An object attached to a spring is pulled across a horizontal frictionless surface. If the force constant (spring constant) of the spring is 45 N/m and the spring is stretched by 0.88 m when the object is accelerating at 1.4 m/s2. What is the mass of the object?

Answers

Answer 1

Answer:

28.3kg

Explanation:

45=0.88*ml1.4

36.6=0.88m

divide through by 0.88

is said that

m=36.6/0.88

m=28.2857kg


Related Questions

How fast would a 106-kg object have to be moving at this height to have zero energy?

Answers

Answer:

This question is inconclusive considering you are not representing either kinetic or potential energy. It would just have to be laying on the ground stagnant to have neither potential or kinetic energy.

Explanation:

01:Posttest 01:Motion Along a Straight Line
5. At the same moment, one rock is thrown upward at 4.5 m/s and another thrown downward at 3.4 m/s. What is the relative velocity of the first rock
from the perspective of the second rock? Assume that up is positive.
ration
0 -7.9 m/s
O 7.9 m/s
jects
O 1.1 m/s
0-1.1 m/s
Motion
wton's
<
5 of 25
>
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99

Answers

Answer:

D

Explanation:

Given that one rock is thrown upward at 4.5 m/s and another thrown downward at 3.4 m/s. What is the relative velocity of the first rock

from the perspective of the second rock? Assume that up is positive.

Solution.

Since both of them are moving in the opposite direction, the relative velocity of the first rock from the perspective of the second rock will be

Relative velocity = 3.4 - 4.5

Relative velocity = - 1.1 m/s

Therefore, the relative velocity from the perspective of the second rock is negative 1.1 m/s.

The correct answer is option D.

PLEASE PLEASE PLEASE HELP

Answers

Answer:

Rain came along with lower temps

Explanation:

There was no rain on the warmer days

There were more clouds as the week went on

and the temp decreased during the week so rain came with lower temps is the only one that can be correct

What is the average velocity of a wave that travels an average distance of 6 m in 0.25 s?

Answers

S=Vt
V=S/t
V= 6/0.25
V=24m/s

What does the upper part of a YOUNGER
mountain top look like?.
A. a flattened pancake
B. it has a flat side
C. the top becomes rounded due to erosion
D. it has sharp peaks

Answers

Answer:

A

Explanation:

The upper part of a Younger mountain top look like a flattened pancake.

What is mountain?

In a process known as plate tectonics, sections of the Earth's crust, known as plates, collide with one another and buckle up like a car's hood in a head-on collision to build the world's largest mountain ranges.

One such enormous catastrophe, which began roughly 55 million years ago, eventually gave rise to the Himalaya in Asia. The Himalaya contains thirty of the tallest mountains in the world. With a height of 29,035 feet (8,850 meters), Mount Everest's peak is the highest point on the planet.

Mauna Kea, an inactive volcano on the island of Hawaii in the Pacific Ocean, is the highest peak in the world when measured from top to bottom.

Therefore, The upper part of a Younger mountain top look like a flattened pancake.

To learn more about mountain, refer to the link:

https://brainly.com/question/10690247

#SPJ2

A guitar string transmits waves at
315 m/s, and oscillates at 370 Hz.
What is the length of the string?
(Unit = m)

Answers

Answer:

The wavelength of the waves on the string is found using v = λf:

λ = v/f = 315/370 = 0.85135m

The first harmonic (fundamental) standing wave  formed on the string  has nodes only at the ends (see diagram in link) so:

String length = λ/2 = 0.85135/2 = 0.426m (to 3 sig. figs.)

0.5-lbm of a saturated vapor is converted to asaturated liquid by being cooled in a weighted piston-cylinder device maintained at 50 psia. During the phase conversion,thesystem volume decreases by 1.5 ft3; 250 Btu of heat areremoved; and the temperature remains fixed at 15F. Estimatethe boiling point temperature of this substance when itspressure is 60 psia.

