Answer:
0.03, 0.06, 0.2, 0.76, 1
Step-by-step explanation:
Select all the expressions that are the result of decreasing x by 80%
Please use the photo, also please don't give me a file cause I know it's a virus
Answer:
A,B,E or 1,2,5
if its letters or numbers.
Step-by-step explanat
The expressions that are the result of decreasing x by 80% will be (1 - 0.80)x, x - (80/100)x, and (20/100)x. Then the correct options are A, C, and E.
What is the percentage?The quantity of anything is stated as though it were a fraction of a hundred. A quarter of 100 can be used to express the ratio. Per 100 is what the term percent signifies. The symbol ‘%’ is used to symbolize it.
The expressions that are the result of decreasing x by 80%.
We know that if something is decreased by a percentage p% then the percentage is written as (1 - p%). Then the expression is written as,
⇒ [(100 - 80) / 100]x
Then the expression can be written as,
⇒ [(100 - 80) / 100]x
⇒ x - (80/100)x
⇒ x - 0.80x
⇒ (1 - 0.80)x
⇒ 0.20x
⇒ (20/100)x
The expressions that are the result of decreasing x by 80% will be (1 - 0.80)x, x - (80/100)x, and (20/100)x. Then the correct options are A, C, and E.
More about the percentage link is given below.
https://brainly.com/question/8011401
#SPJ2
Indicate which formula you would use to solve for the missing side B and then write your answer correct to two decimal places.Write only the formula down.. Single line text.
Answer:
Step-by-step explanation:
Hi there,
The formula depends on what shape you are dealing with. There is no way to determine what formula you need without knowing what type of figure you are dealing with.
Find the average value of a function
Answer:
The average value of g is:
[tex]\displaystyle g_{ave}=\frac{1}{6}e^6-\frac{49}{6}\approx 59.071[/tex]
Step-by-step explanation:
The average value of a function is given by the formula:
[tex]\displaystyle f_{ave}=\frac{1}{b-a}\int_a^b f(x)\, dx[/tex]
We want to find the average value of the function:
[tex]g(x)=e^{3x-3}-4x[/tex]
On the interval [1, 3].
So, the average value will be given by:
[tex]g_{ave}=\displaystyle \frac{1}{3-1}\int_1^3 e^{3x-3}-4x\, dx[/tex]
Simplify. We will also split the integral:
[tex]\displaystyle g_{ave}=\frac{1}{2}\left(\int_1^3e^{3x-3}\, dx-\int _1^3 4x\, dx\right)[/tex]
We can use u-substitution for the first integral. Letting u = 3x - 3, we acquire:
[tex]\displaystyle u=3x-3\Rightarrow du = 3\, dx\Rightarrow \frac{1}{3} du=dx[/tex]
We will also change the limits of integration for our first integral. So:
[tex]u(1)=3(1)-3=0\text{ and } u(3)=3(3)-3=6[/tex]
Thus:
[tex]\displaystyle g_{ave}=\frac{1}{2}\left(\frac{1}{3}\int_0^6 e^{u}\, du-\int _1^3 4x\, dx\right)[/tex]
Integrate:
[tex]g_{ave}=\displaystyle \frac{1}{2}\left(\frac{1}{3}e^u\Big|_0^6-2x^2\Big|_1^3\right)[/tex]
Evaluate. So, the average value of g on the interval [1, 3] is:
[tex]\displaystyle g_{ave}=\frac{1}{2}\left(\frac{1}{3}\left[e^6-e^0\right]-\left[2(3)^2-2(1)^2\right]\right)[/tex]
Evaluate:
[tex]\displaystyle\begin{aligned} g_{ave}&=\frac{1}{2}\left(\frac{1}{3}(e^6-1)-16\right)\\&=\frac{1}{2}\left(\frac{1}{3}e^6-\frac{1}{3}-16\right)\\&=\frac{1}{6}e^6-\frac{49}{6}\approx59.071\end{aligned}[/tex]
A radioactive substance has a continuous decay rate of 0.056 per minute. How many grams of a 120 gram sample will remain radioactive after 40 minutes? Round the answer to the nearest tenth of a gram, and do not include the unit in your answer.
