Anyone know the answer to all of them added together

Answer:

[tex]\boxed{33.5 \ \text{feet/second}}[/tex]

Step-by-step explanation:

To find the unit rate, we need to find out how much distance does the cyclist travel in 1 second. For that, we need to use the unitary method. A unitary method is a method that determines the unit rate of an object.

Note: Since the cyclist travels at a constant rate, unitary method can be used.

[tex]\rightarrow 837 \dfrac{1}{2} \ \text{feet in 25 seconds}[/tex]

[tex]\rightarrow 837.5 \ \text{feet} = 25 \ \text{seconds}[/tex]

Divide both sides by 25:

[tex]\rightarrow \dfrac{837.5}{25} \ \text{feet} = \dfrac{25}{25} \ \text{seconds}[/tex]

[tex]\rightarrow 33.5 \ \text{feet} = 1 \ \text{seconds}[/tex]

[tex]\rightarrow \boxed{33.5 \ \text{feet/second}}[/tex]

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Given :

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Now , x = a ( θ + sin θ )

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Now y = a ( 1-cosθ)

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Diff w.r.t " θ " we get .

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From eqn ( 1 ) & ( 2 )

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Hope Helps!:)

Step-by-step explanation:

if I understand correctly, then we have

h(x) = 2 × cubic root(x - 10) + 4

the x-intercept is the x value where y or h(x) = 0.

0 = 2 × cubic root(x - 10) + 4

0 = cubic root(x - 10) + 2

-2 = cubic root(x - 10)

-8 = x - 10

x = 2

The intercept is the point where a line or curve crosses the axis. The x-intercept of the function is (2,0)

The intercept is the point where a line or curve crosses the axis. Given the function below:

h(x) = 2(∛x-10) + 4

For the x-intercept, it is the point where h(x) = 0.

Substitute

2(∛x-10) + 4 = 0

2(∛x-10)  = -4

(∛x-10)  = -2

Take the cube of both sides

x-10 = (-2)^3
x -10 = -8

x = -8 + 10

x = 2

Hence the x-intercept of the function is (2,0)

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Answer:

13. True, False, True

14. False, True, True

15. All true

Answer:

Step-by-step explanation:

4x + y = 2

y = -4x + 2

Answer:

Step-by-step explanation:

Refer to the definition of a function. I'll just give you a layman's definition to be concise.

For something to be a function, there needs to be exactly 1 output for every input. You cannot have a case where you input 1 value, and get 2 or more values as an output.

In math we call all the possible input values the domain, and we call all the possible output values the range.

Let's take a look at each situation on your worksheet.

1. Is a function. This is because only one arrow stems from each input value. There are cases where the different input values give the same output, sure, but each input returns 1 discrete thing, not an array of things.

(Think of it this way, if i had a machine that could answer any question I had with yes, no or maybe. I wouldn't want the machine to give me "yes and maybe" or "yes and no" as the result when I ask it a question. That doesn't make sense and I would think the machine is broken. What could happen, is that I ask the machine different questions, and for those different questions, it gave me the same answer, like "yes" and "yes" respectively. in that case, it would be acceptable, because it isn't contradicting itself for any individual question.)

2. Not a function. There are 2 different output values for b.

(Refer back to my machine analogy. The "machine" in this question is contradicting itself. I gave the machine one input, and the machine is telling me, "it's this and actually it's this other thing too")

3. Is a function for the same reasons as 1.

4. Isn't a function.

(It's basically telling you, the machine reads -6 as -4, but it also reads -6 as 0, and also 2. And it also tells you the machine reads -4 as -3, but it also reads it as 8. Again, the machine should only read 1 input in 1 way and not contradict itself. )

[tex]\textit{volume of a hemisphere}\\\\ V=\cfrac{1}{2}\cdot \cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ V=74466 \end{cases}\implies 74466=\cfrac{1}{2}\cdot \cfrac{4\pi r^3}{3} \\\\\\ 74466=\cfrac{2\pi r^3}{3}\implies 223398=2\pi r^3\implies \cfrac{22398}{2\pi }=r^3\implies \cfrac{111699}{\pi }=r^3 \\\\\\ \sqrt[3]{\cfrac{111699}{\pi }}=r~\hfill \stackrel{\textit{diameter = 2r}}{2\sqrt[3]{\cfrac{111699}{\pi }}\implies \sqrt[3]{\cfrac{893592}{\pi }}}~~ \boxed{\approx~~65.77}[/tex]

The equation 100 = 100 + y is an algebraic equation

The operation is subtraction property of equality, and the value of y is 0

The equation is given as:

100 = 100 + y

To solve for y, we apply the following operation

Operation: subtraction property of equality

So, we have:

100 - 100 = 100 - 100 + y

Evaluate the differences

0 = y

Rewrite as:

y = 0

Hence, the operation is subtraction property of equality, and the value of y is 0

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Answer:

Step-by-step explanation:

<A and <B are alternate interior angles. That means they are in the interior of the parallel lines and they are on opposite sides of the transversal.