Answers

Answer:

The boiling point temperature of this substance when its pressure is 60 psia is  480.275 R

Explanation:

Given the data in the question;

Using the Clapeyron equation

[tex](\frac{dP}{dT} )_{sat } = \frac{h_{fg}}{Tv_{fg}}[/tex]

[tex](\frac{dP}{dT} )_{sat } = \frac{\frac{H_{fg}}{m} }{T\frac{V_{fg}}{m} }[/tex]

where [tex]h_{fg[/tex] is the change in enthalpy of saturated vapor to saturated liquid ( 250 Btu

T is the temperature ( 15 + 460 )R

m is the mass of water ( 0.5 Ibm )

[tex]V_{fg[/tex] is specific volume ( 1.5 ft³ )

we substitute

[tex](\frac{dP}{dT} )_{sat } =( \frac{250Btu\frac{778Ibf-ft}{Btu} }{0.5})[/tex] / [tex]( (15+460)\frac{1.5}{0.5})[/tex]  

[tex](\frac{dP}{dT} )_{sat } =[/tex] 272.98 Ibf-ft²/R

Now,

[tex](\frac{dP}{dT} )_{sat } =[/tex] [tex](\frac{P_2 - P_1}{T_2 - T_1})_{sat[/tex]

where P₁ is the initial pressure ( 50 psia )

P₂ is the final pressure ( 60 psia )

T₁ is the initial temperature ( 15 + 460 )R

T₂ is the final temperature = ?

we substitute;

[tex]T_2[/tex] [tex]= ( 15 + 460 ) + \frac{(60-50)psia(\frac{144in^2}{ft^2}) }{272.98}[/tex]

[tex]T_2 = 475 + 5.2751\\[/tex]

[tex]T_2 =[/tex] 480.275 R

Therefore, boiling point temperature of this substance when its pressure is 60 psia is  480.275 R

A car travels at constant speed of 60 km per hour for 3 hours.
a) find the distance traveled​

Answers

Answer: 20km

Explanation:

60 divided by 3 equals 20km

1. For the masses shown with the indicated velocities. Consider the increasing
direction of the x-axis toward the right.
9.0 kg 4.0 m/s
8.0 m/s
6.0 kg
a) Find the magnitude of the momentum of the system. (Do not include the units
in the answer)
Your answer
b) What is the direction of the momentum of the system?
Choose
c) Determine the total kinetic Energy of the System. (Do not include the units in
the answer)
Your answer

Answers

Momentum=mv =9x4=36
=8x6=48

Who knows how to do this?

Answers

Answer:

1)   F = 8.789 10² N, 2)   F = 1.5 10⁴ N

Explanation:

We can solve this exercise using Coulomb's law

         F =[tex]k \frac{q_1q_2}{r^2}[/tex]

Knowing that charges of the same sign repel

let's apply this equation to our case

1) the charges are q = - 0.0025 C and the distance between them r = 8 m

       we calculate

           F = 9 10⁹ 0.0025 0.0025 /8²

           F = 8.789 10² N

as the two charges are of the same sign the force is repulsive

2) q₁ = -0.004C and q₂ = -0.003 C with a distance of r = 3.0 m

    we calculate

             F = 9 10⁹ 0.004 0.003 / 3²

             F = 1.5 10⁴ N

state characteristics of the images formed by pin - hole camera​

Answers

Answer:

Real image

Explanation:

The picture is real, but it is reversed and tiny. An picture generated by a pinhole camera has certain features. As compared item, the image created by a pinhole camera is normally pretty small and looks reversed both on the vertically and horizontally axis.

21. Make sure carts are facing so that Velcro strips can stick together when they collide. Keep an extra 250g of mass on the cart 2 which starts at rest. Change sign on velocity center. Practice giving an initial velocity to cart 1 while cart 2 starts at rest so that after the collision both carts move as a combined object with mass m1 m2. What is the type of collision now you are practicing with two carts

Answers

Answer:

his type of shock is called inelastic

Explanation:

This exercise is for vehicle crashes, which corresponds to exercise is momentum conservation.

We must begin by defining a system formed by the two cars so that the forces during the crash have been intense and the moment is preserved.

Looking for the moments

initial. Before the crash

           p₀ = m₁ v₁₀

final. After the crash

           p_f = (m₁ + m₂) v

the conservation of the moment is written

           p₀ = p_f

           m₁ v₁₀ = (m₁ + m₂) v

This type of shock is called inelastic and has the characteristics that the kinetic energy is not conserved.