Answer:
The mass of the radioactive sample after 40 minutes is 12.8 g.
Step-by-step explanation:
The mass of the sample can be found by using the exponential decay equation:
[tex] N_{t} = N_{0}e^{-\lambda t} [/tex]
Where:
N(t): is the amount of the sample at time t =?
N₀: is the initial quantity of the sample = 120 g
t = 40 min
λ: is the decay constant = 0.056 min⁻¹
Hence, the mass of the sample after 40 min is:
[tex] N_{t} = N_{0}e^{-\lambda t} = 120g*e^{-0.056min^{-1}*40 min} = 12.8 g [/tex]
Therefore, the mass of the radioactive sample after 40 minutes is 12.8 g.
I hope it helps you!
What is the value of x
Answer:
it Is a variable..............
Find the area of each figure. Use 3.14 for pi.
Answer:
208m²
Step-by-step explanation:
Okay, so you can split this abomination into a rectangle, another rectangle, and a square, so we're going to start with the rectangle to the far left:
The formula for the area of a rectangle or square is length x width, so we just have to plug:
4 x 8 = 32
Now we do the next rectangle, but we have to figure out the length first, so:
4 + 4 = 8
Now we plug:
8 x 4 = 32 (I now realize that the rectangles are even and we could've just multiplied the first one by two, but it's always good to check)
Now we do the square:
12 x 12 = 144
Now we add it all together:
32 + 32 + 144 = 208
So the area of the figure is 208m²
if this is wrong, let me know so I can fix it
hope this helps:)
A contractor is required by a county planning department to submit 1, 2, 3, 4, or 5 forms (depending on the nature of the project) when applying for a building permit. Let y denote the number of forms required for an application, and suppose the mass function is given by p(y) 5 cy for y 5 1, 2, 3, 4, or 5. Determine the value of c, as well as the long-run proportion of applications that require at most three forms and the long-run proportion that require between two and four forms, inclusive.
Answer:
[tex](a)\ c = \frac{1}{15}[/tex]
[tex](b)\ 40\%[/tex]
[tex](c)\ 60\%[/tex]
Step-by-step explanation:
The given parameters can be represented as:
[tex]P_Y(y) \ge 0, y =1,2,3,4,5[/tex]
[tex]P_y(y) = cy, y=1,2,3,4,5[/tex]
Solving (a): The value of c
To do this, we make use of the following rule;
[tex]\sum\limit^5_{y=1}P_Y(y_i) = 1[/tex]
Given that:
[tex]P_y(y) = cy, y=1,2,3,4,5[/tex]
This is translated to:
[tex]c*1 + c * 2 + c * 3 + c * 4 + c * 5 = 1[/tex]
[tex]c + 2c + 3c + 4c + 5c = 1[/tex]
[tex]15c = 1[/tex]
Solve for c
[tex]c = \frac{1}{15}[/tex]
(b) The proportions of applications that requires at most 3 forms
This implies that: y = 1,2,3
So, we make use of:
[tex]P(Y \le 3) = P(Y=1) + P(y=2) + P(Y=3)[/tex]
Recall that:
[tex]P_y(y) = cy, y=1,2,3,4,5[/tex]
Substitute [tex]c = \frac{1}{15}[/tex]
[tex]P_y(y) =\frac{1}{15}y[/tex]
So:
[tex]P(Y \le 3) = P(Y=1) + P(y=2) + P(Y=3)[/tex]
[tex]P(Y\le 3) = \frac{1}{15} * 1 +\frac{1}{15} * 2 +\frac{1}{15} * 3[/tex]
[tex]P(Y\le 3) = \frac{1}{15} +\frac{2}{15} +\frac{3}{15}[/tex]
Take LCM
[tex]P(Y\le 3) = \frac{1+2+3}{15}[/tex]
[tex]P(Y\le 3) = \frac{6}{15}[/tex]
[tex]P(Y\le 3) = 0.4[/tex]
Express as percentage
[tex]P(Y\le 3) = 0.4*100\%[/tex]
[tex]P(Y\le 3) = 40\%[/tex]
(c) The proportions of applications that requires between 2 and 4 forms (inclusive)
This implies that: y = 2,3,4
So, we make use of:
[tex]P(2 \le Y \le 4) = P(Y=2) + P(Y=3) + P(Y=4)[/tex]
[tex]P(2 \le Y \le 4) = 2 * \frac{1}{15} + 3 * \frac{1}{15} + 4 * \frac{1}{15}[/tex]
[tex]P(2 \le Y \le 4) = \frac{2}{15} + \frac{3}{15} + \frac{4}{15}[/tex]
Take LCM
[tex]P(2 \le Y \le 4) = \frac{2+3+4}{15}[/tex]
[tex]P(2 \le Y \le 4) = \frac{9}{15}[/tex]
[tex]P(2 \le Y \le 4) = 0.6[/tex]
Express as percentage
[tex]P(2 \le Y \le 4) = 0.6 * 100\%[/tex]
[tex]P(2 \le Y \le 4) = 60\%[/tex]
what is 11 one fourth improper fraction
Answer:
Step-by-step explanation:
45/5
¿para cuantos días alcanza una bolsa de 7,5 kg de alimento balanceado, si la ración diaria que le dan al perro de paula equivale a las dos quintas partes de 1kg?
