]k = \frac{1}{3}[/tex]

The rule of dilation about point P is then calculated as:

[tex](x,y) \to k(x_D - x_P, y_D - y_P)[/tex]

So, we have:

[tex](x,y) \to \frac 13 \times (13 - 1, 2- 11)[/tex]

Simplify

[tex](x,y) \to \frac 13 \times (12, -9)[/tex]

Expand

[tex](x,y) \to (\frac 13 \times 12, -\frac 13 \times9)[/tex]

[tex](x,y) \to (4, -3 )[/tex]

This means that, the image of the dilation is (4,-3)

See attachment for the image of the dilation

Read more about dilation at:

https://brainly.com/question/8532602

WILL MARK BRAINLIEST!!!!!!!!!!!!!!!!!! Why would someone choose to use a graphing calculator to solve a system of linear equations instead of graphing by hand? Explain your reasoning.

Answers

Answer:

A graphing calculator is more accurate than graphing by hand. If the slope and/or y-intercept is a fraction or decimal, it is more difficult to accurately graph by hand.

Step-by-step explanation:

Answer:

WHEN U GRAPH WITH A CALCULATOR  IT IS MUCH MORE ACCURATE

ESPECIALLY IF THERE R FRACTIONS AND DECIMALS AND THE GRAPHING CALCULATOR GOES ON FOREVER WHERE AS THE GRAPHING PAPER  ENDS

Step-by-step explanation:

HOPE I HELPED

PLS MARK BRAINLIEST

DESPERATELY TRYING TO LEVEL UP

          ✌ -ZYLYNN JADE ARDENNE

JUST A RANDOM GIRL WANTING TO HELP PEOPLE!

                                         PEACE!



Which function is graphed below?

Answers

Answer:

The answer is f(x) = -sin(x) as you can see in the graph below

Step-by-step explanation:

Select all that apply. If x^2+b/ax+c/a=0 ; then: The sum of its roots = -b/a? The difference of its roots =-b/a? The product of its roots = c/a?The division of its roots = c/a? I can select multiple.

Answers

Answer:

             The first and the third

Step-by-step explanation:

[tex]x^2+\frac bax+\frac ca=0\\\\ ax^2+bx+c=0\\\\x_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a}\qquad\quad x_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\\\\\x_1+x_2=\dfrac{-b-\sqrt{b^2-4ac}}{2a}+\dfrac{-b+\sqrt{b^2-4ac}}{2a}=\dfrac{-2b}{2a}=\dfrac{-b}a\\\\\\x_1\cdot x_2=\dfrac{-b-\sqrt{b^2-4ac}}{2a}\cdot\dfrac{-b+\sqrt{b^2-4ac}}{2a}=\\\\{}\ \ =\dfrac{b^2-b\sqrt{b^2-4ac}+b\sqrt{b^2-4ac}-(\sqrt{b^2-4ac})^2}{2a}=\dfrac{b^2-(b^2-4ac)}{4a^2}=\\\\{}\ \ =\dfrac{b^2-b^2+4ac}{4a^2}=\dfrac{4ac}{4a^2}=\dfrac{c}{a}[/tex]

[tex]x_1-x_2=\frac{-b-\sqrt{b^2-4ac}}{2a}-\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{-2\sqrt{b^2-4ac}}{2a}=\frac{-\sqrt{b^2-4ac}}{a}\\\\\\x_1\div x_2=\frac{-b-\sqrt{b^2-4ac}}{2a}\div\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{-b-\sqrt{b^2-4ac}}{2a}\,\cdot\,\frac{2a}{-b+\sqrt{b^2-4ac}}=\\\\=\frac{-b-\sqrt{b^2-4ac}}{-b+\sqrt{b^2-4ac}}=\frac{b+\sqrt{b^2-4ac}}{b-\sqrt{b^2-4ac}}=\frac{b^2+2\sqrt{b^2-4ac}+b^2-4ac}{b^2-b^2+4ac}=\frac{2b^2+2\sqrt{b^2-4ac}-4ac}{4ac}=[/tex]

[tex]=\frac{b^2+\sqrt{b^2-4ac}-2ac}{2ac}[/tex]

An exponential growth function has a base that is____one?
Please help

Answers

Answer:

greater than

Step-by-step explanation:

An exponential growth function has a base that is__greater than__one.

