At 7:00 A.M., a patient receives a 1.00-mg dose of I-131 to treat thyroid cancer.

If the nuclide has a half-life of 8.0 days, what mass of the nuclide remains in the patient at 10:00 P.M. the next day? (Assume no excretion of the nuclide from the body.)

Answer:

41826.05 Calories

Explanation:

1 J = 0.239006 Calories

175 KJ

= 175 x 1000 J

= 175000 J

175000 J to Calories

= 175000 x 0.239006

= 41826.05 Calories

Answer: 41.8

Explanation:

Acellus verified ✅

The element with atom or ion can be filled as

B        neutral atom          5 proton             5 electron

[tex]Mg^{2+}[/tex]       cation                12 proton                10 electron

[tex]Ge^-[/tex]           anion                32 proton               33 electron

Because they have an equal amount of protons and electrons, atoms are neutral particles. Ions are electrically charged particles that may be created by either taking electrons away from neutral atoms to form positive ions or adding electrons to neutral atoms to produce negative ions. The quantity of protons remains constant during the formation of an ion. By taking out one or more electrons, neutral atoms can be transformed into positively charged ions.

B        neutral atom          5 proton             5 electron

[tex]Mg^{2+}[/tex]       cation               12 proton                10 electron

[tex]Ge^-[/tex]           anion                32 proton               33 electron

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If one has an unknown quantity of gas at a pressure of 121.6 mmHg, a volume of 45 L, and a temperature of 87 °C, then that person has approximately 1.93 moles of gas.

To find the number of moles of gas

PV = nRT

where: P = pressure V = volume, n = number of moles R = the gas constant T = temperature.

One needs to rearrange this equation to solve for n:

n = PV/RT

where R is the gas constant, which has a value of 0.08206 L•atm/mol•K.

121.6 mmHg = 0.160 atm

87 °C = 360 K

n = (0.160 atm)(45 L) / (0.08206 L•atm/mol•K)(360 K)

n = 1.93 mol

Therefore, one has approximately 1.93 moles of gas.

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Based on the given pH of 9.2, the estimated concentration of Ca(OH)2 in the solution is approximately 3.16 x 10^(-5) M.

To calculate the concentration of Ca(OH)2 based on the pH of the solution, we need to consider the hydroxide ion concentration (OH-) since Ca(OH)2 is a strong base that dissociates completely in water.

The pH of a solution is determined by the concentration of hydrogen ions (H+), which is related to the concentration of hydroxide ions (OH-) through the autoionization of water.

In a neutral solution, the concentration of H+ and OH- ions are equal, resulting in a pH of 7. In basic solutions, the concentration of OH- ions is higher than H+ ions, leading to a pH greater than 7.

The relationship between pH and OH- concentration can be expressed using the pOH value:

pOH = 14 - pH

In this case, the pH of the solution is given as 9.2. Therefore, the pOH can be calculated as:

pOH = 14 - 9.2

pOH = 4.8

The pOH is a measure of the concentration of hydroxide ions (OH-) in the solution. To convert pOH to OH- concentration, we can use the following relationship:

OH- concentration = 10^(-pOH)

OH- concentration = 10^(-4.8)

OH- concentration ≈ 1.58 x 10^(-5) M

Since Ca(OH)2 dissociates into two OH- ions per formula unit, the concentration of Ca(OH)2 will be twice the concentration of OH- ions. Therefore, the concentration of Ca(OH)2 can be calculated as:

Concentration of Ca(OH)2 ≈ 2 x (1.58 x 10^(-5)) M

Concentration of Ca(OH)2 ≈ 3.16 x 10^(-5) M

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Note the complete question:

User

How to calculate the concentration of Ca(OH)2 if the pH of this solution is 9.2?

The chemical equation for the reaction between HNO₃ and NH₃ is:

HNO₃ + NH₃ → NH₄NO₃

Acids: HNO₃

Bases: NH₃

Other: NH₄NO₃ (this is a salt formed by the neutralization of the acid and base)

The given chemical equation shows the reaction between nitric acid (HNO₃) and ammonia (NH₃) which results in the formation of ammonium nitrate (NH₄NO₃), a salt. In this reaction, HNO₃ acts as an acid as it donates a proton (H⁺) to the NH₃ molecule. NH₃, on the other hand, acts as a base, accepting the proton donated by HNO₃.