Answer:
7,5*1000/2=37,5
Step-by-step explanation:
a square on a coordinate plane has vertices at (4,-5) and (4,2). what is the perimeter of the square?
Answer:
28
Step-by-step explanation:
2-(-5)=7--one side
square (all sides are the same)
4 sides in total
7x4=28
Select the coefficents in the expression: 5x + 4 - 2x -1 *
Answer:
When you solve it, the leading coefficient is 3.
Step-by-step explanation:
Combine Like Terms:
=5x+4+−2x+−1
=(5x+−2x)+(4+−1)
=3x+3
Hope it helps :)
Answer:
The coefficients are 5, 4, 2 and -1
Step-by-step explanation:
Coefficients are the whole numbers
The median value is ____
Answer:
45
Step-by-step explanation:
Please explain to me how to find y. I’m so confused.
Ivy deposited some money into a savings account that earns 1%
annual simple interest. At the end of 5 years, she earned $32.50 in
interest. How much money did she put into the account initially?
Round to the nearest dollar.
Answer:
Ivy initially put $ 650 in the account.
Step-by-step explanation:
Given that Ivy deposited some money into a savings account that earns 1% annual simple interest, and at the end of 5 years, she earned $ 32.50 in interest, to determine how much money did she put into the account initially, the following calculation must be performed:
32.50 / 5 = 6.5
1 = 6.5
100 = X
100 x 6.5 = X
650 = X
Therefore, Ivy initially put $ 650 in the account.
PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!! DUE TODAY I NEED HELP ASAP
A restaurant has a 15% mandatory tip rate.
(a) Complete the ratio table shown. Show your work.
Pre-Tax Bill ($): 10 __ 60 __
Tip ($) __ 12 __ 15
(b) Using the table, how can you find the total tip paid on $70?
Answer:
Subtotal 70.00
15% Tip 10.50
Total 80.50
Step-by-step explanation:
1% 0.70
2% 1.40
3% 2.10
4% 2.80
5% 3.50
6% 4.20
7% 4.90
8% 5.60
% Tip
9% 6.30
10% 7.00
11% 7.70
12% 8.40
13% 9.10
This dude above is trash and wrong, I got a 0 because of him
The value of a house is increasing by $2500 per year. If it is worth $190,000 today, what will it be worth in four years?
Answer:
5000
Step-by-step explanation:
i dont know this answer but i try that
You are testing the claim that the mean GPA of night students is different from the mea GPA of day students. You sample 20 night students, and the sample mean GPA is 2.84 with a standard mean GPA is 2.55 with a standard deviation of 0.45. Test the claim using a 1% level of significance. Assume the population standard deviations are unequal and that GPAs are normally distributed. Give answer to at least 4 decimal places. What are the correct hypotheses
Answer:
As the calculated value of z does not lie in the critical region the null hypothesis is accepted that the GPA mean of the night students is the same as the GPA mean of the day students.