When that happens <A = <B

8x + 78 = 2x + 114                      Subtract 2x from both sides.

8x - 2x + 78 = 2x - 2x + 114       Combine

6x + 78 = 114                              Subtract 78 from both sides

6x + 78 - 78 = 114 - 78

6x = 36                                       Divide by 6

6x/6 = 36/6

x = 6

I think you are asked for B

<B = 2x + 114

<B = 2*6 + 114

<B = 12 + 114

<B = 126

Answer:

1t = 1000kg

22.69 x 1000= 22690 kg

22690 kg ÷ 100 = 226.9

I would usually round it to 227 but I would say 226, since they are asking how many full bags she sold.

They are corresponding angles

Step-by-step explanation:

We know that x=75⁰ because

[tex]180 - 105 = 75[/tex]

75⁰ is angle EFB

Since we know this, and because we know that AD//EH,

We can conclude that x=75⁰(AD is parallel to EH and angle CBA or x and angle EFB are corresponding angles)

Answer:

the anwer is b

I did the math

Answer:

  5 m

Step-by-step explanation:

The length of the side of a square is the root of the area of the square. The area of this square is the difference between the trapezoid area and the triangle area.

__

  square area = trapezoid area - triangle area

  square area = 57.5 m² -32.5 m² = 25 m²

Then the side length is ...

  side length = √(square area) = √(25 m²)

  side length = 5 m

The length of a side of the square is 5 m.

Answer:

He did not put the numbers in order.

Explanation:

The numbers need to be in order from smallest to largest before you find the median.

22 + 22 x r = 30

22 x r = 30 - 22

r = 8 : 22

r = +36,36%

r = increase rate

Answer:

60 days.

Step-by-step explanation:

This is  a proportion question. You compare two ratios. Unfortunately it is an inverse ratio.

12 = k/100                   Multiply both sides by 100

1200 = k

20 = k/x                       Multiply both sides by x

20x = k

20x = 1200                 Divide by 20

20x/20 = 1200/20

x = 60 days.  

An inverse proportion works by making a constant k. The  constant k makes the days shorter when the number of people increases. You should expect that. More people , less time.

The triple integral that is bounded by a paraboloid x = 4y2 4z2 given as 16.762

Parabloid, x = 4y² + 4z²

plane x = 4

x = 4y² + 4z²

x = 4

4 = 4y² + 4z²

4 = 4 (y² + z² )

1 = y² + z²

from polar coordinates

y = r cos θ

z = r sin θ

r² = y² + z²

0 ≤ θ ≤ 2π

4r² ≤ x ≤ 4

0 ≤ r ≤ 1

[tex]\int\limits\int\limits\int\limits {x} \, dV = \int\limits^1_0\int\limits^a_b\int\limits^c_d {x} \, dx ( rdrdz)[/tex]

where

a = 4

b = 4r²

c = 2r

d = 0

The first integral using limits c and d gives:

[tex]2pi\int\limits^1_0\int\limits^a_b {xr} \, dx[/tex]

The second integral using limits a and b

[tex]pi\int\limits^1_0 {16 } } \, rdr - pi\int\limits^1_0 {16r^{5} \, dx[/tex]

[tex]16pi\int\limits^1_0 { } } \, rdr - 16pi\int\limits^1_0 {r^{5} \, dx[/tex]

[tex]16pi\int\limits^1_0 { } } \, [r-r^{5}]dr[/tex]

The third integral using limits 1 and 0 gives: 16.762

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The triple integral that is bounded by a paraboloid x = 4y2 4z2 given as 16.762

Integration is defined as adding small parts to form a new significant part.

Parabloid, x = 4y² + 4z²

plane x = 4

x = 4y² + 4z²

x = 4

4 = 4y² + 4z²

4 = 4 (y² + z² )

1 = y² + z²

from polar coordinates

y = r cos θ

z = r sin θ

r² = y² + z²

The limits of the integral

0 ≤ θ ≤ 2π

4r² ≤ x ≤ 4

0 ≤ r ≤ 1

[tex]\int\int\intxdV = \int_0_1\int_b_a\int_d_cxdx(rdrdz)[/tex]

where

a = 4

b = 4r²

c = 2r

d = 0

The first integral using limits c and d gives:

[tex]2\pi\int_0^1\int_b^axydx[/tex]

The second integral using limits a and b

[tex]\pi \int_0^116rdr-\pi\int_0^116r^5dx[/tex]

[tex]16\pi \int_0^1rdr-16\pi\int_0^1 r^5dx[/tex]

[tex]16\pi\int_0^1[r-r^5]dr[/tex]

The third integral using limits 1 and 0 gives: 16.762

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