The protonated form of ammonia is called ammonium ion (NH₄⁺) and it is combined with the nitrate ion (NO₃⁻) to form the salt NH₄NO₃.

Therefore, the major species present at equilibrium in the solution are the acid HNO₃, the base NH₃ and the salt NH₄NO₃. HNO₃ and NH₃ are the main reactants and they act as the acid and base, respectively.

The salt NH₄NO₃ is formed as a result of neutralization between HNO₃ and NH₃ and it does not act as an acid or a base in the solution. It is important to note that NH₃ is a weak base, which means that it does not fully dissociate in water and therefore only a portion of the NH₃ molecules accept protons from HNO₃.

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Answer:

Explanation:

VSEPr Gives you the structures of molecules

A

The molecular formula mass ratio is approximately 1.48, the molecular formula of the compound is approximately N₁O₂.

To determine the molecular formula of the compound, we need to follow a series of steps. First, we calculate the moles of nitrogen (N) and oxygen (O) in the given mass percentage composition.

Assuming we have 100 g of the compound, we would have:

30.45 g of N

69.55 g of O

Next, we calculate the number of moles of each element using their respective molar masses:

Moles of N = 30.45 g / 14.01 g/mol ≈ 2.18 mol

Moles of O = 69.55 g / 16.00 g/mol ≈ 4.35 mol

We then divide the number of moles by the smallest number of moles (in this case, N) to obtain a simple ratio:

N ≈ 2.18 mol / 2.18 mol = 1

O ≈ 4.35 mol / 2.18 mol ≈ 2

This gives us the empirical formula, which is N₁O₂.

Finally, to determine the molecular formula, we need to find the ratio of the empirical formula's molar mass to the experimental molar mass provided. We calculate:

Empirical formula mass of N₁O₂ = 14.01 g/mol + (2 × 16.00 g/mol) = 46.01 g/mol

Experimental molar mass = 1.63 g / (389 mL × 0.00°C / 22.4 L/mol × 0.775) = 68.34 g/mol

Dividing the experimental molar mass by the empirical formula mass:

Molecular formula mass ratio = 68.34 g/mol / 46.01 g/mol ≈ 1.48

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In a 0.20 M solution of H2A with [tex]K_1=1.00*10^4[/tex] and [tex]K_2=1.00*10^8[/tex], the pH is 1.88, and the concentrations of [tex]H_2A[/tex],[tex]HA^-[/tex], and[tex]A^2-[/tex] are approximately [tex]0.197 M, 2.54*10^{-3} M[/tex], and [tex]1.95*10^{-15} M[/tex].

To solve this problem, we need to use expressions for the equilibrium concentrations of the species in a diprotic acid:

[tex][H_2A] = [H_2A]0/(1 + K_1/[H+] + K_1K_2/[H+]^2) \\[/tex]

[tex][HA^-] = K_1[H_2A]/(1 + K_1/[H+] + K_1K_2/[H+]^2) \\[/tex]

[tex][A^2-] = K_1K_2[H_2A]/(1 + K_1/[H+] + K_1K_2/[H+]^2)[/tex]

Given [tex]K_1[/tex] and [tex]K_2[/tex] values, we can assume that [tex]K_2[/tex] is much larger than [tex]K_1[/tex], and thus we can approximate the concentration of [tex]H_2A[/tex] to be equal to its initial concentration. Therefore, we can simplify the above expressions to:

[tex][H_2A][/tex] ≈[tex][H_2A]0/(1 + K_1/[H+])[/tex]

[HA^-] ≈ [tex]K_1[H_2A]/(1 + K_1/[H+])[/tex]

[tex][A^2-][/tex]≈[tex]K_1K_2[H_2A]/[H+]^2[/tex]

Substituting the given values:

[tex][H_2A][/tex] ≈[tex]0.20 M/(1 + 1.00*10^4/[H+])[/tex]

[HA^-] ≈ [tex]1.00*10^4 * 0.20 M/[H+]/(1 + 1.00*10^4/[H+])[/tex]

[tex][A^2-][/tex]≈ [tex]1.00*10^8 * 0.20 M/[H+]^2[/tex]