2. An alternating current is represented by the equation I=20sin 100mt.
Compute its frequency and the maximum r.m.s values of current.
Ans: 50Hz,20A,14.14A


please i went to asked ​

Answers

Explanation:

The general equation of an AC current is given by :

[tex]I=I_o sin\omega t[/tex]

Where

I₀ is the peak value of current

[tex]\omega[/tex] is angular frequency

[tex]As\ \omega=2\pi f[/tex]

So,

[tex]f=\dfrac{\omega}{2\pi}\\\\f=\dfrac{100\pi}{2\pi}\\\\f=50\ Hz[/tex]

We know that,

[tex]I_{rms}=\dfrac{I_0}{\sqrt{2}}\\\\=\dfrac{20}{\sqrt{2}}\\\\I_{rms}=14.14\ A[/tex]

So, the frequency is 50 Hz and the maximum rms value of current is 14.14 A.

which mountains are
YOUNGEST?

Answers

The Answer is definitely B

Introduction to Forces
Warm-Up Active
How do forces affect the motion of an object?

Answers

Answer:

Forces can affect an object.

Balanced forces allow an object to continue moving at a constant motion (law of inertia).

Unbalanced forces cause a change in motion.

Answer:

Because of my physics teacher I would put this entire explanation below if i were u

Explanation:

Forces affect how objects move. They may cause motion; they may also slow, stop, or change the direction of motion of an object that is already moving.

Since force cause changes in the speed or direction of an object, we can say that forces cause changes in velocity. Remember that acceleration is a change in velocity. So forces cause acceleration.

While measuring the distance of the magnetic sensor in your phone from the center of the magnet (or coil) you decided to include uncertainties from two places. One is the uncertainty in locating the center of the magnet (or coil) and you estimated it as 0.25 cm. The other is the uncertainty in locating the position of the sensor in the phone and you estimated it as 0.45 cm. What is the uncertainty in the distance measurement when calculated using quadrature method

Answers

Answer:

the uncertainty in the distance measurement is 0.5148

Explanation:

Given the data in the question;

uncertainty in locating the center of the magnet is estimated to be 0.25 cm,

uncertainty in locating the position of the sensor in the phone is estimated to be 0.45 cm,

Using quadrature method, uncertainty in the distance measurement = ?

We know that;

Using  quadrature method, Combined Uncertainty calculated by;

U[tex]_c[/tex] = √( U₁² + U₂² + ........... )

where U₁ is uncertainty in first measurement and U₂ is uncertainty in second measurement, et cetera.

now we substitute;

U[tex]_c[/tex] = √( U₁² + U₂² )

U[tex]_c[/tex] = √( (0.25)² + (0.45)² )

U[tex]_c[/tex] = √( 0.0625 + 0.2025 )

U[tex]_c[/tex] = √( 0.265 )

U[tex]_c[/tex] = 0.5148

Therefore, the uncertainty in the distance measurement is 0.5148

Define wheel and axle 4 example of wheel and axle​

Answers

Answer:

A system of two co-axial cylindersof different diameters which rotate together is called wheel and axle example; the door knob , knob of the tap ,screw driver,water tap

A small car is traveling at a speed of 60 mph on the highway. In the next lane, a large passenger bus is traveling at the same speed.

Answers

Answer:

A. The bus has more kinetic energy than the car.

Explanation:

We know that

Kinetic energy is the energy amount possessed from the body as in the motion

Also, the following formula should be used to determine the kinetic energy

Kinetic energy = 1 ÷ 2mv²

Here m represents the mass of the body  

and v represents the velocity of the body.

Therefore it should be based on the mass & velocity of the body  

In the case when the passenger bus have more kinetic energy as compared to the car so this is because of the the big mass  

Therefore, the first option is correct

If moving charges create magnetic fields and all materials are made up of atoms that have moving charges, why are most things NOT magnetic?

Answers

Magnetism is the result of the "spin" of the electron and most of these cancel each other out in larger bodies thus most things not being magnetic.

The following lists the length and diameter of three copper wires. Wire A
- 5 cm long, 10 mm thick; Wire B- 10 cm long, 5 mm thick; Wire C - 15 cm
long, 1 mm thick. Which of these wires most likely has the highest
resistance? Help i’m taking a test

Answers

Answer:

Resistance is proportional to length and inversely proportional to area.

