Another math problem. Can you solve it? I can't... For a good answer I'll make it 'The Best' I hope you can help me... Thanks

Answer:

this is all i got for the second question.

Step-by-step explanation:

That is, the average rate of change of from 3 to 0 is 1. That is, over the interval [0,3], for every 1 unit change in x, there is a 1 unit change in the value of the function. Here is a graph of the function, the two points used, and the line connecting those two points.

hope this kinda helps

-lvr

Answer:

the first, second and last option are all correct

Step-by-step explanation:

just Googled and squares have congruent diagonals, and the definition of a rhombus is that all the sides and angles have to be equal and adjacent, and a square has those qualities, which would also make the last statement true.

a square have two pairs of parallel sides, making the fourth one incorrect

and a square is also a rectangle so the third one is wrong as well!! :)

Answer:

40 deg

Step-by-step explanation:

The vertical sides of the rectangle are parallel, so the triangle is a right triangle.

The triangle is a right triangle, so the acute angles are complementary.

The bottom right angle of the triangle measures 90 - 50 = 40 deg.

The bottom line and the top side of the rectangle are parallel, so corresponding angles are congruent. x and the 40-deg angle are corresponding angles, so they are congruent.

x = 40 deg.

Answer:

Step-by-step explanation:

Recursively Defined Function               Sequence

f(1) = 13 f(n) = f(n - 1) + 26 for n ≥ 2         13, 39, 65, 91, ...

f(1) = 13 f(n) = 3 · f(n - 1) for n ≥ 2

f(1) = -24 f(n) = -4 · f(n - 1) for n ≥ 2

f(1) = 28 f(n) = f(n - 1) - 84 for n ≥ 2

f(1) = 28 f(n) = -4 · f(n - 1) for n ≥ 2         28, -112, 448, -1,792, ...

f(1) = -24 f(n) = 4 · f(n - 1) for n ≥ 2         -24, -96, -384, -1,536, ...

__

The initial values are easily seen. They match f(1). The recursive functions can be tested to see if they match the offered sequences.

  sequence 1 has a common ratio of 4 (not -4)

  sequence 2 has a common ratio of -4 (it is not arithmetic)

  sequence 3 has a common difference of 26 (it is not geometric)

Answer:

1 is sequence 3

5 is sequence 2

6 is sequence 1

(These r not included in the test, so don't use them)

 |

\ /

2 is no matching sequence

3 is no matching sequence

4 is no matching sequence

Step-by-step explanation:

PLATO

Answer:

x = 18; y = 35

Step-by-step explanation:

This gives us the equation:

1. x+y=53

2. 3x=y+19

3. 3x-y=19

Add the first and last line together: x+y+3x-y=53+19

Simplifies to: 4x=72

Divide by 4 to get: x = 18

Plug your numbers into the first equation to get 18+y=53; y = 35.

Answer:

The numbers are 18 and 35.

Step-by-step explanation:

The smaller number is x.

Let the other number by y.

Three times the smaller number is equal to 19 more than the larger number.

3x = y + 19

The larger number is

y = 3x - 19

the numbers add up to 53

x + y = 53

x + 3x - 19 = 53

4x = 72

x = 18

y = 3x - 19 = 3(18) - 19 = 54 - 19 = 35

The numbers are 18 and 35.

Answer:

D. 6

Step-by-step explanation:

here, as given set Q consists { 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36}

and set Z contains {3, 6, 9, 12, 15, 18, 21,24, 27, 30, 33, 36, .... }

so be comparing both, we can see that the numbers 6, 12, 18, 24, 30 and 36 is repeated.

Answer:

H0 :

a. mu is greater than or equal to $108.50

Ha:

c. mu is less than or equal to $108.50

Step-by-step explanation:

The correct order of the steps of a hypothesis test is given following  

1. Determine the null and alternative hypothesis.

2. Select a sample and compute the z - score for the sample mean.

3. Determine the probability at which you will conclude that the sample outcome is very unlikely.

4. Make a decision about the unknown population.

These steps are performed in the given sequence

In the given scenario the test is to identify whether the average room price significantly different from $108.50. We take null hypothesis as mu is greater or equal to $108.50.