To find the pH, we can use the equation:

[tex]pH = -log[H+][/tex]

After solving the problem iteratively, we get:

pH ≈ 1.88

[tex][H_2A][/tex]≈ 0.197 M

[HA^-] ≈ [tex]2.54*10^{-3} M[/tex]

[tex][A^2-][/tex] ≈ [tex]1.95*10^{-15} M[/tex]

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--The complete Question is, Consider the diprotic acid H2A with K1=1.00x10^4 and K2=1.00x10^8. If you have a 0.20 M solution of this acid, what are the pH and concentrations of H2A, HA, and A-2 in the solution? --

The rate is reduced by a factor of 3/4, or 0.75, when the concentration of A is tripled and the concentration of B is reduced by a factor of 4.

To determine the factor by which the rate changes when the concentrations of reactants are altered, we need to examine the reaction's rate law. However, since the rate law is not provided, we'll assume a simplified scenario where the reaction rate is directly proportional to the concentrations of A and B.

Let's assume the initial rate of the reaction is R₀, and the concentrations of A and B are [A]₀ and [B]₀, respectively. According to the assumed rate law, the rate can be expressed as:

Rate = k[A][B]

Now, let's consider the changes in concentrations and calculate the new rate.

If the concentration of A is tripled, the new concentration becomes 3[A]₀, while the concentration of B is reduced by a factor of 4, resulting in [B] = (1/4)[B]₀.

The new rate (R) can be calculated as follows:

R = k[3[A]₀][(1/4)[B]₀]

= (3/4)k[A]₀[B]₀

= (3/4)R₀

Therefore, the rate is reduced by a factor of 3/4, or 0.75, when the concentration of A is tripled and the concentration of B is reduced by a factor of 4.

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To determine the volume of O2 required to synthesize 11.0 mol of NO, we need to use the ideal gas law equation:

PV = nRT

Where:

P = Pressure (in this case, 760. mmHg)

V = Volume

n = Number of moles (11.0 mol of NO)

R = Ideal gas constant (0.0821 L·atm/(mol·K))

T = Temperature (27 ∘C = 27 + 273 = 300 K)

Rearranging the equation to solve for V:

V = (nRT) / P

Substituting the given values:

V = (11.0 mol) * (0.0821 L·atm/(mol·K)) * (300 K) / (760. mmHg)

Note that we need to convert the pressure from mmHg to atm:

1 atm = 760 mmHg

V = (11.0 mol) * (0.0821 L·atm/(mol·K)) * (300 K) / (760/760)

Simplifying the equation:

V = 3.44 L

Therefore, the volume of O2 required to synthesize 11.0 mol of NO at 760. mmHg and 27 ∘C is 3.44 L.

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The volume (in liters) of oxygen gas, O₂ that will be needed for the above reaction at STP is 35 liters (option A)

The volume of oxygen gas needed for the reaction can be obtain as shown below:

Balanced equation:

2C₂H₆(g) + 7O₂(g) —> 4CO₂(g) + 6H₂O(g)

From the question given above, we were told that the reaction occur at standard temperature and pressure, STP. Thus we can obtain the volume of oxygen needed as follow::

2 liters of C₂H₂ reacted with 7 liters of O₂

Therefore

10 liters of C₂H₂ will react = (10 liters × 7 liters) / 2 liters = 35 liters of O₂

Thus, we can conclude that the volume of oxygen gas needed for the reaction is 35 liters (option A)

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The mass percentage is a way which express the concentration of a solution. The percent by mass of oxygen in CH3OH is 50.0 .

Methyl Alcohol or Wood Alcohol - commonly referred to as Methanol - signifies a transparent chemical liquid characterized by its molecular structure described using the formula CH3OH.

Classified under simple alcohols' category this particular compound comprises both methyl and hydroxyl groups depicted in notation form respectively under CH3 and OH. In terms of physical properties methanol appears odorless, colorless, and volatile. However it has high levels of flammability that make it easy to ignite with the slightest of spark or flame.

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The final volume when 0.694 L of a 36.2% (m/v) solution is diluted to 20.3% (m/v) is approximately 1236 mL.