L1 =  5 cm

L2 = 10 cm

L3 = 15 cm

A1 = k * (.50 cm)^2

A2 = k * (.25 cm)^2 = 1/4 A1

A3 = k * (.05 cm)^2= 1/100 A1

R1 = 1 * 1 = 1

R2 = 2 * 4 = 8 R1

R3 = 3 * 100 = 300 R1

R3 has greatest resistance

On a distance-time graph, what is the difference between a shallow slope and a steep slope?

A. A shallow slope shows the same speed as a steep slope.
B. A shallow slope shows a lower speed than a steep slope.
C. A shallow slope shows a more positive speed than a steep slope.
D. A shallow slope shows a higher speed than a steep slope.

Answers

B. A shallow slope shows a lower speed than a steep slope.

8.
Determine the focal length of a diverging lens that produces an image that is 12.9 cm from the lens
(and on the object's side) when the object is 32.4 cm from the lens.

Answers

Answer:

=-21.43

Explanation:

::::::::::::::::::

We have that the focal length is

[tex]f=19.058[/tex]

From the Question we are told that

image distance [tex]v=12.9[/tex]

object distance [tex]u=32.4[/tex]

Generally the equation for focal length   is mathematically given as

[tex]\frac{1}{f}=\frac{1}{v}-\frac{1}{u}\\\\\frac{1}{f}=\frac{1}{12}-\frac{1}{32.4}[/tex]

[tex]f=19.058[/tex]

For more information on this visit

https://brainly.com/question/16188698

g One arm of a Michelson interferometer has a section of length 2.1 cm where the air can be evacuated. The dielectric constant of air is 1.00059. Find the number of fringes which will shift in the interference pattern of the interferometer when the air is evacuated for an interferometer illuminated with light of 663 nm wavelength.

Answers

Answer:

The answer is "12388.17"

Explanation:

[tex]l = 2.1 cm = 2.1 \times 10^{-2}\ m\\\\k = 1.00059\\\\\eta = \sqrt{k}= \sqrt{1.00059}\\\\\lambda = 663 nm = 663 \times 10^{-9}\ m[/tex]

Users now know that perhaps the number of fingers the shift is provided when a path difference [tex]\Delta d[/tex] are inserts between both the two arms  

[tex]N = \frac{\Delta d}{\lambda}[/tex]

The optical pull-up in the arm is initially given by

[tex]d = 2\eta l[/tex]

Its new length of the different sense as the reflection coefficient adjustments between [tex]\eta[/tex] (air) and 1 so if we evacuate air from of the arm (vacuum).

The new length of a path is therefore

 [tex]d'' = 2l[/tex]

Therefore, the different path  

[tex]\Delta d=d-d''=2l(\eta -1)[/tex]

So, The fringe shifts number are

[tex]N= \frac{2l(\eta -1)}{\lambda}[/tex]

    [tex]= \frac{2 \times 2.1 \times 10^{-2} (\sqrt{1.00059}-1)}{663 \times 10^{-9}}\\\\=12388.17[/tex]

An aircraft lands at a speed of 180km/h
and stops in 2 minutes. The mass of the
aeroplane is 10,000kg. Find the length
of the distance of runway.
a. 18 km
b. 6 km
c. 4 km
d. 3 km​

Answers

B.18 km

Oxkdkkdksksjdkdss
B 6km......................

(c) A coal-fired power station generates electricity at night when it is not needed.
Some of this energy is stored by pumping water up to a mountain lake. When there is high
demand for electricity, the water is allowed to flow back through turbines to generate electricity.
On one occasion, 2.05 x 108kg of water is pumped up through a vertical height of 500 m.
(i) Calculate the weight of the water.
weight =
[1]

Answers

Answer:

ion know tbh

Explanation:

A microscope has an eyepiece with a 1.8 cm focal length and a 0.8 cm focal length objective lens. Assuming a relaxed eye, calculate a) the position of the object if the distance between the lenses is 16 cm, and b) the total magnification.