Step-by-step explanation:
Here n= 20
Sample mean GPA = x`= 2.84
Standard mean GPA = u= 2.55
Standard deviation = s= 0.45.
Level of Significance.= ∝ = 0.01
The hypothesis are formulated as
H0: u1=u2 i.e the GPA of night students is same as the mean GPA of day students
against the claim
Ha: u1≠u2
i.e the GPA of night students is different from the mea GPA of day students
For two tailed test the critical value is z ≥ z∝/2= ± 2.58
The test statistic
Z= x`-u/s/√n
z= 2.84-2.55/0.45/√20
z= 0.1441
As the calculated value of z does not lie in the critical region the null hypothesis is accepted that the GPA mean of the night students is the same as the GPA mean of the day students.
can anyone help me please
PLEASE HELP QUICK
I WILL MARK BRAINLIEST!!!
Answer:
Step-by-step explanation:
c
Find the critical value t for the confidence level c= 0.98 and sample size n=7.
Click the icon to view the t-distribution table.
=(Round to the nearest thousandth as needed.)
Answer:
The critical value is T = 3.143.
Step-by-step explanation:
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 7 - 1 = 6
98% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 6 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.98}{2} = 0.99[/tex]. So we have T = 3.143.
The critical value is T = 3.143.
Helpp me plzzzzzzz
Explain how the following two formulas are the same:
Volume = b x h
Volume = l x w x h
Answer:
they are the same because lxw is the b so all you need to do is bxh
Step-by-step explanation:
What is the slope of the line tangent to the curve square root (x) +square root (y) = 2 at the point ( 9/4, 1/4 )? (photo attached of answer choices)
Answer:
B. [tex]\displaystyle -\frac{1}{3}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to RightEquality Properties
Multiplication Property of EqualityDivision Property of EqualityAddition Property of EqualitySubtraction Property of EqualityAlgebra I
Terms/CoefficientsExponential Rule [Rewrite]: [tex]\displaystyle b^{-m} = \frac{1}{b^m}[/tex]Exponential Rule [Root Rewrite]: [tex]\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}[/tex]Calculus
Derivatives
Derivative Notation
Derivative of a constant is 0
The definition of a derivative is the slope of the tangent line
Basic Power Rule:
f(x) = cxⁿf’(x) = c·nxⁿ⁻¹Implicit Differentiation
Step-by-step explanation:
Step 1: Define
[tex]\displaystyle \sqrt{x} + \sqrt{y} = 2[/tex]
[tex]\displaystyle (\frac{9}{4}, \frac{1}{4})[/tex]
Step 2: Differentiate
Implicit Differentiation
[Function] Rewrite [Exponential Rule - Root Rewrite]: [tex]\displaystyle x^{\frac{1}{2}} + y^{\frac{1}{2}} = 2[/tex][Function] Basic Power Rule: [tex]\displaystyle \frac{1}{2}x^{\frac{1}{2} - 1} + \frac{1}{2}y^{\frac{1}{2} - 1}\frac{dy}{dx} = 0[/tex][Derivative] Simplify: [tex]\displaystyle \frac{1}{2}x^{\frac{-1}{2}} + \frac{1}{2}y^{\frac{-1}{2}}\frac{dy}{dx} = 0[/tex][Derivative] Rewrite [Exponential Rule - Rewrite]: [tex]\displaystyle \frac{1}{2x^{\frac{1}{2}}} + \frac{1}{2y^{\frac{1}{2}}}\frac{dy}{dx} = 0[/tex][Derivative] Isolate [tex]\displaystyle \frac{dy}{dx}[/tex] term [Subtraction Property of Equality]: [tex]\displaystyle \frac{1}{2y^{\frac{1}{2}}}\frac{dy}{dx} = -\frac{1}{2x^{\frac{1}{2}}}[/tex][Derivative] Isolate [tex]\displaystyle \frac{dy}{dx}[/tex] [Multiplication Property of Equality]: [tex]\displaystyle \frac{dy}{dx} = -\frac{2y^{\frac{1}{2}}}{2x^{\frac{1}{2}}}[/tex][Derivative] Simplify: [tex]\displaystyle \frac{dy}{dx} = -\frac{y^{\frac{1}{2}}}{x^{\frac{1}{2}}}[/tex]Step 3: Evaluate
Find slope of tangent line