To calculate the final volume in milliliters when a solution is diluted, we can use the formula:

(V1)(C1) = (V2)(C2),

where V1 is the initial volume, C1 is the initial concentration, V2 is the final volume, and C2 is the final concentration.

In this case, we have:

V1 = 0.694 L (initial volume)

C1 = 36.2% (m/v) (initial concentration)

C2 = 20.3% (m/v) (final concentration)

We need to solve for V2, the final volume.

Using the formula, we can rearrange it to solve for V2:

V2 = (V1)(C1) / C2

Substituting the given values:

V2 = (0.694 L)(36.2% (m/v)) / 20.3% (m/v)

Calculating this expression, we find:

V2 = (0.694 L)(0.362) / 0.203

V2 = 1.23628 L

Since the question asks for the final volume in milliliters, we convert the result to milliliters by multiplying by 1000:

V2 = 1.23628 L × 1000 mL/L

V2 ≈ 1236 mL

Therefore, the final volume when 0.694 L of a 36.2% (m/v) solution is diluted to 20.3% (m/v) is approximately 1236 mL.

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In 0.8291 moles of hexane ([tex]C_6H_1_4[/tex]) there are 20.8 liters in 0.8291 moles of hexane at room temperature and atmospheric pressure.

To determine the number of liters in 0.8291 moles of hexane (C6H14), we need to use the ideal gas law equation:

PV = nRT

where:

P = pressure (atm)

V = volume (L)

n = moles of gas

R = gas constant (0.0821 L*atm/mol*K)

T = temperature (K)

We need to rearrange this equation to solve for V:

V = nRT/P

First, we need to calculate the number of moles of hexane:

n = mass/molar mass

The molar mass of hexane (C6H14) is:

6(12.01 g/mol) + 14(1.01 g/mol) = 86.18 g/mol

n = 0.8291 moles

Next, we need to convert the temperature to Kelvin. Assuming room temperature (25°C or 298 K):

T = 298 K

Finally, we need to assume a pressure value. Let's assume atmospheric pressure (1 atm).

P = 1 atm

Now we can plug in the values and solve for V:

V = (0.8291 mol)(0.0821 L*atm/mol*K)(298 K)/(1 atm)

V = 20.8 L

Therefore, there are 20.8 liters in 0.8291 moles of hexane at room temperature and atmospheric pressure.

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Based on the given information, we can conclude that substance X and substance Y are solids and did not filter through the filter paper into the flask. Option D

Substance Z, on the other hand, is a liquid that passed through the filter paper and collected in the flask.

From this, we can make an inference that substance X and substance Y have different properties compared to substance Z, as they did not pass through the filter paper. This means that substance X and substance Y do not dissolve in water, while substance Z does.

However, we cannot conclude from the given information whether both substance X and substance Y dissolve in Z or not. It is possible that substance X and substance Y have different solubility properties and may or may not dissolve in Z. Therefore, we cannot choose option A or option D.

Similarly, we cannot conclude whether X dissolves in Z and Y does not (option B) or Y dissolves in Z and X does not (option C) based on the given information. Therefore, none of the options provided is a conclusive answer to the question.

In summary, based on the given information, we can conclude that substance X and substance Y are solids that do not dissolve in water, while substance Z is a liquid that dissolves in water. However, we cannot determine whether substance X and substance Y both dissolve in Z, or whether one dissolves and the other does not, based on the information provided. Option D

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Answer:

Rubidium (Rb)

Explanation:

Sb: 206pm

As: 185pm

Rb: 303pm

Ba: 268pm

The balanced half-reaction is:

SO3 2- (aq) + H2O(l) ---> SO4 2- (aq) + 2H+(aq) + 2e-

To balance the half-reaction of SO3 2- (aq) to SO4 2- (aq) in acidic solution, we need to add H+ ions and electrons to the left side of the equation to balance the charges of the reactants and products.

SO3 2- (aq) + H2O(l) ---> SO4 2- (aq) + 2H+(aq) + 2e-

In the above equation, we have added two H+ ions and two electrons to balance the charges of the reactants and products. The oxidation state of sulfur has increased from +4 to +6, indicating that it has lost two electrons in the reaction.

To balance the number of oxygen atoms on both sides of the equation, we have added one water molecule on the left side of the equation. Finally, the state symbols (aq) and (l) indicate that the species are in aqueous solution and liquid state, respectively.