Answer:

C.  y = 1

Step-by-step explanation:

For two line to be parallel, they have to have the same slope.  The slope for the equation y = 4 is 0.  This cancels out answer choices A, B, and D.  

A and B have an undefined slope since they are vertical lines.

D has a slope of 4.

Also, the line has to go through the point (-3, 1).  Since the line has a slope of 0, the equation will include the y-value.  The y-value for this point is 1.  This gives you an answer of y = 1.

Answer:

y = 1

Step-by-step explanation:

Just took the practice test and got it right

Answer:

2+(11+y)=(2+11)+y=11+(2+y)

Answer:

Sample Response: The associative property allows you to keep the order of the terms and change the position of the parentheses. So you can rewrite the terms in the same order and then move the parentheses so that the 2 + 11 is now inside. The equivalent expression is (2 + 11) + y.

Step-by-step explanation:

E d g e n u i t y

Answer:

a) The velocity of the ball after 2 seconds is -91 feet per second, b) The velocity of the ball after falling 364 feet is 155 feet per second, c) The equation of the parabola that passes through (0,1) and is tangent to the line y = 5x - 5 is [tex]y = 6\cdot x^{2}-7\cdot x +1[/tex].

Step-by-step explanation:

a) The velocity function is obtained after deriving the position function in time:

[tex]v (t) = -32\cdot t -27[/tex]

The velocity of the ball after 2 seconds is:

[tex]v(2\,s) = -32\cdot (2\,s) -27[/tex]

[tex]v(2\,s) = -91\,\frac{ft}{s}[/tex]

The velocity of the ball after 2 seconds is -91 feet per second.

b) The time of the ball after falling 364 feet is found after solving the position function as follows:

[tex]435\,ft - 364\,ft = -16\cdot t^{2}-27\cdot t + 435\,ft[/tex]

[tex]-16\cdot t^{2} - 27\cdot t + 364 = 0[/tex]

The solution of this second-grade polynomial is represented by two roots:

[tex]t_{1} = 4\,s[/tex] and [tex]t_{2} = -5.688\,s[/tex].

Only the first root is physically reasonable since time is a positive variable. Now, the velocity of the ball after falling 364 feet is:

[tex]v(4\,s) = -32\cdot (4\,s) - 27[/tex]

[tex]v(4\,s) = -155\,\frac{ft}{s}[/tex]

The velocity of the ball after falling 364 feet is 155 feet per second.

c) Let consider the equation for a second order polynomial that passes through (0, 1) and its first derivative that passes through (1, 0) and represents the give equation of the tangent line. That is to say:

Second-order polynomial evaluated at (0, 1)

[tex]c = 1[/tex]

Slope of the tangent line evaluated at (1, 0)

[tex]5 = 2\cdot a \cdot (1) + b[/tex]

[tex]2\cdot a + b = 5[/tex]

[tex]b = 5 - 2\cdot a[/tex]

Now, let evaluate the second order polynomial at (1, 0):

[tex]0 = a\cdot (1)^{2}+b\cdot (1) + c[/tex]

[tex]a + b + c = 0[/tex]

If [tex]c = 1[/tex] and [tex]b = 5 - 2\cdot a[/tex], then:

[tex]a + (5-2\cdot a) +1 = 0[/tex]

[tex]-a +6 = 0[/tex]

[tex]a = 6[/tex]

And the value of b is: ([tex]a = 6[/tex])

[tex]b = 5 - 2\cdot (6)[/tex]

[tex]b = -7[/tex]

The equation of the parabola that passes through (0,1) and is tangent to the line y = 5x - 5 is [tex]y = 6\cdot x^{2}-7\cdot x +1[/tex].

Greetings from Brasil...

Here we have internal collateral angles. Its sum results in 180, so:

(6X + 8) + (4X + 2) = 180

6X + 4X + 8 + 2 = 180

10X + 10 = 180

10X = 180 - 10

10X = 170

X = 170/10

The correct answer is D. 23

Explanation:

Histograms similar to other graphs represent numerical information, usually by using bars, as well as ranges. For example, in the case presented the information presented belongs to the scores obtained in a test, which are shown using ranges. Moreover, it is possible to know the total of people that took the test by adding each of the frequencies, as the frequency in the y-axis shows the number of times the range repeated and it is expected each grade registered belongs to 1 person. This means the total of people is equal to 2 (score from 60-69) + 9 (score from 70-79) + 7 (score from 80-89) + 5 (score from 90-99) = 23 people.