Substitute in point [Derivative]: [tex]\displaystyle \frac{dy}{dx} \bigg| \limit_{(\frac{9}{4}, \frac{1}{4})} = -\frac{(\frac{1}{4})^{\frac{1}{2}}}{(\frac{9}{4})^{\frac{1}{2}}}[/tex][Slope] Exponents: [tex]\displaystyle \frac{dy}{dx} \bigg| \limit_{(\frac{9}{4}, \frac{1}{4})} = -\frac{\frac{1}{2}}{\frac{3}{2}}[/tex][Slope] Simplify: [tex]\displaystyle \frac{dy}{dx} \bigg| \limit_{(\frac{9}{4}, \frac{1}{4})} = -\frac{1}{3}[/tex]Topic: AP Calculus AB/BC (Calculus I/II)
Unit: Differentiation - Implicit Differentiation
Book: College Calculus 10e
In an effort to determine the most effective way to teach safety principles to a group of employees, four different methods were tried. Some employees were given programmed instruction booklets and worked through the course at their own pace. Other employees attended lectures. A third group watched a television presentation, and a fourth group we divided into small discussion groups. A high of 10 was possible. A sample of 5 tests were selected from each group. The results were: Sample Programmed Instruction Lecture TV Group Discussion 1 6 8 7 8 2 7 5 9 5 3 6 8 6 6 4 5 6 8 6 5 6 8 5 5 At the 0.01 level, what is the critical value
Answer:
critical value = 5.29
Step-by-step explanation:
Given that they are divided into 4 groups and a sample of 5 test was selected
N = 5 * 4 = 20
k = 4
∝ = 0.01
Df for numerator ( SS group )= k - 1 = 3
Df for denominator ( SSE group ) = N - k = 20 - 4 = 16
DF ( degree of freedom )
Next we will use the F table to determine the critical value
Critical value = [tex]F_{16,3,0.01}[/tex] = 5.29
Marvin earns $9.75 per hour at his summer job. He wants to buy a video game system that costs $263.25
Enter an equation to model the relationship between the number of hours worked h and the amount earned e
The equation is:
Answer:
$9.75h=e-$263.25
Step-by-step explanation:
0.5; MATH PROBLEM HERE!!,,,,,,,,,
increase 80 in the ratio of 3:2
Answer:
Ratios describe proportions. We can always multiply across ratios, or divide across them (as long as we do it to all of them). For example, the ratio 3 : 2 is the same as 6 : 4 and 300 : 200. Accuracy Tip.
Step-by-step explanation:
What shape is the cross-section?
a. Triangle
b. Circle
c. Ellipse
d. Hexagon
e. Square
f. Rectangle
g. Pentagon
Ms. Larsen is buying 2 delivery vans for her business. The price of the first van
is shown below.
$16,257
The digit 2 in the price of the second van is 10 times the value of the digit 2 in the price of the first van. Which amount could be the price of the second van?
Answer:
18057
Step-by-step explanation:
uh just 200 x 10 = 200 add that to the 6 to make 18057$ which is the price of the second van.
Figure WXYZ is a rectangle. What are the
coordinates of point W?
Answer:
(2,9)
Step-by-step explanation:
Answer:
(2,9)
Step-by-step explanation:
because you move up by 6. which makes it (2,3)+6
Janey paints a block of wood with gold glitter for an art project. The block measures 8 inches by 10 inches by 20 inches. After she's done, she decides to make two blocks by cutting through the block on the red line. She still wants each block to be covered with gold glitter
1. what is the shape of each cut surface? What are its dimensions? and what is the total area of paint she still needs to paint?
2. What is the area of each cut surface?
Answer:
1. Square, 10in x 8in, 160in^2
2. Each surface has an area of 80in^2
Step-by-step explanation:
1. Rectangle is the shape of each cut surface which is 10in by 8 in. Since the block was already painted with glitter, she needs to paint both sides of the cut surface only, 2*8in * 10in = 160in^2.
2. Each cut will have a surface area of 10in * 8in = 80in^2
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