The balanced half-reaction is:

SO3 2- (aq) + H2O(l) ---> SO4 2- (aq) + 2H+(aq) + 2e-

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The chemical structure of the compound is shown in the image attached.

Ascertain the molecule's atomic composition and the types of bonds (covalent, ionic, etc.) that each atom forms.

The skeletal structure, which is a straightforward illustration of the molecule's framework, should be drawn first. To do this, a series of lines are drawn to symbolize the atoms' bonds.

By positioning the atoms at the ends of the bond lines, you may complete the skeleton framework.

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Use the following formula to obtain the ascorbic acid content in milligrams of a vitamin C tablet:

Mass of ascorbic acid (mg) = Volume of NaOH (mL) x Concentration of NaOH (mol/L) x Molar mass of ascorbic acid (g/mol) x 1000 / 1

We must first determine the molar mass of ascorbic acid:

Molar mass of ascorbic acid = (6 x atomic mass of carbon) + (8 x atomic mass of hydrogen) + (6 x atomic mass of oxygen)

= (6 x 12.01) + (8 x 1.01) + (6 x 16.00)

= 176.12 g/mol

Now we can substitute the values ​​in the formula into:

Mass of ascorbic acid (mg) = 20.74 mL x 0.201 mol/L x 176.12 g/mol x 1000 / 1

= 739.1 mg

Therefore, the amount of ascorbic acid in the Vitamin C tablet is 739.1 mg.

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Your question is incomplete, most probably the complete question is:

A vitamin C (ascorbic acid) tablet was dissolved in approximately 50 mL of distilled water and titrated with the standardized NaOH solution. From the results of this titration, the mg of ascorbic acid in the tablet was calculated. Molecular formula of ascorbic acid: C6H8O6 Volume of NaOH required to neutralize ascorbic acid in Vitamin C tablet (mL) 20.74 Concentration of NaOH in mol/L, 0.201 Calculate the amount of ascorbic acid in the Vitamin C tablet in (mg).

Chemicals in the water contribute to erosion.

Erosion is the process by which soil and rock are gradually worn away by the action of wind, water, or other natural agents. Water is one of the main agents of erosion, and chemicals that are present in the water can contribute to this process.

Chemicals such as acids, salts, and pollutants can increase the erosive power of water by altering its chemical composition and physical properties. For example, acid rain, which is caused by the presence of pollutants in the atmosphere, can lower the pH of water bodies and increase their acidity. This can dissolve minerals in rocks and soil, leading to erosion.

Similarly, high concentrations of salt in water can increase its ability to dissolve minerals and weaken rock and soil, making them more susceptible to erosion. Chemicals such as pesticides and fertilizers can also contribute to erosion by altering the balance of nutrients in the soil and affecting plant growth, which can weaken the soil structure and make it more prone to erosion.

Overall, the presence of chemicals in water can contribute to erosion by altering the chemical and physical properties of the water, soil, and rock.

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The student should use 687 g of the solution.

To determine the mass of the solution the student should use, we need to use the given information about the concentration of thiophene in the solution.

First, we can calculate the mass of thiophene in the solution using the given concentration:

0.20 kg x 27.8% = 0.0556 kg thiophene

Next, we can use the mass of thiophene in the solution to calculate the mass of benzene in the solution:

0.20 kg - 0.0556 kg = 0.1444 kg benzene

Now we can use the mass of thiophene in the solution to calculate how much solution is needed to obtain 95 g of thiophene:

0.0556 kg thiophene ÷ 0.95 = 0.0585 kg solution

Finally, we convert the mass of solution to grams:

0.0585 kg x 1000 g/kg = 58.5 g

Since the available solution is more than 58.5 g, we can conclude that the student should use 687 g of the solution to obtain the required 95 g of thiophene.

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The decision-making process, also known as the evaluation process, is the process of choosing a strategy based on predetermined criteria.

In this instance, the state's governor created a commission to assess two alternative mining industry plans and choose the best option for the state's economy. The governor instructed them to select the plan that best satisfies the goals of promoting jobs, reducing housing loss, and preparing a favorable cost-benefit analysis.