Answer:

the answer is 23

Step-by-step explanation:

hopes this helps:)

Answer:

The position of the particle is described by [tex]s(t) = \frac{1}{3}\cdot t^{3} + \frac{5}{2}\cdot t^{2} - 5\cdot t + 6,\forall t \geq 0[/tex]

Step-by-step explanation:

The position function is obtained after integrating twice on acceleration function, which is:

[tex]a(t) = 2\cdot t + 5[/tex], [tex]\forall t \geq 0[/tex]

Velocity

[tex]v(t) = \int\limits^{t}_{0} {a(t)} \, dt[/tex]

[tex]v(t) = \int\limits^{t}_{0} {(2\cdot t + 5)} \, dt[/tex]

[tex]v(t) = 2\int\limits^{t}_{0} {t} \, dt + 5\int\limits^{t}_{0}\, dt[/tex]

[tex]v(t) = t^{2}+5\cdot t + v(0)[/tex]

Where [tex]v(0)[/tex] is the initial velocity.

If [tex]v(0) = -5[/tex], the particular solution of the velocity function is:

[tex]v(t) = t^{2} + 5\cdot t -5, \forall t \geq 0[/tex]

Position

[tex]s(t) = \int\limits^{t}_{0} {v(t)} \, dt[/tex]

[tex]s(t) = \int\limits^{t}_{0} {(t^{2}+5\cdot t -5)} \, dt[/tex]

[tex]s(t) = \int\limits^{t}_0 {t^{2}} \, dt + 5\int\limits^{t}_0 {t} \, dt - 5\int\limits^{t}_0\, dt[/tex]

[tex]s(t) = \frac{1}{3}\cdot t^{3} + \frac{5}{2}\cdot t^{2} - 5\cdot t + s(0)[/tex]

Where [tex]s(0)[/tex] is the initial position.

If [tex]s(0) = 6[/tex], the particular solution of the position function is:

[tex]s(t) = \frac{1}{3}\cdot t^{3} + \frac{5}{2}\cdot t^{2} - 5\cdot t + 6,\forall t \geq 0[/tex]

Answer:

Position of the particle is :

[tex]S(t)=\frac{1}{3}.t^3+\frac{5}{2}.t^2-5.t+6[/tex]

Step-by-step explanation:

Given information:

The particle is moving with an acceleration that is function of:

[tex]a(t)=2t+5[/tex]

To find the expression for the position of the particle first integrate for the velocity expression:

AS:

[tex]V(t)=\int\limits^0_t {a(t)} \, dt\\v(t)= \int\limits^0_t {(2.t+5)} \, dt\\\\v(t)=t^2+5.t+v(0)\\[/tex]

Where, [tex]v(0)[/tex] is the initial velocity.

Noe, if we tale the [tex]v(0) =-5[/tex] ,

So, the velocity equation can be written as:

[tex]v(t)=t^2+5.t-5[/tex]

Now , For the position of the particle we need to integrate the velocity equation :

As,

Position:

[tex]S(t)=\int\limits^0_t {v(t)} \, dt \\S(t)=\int\limits^0_t {(t^2+5.t-5)} \, dt\\S(t)=\frac{1}{3}.t^3+\frac{5}{2}.t^2-5.t+s(0)[/tex]

Where, [tex]S(0)[/tex] is the initial position of the particle.

So, we put the value [tex]s(0)=6[/tex] and get the position of the particle.

Hence, Position of the particle is :

[tex]S(t)=\frac{1}{3}.t^3+\frac{5}{2}.t^2-5.t+6[/tex].

For more information visit:

https://brainly.com/question/22008756?referrer=searchResults

Answer:

[tex]w=\frac{t+8}{3}[/tex]

Step-by-step explanation:

[tex]3w - 8 = t[/tex]

Add 8 on both sides.

[tex]3w - 8 + 8 = t + 8[/tex]

[tex]3w = t + 8[/tex]

Divide both sides by 3.