If the base is less than one, it will be a decay function.

Note: the above assumes an exponent greater than one as well.

Hi how to solve this simultaneous equation

Answers

Answer:

[tex]\large \boxed{\sf \ \ x=\pm8 \ \ or \ \ x=\pm2 \ \ }[/tex]

Step-by-step explanation:

Hello, please consider the following.

First of all, we can assume that x and y are different from 0, as we cannot divide by 0.

And from the first equation we can write y as a function of x as below.

[tex]y=\dfrac{16}{x}[/tex]

And then, we replace it in the second equation to get.

[tex]\dfrac{x}{\frac{16}{x}}+\dfrac{\frac{16}{x}}{x}=\dfrac{17}{4}\\\\<=> \dfrac{x^2}{16}+\dfrac{16}{x^2}=\dfrac{17}{4}\\\\\text{*** We multiply by }16x^2 \text{ both sides ***}\\\\x^4+16*16=\dfrac{17*16}{4}x^2\\\\x^4-68x^2+3600=0\\\\\text{*** The product of the zeroes is 3600 = 64*4 and the sum is 64+4=68 ***}\\\\\text{*** So we can factorise *** }\\\\x^4-64x^2-4x^2+3600=x^2(x^2-64)-4(x^2-64)=(x^2-64)(x^2-4)=0\\\\x^2=64=8^2 \ \ or \ \ x^2=4\\\\x=\pm8 \ \ or \ \ x=\pm2\\[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Suppose xy > 0. Describe the points whose coordinates are solutions to the inequality. please answer in detail

Answers

Answer

so,if x*y> than zero, we know that neither x nor y can be zero, because anything multiplied by zero is equal to zero. now , we also know, that a negative  times a negative is positive, and a positive  times a positive times a positive is a positive

Step-by-step explanation:

How does the period of f(x)= cos⁡(2x) relate to the period of the parent function cos⁡ x?

Answers

Answer:

Both have the same period which is 2π

Step-by-step explanation:

This is probably pretty easy, I could solve all the other ones but I got stuck on this one.

Answers

Answer:

78

Step-by-step explanation:

Let x be the score on the next test

We are averaging 6 tests and want an average of 75

( 82+91+38+78+83+x) /6 = 75

Multiply each side by 6

( 82+91+38+78+83+x) = 75*6

( 82+91+38+78+83+x)  =450

Combine like terms

x+372 = 450

Subtract 372 from each side

x+372-372 = 450-372

x =78


[tex] \sqrt[3]{y} = a(c + \frac{1}{x})[/tex]

Answers

Greetings from Brasil...

Here we don't have much to go

∛Y = A.(C + 1/X)

∛Y = (AC + A/X)

raising both members to the cube.....

(∛Y)³ = (AC + A/X)³

from Notable Products: (a + b)³ = a³ + 3a²b + 3ab² + b³

Y = (AC)³ + 3(AC)².(A/X) + 3AC(A/X)² + (A/X)³

Y = A³[C³ + (3C²/X) + (3C/X²) + (1/X³)]

Drag the tiles to the correct boxes to complete the pairs.
This table gives Information about vehicles sold at a dealership in a month.
Gasoline Diesel
18
5
Hatchback
Sedan
15
12
SUV
3
7
Analyze this data, and match each percentage to the description It represents. Round your answers to the nearest whole number.
30%
44%
21%
8%
42%
78%
the percentage of hatchbacks that run on gasoline
the percentage of diesel vehicles that are hatchbacks
tum. All rights reserved.

Answers

Answer:

The percentage of hatchbacks that run on gasoline: 78%

The percentage of diesel vehicles that are hatchbacks: 21 %

Step-by-step explanation:

The given table represents the following:

Hatchbacks that run on Gasoline = 18

Hatchbacks that run on Diesel = 5

Total number of hatchbacks = 23

Sedan that run on Gasoline = 15

Sedans that run on Diesel = 12

Total number of sedans = 27

SUVs that run on Gasoline = 3

SUVs that run on Diesel = 7

Total number of SUVs = 23

Total number of gasoline vehicles = 36

Total number of Diesel vehicles = 24

To find:

the percentage of hatchbacks that run on gasoline

the percentage of diesel vehicles that are hatchbacks

Solution:

[tex]\text{Percentage of hatchbacks that run on gasoline = } \dfrac{\text{Number of hatchbacks on gasoline}}{\text{Total number of hatchbacks}}\times 100\\\Rightarrow \text{Percentage of hatchbacks that run on gasoline = } \dfrac{18}{23}\times 100 \approx 78\%[/tex]

[tex]\text{Percentage of diesel vehicles that are hatchbacks = } \dfrac{\text{Number of hatchbacks that run on diesel}}{\text{Total number of diesel vehicles}}\times 100\\\Rightarrow \text{Percentage of diesel vehicles that are hatchbacks = } \dfrac{5}{24}\times 100 \approx 21\%[/tex]

So, the answer is:

The percentage of hatchbacks that run on gasoline: 78%

The percentage of diesel vehicles that are hatchbacks: 21%

Answer:

I used a calculator and this is what can up with

Step-by-step explanation:

 what is the measure of AC 

Answers

Answer:

A

Step-by-step explanation:

The inscribed angle ABC is half the measure of its intercepted arc, thus

arc AB = 2 × 44° = 88° → A

Answer:

A

Step-by-step explanation:

The measure of an inscribed angle is half the measure of it's intercepted arc

The factor tree for 3,025 is shown. A factor tree starts with 3,025 at the top. 3,025 branches down to 5 on the left and 605 to the right. 605 branches down to 5 on the left and 121 on the right. 121 branches down to 11 on the left and 11 on the right. What is the simplest form of StartRoot 3,025 EndRoot?

Answers

Answer:

(5^2)(11^2)

Step-by-step explanation:

Taking all the factors in the left hand side of the factor tree, we have

5,5,11,11

5 twice

5^2=25

11 twice

11^2=121

The factor of 3,025=(5^2)(11^2)

Alternatively

3025÷5=605

605÷5=121

121÷11=11

11÷11=1

We have prime number 5 as divider twice and prime number 11 as a divider twice

Therefore,

5^2*11^2=3,025

Check

(5^2)(11^2)

=(25)(121)

=3,025

Answer:

c

Step-by-step explanation:

what the formula of speed

Answers

Answer:

The formula for speed is s=(distance traveled)/(time elapsed)

Answer:

[tex]\huge \boxed{S =\frac{d }{t} }[/tex]

[tex]\rule[225]{225}{2}[/tex]

Step-by-step explanation:

The formula to find speed is as follows:

[tex]\Longrightarrow \ \ \displaystyle \sf speed =\frac{distance \ travelled }{time \ taken}[/tex]

[tex]\Longrightarrow \ \ \displaystyle S =\frac{d }{t}[/tex]

[tex]\rule[225]{225}{2}[/tex]

What the correct answer now

Answers

Answer:

388.6 yd²

Step-by-step explanation:

the missing angle in triangle is 180 - 32 - 38 = 110

Law of sines: 31/sin 38 = VT/sin 32

VT = 26.68

area = 1/2ab sinC

A = 1/2 (31)(26.68) sin 110

388.6 yd²

Eparture time of a car is 0540 hours and it traveled for 45 minutes before it reached its destination. At what time did the car arrived at its destination : *

Answers

Answer:

The time at which the car arrives at its destination is 0625 hours or 6: 25 am or 25 minutes past 6.

Step-by-step explanation:

Departure time = 0540 Hours means 5: 40 am or 40 minutes past 5 in the morning.

Now add 45 mins

Hours : Minutes

      5:        40

      +         45

    5      :    85

But 1 hour contains 60 minutes so 85 - 60 gives 25 minutes . those 60 minutes = 1 hour are carried over the hours and added .

Hours : Minutes

       1

      5:        40

      +         45

    6      :    25

The time at which the car arrives at its destination is 0625 hours or 6: 25 am or 25 minutes past 6 in the morning.

y=-2x-21 determine the intercepts of the line (,) (,) ASAPPPP

Answers

Answer:

x intercept (10.5,0)

y intercept (0, -21)

Step-by-step explanation:

y=-2x-21

there are two intercept for a line

x intercept, the point of given equation of  line which lies on x axis.

For x intercept corodinate of y is o

Thus, value x intercept is form (x,0)

putting these value in y=-2x-21, we find x intercept

0=-2x-21

2x = 21

x = 21/2 = 10.5

Thus, x intercept (10.5,0)

Y intercept, the point of given equation of  line which lies on y axis.

For Y intercept coordinate of x is o

Thus, value y intercept is form (0,y)

putting these value in y=-2x-21, we find y intercept

y = -2*0 -21

y = -21

Thus, y intercept (0, -21)

The sales tax on clothing in Nebraska is 5.5%. Calculate how much tax you need to pay on a shirt if it costs $18.20 before tax. Round your answer to the nearest cent. ( pls answer asap and thanks ) will give BRANLIEST

Answers

Answer:

$1.00

Step-by-step explanation:

The tax rate in Nebraska = 5.5%

Cost of the shirt before tax = $18.20

Therefore:

Tax to be paid = 5.5% of $18.20

[tex]=0.055 \times \$18.20\\=\$1.00 $(correct to the nearest cent)[/tex]

The amount you need to pay as tax is $1.00.


Help please! Thanks

Answers

Answer:

E. 0

Step-by-step explanation:

There isn't any guarantee that there are any people that have their birthdays in the same month based on what you're given, so your answer would be 0.

WILL GIVE BRAINLIEST A rocket is launched vertically from the ground with an initial velocity of 64. Write a quadratic function that shows the height, in feet, of the rocket t seconds after it was launched. Graphon the coordinate plane.

Answers

Answer:

[tex]h=64t-4.9t^{2}[/tex]

Please refer to the attached graph.

Step-by-step explanation:

Given that

Initial velocity of rocket = 64 and is launched vertically.

To find:

Quadratic equation in time to represent the height of rocket in feet.

Solution:

Unit of initial velocity is not given in the question statement, let the velocity be in feet/second only.

Initial velocity, u  = 64 feet/s

The acceleration will be = -g because it is going opposite to gravitational force so it will be negative acceleration motion (speed will be decreasing) so -g will be the acceleration.

Formula for distance traveled is given as:

[tex]s=ut+\dfrac{1}{2}at^2[/tex]

Here Let us represent s by 'h'

a = -g = 9.8 m/[tex]s^2[/tex]

Let us put the known values in the formula:

[tex]h=64t+\dfrac{1}{2}(-9.8)t^2\\\Rightarrow h =64t-4.9t^2[/tex]

It is a quadratic equation, the equation represents the graph of a parabola.

Please refer to the attached graph.

Value of height is 0 at 0 second and ~13 seconds

2.
The roots of the equation x2-3x - m(m + 3) = 0,
where m is a constant, are
(a) m, m + 3
(b) -m, m + 3
(c) m,- (m+3) (d) -m, -(m + 3)
(AI 2011)​

Answers

Answer:

(b) -m, m + 3

Step-by-step explanation:

x² − 3x − m(m + 3) = 0

x² − 3x = m(m + 3)

x² − 3x + 9/4 = m(m + 3) + 9/4

(x − 3/2)² = m(m + 3) + 9/4

(x − 3/2)² = m² + 3m + 9/4

(x − 3/2)² = (m + 3/2)²

x − 3/2 = ±(m + 3/2)

x − 3/2 = m + 3/2, -m − 3/2

x = m + 3, -m

A small cargo plane currently has 140 pounds of cargo aboard. In addition, n boxes weighing 45 pounds each will be brought aboard. Suppose that the total weight of the cargo on board must be less than p pounds. Using the values and variables given, write an inequality describing this.

Answers

Answer:

The inequality that represents this situation is: [tex]140 + 45*n < p[/tex]

Step-by-step explanation:

Since the plane already had 140 pounds on board and "n" boxes will be loaded on it, then the weigh of each box multiplied by the number of box should be the extra cargo on the plane. This extra cargo added to the previous load must be less than the limit of cargo the plane can take as shown below:

[tex]140 + 45*n < p[/tex]

plzzz hellpppppp...........​

Answers

Answer:

Bearing of R from S = S 45° E or 135°

The bearing of R from Q

= S 66.42° w or 246.42°

Step-by-step explanation:

Distance between R and S

RS²= RP²+PS²

RS²= 15²+15²

RS²=225+225

RS= √450

RS= 21.21

Angle at S

21.21= 15/sins

Sin s= 15/21.21

S= sin^-1 15/21.21.

S= 45°

90+45= 135°

Bearing of R from S = S 45° E or 135°

Distance between R and Q

RQ²= PQ²+PR²

RQ²= 35²+15²

RQ²=1225+225

RQ= √1450

RQ= 38.08

RQ= 15/sinQ

SinQ= 15/38.08

SinQ= 0.40

Q=23.58°

90-23.58 = 66.42°

66.42+180= 246.42°

The bearing of R from Q

= S 66.42° w or 246.42°

32 is an example of A. an algebraic equation B. a numerical expression C. a numerical equation D. an algebraic expression Reset

Answers

ayuda plis nosé donde estoy q Brainli es este

ayuda

Answer:

hmm I'm not sure but i think it's B. a numerical expression

Sowwy if this didn't help :c

The local ice cream shop offers 3 different types of cones and 15 different flavors of ice cream. How many possible ice cream cones (one scoop) can a customer order? a 40 b 18 c 45 d 35

Answers

Answer:

45

Step-by-step explanation:

There are 3 cones and 15 flavors

Multiply the number of cones by the number of flavors

3*15

45

There are 45 possible combinations

Irving cannot remember the correct order of the five digits in his ID number. He does remember that the ID number contains the digits 1, 4, 3, 7, 6. What is the probability that the first three digits of Irving's ID number will all be odd numbers?

Answers

Answer: 1/10

Step-by-step explanation:

given:

numbers contained in the i.d

1,4,3,7,6

1. permutations of 5 possible outcome

T = 5

= 5 * 4 * 3 * 2 *1

= 120 times.

2. permutations  of  3 odd numbers

( 1,3 and 7 )

T = 3

= 3 * 2 * 1 * 2 * 1

= 12

probability of of first three digits being odd numbers

P = 12 / 120

= 1 / 10

Answer: The probability is 0.10

Step-by-step explanation:

The ID number has five digits, and the digits can be 1, 4, 3, 7 and 6, and I will assume that each digit appears only once.

Then if we want to calculate the probability that the first 3 digits will be odd is:

Suppose that we have 5 slots, we want that in the first two slots to have odd numbers.

In our set, we have only 3 odd numbers {1, 3 and 7}

Then if we want an odd number in the first digit, we have 3 options

If we want an odd number in the second digit, we have two options (because we already selected one in the first selection)

If we want an odd number in the first digit, we have only one option.

For the fourth digit we have one of the two remaining even options, so we have 2 options.

For the fifth digit, we have only one digit.

The number of combinations is equal to the product of the number of options in each selection:

c = 3*2*1*2*1 = 12

Now, the total number of combinations is:

For the first digit we have 5 options

for the second digit we have 4 options.

for the third digit we have 3 options.

for the fourth digit we have 2 options.

for the fifth digit we have 1 options.

The number of combinations is:

C = 5*4*3*2*1 = 120.

Then the probability that the first 3 digits are odd numbers, is equal to the quotient between number of combination that start with 3 odd digits and the total number of combinations:

P = c/C = 12/120 = 0.10

2 There are x fish in a pond.
Omar puts 5 more fish in the pond.
How many fish are in the pond now?​

Answers

Answer:

x+5

Step-by-step explanation:

We are adding fish

There were x and then we added 5

There are now

x+5

Answer:

x+5

Step-by-step explanation:

since there are x fish, adding five more would make it x+5        

Please answer ASAP. A baseball is hit upward from a platform that is m high at an initial speed of 29m/s. The approximate height of the baseball, h meters, after x seconds is given by the equation: h - 1= -5x^2 + 29x a) determine the time period for which the baseball is higher than 18m. Give the answer to the nearest tenth of a second. Explain your strategy. b) What are the restrictions on the domain and range of the related function?

Answers

Answer:

a) about 0.7 seconds to 5.1 seconds.

b) Listed below.

Step-by-step explanation:

h - 1 = -5x^2 + 29x

h = -5x^2 + 29x + 1

a) We will find the amount of time it takes to get to 18 meters.

18 = -5x^2 + 29x + 1

-5x^2 + 29x + 1 = 18

-5x^2 + 29x - 17 = 0

We will then use the quadratic formula to find the answer.