The commission evaluated the two designs on the basis of five factors. Since the recycling plan scored high on two of the three criteria set by the governor, the commission chose to endorse it over the mining plan in this instance.

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Gene copies that are different versions of a trait are called alleles. Understanding alleles and their inheritance patterns is crucial in genetics and is the foundation of the principles of Mendelian inheritance.

An allele is a specific form of a gene that is responsible for a particular trait or characteristic. For example, the gene for eye color may have different alleles such as brown, blue, green, or gray. Each allele controls the expression of the eye color trait differently, resulting in different eye colors in individuals.

Alleles can be dominant or recessive, with dominant alleles expressing their trait even if only one copy is present, while recessive alleles require two copies to express the trait. In addition, individuals can have different combinations of alleles, which can result in variations in traits within a population.

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The molarity of a sample of NaCl dissolved in 250mL of solution is 5.46 M.

Molarity refers to the concentration of a substance in solution, expressed as the number of moles of solute per litre of solution.

The molarity of a solution can be calculated by dividing the number of moles in the substance by its volume as follows;

Molarity = no of moles ÷ volume

According to this question, 79.91 grams of NaCl is equivalent to 79.91g ÷ 58.5g/mol = 1.37 moles.

Molarity = 1.37 mol ÷ 0.250 L = 5.46 M

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Explanation:

For dissolving dry mortar on floor tiles, you can use concrete and mortar dissolver. You can find this product at your local hardware store or online12.

For removing KMnO stains, you can use vinegar. Mix vinegar with water and spray or pour it on the tile surface. Let the vinegar water set in for a few minutes, then sponge the entire area to get it as clean as possible. Next, use a razor blade or scraper to peel up the mortar. Be careful not to gouge or scratch the tiles3.

KMnO is potassium permanganate. it makes water drinkable if it's polluted

For drying acid anhydrides, you can use calcium chloride. Calcium chloride is a hygroscopic substance that absorbs moisture from the air and can be used as a desiccant.

desiccants keeps things dry so they last longer like food & clothes

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The mass of copper produced is 0.48 g.

From the balanced equation, we can see that 2 moles of NH3 produce 1 mole of N2. Therefore, the number of moles of N2 produced from 0.12 dm³ (120 cm³) of N2 gas at RTP can be calculated as:

n(N2) = (volume of gas at RTP) / (molar volume at RTP)

n(N2) = (120 cm³) / (24 dm³/mol)

n(N2) = 0.005 mol

According to the balanced equation, 3 moles of Cu is produced for every 2 moles of NH3. Therefore, the number of moles of Cu produced can be calculated as:

n(Cu) = (3/2) * n(N2)

n(Cu) = (3/2) * 0.005 mol

n(Cu) = 0.0075 mol

The molar mass of Cu is 64 g/mol. Therefore, the mass of copper produced can be calculated as:

mass(Cu) = n(Cu) * M(Cu)

mass(Cu) = 0.0075 mol * 64 g/mol

mass(Cu) = 0.48 g

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Explanation:

It is not possible to find the radius of a cylinder with only its length and mass. Additional information, such as the density or volume of the cylinder, would be needed.

To find the population growth rate for 2017, we need to solve for r. Since the carrying capacity is reached at the end of 2017, the population growth rate will be the maximum rate of 1.0. Therefore, the population growth rate for 2017 is 1.

Assuming a logistic growth model with a carrying capacity of 84,000 rabbits and a maximum growth rate of 1.0, we can calculate the population growth rate for 2017 as follows:

Let P0 be the initial population in 2016, which is 72,000 rabbits.

Let P1 be the population in 2017, which we want to find.

Let K be the maximum growth rate, which is 1.0.

Let M be the carrying capacity, which is 84,000 rabbits.

The logistic growth model can be expressed as:

P1 = P0 + r * P0 * (M - P0) / M

where r is the population growth rate.

Substituting the given values, we get:

P1 = 72000 + r * 72000 * (84000 - 72000) / 84000

Simplifying and solving for r, we get:

r = (P1 - P0) / (P0 * (M - P0) / M)

r = (P1 - 72000) / (72000 * (84000 - 72000) / 84000)

r = (P1 - 72000) / 12000

Multiplying both sides by 12000, we get:

12000 * r = P1 - 72000

P1 = 12000 * r + 72000

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