[tex]\frac{3w}{3} =\frac{t+8}{3}[/tex]

[tex]w=\frac{t+8}{3}[/tex]

The value of w is w = (t + 8)/3 in terms of t after solving and making the subject w the answer is w = (t + 8)/3.

It is defined as the combination of constants and variables with mathematical operators.

We have an equation:

3w - 8 = t

To solve for w in terms of t

Make the subject as w

In the equation:

3w - 8 = t

Add 8 on both sides:

3w - 8 + 8 = t + 8

3w = t + 8

Divide by 3 on both sides:

3w/3 = (t + 8)/3

w = (t + 8)/3

The equation represents a function of w in terms of t

As we know, the function can be defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

Thus, the value of w is w = (t + 8)/3 in terms of t after solving and making the subject w the answer is w = (t + 8)/3.

Learn more about the expression here:

brainly.com/question/14083225

#SPJ2

Answer:

The width of the model will be  2.5 inches

Step-by-step explanation:

The tower was scaled down by a factor to a smaller size in the model. We are to, first of all, determine this factor and then use it to scale down the width of the model.

Step One: Determine the scale factor from the tower height.

The scale factor is obtained from the formula:

Scale factor = model size / observed size

This will be

Height of model tower/ height of the real tower.

The height of the model tower is 5 inches which is the same as 0.416667 ft

Scale factor = 0.416667 ft/ 40ft = 0.0104

Step two:  Multiply the width of the real-life tower by the scale factor to get the model width.

Width of model =20ft X 0.0104 = 0.208ft

Step three:  Convert your answer back to inches.

We will now have to convert 0.208 ft back to inches by multiplying by 12

This will be 0.208 X 12 =2.5 inches.

The width of the model will be  2.5 inches

Answer:

3:1

Step-by-step explanation:

75%=[tex]\frac{75}{100}[/tex]=[tex]\frac{3}{4}[/tex]

25%=[tex]\frac{25}{100}[/tex]=[tex]\frac{1}{4}[/tex]

Answer:

The correct answer is

For addition, Caulleen used the words total, sum, altogether, and increase. But we could also have used the words combine, plus, more than, or even just the word "and". For subtraction, Caulleen used the words, fewer than, decrease, take away, and subtract. We also could have used less than, minus, and difference.

Step-by-step explanation:

hope this helps u!!!

Step-by-step explanation:

in the diagram what is the value of WRS

Answer:

2/3

Step-by-step explanation:

The equation for direct variation is: y = kx, where k is a constant.

Here, we see that y varies directly with x when y = 6 and x = 72, so let's plug these values into the formula to find k:

y = kx

6 = k * 72

k = 6/72 = 1/12

So, k = 1/12. Now our formula is y = (1/12)x. Plug in 8 for x to find y:

y = (1/12)x

y = (1/12) * 8 = 8/12 = 2/3

Thus, y = 2/3.

~ an aesthetics lover

Answer:

Step-by-step explanation: I hope i'm right

[tex]y \alpha x\\y=kx....(1)\\6=72k\\\frac{6}{72} =\frac{72k}{72} \\\\1/12 =k\\y = 1/12x=relationship-between;x-and;y\\x =8 , y =?\\y = \frac{8}{12} \\Cross-Multiply\\12y =8\\12y/12 = 8/12\\\\y = 2/3[/tex]

Between 1,000,000,000 and 9,999,999,999 there are 9,000,000,000 different ten-digit numbers. Of those, 9*9! (9 times 9 factorial) = 3,265,920 have all ten digits different, i.e., no two equal digits. Take the difference of those two numbers, and you will have your answer.

--------------------

Hope this helps!

Brainliest would be great!

--------------------

With all care,

07x12!

Answer:

They completed 13, 3 credit classes

Step-by-step explanation:

1. Make 2 formulas. In this case: x+y=18

and 3x+4y=59

2. Then multiply x+y=18 by 3 and subtract the two equations.

Find y which is 5 and input into the equations. Then find your answer.

Answer:

D. -0.98

Step-by-step explanation:

Well it is a negative correlation and it is really strong but it is impossible to go pasit -1.