Answers

Answer:

[tex]0.848\ \text{cm}[/tex]

[tex]232.66[/tex]

Explanation:

N = Near point of eye = 25 cm

[tex]f_o[/tex] = Focal length of objective = 0.8 cm

[tex]f_e[/tex] = Focal length of eyepiece = 1.8 cm

l = Distance between the lenses = 16 cm

Object distance is given by

[tex]v_o=l-f_e\\\Rightarrow v_o=16-1.8\\\Rightarrow v_o=14.2\ \text{cm}[/tex]

[tex]u_o[/tex] = Object distance for objective

From lens equation we have

[tex]\dfrac{1}{f_o}=\dfrac{1}{u_o}+\dfrac{1}{v_o}\\\Rightarrow u_o=\dfrac{f_ov_o}{v_o-f_o}\\\Rightarrow u_o=\dfrac{0.8\times 14.2}{14.2-0.8}\\\Rightarrow u_o=0.848\ \text{cm}[/tex]

The position of the object is [tex]0.848\ \text{cm}[/tex].

Magnification of eyepiece is

[tex]M_e=\dfrac{N}{f_e}\\\Rightarrow M_e=\dfrac{25}{1.8}\\\Rightarrow M_e=13.89[/tex]

Magnification of objective is

[tex]M_o=\dfrac{v_o}{u_o}\\\Rightarrow M_o=\dfrac{14.2}{0.848}\\\Rightarrow M_o=16.75[/tex]

Total magnification is given by

[tex]m=M_eM_o\\\Rightarrow m=13.89\times 16.75\\\Rightarrow m=232.66[/tex]

The total magnification is [tex]232.66[/tex].

Yellow light has a frequency of 5.21 x 10^15 Hz. What is the wavelength of yellow light?

Answers

Answer: The yellow light with a frequency equal to 5.21 x 1014 Hz will have a wavelength of E) 576 nm

Objectives
Pecina
y
01:Posttest 01:Motion Along a Straight Line
eration
1. An elevator moving down passes its neighbor, an elevator moving up. Their speed relative to one another is 8 m/s. What is the velocity of each
elevator relative to someone standing on the first floor? Assume that the elevators are traveling at the same speed, and that the upward direction is
positive.
tant Acceleration
O Both elevators are moving at 8 m/s.
y Falling Objects
O One elevator is moving at 4 m/s; the other elevator is moving at -4 m/s.
O Both elevators are moving at 4 m/s.
tive Velocity
O One elevator is moving at 8 m/s; the other elevator is moving at -8 m/s.
Posttest
on in a Plane
ton's Laws of Motion
>
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Submit
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Description
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4/4/2021

Answers

Answer:

B

Explanation: Given that an elevator moving down passes its neighbor, an elevator moving up. Their speed relative to one another is 8 m/s. What is the velocity of each elevator relative to someone standing on the first floor? Assume that the elevators are traveling at the same speed, and that the upward direction is positive.

O Both elevators are moving at 8 m/s.

y Falling Objects

O One elevator is moving at 4 m/s; the other elevator is moving at -4 m/s.

O Both elevators are moving at 4 m/s.

tive Velocity

O One elevator is moving at 8 m/s; the other elevator is moving at -8 m/s.

Solution.

Since the upward direction is positive, the downward direction will be negative.

For their speed relative to one another to be 8 m/s, the individual velocity will be:

4 - ( - 4 ) = 8

Therefore, the correct answer is:

One elevator is moving at 4 m/s; the other elevator is moving at -4 m/s

Which is option B

Because the negative sign multiply by negative sign will give positive.

That is,

4 + 4 = 8

3. How did the light wave interact with the water? | I​

Answers

Answer:

Refraction is another way that waves interact with matter. ... Waves bend as they enter a new medium because they start traveling at a different speed in the new medium. For example, light travels more slowly in water than in air. This causes it to refract when it passes from air to water or from water to air.

Explanation:

i hope this helps but if it doesnt im rlly srry :p

Newton's laws of motion

Answers

1st law- an object at rest will stay at rest, and an object in motion will stay in motion at constant velocity, unless acted upon by an unbalanced force
2nd law- force equals mass times acceleration (f=ma)
3rd law- for every action there is an equal and opposite reaction
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