[please ignore the A-hat; that is a bug]

[tex]\frac{-29±\sqrt{29^2 - 4 * -5 * -17} }{2 * -5}[/tex]

= [tex]\frac{-29±\sqrt{841 - 340} }{-10}[/tex]

= [tex]\frac{-29±\sqrt{501} }{-10}[/tex]

= [tex]\frac{-29 ± 22.38302929}{-10}[/tex]

= [tex]\frac{-6.616970714}{-10}[/tex] and [tex]\frac{-51.38302929}{-10}[/tex]

= 0.6616970714 and 5.138302929

So, the time period for which the baseball is higher than 18 metres ranges from about 0.7 seconds to 5.1 seconds.

b) Restrictions on the domain and range of the function are that the domain and range can never be negative, since time cannot be negative, and height cannot be negative. The height cannot exceed the vertex of the parabola, since that is the highest the ball will ever go. It cannot exceed that height since gravity will cause the ball to fall down.

Hope this helps!

Other Questions
In a survey of 2957 adults, 1455 say hey have started paying bills online in the least year construct a 99% confidence interval for the population proportion PLEASE HELP ASAP. IT'S URGENT Suppose that a perfectly competitive firm faces a market price of $7 per unit, and at this price the upward-sloping portion of the firm's marginal cost curve crosses its marginal revenue curve at an output level of 1 comma 400 units. If the firm produces 1 comma 400 units, its average variable costs equal $6.50 per unit, and its average fixed costs equal $0.80 per unit.Required:a. What is the firm's maximizing (or loss-minimizing output level?b. What is the amount of it's economic profits (or losses) at this output level? A workstation must produce 200 units an hour. It takes 45 minutes to receive the necessary material for production from the previous workstation. Output is moved between workstations in containers holding 30 units. If the process uses a safety factor of 20%, then the number of kanbans that should be circulating between this workstation and the previous workstation is: Group of answer choices LineA.C.D.B.DefinedPostulatesTheoremsUndefinedTerms If you put up $39,000 today in exchange for a 6.5 percent, 16-year annuity, what will the annual cash flow be? (Do not round intermediate calculations and round your answer to 2 decimal places, e.g., 32.16.) FINAL QUESTION!!!!! PLEASE TAKE A LOOK!!!! EASY BUT IM JUST DUMB!!!! PLS LOOK AT LEAST!!!!!!!!!!!!!!! I REALLY NEED IT!!!!!!! HELPPPPPPP!!!! LAST QUESTIONS!!!!What difficulties did African Americans and secondgeneration Americans face in America between the 1940s and 1960s, and how did at least two of the writers in this module address these issues? help me please and thank u if u help me u get 5 starsLook at these details from a paragraph about the same topic: The zebra shark squeezes into small places to look for prey. Special whisker-like feelers help these sharks find food. The zebra shark keeps still for long periods of time to wait for prey.Choose the main idea that ties all the details together.A. The zebra shark can stay very still and fit into small places.B. The zebra shark can suck fish out of hidden places with its mouth.C. The zebra shark has special ways of hunting for food. What value, written as a decimal, should Lena use as the common ratio? Calculate the pH of a buffer solution that contains 0.25 M benzoic acid (C 6H 5CO 2H) and 0.15M sodium benzoate (C 6H 5COONa). [K a = 6.5 10 5 for benzoic acid] Which expression is equivalent to-21/4over -2/3 Which of these statements are true about managing through Active Directory? Check all that apply. How can you fit data into a pictogram? A company issues $60,000 of 6%, 5-year bonds dated January 1 that pay interest semiannually on June 30 and December 31 each year. If the issuer accepts $62,000 for the bonds, the premium on bonds payable will _________________ total interest expense recognized over the life of the bond by $ ______________. HELP PLEASE Solve the equation for x. the square root of the quantity x plus 4 end quantity minus 7 equals 1 x = 4 x = 12 x = 60 x = 68 Solve for x: (-1/2) x = 6 8. Which of the following prohibits association between church and government?O The Church and State ClauseO Free Exercise ClauseO Necessary and Proper ClauseEstablishment Clause state police job description Julie finds a snail on the sidewalk and wants to know whether or not the snail moves throughout the day. She places asingle mark on the sidewalk next to the snail.What will Julie use the mark for initially?determining how fast the snail movesacting as a standard unit of measuredetermining the displacement of the snailO acting as a reference point for detecting motion George spent $40.80 on 3 identical files and 2 identical pencil cases. Each file cost $5.40 less than a pencil case. How much did George pay for each file?