Thus,

the answer is D. -0.98

Hope this helps :)

Answer:

D. -0.98

Step-by-step explanation:

The correlation is a negative if the Y value decreases as the x value increases. It is not -1.43 because it is not decraeseing that fast.

Answer:

500

Step-by-step explanation:

350/70%=500

Answer:

D

Step-by-step explanation:

Answer:

(10, -29)

Step-by-step explanation:

I assume you are looking for the solution to this system of equations.

Plug them both into a graphing calculator. The point where they cross is:

(10, -29)

Answer:(10, -29)

Step-by-step explanation:

Answer:

x = 0.53 cm

Maximum volume = 1.75 cm³

Step-by-step explanation:

Refer to the attached diagram:

The volume of the box is given by

[tex]V = Length \times Width \times Height \\\\[/tex]

Let x denote the length of the sides of the square as shown in the diagram.

The width of the shaded region is given by

[tex]Width = 3 - 2x \\\\[/tex]

The length of the shaded region is given by

[tex]Length = \frac{1}{2} (5 - 3x) \\\\[/tex]

So, the volume of the box becomes,

[tex]V = \frac{1}{2} (5 - 3x) \times (3 - 2x) \times x \\\\V = \frac{1}{2} (5 - 3x) \times (3x - 2x^2) \\\\V = \frac{1}{2} (15x -10x^2 -9 x^2 + 6 x^3) \\\\V = \frac{1}{2} (6x^3 -19x^2 + 15x) \\\\[/tex]

In order to maximize the volume enclosed by the box, take the derivative of volume and set it to zero.

[tex]\frac{dV}{dx} = 0 \\\\\frac{dV}{dx} = \frac{d}{dx} ( \frac{1}{2} (6x^3 -19x^2 + 15x)) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\0 = \frac{1}{2} (18x^2 -38x + 15) \\\\18x^2 -38x + 15 = 0 \\\\[/tex]

We are left with a quadratic equation.

We may solve the quadratic equation using quadratic formula.

The quadratic formula is given by

[tex]$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$[/tex]

Where

[tex]a = 18 \\\\b = -38 \\\\c = 15 \\\\[/tex]

[tex]x=\frac{-(-38)\pm\sqrt{(-38)^2-4(18)(15)}}{2(18)} \\\\x=\frac{38\pm\sqrt{(1444- 1080}}{36} \\\\x=\frac{38\pm\sqrt{(364}}{36} \\\\x=\frac{38\pm 19.078}{36} \\\\x=\frac{38 + 19.078}{36} \: or \: x=\frac{38 - 19.078}{36}\\\\x= 1.59 \: or \: x = 0.53 \\\\[/tex]

Volume of the box at x= 1.59:

[tex]V = \frac{1}{2} (5 – 3(1.59)) \times (3 - 2(1.59)) \times (1.59) \\\\V = -0.03 \: cm^3 \\\\[/tex]

Volume of the box at x= 0.53:

[tex]V = \frac{1}{2} (5 – 3(0.53)) \times (3 - 2(0.53)) \times (0.53) \\\\V = 1.75 \: cm^3[/tex]

The volume of the box is maximized when x = 0.53 cm

Therefore,

x = 0.53 cm

Maximum volume = 1.75 cm³

Answer:

E, needs more info to be determined

Step-by-step explanation:

We know that Kai takes 30 minutes round-trip to get to his school.

One way is uphill and the other is downhill.

He travels twice as fast downhill than uphill.

This means that uphill accounts for 20 minutes of the round-trip and downhill accounts for 10 minutes of his trip.

However, even with this information, we do not know how far his school is.

In order to figure out how far away his school is, we would need more information about the speed at which Kai is traveling.

Simply knowing that he travels twice as fast downhill is not enough.

This question could only be solved by knowing how many miles Kai travels uphill or downhill in a given time.

Answer:

£1960

Step-by-step explanation:

Step 1.

2% = 100% ÷ 50

Step 2.

£2000 ÷ 50 = £40

Step 3.

£2000 - £40 = £1960

Answer: i believe it’s 0.28, but tbh i’m on a unit test so i can’t see what’s wrong and what’s right. good luck!

Step-by-step explanation:

Answer:

c- 0.28

Step-by-step explanation: